In comparison to a galaxy and a planet, a star is heavier. an accurate comparison of the cosmological masses of various objects.
Do stars have more mass than planets and less mass than galaxies?A galaxy has a mass that is between that of a moon and that of a planet. A planet has more mass than a star, which has less mass than a galaxy. The stars need a lot of mass to maintain nuclear fusion, which requires resulted in the production of each.
What is the proper ranking of the universe's elements, from smallest to largest?Planets and stars, solar systems, galaxies, and the cosmos are some key concepts to keep in mind in the following order: smallest to largest. Each phrase is a part of the following.
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What is the new period if the pendulum is taken to a planet that has 4 times the mass and 4 times the radius of earth
The new period of the pendulum when it is taken to the new planet is double of its period on Earth.
Period of a pendulumThe period of a pendulum is given by the following formula;
\(T = 2\pi \sqrt{\frac{l}{g} }\)
where;
g is acceleration due to gravity of the pendulumL is length of the pendulumAcceleration due to gravity of the new planetThe acceleration due to gravity of the new planet is calculated as follows;
\(g_E = \frac{GM_E}{R_E^2} = 9.81 \ m/s^2 \\\\g(new \ planet) = \frac{G(4M_E)}{(4R_E)^2} = \frac{4GM_E}{16R_E^2} = \frac{GM_E}{4R_E^2} = \frac{9.81}{4} = 2.45 \ m/s^2\)
New period of the pendulum\(T = 2\pi \sqrt{\frac{l}{g} } \\\\T =\frac{2\pi \sqrt{l} }{\sqrt{g} } \\\\T_1\sqrt{g_1} = T_2\sqrt{g_2} \\\\T_E\sqrt{g_E} = T\sqrt{g} \\\\T = \frac{T_E\sqrt{g_E}}{\sqrt{g} } \\\\T = \frac{T_E \times \sqrt{9.81} }{\sqrt{2.45} } \\\\T = 2T_E\)
Thus, the new period of the pendulum when it is taken to the new planet is double of its period on Earth.
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a subway train is brought to a stop from a speed of 0.500 m/s in 0.400 m by a large spring bumper at the end of its track. what is the force constant of the spring?
The force constant k of the spring is 781000 N/m
What is force?
Once applied, force is described as an external cause that alters or tends to modify the state of the body; if the body is in motion, it comes to rest, and if at rest, it comes to motion. It can also induce a shift in the body's direction, shape, or size. Pushing or pulling a door with force is an example.
Because force is a vector quantity, it has both magnitude and direction. Newton's second law defines force as the "product of a body's mass and acceleration."
In physics, a force is an effect that can change the velocity of an object. A force can cause a mass object's velocity to change (e.g., moving from rest), causing it to accelerate. Force can be thought of as either a push or a pull. Because it has both magnitude and direction, force is a vector quantity. It is measured in newtons, the SI mass unit (N). The letter F stands for force (formerly P).
In its original form, Newton's second law states that the net force acting on an object is equal to the rate at which its momentum varies with time.
Here,
let the force constant is k
Using conservation of energy
0.50 * 5 *10^5 * 0.50^2 = 0.50 * k * 0.40^2
solving for k
k = 781000 N/m
The force constant k of the spring is 781000 N/m
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An electron is released 9. 0 cm from a very long nonconducting rod with a uniform linear charge density 6. 0 µC/m. What is the magnitude of the electron's initial acceleration?
The magnitude of the electron's initial acceleration is \(2.53 * 10^_{30\) \(m/s^2\). Calculated using Coulomb's law and Newton's second law.
At the point when an electron is delivered close to a charged pole, it encounters an electric power because of the electric field created by the bar.
To find the extent of the electron's underlying speed increase, we really want to ascertain the power following up on it and afterward utilize Newton's subsequent regulation, which expresses that power is equivalent to mass times speed increase.
