Which of the following ratios are not equivalent to 7 : 3?

Multiple choice question.

A)
14 : 3


B)
14 : 6


C)
21 : 9


D)
28 : 12

60% decrease

15 is 60% of 25

What is 60% of 25?

Y is 60% of 25

Equation: Y = P% * X

Solving our equation for Y

Y = P% * X

Y = 60% * 25

Converting percent to decimal:

p = 60%/100 = 0.6

Y = 0.6 * 25

Y = 15

Answer:

It decreased by 71%

Step-by-step explanation:

25 divided by 35

No, {2,3} everything else es equal except for.

Answer:

t ≈ 11.7

Step-by-step explanation:

                  r

A = P (1 + -------)^(n)(t)

                  n

A = 5000

P = 2500

r = 0.06

n = 2

t = ?

                              0.06

5000 = 2500 (1 + ----------)^(2)(t)

                                  2

                              0.06

5000 = 2500 (1 + ----------)^(2)(t)

÷2500 ÷2500           2

             0.06

2 = (1 + ----------)^(2)(t)

                2

            log 2

------------------------ =  2t

             0.06

log (1 + ----------)

                2

            log 2

(1/2) ------------------ = 2t (1/2)

                    0.06

      log (1 + ----------)

                      2

11.72488612 = t

11.7 ≈ t

I hope this helps!

a) Probability that the time headway will be less than 10 seconds is 0.0228.

b) Probability that the time headway will be more than 9 seconds is 0.8737.

c) Probability that the time headway will be between 5 and 8 seconds (inclusive) is 0.2331.

(a) The probability that the time headway will be less than 10 seconds can be found by using the Poisson distribution formula and substituting λ = 3.5 (since the traffic flow is 210 veh/h, which corresponds to an average of 3.5 veh/min). Thus,

(b) The probability that the time headway will be more than 9 seconds is equal to 1 minus the probability that the time headway will be less than or equal to 9 seconds. Thus,

(c) The probability that the time headway will be between 5 and 8 seconds (inclusive) can be found by subtracting the probability that the time headway is less than or equal to 4 seconds from the probability that the time headway is less than or equal to 8 seconds, i.e.,

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This equation is not dependent on the number of months, so there is no solution to the equation. This means that the two gyms will never have the same cost.

In other words, even if you go to the gym for a very long time, the total cost for Gym A will always be $15 less than the total cost for Gym B.

Given that;

Gym A has a one-time membership fee of $45 and costs $18 per month.

And, Gym B has a one-time membership fee of $60 and costs $18 per month.

Let number of months = x

Hence, We can formulate;

The expression for Gym A;

⇒ 45 + 18x

And, The expression for Gym B;

⇒ 60 + 18x

Hence, For find the number of months for which the two gyms have the same cost as;

⇒ 45 + 18x = 60 + 18x

⇒ 45 = 60

Thus, It has no solution,

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The given expression is

First, we change 1/3 for its reciprocal to transform the division into a product.

Then, we multiply the fractions.

At last, we transform the fraction into a mixed fraction.

Yes, the starting position of these players form a perpendicular line.

The area of mathematics that deals with particular angles' functions and how to use those functions in calculations. There are six popular trigonometric functions for an angle. Sine (sin), cosine (cos), tangent (tan), cotangent (cot), secant (sec), and cosecant are their respective names and acronyms (csc).

Given:

Using Trigonometry

sin \(\theta\) = 33.33/100

sin \(\theta\) = 0.3333

\(\theta\) = \(sin^{-1}\) (0.3333)

\(\theta\) = 19.469

cos 19.469 = B/ 100

0.9428 = B/ 100

B= 94.28

tan  \(\theta\) = P/B

tan  \(\theta\) = 94.28/ 33.33

\(\theta\) = 70.5

Using Angle Sum property

< 3= 180 - (70.5 + 19.5)

<3 = 180 - 90

<3 = 90

Hence, they form perpendicular line.

