Which of the following wavenumber corresponds to the carbon/carbon triple bond region on an IR spectrum? 500 4000 cm 400-4000 cm1 400 1500 cm1 2100 2300 cm1 1600 - 1850 cm1

The depth of the Grand Canyon at the spot where you can hear your echo 5.2 seconds after you shout is 884 meters.

The equation to find the distance from speed and time is:

distance = speed x time

In this problem, we are given the speed of sound (340 m/s) and the time it takes for the sound to travel to the bottom of the canyon and back (5.2 s). To find the distance from the top of the canyon to the bottom, we can use the above equation:

distance = speed x time = 340 m/s x 5.2 s = 1768 m

However, this distance represents the total distance traveled by the sound wave, which includes the distance from the top of the canyon to the bottom and back to the top. Since we are only interested in the depth of the canyon, we need to divide the total distance by two:

depth of canyon = distance / 2 = 1768 m / 2 = 884 m

Therefore, the depth of the Grand Canyon at the spot where you can hear your echo 5.2 seconds after you shout is 884 meters.

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Answer:

ATP is a stored form of energy

Explanation:

it is the main source of this

Answer:

cannot be measure

Hope this helps :) !!!

The balanced redox reaction is

\(3F(e)_3+ + 2N O^{-2} + 4H_2O\)→ \(3F(e)_2+ + 2N O^{-3} + 4H+\)

Let's start balancing the redox reaction. Here is the given redox reaction:

\(3F(e)_3+ + 2N O^{-2} + 4H_2O\) → \(F(e)_2+ + H+ + N O^{-3}\)

Step 1: Separate the redox reaction into two half-reactions.Half-reaction 1: \(F(e)_3+\)→ \(F(e)_2+\) Half-reaction 2: \(N O^{-2}+ H_2O\) → \(N O^{-3}+ H+\)

Step 2: Balance the elements other than H and O in each half-reaction. Balanced Half-reaction 1: \(F(e)_3+\) →\(F(e)_2+\)Balanced Half-reaction 2: \(N O^{-2} + H_2O\) → \(N O^{-3} + H+\)

Step 3: Balance the oxygen atoms by adding H2O to the side that needs oxygen . Balanced Half-reaction 1: \(F(e)_3+\) → \(F(e)_2+\) Balanced Half-reaction 2: \(N O^{-2}+ H_2O\) →\(N O^{-3} + H+ + H_2O\)

Step 4: Balance the hydrogen atoms by adding H+ to the side that needs hydrogen . Balanced Half-reaction 1: \(F(e)_3+\) → \(F(e)_2+\) + e− + H+Balanced Half-reaction 2: \(N O^{-2} + H_2O + H+ - > N O{-3}+ H+ + H_2O + e^-\)

Step 5: Determine the number of electrons required to balance the half-reaction . Balanced Half-reaction 1: \(F(e)_3+ - > F(e)_2+ + e^{-}+ H+\) [3 electrons are required]Balanced Half-reaction 2: \(N O^{2} + H_2O + H+ - > N O^{-3} + H+ + H_2O + e^-\)[2 electrons are required]

Step 6: Multiply the half-reactions by integers to make the number of electrons equal for both half-reactions.Balanced Half-reaction 1:\(3(F(e)_3+ - > F(e)_2+ + e^{-} + H+\) ).Balanced Half-reaction 2: \(2(N O^{-2} + H_2O + H+ - > N O^{-3}+ H+ + H_2O + e^{-})\)

Step 7: Add the balanced half-reactions together\(3F(e)_3+ + 2N O^{-2} + 4H+ - > 3F(e)_2+ + 2N O^{-3} + 2H_2O\) .The balanced redox reaction is:\(3F(e)_3+ + 2N O{-2} + 4H_2O - > 3F(e)_2+ + 2N O^{-3} + 4H+\)

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In an investigation of the decomposition of water, a student compared the amount of oxygen in one test tube to the amount of hydrogen in the other test tube is There is one - half as much as hydrogen.

