Which of the following is the cause of an acceleration or a change in an object's motion?

12. The time taken for the journey is 400 s

13. The time taken for the train is 200 s

14. The time taken is 7 h

15. The time taken for the beetle is 12 s

16. The time taken for the journey is 0.0068 h

The time taken in each case as given by the question can be obtain as follow:

12. The time taken for the journey

Time taken = Distance / Speed

Time taken = 26000 / 65

Time taken = 400 s

13. The time taken for the train

Time taken = Distance / Speed

Time taken = 3200 / 16

Time taken = 200 s

14. The time taken to travel

Time taken = Distance / Speed

Time taken = 672 / 96

Time taken = 7 h

15. The time taken for the beetle

Time taken = Distance / Speed

Time taken = 1.08 / 0.09

Time taken = 12 s

16. The time taken for the journey

Time taken = Distance / Speed

Time taken = 35 / 5147

Time taken = 0.0068 h

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The total heat required to convert 1 kg of ice at -2°C to steam is 721 calories.

To calculate the total heat required to convert 1 kg of ice at -2°C to steam, we need to consider three steps: heating the ice from -2°C to 0°C (using specific heat), melting the ice at 0°C (using latent heat of ice), and heating the resulting water from 0°C to steam at 100°C (using specific heat and latent heat of steam).

The total heat can be calculated by summing up the heat for each step: (mass of ice x specific heat x temperature change) + (mass of ice x latent heat of ice) + (mass of water x specific heat x temperature change) + (mass of water x latent heat of steam).

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The total heat required to convert 1kg of ice at -2°C to steam at 100°C is 721kJ with specific and latent heat.

From the given,

mass of ice (m) = 1kg = 1000g

Specific heat of ice (Ci) = 0.5 cal/gm.C

Specific heat of water(Cw) = 1 cal/gm.C

Latent heat of ice (Li) = 80 cal/gm

Latent heat of steam (Ls) = 540 cal/gm

The heat required to take the ice from -2°C to 0°C

Q = mCΔT = 1000×0.5×2 = 1000J

The heat required to melt ice at 0°C to water

Q = mL(i)ΔT = 1000×80 = 80,000J

The heat required to take 1kg of water from 0°C to 100°C

Q = mCΔT = 1000×1×100 = 100,000J

The heat required to convert 1kg of ice at 100°C to steam

Q = mL(s)ΔT = 1000×540 = 540,000 J

The total heat required (Q) = 1000J + 80000 J + 100000 J + 540000 J

      Q = 721000J

Thus, the total heat required to convert 1kg of ice to steam is 721kJ.

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The kinetic energy of the cylinder and crank at the moment when the bucket is moving with a velocity of 5.0 m/s can be determined by making use of the law of conservation of energy. The law states that the total energy of a closed system remains constant provided that no energy is lost to the surroundings, and this law is applicable for the present scenario since the system consists of the bucket, rope, cylinder, and crank.

According to this law, the initial potential energy (PEi) of the bucket when it is raised to the top of the well is equal to the final kinetic energy (KEf) of the cylinder and crank when the bucket is moving with a velocity of 5.0 m/s.

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Answer-

a. iron - 60 grams and nickel 6 grams

b. \(14\) grams

Explanation

The complete question is given in the two attached images

Solution

As shown in the graph

Part A

The weight of iron is 60 gram

Weight of nickel is 6 grams

Part B

Weight of chromium is equal to

\(80-60-6\\= 14\)

\(14\) grams

According to Chargaff's rule, the amounts of adenine (A), thymine (T), and guanine (G) in the DNA molecule are equal to each other. The amounts of cytosine (C) and guanine (G) are also equal.

Erwin Chargaff was a biochemist, author, Bucovinian Jew who immigrated to America during the Nazi era, and professor of biochemistry at Columbia University's medical school.

Chargaff found patterns among the four bases, or chemical building blocks, of DNA, which are directly related to DNA's function as the genetic material of living things.

He was born in Austria-Hungary. Heraclitean Fire: Sketches from a Life Before Nature, an autobiography he penned, received positive reviews.