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The number of mole of pure 11C (carbon-11) initially present is 0.2727 mole

The mole of a substance is related to it's mass and molar mass according to the following equation

Mole = mass / molar mass

With the above formula, we can obtain the number of mole of pure 11C. Detail below:

From the question given, the following data were obtained:

Mole = mass / molar mass

Mole = 3 / 11

Mole = 0.2727 mole

Therefore, the number of mole of pure 11C initially present is 0.2727 mole

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However, we need to substitute a with s since that is the value we have calculated. Therefore, we get \(A(s) = (1/4)(5 + sqrt(5))s^2.\) This is the function notation that represents the area of a regular pentagon whose perimeter is 140 cm.

Let's consider that s be the length of a side of the regular pentagon.

The perimeter of the regular pentagon will be 5s. Therefore, we have the equation:5s = 140s = 28 cm

Also,

we have the formula for the area of a regular pentagon as:

\($A=\frac{1}{4}(5 +\sqrt{5})a^{2}$,\)

where a is the length of a side of the pentagon.

In order to represent the area of a regular pentagon whose perimeter is 140 cm, we need to substitute a with s, which we have already calculated.

Therefore, we have:\(A(s) = $\frac{1}{{4}(5 +\sqrt{5})s^{2}}$\)

Now, we have successfully used function notation (with the appropriate functions above) to represent the area of a regular pentagon whose perimeter is 140 cm.

The area of a regular pentagon can be represented using function notation (with the appropriate functions above). The first step is to calculate the length of a side of the regular pentagon by dividing the perimeter by 5, since there are 5 sides in a pentagon.

In this case, we are given that the perimeter is 140 cm, so we get 5s = 140, which simplifies to s = 28 cm. We can now use the formula for the area of a regular pentagon, which is\(A = (1/4)(5 + sqrt(5))a^2\), where a is the length of a side of the pentagon.

However, we need to substitute a with s since that is the value we have calculated. Therefore, we get\(A(s) = (1/4)(5 + sqrt(5))s^2.\) This is the function notation that represents the area of a regular pentagon whose perimeter is 140 cm.

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The lower base will be 18 units.

A trapezoid is a quadrilateral whose one opposite sides are parallel.

The tangent of an angle is the ratio between the opposite side of the angle and the adjacent side of the angle.

\(\tan\theta=\dfrac{\text{opposite side}}{\text{adjacent side}}\)

So according to asked question:

in the trapezoid VWXZ,

\(\text{VW} \ || \ \text{XZ}\)

Height of trapezoid = VZ = WY = \(8\sqrt{3}\)

\(\text{VW}=10\)

\(\angle \text{YWX}=30^\circ\)

\(\angle\text{WXY}=60^\circ\)

In triangle ΔWYX,

\(\angle\text{WYX}=90^\circ\)

ΔWYX is a right angle triangle

So,

\(\tan\angle\text{YWX}= \dfrac{\text{XY}}{\text{WY}}\)

\(\rightarrow \tan30^\circ=\dfrac{\text{XY}}{8\sqrt{3}}\)

\(\rightarrow \dfrac{1}{\sqrt{3}}=\dfrac{\text{XY}}{8\sqrt{3}}\)

\(\rightarrow \text{XY}=\dfrac{8\sqrt{3}}{\sqrt{3}}\)

\(\rightarrow \text{XY}=8 \ \text{units}\)

The length of the lower base: \(\text{ZX}= \text{ZY}+\text{XY} = \text{VW} + \text{XY}= 10+8=\bold{18 \ units}\)

Therefore, the lower base will be 18 units.

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Report on Commonalities Among Three Chosen Regions

For this assignment, three regions of the world have been selected to identify commonalities among them. The chosen regions are North America, Europe, and East Asia. Through internet research, several commonalities have been identified that are shared among these regions. Below are five commonalities found:

Economic Development:

All three regions, North America, Europe, and East Asia, are characterized by significant economic development. They are home to some of the world's largest economies, such as the United States, Germany, China, and Japan. These regions exhibit high levels of industrialization, technological advancement, and trade activities. Their economies contribute significantly to global GDP and are major players in international commerce.

Technological Advancement:

Another commonality among these regions is their emphasis on technological advancement. They are known for their innovation, research and development, and technological infrastructure. Companies and industries in these regions are at the forefront of technological advancements in fields such as information technology, automotive manufacturing, aerospace, pharmaceuticals, and more.