The power following up on the electron can be found utilizing Coulomb's regulation, which relates the extent of the electric power between two charged particles to the result of their charges and the distance between them. For this situation, the electron is set 9.0 cm free from the bar, which has a uniform direct charge thickness of 6.0 µC/m.
Utilizing Coulomb's regulation, we can find the size of the electric power following up on the electron:
\(F = k * (q1 * q2)/r^2\)
where k is Coulomb's consistent, q1 is the charge of the electron, q2 is the charge thickness of the bar, and r is the distance between the electron and the bar.
Subbing the given qualities, we get:
\(F = (9.0 * 10^9 N.m^2/C^2) * [(1.6 * 10^-19 C) * (6.0 * 10^-6 C/m)]/(0.09 m)^2 = 2.304 N\)
Then, we can utilize Newton's second regulation to track down the extent of the electron's underlying speed increase:
a = F/m
where an is the speed increase, F is the power determined utilizing Coulomb's regulation, and m is the mass of the electron.
The mass of an electron is around \(9.11 x 10^_-31} kg\). Subbing this worth, we get:
\(a = 2.304 N/9.11 * 10^-31 kg = 2.53 * 10^_{30}\) \(m/s^2\)
Thusly, the greatness of the electron's underlying speed increase is 2.53 x \(10^_{30\) \(m/s^2\).
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he first right-hand rule relates which two quantities?
A.
current (thumb) to magnetic field (fingers)
B.
magnetic field (thumb) to current (fingers)
C.
current (thumb) to force (fingers)
D.
force (thumb) to current (fingers)
Reset Next
Answer: A.
current (thumb) to magnetic field (fingers)
Answer:
A. current (thumb) to magnetic field (fingers)
Explanation:
According to the Right-Hand Thumb rule, if we are holding a current- carrying straight conductor in our right hand such that the thumb points toward the direction of current, then the fingers will wrap around the conductor in the direction of the field lines of the magnetic field.
Hope it helps.
If you have any query, feel free to ask.
During the push-up, the hips should never hit the ground and should move 1 point
in time with the shoulders. *
True
False
Other:
A race car has a mass of 710 kg. It starts from rest and travels 40 m in 3.0 s. The car is uniformly accelerated during the entire time. What net force is applied to it
The net force applied to it is 6311.9 N.
To calculate the net force to the car, first, we need to find the acceleration using the equation of motion.
Force: This as be defined as the product of mass and acceleration of a body. The S.I unit of force is Newton (N)
⇒ Formula
S = ut+at²/2................. Equation 1⇒ Where:
u = Initial velocityS = Distancet = Timea = accelerationFrom the question,
⇒Given:
S = 40 mt = 3.0 su = 0 m/s (at rest)⇒ Substitute these values into equation 1
40 = 0(3)+a(3²)/2⇒ Solve for a
9a = 80a = 80/9a = 8.89 m/s²⇒ To get the force, we use the formula below
F = ma .................... Equation 2⇒ Where:
F = Force appliedm = mass of the car⇒ Given:
m = 710 kga = 8.89 m/s²⇒ Substitute these values into equation 2
F = 710(8.89)F = 6311.9 NHence the net force applied to it is 6311.9 N.
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An issue the students encountered is that the marble doesn't land on the launch pad all of the time. To remedy this, they consider constructing a funnel to help direct the marble. How do you suggest the students move forward with their design process in order to find a solution?
A Test funnels of the same size and material with varying sized openings.
B Test funnels of the same shape and size with varying materials.
C Test funnels with identical openings and material with varying size.
D Test all of the above funnels and then construct a funnel with the best design elements from each.
I suggest that the students move forward with option A.
Test funnels of the same size and material with varying sized openings. This will allow them to determine the optimal size for the opening that will help direct the marble to the launch pad. Once they have determined the optimal size, they can move forward with constructing the funnel with that size opening.
Calculate the change in gravitational potential energy
when a 1.5Kg box falls from a 2m shelf. Take
g=10N/Kg.
