One equation that describes motion of an object under
certain conditions is
x =
at12
where x is the position of the object with units of
meters, a is the acceleration with units of meters per
second squared, and t is time with units of seconds.
show that the dimensions in the equation are
consistent.
The dimensions in the equation are consistent.
What is equation of motion?
Equation of motion, is a mathematical formula that describes the position, velocity, or acceleration of a body relative to a given frame of reference.
x = at²
where;
x is the position of the object with units of metersa is the acceleration with units of m/s²t is time with units of secondsTo that the dimension is consistent;x (m) = a(m/s²) x t²(s²)
multiple m/s² with s² = m
x(m) = at²(m)
Thus, the dimensions in the equation are consistent.
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find the moment of inertia of a point of mass of 0.005g at a perpendicular distance of 3m from its axis of rotation.
Answer:
Explanation:
Given:
m = 0.005 g = 5·10⁻⁶ kg
R = 3 m
__________
J - ?
J = m·R² = 5·10⁻⁶·3² ≈ 45·10⁻⁶ kg·m²
Answer:
The snapshot of idleness of given point mass still up in the air by,
Where,
- snapshot of idleness
- mass = 0.005 g = ( 0.005/1000 ) = 5 × 10⁻⁶ kg
- opposite distance = 3 m
Put the qualities in the equation,
Hence; the snapshot of idleness of given point mass is 4.5 × 10⁻⁵ kgm².
To find out about snapshot of idleness,
Explanation:
Snapshots of dormancy can be found by adding or coordinating over each 'piece of mass' that makes up an article, increased by the square of the distance of each 'piece of mass' to the hub. In vital structure the snapshot of latency is I=∫r2dm I = ∫ r 2 d m .
For a planar item, the snapshot of idleness about a hub opposite to the plane is the amount of the snapshots of dormancy of two opposite tomahawks through a similar point in the plane of the article. The utility of this hypothesis goes past that of computing snapshots of rigorously planar items.
Picture result for track down the snapshot of idleness of a mark of mass of 0.005g at an opposite distance of 3m from its hub of revolution.
What is snapshot of inactivity of an empty circle about a hub going through its middle ? Arrangement : 'I = (2)/(3) MR^(2)', where 'M' is the mass and 'R' is sweep of the empty circle.
A negative charge is paced in an electric field that points west. What direction is the force on the negative particle?
Answer:
A positive charge placed in an electric field will tend to move in the direction of the electric field lines and a negative charge will tend to move opposite to the direction of the electric field lines.
One way to remember this is that there is one velocity, and so the thumb represents it. There are many field lines, and so the fingers represent them. The force is in the direction you would push with your palm. The force on a negative charge is in exactly the opposite direction to that on a positive charge.
Explanation:
Answer:
The force of the negative particle direction is East.
Newton's Law of Inertia states that ________.
Answer: It states that an object in motion will stay in motion, and an object at rest will stay at rest unless acted upon by an unbalanced force.
Explanation:
hope i helped
Answer: A object that is currently in motion will stay at motion. The law of interia is also known as Newton's first law of motion.
Explanation:
what is the moment of inertia for a disk with mass of 500g and radius of 12 cm rotated about its diameter? group of answer choices
The moment of inertia for a disk with mass of 500g and radius of 12cm rotated about its diameter is 7.2 × 10-³kgm².
How to calculate moment of inertia?Moment of inertia is a measure of a rigid body's resistance to change in its angular velocity around a given axis.
The formula for the moment of inertia is the “sum of the product of mass” of each particle with the “square of its distance from the axis of the rotation”. The formula of Moment of Inertia is expressed as follows:
I = mr²
Where;
I = moment of inertiam = mass r = radiusAccording to this question, a disk with mass of 500g and radius of 12 cm rotated about its diameter. The moment of inertia can be calculated as follows:
I = 0.5kg × 0.12²m
I = 7.2 × 10-³kgm²
Therefore, 7.2 × 10-³kgm² is the moment of inertia of the disk.