Cultural Diversity:

North America, Europe, and East Asia are culturally diverse regions, with a rich tapestry of different ethnicities, languages, and traditions. Immigration and historical influences have contributed to the diversity seen in these regions. Each region has a unique blend of cultural practices, cuisines, art, music, and literature. This diversity creates vibrant multicultural societies and fosters an environment of cultural exchange and appreciation.

Democratic Governance:

A commonality shared among these regions is the prevalence of democratic governance systems. Many countries within these regions have democratic political systems, where citizens have the right to participate in the political process, elect representatives, and enjoy individual freedoms and rights. The principles of democracy, rule of law, and respect for human rights are important pillars in these regions.

Education and Research Excellence:

North America, Europe, and East Asia are known for their strong education systems and institutions of higher learning. These regions are home to prestigious universities, research centers, and educational initiatives that promote academic excellence. They attract students and scholars from around the world, offering a wide range of educational opportunities and contributing to advancements in various fields of study.

In conclusion, the regions of North America, Europe, and East Asia share several commonalities. These include economic development, technological advancement, cultural diversity, democratic governance, and education and research excellence. Despite their geographical and historical differences, these regions exhibit similar traits that contribute to their global significance and influence.

Answer:

For this assignment, three regions of the world have been selected to identify commonalities among them. The chosen regions are North America, Europe, and East Asia. Through internet research, several commonalities have been identified that are shared among these regions. Below are five commonalities found:

Economic Development:

All three regions, North America, Europe, and East Asia, are characterized by significant economic development. They are home to some of the world's largest economies, such as the United States, Germany, China, and Japan. These regions exhibit high levels of industrialization, technological advancement, and trade activities. Their economies contribute significantly to global GDP and are major players in international commerce.

Technological Advancement:

Another commonality among these regions is their emphasis on technological advancement. They are known for their innovation, research and development, and technological infrastructure. Companies and industries in these regions are at the forefront of technological advancements in fields such as information technology, automotive manufacturing, aerospace, pharmaceuticals, and more.

Cultural Diversity:

North America, Europe, and East Asia are culturally diverse regions, with a rich tapestry of different ethnicities, languages, and traditions. Immigration and historical influences have contributed to the diversity seen in these regions. Each region has a unique blend of cultural practices, cuisines, art, music, and literature. This diversity creates vibrant multicultural societies and fosters an environment of cultural exchange and appreciation.

Democratic Governance:

A commonality shared among these regions is the prevalence of democratic governance systems. Many countries within these regions have democratic political systems, where citizens have the right to participate in the political process, elect representatives, and enjoy individual freedoms and rights. The principles of democracy, rule of law, and respect for human rights are important pillars in these regions.

Education and Research Excellence:

North America, Europe, and East Asia are known for their strong education systems and institutions of higher learning. These regions are home to prestigious universities, research centers, and educational initiatives that promote academic excellence. They attract students and scholars from around the world, offering a wide range of educational opportunities and contributing to advancements in various fields of study.

In conclusion, the regions of North America, Europe, and East Asia share several commonalities. These include economic development, technological advancement, cultural diversity, democratic governance, and education and research excellence. Despite their geographical and historical differences, these regions exhibit similar traits that contribute to their global significance and influence.

Answer:

b = (looks to be) -3.5

m = \(\frac{1}{2}\)

Type of Slope = Positive, linear

Equation = y = \(\frac{1}{2}\)x - 3.5

Answer:

-12; 5

Step-by-step explanation:

x^2 + 7x - 60 = 0

D = b^2 - 4ac

D = 7 * 7 + 60 * 4 * 1 = 289

sqrt(D) = sqrt(289) = 17

x₁ = (-b - √D) / 2a = (-7 - 17) / 2 = -24 / 2 = -12

x₂ = (-b + √D) / 2a = (-7 + 17) / 2 = 10 / 2 = 5

Given parameters:

First point  = (12, -5)

Second point  = (10, -4)

Unknown:

Slope of the line = ?

Slope is simply the vertical rise divided by the horizontal distance.

