Which of the following is the correct factorization of the polynomial below? 8x3 + 64y3 A. (4x + 4y) (2x+8y) B. (2x + 4y)(4x2 - 8xy + 16y2) C. (4x + 2y)(4x2 - 2xy + 16y?) D. The polynomial is irreducible.​

P1 = (-4, 8)

P2 = (0, 0)

slope = (8 - 0) / (-4 - 0 )

= (8) / -4

= -2

Result slope = -2

Answer: 5

Step-by-step explanation:

(9 × 3 + 1)× 6 over 3d (Cancel out 3 in both numerator and denominator)

2(1 + 3 × 9 ) over d (Multiply 3 and 9 to get 27)

2(1 + 27) over d (Add 1 and 27 to get 28)

2×28 over d (Multiply 2 and 28 to get 56)  

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Answer:

250m² drawing a model or visualizing it would help

Answer:

x=10 since 8x+10 and 6x+30 are equal just equate

Subtract m + ? from m:

11-7 = 4

12-8 - 4

16-12 = 4

21-17 - 4

All the differences are identical, so the rule is to add 4 to m.

The expression would be m + 4

The division 292,000 divide 100. results to 2920.

Repetitive subtraction is the process of division. It is the multiplication operation's opposite. It is described as the process of creating equitable groups. When dividing numbers, we divide a larger number down into smaller ones such that the larger number obtained will be equal to the multiplication of the smaller numbers.

Given:

292,000 divide 100.

We know division with zero in the denominator is different and easy.

As, 292000 have three and 100 have two zeroes.

So, the two zero of hundred cancels out the two zeroes of  292000.

So, 292000/ 100

= 2920

Hence, the division results to 2920.

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The theoretical probability of having three dogs or three cats is p^3 + q^3.

The theoretical probability of the family having two dogs or two cats depends on the specific probability of each event. Let's assume that the probability of having a dog is 0.5 and the probability of having a cat is also 0.5 (which is a simplification). In this case, the probability of having two dogs is 0.5 x 0.5 = 0.25, and the probability of having two cats is also 0.5 x 0.5 = 0.25. Therefore, the theoretical probability of the family having two dogs or two cats is 0.25 + 0.25 = 0.5 or 50%.

To simulate which two pets the family has using two different coins, we can assign one pet to each coin face (e.g., heads for dog and tails for cat). Then, we can flip both coins and record the outcome to determine which pets the family has. For example, if the first coin shows heads and the second coin shows tails, the family has one dog and one cat.

After flipping both coins 50 times and recording the outcomes in a table, we can calculate the experimental probability of the family having two dogs or two cats. Let's assume that we observed 12 occurrences of two dogs, 10 occurrences of two cats, and 28 occurrences of other outcomes (e.g., one dog and one cat). The experimental probability of the family having two dogs or two cats is (12 + 10) / 50 = 0.44 or 44%.

If the family has three pets, the theoretical probability of having three dogs or three cats can be calculated using a similar approach. Let's assume that the probability of having a dog is p and the probability of having a cat is q (where p + q = 1). Then, the probability of having three dogs is p x p x p = p^3, and the probability of having three cats is q x q x q = q^3. Therefore, the theoretical probability of having three dogs or three cats is p^3 + q^3.

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Answer:

Question 4 is B and Question 5 is C

Step-by-step explanation:

Question 4 is B because the DIFFERENCE between the two terms is 15 therefore when you subtract the terms it must equal 15 so B could no be an answer. Also since they both equal 24 they both add up to 24

Answer:

n = 51

Step-by-step explanation:

You can rearrange this to make it easier:

107-56=n

51=n

Answer:

C) 5/36

Step-by-step explanation:

Now, suppose, dice 1 gives 2. Here also, dice 2 can be anything between 1 and 6. But, the sum of both the dices will be 8 only if dice 2 shows 6.

Similarly, now, if dice 1’s face is 3, sum will be 8 only if dice 2’s upper face shows 5.

If dice 1 shows 4, sum = 8 only if dice 2 is 4.

If dice 1 is 5, sum = 8 only if dice 2 is 3.

