Which of the following is true for the equilibrium constant of a reaction? (5 points)Select one:a.It is a ratio of coefficients of reactants to products. Incorrectb.It has a different value at different temperatures.c.It is represented by the symbol H.d.Its value is always less than 1.

..........volume..........

Answer:

another answer would be Pressure and Volume, dependeing on the question you get

Explanation: godly

Answer:

The correct answer is 3.675 moles.

Explanation:

Based on the question, the reaction taking place is,  

Tl₂(O₂)₃ ⇒ 2Tl⁺³ + 3O₂⁻²

Thus, 1 mole of thallium peroxide comprise 2 moles of thallium and 3 moles of peroxide ions.  

However, based on the given question, a sample of thallium peroxide comprise 2.45 moles of thallium ions. The moles of peroxide ions present in the sample will be,  

= 2.45 × 3 / 2

= 3.675 moles.  

Hence, the moles of peroxide ions present in the given sample is 3.675.  

Answer:

if the temperature increases to 44°C, the pressure exerted on the damaged lungs would be approximately 1.334 atm.

Explanation:

To determine the pressure being exerted on the damaged lungs, we can use the combined gas law, which states that the pressure of a gas is inversely proportional to its volume when temperature and amount of gas remain constant.

The combined gas law equation is: P₁V₁/T₁ = P₂V₂/T₂

Where:

P₁ = Initial pressure (1 atm)

V₁ = Initial volume (6 L)

T₁ = Initial temperature (32°C + 273.15 = 305.15 K)

P₂ = Final pressure (unknown)

V₂ = Final volume (4.5 L)

T₂ = Final temperature (44°C + 273.15 = 317.15 K)

Rearranging the equation to solve for P₂, we have:

P₂ = (P₁V₁T₂) / (V₂T₁)

Substituting the values:

P₂ = (1 atm * 6 L * 317.15 K) / (4.5 L * 305.15 K)

Calculating this expression gives us:

P₂ ≈ 1.334 atm

A solid substance formed from a solution is a(n).

D. Precipitate

A solid substance formed from a solution is a(n)

a. reactant

b. equation

C. compound

d. precipitate

D. Precipitate

Answer:

Aluminium

Explanation:

From the question given above, the following data were obtained:

Diameter (d) = 1.25 cm

Height (h) = 6.48 cm

Volume (V) of cylindrical=.?

Mass (m) of cylindrical object = 21.535 g

Density of the cylindrical object =..?

Next, we shall determine the radius of the cylindrical object. This is illustrated below:

Diameter (d) = 1.25 cm

Radius (r) =?

r = d/2

r = 1.25/2

Radius (r) = 0.625 cm

Next, we shall determine the volume of the cylindrical object. This can be obtained as follow:

Height (h) = 6.48 cm

Radius (r) = 0.625 cm

Pi (π) = 3.14

Volume (V) of cylindrical=.?

V = πr²h

V = 3.14 × 0.625² × 6.48

V = 7.948 cm³

Recall:

1 cm³ = 1 mL

Therefore

7.948 cm³ = 7.948 mL

Thus, the volume of the cylindrical object is 7.948 mL

Finally, we shall determine the metal in which the cylindrical object is made up of by calculating the density of the cylindrical object. This can be obtained as follow:

Mass (m) of cylindrical object = 21.535 g

Volume of the cylindrical object = 7.948 mL

Density of cylindrical object =?

Density = mass /volume

Density = 21.535 / 7.948

Density of cylindrical object = 2.7 g/mL

Comparing the density of the cylindrical object (i.e 2.7 g/mL) with those given in the table in the question, the cylindrical object is made of aluminium since they have the same density.

Reaching the equivalent point requires the same amount of sodium hydroxide.

When the volume of analyte is equal to the concentration of titrant administered, this occurs. With 12.3 mL of 0.2 molL-1 HCl, 30 mL of NaOH are neutralized.

When just enough titrant is injected to completely neutralize the analyte solution during titration, this is known as the equivalence point. Molecules of base equal molecular weights of acid at the equivalence point in an acid-base titration, and the solution is made up entirely of salt and water.

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The amount of nitrogen-13 sample that remained after 60 minutes has been 25mg.

Half-life can be described as the time required by the substance to reduce half of its initial concentration.

The half-life of Nitrogen-13 has been 20 minutes. In 20 minutes, the sample will be reduced to half of its concentration,

The total time has been 60 minutes.