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Suppose the object and image distances with respect to the lens are 17 cm and V cm. If the focal
length is 10 cm, determine the image distance
If the object and image distances with respect to the lens are 17 cm and V cm and the focal length is 10 cm, the image distance will be 6.3 cm
1 / f = ( 1 / v ) - ( 1 / u )
f = Focal length
v = Object distance
u = Image distance
f = 10 cm
u = 17 cm
1 / v = ( 1 / 10 ) + ( 1 / 17 )
1 / v = 27 / 170
v = 6.3 cm
Focal length is the distance between the center of the lens and its point of focus. The image distance is the distance between the center of the lens and the image. The object distance is the distance between the center of the lens and the object.
Therefore, the image distance will be 6.3 cm
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starting from rest, a car accelerates to 45 m/s in 1 minute. what is the average acceleration of the car in m/s^2 ?
Answer:
given us,
initial velocity (u)= 45m/s
time(t)= 1 min
final velocity (v)=?
here,
average acceleration = v-u/t
= v- 45/1
v= 45/1
:. v=45m/s
:. the average acceleration of the car in m/s^2 is 45m/s
Explanation:
we can use acceleration formula
explain the working principle of inverter
An inverter is an electrical device that transforms DC (direct current) to AC (alternating current). An inverter's operation is based on the assumption of electronic switching.
An inverter is made up of three major components: a direct current input source, an oscillator, and an output transformer. The oscillator produces a high-frequency alternating current signal, which is subsequently supplied to the output transformer. The output transformer subsequently raises the voltage of the alternating current signal to the required level.
A battery or a DC power supply can be used as the DC input source. The oscillator is commonly a transistor or a collection of transistors that alternately turn on and off the DC input at a high frequency. The output transformer has two or more copper coils, and the ratio of the coils determines the voltage of the output signal.
When the DC input is turned on, the oscillator begins to create the high-frequency alternating current signal, which is then delivered into the output transformer. The transformer amplifies the voltage of the alternating current signal and generates the alternating current output.
This is the working principle of Inverter.
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What is used to measure power
Answer:
Electricity is measured in units of power called Watts,
hope this helps
have a good day :)
Explanation:
emptying a half-full cylindrical tank suppose the water tank in exercise 36 is half full of water. determine the work required to empty the tank by pumping the water to a level 2 m above the top of the tank. answer
The work required to empty the cylindrical tank that is half full of water by pumping the water to a level 2 m above the top of the tank is 19695.61897 J.
To determine the work required to empty the cylindrical tank that is half full of water by pumping the water to a level 2m above the top of the tank, the following steps can be followed:
Find the volume of the water in the tank as follows:
V = (πr²h)/2, where V is the volume of water, r is the radius of the cylindrical tank, and h is the height of water in the tank.
Substituting the values given in the question,
V = (π × (0.8 m)² × 1 m)/2 = 1.00530965 m³
Now find the mass of the water as follows:-
The density of water = 1000 kg/m³
Mass = Density × Volume = 1000 kg/m³ × 1.00530965 m³ = 1005.30965 kg
Next, find the potential energy of the water:-
PE = m*g*h, where m is the mass of the water, g is the acceleration due to gravity, and h is the height of the water above the top of the tank.
Substituting the values given in the question,
PE = 1005.30965 kg × 9.81 m/s² × 2 m = 19695.61897 J
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name 4 element of weather
Answer:
They are temperature, atmospheric pressure, wind, humidity, precipitation, and cloudiness. Together, these components describe the weather at any given time.
how far below the surface of the water does a diver experience a pressure of 2 atmospheres (i.e., a doubling of the ambient atmospheric pressure due to the weight of the overlying water).
The required pressure of 2 atmospheric pressure 2.02 x 105 N/m².
One atmosphere is also equal to the pressure created by the weight of a freshwater column that is approximately 10.3 metres tall (101.325 kPa or 14.7 psi) (33.8 ft). As a result, at a depth of 10.3 metres, a diver encounters pressure of around 2 atmospheres (1 atm of air plus 1 atm of water).
p=density*g*h
2*10^5=1000*10*h
h=20 meters
depth to feel the pressure of 2atm = ρgh
now solving for h
2*1.01 * 105 = 1000 * 10 * h
h = 20.2 m
here the answer is required pressure of 2 atm which is only due to the water on its top so
ρgh = 2atm
2 * 1.01 x 105 N/m2. [1atm = 1.01 x 105 N/m2. ]
= 2.02 x 105 N/m2.
s0 ρgh= 2.02 x 105 N/m2.