Answer:
30J
Explanation:
Given parameters:
Mass of box = 1.5kg
Height = 2m
Acceleration due to gravity = 10N/kg
Unknown:
Change in gravitational potential energy = ?
Solution:
The change in gravitational potential energy is given as:
ΔGPE = mgh
m is the mass
g is the acceleration due to gravity
h is the height
ΔGPE = 1.5 x 10 x 2 = 30J
A car is travelling with a uniform speed of 72 kmph. Find the distance travelled by it in
20 minutes.
Answer:
The explanation says the answer
Explanation:
72 km/h = (72 * 1000) / 3600 m/s ≈ 20 m/sNext, we can use the formula:distance = speed × timeIn this case, the time is 20 minutes, which is 20/60 = 1/3 hours.So, the distance travelled is:distance = 20 m/s × (1/3) h = 20/3 kmTherefore, the car travels 20/3 km in 20 minutes at a speed of 72 km/h.
do you believe that the universe is expanding?
Answer:
Yes
Explanation:
Many scientists believe that the universe is expanding at an increasing rate. Scientists cannot explain how the universe is expanding at an increasing rate because by law of conservation of energy, there is only a finite amount of energy. Thus, scientists have called this new source of energy dark matter and it is all around the universe helping shape and form the universe.
Pls help answer this quickly, explain thoroughly. Prefer
if typed. Will rate answer good, thanks.
9. Describe what is Electron Beam Lithography and for what specific purpose is this type of lithography is used or why not in semiconductor industry. \( [8 \) marks]
Electron Beam Lithography (EBL) is a technique used in the microfabrication process. In EBL, an electron beam is used to create a pattern or design on a surface. The process involves directing an electron beam onto a surface that is coated with a resist material.
EBL is used for the fabrication of nanostructures and microstructures. It is an essential technique in the field of microelectronics and photonics. It is used to create complex structures that cannot be made using traditional photolithography techniques. The technique is particularly useful in the production of high-resolution images and structures.
In semiconductor industry, EBL is used to create the masks required in photolithography. EBL is a high-resolution process that allows for the creation of masks with feature sizes that are smaller than those possible with conventional photolithography. EBL is also used in the development of new materials and devices.
EBL is not commonly used in semiconductor industry due to its high cost, low throughput, and complexity. The process is slow and requires a lot of time to create patterns. It is also limited in its ability to fabricate large-area structures. Therefore, the technique is more commonly used in research and development applications rather than in industrial production.
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How to integrate 1/ 1 + x2
The integral of 1/(1 + x²) is (1/2)ln|1 + x²| + C where C is the constant of integration.
Integration is a mathematical process of finding the antiderivative of a function. To integrate the given expression 1/(1 + x²), we will use the substitution method.
Let u = 1 + x², du/dx = 2x dx, then dx = du/2x and the integral becomes:
∫1/(1 + x²) dx = ∫1/u * (1/2x) du= (1/2)∫1/u du
The antiderivative of 1/u is ln|u| + C, where C is the constant of integration.
Therefore, the final solution of the integral is (1/2)ln|1 + x²| + C.
Let us work through the steps:
Step 1:Let u = 1 + x² and then differentiate both sides with respect to x to obtain du/dx. du/dx = 2x
Substitute 2x dx = du into the integral ∫1/(1 + x²) dx to get the integral in terms of u:∫1/u * (1/2x) du = (1/2) ∫1/u du
Step 2:Calculate the antiderivative of 1/u, which is ln|u|. Thus, the final solution is (1/2)ln|1 + x²| + C, where C is the constant of integration. The constant C will vary depending on the initial conditions of the problem.
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how is mass related to momentum???
the formula for (momentum) P = (force) F * (Mass) M
P = FM
if mass = 0 momentum = 0
Hope this helps...
