Which of these chemical properties of a sheet of paper

Answer:

O.8A

Explanation:

Answer:

Seahawks

Explanation:

THEY ARE THE BEST TEAM!!!

Answer:

seahawks

Explanation:

yes they r gud

Answer:

3a. 240 C

3b. 3666.67 A

Explanation:

3a. Determination of the charge.

Current (I) = 2 A

Time (t) = 120 s

Charge (Q) =?

The charge, current and time are related by the following equation:

Charge (Q) = current (I) × time (t)

Q = It

With the above formula, we can obtain the charge as follow:

Current (I) = 2 A

Time (t) = 120 s

Charge (Q) =?

Q = It

Q = 2 × 120

Q = 240 C

Thus, the charge is 240 C

3b. Determination of the current

We'll begin by converting 220 KC to C. This can be obtained as follow:

1 KC = 1000 C

Therefore,

220 KC = 220 KC × 1000 C / 1 KC

220 KC = 220000 C

Next, we shall express 1 minute in second. This is shown below:

1 min = 60 s

Finally, we shall determine the current. This can be obtained as follow:

Charge (Q) = 220000 C

Time (t) = 60 s

Current (I) =?

Q = It

220000 = I × 60

Divide both side by 60

I = 220000 / 60

I = 3666.67 A

Thus, the current flowing through the bulb is 3666.67 A

The ball that is projected 125 meters straight upward has a total time in the air of: 10.1 s

The formulas for the vertical launch upward and the procedures we will use are:

Where:

Information about the problem:

Applying the maximum height formula and clearing the initial velocity we get:

y max = v₀²/(2*g)

v₀ = √(y max * (2*g))

v₀ = √( 125 m * (2 * 9.8 m/s²))

v₀ = √( 125 m * 19.6 m/s²)

v₀ = √2450 m²/s²

v₀ = 49.497 m/s

Applying the maximum time formula we get:

t max= v₀ / g

t max= 49.497 m/s / 9.8 m/s²

t max = 5.050 s

Applying  the time of flight formula, we get:

t(of) =2 * t max

t(of) =2 * 5.050 s

t(of) = 10.1 s

In physics vertical launch upwards is the motion described by an object that has been launched vertically upwards in which the height and the effect of the earth's gravitational force on the launched object are taken into account.

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The time taken now is 10 s

We know that in this case, the object was projected vertically upward and we know that in this direction the acceleration due to gravity is negative. Then the ball falls straight down to  the ground. We have to use the equation of kinematics under gravity to approach the problem.

We now have that;

h = ut + 1/2gt^2

Considering the downward motion were g is positive u = 0 m/s

h =  1/2gt^2

t = 2h/g

t = √2h/g

t = √ 2 * 125/10

t = 5 s

Given that the time taken to go up is the same as the time taken to come down;

Total time spent in air = 2 (5 s) = 10 s

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Answer:

a.200 Newtons

Explanation:

Given the following data;

Mass = 20kg

Acceleration = 10m/s²

To find the force;

Force is given by the multiplication of mass and acceleration.

Mathematically, Force is;

\( F = ma\)

Where;

F represents force.

m represents the mass of an object.

a represents acceleration.

Substituting into the equation, we have

\( Force = 20 * 10 \)

Force = 200 Newton.

In an ideal-offset model for diodes, we assume that the diodes have an infinite resistance in the reverse direction and zero resistance in the forward direction. Using this model, we can calculate the current through and voltage across the diode. If we have and in the forward direction, we can assume that the voltage across the diode is zero. This means that the current through the diode will be determined solely by the resistor value. Therefore, the current through the diode will be .

In the reverse direction, the voltage across the diode will be equal to the voltage across the resistor, which is . Since the diode has an infinite resistance in the reverse direction, no current will flow through it, and the current through the resistor will be zero.To summarize, the current through the diode in the forward direction is , and the voltage across the diode is zero. In the reverse direction, the voltage across the diode is , and no current flows through it.

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Power is given by, P= W/t, where W is mechanical work done and t is time taken.

From work-energy relation, work done is equal to the change in potential or kinetic energy.

W = mg\(h_{2}\) - mg\(h_{1}\)

Given,

Mass of mountain climber, m =76.5kg

Height of mountain hill, \(h_{2}\) = 305m

Time taken to climb, t = 42 min= 42×60s= 2520s.

Since climber starts from the down of hill,  \(h_{1}\) = 0m. So, \(h_{2} - h_{1}\) = 305m.

Work done, W = 76.5kg × 9.8m/\(s^{2}\) × 305m

⇒W = 22.866×\(10^{4}\) J.

Average mechanical power, P = 22.866×\(10^{4}\)J ÷ 2520s

⇒P = 90.7375 W (watt)

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Explanation:

v= (f) x ( lambda)

1.7 ms^-1/12.05 m = f =o.14 hz

The airline will need to have at least 167 passengers on each flight to break even.

To calculate the number of passengers needed to break even, we need to consider the total costs and the revenue generated per flight.

The total cost per flight consists of the fixed costs (£25,000) and the variable costs (£75 per passenger). The revenue per flight is determined by the ticket price (£225) multiplied by the number of passengers.

Let's denote the number of passengers as 'P'. The total cost per flight is given by:

Total Cost = Fixed Costs + (Variable Cost per Passenger * Number of Passengers)

Total Cost = £25,000 + (£75 * P)

The revenue per flight is given by:

Revenue = Ticket Price * Number of Passengers

Revenue = £225 * P

To break even, the total cost should equal the revenue:

£25,000 + (£75 * P) = £225 * P

Now, we can solve this equation for P to find the number of passengers needed to break even:

£25,000 + (£75 * P) = £225 * P

£25,000 = £225 * P - £75 * P

£25,000 = £150 * P

P = £25,000 / £150

P ≈ 166.67

Since the number of passengers must be a whole number, we round up to the nearest whole number:

P = 167

The airline will need at least 167 passengers on each flight to break even. However, since the maximum capacity of the aircraft is 200 passengers, the airline will need to fill the aircraft to its maximum capacity to break even on each flight.

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Answer:

C. oversaturated

Explanation:

Sana nakatulong

Answer:

See below

Explanation:

The force applied and the length of the arm

The magnitude of an applied torque depend on force vector, 'θ' is the angle between r and F, and the distance vector.

What is torque?

The force that can cause an object to rotate along an axis is measured as torque. Similar to how force accelerates an item in linear kinematics, torque accelerates an object in an angular direction. A vector quantity is a torque.

Torque is defined as Γ=r×F=rFsin(θ). In other words, torque is the cross product of the force vector, where 'θ' is the angle between r and F, and the distance vector (the distance between the pivot point and the place where force is applied).

The magnitude of an applied torque depend on force vector, 'θ' is the angle between r and F, and the distance vector.

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This statement is "for a non-newtonian fluid, the shear stress is linearly correlated with the velocity gradient." False.

Non-Newtonian fluids do not follow the simple linear relationship described by Newton's law of viscosity, which states that shear stress is directly proportional to the velocity gradient (rate of deformation) in a fluid.

In non-Newtonian fluids, the viscosity or flow behavior can change with the applied shear stress or the rate of deformation.

Non-Newtonian fluids can exhibit various types of flow behavior, such as shear-thinning, shear-thickening, or viscoelastic behavior. In shear-thinning fluids, the viscosity decreases as the shear rate or velocity gradient increases.

In shear-thickening fluids, the viscosity increases with an increasing shear rate. Viscoelastic fluids exhibit both elastic and viscous properties, and their response depends on both the rate and duration of applied stress.

The complex relationship between shear stress and velocity gradient in non-Newtonian fluids makes it necessary to employ specialized mathematical models or empirical equations to describe their behavior accurately.

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Answer:

Alpha decay

Explanation:

Answer:

C

Explanation:

Alpha Decay

Answer: Es importante conocer el sistema ingles porque luego podemos cmmunicar con otros que solo abalan ingles y les podes ayudar con espanol si solo abaln ingles

Explanation:

The electric force between the droplets, and the horizontal acceleration this force produce on the droplets are: 5.84*10^-7 N and 0.32 m/s² respectively

In physics the electric force is the force that attracts or repels two charges (q) separated at a distance called (r), this is expressed in the international system of units in Newton.

To solve this exercise the electric force formulas and the procedures we will use are:

Where:

Given Info:

Applying the electric force formula we have:

F = (k * q1 * q2)/r²

F = [(9 *10^9 N*m²/C² * (2.9*10^-11 C) * (2.9*10^-11 C)]/ (3.6*10^-3 m)²

F = 7.569*10^-12 N*m² /1.296*10^-5 m²

F = 5.84*10^-7 N

Applying the force formula and clearing the acceleration, we get:

a= F/m

a= 5.84*10^-7 N/ 1.8*10^-6 kg

a= 0.32 m/s²

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To determine the number of storage bits required in the controller memory for the twisting joint (type T) of the industrial robot, we need to calculate the repeatability, round the deviations to a reasonable precision, and then calculate the number of addressable positions based on the range of the joint and the chosen accuracy level.

First, let's calculate the repeatability of the joint. Given that the range of rotation is 322°, the repeatability can be calculated as 6 times the standard deviation. Since the standard deviation is a measure of how spread out the data is, multiplying it by 6 ensures that the accuracy of the joint is as close as possible to, but less than, its repeatability.
Next, let's analyze the given data. The 10 samples of deviations from the commanded angles are: 0.176, 0.04, -0.345, 0.079, 0.309, -0.004, -0.102, 0.12, 0.075, and 0.1.
To calculate the standard deviation of these deviations, we need to find the mean and then calculate the differences from the mean. Squaring these differences and taking the average will give us the variance, which we can then take the square root of to obtain the standard deviation.

After calculating the standard deviation, we multiply it by 6 to obtain the repeatability.
Now, to determine the number of storage bits required, we need to consider the accuracy of the joint. The accuracy depends on the precision required for representing the deviations. Assuming a reasonable level of precision, we can round the deviations to, for example, 3 decimal places.
Finally, the number of storage bits required in the controller memory can be calculated by multiplying the range of the joint (322°) by the accuracy (e.g., 0.001°, considering 3 decimal places). This will give us the number of addressable positions, which can be represented by the required number of storage bits.

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A truck accelerating at 0.0083 meters/second2 covers a distance of 5.8 ×\(10^4\) meters. If the truck's mass is 7,000 kilograms, the work done to reach this distance is 3.3× \(10^6\) joules.

The correct answer is option E.

To calculate the work done by the truck to cover a distance of 5.8 × \(10^4\)meters, we need to use the equation for work:

Work = Force × Distance

In this case, the force can be calculated using Newton's second law:

Force = mass × acceleration

Where:

Acceleration (a) = \(0.0083 meters/second^2\)

Distance (d) = 5.8 ×\(10^4\) meters

Mass (m) = 7,000 kilograms

First, let's calculate the force exerted by the truck:

Force = mass × acceleration = (7,000 kg) ×\((0.0083 meters/second^2)\)= 57.1 Newtons

Next, we can calculate the work done:

Work = Force × Distance = (57.1 N) × (5.8 × 10^4 meters) = 3.3158 × \(10^6\)joules

Rounded to the nearest significant figure, the work done by the truck is approximately 3.3 × \(10^6\) joules.

Therefore, the correct answer is E.

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The question probable may be:

A truck accelerating at 0.0083 meters/second2 covers a distance of 5.8 ×\(10^4\)meters. If the truck's mass is 7,000 kilograms, what is the work done to reach this distance?

A. 1.7 × \(10^6\) joules

B. 3.4 ×\(10^6\) joules

C. 5.6 × \(10^6\)joules

D. 6.8 ×  \(10^6\)joules

E. 3,3  ×\(10^6\)  joules

Answer:

average speed is 60km/h

Explanation:

you sum up the speed attained in each distance covered and divide it by 2 to get your answer

Answer:

Concave mirror

Explanation:

Because as we move the object far away from the mirror, the image gets inverted.

Answer:

Concave mirror

Explanation:

The compression of the spring when the mass is placed on it and doesn't move is \(\frac{{M \cdot g}}{{k}}\). The maximum compression when the mass is released is \(\frac{{2 \cdot M \cdot g}}{{k}}\). The speed of the mass when it reaches a height of 2L is sqrt(4 * g * L).

Assumptions: neglecting air resistance, ideal linear spring, one-dimensional motion.

(a) To determine the compression of the spring when the mass is placed on it and doesn't move, we can equate the gravitational force acting on the mass (M * g) to the force exerted by the spring (k * s), where s is the compression of the spring. Therefore, we have:

M * g = k * s

Rearranging the equation to solve for s:

\(s = \frac{{M \cdot g}}{{k}}\)

The correct answer for the compression of the spring is indeed \(s = \frac{{M \cdot g}}{{k}}\).

(b) When the mass is released from being barely touching the top of the spring, it will experience a maximum compression. This maximum compression occurs when all the potential energy of the mass is converted into elastic potential energy of the spring. Therefore, we can equate the potential energy of the mass (M * g * s) to the elastic potential energy of the spring (0.5 * k * s²), where s is the maximum compression of the spring. Solving this equation:

M * g * s = 0.5 * k * s²

Simplifying and solving for s:

\(s = \frac{{2 \cdot M \cdot g}}{{k}}\)

The correct answer for the maximum compression of the spring is \(s = \frac{{2 \cdot M \cdot g}}{{k}}\).

