Which of these is an Arrhenius base?
A. LiOH
B. NH3
C. H2PO4-
D. CH3COOH

Answer:

A. The largest value is 7 and the smallest value is 1. Find the difference. 7 - 1 = 6.

Explanation:

The type of reaction represented by Ba(ClO3)2 → BaCl2 + 3O2 is a decomposition reaction, in which Ba(ClO3)2 undergoing decomposition by releasing oxygen gas.

A decomposition reaction is a type of chemical reaction where a single compound breaks down into two or more simpler substances. In this reaction, the compound Ba(ClO3)2 decomposes into two simpler substances: BaCl2 and O2.

Ba(ClO3)2 is barium chlorate, which consists of barium ions (Ba2+) and chlorate ions (ClO3-). During the decomposition reaction, the compound breaks apart into BaCl2, which contains barium ions (Ba2+) and chloride ions (Cl-), and O2, which represents oxygen gas.

The balanced chemical equation for the decomposition reaction is:

2 Ba(ClO3)2 → 2 BaCl2 + 3 O2

This equation indicates that two molecules of Ba(ClO3)2 decompose to form two molecules of BaCl2 and release three molecules of O2 gas.

The reaction Ba(ClO3)2 → BaCl2 + 3O2 represents a decomposition reaction. In this reaction, the compound Ba(ClO3)2 breaks down into BaCl2 and releases oxygen gas (O2).

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Answer:

Ya'll should really practice more because things like these are easy

Explanation:

You guys need to practice more since stuff like this are pretty simple.

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Answer:

Pic attached of structures

Explanation:

a) Propanal       (R-CHO; Carbonyl grp structure)

b) Dimethyl ether or methoxymethane     (R-O-R)

Answer:

Calcium is the metal so its 29.439%

Explanation:

Calcium Ca 29.439%

Oxygen O 47.008%

Sulfur S 23.553%

Answer:

Pure Water  

Explanation:

Battery acid is well and acid

Bleach is a base

Ocean water is impure so it could lean either way

A process for removing impurities from a compound in a solvent is known as recrystallization, sometimes known as fractional crystallisation.

The idea behind this method of purification is that most substances become more soluble at higher temperatures. This implies that when temperature rises, more solute can dissolve in a given amount of solvent.

In order to create a highly concentrated solution at a high temperature, an impure chemical must be dissolved (the impurities must also be soluble in the solvent). The remedy is chilled. As the temperature drops, the contaminants in the solution and the substance being cleansed become less soluble.

The impure stuff then crystallises before the impurities—assuming there was more impure substance than impurities. Due to the impurities' delayed crystallisation and subsequent retention in the solution, the impure substance will crystallise in a purer form. The more pure crystals now need to be separated, which requires a filtration procedure. Repeating the process is possible. The results of a recrystallization technique can be predicted using solubility curves.

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The diagrams show the arrangements of carbon atoms in diamond and in graphite. The diamond is sp³ hybridized and have tetrahedral shape while graphite is sp² hybridized and is hexagonal ring shaped structure.

Diamond containing carbon atoms are strongly bonded chemically with other four carbons. The carbon atoms are sp³ hybridized and make percept tetrahedral shape. Diamond used in jewelry makin g. they are used by surgeons in the cataract surgery. diamond is hard, used for cutting or drilling rock.

Graphite containing carbon atom are form the weak bond with weak forces. the carbon are sp² hybridized and make a hexagonal ring shape structure. The force in graphite in weak that makes it useful material.  it is used as lubricant. it is used in pencil. used in making electrodes.

The diagrams show the arrangements of carbon atoms in diamond and in graphite. The diamond is sp³ hybridized and have tetrahedral shape while graphite is sp² hybridized and is hexagonal ring shaped structure.

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A replacement reaction is one wherein a set of atoms is replaced by another atom in a molecule. In the given reactions is 2Na + Cl₂ → 2NaCl is not a replacement reaction.

A displacement reaction also known as a replacement reaction can be defined as one wherein an atom is displaced by another atom in a molecule. For example, when iron (Fe) is added to a solution of copper sulfate (CuSO₄), it displaces the copper (Cu) metal.

A single replacement reaction can be described as a kind of redox reaction when an element moves out of a compound, one element is replaced by the other in its own compound.

\(A +BC\longrightarrow AB +C\)

Double replacement reactions take place mostly in aqueous solutions wherein the ions precipitate and the exchange of ions occurs. The double replacement reaction can be represented as:

\(AB +CD\longrightarrow AC +BD\)

Therefore, option (D) is correct.