If dice 1 is 6, sum= 8 only if dice 2 is 2.

Therefore, sum will be 8 only 5 times. But, sample space consists of 36 values ( combination of values of dice 1 and dice 2).

Therefore, probability = 5/36.

Hope it helps.

Answer:

Now, suppose, dice 1 gives 2. Here also, dice 2 can be anything between 1 and 6. But, the sum of both the dices will be 8 only if dice 2 shows 6.

Similarly, now, if dice 1’s face is 3, sum will be 8 only if dice 2’s upper face shows 5.

If dice 1 shows 4, sum = 8 only if dice 2 is 4.

If dice 1 is 5, sum = 8 only if dice 2 is 3.

If dice 1 is 6, sum= 8 only if dice 2 is 2.

Therefore, sum will be 8 only 5 times. But, sample space consists of 36 values ( combination of values of dice 1 and dice 2).

Therefore, probability = 5/36.

Hope it helps.

Step-by-step explanation:

Answer:

how to divide fractions

1. Flip (or invert) the divisor into a reciprocal

2. Change the division sign to a multiplication symbol and multiply

3. Simplify your answer if possible

Answer:

2. The standard deviation of the distances in kilometers is larger.

Step-by-step explanation:

Let us assume the distance of car travel in miles is x

And, the  distance of car travel in kilometers is y

Given that

1 mile = 1.6 km

That means

y = 1.6x

Therefore

The standard deviation of y =  1.6 × (standard deviation of x)

The above equation represents

The standard deviation of y > standard deviation of x

hence, the correct option is 2.

Answer:

0.24

Step-by-step explanation:

Answer:

B. 3x³ - 5x² + 3x - 3

Step-by-step explanation:

8x³ - 2x² + 5x - 7 - 5x³ - 3x² - 2x + 4 <== combine like terms

3x³ - 5x² + 3x - 3

Hope this helps!

The missing number in the expression (5 x 7) + (n x 4) = 5 x (7+ 4) is 5.

The GCF of two or more than two numbers is the highest number that divides the given two numbers completely.

We also know that distributive property states a(b + c) = ab + ac.

Given, An expression (5 × 7) + (n × 4) = 5 × (7 + 4).

Now, If we expand the RHS we have,

5×(7 + 4).

= (5 × 7) + (5 × 4).

Now, Writing the obtained RHS with LHS we have,

(5 × 7) + (n × 4) =  (5 × 7) + (5 × 4).

So, The missing number is 5.

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Step-by-step explanation:

\(a = \frac{ - 4 - 8}{2 - ( - 1)} = \frac{ - 12}{3} = - 4\)

The slope of the line passing through the points (-1, 8) and (2, -4) is -4.

To find the slope of a line passing through two points, we can use the slope formula:

\(slope = (y_2 - y_1) / (x_2 - x_1)\)

Let's use the given points (-1, 8) and (2, -4) to calculate the slope:

\(x_1 = -1, y_1 = 8\\\\x_2 = 2, y_2 = -4\)

slope = (-4 - 8) / (2 - (-1))

     = (-12) / (2 + 1)

     = -12 / 3

     = -4

Therefore, the slope of the line passing through the points (-1, 8) and (2, -4) is -4.

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To get the Prime factorization of 3000 we need to multiply by 5.

When the number is factored using prime numbers, or primes, the process is known as prime factorization. The easiest method to determine the prime factors of a given number is to keep dividing the given number by the prime factors until we will get 1.

For example, the Prime factorization of 45 is given below

=> 45/5 = 9, 9/3 = 3,  3/3 = 1

=> 45 = 5 × 3 × 3

Here we have

The prime factorization of 600 is 2 x 2 × 2 × 3 × 5 × 5

Let us assume that on multiplying with p,

we will get the factorization of 3000

=> 2 x 2 × 2 × 3 × 5 × 5 × p = 3000

=> p = \(\frac{3000}{2\times 2 \times 2 \times 3 \times 5 \times 5}\)  

Her 2 x 2 × 2 × 3 × 5 × 5 = 600

=> p = \(\frac{3000}{600}\)

=> p = 5  

Therefore,

To get the Prime factorization of 3000 we need to multiply by 5.

