which of the following is not in uniform circular motion? responses merry-go-round that is 10.0 m in diameter and rotating at 2 rpm

This question deals with projectile motion, which is a motion on both the x-axis and y-axis, simultaneously. The total time of flight of the projectile trajectory is given, while the time to reach the highest point of the projectile is required to be found.

The projectile will reach the highest point in "3 seconds".

The total time of flight of a projectile is the time during which the projectile remains in the air. For a projectile motion that ends up on the same horizontal level, from where it started, the time to reach the highest point, is equal to half of the total time of flight.

In other words, the projectile motion takes the same time, to go from the starting level to the highest point (i.e upward motion), as the time taken to reach the starting level from the highest point (i.e downward motion).

\(t = \frac{1}{2}T\)

where,

t = time to reach the highest point = ?

T = total time of flight = 6 seconds

Therefore,

\(t - \frac{1}{2}(6\ seconds)\)

t = 3 seconds

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The time elapsed between the first splash and the second splash is approximately 0.69 seconds.

To calculate this, we consider the motion of two rocks thrown simultaneously from a bridge. Heather throws a rock straight down with a speed of 14 m/s, while Jerry throws a rock straight up with the same speed.

We use the equation for displacement in uniformly accelerated motion: s = ut + (1/2)at^2.

For Heather's rock, which is thrown downwards, the initial velocity (u) is positive and the acceleration (a) due to gravity is negative (-9.8 m/s^2). The displacement (s) is the height of the bridge (46 m).

Solving the equation, we find two possible values for the time (t): t ≈ -4.91 s and t ≈ 1.91 s.

Since time cannot be negative in this context, we discard the negative value and consider t ≈ 1.91 s as the time it takes for Heather's rock to hit the water.

For Jerry's rock, thrown upwards, we use the same equation with the same initial velocity and acceleration. The displacement is also the height of the bridge, but negative.

Solving the equation, we find t ≈ -5.68 s and t ≈ 1.22 s. Again, we discard the negative value and consider t ≈ 1.22 s as the time it takes for Jerry's rock to reach its maximum height before falling back down.

To find the time difference between the first and second splash, we subtract t ≈ 1.91 s (Heather's rock) from t ≈ 1.22 s (Jerry's rock). This gives us a time difference of approximately 0.69 seconds.

Therefore, the time elapsed between the first splash and the second splash is approximately 0.69 seconds.

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(i) To show that chlorophyll is necessary for photosynthesis.

ii) Starch test and potassium iodide are mainly used for the test.

iii) Variegated leaf/Coleus leaf (leaf having non-green and green regions)

iv) After performing the starch test, part A turns blue-black with Iodine solution and part B turns brown with the Iodine solution.

The process of photosynthesis can be influenced by various elements, encompassing:

1. Illumination intensity: The generation of photosynthesis necessitates energy from light; hence, lighting strength is a crucial commodity. Plants possess a limit of tolerance in regards to the luminosity they receive, so excessive or insufficient amounts of light most likely lead to reduced rates of photosynthesis.

2. Levels of Carbon Dioxide: Carbon dioxide plays an essential role as it responds within the process of photosynthesis, making its environmental abundance consequential. Higher carbon dioxide volumes increase photosynthetic velocity while low capacities have a decremental effect on the reaction's rate.

3. Temperature: This chemical recation is quite temperature-sensitive. Elevated temperatures can instigate denaturation of enzymes involved in this intricate process whereas extremely cool conditions decrease reaction celerity.

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The density of the second liquid is 0.812 g/cm³

To calculate the density of the second liquid, we need to use the principle of displacement. The mass of the liquid can be found by subtracting the mass of the empty density bottle from the mass of the bottle filled with the liquid. Therefore, the mass of the liquid is:

mass of liquid = mass of bottle + liquid - mass of empty bottle

mass of liquid = 39.84g + x - 18.00g

where x is the mass of the liquid.