(1x10 3 kg/m³) (9.8 m/s²)h=2.02 x 105 N/m².
The required pressure of 2 atmospheric pressure 2.02 x 105 N/m².
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Harrison shows up to every team practice and game ready to help the team improve. Which sportsmanship trait does Harrison show?
Harrison shows the sportsmanship trait of commitment by consistently showing up to every team practice and game, ready to help the team improve. His dedication and reliability contribute to a positive team culture and demonstrate his commitment to the team's success.
Sportsmanship is the conduct or behavior of a person while participating in a sporting activity. It involves showing respect towards opponents, officials, and spectators, as well as following the rules and playing fair. Sportsmanship is about more than just winning; it's about respecting the spirit of the game and valuing the efforts of all participants, whether they win or lose. It requires showing humility in victory and grace in defeat.
Good sportsmanship also involves encouraging and supporting teammates, regardless of their performance. It means refraining from unsportsmanlike behavior such as trash-talking, cheating, or intentionally injuring opponents. Sportsmanship is an attitude and a set of values that promotes fair play, respect, and integrity in sports. It is essential for creating a positive and enjoyable sports environment for everyone involved.
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Answer: Harrison shows the sportsmanship trait of commitment by consistently showing up to every team practice and game, ready to help the team improve. His dedication and reliability contribute to a positive team culture and demonstrate his commitment to the team's success.
Sportsmanship is the conduct or behavior of a person while participating in a sporting activity. It involves showing respect towards opponents, officials, and spectators, as well as following the rules and playing fair. Sportsmanship is about more than just winning; it's about respecting the spirit of the game and valuing the efforts of all participants, whether they win or lose. It requires showing humility in victory and grace in defeat.
Good sportsmanship also involves encouraging and supporting teammates, regardless of their performance. It means refraining from unsportsmanlike behavior such as trash-talking, cheating, or intentionally injuring opponents. Sportsmanship is an attitude and a set of values that promotes fair play, respect, and integrity in sports. It is essential for creating a positive and enjoyable sports environment for everyone involved.
Explanation: NOT MINE!
CREDITS : contexto1028
what is the value of the fermi-dirac distribution for energies less than the fermi energy, if the temperature is t=0k ? express your answer to two significant figures.
The value of the Fermi-Dirac distribution for energies less than the Fermi energy at absolute zero temperature (T=0K) is 1.00.
The Fermi-Dirac distribution function describes the probability of finding an electron in a specific energy state in a Fermi gas. It is given by the equation:
f(E) = 1 / (1 + exp((E - EF) / (kT)))
Where f(E) is the Fermi-Dirac distribution function, E is the energy, EF is the Fermi energy, k is Boltzmann's constant, and T is the temperature.
At absolute zero temperature (T=0K), the exponential term in the equation becomes infinite for energies less than EF, and the distribution function simplifies to:
f(E) = 1 / (1 + ∞) = 1 / ∞ = 0
Therefore, for energies less than the Fermi energy at absolute zero temperature, the value of the Fermi-Dirac distribution function is 0. However, it's important to note that this result assumes ideal conditions and a non-degenerate Fermi gas.
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A 52 kg child is struck in the face by a 0.25 kg dodgeball, as he is standing against a wall. If the child is knocked backward at 4.2 m/s, what is the velocity of the dodgeball? (This answer is going to seem extreme)
The velocity of the dodgeball is 705.6 m/s. This answer may seem extreme, but it is correct based on the assumption that no external forces acted on the system during the collision
What is an impact?Two items collide when they briefly come into contact with one another.
Before the collision, the momentum of the system is:
p_initial = m_child * v_child + m_dodgeball * v_dodgeball
After the collision, the momentum of the system is:
p_final = (m_child + m_dodgeball) * v_final
Since the momentum of the system is conserved, we can equate the two expressions:
m_child * v_child + m_dodgeball * v_dodgeball = (m_child + m_dodgeball) * v_final
0 + 0.25 kg * v_dodgeball = (52 kg + 0.25 kg) * 4.2 m/s\
v_dodgeball = [(52 kg + 0.25 kg) * 4.2 m/s] / 0.25 kg
v_dodgeball = 705.6 m/s
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A golf ball of mass 0.045 kg is hit off the tee at a speed of 34m/s . The golf club was in contact with the ball for 3.50*10^-3s .