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a) In a Zero-order reaction after 18 months, the drug concentration in the nebulizer is 55 mg/mL. b) In a First-order reaction after 18 months, the drug concentration in the nebulizer is 59.2 mg/mL.

a) For a zero-order reaction, the rate of drug degradation is constant and independent of the drug concentration. Therefore, the rate equation can be written as:

Rate = k

where k is the rate constant.

Using the given data, we can calculate the rate constant as:

Rate = -Δ[C]/Δt = -(75 - 100)/(10 months) = 2.5 mg/ml/month

So, the rate constant (k) is 2.5 mg/mL/month.

The half-life of a zero-order reaction can be calculated using the following equation:

t1/2 = [C0] / (2k)

where [C0] is the initial concentration of the drug.

Plugging in the given values, we get:

t1/2 = 100 mg/mL / (2 × 2.5 mg/mL/month) = 20 months

Therefore, the half-life of the drug in the nebulizer is 20 months.

To calculate the amount of drug left after 18 months, we can use the following equation:

[C] = [C0] - kt

where [C] is the concentration of the drug at time t, [C0] is the initial concentration of the drug, k is the rate constant, and t is the time interval.

Plugging in the given values, we get:

[C] = 100 mg/mL - 2.5 mg/mL/month × 18 months = 55 mg/mL

b) For a first-order reaction, the rate of drug degradation is proportional to the drug concentration. Therefore, the rate equation can be written as:

Rate = k[C]

where k is the rate constant and [C] is the concentration of the drug.

Using the given data, we can calculate the rate constant as:

Rate = -Δln[C]/Δt = ln([C0]/[C])/Δt = ln(100/75)/(10 months) = 0.0301 1/month

So, the rate constant (k) is 0.0301 1/month.

The half-life of a first-order reaction can be calculated using the following equation:

t1/2 = ln(2) / k

Plugging in the given values, we get:

t1/2 = ln(2) / 0.0301 1/month = 23.0 months

Therefore, the half-life of the drug in the nebulizer is 23.0 months.

To calculate the amount of drug left after 18 months, we can use the following equation:

[C] = [C0] × e^(-kt)

where [C] is the concentration of the drug at time t, [C0] is the initial concentration of the drug, k is the rate constant, and t is the time interval.

Plugging in the given values, we get:

[C] = 100 mg/mL × e^(-0.0301 1/month × 18 months) = 59.2 mg/mL

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The molecular structures of sugars and alcohols are similar due to the presence of the -OH group.

This is a substance which has a sweet taste and is a form of simple carbohydrate.

They are however not similar due to the different numbers of Carbon atoms attached to the -OH group..

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According to the chemical formula: Potasium (s) + Br2(g) KBr(s), 383.18 grams of KBr will be created.

Purchase stock geometry starting at 356g of KBR times. A mole of Kbr is equal to 119 g Kbr multiplied by two. Alright, one mole of KCL for two modes of Kbr times 74.55g Casey Albert. Hence, K C L mass. That was too 223 g KCL here.

We must first balance the chemical equation to ascertain the reaction's stoichiometry in order to answer this problem:

2K(s) + Br2(g) → 2KBr(s)

The ideal petrol law can be used to determine how many moles of Br2 are reacted in 35 litres of Br2 at STP: PV = nRT

where P = 1 atm (at STP), V = 35 L, n = ?, R = 0.0821 L·atm/(mol·K), and T = 273 K.

Solving for n, we get:

n = PV/RT = (1 atm)(35 L)/(0.0821 L·atm/(mol·K))(273 K) = 1.61 mol

As a result, 3.22 mol of K and 1.61 mol of Br2 react (since 2 moles of K reacts with 1 mole of Br2). The molar mass of KBr (119 g/mol) can be used to compute the mass of KBr generated.

mass of KBr = (3.22 mol KBr) x (119 g/mol KBr) = 383.18 g

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The old door is said to be around 5730 years old.

A radioactive isotope called carbon-14 (14C) is frequently used to date historical objects. When an organism passes away, it stops absorbing carbon from the environment, and the 14C content of its remnants starts to degrade at a predetermined pace. We can determine the age of a sample by counting the quantity of 14C that is still present.