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Answer:

The drop voltage is 0.3 V

Explanation:

Electromotive Force EMF

When connecting a battery of internal resistance Ri and EMF ε to an external resistance Re, the current through the circuit is:

\(\displaystyle i=\frac{\varepsilon }{R_e+R_i}\)

The battery has an internal resistance of Ro=2 Ω, ε=24 V and is connected to an external resistance of Re=158 Ω. Thus, the current is:

\(\displaystyle i=\frac{24 }{158+2}\)

\(\displaystyle i=\frac{24 }{160}\)

i = 0.15 A

The drop voltage is the voltage of the internal resistance:

\(V_i = i.R_i\)

\(V_i = 0.15*2\)

\(\boxed{V_i = 0.3\ V}\)

The drop voltage is 0.3 V

Answer:

D. An object at rest will move due to an applied balanced force

Explanation:

Newton's first law states that an object at rest stays at rest, and an object in motion will stay in motion, until acted upon by an unbalanced forced. In other words, a net force is required for a change in motion.

Answers A and B are true of Newton's second law (F=ma), and answer C is true of Newton's third law (every action has an opposite and equal reaction).

The angle between vector A and B is 90 degrees.

Let’s consider the vectors A and B with equal magnitudes of 5.

Thus, we can assume that the angle between A and B is θ.

Now, if the sum of A and B is vector 6j, then we can write the vector equation below:

\(A + B = 6j\)

Let's first express vector A and B in terms of their components.

Let’s assume that vector A has components Ax and Ay, while vector B has components Bx and By.

Thus, the vector equation above can be rewritten in terms of components below:

\(Ax + Bx = 0\)       ------------(1)

\(Ay + By = 6\)       ------------(2)

We know that the magnitudes of vectors A and B are equal to 5, thus we can write the following equations:

\(x^2+y^2 = 5^2\)       ------------(3)

\(x^2+y^2 = 25\)      ------------(4)

From equation (4), we can write:

\(y = \sqrt{(25-x^2)}\)      ------------(5)

By substituting equation (5) into equation (2), we have:

\(Ay + By = 6Ay + \sqrt{(25-x^2)} = 6Ay\)

\(= 6 - \sqrt{(25-x^2)}\)    ------------(6)

We can now substitute equation (6) into equation (3):

\(x^2 + (6-\sqrt{(25-x^2)})^2 = 25\)

Solving for x:

\(2x^2 + 12\sqrt{(25-x^2)} = 0x^2 + 6\sqrt{(25-x^2)}\)

\(= 0x^4 + 36x^2 - 225\)

\(= 0x^2\)

\(= 3, -15\)

We choose \(x^2 = 3\) since it is positive and obtain:

\(y = 4By\)

substituting x and y into the original equations \(A = Ax + Ay\) and

\(B = Bx + By\), we obtain:

\(A = (-\sqrt{3}, 6-\sqrt{3})\)

\(B = (\sqrt{3}, -1+\sqrt{3})\)

Thus, the dot product of vectors A and B can be expressed as:

\(A \cdot B = |A||B| cos(\theta)\)

Now, we know that

\(|A| = |B| = 5\)

thus we can write:

\(A \cdot B = 25 cos(\theta)\)

Using the formula above, we can obtain the angle θ between vectors A and B as follows:

\(cos(\theta) = \frac{(A \cdot B)}{|A||B|}\)

\(cos(\theta) = \frac{[(\sqrt{3}(-\sqrt{3}) + (6-\sqrt{3})(-1+\sqrt{3})] }{(5)(5)}\)

\(cos(\theta) = \frac{ [-3 + 3]}{25}\)

\(cos(\theta) = 0\)

\(\theta= cos^{-1}(0)\)

\(\theta =90^{\circ}\)

Therefore, the angle between vector A and B is 90 degrees.

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The speed of the electron when it is 10.0 cm from the +3.00 nC charge is 30×\(10^{-2}\) meters per second.

