Answers
Hope this helps!! (:
Answer:matter is anything has mass and take up space
Explanation:
Related Questions
Guysss how to explain nuclear chemistry? And define nuclear chemistry ?
Answers
Answer:
How do amoeba respire.
Define Diffusion.
Show that the following species have the same number of electron Na, Mg, O, and Ne
Answers
Answer:
in its neutral state an atom of Na has 11 electrons so when it loses an electron it becomes Na^+ with 10 electrons.
a neutral atom of Mg has 12 electrons by losing 2 elections it becomes Mg^2+ with 10 electrons
a neutral atom of oxygen has 8 electrons if it gains 2 electrons it becomes O^2- with 10 electrons
a neutral atom of Ne has 10 electrons
All of the above species in their excited states has 10 electrons (except for Ne which has 10 electrons in its neutral state) so they are all isoelectronic with Na^+
13a. [3 marks]
A 4.406 g sample of a compound containing only C, H and O was burnt in excess oxygen. 8.802 g of CO2 and 3.604 g of H20 were produced.
Determine the empirical formula of the compound.
Answers
The empirical formula of the original compound given the combustion analysis data is C₂H₄O
How to determine the mass of Carbon Mass of CO₂ = 8.802 gMolar mass of CO₂ = 44 g/mol Molar of C = 12 g/mol Mass of C =?Mass of C = (12 / 44) × 8.802
Mass of C = 2.4 g
How to determine the mass of HMass of H₂O = 3.604 gMolar mass of H₂O = 18 g/mol Molar of H = 2 × 1 = 2 g/mol Mass of H =?Mass of H = (2 / 18) × 3.604
Mass of H = 0.4 g
How to determine the mass of O
Mass of compound = 4.406 gMass of C = 2.4 gMass of H = 0.4 gMass of O =?Mass of O = (mass of compound) – (mass of C + mass of H)
Mass of O = 4.406 – (2.4 + 0.4)
Mass of O = 1.606 g
How to determine the empirical formula C = 2.4 gH = 0.4 gO = 1.606 gEmpirical formula =?Divide by their molar mass
C = 2.4 / 12 = 0.2
H = 0.4 / 1 = 0.4
O = 1.606 / 16 = 0.1
Divide by the smallest
C = 0.2 / 0.1 = 2
H = 0.4 / 0.1 = 4
O = 0.1 / 0.1 = 1
Thus, the empirical formula of the compound is C₂H₄O
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Which of the following are elements, which are mol-
ecules but not compounds, which are compounds but
not molecules, and which are both compounds and
molecules? (a) SO₂, (b) Sg, (c) Cs, (d) N₂O5, (e) 0.
(f) O₂, (g) 03. (h) CH₁, (i) KBr, (j) S. (k) P4, (1) LiF
Answers
Atoms of different element can not have same atomic number because only same type of atoms combine to form element. Atoms belonging to different element can have different atomic number. Therefore, given elements can be classified as compound and molecules.
What is element?Element generally consist of atoms or we can atoms combine to form element. Atoms of an element is always same, means all the properties of all atoms of one type of element is same. Two or more than two atoms with different physical or chemical properties can not combine together to form an element.
SO₂, N₂O5, CH₁ , Kerr, LiF are compound
O₂, O\(_3\), P4 are molecules
Sg, Cs, O, S are neither molecules nor compounds
Therefore, given elements can be classified as compound and molecules.
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Which is NOT an agent of chemical weathering?
A. water
C. carbon dioxide
B. oxygen
D. wind
Answers
Answer:
water is a water, but is also known as water. water means water, and the synonym of water is water, and antonym of water is non-water. water is located in earth. water's friends are pure water, salt water, dirty water and ice water. water's best friend is pure water, because when water gives water to pure water, pure water uses the water and gives back the water to the water.
thank you for enjoying my story
Explanation:
The act of changing something but not being able to change it back
Answers
A chemical reaction between X and Y forms C according to the reaction below. The data for three trials to measure the
rate of this reaction are also given.
Trial
1
2
3
[X] (M)
0.01
0.01
0.02
X+Y→C
[Y] (M)
0.015
0.030
0.015
What is the rate law for this reaction?