             Slope  = \(\frac{Rise }{horizontal distance}\)

Simply to find slope;

           Slope  = \(\frac{y_{2} - y_{1} }{x_{2} - x_{1} }\)

First point  = (12, -5), x₁  = 12 and y₁  = -5

Second point  = (10, -4), x₂  = 10 and y₂  = -4

Input the parameters:

       Slope  =  \(\frac{-4 -(-5)}{10 - 12}\)

                  = \(\frac{-4 + 5}{-2}\)

                  = - \(\frac{1}{2}\)

The slope of the line is -\(\frac{1}{2}\)

Using proportions, it is found that the total distance covered by him in 6 days is of 28.5 km.

A proportion is a fraction of a total amount, and the measures are related using a rule of three. Due to this, relations between variables, either direct or inverse proportional, can be built to find the desired measures in the problem.

The daily distance is of 2 x 2.375 km, as 1000 m = 1 km and he walks both ways. Hence, the total distance covered by him in 6 days is given by:

D = 6 x 2 x 2.375 = 28.5 km.

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To determine the cost allocated to the land, we need to calculate the proportionate cost of the land in relation to the total appraised value of the real estate. Therefore, the cost allocated to the land is $32,500.

The total cost paid for the real estate is $310,000 plus $15,000 in closing costs, totaling $325,000. To allocate the cost to the land, we need to calculate the proportion of the land's appraised value to the total appraised value of the real estate.

The total appraised value of the real estate is the sum of the appraised values of the land, building, and land improvements, which amounts to $35,000 + $105,000 + $210,000 = $350,000.

To calculate the cost allocated to the land, we divide the appraised value of the land by the total appraised value of the real estate and multiply it by the total cost paid:

Cost allocated to land = (Appraised value of land / Total appraised value) * Total cost

= ($35,000 / $350,000) * $325,000

= 0.1 * $325,000

= $32,500

Therefore, the cost allocated to the land is $32,500. This allocation is based on the relative appraised value of the land compared to the total appraised value of the real estate.

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Answer:

g(x) = x is the base function.

To shrink it vertically by 1/2, make 1/3 the coefficient of the variable x.

To shift it 4 units to the right, subtract 4 from within the squared variable.

To shift 5 units down, subtract 5 from the entire function.

Step-by-step explanation:

Answer:

78 and 6 tenths

Step-by-step explanation:

Seventy-eight point six

a) The chance of drawing no court cards (J, Q, K, A) in a hand of 13 cards randomly drawn from a pack of 52 is approximately 0.294. b) The chance of drawing at least one ace but no other court cards in a hand of 13 cards is approximately 0.089. c) The chance of drawing at most one kind of court card (J, Q, K, A) in a hand of 13 cards is approximately 0.633.

a) To find the chance of drawing no court cards, we need to determine the number of favorable outcomes and divide it by the total number of possible outcomes. In this case, there are 36 non-court cards (52 cards - 16 court cards), and we want to draw 13 cards without any court cards. The probability can be calculated using the formula:

Probability = (number of favorable outcomes) / (total number of possible outcomes)

The number of favorable outcomes is the number of ways to choose 13 cards from the 36 non-court cards, which can be calculated using combinations. Thus, the probability is:

Probability = C(36, 13) / C(52, 13) ≈ 0.2936

b) To find the chance of drawing at least one ace but no other court cards, we need to determine the number of favorable outcomes and divide it by the total number of possible outcomes. There are 4 aces in the deck, and we want to draw at least one of them along with 12 non-court cards (36 non-court cards - 4 aces).

The probability can be calculated using the formula:

Probability = (number of favorable outcomes) / (total number of possible outcomes)

For drawing two aces, there are C(4, 2) ways to choose two aces and C(36, 11) ways to choose the remaining non-court cards.

Thus, the probability is:

Probability = [C(4, 1) * C(36, 12) + C(4, 2) * C(36, 11)] / C(52, 13) ≈ 0.0892

c) To find the chance of drawing at most one kind of court card, we need to determine the number of favorable outcomes and divide it by the total number of possible outcomes. There are 4 court cards of each kind (J, Q, K, A), and we want to draw at most one kind of court card.

The probability can be calculated using the formula:

Probability = (number of favorable outcomes) / (total number of possible outcomes)

The number of favorable outcomes is the sum of three cases: drawing no court cards, drawing only one kind of court card, and drawing one court card of each kind. We have already calculated the probability of drawing no court cards in part (a).