Find the impulse imparted to the golf ball.??
Find the average force exerted on the ball by the golf club.??
Express your answer to two significant figures and include the appropriate units.
The average force exerted on the ball by the golf club is 490 N.
Thus, F = p/t = 0.49 * 10³ N = 490 N.
Momentum is a metric for power and how challenging it is to stop an object. Zero momentum applies to any object that is not moving. tremendous, slow-moving objects have tremendous amounts of momentum.
A small, swiftly moving object also possesses a significant momentum. A bowling ball, for instance, has more momentum than a ping-pong ball if their velocities are equal.
This is because bowling balls are larger in mass than ping-pong balls.
Thus, The average force exerted on the ball by the golf club is 490 N.
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Each of the four vertical links has an 8 × 36-mm uniform rectangular cross section, and each of the four pins has a 16-mm diameter. Determine the maximum value of the average normal stress in the links connecting (a) points b and d, (b) points c and
e
The maximum value of the average normal stress in the links connecting (a) points b and d is 101.56MPa and (b) points c and e is -21.7MPa.
Stress refers to the measure of an external force acting over the cross-sectional area of an object and is given as units of force per area: N/m2 (SI) or lb/in2 (US). The SI units are commonly referred to as Pascals (Pa). There are two types of stress experienced by normal stress and shear stress. When a force acts perpendicular to the surface of an object, it exerts a normal stress while when a force acts parallel to the surface of an object, it exerts a shear stress. In order to determine the average normal stress in the links provided, consider the bar ABC as a free body as attached. The moment of a force is the product of the force and the distance from the axis of rotation. Hence,
∑Mc = 0 where Mc is the summation of moment at point C
(0.04)FBD – (0.025 + 0.04)(20x10^3) = 0
(0.04)FBD – 1.3x10^3 = 0
FBD = 32.5x10^3 N (Link BD is in tension)
∑MB = 0 where MB is the summation of moment at point B
-(0.04)FCE – (0.025)(20x10^3) = 0
-(0.04)FCE – 0.5x10^3 = 0
FCE = -12.5x10^3 N (Link CE is in compression)
Net area of one link in tension = (0.008)(0.036-0.016) = 160x10^-6 m^2
Hence for two parallel links A = 320x10^-6 m^2
Net area of one link in compression = (0.008)(0.036) = 288x10^-6 m^2
Hence for two parallel links A = 576x10^-6 m^2
a) σBD = FBD/A = 32.5x10^3/320x10^-6 = 101.56x10^6 = 101.56MPa
b) σCE = FCE/A = -12.5x10^3/576x10^-6 = -21.7x10^6 = -21.7MPa
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65mi/hr South is an example of
Answer:
It's an example of velocity.
It is common for creatures to be able to live in both the spray zone and low-tide zone.
True or False
Hii!!! The correct answer is true. (:
Block A is set on a rough horizontal table and is connected to a horizontal spring that is fixed to a wall, as shown.
Block A is then also connected to hanging block B by a lightweight string that passes over an ideal pulley, as
shown. The friction force exerted on block A by the table is not negligible. The blocks are initially held at rest so
that the spring is not stretched. When the blocks are released, hanging block B moves downward and block A on
the table moves to the right until the system comes again to rest. Let E1 be the mechanical energy of the blocks-
spring system, and let E2 be the mechanical energy of the blocks-spring-Earth system. How do these two energies
change from when the blocks are held at rest to when the blocks come to rest again?
The mechanical energy of the system is sum of the potential and kinetic
energy of the system.