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The constant differences between the consecutive terms are 2 (a); 2 (b), -3 (c), 7 (d), 1(e), and 6(f).

In math, the constant difference can be defined as the number that defines the pattern of a sequence of numbers. This means that number that should be added or subtracted to continue with the sequence.

Due to this, to determine the constant difference it is important to observe the pattern and find out the number that should be added. For example, if the sequence is 2, 4, 6, 8, there is a difference of 2 between each of the numbers and this is the constant difference.

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Let z = 2 - 2√3 i. In polar form, we have

\(z = |z| e^{i\arg(z)}\)

where

\(|z| = |2-2\sqrt3| = \sqrt{2^2 + (-2\sqrt3)^2} = 4\)

\(\arg(z) = \tan^{-1}\left(-\dfrac{2\sqrt3}2\right) = -\tan^{-1}(\sqrt3) = -\dfrac\pi3\)

Equivalently,

\(z = 4\left(\cos\left(-\dfrac\pi3\right) + i\sin\left(-\dfrac\pi3\right)\right)\)

Let w be a complex number such that w ² = z. By DeMoivre's theorem,

\(z = 4\left(\cos\left(-\dfrac\pi3\right) + i\sin\left(-\dfrac\pi3\right)\right) \\\\ \implies z^{1/2} = 4^{1/2} \left(\cos\left(\dfrac{-\frac\pi3+2k\pi}{2}\right) + i \sin\left(\dfrac{-\frac\pi3+2k\pi}{2}\right)\right)\)

where k ∈ {0, 1}. So the two square roots of z are

\(z^{1/2} = \begin{cases}2\left(\cos\left(-\dfrac\pi6\right) + i\sin\left(-\dfrac\pi6\right)\right) & \text{for }k=0 \\\\ 2\left(\cos\left(\dfrac{5\pi}6\right) + i\sin\left(\dfrac{5\pi}6\right)\right) & \text{for }k=1\end{cases}\)

\(z^{1/2} = \begin{cases}2\left(\dfrac{\sqrt3}2 - \dfrac12 i\right) & \text{for }k=0 \\\\ 2\left(-\dfrac{\sqrt3}2 + \dfrac12 i\right) & \text{for }k=1\end{cases}\)

\(\boxed{z^{1/2} = \begin{cases}\sqrt3 - i & \text{for }k=0 \\ -\sqrt3 + i & \text{for }k=1\end{cases}}\)

Answer:

10 tickets for $31.50

Step-by-step explanation:

So If we divide 22.75 by 7 it gives you 3 dollars and 25 cents per ticket

If you divide 31.50 by 10 it gives you 3 dollars and 15 cents.

So In conclusion 10 tickets for $31.50 dollars is the better buy

Answer:

10 Tickets Is The Better Deal

Step-by-step explanation:

So What You Do Is You Will Divide 22.75 By 7

You Will Get 3.25! That Means Its 3.25 Each For 7 Tickets

For The Next One You Do The Same Thing

You Want To Divide 31.50 By 10

You Will Get 3.15! That Means Its 3.15 Each For 10 Tickets

So 3.15 Is 10 Cheaper Than 3.25 So Getting 10 Tickets Is A Better Deal

Hope This Help

DOH! My Brain Hurts

Answer:

770,400

Step-by-step explanation:

770,400 seconds

Answer:

We want to find:

\(\lim_{n \to \infty} \frac{\sqrt[n]{n!} }{n}\)

Here we can use Stirling's approximation, which says that for large values of n, we get:

\(n! = \sqrt{2*\pi*n} *(\frac{n}{e} )^n\)

Because here we are taking the limit when n tends to infinity, we can use this approximation.

Then we get.