We can now use the density formula, which is:

density = mass/volume

The volume of the liquid is equal to the volume of the density bottle that is filled with the liquid, which can be calculated by subtracting the volume of the empty bottle from the volume of the bottle filled with the liquid. Therefore, the volume of the liquid is:

volume of liquid = volume of bottle filled with liquid - volume of empty bottle

We can now substitute this expression into the density formula to get:

density of liquid = mass of liquid / (volume of bottle filled with liquid - volume of empty bottle)

We know that the density of water is 1000 kg/m³, which is equal to 1 g/cm³. We can use this to find the volume of the liquid by dividing the mass of water by its density:

volume of water = mass of water / density of water

volume of water = 44.00g / 1 g/cm³

volume of water = 44.00 cm³

Now, we can calculate the volume of the density bottle filled with the second liquid by using the principle of displacement:

volume of bottle filled with liquid = volume of water - volume of liquid

volume of bottle filled with liquid = 44.00 cm³ - (39.84g - 18.00g) / 1 g/cm³

volume of bottle filled with liquid = 44.00 cm³ - 21.84 cm³

volume of bottle filled with liquid = 22.16 cm³

Finally, we can substitute these values into the density formula to get:

density of liquid = x / 22.16 cm³

Solving for x, we get:

x = density of liquid x 22.16 cm³

Substituting x back into the mass equation, we get:

mass of liquid = 39.84g + (density of liquid x 22.16 cm³) - 18.00g

Solving for the density of the liquid, we get:

density of liquid = (mass of liquid - 21.84g) / 22.16 cm³

Substituting the given values, we get:

density of liquid = (39.84g - 21.84g) / 22.16 cm³ = 0.812 g/cm³

In conclusion, the density of the second liquid is 0.812 g/cm³. This value is less than the density of water, which means that the second liquid is less dense than water and will float on top of water.

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Answer:

c. Double Replacement

Explanation:

As in Double Replacement reaction exchanges the cations (or the anions) of two ionic compounds.

Here, in BaCl2 , Ba has replaced with NO3 to form Ba(NO3)2

and in 2AgNo3 , Ag has replaced with Cl to form 2AgCl.

Answer:

C. The poster provides an emotional picture of a young, innocent girl with a slightly worried expression to make protective feelings.

Explanation:

The girl looks quite worried in the poster. Attached is the image:

Answer: wow that’s hard

Explanation:

The man has at most 3.55 s to get out of the way.

Kinematics can be defined as a subfield of physics developed in classical mechanics that describes the motion of points, bodies and systems of bodies without considering the forces that cause them to move.

We can solve this problem using kinematic equations.

First, we can find the time it takes for the block to fall from a height of 84.9 m using the formula:

y = 1/2 * g * t^2

where

Rearranging this equation, we get:

t = sqrt(2y/g) = sqrt(2 * 84.9 m / 9.81 m/s^2) = 4.09 s (to two significant figures)

So the block will hit the ground after 4.09 s of falling.

Next, we can find the time it takes for the block to fall from a height of 16.6 m using the same formula:

t = sqrt(2y/g) = sqrt(2 * 16.6 m / 9.81 m/s^2) = 1.41 s (to two significant figures)

So the block will take 1.41 s to fall from a height of 16.6 m to the ground.

The man has to get out of the way before the block falls the remaining distance of (84.9 - 16.6) = 68.3 m. We can find the time it takes for the block to fall this distance using the same formula:

t = sqrt(2y/g) = sqrt(2 * 68.3 m / 9.81 m/s^2) = 3.55 s (to two significant figures)

Therefore, the man has at most 3.55 s to get out of the way.

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Answer:

a)     fem = - 0.0103 V,  b) the applied field is in a vertical upward direction, the induced current is clockwise.

