Which of the following springs (described by its spring constant) has the shortest period when attached to a 100 g mass?
Answer Choices:
30.0 N/m.
10.0 N/m.
20.0 N/m.
40.0 N/m.

Answer:

(a). The kinetic friction force is 1950 N.

(b). The magnitude of force will be equal of friction force

Explanation:

Given that,

Constant speed = 6.38 m/s

Force \(F=7.50\times10^{3}\ N\)

Kinetic friction = 0.26

(a). We need to calculate the friction force

Using formula of friction force

\(f_{k}=\mu F_{N}\)

Put the value into the formula

\(f_{k}=0.26\times7.50\times10^{3}\)

\(f_{k}=1950\ N\)

(b). If the only other horizontal force exerted on the sleigh is due to the horses pulling the sleigh,

We need to calculate the magnitude of this force

According to given data,

The same force will be applied to keep constant velocity.

Hence, (a). The kinetic friction force is 1950 N.

(b). The magnitude of force will be equal of friction force.

(a). The kinetic friction force is 1950 N.

(b). The magnitude of force will be equal of friction force

a. The magnitude of the kinetic friction force experienced by the sleigh is

\(= 0.76 \times 7.50 \times 10^3\)

= 1950 N

b. It should be equivalent to the friction force.

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Answer:

Gravity

Explanation:

Hope this helps:) Have a good day!!

When the spring is replaced with a spring with double of initial spring constant k2 = 2k₁, the new period, T2, is \(\sqrt{\frac{1}{2} } \ T_1\).

The period of the oscillation of the mass or cart on the spring is given by the following formula;

\(T = 2\pi \sqrt{\frac{m}{k} } \\\\\)

at a costant mass;

\(T_1\sqrt{k_1} = T_2\sqrt{k_2} \\\\T_2 = \frac{T_1\sqrt{k_1} }{\sqrt{k_2} }\)

when spring constant is doubled, k2 = 2k1. the new period, T2 is determined as follows;

\(T_2 = \frac{T_1\sqrt{k_1} }{\sqrt{2k_1} } \\\\T_2 = \frac{T_1\sqrt{k_1} }{\sqrt{2} \times \sqrt{k_1} } \\\\T_2 = \frac{T_1}{\sqrt{2} }\\\\T_2 = \sqrt{\frac{1}{2} } \ T_1\)

Thus, when the spring is replaced with a spring with double of initial spring constant k2 = 2k₁, the new period, T2, is \(\sqrt{\frac{1}{2} } \ T_1\).

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The hiker travelled 4.02 km North/South and 4.74 km East/West during her hike.

This question involves vector addition, the resolution of vectors, the use of bearings, and trigonometry in the calculation of the hiker's movement.

This may appear to be a difficult problem, but with some visual aid and the proper use of mathematical formulas, the issue can be addressed correctly.

Resolution of VectorThe resolution of a vector is the process of dividing it into two or more components.

The angle between the resultant and the given vector is equal to the inverse tangent of the two rectangular components.

Angles will always be expressed in degrees in the solution.

The sine, cosine, and tangent functions in trigonometry are denoted by sin, cos, and tan.

The tangent function can be calculated using the sine and cosine functions as tan x = sin x/cos x. Also, in right-angled triangles, Pythagoras’ theorem is used to find the hypotenuse or one of the legs.

Distance Travelled North/SouthThe hiker traveled North for the first part of the hike and South for the second.

The angles that the hiker traveled in the first part and second parts are 53 degrees and 17 degrees, respectively.

The angle between the two is (180 - 53 - 17) = 110 degrees.

The angle between the resultant and the Northern direction is 110 - 53 = 57 degrees.

Using sine and cosine, we can calculate the north/south distance traveled to be 5 sin 57 = 4.02 km, and the east/west distance to be 5 cos 57 = 2.93 km.

Distance Travelled East/WestThe hiker walked East for the second part of the hike.

To calculate the distance travelled East/West, we must first calculate the component of the first part that was East/West.

The angle between the vector and the Eastern direction is 90 - 53 = 37 degrees.

Using sine and cosine, we can calculate that the distance travelled East/West for the first part of the hike is 5 cos 37 = 3.88 km.

To determine the net distance travelled East/West, we must combine this component with the distance travelled East/West in the second part of the hike.

The angle between the second vector and the Eastern direction is 17 degrees.

Using sine and cosine, we can calculate the distance traveled East/West to be 3 sin 17 = 0.86 km.

The net distance traveled East/West is 3.88 + 0.86 = 4.74 km.

Therefore, the hiker travelled 4.02 km North/South and 4.74 km East/West during her hike.

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Answer:

the magnitude of the electric field intensity is 20 N/C

Explanation:

 Given the data in the question;

mass m = 1 micro gram = 1 × 10⁻⁹ kg

time duration t = 10 sec

distance s = 1 m

the charge on the particle q = 10⁻¹² Coulomb

force applied on a charged particle due to electric field E is;

F = Eq  ------ equ 1

where q is the charge on the particle.

Also, force on a particle with mass m  will be;

F = ma  ------ equ

where a is acceleration

so F = ma = Eq

ma = Eq -------- equ 3

using kinetic equation

Distance = 1/2×at²

where a is acceleration and t is the time period

now lets consider that initial velocity is zero (0)

Here;

1 m = 1/2 × a × ( 10 s )²

1 m = a × 50 s²

a = 1 m / 50 s²

a = 0.02 m/s²

so, from equation 3

ma = Eq

E = ma / q

we substitute

E = (1 × 10⁻⁹ kg × 0.02) / 10⁻¹² Coulomb

E = 2 × 10⁻¹¹ / 10⁻¹²

E = 20 N/C

Therefore, the magnitude of the electric field intensity is 20 N/C

Answer:

The effectiveness of that same country's worldwide weights, as well as Measures Bureau, has always been chosen to give elsewhere here.

Explanation:

Torque is a measure of the turning force applied to an object about a rotational axis. It is calculated as the product of the force applied to the object and the distance from the axis of rotation at which the force is applied.

Use the equation slope = mod to calculate the unknown mass (mo) for parcels A and C, setting d = 1.0 m, and parcels G and H, setting d = 1.5 m.

Record all data, tables, and four graphs for analysis.

The experiment demonstrates the application of torque in determining unknown masses and provides valuable insights into the concept of torque in physics.

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Answer:

The  frequency is  \(F = 325 Hz\)

Explanation:

From the question we are told that

    The frequency for the first note is  \(F_1 = 330 Hz\)

     The  beat frequency of the first note is  \(f_b = 5 \ Hz\)

     The  frequency for the second note is  \(F_2 = 350 \ H_z\)

      The  beat frequency of the first note is \(f_a = 25 \ Hz\)

Generally beat frequency is mathematically represented as

        \(F_{beat} = | F_a - F_b |\)

Where \(F_a \ and \ F_b\) are frequencies of two sound source

  Now in the case of this question

For the first note

     \(f_b = F_1 - F \ \ \ \ \ ...(1)\)

Where  F is the frequency of the string note

For the second note  

      \(f_a = F_2 - F \ \ \ \ \ ...(2)\)

Adding  equation 1 from 2

      \(f_b + f_a = F_1 + F_2 + ( - F) + (-F) )\)

      \(f_b + f_a = F_1 + F_2 -2F\)

substituting values

       \(5 +25 = 330 + 350 -2F\)

=>     \(F = 325 Hz\)

Explanation:

u7ruey737€*hr7j37j27jw7uw7bwydbe7887yeyhduheyheyy755÷÷+5÷÷8€737€=67577

Answer:

Centripetal acceleration must involve a change in a. an object's tangential speed.

Explanation:

Centripetal acceleration must involve a change in direction of motion of the object.

centripetal acceleration is the acceleration of a body traversing a circular path. Because velocity is a vector quantity (that is, it has both a magnitude, the speed, and a direction), when a body travels on a circular path, its direction constantly changes and thus its velocity changes, producing an acceleration. The acceleration is directed radially toward the center of the circle.

In your daily existence, you must have encountered numerous instances of centripetal acceleration. A centripetal acceleration occurs when you drive in a circle, and a centripetal acceleration also occurs when a satellite orbits the earth. Centripetal refers to being in the center.

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The statement which is correct about the lighter dart leaves the spring moving faster than the heavy dart. Option B is correct.

This is because both darts are launched with the same initial elastic potential energy from the compressed springs, but the lighter dart has less mass than the heavier dart. According to the law of conservation of energy, the lighter dart must move faster than the heavier dart in order to have the same amount of kinetic energy as the heavier dart once it leaves the spring.

The initial potential energy is the same for both darts, and since the potential energy is converted to kinetic energy, the lighter dart must have a higher velocity than the heavier dart in order to have the same amount of kinetic energy.

Therefore, option B is correct, while options A, C, D, and E are not, as they do not accurately describe the behavior of the darts in this scenario.

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--The complete question is, A heavy dart and a light dart are launched horizontally on a frictionless table by identical ideal springs. Both springs were initially compressed by the same amount. Which of the following statements about these darts are correct?

A) The darts both have the same kinetic energy just as they move free of the spring.

B) The lighter dart leaves the spring moving faster than the heavy dart.

C) The heavy dart had more initial elastic potential energy than the light dart.

D) Both darts move free of the spring with the same speed. E) Both darts had the same initial elastic potential energy.--

From this data it is clear that the time require to complete ramp 3 is more than any other, hence it can be large ramp or there are more objectless or  turns. Ramp 2 requires least time to complete, it can be shorter or having less number of obstacles.

An inclined plane, also known as a ramp, is a flat supporting surface that is slanted at an angle from the vertical direction, with one end higher than the other, and is used to help raise or reduce a weight. The inclined plane is one of the six traditional basic devices established by Renaissance scientists. Inclined aircraft are used to transport big cargoes over vertical obstructions. Examples include a ramp used to load items into a truck, a person going up a pedestrian ramp, and an automobile or railroad train climbing a gradient. it can have obstacles in the path

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The graph is displayed in the following attachment.

The graph shows that the answers to the problem are x = -1.2 and x = 1.7.

From the image, we may deduce that

The graph is displayed in the following attachment.

The graph shows that the answers to the problem are x = -1.2 and x = 1.7.

We must create the graph of the function for the given range of values based on the image (that is for values of x from -3 to 3)

We will first establish the function's table of values.

Values for the function x y -3 in a table 1.33 -2 2 -1 4 0 Definable

1 -4 2 -2\s3 -1.33

(The docx attachment provides a better view.)

Additionally, the function's graph (purple lines) is

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The airplane will strike the ground at a horizontal distance of 490 meters.

To determine how far the airplane will strike on the ground, we need to consider the horizontal distance traveled by the airplane during its flight.

The horizontal distance traveled by an object can be calculated using the formula:

Distance = Speed × Time

In this case, the speed of the airplane is given as 100 meters per second and the time it takes to cover the distance of 490 meters is unknown. Let's denote the time as t.

Distance = 100 m/s × t

Now, to find the value of time, we can rearrange the equation as follows:

t = Distance / Speed

t = 490 m / 100 m/s

t = 4.9 seconds

Therefore, it takes the airplane 4.9 seconds to cover a horizontal distance of 490 meters.

Now, to calculate the distance on the ground where the airplane will strike, we can use the formula:

Distance = Speed × Time

Distance = 100 m/s × 4.9 s

Distance = 490 meters

It's important to note that this calculation assumes a constant speed and a straight flight path. In reality, various factors such as wind conditions, changes in speed, and maneuvering can affect the actual distance traveled by the airplane.

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It is not recommended to fire a gun straight up into the air.

When a bullet is fired into the air, it will eventually come down and can pose a danger to people and property below. The bullet can still be lethal when it reaches the ground, especially if it lands on a hard surface or hits someone directly.

Additionally, firing a gun in a residential area can be illegal and can result in legal consequences. In general, guns should only be fired in designated shooting ranges or in self-defense situations where there is an immediate threat to life. It is important to handle firearms responsibly and follow all safety guidelines to prevent accidents and injuries.

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The work done on the box from y=0 to 6.0m is 120 J.

To calculate the work done on the box from y=0 to 6.0m, we need to find the area under the force vs. position graph over that interval.

First, we can find the work done from 0 m to 2 m. Since the force is constant at 40 N over this interval, the work done is simply:

W = F * d = 40 N * 2 m = 80 J

From 2 m to 6 m, the force is constant at -20 N, so the work done is:

W = F * d = (-20) N * 4 m = -80 J

Note that the negative sign indicates that the work is done by the box on the force (since the force is in the opposite direction of the displacement).

Therefore, the total work done on the box from y=0 to 6.0m is:

W_total = 80 J - 80 J = 0 J

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Doppler radars work by using radio waves that bounce off objects and thus the object can be tracked.

Doppler radars work by emitting a beam of energy from an antenna known as radio waves. The energy they release when they collide with airborne objects scatters in all directions, with some of it returning directly to the radar.

The quantity of energy returned to the radar increases with object size. We can now perceive raindrops in the atmosphere because of this.

The amount of time it takes for the energy beam to be delivered and returned to the radar also gives us the object's distance.

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Hello!

For this, first let's calculate time of stop:

t = (V - Vi) / a

Replacing:

t = (0 m/s - 18 m/s) / -5,4 m/s^2

Resolving:

t = -18 m/s / -5,4 m/s^2

t = 3,33 s + 0,25 s = 3,58 s

Now lets calculate distance traveled, with formula:

d = Vi*t + (a*t^2)/2

Replacing:

d = 18 m/s * 3,58 s + (-5,4 m/s^2 * (3,58 s)^2) /2

Resolving:

d = 64,44 m + (-34,604 m)

d = 29,83 m

Then, the vehicle will CRASH

Answer:

question, report, observe, research, draw conclusions, hypothesize, test hypothesis, experiment

Explanation:

The potential energy U of an object with mass m located a distance h above the ground is given by the expression:

Where g=9.81m/s^2 is the gravitational acceleration on the surface of Earth.

Since the 2.85kg object is located 12.7 meters below the ground, we can consider h to be negative. Replace m=2.85kg, g=9.81m/s^2 and h=-12.7m to find the potential energy of the object measured from the ground level:

Therefore, the potential energy of the object measured from the ground level is approximately 355J.

I could make a poem for you if you actually gave the words...... what 10 words do i need to incorporate???☹︎

The statement regarding the electric forces on the objects is true: f: ab 5 2f: ba.

As the space between two charged items grows, so do the electric forces between them. With more charge on the objects, there are greater electric forces between the charged things. Each object's charge has a direct impact on electrostatic force. Therefore, if the charge of one object is doubled, the force will increase by two times.

There is either a push or a pull. The effects of forces include moving an object, altering its speed, altering its shape, or changing the volume of a body.

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The average acceleration of the motorcycle over the given distance is approximately 9.39 m/s².

To calculate the average acceleration of the motorcycle, we can use the formula:

Average acceleration = (final velocity - initial velocity) / time

First, let's convert the final velocity from km/h to m/s since the distance is given in meters. We know that 1 km/h is equal to 0.2778 m/s.

Converting the final velocity:

Final velocity = 78 km/h * 0.2778 m/s = 21.67 m/s

Since the motorcycle starts from rest (initial velocity is zero), the formula becomes:

Average acceleration = (21.67 m/s - 0 m/s) / time

To find the time taken to reach this velocity, we need to use the formula for average speed:

Average speed = total distance/time

Rearranging the formula:

time = total distance / average speed

Plugging in the values:

time = 50 m / 21.67 m/s ≈ 2.31 seconds

Now we can calculate the average acceleration:

Average acceleration = (21.67 m/s - 0 m/s) / 2.31 s ≈ 9.39 m/s²

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Answer:

Absolute magnitude

Explanation:

The brightness a star would have if it were at 10 pc from Earth is called Absolute magnitude.

Hi there!

On a level road:

∑F = Ff (Force due to friction)

The net force is the centripetal force, so:

mv²/r = Ff

Rewrite the force due to friction:

mv²/r = μmg

Cancel out the mass:

v²/r = μg

Solve for v:

v = √rμg

v = √(25)(9.81)(0.8) = 14.01 m/s

Answer:

=18 sec

Explanation:

240m=20m/s, find 360m

360×20÷240=30m/s

time=distance÷speed

240÷20=12sec

if 240=12sec,find 360

360×12÷240

=18 sec

Answer:

12,000 grams = 12 kg

Explanation:

Volume V = 20 x 20 x 30 cm³ = 12,000 cm³

density of water d = 1 g/cm³

so the mass is 12,000 grams = 12 kg