In decomposition of water , water can be broken into the hydrogen gas and the oxygen gas. The water decomposition reaction is given as :

2H₂O   ------>     2H₂     +     O₂

The ratio of  hydrogen and oxygen in the decomposition reaction of water is 2 : 1.

Thus, In an investigation of the decomposition of water, a student compared the amount of oxygen in one test tube to the amount of hydrogen in the other test tube is There is one - half as much as hydrogen.

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Answer: I'm not 100% sure this is the formula but I hope it still helps! :)

Explanation:

Bornane; Cyclodecene; Decalin; Decynes. 1-Decyne; 2-Decyne; 3-Decyne; 4-Decyne; 5-Decyne, also known as dibutylethyne; Spirodecane

Answer: Toxic exposure can be defined as the exposure of a toxin or poison and when it gets imbibe or absorbed in the body of a person and get circulated to all the parts of the body through blood circulation.

Explanation:

A person may get exposed to the toxin either accidentally or for a purpose. The toxin can also be used a weapon to kill another person. There are two main kinds of exposure acute and chronic. The acute exposure of the toxin may remain for a short period of time and the chronic exposure is for prolonged period. Sometimes acute poison can cause instant death and the chronic poison shows a later profound impact on the body with daily intake of some amount of poison. Levels of toxicity can be defined as the different ranges of exposure of toxic.

CuI2 is not a known compound. Copper compounds typically have different oxidation states for copper, resulting in various compound names.

Copper(II) oxide (CuO): It is a black solid compound where copper is in the +2 oxidation state. It is commonly used as a pigment and in catalytic reactions.

Copper(II) sulfate (CuSO4): It is a blue crystalline compound in which copper is in the +2 oxidation state. It is used in various applications such as agriculture, electroplating, and as a laboratory reagent.

Copper(I) oxide (Cu2O): It is a red crystalline compound in which copper is in the +1 oxidation state. It is used as a pigment, in solar cells, and as a catalyst.

Copper(II) chloride (CuCl2): It is a greenish-brown solid compound in which copper is in the +2 oxidation state. It is utilized in various chemical processes, including etching and catalyst synthesis.

Copper(II) nitrate (Cu(NO3)2): It is a blue crystalline compound where copper is in the +2 oxidation state. It is commonly used in the production of catalysts, as a coloring agent, and in electroplating.

These are just a few examples of copper compounds with different oxidation states and properties. It's important to note that the compound CuI2 mentioned in the question, if it exists, would be an exception to the typical nomenclature for copper compounds.

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- In reactions 1 and 2, the highlighted atom (oxygen) is reduced.

- In reaction 3, the highlighted atom (sulfur) is neither oxidized nor reduced.

- In reaction 4, the highlighted atom (oxygen) is reduced.

In the given chemical reactions, we need to identify whether the highlighted atom is being oxidized or reduced. Let's analyze each reaction individually:

Reaction 1: 4 HF (g) + SiO₂ (s) → SiF₄ (g) + 2 H₂O (g)

In this reaction, the highlighted atom is oxygen (O). Oxygen in SiO₂ undergoes a change in oxidation state from -2 to 0 in SiF₄. Therefore, the highlighted atom (oxygen) is reduced.

Reaction 2: 2 Cl (aq) + 2 H₂O (l) → 2 OH (aq) + H₂ (g) + Cl₂ (g)

In this reaction, the highlighted atom is oxygen (O). Oxygen in H₂O undergoes a change in oxidation state from -2 to -1 in OH. Therefore, the highlighted atom (oxygen) is reduced.

Reaction 3: H₂S (aq) + 2 NaOH (aq) → Na₂S (aq) + 2 H₂O (l)

In this reaction, the highlighted atom is sulfur (S). Sulfur in H₂S undergoes a change in oxidation state from -2 to -2 in Na₂S. Therefore, the highlighted atom (sulfur) is neither oxidized nor reduced.