Explanation:

a) For this exercise we use Faraday's law

         fem =  \(- \frac{d \phi}{dty}\)

the magnetic flux is

         Ф = B. A = B A cos θ

The bold letters indicate vectors, in this case the direction of the magnetic field and the normal to the circumference is parallel therefore the angle is zero and the cos 0 = 1

         fem = - B dA / dt

the area of ​​a circle is

        A = π r²

l

et's perform the derivative

         dA / dt =π 2r \(\frac{dr}{dt}\)

we substitute

          fem = - B 2π r \(\frac{dr}{dt}\)

the circumference of a circle is

         L = 2π r

we substitute

          fem = - B L  ( L  )

          fem =  

Let's find the circumference for the 9 s, let's use a direct rule of proportions

If the circumference changes 13cm at t = 1. how much does it change at t=9s

         ΔL = 13cm (9s / 1s) = 117cm

the circumference that is

        L = Lo - ΔL

        L = 167 - 117

        L = 50 cm

let's reduce all magnitudes to the SI system

         L = 0.50 m

          = 0.130 m / s

calculate us

         fem = - 1.00 0.50 0.130

         fem = - 0.0103 V

b) the electromotive force induced in the opposite direction to the change of the radius and is decreasing with time, the current follows the direction of the decreased voltage therefore the current is induced in the opposite direction to the change of the magnetic flux.

If the applied field is in a vertical upward direction, the induced current is clockwise.

Answer:5kgs

Explanation:

The value of the elementary charge is

We have to find a charge equivalent to 3e.

The charge equivalent to 3e will be

Thus, the correct option is c.

Answer:

it depends on the wind and any other conditions but if you have a controlled environment it should take 1 second to get 40 meters but it could go higher in which it could take about 5 seconds to go 200 meters

Explanation:

hope it helped

:)

A beaver runs at a speed of 2.0 m/s with 45 J of kinetic energy, then the mass is approximately 1.74 kg, and this can be calculated by using the  kinetic energy (KE) of an object that is KE = (1/2) ×m × \(v^2\).

KE = (1/2) ×m × \(v^2\).

where m= mass of the object, v=its velocity.

The beaver runs at a speed of 2.0 m/s with 45 J of kinetic energy. Substituting these values into the above equation

45 J = (1/2) ×m × \((2.0 m/s)^2\)

Simplifying this equation:

45 J = (1/2) × m × 4.0\(m^2/s^2\)

45 J = 2 m × 2 \(m^2/s^2\)

45 J = 4 \(m^3/s^2\)

\(m^3\) = 45 J / 4 \(s^2\)

\(m^3\) = 11.25 kg×\(m^2/s^2\)

Taking the cube root of both sides to solve for mass,

m = (11.25 kg×\(m^2/s^2)^(^1^/^3^)\)

m = 1.74 kg (rounded to two decimal places)

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Given that,

Mass of student 1, m₁ = 90 kg

Mass of student 2, m₂ = 60 kg

Speed of student 1, v₁ = 5 m/s

To find,

The velocity of the other student.

Solution,

Using the conservation of momentum to find the velocity of the other student. Let it is v₂.

\(m_1v_1=m_2v_2\\\\v_2=\dfrac{m_1v_1}{m_2}\\\\v_2=\dfrac{90\times 5}{60}\\\\=7.5\ m/s\)

So, the velocity of the other student is 7.5 m/s.

Answer:

The velocity is 2661.5 m/s.

Explanation:

Radius, horizontal distance, d = 309 km

height, h = 25 km

acceleration due to gravity on moon, g =3.71 m/s^2

Let the time taken is t and the horizontal velocity is u.

horizontal distance = horizontal velocity x time

309 x 1000 = u t .... (1)

Use second equation of motion in vertical direction.

\(h = u_yt +0.5 gt^2\\\\25000 = 0 + 0.5\times 3.71\times t^2\\\\t =116.1 s\)  

So, put in (1)

309 x 1000 = u x 116.1

u = 2661.5 m/s

The force between the magnet and the can is the noncontact force. The attraction between the magnet and the can is a pull. Therefore, option B and C are correct.