The number of half-life experienced by the sample has:

Number of half life= Total time/half life

Number of half life cycles= 60/20=3

The number of half-life cycles = 3

The sample has been reduced to 50% in the first half-life cycle and reduced to 25% by the end of 2nd half-life cycle.

The sample remained = 25% of the initial concentration.

The sample remained =  25/100.100 mg

The sample remained = 25 mg

Therefore, the amount of nitrogen-13 sample that remained after 60 minutes has been 25mg.

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The degree of association of AlCl3 into Al2Cl6 is 0.663. The degree of association of AlCl3 into Al2Cl6 can be determined using the ideal gas law and the van't Hoff factor.

Firstly, we need to calculate the number of moles of AlCl3 present in the vessel using the formula n = m/M, where m is the mass of AlCl3 and M is the molar mass of AlCl3.

n = 10.32g / 133.34 g/mol = 0.0774 mol

Next, we can use the ideal gas law equation PV = nRT to calculate the number of moles of particles in the gas phase. Rearranging this equation, we get:

n = PV/RT

where P is the pressure, V is the volume, R is the gas constant and T is the temperature in Kelvin.

n = (1.7 x 10 N/m²) x 1 dm³ / (8.31 J/mol/K x 353 K) = 7.55 x 10⁻⁴ mol

The van't Hoff factor (i) is the ratio of the actual number of particles in solution to the number of formula units dissolved. For a completely dissociated compound, the van't Hoff factor is equal to the number of ions produced. In the case of AlCl3, it undergoes a degree of association to form Al2Cl6, so the van't Hoff factor is less than 1.

We can now use the formula i = 1 + (α - 1)β, where α is the degree of association and β is the number of particles in solution per formula unit. For AlCl3, β = 4 (AlCl3 contains one Al and three Cl atoms), and assuming a degree of association of x, we get:

i = 1 + (x - 1) x 4 = 4x - 3

Substituting the values for n and i into the equation n = iC, where C is the concentration in mol/dm³, we get:

7.55 x 10^-4 mol = (4x - 3) C

Solving for x, we get:

x = 0.663

Therefore, the degree of association of AlCl3 into Al2Cl6 is 0.663.

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The number of mole of cyclopentadiene present in the solution is 0.0232 mole.

We'll begin by converting 5.8 mL to litre (L). This can be obtained as follow:

1000 mL = 1 L

Therefore,

5.8 mL = 5.8 / 1000

Finally, we shall determine the number of mole of cyclopentadiene present in the solution. This can be obtained as follow:

Volume = 0.0058 L

Molarity = 4 M

Mole = Molarity x Volume

Mole = 4 × 0.0058

Therefore, the number of mole of cyclopentadiene present in the solution is 0.0232 mole.

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Answer:

D

Explanation:

The bottommost layer is always the oldest.

Answer:

Particles of matter possess energy called kinetic energy.

Solid cannot be compressed, but gases are highly compressible.

The Kinetic energy of molecules of gases is very large & solids the least.

On heating a sublimable liquid, the molecules break free & escape from the surface of the solid directly into vapour.

Particles of matter move more rapidly on the application of heat

Moles of gas=19.75

The gas equation can be written  

\(\large {\boxed {\bold {PV = nRT}}}\)

where  

P = pressure, atm  

V = volume, liter  

n = number of moles  

R = gas constant = 0.08206 L.atm / mol K  

T = temperature, Kelvin  

V=150 L

P=4.2 atm

T=389 K

\(\tt n=\dfrac{PV}{RT}\\\\n=\dfrac{4.2\times 150}{0.082\times 389}\\\\n=19.75\)

NaOH has ais a liter value for titration molarity of 1 mole.

Molarity-

The amount of a substance in a specific volume of solution is known as its molarity (M). The number of moles of a solute per liter of a solution is known as molarity. The molar concentration of a solution is another term for molarity.

If you know how many grams of NaOH is dissolved in a known amount of solvent, you can use the formula below to calculate its molarity.

The molarity of NaOH is determined, for instance, when 10 gm of NaOH is dissolved in 250 ml of water.

Molarity is calculated as (Weight of NaOH taken*1000)/(250*NaOH's molecular weight).

Molarity equals (10*1000)/(250*40).

NaOH has a molarity of 1 mole.

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The full question-

How do you calculate the molarity of NaOH?

The mass of E85 fuel that has a specific gravity of 0.801 is 3032.11grams.

The specific gravity is the ratio of the mass of a substance to that of an equal volume of water at 4°C (or to some other reference substance).