Given :

q=3.00 nC

r=distance=10 c.m

we apply formula

Velocity of electron =qd

=10×\(10^{-2}\)×3=30×\(10^{-2}\) m/sec

The speed of electricity is determined by what you mean by the term "electricity." This is a broad term that essentially means "all things relating to electric charge." I'll presume we're talking about an electrical charge current moving through a metal wire, like the power cord of a light. Electrical currents passing through metal wires have three different velocities, all of which are physically significant:

The velocity of electron drift.

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The frictional force of an object is the product of the normal force and coefficient of kinetic friction. Here the frictional force acting on the object  is 16.4 N.

Frictional force is a kind of force acting on a body to resist it from motion. Thus, the direction of the force will be in negative with the magnitude. Frictional force is the product of coefficient of friction and the normal force.

The normal  force acting on the object of mass 4.2 Kg is N = mg

N = 4.2 Kg × 9.8 m/s² = 41.16 N

Frictional force = ц N

                         = 0.40 × 41.16 N

                         = 16.4 N.

Therefore, the frictional force acting between the surface of the object and the floor is 16.4 N

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Your question is incomplete. But your complete question probably was:

The coefficient of kinetic friction between an object and the surface upon which it is sliding is 0.40 the weight of the object is 4.2 kg. What is the frictional force of the object?

Answer:

Weight of an object = 225 newtons

Explanation:

Given:

Mass = 60 kilograms

Acceleration due to gravity = 3.75 m/s²

Find:

Weight of an object

Computation:

Weight of an object = Mass x Acceleration due to gravity

Weight of an object = 60 x 3.75

Weight of an object = 225 newtons

Answer:

See image

Explanation:

Plato

Answer:

hello your question has some missing parts

A juggler performs in a room whose ceiling is 3 m above the level of his hands. He throws a ball vertically upward so that it just reaches the ceiling.

answer : c) 0.39 sec

               d)  2.25 m

               e) 1.92 m/sec

Explanation:

The initial velocity of the first ball = 7.67 m/sec ( calculated )

Time required for first ball to reach ceiling = 0.78 secs ( calculated )

Determine how long after the second ball is thrown do the two balls pass each other

Distance travelled by first ball downwards when it meets second ball can be expressed as : d = 1/2 gt^2 =  9.8t^2 / 2

hence d = 4.9t^2  ----- ( 1 )

Initial speed of second ball = first ball initial speed = 7.67 m/sec

3 - d = 7.67t - 4.9t  ---- ( 2 )

equating equation 1 and 2

3 = 7.67t   therefore t = 0.39 sec

Determine how far the balls are above the Juggler's hands ( when the balls pass each other )

form equation 1 ;

d = 4.9 t^2 = 4.9 *(0.39)^2 = 0.75 m

therefore the height the balls are above the Juggler's hands is

3 - d = 3 - 0.75 = 2.25 m

determine their velocities when the pass each other

velocity = displacement / time

velocity = d / t = 0.75 / 0.39 sec  = 1.92 m/sec

The SI unit for pressure is the pascal (Pa), equal to one newton per square metre (N/m2, or kg·m−1·s−2).

Answer:

3.84 m/s^2.

Explanation:

To solve this problem, we can use the following kinematic equation:

v^2 = u^2 + 2as

where:

v is the final velocity (31 m/s)

u is the initial velocity (13 m/s)

a is the acceleration (which is assumed to be constant)

s is the distance traveled (220 m)

We want to solve for the acceleration, so we can rearrange the equation as follows:

a = (v^2 - u^2) / 2s

Substituting the given values:

a = (31^2 - 13^2) / (2 x 220)

a = 3.84 m/s^2

Therefore, the acceleration of the car is 3.84 m/s^2.

please rate

Answer:

\(\huge\boxed{\sf P = 10\ Watts}\)

Explanation:

Given:

Energy = E = 200 J

Time = t = 20 s

Required:

Power = P = ?

Formula:

P = E / t

Solution:

P = 200 J / 20 s

P = 10 Watts

\(\rule[225]{225}{2}\)

Hope this helped!