Answer:
In terms of an equation, the momentum of an object is equal to the mass of the object times the velocity of the object. ... The equation illustrates that momentum is directly proportional to an object's mass and directly proportional to the object's velocity. The units for momentum would be mass units times velocity uni
Explanation:
Maximize points by completing the tasks correctly on first attempt. Incorrect responses incur a 2 point penalty per attempt. Calculate the distance and luminosity of Dargo in the following units: Distance meters Luminosity watts L s
Calculate the luminosities, in L s
, of the other stars.
No, without additional information such as apparent magnitude or spectral type, it is not possible to accurately calculate the distance and luminosity of Dargo or the luminosities of other stars.
Can the distance and luminosity of Dargo be calculated without additional information?In order to calculate the distance and luminosity of Dargo, we need additional information such as the star's apparent magnitude, spectral type, or any other relevant data. Without this information, it is not possible to provide accurate calculations for the distance and luminosity of Dargo or the luminosities of other stars.
Distance in astronomy is typically measured using units such as parsecs (pc) or light-years (ly). Luminosity, on the other hand, is a measure of the total amount of energy emitted by a star per unit time and is usually expressed in units of watts (W) or solar luminosities (L☉).
To calculate the distance to a star, methods such as parallax measurements or spectroscopic parallax can be used. These methods rely on observations and measurements of the star's apparent position or characteristics to determine its distance from Earth.
Luminosity can be calculated using various methods, including the star's temperature, radius, and the Stefan-Boltzmann law, which relates the luminosity of a star to its temperature and radius.
Without specific data or parameters for Dargo or other stars, it is not possible to provide accurate calculations for their distances or luminosities.
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A student pushes a 40-N block across the floor for a distance of 10 m. How much work was done to move the block? 4 J 40 J 400 J 4,000 J.
Answer:
\(\boxed {\boxed {\sf 400 \ J}}\)
Explanation:
Work is a force that causes the displacement of an object. It is the product of force and displacement.
\(W=Fd\)
The force is 40 Newtons and the displacement is 10 meters.
F=40 N d=10 mSubstitute the values into the formula.
\(W= 40 \ N * 10 \ m\)
Multiply.
\(W= 400 \ N*m\)
Convert the units. 1 Newton meter is equal to 1 Joule, so our answer is equal to 400 Joules.
\(W= 400 \ J\)
400 Joules of work was done to move the block.
Answer:
400 J
Explanation:
This is the correct answer for k12
From rest, a car accelerates to 4.2 m/s2 for 10 seconds before winning the race. How far did it run?
Write the final answer in complete sentence.
Answer:
\( s = ut + \frac{1}{2} a {t}^{2} \\ u = 0 \\ a = 4.2 \: m {sec}^{ - 2} \\ t = 10sec \\ s = 0 + \frac{1}{2} (4.2) {10}^{2} \\ = 1.2 \times 100 \\\boxed{ s = 120 \: m}\)
after the dark wand touched the basket, what was the polarity of the basket? did the basket gain or lose electrons during the contact with the dark wand? where did the electrons go (or come from)?
After the dark wand touched the basket, The basket took on a negative charge, the charge was decreased. The dark wand stole electrons from the pail since it had a negative charge.
Charge is a fundamental property of matter that describes the electrical interaction between objects. It is a scalar quantity with units of Coulombs (C) in the SI system. There are two types of charges: positive and negative.
Positive charges have more protons than electrons and are attracted to negative charges. Negative charges have more electrons than protons and are attracted to positive charges. Objects with the same charge will repel each other.
Charge is conserved, meaning that the total charge in a system remains constant, even though the charge distribution can change. This is known as the law of conservation of charge.
Therefore, After the dark wand touched the basket, The basket took on a negative charge, and the charge was decreased. The dark wand stole electrons from the pail since it had a negative charge.
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Suppose that you have left a 200-mL cup of coffee sitting until it has cooled to 30âC , which you find totally unacceptable. Your microwave oven draws 1100 W of electrical power when it is running. If it takes 45 s for this microwave oven to raise the temperature of the coffee to 60âC , what is the efficiency of heating with this oven?
e=(what you get/what you had to pay)
A) Which of the following is the quantity you would label as "what you got"?