Reaction 4: 2 H₂ (g) + O₂ (g) → 2 H₂O (g)

In this reaction, the highlighted atom is oxygen (O). Oxygen in O₂ undergoes a change in oxidation state from 0 to -2 in H₂O. Therefore, the highlighted atom (oxygen) is reduced.

To summarize:

- In reactions 1 and 2, the highlighted atom (oxygen) is reduced.

- In reaction 3, the highlighted atom (sulfur) is neither oxidized nor reduced.

- In reaction 4, the highlighted atom (oxygen) is reduced.

It's important to note that oxidation and reduction involve changes in the oxidation state of atoms, indicating the gain or loss of electrons. The analysis above is based on the change in oxidation state of the highlighted atom in each reaction.

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Answer:

Fossil fuels.

Explanation:

Non-renewable energy comes from sources that will run out or will not be replenished in our lifetimes—or even in many, many lifetimes. Most non-renewable energy sources are fossil fuels: coal, petroleum, and natural gas. Carbon is the main element in fossil fuels.

Answer:

Fossil fuel

Explanation:

I searched this up since I forgot.

Answer: 1 more of hydrogen =22.4dm3

X moles of hydrogen =4.48dm3

22.4dm3x = 4.48dm3

4.48dm3\22.4dm3

X=0.2 moles

Explanation: 1 volume of hydrogen at STP is 22.4dm3

Answer:

The number of proton in an atom is equal to the atomic number of that element. Thus, Number of protons = Atomic number ( Z )

Some of the muscle attached to the skeleton is voluntary and may be used for movement.

Answer:C: Some of the muscle attached to the skeleton is voluntary and may be used for movement.

Explanation:EDGE2021

Answer:

It is the first or second one. The other two didn't work for me.

Explanation:

Hope this helps :)

Answer:

It will be apathetic and non-caring

Explanation:

In a chemical reaction at equilibrium, the rate of the forward reaction is equal to

the rate of the reverse reaction. If the rate of the forward reaction increases, more products are formed.

A chemical reaction is defined as the type of reaction in which new substances are formed through the formation of chemical bonds.

A chemical reaction is also defined as the combination of two or more chemical elements called reactants to form new substances called the products.

A chemical reaction in equilibrium occurs when the rate of formation of products (forward reaction)is equal to the rate of formation of the reactants (reverse reaction).

Also according to the Le Chatelier's Principle, the change to the equilibrium position in every case is either a favoring of the forward reaction or a favoring of the reverse reaction.

Therefore an increase in the rate of the forward reaction will lead to an increase in the amount of products that are formed.

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Answer:the rate of forward reaction is equal to & increases

Explanation:  I got it right on the test

Answer:

∑Q(TTL) = 347 Kj. = 82.8 Kcal. (3 sig. figs.)

Explanation:

Draw a typical heating curve for water (see figure below) and label each section with data needed to calculate the amount of heat flow in the specified section.  

Super-imposing given data onto a trace of a typical heat flow chart for water finds there are three segments of the heating curve that can utilize the given data to calculate heat flow for each segment. With all three heat flow quantities, the total heat quantity associated with this problem is marked in orange. Calculate the heat quantity associated with the designated segments and add to obtain total heat flow for the transitions listed.  

Point E to D => Q₄ = m∙ΔHᵥ = (115g)(540 cal/g) = 62,100 cals.

Point D to C => Q₃ = m∙c∙ΔT = (115g)(1 cal/g∙˚C)(100˚C) = 11,500 cals.

Point C to B => Q₂ = m∙ΔHₓ = (115g)(80cal/g) = 9,200 cals.

Total Heat Flow (∑Qₙ) = Q₄ + Q₃ + Q₂ = 62,100 cals.  +  11,500 cals.  +  9,200 cals. = 82,800 cals.

= (82,800 cals.)(4.184 joules/cal.) = 346,435 joules = 346.435 Kj ~ 347 Kj (3 sig. figs.) _____________________________________________________

m = mass = 115g

c = specific heat of liquid water = 1 calorie/gram·°C = 4.184 j/g·°C

ΔT = temperature change in degrees Celsius

ΔHᵥ = heat of vaporization = 540 cals./gram

ΔHₓ = heat of crystallization = 80 cal./gram

Qₙ = heat flow quantity per specific segment (calories or joules)

∑Qₙ = total heat flow

Heating curve for water:

Note in the diagram that only two formulas are used.