Answer:

10800 kg m/s

Explanation:

Since the dumpster was initially at rest, its momentum before collision equal to zero. So that the total momentum of the car and dumpster before collision is 10800 kg m/s.

The principle of conservation of linear momentum states that: in a system of colliding bodies, total momentum is conserved. Therefore, the total momentum of the car and dumpster after collision is 10800 kg m/s.

We can see here that the statement that is correct will be: B. The rock display with larger holes shows petroleum drilling, which is deep underground.

A geologist is a scientist who focuses on the solid components of the Earth, such as minerals and rocks, as well as the processes that shape the planet's surface.

Geologists study the make-up, structure, and past of the Earth's crust in order to comprehend geological processes including mountain creation, earthquake and volcanic activity, and the exploitation of natural resources. They frequently perform fieldwork, gathering samples, running surveys, and researching geological formations.

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The complete question is that:

Your class goes on a field trip to observe drilling machinery. The geologists at the drill site show you displays of drilled rocks to compare different types of drills and methods. The drilled holes in one rock display are significantly larger than the holes drilled in the display next to it. Given this information, which statement is correct? (1 point)

A. The rock display with smaller holes shows copper drilling, which is deep underground.

B. The rock display with larger holes shows petroleum drilling, which is deep underground.

C. The rock display with smaller holes shows petroleum drilling, which is closer to the surface.

D. The rock display with larger holes shows copper drilling, which is closer to the surface.

The frequency of f3 is approximately 716 Hz.

The frequency of a repeated event is its number of instances per unit of time. Hertz (Hz), which stands for the number of cycles per second, is a popular unit of measurement.

a. Given two frequencies, f1 and f2, the frequency ratio is as follows:

frequency ratio= \(\frac{f2}{f1}\)

Inputting the values provided yields:

frequency ratio = \(\frac{576}{320Hz}\) =1.8.

As a result, the difference in frequency between f1 = 320 Hz and f2 = 576 Hz is 1.8.

b. Since there are 12 half-steps in an octave and a fourth is a distance of 5 half-steps, going down a fourth requires dividing the frequency by \(2^{(4/12)}\). Hence, once a fourth is subtracted, the frequency ratio between f and f1 is:

frequency ratio= \(\frac{f}{ (f1 /f2 ) }\)=  \(\frac{f}{ (f1 / 1.3348) }\)

By dividing the numerator and denominator by 1.3348, we may make this more straightforward:

frequency ratio= (f × 1.33348)/f1

As a result, (f × 1.3348) / f1 is the frequency ratio between f and f1 after descending a fourth.

c. (c) To find the frequency of f3, we need to know the interval between f1 and f3. Let's assume that f3 is a fifth above f2. The frequency ratio for a fifth is given by: \(2^{(7/12)}\) = 1.49831

Therefore, the frequency of f3 is:

f3 = f1 × (\(2^{(7/12)}\)) × (\(2^{(7/12)}\)) = 320 Hz × 1.49831 ×1.49831 = 716 Hz

Therefore, the frequency of f3 is approximately 716 Hz.

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Answer:

b. 2 m

Explanation:

Given that:

the identical speakers are connected in phases ;

Let assume ; we have speaker A and speaker B which are = 3 meter apart

An observer stands at X = 4m in front of one speaker.

If the amplitudes are not changed, the sound he hears will be least intense if the wavelength is:                  

From above;  the distance between speaker  A and speaker B can be expressed as:

\(\sqrt{3^2 + 4^2 } \\ \\ = \sqrt{9+16 } \\ \\ = \sqrt{25} \\ \\ = 5 \ m\)

The path length difference  will now be:

= 5 m - 4 m

= 1 m

Since , we are to determine the least intense sound; the destructive interference for that path length  will be half the wavelength; which is

= \(\dfrac{1}{2}*4 \ m\)

= 2 m

The sound will be heard with least intensity if the wavelength is 2 m. Hence, option (b) is correct.

Given data:

The distance between the speakers is, d = 3 m.

The distance between the observer and speaker is, s = 4 m.