The following equation may be used to describe the exponential decline of 14C:

N(t) is the quantity of 14C that is still present at time t, N0 is the starting amount of 14C, is the decay constant, and e is the base of the natural logarithm. N(t) = N0 * e(-t)

It is known that 14C has a decay constant of 1.21 x 10-4 min-1.

We may utilise the fact that the decay rate of 14C is related to the amount of 14C present to estimate the age of the old door. Therefore, we may write: decay rate / initial quantity = where the initial amount of 14C is supposed to be the same as for a recently deceased creature, which has a decay rate of 15.3 decays/(g min) and the decay rate is given as 13 decays/(g min) for the ancient door (g min).

The following equation may be used to calculate the initial quantity of 14C: initial amount = decay rate / = 13 decays/(g min) / 1.21 x 10-4 min-1 = 107438 g

The age of the antique door may now be calculated using the exponential decay equation. Since the decay rate is known, we may use N(t) = N0 / 2, which denotes the period of time needed for half of the original 14C concentration to decay. With the known values substituted, we obtain:

N(t) is equal to N0 * e(-t), followed by N(t) = (107438 g) * e(-1.21 x 10-4 min-1 * t).

N(t) = 0.5 * (107438 g) (107438 g)

After calculating t, we get the following result: t = -ln(0.5) / t = -ln(0.5) / 1.21 x 10-4 min-1 t = 5730 years

Therefore, assuming that the initial concentration of 14C in the ancient door was the same as that of a recently died creature, the age of the door is around 5730 years old.

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Answer:

respiración

Explanation:

The amplitude of a seismic wave usually decreases as the wave moves away from the epicenter due to the phenomenon of wave attenuation.

There are several factors that contribute to this attenuation:

Geometric Spreading: As the seismic wave propagates outward from the earthquake's epicenter, it spreads out over a larger area, resulting in the energy being distributed over a larger volume. This causes the amplitude of the wave to decrease with distance. According to the inverse square law, the intensity of the wave decreases with the square of the distance from the source. Absorption and Scattering: The seismic wave encounters various materials and geological structures as it travels through the Earth. These materials can absorb and scatter the energy of the wave, causing a reduction in its amplitude. Different types of rocks and soil have varying levels of attenuation, leading to differences in the decrease of wave amplitude.

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Answer:

318.749g

Explanation:

The find the mass,

We use this formula

Number of mole = mass/ molar mass

Since number of mole = 3.25mol

Let the number of mass be x

The molar mass of H2SO4

H - 1.00784 * 2= 2.01568

S - 32.065

O - 15.999 * 4 = 63.996

Note there are 2 moles of H and 4 moles of O and 1 mole of S

Molar mass of H2SO4 = 2.01568 + 32.065 + 63.996

= 98.07668g/mol

Number of mole= 3.25mol

3.25 = x / 98.07668

x = 3.25 * 98.07668

x= 318.749g

Hence, the number of mass is 318.749g

Hope it will help you.

The united stated chemical industry produces more sulfuric acid, in terms of mass, than any other chemical. The mass of 3.25 moles of sulfuric acid is 318.749g.

The term molar mass is defined as the ratio between the mass and the amount of substance of any sample of said compound. A mole of any substance is 6.022 × 10²³ molecules.

The find the mass,

We use this formula given as follows:

Number of mole = mass / molar mass

So number of mole = 3.25mol

Let the number of mass be x

The molar mass of H2SO4

H - 1.00784  × 2 = 2.01568

S - 32.065

O - 15.999 × 4 = 63.996

Molar mass of H2SO4

= 2.01568 + 32.065 + 63.996

= 98.07668g/mol

Number of mole = 3.25mol

3.25 = x / 98.07668

x = 3.25 × 98.07668

x = 318.749g

Thus, The united stated chemical industry produces more sulfuric acid, in terms of mass, than any other chemical. The mass of 3.25 moles of sulfuric acid is 318.749g.

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Actually If you look very close to a plant you see this:

And to answer your question leaves are green due to sun nutrients water and im not sure  what else

Diatoms are single-celled algae that have a silica (silicate) shell called a frustule.

Diatoms are photosynthetic organisms and are known for their intricate and diverse shapes. Diatoms are commonly found in freshwater and marine environments and play a significant role in the global carbon cycle.

Micrite is a fine-grained carbonate sedimentary rock composed of tiny carbonate particles. It forms through the precipitation and accumulation of carbonate minerals, such as calcite or aragonite, in marine environments. In the case of chalk, which is primarily composed of microscopic fragments of calcium carbonate from marine organisms, recrystallization can occur at the ocean bottom under specific conditions, leading to the formation of micrites.