Q = m·c·ΔT => heating or cooling the pure condensed state. The segments demonstrate temperature change.

Q = m·ΔHₙ => heat flow during phase change. Note, in these segments of the heating curve two phases are in contact. That is solid/liquid or liquid/gas phase substances. Also note, in these segments, when two phases are in contact no temperature change occurs. Examples, ice water remains at a constant temperature until all ice is melted or all of the liquid water is frozen depending upon the direction of heat flow. The same is true for boiling water in that when two phases are in contact (liquid/gas), temperature remains constant. The portions of the heating curve designating phase transitions are horizontal and are defined by the equation Q = m·ΔH,  while the curve segments that are only one phase demonstrate temperature change and are defined by the equation containing temperature change, Q = m·c·ΔT.  

The total energy released during this whole process was 346.4 kiloJoules.

Explanation:

Given:

115 g of steam at 100°C condenses, cools, and falls as snow at 0.0°C.

To find:

The energy released during this whole process.

Solution:

In the given three stages will appear:

1) \(H_2O(g)\rightarrow H_2O(l) (at 100^oC)\)

Phase change will occur at 100°C, that is from gas to liquid.

Energy released during the phase change of water from gas to liquid =\(Q_1\)

Latent heat of vaporization of water =\(\Delta H_{vap}=2.260 kJ/g\)

Latent heat of condensation of water =\(\Delta H_{con}=- \Delta H_{vap}=2.260 kJ/g=-2.260 kJ/g\)

Mass of steam = 115 g

\(Q_1=115 g\times \Delta H_{con}\\=115g\times -2.260 kJ/g=-259.9 kJ\)

2) \(H_2O(l)(at 100^oC)\rightarrow H_2O(l) (at 0.0^oC)\)

Mass of water = m = 115 g ( steam converted into water)

Initial temperature of water = \(T_i=100^oC\)

Final temperature of water =\(T_f=0.0^oC\)

The specific heat of water = c = 8.186J/g°C

Energy released during this stage = \(Q_2\)

\(Q_2=m\times c\times (T_f-T_i)\\=115g\times 4.186 J/g^oC\times (0.0^oC-100^oC)\\=-48,139 J= -48.139 kJ\\(1 J=0.001kJ)\)

3)\(H_2O(l)(at 0.0^oC)\rightarrow H_2O(s) (at 0.0^oC)\)

Water freezes at 0°C ,phase change will occur at 0.0°C, that is from liquid to solid.

Energy released during the phase change of water from liquid to solid=\(Q_3\)

Latent heat of fusion of water =\(\Delta H_{fus}=-334J/g\)

Mass of water = 115 g

Energy released during this stage:

\(Q_3=115g\times \Delta H_{fus}\\115\times -334 J/g=-38,410 J\\=-38,410 J=-38.410 kJ\\(1 J=0.001kJ)\)

Total energy released during this whole process = Q

\(Q = Q_1+Q_2+Q_3\\Q=(-259.9 kJ)+( -48.139 kJ)+(-38.410 kJ)\\=-346.449 kJ\approx -346.4 kJ\)

(negative sign indicates that heat energy is released))

The total energy released during this whole process was 346.4 kiloJoules.

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Answer:

false

Explanation:

Answer:

Steel

Explanation:

I took a test and got this question right

The cart with the fastest acceleration is 5 kg cart because its mass is the smallest.

Mass can be experimentally defined as a measure of the body's inertia, meaning the resistance to acceleration when a net force is applied.

The parameters given include;

applied force, F_ = 90 N

mass of cart: 5kg, 6kg, 8 kg, 9 kg

According to Newton's second law of motion, the force applied to an object is directly proportional to the product of mass and acceleration of the object.