OR=KX²M
OR=KX³M²
OR=KXM²
OR=KX²M²
Initial Rate (M/s)
7.83x10-5
BIBE
3.13x 104
1.57x10
Answers
Explanation: The rate law for a chemical reaction is an equation that relates the rate of the reaction to the concentrations of the reactants. To determine the rate law for a reaction, experiments are typically conducted with different initial concentrations of the reactants and the initial rate of the reaction is measured.
From the data provided, it appears that the reaction is of the form X + Y → C. And the concentration of X and Y are varied in three trials and the corresponding Initial rate is measured.
In the first trial, [X] = 0.01 M and [Y] = 0.015 M, and the initial rate of the reaction is 7.83x10-5 M/s.
In the second trial, [X] = 0.01 M and [Y] = 0.03 M, and the initial rate of the reaction is 3.13x104 M/s.
In the third trial, [X] = 0.02 M and [Y] = 0.015 M, and the initial rate of the reaction is 1.57x10 M/s.
Given the data, the rate law for this reaction is OR = KX²M. This is because when the concentration of X is doubled, the rate of the reaction is quadrupled, which is consistent with a rate law of the form OR = k[X]^2.
A gas mixture containing only helium and neon is 27.1 %% neon (by volume) and has a total pressure of 759 mmHgmmHg. What is the partial pressure of neon?
Answers
Step 1 - Understanding the relation between volume percent and parcial pressure
The parcial pressure of a gas in a mixture can be obtained by the following expression:
\(p_p=x\times p_t\)In the equation above, pp represents the parcial pressure and pt the total pressure. x is the molar fraction, which can be defined as:
\(x=\frac{n_{gas}}{n_{\text{total}}}\)I.e., is the quociente between the number of moles of the gas you want to calculate the parcial pressure of and the total number of moles.
Since, for a gas, the number of mols is proportional to the volume, the molar fraction is equal the volume percent:
\(n\propto V\rightarrow x=\frac{kV_{gas}}{kV_{\text{total}}}\)K is a constant of proportionallity. It doens't matter its value, since it will be cancelled. We obtain thus:
\(x=\frac{V_{gas}}{V_{\text{total}}}\)I.e., the molar fraction is exactly equal the volume percentage.
Step 2 - Using the relation between parcial pressure and volume percentage to solve the exercise
Since, as we saw, the molar fraction x is exactly equal to the volume percentage, we can substitute it by the volume percentage in the formula for the parcial pressure:
\(p_p=V_{\text{percentage}}\times p_t\)From the exercise, we know that:
\(\begin{gathered} V_{\text{percentage}}=27.1\text{ \% = 0.271} \\ \\ p_t=759\operatorname{mm}Hg_{} \end{gathered}\)Substituting these values on the equation we obtain the parcial pressure of Neon:
\(p_p=0.271\times759=205.6\text{ mmHg}\)The parcial pressure of Neon is thus 205.6 mmHg.
(a) using principles of atomic structure, explain why the first ionization energy of rn is less than that of xe.
Answers
The difference in first ionization energy between Xe and Rn can be explained by the combination of differences in electron configuration and shielding effect.
The energy needed to remove one electron from an atom or ion is known as the initial ionization energy. The number of electrons in the atom and the arrangement of those electrons are two parameters that affect an element's ionization energy.
The electron configurations of the elements Rn (Radon) and Xe (Xenon) are similar, although Radon contains more electrons than Xenon. In contrast to the outermost electrons of Xenon, the outermost electrons of Radon are bound by the nucleus more securely and are therefore more difficult to remove. Because Xe has a lower initial ionization energy than Rn, it is simpler to remove one electron from Xe than from Rn.
Additionally, the shielding effect of inner electrons also affects the ionization energy. The shielding effect refers to the ability of inner electrons to screen or reduce the attraction between the nucleus and outer electrons. In Xe, there are more inner electrons than in Rn, which provides a stronger shielding effect, further reducing the ionization energy of Xe.
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How much carbon dioxide is released when it is fully combusted with 4Kg of ethanol with more than enough oxygen? How do you work it out?
Answers
Answer:
7.640 kg
Explanation:
Step 1: Write the balanced complete combustion equation for ethanol
C₂H₆O + 3 O₂ ⇒ 2 CO₂ + 3 H₂O
Step 2: Calculate the moles corresponding to 4 kg (4000 g) of C₂H₆O
The molar mass of C₂H₆O is 46.07 g/mol.