\(\lim_{n \to \infty} \frac{\sqrt[n]{n!} }{n} = \lim_{n \to \infty} \frac{\sqrt[n]{\sqrt{2*\pi*n} *(\frac{n}{e} )^n} }{n} = \lim_{n \to \infty} \frac{n}{e*n} *\sqrt[2*n]{2*\pi*n}\)

Now we can just simplify this, so we get:

\(\lim_{n \to \infty} \frac{1}{e} *\sqrt[2*n]{2*\pi*n} \\\)

And we can rewrite it as:

\(\lim_{n \to \infty} \frac{1}{e} *(2*\pi*n)^{1/2n}\)

The important part here is the exponent, as n tends to infinite, the exponent tends to zero.

Thus:

\(\lim_{n \to \infty} \frac{1}{e} *(2*\pi*n)^{1/2n} = \frac{1}{e}*1 = \frac{1}{e}\)

Answer:

Step-by-step explanation:

To complete the math table, substitute the given x-values in the given function, compute and fill the table:

Answer:

Option 3

(3xy³ + 5x²y⁴)  (3xy³ - 5x²y⁴)

Step-by-step explanation:

Factorize polynomials:

Use exponent law:

                   \(\boxed{\bf a^{m*n}=(a^m)^n} \ & \\\\\boxed{\bf a^m * b^m = (a*b)^m}\)

9x²y⁶ = 3²* x² * y³*² = 3² * x² * (y³)² = (3xy³)²

25x⁴y⁸ = 5² * x²*² * y⁴*² = 5² * (x²)² * (y⁴)² = (5x²y⁴)²

Now use the identity:  a² - b² = (a +b) (a -b)

Here, a = 3xy³ & b = 5x²y⁴

9x²y⁶ - 25x⁴y⁸ = 3²x²(y³)² - 5²(x²)² (y⁴)²

                       = (3xy³)² - (5x²y⁴)²

                      = (3xy³ + 5x²y⁴)  (3xy³ - 5x²y⁴)

Using the definition of congruent triangles, the value of x is evaluated as: x = 6.

To find the sides of congruent triangles, note that the corresponding sides of two triangles that are congruent to each other have equal length measurement.

Given that triangular poor ABC and triangular pool PQR are congruent to each other, therefore, their corresponding sides will have the same length.

This means that the third sides of both triangles will be equal, which are:

(3x + 2) = 20

Solve for x:

3x + 2 = 20

3x + 2 - 2 = 20 - 2

3x = 18

3x/3 = 18/3

x = 6

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Due to modulus there can be two answers, one with greater than equal to and one with less than equal to. So the answer is 11 and -7.

Solve the inequality |x−2|≥9

Inequality is a Mathematical statement that shows the relation between two expressions using the inequality symbol. The expressions on both sides of an inequality sign are not equal. It means that the expression on the left-hand side should be greater than or less than the expression on the right-hand side or vice versa.

a) |x−2|≥9 = x-2≥ 9

=> x≥ 9+2

=> x≥ 11

b)  |x−2|≥9 = x-2≥ -9 (when sign the negative the greater than equal to sign changes to less than equal to sign)

= x ≤ -9+2 ≤-7

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The denominator is zero (0/0 is undefined), we cannot determine the exact value of f(-3) using this equation.

To solve the given equations, we need to find the value of the function f(x) for specific values of x.

"If f(x) / (x - 2) = x³ + 2x - 4 + 13/(x - 2), what is f(2)?"

To find f(2), we can substitute x = 2 into the equation and solve for f(2).

Plugging in x = 2, we get:

f(2) / (2 - 2) = 2³ + 2(2) - 4 + 13/(2 - 2)

Since the denominator is zero (2 - 2 = 0), the equation is undefined. Therefore, there is no solution for f(2) in this case.

"If f(x) / (x + 3) = 3x² - 4x + 2, what is f(-3)?"

To find f(-3), we can substitute x = -3 into the equation and solve for f(-3).

Plugging in x = -3, we get:

f(-3) / (-3 + 3) = 3(-3)² - 4(-3) + 2

Simplifying, we have:

f(-3) / 0 = 3(9) + 12 + 2

f(-3) / 0 = 27 + 12 + 2

f(-3) / 0 = 41

Additional information or context is needed to solve for f(-3).

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Answer:

31 + 32 + 33 = 96.

Step-by-step explanation:

I think you are meaning 96 not -96