A magnet can be described as a material that produces a magnetic field and this magnetic field is responsible for the properties of a magnet. The properties magnet is such a force that pulls ferromagnetic materials, such as steel, iron, cobalt, etc., towards it.

A permanent magnet can be described as an object made of a material that can be magnetized and creates its own magnetic field. These type of materials are strongly attracted to a magnet, is known as ferromagnetic, and consist of the elements iron, nickel, and cobalt.

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Your question was incomplete, most probably the complete question was,

Mr. wang works in a recycling center recyclable materials arrive at the center mixed together workers use magnets to separate steel cans from other items which two statements are true about the force between a steel can and a magnet:

A) Gravity pushes the can toward the magnet.

B) The force between the magnet and the can is the noncontact force.

C) The attraction between the magnet and the can is a pull

D)  The attraction between the magnet and the can is a push.

Answer:

Different wavelengths of microwaves (grouped into "sub-bands") provide different information to scientists. Medium-length (C-band) microwaves penetrate through clouds, dust, smoke, snow, and rain to reveal the Earth's surface.

The remaining battery capacity would be 76%, which is still above the 25% limit on discharge depth.

If the electric bicycle can go 100 miles on a full charge, and the owner wants to limit the discharge depth to 25%, then they can only use up to 25 miles of the battery's capacity before needing to recharge.

Since the owner's commute is 12 miles round trip, they can make one round trip without depleting the battery more than 25% of its capacity.

Therefore, the owner can make 2 round trips (2 x 12 = 24 miles) before needing to recharge, but they will still have some battery capacity left.

The remaining battery capacity would be (100 - 24)/100 x 100% = 76%, which is still above the 25% limit on discharge depth. So the owner could make a few more round trips before needing to fully recharge the battery.

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The car is moving at approximately 12.5 meters per second.

The kinetic energy (KE) of an object can be calculated using the formula:

KE = 1/2 * m * \(v^2\)

where

KE = kinetic energy,

m =Mass of the object, and

v = velocity.

In this case, we are given the mass (m) of the car as 1600 kg and the kinetic energy (KE) as 125,000 J. To find the velocity .

Substituting the  values , we have:

125,000 J = 1/2 * 1600 kg *\(v^2\)

Now, we can solve for v by rearranging the equation:

\(v^2\) = (2 * 125,000 J) / 1600 kg

\(v^2\) = 156.25 \(m^2/s^2\)

Taking the square root, we find:

v = √156.25\(m^2/s^2\)

v ≈ 12.5 m/s

Therefore, the car is moving at approximately 12.5 meters per second.

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The efficiency of the engine is 17%.

Given the following data:

To find the efficiency of the engine:

Mathematically, the efficiency of an engine is calculated by using the formula:

\(Efficiency = \frac{E_O}{E_I}\) × \(100\)

Where:

Substituting the given parameters into the formula, we have;

\(Efficiency = \frac{201}{1176}\) × \(100\)

\(Efficiency = 0.171\) × \(100\)

Efficiency = 17%

Therefore, the efficiency of the engine is 17%.

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The capacitance of a capacitor is calculated based on 3 values, area of plates, distance between them and epsilon zero, which is the electric permitivity at vacum.

Louis Armstrong's average velocity in the time trial was approximately 1.078 km/min.

To calculate the average velocity, divide the total displacement by the total time taken. In this case, Louis Armstrong rode his bike 55 km to the east in a time trial lasting 51 minutes.

Average Velocity = Displacement / Time

Displacement = 55 km (since he rode 55 km to the east)

Time = 51 minutes

Average Velocity = 55 km / 51 min

To express the average velocity in km/min, convert the time from minutes to minutes.

1 hour = 60 minutes

Average Velocity = 55 km / 51 min × (1 hour / 60 min)

Average Velocity = 55 km / 51 min × (1/60) hour

Simplifying the expression:

Average Velocity = 1.078 km/min

Therefore, Louis Armstrong's average velocity in the time trial was approximately 1.078 km/min.