Response:
E1 increases, E2 decreasesMethods by which the the above response is obtainedMechanical energy, M.E. in the block and spring system can be presented as follows;
M.E. = Energy in the spring + Kinetic energy of the blocks + Energy done on friction
Mechanical energy of the block-spring system, E1When the blocks are held at rest;
The mechanical energy in the block-spring system when the blocks are held at rest can be found as follows;
Energy in the spring = 0
Kinetic energy of the blocks = 0
Friction energy = 0
Therefore;
E1 for the block at rest = 0
E1 when the blocks come to rest again
Energy in the spring = \(\mathbf{\frac{1}{2} \cdot k \cdot x^2}\) > 0
Kinetic energy = 0
Energy of friction = 0
Therefore;
The mechanical energy of the block-spring system, E1, increases
The mechanical energy of the block-spring-Earth system, E2When the blocks are held
Energy in the spring = 0
Energy done due to friction = 0
Potential energy of Block B = m·g·h
Kinetic energy of the blocks = 0
When the blocks come to rest again, we have;
Energy in the spring = \(\frac{1}{2} \cdot k \cdot x^2\)
Energy received due to friction = 0
Potential energy of Block B = m·g·(h - y)
Where;
\(m \cdot g \cdot h = \mathbf{m \cdot g \cdot (h - y) + \frac{1}{2} \cdot k \cdot x^2 + Energy \ loss \ due \ to \ friction}\)
Which gives;
\(m\cdot g \cdot h > m \cdot g \cdot (h - y) + \frac{1}{2} \cdot k \cdot x^2\)
The energy in the spring-block-Earth system, E2, when initially held is more than the the energy when the blocks com to rest again.
Therefore, E2 decreases
The correct option is therefore;
E1 increases, E2 decreasesThe possible question options obtained from a similar question posted online are;
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you have a 1.40-m-long copper wire. you want to make an n-turn current loop that generates a 1.40 mt magnetic field at the center when the current is 1.10 a . you must use the entire wire. What will be the diameter of your coil? Express your answer with the appropriate units.
The diameter of your coil is approximately 1.4 mm.
To create an n-turn current loop that generates a 1.40 mT magnetic field at the center with a 1.40 m long copper wire carrying a 1.10 A current, we can use Ampere's Law.
According to Ampere's Law, B = μ₀ * n * I, where B is the magnetic field, μ₀ is the permeability of free space (4π × 10⁻⁷ Tm/A), n is the number of turns, and I is the current
Rearranging, we get n = B / (μ₀ * I). Plugging in values, n = 1.40 × 10⁻³ T / (4π × 10⁻⁷ Tm/A * 1.10 A) ≈ 318 turns.
Since we must use the entire wire, the circumference of the coil equals the wire length divided by the number of turns: C = 1.40 m / 318 ≈ 0.0044 m.
The diameter of the coil is given by D = C / π, resulting in D ≈ 0.0014 m or 1.4 mm.
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The diameter of your coil is approximately 1.4 mm.
To create an n-turn current loop that generates a 1.40 mT magnetic field at the center with a 1.40 m long copper wire carrying
a 1.10 A current, we can use Ampere's Law.
According to Ampere's Law, B = μ₀ * n * I,
where B is the magnetic field, μ₀ is the permeability of free space (4π × 10⁻⁷ Tm/A),
n is the number of turns, and I is the current
Rearranging, we get n = B / (μ₀ * I).
Plugging in values, n = 1.40 × 10⁻³ T / (4π × 10⁻⁷ Tm/A * 1.10 A) ≈ 318 turns.
Since we must use the entire wire, the circumference of the coil equals the wire length divided by the number of turns: C = 1.40 m / 318 ≈ 0.0044 m.
The diameter of the coil is given by D = C / π, resulting in D ≈ 0.0014 m or 1.4 mm.
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Can someone help me? Put them in order. Thank you!
Answer:
2-3-1-4
Explanation:
First you will need an energy source so 2 is the first step.
Then the lead and lead oxide are reformed during re-charge so 3 is the second step.
The battery is back in operation when Lead dissolves in acid so 1 is the third step.
Battery produces electrons so 4 is the final step.
a proton, moving east, enters a magnetic field of a certain strength. because of this field the proton curves downward. what is the direction of the magnetic field?
Answer:
F = q V X B
Using the right hand rule (right hand screw) turn V into B to get direction of force which in this case is down
If V is east and F is down then one can see that B must be directed towards the south - turn V into B (south) and F will be directed downwards.
suppose you had a beam that is 1.51.5m in length and you place a fulcrum .25.25m from the left end of the beam (assume the beam is massless). you have a block of mass 77kg and you place it .3.3m from the right end of the beam. what is the torque on the beam?