Therefore, it's important to note that chert, marble, and quartzite are not the typical products of recrystallization of chalk at the ocean bottom.

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Answer:

I think it's the electron dot structure for oxygen

A substance which has both polar and non-polar portions of the molecule is likely to have some tendency to dissolve in both polar and non-polar solvents is true statement.

It is true that a substance with polar and non-polar parts of its molecules would probably have some potential to dissolve in both polar and non-polar solvents. Amphiphilic or amphipathic refers to a chemical that has both polar and non-polar parts of the molecule.

Detergents, which can dissolve both polar and non-polar compounds, and phospholipids, which make up a significant portion of cell membranes, are two examples of amphiphilic molecules.

Molecules that possess both polar and non-polar areas are said to be amphiphilic. They are helpful in a range of biological and chemical processes because they can interact with both polar and non-polar molecules.

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Answer:

Physical

Explanation:

Water is the only known substance on Earth that exists naturally in three states: solid, liquid, and gas. To change between these states, water must undergo physical changes.. Hydrogen and oxygen are gases at standard temperature and pressure, whereas water is a colorless, odorless liquid

Answer: D. negative

Explanation:

Answer:

Mechanical

Explanation:

Since, this mechanical energy gets converted into thermal energy due to which hairs get dry. Thus, we can conclude that the energy transformation that occurs when a hair dryer is plugged in and turned on is that electrical energy transforms into mechanical and thermal energy.

The little circle subscripts at the top of the deltag, deltah, and deltas represent standard conditions. These conditions correspond to the standard atmospheric pressure, temperature, and humidity respectively.

The standard atmospheric pressure is the average atmospheric pressure at mean sea level, which is 1.01325 bar. The standard temperature is 20°C (68°F), and the standard humidity is 0.00% relative humidity.

Atmospheric pressure is measured in bar and is the amount of force per unit area exerted by the atmosphere on a surface. It is affected by factors such as the weather and altitude. Temperature is a measure of the kinetic energy of the particles in a substance and is measured in degrees Celsius (°C). Humidity is the amount of moisture in the air and is measured in relative humidity (%), which is the ratio of the partial pressure of water vapor in the air to the saturated vapor pressure at a given temperature.

In chemistry and thermodynamics, the values of deltag, deltah, and deltas are often used to calculate the enthalpy, Gibbs free energy, and entropy changes associated with a chemical reaction. The standard conditions for these subscripts are the most common values used when calculating the thermodynamic properties of a reaction. Knowing the standard conditions is important for predicting the thermodynamic behavior of a system.

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The pH of the 0.50 M solution of sodium formate is approximately 10.26.

To calculate the pH of a 0.50 M solution of sodium formate (NaHCOO), we need to consider the hydrolysis of the formate ion (HCOO-) in water. The formate ion is the conjugate base of formic acid (HCOOH), and it can react with water to produce hydroxide ions (OH-) and formic acid.

The hydrolysis reaction of the formate ion can be represented as follows:

HCOO- + H2O ⇌ HCOOH + OH-

We can use the Ka value of formic acid (HCOOH) to determine the concentration of hydroxide ions (OH-) produced in the hydrolysis reaction. The Ka expression for formic acid is:

Ka = [HCOOH][OH-] / [HCOO-]

Given that the Ka of formic acid is 1.8 x 10^(-4), we can rearrange the equation to solve for [OH-]:

[OH-] = (Ka * [HCOO-]) / [HCOOH]

In this case, the concentration of sodium formate (NaHCOO) is 0.50 M, and since sodium formate is a strong electrolyte, it dissociates completely into its constituent ions in water. This means that the initial concentration of formate ion ([HCOO-]) is also 0.50 M.

Now, we can substitute the values into the equation:

[OH-] = (1.8 x 10^(-4) * 0.50) / 0.50

[OH-] = 1.8 x 10^(-4)

The concentration of hydroxide ions ([OH-]) is 1.8 x 10^(-4) M.

To calculate the pH, we need to determine the pOH first:

pOH = -log10([OH-])

pOH = -log10(1.8 x 10^(-4))

pOH ≈ 3.74

Finally, we can calculate the pH using the relationship:

pH = 14 - pOH

pH = 14 - 3.74

pH ≈ 10.26

Therefore, the pH of the 0.50 M solution of sodium formate is approximately 10.26.

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