B) Which of the following is the quantity you would label as "what you had to pay"?
C) Find the efficiency e of the oven. You will need to use the fact that 4.2 J of energy is required to raise the temperature of 1.0 mL of coffee by 1.0âC .
D) The oven draws 1100 W of power, and you have determined that it heats with an efficiency of 51%. Using this information, determine the time t it would take to bring 240 mL of water from 25âC to 100âC . Note that 4.2 J of energy is required to raise the temperature of 1.0 mL of water by 1.0âC (the same as for the coffee above).
A) The quantity labeled as "what you got" is the increase in thermal energy of the coffee, which is given by the equation:
ΔQ = mcΔT
where m is the mass of the coffee, c is the specific heat capacity of coffee (assumed to be the same as water), and ΔT is the temperature increase.
B) The quantity labeled as "what you had to pay" is the electrical energy consumed by the microwave oven, which is given by the equation:
E = Pt
where P is the power of the microwave oven and t is the heating time.
C) We can first calculate the thermal energy gained by the coffee:
ΔQ = mcΔT = (0.2 kg)(4.2 J/g°C)(60°C - 30°C) = 504 J
Next, we can calculate the electrical energy consumed by the microwave oven:
E = Pt = (1100 W)(45 s) = 49500 J
The efficiency of heating is then:
e = ΔQ/E = 504 J/49500 J = 0.0102 or 1.02%
D) We can use the same equations as above, but solve for the heating time instead of the efficiency:
ΔQ = mcΔT = (0.24 kg)(4.2 J/g°C)(100°C - 25°C) = 2268 J
E = Pt = (1100 W)t
e = ΔQ/E = 0.51 = 2268 J/(1100 W)t
Solving for t, we get:
t = ΔQ/(0.51E) = 2268 J/(0.51)(240 mL)(4.2 J/g°C)(75°C)(1 kg/L)(1100 W/s) = 925 seconds or 15.4 minutes.
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What is a specific heat capacity?
Answer:
C.
Explanation:
Specific heat capacity is defined as the amount of heat energy needed to increase the temperature of 1kg of a substance by 1°C.
The formula for specific heat capacity is as follows:
\(C = \frac{Q}{m \Delta T}\)
where:
C → specific heat capacity
Q → heat energy required
m → mass of the object
ΔT → change in temperature.
In the column, the red (water) substance has a _____________ density than the black (corn syrup) substance. 18 points
In the column, the red (water) substance has a less density than the black (corn syrup) substance.
Explain what density is.The measure of how densely a material is packed together is called density. As the mass per unit volume, it has that definition. Density Numeral: D or The density is calculated using the following formula: = m/V, where m is the object's mass and V is its volume.
The relationship between a substance's mass and the amount of space it occupies is known as its density (volume). The density of a substance is determined by the mass, size, and arrangement of its atoms. Density is calculated by dividing a substance's mass by its volume.
From the image, you can see that the black section is thicker and the red is a little bit light.
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ifif it takes 1-minute for 45 c of charge to pass a point in an electric circuit what is the current through the circuit?
Answer:
45C in a minute is
45/60 C in a second
.75 C in a second is 3/4 of an ampere.
Explanation:
The current through a circuit when it takes one minute for 45C of charge to pass to a point in an electric circuit is 0.75 Ampere.
What is an electric circuit?
The electric circuit: a way for current to travel. A battery or generator is a device that provides energy to the charged particles that make up the current, a device that uses current, such as a lamp, an electric motor, or a computer, and the connecting wires or transmission lines to make up an electric circuit. Ohm's law and Kirchhoff's rules are two fundamental laws that quantitatively define how electric circuits function.
Given information,
The charge, q = 45 coulombs,
the time, t =1 minute
t = 60 sec
A minute at 45C is, In one second, 45/60 C,3/4 of an ampere is equal to 0.75 C per second.
Therefore, the current through a circuit when it takes one minute for 45C of charge to pass to a point in an electric circuit is 0.75 Ampere.
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this force acting on the wind flow at little rock was directed generally toward the ______.
This force acting on the wind flow at Little Rock can be described as being directed generally toward a particular direction.
However, it is important to note that wind patterns are influenced by various factors, including local topography, weather systems, and seasonal variations. Therefore, the precise direction of the wind force at any given moment can vary.
Little Rock, the capital city of Arkansas, is located in the southeastern United States. The prevailing wind patterns in this region are influenced by the general weather patterns and geographic features of the area.
In the United States, wind patterns are commonly influenced by the movement of weather systems from west to east. Based on this general pattern, the prevailing winds in Little Rock often come from the south or southwest. This is because air masses tend to move in a counterclockwise direction around low-pressure systems, resulting in a southerly flow of air.
Additionally, Little Rock is situated near the southern edge of the Central Plains, which can also contribute to a south or southwest wind component. The presence of the Ozark Mountains to the north and the Gulf of Mexico to the south can further influence wind patterns in the region.
However, it is important to note that wind direction can change based on daily weather conditions, seasonal variations, and local influences. Therefore, while the prevailing wind direction in Little Rock is generally from the south or southwest, specific wind events and local conditions can cause temporary variations in wind direction.
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determine the internal normal force at point cc . express your answer to three significant figures and include the appropriate units.
The internal normal force at point CC is 200.04 N.
Length of beam is 8 meters
Internal normal force at point CC
Impose equilibrium equations; the sum of forces acting in the vertical direction must be zero. That is,ΣFv = 0∑Fv=0There is a vertical reaction at A, and a vertical reaction at B.
Let us assume that both are upward. At the mid-span, there is a downward force due to the load, which acts as shown below:FBD of the beam shown above is as follows:
The free body diagram shows that the beam is subjected to a uniformly distributed load (UDL) of w kN/m over its entire length. At the mid-span, the load acting on the beam is half of the total load.
That is, 4w/2 = 2w kN. Summing the moments of forces about
Point C, it yields the following equation:ΣMC = 0∑MC=0Internal normal force can be determined using the formula as given below:N = (wL/8) × (2L/3) + wL/2N=200.04 N
The internal normal force at point CC is 200.04 N.
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50 POINTS!!!!
A certain atom has 11 electrons, 8 neutrons, and a charge of -1. What is its atomic mass?
A. 19
B. 15
C. 11
D. 18
Answer:
19
Explanation:
To find the atomic mass, you have to add together the number of neutrons and protons. It gives you the number of neutrons and the number of electrons is the same amount as the protons
Unpolarized light passes through two polarizers whose transmission axes are at an angle of 35.0 ∘ with respect to each other. What fraction of the incident intensity is transmitted through the polarizers? I/I0=??
About 6.15% of the incident intensity is transmitted through the polarizers. When unpolarized light passes through a polarizer, only the component of the electric field vector that is parallel to the transmission axis is transmitted, while the component perpendicular to it is absorbed. If the light passes through another polarizer whose transmission axis is at an angle to the first polarizer, the intensity of the transmitted light depends on the relative orientation of the axes.
In this case, the transmission axes of the two polarizers are at an angle of 35.0 ∘ with respect to each other. We can use Malus' law to calculate the fraction of the incident intensity that is transmitted through the polarizers. Malus' law states that the intensity of light transmitted through a polarizer is proportional to the square of the cosine of the angle between the transmission axis and the polarization direction of the incident light.
Let I0 be the incident intensity of the unpolarized light, and I1 and I2 be the intensities of the light transmitted through the first and second polarizers, respectively. The first polarizer will transmit only half of the incident intensity, since the light is unpolarized and has equal components in all directions. Therefore, I1 = (1/2)I0.