The amplitude of sound wave is the vertical distance from the base to peak of wave. Since sound amplitudes are not changed in the given problem. Then  the distance between speaker  A and speaker B can be expressed as:

\(=\sqrt{3^{2}+4^{2}}\\\\=\sqrt{25}\\\\=5\;\rm m\)

And the path length difference is,

= 5 m - 4 m

= 1 m

Since , we are to determine the least intense sound; the destructive

interference for that path length  will be half the wavelength; which is

 \(=\dfrac{1}{2} \times s\\\\=\dfrac{1}{2} \times 4\)

= 2 m

Thus, we can conclude that the sound will be heard with least intensity if the wavelength is 2 m.

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Answer:

The change in momentum will be 100 kg*m/s, and the change in velocity will be 33 m/s.

Explanation:

Answer:

48 m/s - 16 m/s = 32 m/s

(32 m/s )/ (8 s) = 4 m/s²

If A box of mass 210 kg is pulled from rest with a string of tension 1300n inclined at 35° to the horizontal. if the box moved with a speed of 10m/s and the frictional force between the box and surface is 100 n, Then the distance covered by the box is 10.89 meters.

To calculate the distance covered by the box, we need to analyze the forces acting on it and apply the work-energy principle.

Given:

Mass of the box, m = 210 kg

Tension in the string, T = 1300 N

The angle of inclination, θ = 35°

Frictional force, f = 100 N

Initial speed, u = 0 m/s

Final speed, v = 10 m/s

First, let's resolve the tension force into components parallel and perpendicular to the incline. The parallel component of the tension force can be calculated as:

T_parallel = T * cos(θ)

Next, let's calculate the net force acting on the box along the incline. The net force is given by:

Net force = T_parallel - f

Now, using Newton's second law, we can calculate the acceleration (a) of the box:

Net force = m * a

From the given information, we have the final velocity (v), initial velocity (u), and acceleration (a). We can use the following kinematic equation to calculate the distance covered (s):

v^2 = u^2 + 2as

Rearranging the equation, we get:

s = (v^2 - u^2) / (2a)

Now, let's plug in the given values and calculate the distance covered:

T_parallel = 1300 N * cos(35°) ≈ 1067.35 N

Net force = 1067.35 N - 100 N = 967.35 N

a = (967.35 N) / (210 kg) ≈ 4.61 m/s^2

s = (10 m/s)^2 - (0 m/s)^2 / (2 * 4.61 m/s^2) ≈ 10.89 m

Therefore, the distance covered by the box is approximately 10.89 meters.

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When using a dial test indicator (DTI), it is essential to ensure that the gauge is positioned at a right angle to the contact surface for accurate readings.

However, in certain situations, it may be challenging to achieve a perfect right angle alignment. In such cases, adjustments can be made to compensate for the misalignment and obtain accurate measurements.To adjust the DTI reading when the gauge is not positioned at a right angle to the contact surface, the following steps can be taken:Determine the misalignment angle: Measure the angle at which the DTI is misaligned from the right angle position. This can be done using a protractor or by estimating the deviation visually.Calculate the correction factor: Based on the misalignment angle, calculate the correction factor using trigonometric functions such as sine or cosine. The correction factor accounts for the difference between the actual displacement and the displacement measured by the DTI.Apply the correction factor: Multiply the correction factor by the DTI reading to adjust the measurement. This compensates for the misalignment and provides a more accurate reading.It's important to note that adjusting the DTI reading can introduce some degree of error, especially if the misalignment is significant. Therefore, it is always preferable to position the gauge at a right angle to the contact surface whenever possible to obtain the most precise measurements.

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Answer: 3

Explanation:

khan academy

Answer:

Crown glass

Explanation:

We can use Snell's Law to determine the material through which the light is passing.

Snell's Law states that n1 sinθ1 = n2 sinθ2, where n1 and n2 are the indices of refraction of the two materials, θ1 is the angle of incidence, and θ2 is the angle of refraction.

In this case, we know that the angle of incidence is 26.7 degrees, and the angle of refraction is 36 degrees. We also know that air has an index of refraction of approximately 1.