F_ = ma

The acceleration of the 5 kg cart is calculated as follows;

a = f_ /mass

a = 90/5

a= 18m/s²

The acceleration of the 6 kg cart is 15 m/s² (using Newton's second law)

The acceleration of the 8 kg cart is 11/25 m/s² (using Newton's second law)

The acceleration of the 9 kg cart is 10m/s² (using Newton's second law)

Therefore, the cart with the fastest acceleration is 5 kg cart because its mass is the smallest.

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Complete question:

A force of 90N is applied to each cart below, which one will accelerate the fastest?

Mass: 5 kg

Mass: 6 kg

mass: 8 kg

Mass: 9 kg

Answer:si and ge

Explanation:

Both silicon (Si) and arsenic (As) have 5 valence electrons. This means that they both have 5 dots around their chemical symbols in their electron dot diagrams. Thus, option B is correct. The images are attached below.

Phosphorus (P) has 5 valence electrons, but it also has a ground state electron configuration of 1s²2s²2p⁶3s²3p³. This means that phosphorus has 3 dots around its chemical symbol in its electron dot diagram, and 2 dots that are not shown.

Sulfur (S) has 6 valence electrons, but it also has a ground state electron configuration of 1s²2s²2p⁶3s²3p⁴. This means that sulfur has 4 dots around its chemical symbol in its electron dot diagram, and 2 dots that are not shown. Thus, option B is correct.

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Values of entropy, from lowest to greatest

N2 = 191.6, NO = 210.8, NO2 = 240.0, N2O4 = 304.4, N2 is the lowest and N2O4 is the greatest entropy values.

Entropy, broadly speaking, serves as a metric for energy quality, with lower entropy indicating higher quality. Entropy is lower for energy that has been carefully organised (the efficient library). The random-pile library is a chaotic energy storage system with high entropy.

In other terms, entropy is the growth in disorder inside a system. It is described as the measurement of degree of unpredictability.

Greek words en- = in + trope = a turning were combined to form the word entropy by German physicist Rudolf Clausius in 1865 [Cl] (point). The name has an energy analogue, and etymologists think it was intended to signify the type of energy that all energy eventually and inevitably transforms into: wasteful heat.

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Answer:

Hot material near the core is less dense and rises, when it cools, it becomes more dense and sinks.

Explanation:

This best explains how heat plays a role in the movement of materials within Earth's interior because it's how convection works. Convection is the circular motion that happens when warmer air or liquid which has faster moving molecules, making it less dense rises, while the cooler air or liquid drops down. Convection currents within the earth move layers of magma, and convection in the ocean creates currents.

Earth’s interior is like a closed chamber, hot material near Earth's surface is more denser and sinks, and when it cools, it becomes less dense and Rises.

Convection is the process of heat transfer by the bulk movement of molecules within fluids such as gases and liquids. The heat transfer take place from solid to no solid material. like air and water.

As we take example of home. In home heat take nearer the roof and cold air will be nearer to the flour. It is because of hot is less denser then the cold air. Hot air will become less denser and move towords upside. Cold air become denser move towards down.

Similarly, on earth. Nearer to earth hot materials are more dense and sinks. When it cools, it become less dense and rises.

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Answer:

Here's the answer. It's on the photo. Basically, the liquids are moving around, fast and shortly, when they become solid, they slowly stop moving and become still hope i helped :)

The intermolecular force increases and the particles of liquid come together in a proper arrangement when it freezes into a solid.

The matter is composed of incredibly minute particles, which are so microscopic that humans cannot see them with the unaided eye.

It has been noted that matter may be found in nature in a variety of shapes. There are certain materials that are hard and have a defined shape, like wood and stone; others that can flow and adopt the shape of their container, like water; and yet others that have no set shape or size, like air.

According to their physical characteristics and the states in which they are found, or states of matter, the matter may be divided into many groups.

The fundamental three states of matter are as follows:

In addition to the three just described, there are two more states of matter that we do not see frequently. They are Bose-Einstein condensate and plasma.