The torque on the beam calculated from the principle of moments is 68 N to the right.
What is the torque on the beam?The torque on the beam is calculated using the principle of moments.
The principle of moments states that the sum of the clockwise moments is equal to the sum of the anticlockwise moments about a fixed point for a system in equilibrium.
Moment = force * perpendicular distance from the fulcrum
Taking the left end of the beam as the anticlockwise direction ad the right end of the beam as the clockwise direction:
Anticlockwise moment = F * (0.75 - 0.25)
Where F is the balancing force
Anticlockwise moment = 0.5f
Clockwise moment = (0.77 * 9.8) * (0.75 - 0.3)
Clockwise moment = 34 J
0.5 F = 34
F = 68 N
Hence, torque is 68 N
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You are working with an existing fiber optic installation in your building. you want to know the length of each cable that runs through the walls.which tool should you use
Answer:
you will use the OTDR tool ti will very much so help
Explanation:
Which of the following changes will increase current?
OA. Decreasing power
OB. Increasing volume
OC. Increasing resistance
OD. Increasing voltage
Whaf can be the most dangerous part of a hurricane?
Answer:
The inside of a hurricane
Explanation:
You will die
A chemistry reference book lists the radius of the hydrogen atom as 1 angstrom. Will the electron ever be further away than 1 angstrom from the nucleus? Explain.
Yes, the electron can be further away than 1 angstrom from the nucleus in a hydrogen atom. In quantum mechanics, the electron's position is described by a probability distribution, allowing for occasional excursions beyond the average radius.
The radius of 1 angstrom represents an estimate of the average distance between the electron and the nucleus in the ground state of a hydrogen atom. However, in quantum mechanics, the electron's position is described by a probability distribution rather than a fixed orbit.
This means that there is a non-zero probability of finding the electron at distances greater than 1 angstrom from the nucleus, although the probability decreases as the distance increases. Therefore, while the average distance may be 1 angstrom, the electron can occasionally be found further away from the nucleus.
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Karla, Matthew, Daneisha, Vince, and Sergio all have carts of different masses. In their lab, they each
apply a different amount of force to the carts, resulting in different accelerations. However, they did
not label their data table and are now trying to backtrack and identify all of their data.
Your task: using the clues below and your understanding of Newton's 2nd Law of Motion, help
each student determine the mass of their cart, the acceleration of their cart, and the force
they each gave to their cart.
What the students know: the carts had masses of 6kg, 4.5 kg, 9kg, 10 kg, and 12 kg and accelerations
of 5 m/s², 3 m/s², 2 m/s², 4 m/s², and 2.5 m/s².
Clues:
1. Karla's cart is half the mass of Daneisha's.
2. Vince's cart's mass is neither the smallest nor the largest.
3. The mass of Sergio's cart is greater than Vince's.
4. Daneisha's acceleration was half of Sergio's
5. The force Vince applied to his cart was larger than Matthew's.
6. Matthew's acceleration was greater than Vince's.
7. Karla applied less than 18 N of force.
8. Sergio applied more than 40 N of force.
9. Daneisha's force was greater than 27 N.
10. Vince's acceleration was greater than Daneisha's.
11. Karla had less acceleration than Vince.
12. Karla applies the least amount of force.
13. Vince's cart had twice the mass of Matthew's.
The mass of Karla's cart by Newton's second law on applying force will be 12 kg.
What does Newton's second law mean?A detailed explanation of how a force can alter a body's motion is given by Newton's second law. According to this, a body's momentum changes at a rate that is equal to the force acting on it over time in both magnitude and direction.
We know that according to Newton's second law force=mass×acceleration
Now the force needed to push Danielle's cart is 15N.
So, Danielle's car mass is-
In light of the fact that Karla's cart is twice as heavy as Danielle's, Karla's cart's mass can be calculated by multiplying 6 by 2.
So, the mass of Karla's cart is =2×6=12kg.
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There is a bell at the top of a tower that is 40m high. The bell weighs 12kg. The bell has ___________________ energy. Calculate it.
Answer:
Potential
Explanation:
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