4000 g × 1 mol/46.07 g = 86.82 mol
Step 3: Calculate the moles of CO₂ released
86.82 mol C₂H₆O × 2 mol CO₂/1 mol C₂H₆O = 173.6 mol CO₂
Step 4: Calculate the mass corresponding to 173.6 moles of CO₂
The molar mass of CO₂ is 44.01 g/mol.
173.6 mol × 44.01 g/mol = 7640 g = 7.640 kg
What is the formula for calculating pH?
O A. pOH= [H*]
————
[OH -]
B. pH = -log[OH-]
C. pH = -log[H+]
D. pH = log[ht]
Answers
Answer:
c. pH=-log[H+]
Explanation:
pH=-log10[H+]
Directions: show all your work, box your answer, and use significant figures to receive credit.What mass of oxygen is needed to react with 55.1g of aluminum in the synthesis of aluminum oxide?
Answers
Answer
49.0 grams of oxygen is needed.
Explanation
Given:
Mass of Aluminum = 55.1 g
What to find:
The mass of oxygen needed to react with the Al.
Step-by-step solution:
The equation for the reaction is:
4Al + 3O₂ → 2Al₂O₃
From the equation; 4 moles of Al reacts with 3 moles of O₂
1 mole of Al = 26.982 g/mol
1 mole of O₂ = 31.998 g/mol
It implies;
(4 mol x 26.982 g/mol) = 107.928 g of Al reacts with (3 mol x 31.998 g/mol) = 95.994 g of O₂
So, 55.1 g of Al will need
\(\frac{55.1\text{ }g\text{ }Al}{107.928\text{ }g\text{ }Al}\times95.994\text{ }g\text{ }O_2=49.0\text{ }g\text{ }O_2\)Therefore, the mass of oxygen needed to react with 55.1g of aluminum in the synthesis of aluminum oxide is 49.0 grams
What is the largest unit of ordinary matter
Answers
Answer:
Explanation:
Conversely, the largest (in terms of mass) fundamental particle we know of is a particle called a top quark, measuring a whopping 172.5 billion electron volts, according to Lincoln.
what is the first step in the scientific inquiry process
Answers
Answer:
make an observation that describes a problem
Explanation:
Answer:
The first step in the Scientific Method is to make objective observations.
Explanation:
....-
Consider two compounds. Compound A contains 15.7 g of sulfur and 18.6 g of fluorine. Compound B contains 25.4 g of sulfur and 60.2 g of fluorine. For Compound A, the ratio of fluorine to sulfur is 1.18. For Compound B, the ratio of fluorine to sulfur is 2.37. Using the Law of Definite Proportions (also called the Law of Constant Composition), could Compound A and Compound B be the same compound
Answers
Answer:
No, compound A and B are not the same compound
Explanation:
According to the law of definite proportion "every chemical compound contains fixed and constant proportions (by mass) of its constituent elements." (Encyclopedia Britannica)
We can see in the question that the ratio of flourine to sulphur in compound A is 1.18 while the ratio of flourine to sulphur in compound B is 2.37.
The two chemical compounds do not contain a fixed proportion by mass of their constituent elements therefore, they can not be same compound according to the law of definite proportions.
Select the correct answer.
What is the molecularity of this elementary step?
A+ A+B-->C+D
A.
unimolecular
B.
bimolecular
c.
trimolecular
D.
tetramolecular
Answers
Answer: C not really sure thoo
Which climatic change in Earth's history has resulted in glaciers?
cold climate
tropical climate
temperate climate
warm climate
Answers
The climatic change in Earth's history that has resulted in glaciers is the cold climate.
During the last 2.6 million years, the Earth has experienced a series of ice ages, or periods of colder global climate, which have led to the growth of glaciers in regions with sufficient snowfall.
These colder periods are associated with changes in the Earth's orbit, tilt, and precession, which affect the amount and distribution of solar radiation received by the Earth. These climatic changes have had significant impacts on the Earth's surface and have influenced the evolution of life on our planet.
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Consider the compound hydrazine N2H4 (MW = 32.0 amu). It can react with I2 (MW = 253.8 amu) by the following reaction 2 I2 + N2H4 ------------- 4 HI + N2 (a) How many grams of I2 are needed to react with 36.7 g of N2H4? (b) How many grams of HI (MW = 127.9 amu) are produced from the reaction of 115.7 g of N2H4 with excess iodine?
Answers
Answer:Cobb
Explanation:What y'all
excactly 1 mole of Ca Cr2 O7 contains how many moles of Ca Cr O?
Answers
1. The number of mole of Ca in 1 mole of CaCr₂O₇ is 1 mole
2. The number of mole of Cr in 1 mole of CaCr₂O₇ is 2 moles
3. The number of mole of O in 1 mole of CaCr₂O₇ is 7 moles
Composition of CaCr₂O₇Composition simply describes the things that makes up a subtance.
From the formula of the compound, CaCr₂O₇, the following were obtained:
1 mole of CaCr₂O₇ contains
1 mole of calcium, Ca2 moles of Chromium, Cr7 moles of Oxygen, OSnice the question is requesting for the number of moles of each element present in one mole of CaCr₂O₇, the answer can be given as follow:
Number of mole of Ca in 1 mole of CaCr₂O₇ = 1 × 1 = 1 moleNumber of mole of Cr in 1 mole of CaCr₂O₇ = 1 × 2 = 2 molesNumber of mole of O in 1 mole of CaCr₂O₇ = 1 × 7 = 7 molesLearn more about composition:
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Of the following statements, the one that is not part of Dalton's atomic theory is that a. each element is composed of indestructible particles called atoms b. all atoms of a given element have the same mass and other properties c. atoms are themselves composed of protons, neutrons, and electrons d. atoms combine in simple whole-number ratios to form compounds
Answers
The statement that is not part of Dalton's atomic theory is that atoms are composed of protons, neutrons, and electrons. Option C.
Dalton's atomic theoryThe statement that is not part of Dalton's atomic theory is that atoms are composed of protons, neutrons, and electrons.
This statement is not part of Dalton's atomic theory because the existence of subatomic particles such as protons, neutrons, and electrons was not discovered until much later, after Dalton's time.
Dalton believed that atoms were indivisible and indestructible particles, and did not have knowledge of the internal structure of atoms. The discovery of subatomic particles and the development of atomic models to explain their behavior came after Dalton's atomic theory was formulated.
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Classify each given species as a strong acid, weak acid, strong base or weak base
KOH, Sr(OH)2, HaPO4, NH3, NaOH, LiOH, HBr, HCl, H2SO4, Ca(OH)2.
Answers
Strong base KOH, Sr(OH)2, NaOH, LiOH, Ca(OH)2. Strong acid HBr, HCl, H2SO4. Weak acid H3PO4. Weak base NH3.
KOH - Strong base: KOH is a strong base because it dissociates completely in water to form hydroxide ions (OH-), which are strong bases.Sr(OH)2 - Strong base: Sr(OH)2 is a strong base because it dissociates completely in water to form hydroxide ions (OH-), which are strong bases.H3PO4 - Weak acid: H3PO4 is a weak acid because it only partially dissociates in water to form hydrogen ions (H+) and phosphate ions (PO4^3-).NH3 - Weak base: NH3 is a weak base because it only partially reacts with water to form hydroxide ions (OH-) and ammonium ions (NH4+).NaOH - Strong base: NaOH is a strong base because it dissociates completely in water to form hydroxide ions (OH-), which are strong bases.LiOH - Strong base: LiOH is a strong base because it dissociates completely in water to form hydroxide ions (OH-), which are strong bases.HBr - Strong acid: HBr is a strong acid because it dissociates completely in water to form hydrogen ions (H+) and bromide ions (Br-).HCl - Strong acid: HCl is a strong acid because it dissociates completely in water to form hydrogen ions (H+) and chloride ions (Cl-).H2SO4 - Strong acid: H2SO4 is a strong acid because it dissociates completely in water to form hydrogen ions (H+) and sulfate ions (SO4^2-).Ca(OH)2 - Strong base: Ca(OH)2 is a strong base because it dissociates completely in water to form hydroxide ions (OH-), which are strong bases.To know more about acid please refer:
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A solution is made by dissolving 38.81 grams of nickel (II) sulfate, NiSO4, in enough water to make 0.467
liters of solution. Calculate the molarity of this solution.
Answers
The molarity of the NiSO₄ solution made by dissolving 38.81 grams of nickel (ii) sulfate, NiSO₄, in enough water to make 0.467 liters of solution is 0.535 M
How do i determine the molarity of the solution?First, we shall obtain the mole of 38.81 grams of nickel (ii) sulfate, NiSO₄. Details below:
Mass of NiSO₄ = 38.81 grams Molar mass of NiSO₄ = 154.75 g/molMole of NiSO₄ = ?Mole of NiSO₄ = mass / molar mass
= 38.81 / 154.75
= 0.25 mole
Now, we shall determine the molarity of the solution. Details below:
Mole of NiSO₄ = 0.25 moleVolume of solution = 10.467 LMolarity of solution = ?Molarity of solution = mole / volume
= 0.25 / 0.467
= 0.535 M
Thus, the molarity of the solution is 0.535 M
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Convert 1020 mm Hg to atm
Answers
Answer:
1.34
Explanation:
Identify which statement about a solution is correct. Group of answer choices The solution has the same physical state as the physical state of the solvent. The solvent is typically the substance present in the lesser amount. Water can only be the solvent, never the solute. The solute is typically the substance present in the greater amount.
Answers
Water can only be the solvent, never the solute is the statement about a solution that is correct.
The solute is the substance that, in general, is found in less quantity and that dissolves in the mixture.The solvent, on the other hand, is the substance that usually appears in greater quantity and where the solute dissolves.The most usual thing is that the solvent is the substance that establishes the physical state of the solution.Water is considered a universal solvent, since it is the liquid that dissolves the most substances, a quality linked to its status as a “polar molecule”, this is due to its ability to form hydrogen bonds with other substances.
Solubility depends on the properties of a solvent that allow it to interact with a solute in a stronger way than the solvent particles do with each other.
In particular, the polar character of water makes it an excellent solvent for polar and ionic solutes, which are called hydrophilic.
Therefore, we can conclude that water can only be the solvent, never the solute is the statement about a solution that is correct.
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What species are most important in chemical bond formation of atoms? A) Valence electrons B) Protons C) Electrons in the inner most shell D) Neutrons
Answers
Answer:
Valence Electrons
Explanation:
Helium is located in group 8A but does not have eight valence electrons. Why is it located in 8A, not 2A?
Answers
Answer:
its outermost shell is completely full making it extremely stable.
Explanation:
It only has two electrons in its outer shell so its valence electron configuration is 1s2. Even though it only has two electrons, it is grouped with elements that have eight valence electrons. Helium is still happy because its outermost shell is completely full making it extremely stable.
1000j of energy is transferred to a kettle. 850j ends up stores In the hot water in the kettle explain how much energy is transferred to the kettle itself and its surroundings?
Answers
Answer: 150 J
Explanation: kettle also warms up and heat is transferred in surroundings. Amount of heat remains same. Then 1000 J -850 J for water = 150 J
A sentence with the word atom
Answers
Answer:
we use atom in our sentences all the time
Explanation:
that what i put
An American visiting Canada puts 41.2 liters of gas in his car. How much is that in gallons? (1 gal = 3.78 L)
Answers
Answer:
41.2/3.78=10.9
(this is rounded off to the first decimal)
Answer:
10.9 gal
Explanation:
Recall that 1gal = 3.78l
if 1gal = 3.78l
then Xgal = 41.2l
cross multiplywe have 1gal*41.2L=Xgal* 3.78L
divide both by 3.78L1gal*41.2L/3.78= Xgal
Xgal = 10.89L or 10.9L
(04.03 hc) what is cellular respiration? use complete sentences to explain how the mass of carbon is conserved during cellular respiration.
Answers
The cellular respiration is the process where the chemical reactions takes place to break down the glucose to produce the ATP.
The reaction of cellular respiration is given as :
C₆H₁₂O₆ + 6 O₂ ---> 6CO₂ + 6 H₂O
The mass of carbon is conserved during cellular respiration. The law of conservation of mass states that the mass is conserved throughout the reaction.
reactant products
C 6 6
O 12 12
H 18 18
The mass of the carbon conserver during the reaction. The reaction is balanced as the number of atoms in the reactant side equals to the product side.
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