Thus, the probability is:

Probability = [C(36, 13) + 4 * C(36, 13) + 4 * C(36, 12)] / C

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To find the chances in a hand of 13 cards drawn randomly from a pack of 52, we can use probability. The chance of no court cards can be calculated using combinations. The probability of at least one ace but no other court cards can be found by subtracting the probability of no aces from the probability of no court cards. The probability of at most one kind of court card can be calculated by finding the probability of having zero court cards and one court card.

To find the chances in a hand of 13 cards drawn randomly from a pack of 52, we can use probability.

There are 12 court cards (J, Q, K, A) in a deck of 52 cards. So, to have no court cards in a hand, we need to select all 13 cards from the remaining 40 non-court cards. The probability can be calculated as 40C13/52C13.

To find this probability, we need to subtract the probability of having no aces from the probability of having no court cards. The probability of having no aces is 48C13/52C13, and the probability of having no court cards is 40C13/52C13. The result is the difference between these two probabilities.

To find the probability of having at most one kind of court card, we can calculate the probability of having zero court cards or one court card. The probability of having zero court cards can be calculated as 40C13/52C13, and the probability of having one court card can be calculated as 12C1 * 40C12/52C13. The sum of these two probabilities gives the probability of having at most one kind of court card.

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Answer:

i would imagine the ratio would be 3:4

Step-by-step explanation:

3 liters of red paint compared to 4 liters of blue i believe hope this help :D

Answer: B & D

Step-by-step explanation:

In this scenario we want to come out with a situation where both sides are in an even playing field, as the equation solves to zero.

If a diver is 35 feet below water (-35) and he comes up to breathe, he goes up 35ft (35) meaning he is at the surface (0).

If Manuel is in debt for 35$ (-35) and then he pays off the 35$ (+35) then he is even (at 0).

Answer:

A diver is 35 feet below the surface of the water and then comes up to the surface.

Answer:

I believe the answer is 10

the percent change in the number of cards collected from last month to this month is:

that is equivalent to say:

the percent change in the number of cards collected from last month to this month is 60%

Answer:

x=9

Step-by-step explanation:

1(x)+0=9

Why?

Because the larger the coeffient, the smaller x gets.

1x=9

x=9

2x=9

x=4.5

3x=9

x=3

You wouldn't want to add any number either, but conviniently, whole numbers also include 0

Answer: m=-2/3

Y=-2

Equation=-2/3x-2

Step-by-step explanation:

M is the slope

Y is where it touches that y axis

Put it together

\(625=5^{7x-3}\implies 5^4=5^{7x-3}\implies 4=7x-3 \\\\\\ 7=7x\implies \cfrac{7}{7}=x\implies 1=x\)

The equation to illustrate the information that the number of tickets sold was 4 less than twice the cube of the participants is 2p³ - 4.

An equation is the statement that illustrates that the variables given. In this case, two or more components are taken into consideration to describe the scenario.

From the information, for a fundraiser event, the number of tickets sold was 4 less than twice the cube of the participants.

Let the number of participants be p.

In this case, the tickets will be:

= 2(p³) - 4.

= 2p³ - 4

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The linear equation of the line which passes through the points (-2, -3) and (2, -1) is:

   y + 3 = 0.5 (x + 2)

What is meant by a linear equation?

An equation is said to be linear if the maximum power of the variable is consistently 1. Another name for it is a one-degree equation. A linear equation is a straight line equation.

It is of the form: y = mx + c

where m = slope of the line

c = x-intercept of line.

The linear equation of a line is:

y - y₁ = m ( x - x₁)

Given two points on the line

(x₁ , y₁) = (-2, -3)

(x₂ , y₂) = (2, -1)

m = slope of line =  (y₂ - y₁) / (x₂ - x₁) = (-1 - (-3)) / (2 - (-2)) = 2/4 = 1/2

Now substituting this value in the general equation, we can write the equation as:

y - (-3) = 1/2 ( x -(-2))

y + 3 = 0.5 (x + 2)

Therefore the linear equation of the line which passes through the points (-2, -3) and (2, -1) is:

   y + 3 = 0.5 (x + 2)

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