(c) To find the speed of the mass when it reaches a height of 2L above the table, we can apply the principle of conservation of mechanical energy. The initial mechanical energy of the system is the sum of the potential energy (M * g * s) and the elastic potential energy of the compressed spring (0.5 * k * s²). When the mass reaches a height of 2L, all the initial potential energy is converted into kinetic energy (0.5 * M * v²), where v is the speed of the mass.

M * g * s + 0.5 * k * s² = 0.5 * M * v²

Substituting the expression for s from part (c):

\((M \cdot g \cdot \frac{{2 \cdot M \cdot g}}{{k}}) + 0.5 \cdot k \cdot \left(\frac{{2 \cdot M \cdot g}}{{k}}\right)^2 = 0.5 \cdot M \cdot v^2\)

Simplifying and solving for v:

|v| = sqrt(4 * g * L)

The correct answer for the speed of the mass when it reaches a height of 2L above the table is |v| = sqrt(4 * g * L).

Approximations and simplifying assumptions made in this problem may include:

- Assuming negligible effects of air resistance or friction.

- Assuming an ideal spring with linear behavior (Hooke's Law) throughout its range of compression.

- Treating the spring as massless and neglecting its own gravitational potential energy.

- Assuming a one-dimensional motion without any lateral or rotational effects.

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Answer:

wet farts, JK its condensation.

Answer:

It has about 11 fewer days. It does not have seasons. Its new year always occurs in February instead of on January 1.

Explanation:

Answer:

1)  10 kg-m/s

2)  2 kg

3)  20 m/s

Explanation:

The momentum of an object can be calculated using the equation:

\(\large\boxed{p=mv}\)

where:

\(\hrulefill\)

For this question we need to find the momentum of a bowling ball whose mass is 4.0 kg is rolling at a rate of 2.5 m/s.

Given values:

Substitute the given values into the momentum formula and solve for p:

\(p=4.0\;\text{kg} \cdot 2.5\;\text{m/s}\)

\(p=10\;\text{kg m/s}\)

Therefore, the momentum of the bowling ball is 10 kg-m/s.

\(\hrulefill\)

For this question we need to find the mass of a skateboard rolling at a velocity of 3.0 m/s with a momentum of 6.0 kg-m/s.

Given values:

As we want to find mass, rearrange the momentum formula to isolate m:

\(\large\boxed{m=\dfrac{p}{v}}\)

Substitute the given values into the formula and solve for m:

\(m=\dfrac{6.0\; \text{kg m/s}}{3.0\; \text{m/s}}\)

\(m=2\;\text{kg}\)

Therefore, the mass of the skateboard is 2 kg.

\(\hrulefill\)

For this question we need to find the velocity of a baseball with a mass of 0.5 kg and a momentum of 10 kg-m/s.

Given values:

As we want to find velocity, rearrange the momentum formula to isolate v:

\(\large\boxed{v=\dfrac{p}{m}}\)

Substitute the given values into the formula and solve for v:

\(v=\dfrac{10\; \text{kg m/s}}{0.5\; \text{kg}}\)

\(v=20\;\text{m/s}\)

Therefore, the velocity of the baseball is 20 m/s.

A helicopter is a type of aircraft which uses spinning blades ( wings) to fly .

The banana will slide a distance of 20.75 m on the pavement before coming to a stop.

we have

v² = u² + 2ghv² = 0.5² + 2 × 9.8 × 5v²

= 0.25 + 98v² = 98.25v

= √98.25v

≈ 9.91 m/s

When the banana reaches the pavement, the force of friction is responsible for the stopping of the banana.

The frictional force, f = μR

Here, R is the reaction force that acts perpendicular to the surface. So, R = mg, where m is the mass of the banana and g is the acceleration due to gravity. f = μmg

Also, the force that is responsible for stopping the banana is the frictional force, f.

So, f = ma

Here, a is the acceleration of the banana just after it leaves the ramp and starts moving on the pavement.

So, we can write,

μmg = ma

μg = a

At the instant when the banana leaves the ramp and starts moving on the pavement, its velocity is 9.91 m/s.

Therefore, using the equations of motion,

v² = u² + 2as0 = 9.91² + 2a × ss = (0 - 98.2)/2 × (-0.23)s = 20.75 m

The banana will slide a distance of 20.75 m on the pavement before coming to a stop.

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The potential energy of Nan suitcase of mass 14 kg is 54.88 J.

Potential energy is the energy of a body due to its position in the gravitational field.

To calculate the potential energy, we use the formula below

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the potential energy is 54.88 J.

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