The second polarizer will transmit a fraction of the light that depends on the angle between its transmission axis and the polarization direction of the light transmitted through the first polarizer. This angle is the sum of the angles between the first polarizer and the incident light and between the second polarizer and the transmitted light. Since the transmission axes are at an angle of 35.0 ∘ with respect to each other, this angle is 70.0 ∘. Therefore, the fraction of the intensity transmitted through the second polarizer is:
I2/I1 = cos²(70.0 ∘) = 0.123
Multiplying this by the intensity transmitted through the first polarizer gives:
I2 = (0.123)(1/2)I0 = 0.0615I0
Therefore, the fraction of the incident intensity that is transmitted through both polarizers is:
I/I0 = I2/I0 = 0.0615
So, about 6.15% of the incident intensity is transmitted through the polarizers.
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Riki is standing in the middle of two identical loudspeakers that are 8 m apart and face each other. The speakers are driven in phase by the same oscillator at a frequency of 800 Hz. The speed of sound in the room is 344 m/s. Find the shortest distance in centimeters Riki can walk toward either speaker in order to hear a minimum of sound. Please give your answers with 1 decimal place.
Answer:When two sound waves from two identical sources interfere with each other constructively, the sound intensity at the point of constructive interference is maximum. On the other hand, when the two waves interfere destructively, the sound intensity at the point of destructive interference is minimum.
In this problem, Riki is standing in the middle of two identical loudspeakers that are 8 m apart and face each other, and the speakers are driven in phase by the same oscillator at a frequency of 800 Hz. This means that Riki will experience constructive interference at the point where the distance traveled by the sound waves from each speaker to Riki differs by an integer multiple of the wavelength of the sound waves.
The wavelength of sound waves at a frequency of 800 Hz in air is:
λ = v/f = 344 m/s / 800 Hz = 0.43 m
Let x be the shortest distance that Riki can walk towards either speaker to hear a minimum of sound. In order to have destructive interference at Riki's position, the distance traveled by the sound waves from one speaker should be (n + 1/2)λ farther than the distance traveled by the sound waves from the other speaker, where n is an integer. This can be expressed as:
∣x - (n + 1/2)λ∣ = (m + 1/2)λ
where m is also an integer. In other words, the absolute difference between the distances traveled by the sound waves from each speaker and the distance traveled by Riki should be equal to an odd multiple of half the wavelength.
To find the shortest distance x, we need to find the smallest possible value of m. Since the wavelength is much smaller than the distance between the speakers, we can assume that the sound waves from each speaker travel straight towards Riki, and we can use the Pythagorean theorem to calculate the distance traveled by each sound wave:
d1 = sqrt((8/2 - x)^2 + Riki^2)
d2 = sqrt((8/2 + x)^2 + Riki^2)
where d1 is the distance traveled by the sound wave from the left speaker, d2 is the distance traveled by the sound wave from the right speaker, and Riki is the distance from the midpoint between the speakers to Riki.
Substituting the values into the equation, we get:
∣sqrt((8/2 - x)^2 + Riki^2) - sqrt((8/2 + x)^2 + Riki^2)∣ = (m + 1/2)λ
Squaring both sides and simplifying, we get:
x = (8mλ^2)/(32Riki)
Now, we need to find the smallest value of m that satisfies the condition for destructive interference. Since the wavelength is 0.43 m and we want an odd multiple of half the wavelength, we can substitute m = 0, 1, -1, 2, -2, etc. into the equation and find the corresponding value of x for each case. We then choose the smallest positive value of x, which corresponds to the minimum sound intensity.
For m = 0, we have:
x = (8*0.5*0.43^2)/(32*Riki) = 0.0007Riki
For m = 1, we have:
x = (8*1.5*0.43^2)/(32*Riki) = 0.0021Riki
For m = -1, we have:
x = (8*(-0.5)*0.43^2)/(32*Riki) = -0.0004Riki
For m = 2,
Explanation:
The shortest distance Riki can walk towards either speaker to hear a minimum of sound is half of the wavelength.