The specific gravity is the ratio of the densities of two substances, which is the E85 fuel and water in this case.

The density of water = 1.00 g/cm³

Specific gravity = density of fuel/density of water

0.801 = density of fuel ÷ 1.000

density of fuel = 0.801g/cm³

1 us liquid gallon = 3785.412 cubic centimetres

0.801 = mass ÷ 3785.412

mass = 3032.11grams

Therefore, the mass of E85 fuel that has a specific gravity of 0.801 is 3032.11grams.

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Answer:

5.09 moles of Fe is required to react with 3.82 moles of O₂.

0.326 moles of O₂ are needed to produce 34.7 grams of Fe₂O₃.

Reaction stoichiometry

In first place, the balanced reaction is:

4 Fe + 3 O₂ → 2 Fe₂O₃

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

Fe: 4 moles

O₂: 3 moles

Fe₂O₃: 2 moles

The molar mass of the compounds is:

Fe: 55.85 g/mole

O₂: 32 g/mole

Fe₂O₃: 159.7 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

Fe: 4 moles ×55.85 g/mole= 223.4 grams

O₂: 3 moles ×32 g/mole= 96 grams

Fe₂O₃: 2 moles ×159.7 g/mole= 319.3 grams

Moles of Fe needed

The following rule of three can be applied: If by stoichiometry of the reaction 3 moles of O₂ react with 4 moles of Fe, 3.82 moles of O₂ react with how many moles of Fe?

moles of Fe= 5.09 moles

Finally, 5.09 moles of Fe is required to react with 3.82 moles of O₂.

Moles of O₂ needed

The following rules of three can be applied: If by reaction stoichiometry 319.3 grams of Fe₂O₃ are formed from 3 moles of O₂, 34.7 grams of Fe₂O₃ are formed from how many moles of O₂?

moles of O₂= 0.326 moles

Finally, 0.326 moles of O₂ are needed to produce 34.7 grams of Fe₂O₃.

Explanation:

Answer:

This water has a level acceptable, 0.1359ppm and 135.9ppb.

Explanation:

1.40g of Cl⁻ are:

1.40g Cl⁻ × (1000mg / 1g) = 1400mg Cl⁻

In 1.03x10⁴L:

1400mg / 1.03x10⁴L = 0.1359mg/L.

As the upper limit of Cl⁻ in water is 250mg/L, this water has a level acceptable

ppm are the ratio between mg of solute and liters of solution, that means the tank contains 0.1359mg/L = 0.1359ppm

ppb, parts per billion are 1000 times ppm, thus, parts per billion of the storage tank are:

0.1359ppm × 1000 = 135.9ppb

It is a salt formed from the potassium cation (K+) and the phosphate anion (H2PO4-). This salt is considered monobasic because it contains one replaceable hydrogen ion (H+).

KH2PO4 is actually potassium dihydrogen phosphate, not potassium phosphate monobasic. Potassium phosphate monobasic, or monopotassium phosphate, is correctly represented by the chemical formula KH2PO4. It is a salt formed from the potassium cation (K+) and the phosphate anion (H2PO4-). This salt is considered monobasic because it contains one replaceable hydrogen ion (H+).

On the other hand, potassium dihydrogen phosphate, or K2HPO4, is a different compound. It is formed from the potassium cation (K+) and the hydrogen phosphate anion (HPO4^2-). This compound is considered dibasic because it contains two replaceable hydrogen ions (H+).

Therefore, KH2PO4 is correctly identified as potassium phosphate monobasic, while K2HPO4 is potassium dihydrogen phosphate.

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The solubility of\(LaF_3\) in water is 3.04 x 10^-6 mol/L.

The solubility of \(LaF_3\) in water can be determined using the Ksp expression:

\(Ksp = [La^{3+}][F^-]^3\)

Where \([La^{3+}]\)and \([F^-]\) are the molar concentrations of the \(La^{3+}\) and \(F^-\) ions in the solution.

Since each \(LaF_3\) formula unit dissociates into one \(La^{3+}\) ion and three \(F^-\) ions, the molar solubility of \(LaF_3\) can be represented as x. Thus, the molar concentrations of \(La^{3+}\) and \(F^-\) ions in the solution can be written as x and 3x, respectively.