Using Snell's Law, we can solve for the index of refraction of the material:

1 sin 26.7 = n2 sin 36

n2 = (1 sin 26.7) / (sin 36)

n2 ≈ 1.52

The index of refraction of the material is approximately 1.52. This corresponds to the index of refraction of crown glass, which is a common optical material used in lenses and prisms. Therefore, the light is most likely passing through crown glass.

Answer:

A) Energy is dissipated into heat and sound energy due to Friction

B) The energy goes into heat and sound energy due to friction again, otherwise the cart would accelerate due to an unbalanced force. Therefore, we know there's friction, and the friction causes energy loss.

Three facts I have learned this year in Physical Education are:

a) The importance of stretching before and after exercising.

b) The benefits of cardiovascular exercise.

c) The importance of staying hydrated during exercise.

Firstly, I have learned the importance of stretching before and after exercising. Stretching helps prevent injury and improves flexibility. I will make sure to incorporate stretching into my daily routine, whether it's through a short stretching session in the morning or by taking a few minutes to stretch before and after a workout.
Secondly, I have learned the benefits of cardiovascular exercise. Cardiovascular exercise, such as running or cycling, helps improve heart health and endurance. I will try to incorporate more cardiovascular exercise into my daily routine, such as going for a run or bike ride after work.
Lastly, I have learned the importance of staying hydrated during exercise. Dehydration can lead to fatigue and muscle cramps, so it's important to drink plenty of water before, during, and after exercise. I will make sure to carry a water bottle with me throughout the day and refill it regularly to ensure that I am staying hydrated.
In summary, by incorporating stretching, cardiovascular exercise, and staying hydrated into my daily routine, I hope to improve my overall physical health and well-being.

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Answer:

Explanation:

Sure, I'd be happy to help you with the question!

Let's denote the input as x. According to the function machine, the input is multiplied by 6 and then 80 is subtracted from the result to obtain the output.

So, the function can be written as:

Output = (6 * x) - 80

Now, the problem states that the input is the same as the output. Therefore, we can set up the equation:

x = (6 * x) - 80

Let's solve this equation to find the value of x:

x = 6x - 80

Subtracting 6x from both sides, we get:

x - 6x = -80

Combining like terms, we have:

-5x = -80

Dividing both sides by -5, we find:

x = (-80) / (-5)

Simplifying the expression, we have:

x = 16

Therefore, the input (x) that results in the input being the same as the output is 16.

To work out these types of questions, it's important to carefully read the instructions and understand the operations being performed in the function machine. Then, you can set up an equation with the input and output, and solve for the unknown value. Always double-check your solution to ensure it satisfies the given conditions of the problem.

Answer:

16

Explanation:

(x*6) - 80 = x

Multiply the parentheses

6x - 80 = x
Add 80 to each side to get
6x = x + 80
Subtract x from both sides to get
5x = 80
Divide both sides by 5
x = 16

Answer:

2.57 seconds  (rounded to 2.6 Seconds)

Step-by-step explanation:

Great question, it is always good to ask away and get rid of any doubts that you may be having.

Before we can solve this question we need to create a formula that calculates the final speed. The formula will be the following,

Where:

Vf is the final Velocity

Vi is the initial velocity

A is the acceleration

t is the time in seconds

Now that we have the formula we can plug in the values given to us in the question and solve for the amount of time (t).

Finally, we can see that it would take the cyclist 2.57 seconds (approximately) to reach a speed of 18 m/s

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

In a position-time graph, the velocity of the moving object is represented by the slope, or steepness, of the graph line. If the graph line is horizontal, like the line after time = 5 seconds in Graph 2 in the Figure below, then the slope is zero and so is the velocity. The position of the object is not changing.

Explanation:

The slope of a position time graph gives the velocity of an object. It can be calculated as follows:

\(v=\dfrac{dx}{dt}\)

Where

\(dx\) is the change in position

\(dt\) is the change in time

If the position vs time graph of an object is a horizontal line, it shows that the object is at rest. At this point the object is not moving.

Answer:

If the position versus time graph of an object is a horizontal line, the object is at rest.

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