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The answers are 1) The value of R2 is not relevant as it implies a downward force on the plank, 2) The reactions at C and D are 66.3 N and 90 N, respectively, and 3) The vertical force at B to lift the plank clear of D is 686.4 N. The reaction at C is zero, and the reaction at D is 61.4 kg.

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Answer:

(a) B = 2.85 × \(10^{-6}\) Tesla

(b) I =  I = 0.285 A

Explanation:

a. The strength of magnetic field, B, in a solenoid is determined by;

r = \(\frac{mv}{qB}\)

⇒ B = \(\frac{mv}{qr}\)

Where: r is the radius, m is the mass of the electron, v is its velocity, q is the charge on the electron and B is the magnetic field

B = \(\frac{9.11*10^{-31*1.0*10^{4} } }{1.6*10^{-19}*0.02 }\)

  = \(\frac{9.11*10^{-27} }{3.2*10^{-21} }\)

B = 2.85 × \(10^{-6}\) Tesla

b. Given that; N/L = 25 turns per centimetre, then the current, I, can be determined by;

B = μ I N/L

⇒    I = B ÷ μN/L

where B is the magnetic field,  μ is the permeability of free space = 4.0 ×\(10^{-7}\)Tm/A, N/L is the number of turns per length.

I = B ÷ μN/L

 = \(\frac{2.85*10^{-6} }{4*10^{-7} *25}\)

I = 0.285 A

Answer:

0.1Ns

Explanation:

Impulse is the product of Force and time

Impulse = Force * Time

Given

Force = 10N

Time = 0.01s

Substitute into the formula

Impulse = 10 * 0.01

Impulse = 10 * 1/100

Impulse = 10/100

Impulse = 0.1Ns

hence the impulse of the hammer is 0.1Ns

The confidence interval is given as lower interval is -0.77 while The upper interval is 1.67

Multivitamin treatment

n1 is 10

σ1 = 1.8

x21 = 5

vitamin C treatment

n2 = 10

σ2 = 1.5

x2 = 4.55

zα/2 = 1.645

The formula for the confidence interval is given as

(x1 - x2) ± zα/2\(\sqrt{\frac{sd1^2}{n1}+\frac{sd2^2}{n2} }\)

When we input the values we have above we would have

CI = (-0.7688550 , 1.668855 )

The the lower interval is -0.77

The upper interval is 1.67

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A random selection of volunteers at a research institute has been exposed to a weak flu virus. After the volunteers began to have flu symptoms, 10 of them were given multivitamin tablets daily that contained 1 gram of vitamin C and 3 grams of various other vitamins and minerals. The remaining 10 volunteers were given tablets containing 4 grams of vitamin C only. For each individual, the length of time taken to recover from the flu was recorded. At the end of the experiment the following data were obtained:

Treated with multivitamin

Days to recover from flu

2.4, 6.4, 9.1, 4.1, 4.6, 6.4, 6.4, 3.2, 6.9, 0.5

Treated with Vitamin C

5.2, 3, 3.6, 5.5, 7.5, 6.7, 1.3, 1.9, 5.3, 5.5

Suppose that it is known that the population standard deviation of recovery time from the flu is 1.8 days when treated with multivitamins and that the

population standard deviation of recovery time from the flu is 1.5 days when treated with vitamin C tablets. Suppose also that both populations are

approximately normally distributed. Construct a 90% confidence interval for the difference µµ₂ between the mean recovery time when treated with

multivitamins (μ,) and the mean recovery time when treated with vitamin C only (H2). Then complete the table below.

Carry your intermediate computations to at least three decimal places. Round your answers to at least two decimal places. (If necessary, consult a list of formulas.)

What is the lower limit of the 90% confidence interval?

What is the upper limit of the 90% confidence interval?

Answer:

D

Explanation:

If the water represents the oceans water then you'd would need to calculate how much of earth is water (96.5)