Substituting these values into the Ksp expression gives:

Ksp = x*(3x)^3 = 27x^4

Now, we can solve for x:

x = (Ksp/27)^(1/4)

= (2 x 10^-19 / 27)^(1/4)

= 3.04 x 10^-6 mol/L

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the possible quantum numbers (ordered n, ℓ, mℓ ) are:Option B.5, 3, -3 and Option C. 4, 3, -2

The quantum numbers n, ℓ, mℓ represent respectively the principal quantum number, the orbital angular momentum quantum number and the magnetic quantum number.

These are the three most important quantum numbers. T

here is another quantum number called the spin quantum number, denoted by ms.

Let's see which of the given quantum number sets is possible.2, 1, 3 is not possible because for ℓ = 1, mℓ can only be -1, 0, or 1. 5, 3, -3 is possible.4, 3, -2 is possible. -4, 3, 1 is not possible.

For any value of ℓ, mℓ must be between -ℓ and +ℓ. e. 2, 1, -2 is not possible because for ℓ = 1, mℓ can only be -1, 0, or 1. f. 3, 2, 2 is not possible because for ℓ = 2, mℓ can only be -2, -1, 0, +1, or +2. g. 3, 3, 1 is not possible because for any value of ℓ, mℓ must be between -ℓ and +ℓ.

Therefore, the possible quantum numbers (ordered n, ℓ, mℓ ) are:5, 3, -34, 3, -2

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The boiling point of benzene when the external pressure is 440 torr is 80.1 °C (176.2 °F).

What is benzene?

Benzene is an organic compound composed of six carbon atoms in a ring structure, with one hydrogen atom attached to each carbon atom. It is a highly flammable, colorless liquid with a sweet smell. Benzene is a natural component of crude oil and is one of the most important organic chemicals used in industry. It is used in the production of plastics, resins, synthetic fibers, rubber, pesticides, detergents, drugs, and dyes. It is also used as a solvent for fats, oils, waxes, resins, and inks. Benzene is classified as a carcinogen and its exposure can cause a variety of adverse health effects, including acute myelogenous leukemia, lymphomas, and other forms of cancer.

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try and find a better answer or ask ur teacher please

Answer:

Competition

Explanation:

Competition, is preys, and predators fighting for survival. Whether it be on the african dessert, lions fighting hyenas over territory, or water.

29 is not the best answer depends on the context and the rules for significant figures.

What is best answer?

The best answer depends on the context and the rules for significant figures. If we assume that we need to round to three significant figures:

Therefore, 29 is not the best answer.

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Answer: boiling, melting, freezing, and shredding

Explanation:

Answer:

b. dry ice becoming vapor

Explanation:

pls mark brainiest

Answer:

It takes six molecules of carbon dioxide and six molecules of water to make one molecule of glucose.

Answer:

Explanation:

The reaction between 2 chloro- 2 methyl pentane and sodium iodide takes place through SN2 mechanism . iodide ion is the nucleophile which attacks the substrate . The rate of such reaction depends upon concentration of both the nucleophile and the substrate .

Hence rate of reaction will be increased by 2 x 2 = 4 times.

option D ) is correct.

Explanation:

The given reaction represents the reaction between a tertiary alkyl halide that is 2-chloro-2-methylpentane and a nucleophile that is NaI.

This reaction favors SN1 mechanism which has order one.

So, the given reaction follows first-order kinetics.

For a first-order reaction, the rate law is:

rate =k [A]

That means the rate of the reaction is dependent on the concentration of reactants.

So, when the concentration of the reactant is doubled then, the rate of the reaction is also doubled.

Among the given options the correct answer is option B) It would double the rate.

Answer:

Which of the following best describes the make up of Saturn's rings?(1 point) solid bands of sand and dust that formed from the start of the universe solid bands of sand and dust that formed from the start of the universe material from comets that have passed through Saturn's atmosphere material from comets that have passed through Saturn's atmosphere dust, rock, and ice particles that orbit due to Saturn's gravity dust, rock, and ice particles that orbit due to Saturn's gravity debris and rocks from other planets that orbit around Saturn

The make up of Saturn's ring are dust, rock, and ice particles that orbit due to Saturn's gravity"

Saturn is one of the 9 planets of the solar system. It is considered to be the second largest planet.

Saturn has seven large rings orbiting around it. These rings are believed to be pieces of comets, asteroids, or shattered moons that broke up before they reached the planet. And this shattered comets or asteroid are believed to be torn apart by Saturn's powerful gravity.

These comets or asteroids are made of billions of small chunks of ice and rocks which are covered or coated with other small materials such as dust particles.

Thus, the correct option that matches the above explanation is "dust, rock, and ice particles that orbit due to Saturn's gravity"

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