Which of the following locations will be relatively warmer during summers, and why? A. An inland location, because water heats up faster than land.
B. A coastal location, because water heats up faster than land.
C. A coastal location, because water has higher specific heat than land.
D. An inland location, because land has lower specific heat than water.​

Answer:

50\(\sqrt{3}\)

Explanation:

As the force makes an angle 60 degree with y axis , the horizontal component (along x axis) will be 100sin(60) = 50\(\sqrt{3}\)

Answer:

AB=0.79

Explanation:

hope this helped

The most denser among the given materials is gold and the least dense one is helium. The order of density from least to most dense is helium, carbon dioxide, water, lead and gold.

Density of a substance is the measure of its mass per unit volume. It describes how  closely packed its particles. density depends on the bond type, temperature and pressure.

The density of helium is very low and it is the lightest element after hydrogen. It density is about 0.00017 g/ml. Density of carbon dioxide is 0.0019 g/ml and the density of water is 1 g/ml.

Gold is a denser metal and its density is about 19.3 g/ml and that of lead is 11.3 g/ml. Hence, the order of density from least to most dense is He < carbon dioxide< water< lead < gold.

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Answer:

₮₣ ₮₣ ₮₣ ₮₣ ₮₣ ₮₣ ₣5₣ đ₮ɽ ₮₣ ₮ɽ

Answer:

75%

\(\dfrac{A}{\sqrt{2}}\)

Explanation:

x = Displacement of spring = \(\dfrac{1}{2}A=\dfrac{A}{2}\)

k = Spring constant

Total energy of the spring is

\(E=\dfrac{1}{2}kA^2\)

Elastic potential energy is given by

\(U=\dfrac{1}{2}kx^2\\\Rightarrow U=\dfrac{1}{2}k(\dfrac{A}{2})^2\\\Rightarrow U=\dfrac{1}{2}k\dfrac{A^2}{4}\\\Rightarrow U=\dfrac{1}{4}\times \dfrac{1}{2}kA^2\\\Rightarrow U=\dfrac{1}{4}E\)

Total energy is given by

\(E=U+K\\\Rightarrow K=E-U\\\Rightarrow K=E-\dfrac{1}{4}E\\\Rightarrow K=\dfrac{3}{4}E\\\Rightarrow \dfrac{K}{E}=0.75\)

The percentage will be

\(\dfrac{K}{E}=0.75\times 100\%\\\Rightarrow \dfrac{K}{E}=75\%\)

The required percentage is 75%

According to the given condition

\(\dfrac{E}{2}=\dfrac{1}{2}kx^2\\\Rightarrow \dfrac{\dfrac{1}{2}kA^2}{2}=\dfrac{1}{2}kx^2\\\Rightarrow \dfrac{1}{2}kA^2=kx^2\\\Rightarrow x=\sqrt{\dfrac{1}{2}A^2}\\\Rightarrow x=\dfrac{A}{\sqrt{2}}\)

So, the energy is half when displacement is \(\dfrac{A}{\sqrt{2}}\)

Let x be the displacement of spring which is given to be  \(\frac{1}{2} A=\frac{A}{2}\)

k= spring constant

Total energy of the spring is:

\(E=\frac{1}{2} kA^2\)

Elastic potential energy is given as:

\(U=\frac{1}{2} kx^2\)

Now on substituting the value of x in above equation:

\(U=\frac{1}{2} k\frac{A^2}{4}\)

It can also be written as:

\(U=\frac{1}{4} *\frac{1}{2} kA^2 \\\\U=\frac{1}{4} E\)    (∵\(E=\frac{1}{2} kA^2\))

Total energy can be written as:

E=U+K

⇒K=E-U

⇒K=E-1/4 E

⇒K=3/4 E

⇒\(\frac{K}{E} =0.75\)

(i) Now, we need to calculate the percentage of kinetic energy:

\(\frac{K}{E} =0.75*100=75\%\)

The percentage of kinetic energy is 75%.

(ii) In second it is asked at what displacement, as a fraction of A, is the energy half kinetic and half potential?

∴\(\frac{E}{2} =\frac{1}{2} kx^2\)

On substituting the value of E in above equation we will get:

\(x=\sqrt{\frac{1}{2} A^2} \\\\x=\frac{A}{\sqrt{2} }\)

So, the energy is half when displacement is \(\frac{A}{\sqrt{2} }\) .

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25  m/s² is the object's acceleration

m1a1=m2a2

m1=5kg

m2=3 kg

a1= 15 m/s²

a2=?

m1a1=m2a2

a2=m1a1/m2

a2=5×15÷3

a2= 25  m/s²

Acceleration is a vector variable that describes the rate at which an object changes its velocity.

An object is said to be accelerating if its velocity is changing. Occasionally, a moving object can change its velocity by the same amount each second. a moving object whose speed fluctuates by 10 m/s every second. This is referred to as a constant acceleration since the velocity is changing by a fixed amount each second.

The difference between an object with a constant acceleration and one with a constant velocity must be understood. Do not be fooled! If an object's velocity changes, whether it does so by a constant amount or a variable amount, then it is accelerating. Furthermore, something that is travelling at a steady speed is not accelerating.

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Answer:

1.08 ×10^9 N attraction

Explanation:

By employing Columbs law of force between charge .the force is defined as;

F = KQ1Q2/ r2

= 9×10^9 ×80×40×(6×10^-6) / 0.4 ^2

= 1.08 ×10^9 N

K = 9×10^9 N m2/C2

((v² ÷ 2g) + LSinα) ÷ (Sinβ + µcosβ) is the distance that the truck moves up the ramp before coming to a halt.

Let the distance the truck moves up the ramp be by x.

The kinetic energy of the truck on an icy road is given by,

K1 = (1÷2)mv²

The potential energy of the truck on an icy road is given by,

U1 = mgLSinα

The kinetic energy of the truck on the tuck ramp is given by,

K2 = 0

The potential Energy of the truck-on-truck ramp is given by,

U2 = mgxSinβ

Work done is given by,

W(others) = -µ×mg×cosФ

Hence, by using the work-energy theorem,

W(others) = (K2 + U2)(K1 + U1)

Therefore, by putting the values we get,

((1÷2)mv² + mgLSinα)(0 + mgxSinβ) = -µ×mg×cosФ

x = (K1 + mgLSinα) ÷ (mg(Sinβ + µcosβ))

x = ((v² ÷ 2g) + LSinα) ÷ (Sinβ + µcosβ)

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Answer:

Speed of Sound = 2D

Time

Where D is the depth of water

2D = Speed × Time

2D = 1450m/s × 0.6s

D = 1450m/s × 0.6s

D

Depth D = 870m

Answer:

1.4 * 10 ^-1 Ω

Explanation:

Hi,

For this question, we gotta use the formula

R = pL/A

p = The resistivity of your material at 20°C

L = length of the wire

A = cross-sectional area

The resistivity of tungsten is 5.60 * 10^-8 at 20°C

By plugging the values, we get:

R = (5.60 * 10^-8)(2.0)/(7.9*10^-7) = 1.4 * 10 ^-1 Ω

Answer:

what does the outer part of the disk turn into

Explanation:

4) it gets sucked into the star

C) a bicyclist riding up a steep hill

The metaphor for a system with rising gravitational potential energy is "a bicyclist riding up a steep hill." Let's get into greater detail:

A cyclist faces resistance from gravity as they ride up a steep slope. The cyclist's elevation, or height above the ground, rises as they cycle and climb uphill. Gravity is pulling the cyclist down the hill by exerting downward force. The cyclist must apply force to the pedals in order to move forward and overcome the pull of gravity. In order to do this, the bicyclist must transform chemical energy from their body into mechanical energy. The distance of the cyclist from the centre of the Earth grows as they ride up the hill. The height and mass of an object affect its gravitational potential energy. In this scenario, as the bicyclist's height rises, their gravitational potential energy also rises.

     Due to the higher elevation, the energy input from the biker is stored as increased potential energy. When the bicycle descends the hill or does work, this potential energy can be transformed back into kinetic energy or other types of energy.

Answer:

I think it is O only nonliving

The bike is travelling at 22.5 m/s after 2.5 s

This is defined as the rate of change of velocity which time. It is expressed as

a = (v – u) / t

Where

a = (v – u) / t

a = (15 – 0) / 5

a = 3 m/s²

a = (v – u) / t

3 = (v – 15) / 2.5

Cross multiply

v – 15 = 3 × 2.5

v – 15 = 7.5

Collect like terms

v = 7.5 + 15

v = 22.5 m/s

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Answer:

100kg

Explanation:

100kg=100kg

:P

Answer: 50 because thats the mass weight

Explanation: Its the obviouse answer.

Explanation:

Her cells will not work well when they have low levels of oxygen.

If the dog walked at a constant speed the whole way, the graph of the dog's position versus time would be a straight line. This is because the dog's velocity (which is the derivative of position with respect to time) would be constant, and the acceleration (which is the derivative of velocity with respect to time) would be zero.

A straight line on a position-time graph indicates that the object is moving at a constant velocity. The slope of the line would be equal to the velocity of the dog.

If the graph is a horizontal line, it would indicate that the dog is at rest. If the line slopes upward, the dog is moving in the positive direction (for example, to the right in a position-time graph), and if the line slopes downward, the dog is moving in the negative direction.

In all, A constant speed means a constant velocity and the line is a straight line with a particular slope.

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(a) A 1 000 kg car is pulling a 300 kg trailer, together the car and trailer move forward with an acceleration of 2. 15 m/s² the net force acting on the car (and trailer) is approximately 2,795 Newtons (N).

To determine the net force on the car, we can use Newton's second law of motion, which states that the net force acting on an object is equal to the product of its mass and acceleration.

The total mass of the car and trailer combined is the sum of their individual masses: 1,000 kg + 300 kg = 1,300 kg.

The acceleration of the car and trailer system is given as 2.15 m/s².

Using Newton's second law:

Net force = mass × acceleration

Net force = 1,300 kg × 2.15 m/s²

Net force ≈ 2,795 N

Therefore, the net force acting on the car (and trailer) is approximately 2,795 Newtons (N).

This net force is responsible for accelerating the combined mass of the car and trailer in the forward direction. It represents the sum of all external forces acting on the system, such as the force exerted by the car's engine and the tension in the connection between the car and trailer.

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Considering the Coulomb's Law, the force between the two ballons is 9.216×10⁻⁸ N.

Charged bodies experience a force of attraction or repulsion on approach.

From Coulomb's Law it is possible to predict what the electrostatic force of attraction or repulsion between two particles will be according to their electric charge and the distance between them.

From Coulomb's Law, the electric force with which two point charges at rest attract or repel each other is directly proportional to the product of the magnitude of both charges and inversely proportional to the square of the distance that separates them:

\(F=k\frac{Qq}{d^{2} }\)

where:

The force is attractive if the charges are of opposite sign and repulsive if they are of the same sign.

In this case, you know that two balloons have a negative charge of 1.6×10⁻¹⁰ C and the balloons are 0.05 m apart.

Replacing in the Coulomb's Law, you get:

\(F=9x10^{9} \frac{Nm^{2} }{C^{2} } \frac{(-1.6x10^{-10} C)x(-1.6x10^{-10} C)}{(0.05 m)^{2} }\)

Solving:

\(F=9x10^{9} \frac{Nm^{2} }{C^{2} } \frac{2.56x10^{-20} C^{2} }{(0.05 m)^{2} }\)

\(F=9x10^{9} \frac{Nm^{2} }{C^{2} } 1.024x10^{-17}\frac{ C^{2} }{m^{2} }\)

F= 9.216×10⁻⁸ N

Finally, the force between the two ballons is 9.216×10⁻⁸ N.

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Answer:

22/25 m/s^

Explanation:

The magnitude of the acceleration of the 20 kg box as it moves to the right is 7.84 m/s².

In this system, the force of gravity acts on both boxes, but the tension in the rope is the same on both sides of the pulley, so it cancels out. The frictional force acts only on the 20 kg box, opposing its motion to the right.

To find the acceleration of the 20 kg box, we need to use Newton's second law of motion, which states that the net force acting on an object is equal to its mass times its acceleration:

Net force = mass x acceleration

The net force on the 20 kg box is the force of gravity pulling it down minus the force of friction opposing its motion to the right:

net force = (20 kg)(9.8 m/s²) - (0.14)(20 kg)(9.8 m/s²) = 156.8 N

The net force on the 5 kg box is the force of gravity pulling it down plus the tension in the rope pulling it up:

Net force = (5 kg)(9.8 m/s²) + T

Since the tension is the same on both sides of the pulley, we can set these two equations equal to each other and solve for the tension:

T = (20 kg)(9.8 m/s²) - (0.14)(20 kg)(9.8 m/s²) - (5 kg)(9.8 m/s²) = 93.68 N

Now we can use the net force on the 20 kg box to find its acceleration:

Net force = (20 kg) x acceleration

156.8 N = (20 kg) x acceleration

Acceleration = 7.84 m/s²

Therefore, the magnitude of the acceleration of the 20 kg box as it moves to the right is 7.84 m/s².

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Answer:

The ability to do work

Explanation:

Energy can be defined as the ability to do work. We apply energy in basically everything we do in life, energy is needed to walk or move from one position to another, it is required to eat and do other basic things of life. The body system converts the food that is being consumed into energy, this energy can be switched from one form to another.

There are various forms of energy which include solar energy , wind energy, electrical energy, mechanical energy, kinetic energy, potential energy etc. This forms of energy can be converted from one form to anothe but cannot be destroyed.

Answer:

ability to work

Explanation:

The value of spring constant (k) is 25 N/m.

Conservation of energy, potential energy of a stretched spring, gravitational potential energy, frequency of oscillation in a spring coupled to a mass, and variation of acceleration due to gravity with altitude are the principles necessary to answer the given problem.

To begin, use energy conservation to equal change in gravitational potential energy on mass attached to spring and elastic potential energy of stretched spring. Then, in the equation, substitute the specified numbers and solve for the spring constant. Then, calculate the amplitude by taking half of the value of spring stretching from equilibrium, and the frequency of oscillation by using the calculation for frequency of oscillation in a stretched string in terms of mass and spring constant.

Formula apply

U=mgh

U=1/2kx^2

putting the value of K ,x ,mass and g then

k is 25N/m

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Answer:

Explanation:

time to travel first leg

D = Vt₁

t₁ = D/V

time to travel second leg.

at constant deceleration, the average velocity will be half of the original.

2D = (V/2)t₂

t₂ = 4D/V

t = t₁ + t₂ = 5D/V

Vavg = d/t = (D + 2D)/(5D/V) = (3D/5D)V = 0.6V

With the concept of kinematics we find the average speed is 0.6V

given parameters

   * initial velocity V

   * the distances in each part of the movements x₁ = D and x₂ = 2D

to find

  The average speed of the entire trajectory

In kinematics we analyze the motion of bodies, the average velocity is defined by

        \(V_{avg} = \frac{\Delta x}{\Delta t}\)           1

where \(V_{avg}\) is the average velocity, Δx and Δt are the variation of displacement and time in the interval

For this exercise we have two types of movement in the first part a uniform movement and in the second part an accelerated movement  let's solve each onaccelerated movement,e separately

1 Part. uniform motion

we look for the time

          V = \(\frac{x_1}{t_1}\)

          t₁ = x₁ / V

          t₁ = \(\frac{D}{V}\)

2 Part. Accelerated movement, let's start by looking for acceleration, they tell us that the body stops at the end of the interval so its velocity is zero v_f=0, the initial velocity is v₀ = V

           \(v_f^2 = v_o^2 - 2 \ a \ x_2\)

           0 = v₀² - 2 a x₂

           a = \(\frac{v_o^2}{2x_2}\)

we substitute

           a = \(\frac{V^2}{D}\)

now we look for the time it takes to stop

          v = v₀ - a t₂

          0 = v₀ - a t₂

          t₂ = \(\frac{v_o}{a}\)

we substitute

          t₂ = \(\frac{V}{\frac{V^2}{4D} }\)

          t₂ = \(\frac{4D}{V}\)4D / V

for the entire movement, the total displacement is

          Δx = x₁ + x₂

          Δx = D + 2D

          Δx = 3D

the total time is  

          Δt = t₁ + t₂

          Δt = \(\frac{D}{V} + \frac{4D}{V}\)

          Δt = \(\frac{5D}{V}\)

we substitute in equation 1 of average velocity

         \(V_{avg} = \frac{3D}{\frac{5D}{V} }\)

         \(V_{avg} = \frac{3}{5} \ V\)

         \(V_{avg } = 0.6 V\)

With the use of the kinematics equations with constant acceleration we can find the average velocity of the body throughout the journey is 0.6V

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Yes, black holes 100% exist. They suck everything in their paths through a process known as spaghettification.

The power required from a 75-kg patient when the treadmill is sloping at required speed is 131.58 W.

The parallel force on the patient is calculated as follows;

F = mg sinθ

F = (75 x 9.8) x sin(12)

F = 152.82 N

P = FV

where;

F = 152.82 x 0.861

F = 131.58 W

Thus, the power required from a 75-kg patient when the treadmill is sloping at required speed is 131.58 W.

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It is false that if one pound of force acts through a distance of two feet, one foot-pound of work is done.

Work is a measure of energy expended in moving an object. It is most commonly calculated by multiplying the force by distance.

It is said that no work is done if the object does not move.

According to this question, if one pound of force acts through a distance of two feet, a work of one pound-two feet is done.

It is therefore, false that if one pound of force acts through a distance of two feet, one foot-pound of work is done.

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Answer:

0.01j

Explanation:

the energy equals the work done by the bulb.

Workdone=

\(workdone = \frac{power}{time} \)

power=voltage×current

=9×0.2

=1.8 W.

THEREFORE,

time=3×60

= 180s

workdone=1.8/180

=0.01 j

We are given two points on the distance-time graph: (1, 40) and (3,130)

This means that:

At time 1 hour, the distance traveled was 40 km

At time 3 hours, the distance traveled was 130 km

We want to find the average speed during this 2 hour interval (from 1 hour to 3 hours).

Average speed is defined as:

Average Speed = Change in Distance / Change in Time

The change in distance is the distance traveled from 1 hour to 3 hours, which is 130 km - 40 km = 90 km

The change in time is 3 hours - 1 hour = 2 hours

Average Speed = 90 km / 2 hours

= 45 km/hr

Therefore, the average speed during this interval of time is 45 km/hr.