We can use the formula wavelength = speed of sound / frequency to find the wavelength of the sound wave produced by the speakers.
wavelength = 344 m/s / 800 Hz = 0.43 m
Since Riki is standing in the middle of the two speakers, the distance to each speaker is equal. Therefore, the distance from Riki to either speaker is 8 m / 2 = 4 m.
To find the shortest distance Riki can walk towards either speaker to hear a minimum of sound, we need to find half of the wavelength.
Half of the wavelength = 0.43 m / 2 = 0.215 m
Converting this to centimeters, we get:
Shortest distance = 0.215 m x 100 cm/m = 21.5 cm
Therefore, Riki needs to walk towards either speaker by a distance of 21.5 cm to hear a minimum of sound.
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Select all of the statements that are true about the rubber ball.
If the ball is cold, its particles tend to have a small amount of kinetic energy
The particles that make up the ball are moving even when the ball is not.
The temperature of the ball depends on the kinetic energies of the particles that make up the ball.
✔️If the ball is cold, its particles tend to have a smallamount of kinetic energy.
When a substance is hot its particles generally have a large amount of kinetic energy when a substance is cold it's particles do not move as much that means the particles tend to have less kinetic energy.✔️The particles that make up the ball are moving even when the ball is not.
Like all matter the ball is made up of particles that are constay moving even ig the ball is sitting still the particles that make up the ball are still moving.✔️The temperature of the ball depends on the kinetic energies of the particles that make up the
ball.
A substance temperature is a measure of the kinetic energies of the substance's particles so the ball's temperature depends of the particles that make up the ball.#CarryOnLearning!
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True or false? If the line of action of the weight of an object lies outside the base of the object, there will be a resultant moment.
The answer is true that if the line of action of the weight of an object lies outside then the base of the object, then there will be a resultant moment.
What is Moment?A force's moment is a measurement of how likely it is to make a body rotate around a certain point or axis. This differs from a body's propensity to translate or move in the direction of the force.
A body must experience the force in such a way that it starts to twist before a moment may emerge.
This happens each time a force is applied so that it misses the body's centroid. When a force does not have an equal and opposing force acting immediately across its path of action, a moment results.
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Electron cloud definition
ANSWER:
STEP-BY-STEP EXPLANATION:
\(\)what is the magnitude of the electric field along the positive z axis? use k in your answer, where k
The magnitude of the electric field along the positive z axis due to the ring is equal to Ez = kqz/√(z² + a²)^{3/2}.
Given the following data:
Radius of ring = a.
Charge of ring = q.
Coulomb's constant, k = = 1/4πε₀.
What is an electric field?An electric field can be defined as a region in which charged particles are placed with force being applied on the particle as a result of the field.
How to determine the magnitude of the electric field?In order to determine the magnitude of the electric field along the positive z axis, we would apply Coulomb's law in order to find the electric field due to a point charge:
\(E = k\frac{q}{r^2}\)
Where:
q represent the charge.r is the distance between two charges.k is Coulomb's constant.Note: The value of r is equal to √(z² + a²) and cosθ is equal to z/√(z² + a²).
Substituting the value of r into Coulomb's law, we have;
\(E = k\frac{q}{(\sqrt{z^2 + a^2}) ^2}\)
Along the z-direction, the electric field is given by:
dz = dEcosθ
Integrating, we have:
∫dz = ∫dEcosθ
Ez = Ecosθ
\(E_z = (\frac{kq}{(\sqrt{z^2 + a^2}) ^2})\frac{z}{\sqrt{z^2 + a^2}} \\\\E_z = \frac{kqz}{(\sqrt{z^2 + a^2}) ^\frac{3}{2} }\)
Ez = kqz/√(z² + a²)^{3/2}.
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Complete Question:
Consider a uniformly charged ring in the xy plane, centered at the origin. The ring has radius a and positive charge q distributed evenly along its circumference. What is the magnitude of the electric field along the positive z axis due to the ring? Use k in your answer, where k = 1/4πε₀