States of matter are distinguished by variations in their physical properties that are caused by external factors like pressure and temperature.

Therefore, when a liquid cools down to solids, the intermolecular force increases, and the particles of the liquid come together in a proper arrangement.

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The right response is an atom with 8 valence electrons, or (c). Because of its stable electron configuration, an atom with an entire octet (8 valence electrons) is not reactive.

Valence electrons range in number from 1 to 8 depending on the element. Bonding: Atoms with 8 valence electrons tend to be more stable. Because they have 8 valence electrons, neon, argon, krypton, and xenon atoms are nonreactive.

The least reactive elements are noble gases. They have eight valence electrons, which fill their outer energy level, and this explains why. Noble gases rarely interact with other elements to form compounds since this is the arrangement of electrons that is the most stable.

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Answer:

Br-CH2-CH(CH3)2-C(Cl)H-CH(CH3)2-CHO

Explanation:

The molecule has a total of 14 carbon atoms, 13 hydrogen atoms, and 1 bromine atom. The carbon atoms are arranged in a chain with a methyl group attached to the second carbon atom, a chlorine atom attached to the third carbon atom, and two methyl groups attached to the fourth carbon atom. The fifth carbon atom has a carbonyl group attached to it.

The molecule is an aldehyde, which means that it has a carbonyl group (C=O) at the end of the chain. The carbonyl group is polar, and the oxygen atom has a partial negative charge. The hydrogen atom has a partial positive charge. This polarity makes the aldehyde group susceptible to nucleophilic attack.

The bromine and chlorine atoms are both electrophilic, which means that they have a partial positive charge. This makes them susceptible to nucleophilic attack.

The methyl groups are non-polar and do not have any significant reactivity.

The molecule is a chiral molecule, which means that it has a mirror image that is not superimposable on itself. This is because the carbon atom with the carbonyl group is attached to four different groups.

The molecule is a liquid at room temperature and has a strong odor. It is used in a variety of products, including perfumes, flavorings, and plastics.

1. The IUPAC name of N is nitrogen.

2. Nitrogen dioxide

3.The IUPAC name of O is oxygen

4.The IUPAC name of OH is hydroxyl.

The IUPAC name of ·0 is a radical. It is commonly found in organic chemistry and plays an important role in many reactions.

IUPAC names for the given compounds are:1.1. N: Nitrogen

The IUPAC name of N is nitrogen.

It is a non-metal and belongs to group 15 in the periodic table. It has an electronic configuration of 1s2 2s2 2p3.1.2. NO2: Nitrogen dioxide

Explanation: NO2 is a chemical compound that is formed by the combination of nitrogen and oxygen. It is a reddish-brown gas that has a pungent odor.

The IUPAC name of NO2 is nitrogen dioxide.1.3. O: Oxygen

Explanation: The IUPAC name of O is oxygen.

It is a non-metal and belongs to group 16 in the periodic table. It has an electronic configuration of 1s2 2s2 2p4.

X: UnknownExplanation: No IUPAC name can be given to an unknown compound as the structure and composition are not known.

Y: Hydroxyl Explanation: The IUPAC name of OH is hydroxyl.

It is a functional group that is composed of an oxygen atom and a hydrogen atom (-OH). It is commonly found in alcohols and phenols. ·0: RadicalExplanation: A radical is a molecule or an ion that contains an unpaired electron.

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Note: The complete question is given below

Provide the IUPAC names for the following compounds:

\(CH_3CH_2CH(CH_3)CH_2CH_2CH_2CH_3\)

C6H5CH(CH3)2

H2NCH2CH2CH2CH2CH2NH2

CH3CH2CH2CH2CH2OH

CH3CH2CH2CHOHCH3

Answer:

CO (carbon monoxide)

Explanation:

Answer:

C.) protons and neutrons

Explanation:

Most atoms contain proton(s), neutron(s), and electron(s). Within the nucleus of an atom, there are protons and neutrons. Electrons are located outside of the nucleus.

Answer:

Search it up. It says it on this link: