Answer: C
Explanation:
A. As they do not have a given shape and expand to fill the container, modifying the size of the container modifies the space the gas occupies
B. They are nearly free molecules, which means no bound between them, moving fast and freely around the container
C. NOT A PROPERTY. As said before, as there are no bindings between molecules and move freely, they cannot have a fixed size cause they're always on the move.
D. Because they expand to fill the container, it's easy to them to occupy more space than in any other state, as the container is the only thing that defines how much volume they occupy
Given: H2 + O 2 → H2O1
the reaction occurs at ST.P a) Balance the chemical equation. (1 pts) b) Calculate the number of moles of the reactants needed to obtain 45 liner of H2O (2 pt) 4) Deduce the volume of the reactants (2 pts)
a) The balanced chemical equation for the reaction is: 2H₂ + O₂ → 2H₂O
b) the number of moles of O₂ required is approximately 1.004 moles.
c) approximately 45 liters of H₂ and 22.5 liters of O₂ are needed to obtain 45 liters of H₂O.
a) Balancing the chemical equation:
The balanced chemical equation for the reaction is: 2H₂ + O₂ → 2H₂O
b) Calculating the number of moles of the reactants needed to obtain 45 liters of H₂O:
From the balanced equation, we can see that for every 2 moles of H₂O produced, we need 2 moles of H₂ and 1 mole of O₂. Since the stoichiometry is based on moles, we need to convert the given volume of H2O into moles.
To convert volume to moles, we need to use the ideal gas law, PV = nRT. At standard temperature and pressure (STP), the molar volume of an ideal gas is 22.4 liters.
Given that we have 45 liters of H2O, we can calculate the number of moles as follows:
moles of H₂O = (volume of H₂O) / (molar volume at STP)
= 45 liters / 22.4 liters/mol
≈ 2.008 moles of H₂O
Since the stoichiometry of the reaction is 2 moles of H₂O for every 2 moles of H₂, we need an equal number of moles of H₂. Therefore, the number of moles of H₂ required is also approximately 2.008 moles.
For O₂, since the stoichiometry is 1 mole of O₂ for every 2 moles of H₂O, we need half the number of moles of H₂O. Thus, the number of moles of O₂required is approximately 1.004 moles.
c) the volume of the reactants:
Since the stoichiometry of the balanced equation is 2 moles of H₂for every 1 mole of O₂ and 2 moles of H₂O, we can deduce the volume of the reactants based on their molar volumes at STP.
For 2.008 moles of H₂, the volume can be calculated as follows:
volume of H₂= (moles of H₂) * (molar volume at STP)
= 2.008 moles * 22.4 liters/mol
≈ 45 liters of H₂
For 1.004 moles of O₂, the volume can be calculated similarly:
volume of O₂= (moles of O₂) * (molar volume at STP)
= 1.004 moles * 22.4 liters/mol
≈ 22.5 liters of O₂
Therefore, approximately 45 liters of H₂and 22.5 liters of O₂ are needed to obtain 45 liters of H₂O
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1. Suppose 1.00 g of NaOH is used to prepare 250 mL of an NaOH solution. Compare the expected molarity of this solution to the actual average molarity you measured in the standardization. What do you notice
Answer:
0.1M solution of NaOH
Explanation:
1 mole of NaOH - 40g
? moles - 1 g = 1/40 = 0.025 moles.
Molarity of 1.00g of NaOH in 0.25L (250 mL) = no. of moles/volume
= 0.025/0.25
= 0.1M.
How much heat is required to raise the temperature of 22.6 g of water from −15 °C to 145 °C?
Therefore, 22.6 g of water must be heated from 15 °C to 145 °C using about 15.3 kilojoules (kJ) or 15,251.2 joules (J) of heat.
How much heat is needed to bring 12 g of water from a temperature of 15.4 C to a temperature of 93 C?The specific heat of water must be multiplied by the mass of water to determine the amount of heat required to elevate 12.0 g of water from 15.4 °C to 93 °C. (12.0 g). 120.8 J are required to bring the temperature of 12.0 g of water from 15.4 °C to 93 °C.
You can use the following formula to determine the amount of heat necessary to increase a substance's temperature:
Q = m × c × ΔT
Calculate the change in temperature:
ΔT = 145 °C - (-15) °C = 160 °C
Calculate the heat required:
Q = m × c × ΔT = 22.6 g × 4.184 J/g°C × 160°C = 15,251.2 J or 15.3 kJ (rounded to 2 decimal places)
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Consider the following reaction.
2CH3OH(g)⟶2CH4(g)+O2(g)Δ=+252.8 kJ
Calculate the amount of heat transferred when 38.34 g of CH3OH is decomposed by this reaction at constant pressure.
For a given sample of CH3OH, the enthalpy change during the reaction is 373.0 kJ. What mass of methane gas is produced?
mass of CH4 produced:
The enthalpy of a chemical reaction is defined as the heat absorbed or released in a chemical reaction when chemicals are transformed at constant pressure.
The enthalpy is an extensive property. This means that the enthalpy depends on the amount of matter present.
On the other hand, you have to consider that:
An exothermic reaction is one whose enthalpy value is negative, that is, the system gives off or releases heat to the surroundings (ΔH < 0).An endothermic reaction is one whose enthalpy value is positive, that is, the system absorbs heat from the surroundings (ΔH > 0).Amount of heat transferredIn this case, the balanced reaction is:
2 CH₃OH (l) → 2 CH₄ (g) + O₂ (g)
and the enthalpy reaction ∆H° has a value of 252.8 kJ/mol.
This equation indicates that when 2 moles of CH₃OH, 252.8 kJ of heat is absorbed.
Being the molar mass of CH₃OH 32 g/mole, the mass of 2 moles of the compound can be calculated as:
mass= 2 moles×32 g/mole
mass= 64 grams
So, when 64 grams of CH₃OH, 252.8 kJ of heat is absorbed.
When 64 grams of CH₄ are burned, then you can apply the following rule of three: if 64 grams of CH₃OH releases 252.8 kJ of heat, 38.34 grams of CH₃OH releases how much heat?
heat= (38.34 grams of CH₃OH× 252.8 kJ)÷ 64 grams of CH₃OH
heat= 151.443 kJ
Finally, the quantity of heat transferred is 151.443 kJ.
Amount of mass of CH₃OHIf the enthalpy change during the reaction is 373.0 kJ, you can apply the following rule of three: If 252.8 kJ of heat is released when 2 moles of CH₄ is produced, 373 kJ of heat is released when how many moles of CH₄ is produced?
amount of moles= (373 kJ× 2 moles of CH₄)÷ 252.8 kJ
amount of moles= 2.95 moles of CH₄
Being the molar mass of CH₄ 16 g/mole, the mass of 2.95 moles of the compound can be calculated as:
mass= 2.95 moles×16 g/mole
mass= 47.2 grams
Finally, the mass of methane produced is 47.2 grams.
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help me in my hw,wt is physical change and chemical change Answer it asap plz don't spam
Answer:
Sorry but i don't undertsnad the question.
Explanation:
Answer:
A physical change is a change to the physical—as opposed to chemical—properties of a substance. They are usually reversible. The physical properties of a substance include such characteristics as shape, color, texture, flexibility, density, and mass.
A chemical change happens when one chemical substance is transformed into one or more different substances, such as when iron becomes rust.
Do u want examples ?
PLEASE HELP!
Carbon dioxide consists of a central carbon atom with an oxygen atom on each side. Draw a model of the molecule formed by putting lines between the atoms to represent bonds so that each atom has the correct number of bonds.
Answer:
O=C=O
Explanation:
PLATO ANSWER
In carbon dioxide (CO₂), bonding occurs through a combination of covalent and double covalent bonds between the carbon atom and the oxygen atoms.
Carbon dioxide is a linear molecule composed of one carbon (C) atom and two oxygen (O) atoms. Each oxygen atom shares a double bond with the central carbon atom, resulting in a stable molecular structure.
Covalent bonding involves the sharing of electrons between atoms to achieve a stable electron configuration. In the case of carbon dioxide, each oxygen atom shares four electrons with the carbon atom, and the carbon atom shares four electrons overall with the two oxygen atoms.
The image is attached below.
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Which refers to the passing of a wave through an object?
sound
O interference
O transmission
O frequency
O sound
The term that refers to the passing of a wave through an object is "transmission."
Transmission refers to the process by which a wave passes through an object or medium. In the context of sound, transmission occurs when sound waves travel through different substances, such as air, water, or solids.
When a sound wave encounters an object, it can be transmitted through it, reflected off it, or absorbed by it, depending on the properties of the object and the medium through which the sound is traveling.
For example, when you speak into a microphone, the sound waves produced by your voice travel through the air and are transmitted to the microphone's diaphragm. The diaphragm converts the sound waves into electrical signals, which can then be amplified and reproduced as sound through speakers.
In summary, transmission is the term used to describe the passage of a wave, such as a sound wave, through an object or medium. It is an essential concept in understanding how waves interact with their surroundings and how sound propagates through different materials.
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What is the molecular formula of each of the following
compounds?
(a) empirical formula CH₂, molar mass = 84 g/mol
(b) empirical formula NH₂Cl, molar mass = 51.5 g/mol
(a) the molecular formula of the compound is C₆H₁₂.
(b) the molecular formula of the compound is NH₂Cl.
(a) Given the empirical formula CH₂ and a molar mass of 84 g/mol, we need to determine the molecular formula. To do so, we need to find the factor by which the empirical formula needs to be multiplied to achieve the given molar mass.
The empirical formula CH₂ has a molar mass of 14 g/mol (12 g/mol for carbon + 2 g/mol for hydrogen).
To find the factor, we divide the molar mass by the empirical formula mass:
Factor = (molar mass) / (empirical formula mass) = 84 g/mol / 14 g/mol = 6
Therefore, the molecular formula is obtained by multiplying the empirical formula by the factor:
CH₂ × 6 = C₆H₁₂
Thus, the molecular formula of the compound is C₆H₁₂.
(b) Given the empirical formula NH₂Cl and a molar mass of 51.5 g/mol, we follow a similar approach.
The empirical formula NH₂Cl has a molar mass of 51.5 g/mol (14 g/mol for nitrogen + 2 g/mol for each hydrogen + 35.5 g/mol for chlorine).
To find the factor, we divide the molar mass by the empirical formula mass:
Factor = (molar mass) / (empirical formula mass) = 51.5 g/mol / 51.5 g/mol = 1
Therefore, the molecular formula is the same as the empirical formula: NH₂Cl
Hence, the molecular formula of the compound is NH₂Cl.
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the photoelectric effect is the ___ of electrons when electromagnetic radiation, such as light, hits a material
The photoelectric effect is the emission of electrons when electromagnetic radiation, such as light hits the material.
What is the photoelectric effect?When a substance absorbs electromagnetic radiation, a phenomenon known as the photoelectric effect causes electrically charged particles to be discharged from or within the material.
When light strikes a metal plate, the action is frequently described as the ejection of electrons from the plate.
In a more general definition, the substance may be solid, liquid, or gas, the radiant energy may take the form of infrared, visible, or ultraviolet light, X-rays, or gamma rays, and the discharged particles may include ions (electrically charged atoms or molecules) in addition to electrons.
Therefore, The photoelectric effect is the emission of electrons when electromagnetic radiation, such as light hits the material.
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The density of aluminium is 2.7 g/cm3. Find the mass in grams of a bar of aluminum measuring 1.7 cm by 3.0 cm by 12.9 cm.
Answer: 177.23 g.
Explanation:
the volume of the aluminum bar is
1.7 cm x 3.0 cm x 12.9 cm
= 65.61 cm^3
2.7 g/cm^3 x 65.61 cm^3
177.23g
A grain of sand weighs approximately 0.0102 grams. How many molecules of SiO2 are in a grain of sand? Assume that sand is 100% SiO2.
Answer:
0.5
Explanation:
mol = mass : MM SiO₂
mol = 0.0102 : 60 g/mol = 0.00017
molecules = 0.00017 x 6.02 x 10²³ = 1.0234 x 10²⁰
A student combines a solution of NaCl(aq) with a solution of AgNO3(aq), and a precipitate forms. Assume that 50.0mL of 1.0MNaCl(aq) and 50.0mL of 1.0MAgNO3(aq) were combined. According to the balanced equation, if 50.0mL of 2.0MNaCl(aq) and 50.0mL of 1.0MAgNO3(aq) were combined, the amount of precipitate formed would:_________
Answer:
Based on the given information, the balanced equation is:
NaCl + AgNO3 = AgCl + NaNO3
Now the moles present in 50 ml of 1M NaCl is,
= 50 * 1/1000 mole = 0.05 mole
And the moles present in 50 ml of 1 M AgNO3 is,
= 50*1/1000 mole = 0.05 mole
Therefore, 0.05 mole of NaCl combines with 0.05 mole of AgNO3 to precipitate 0.05 mole of AgCl.
Now in the second case, to balance the chemical equation, 50 ml of 2 M NaCl combines with 50 ml of 1 M AgNO3. So, the moles present in 50 ml of 2 M NaCl will be,
= 50*2/1000 mole = 0.1 mole
However, the amount of AgNO3 in the second case is not changing, therefore, the amount of AgCl precipitated will be,
= 0.1 - 0.05 = 0.05 mole
Therefore, the amount of precipitate would not change as there is no change in the amount of AgNO3.
The amount of precipitate (NaCl) formed would be 0.05 mole
From the question,
We are to determine the amount of precipitate formed.
First, we will write the balanced chemical equation for the reaction
The balanced chemical equation for the reaction is
NaCl(aq) + AgNO₃(aq) → AgCl(s) + NaNO₃(aq)
This means
1 mole of NaCl reacts with 1 mole of AgNO₃ to produce 1 mole of AgCl and 1 mole of NaNO₃
The precipitate formed is AgCl
Now, we will determine the number of moles of each reactant present
For NaClVolume = 50.0 mL = 0.05 L
Concentration = 2.0 M
Using the formula
Number of moles = Concentration × Volume
∴ Number of moles of NaCl present = 2.0 × 0.05
Number of moles of NaCl present = 0.10 mole
For AgNO₃Volume = 50.0 mL = 0.05 L
Concentration = 1.0 M
∴ Number of moles of AgNO₃present = 1.0 × 0.05
Number of moles of AgNO₃ present = 0.05 mole
Since
1 mole of NaCl reacts with 1 mole of AgNO₃ to produce 1 mole of AgCl
Then,
0.05 mole of NaCl will react with 0.05 mole of AgNO₃ to produce 0.05 mole of AgCl
∴ The number of moles of NaCl formed is 0.05 mole
Hence, the amount of precipitate (NaCl) formed would be 0.05 mole
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Which slow carbon reservoir is being turned into a fast carbon reservoir by humans?
classify N a + as cation, anion or neither
What's galactose's empirical formula?
Answer:
C6H12O6
Explanation:
C6H12O6
Calculate the [H+]
and pH of a 0.000295 M
butanoic acid solution. Keep in mind that the a
of butanoic acid is 1.52×10−5
[H⁺]=6.696 x 10⁻⁵
pH = 4.174
Further explanationGiven
The concentration of 0.000295 M (2.95 x 10⁻⁴ M) butanoic acid solution
Required
the [H+] and pH
Solution
Butanoic acid is the carboxylic acid group. Carboxylic acids are weak acids
For weak acid :
\(\tt [H^+]=\sqrt{Ka.M}\)
Input the value :
[H⁺]=√1.52 x 10⁻⁵ x 2.95 x 10⁻⁴
[H⁺]=6.696 x 10⁻⁵
pH = - log [H⁺]
pH = - log 6.696 x 10⁻⁵
pH = 5 - log 6.696
pH = 4.174
In a neutralization reaction with a strong acid or base, all of the hydrogens from the acid and the hydroxides from the base react to form water.
Balance the following neutralization reaction:
H3PO4 (aq) + NaOH (aq) â H2O (l) + Na3PO4 (aq)
Enter the appropriate coefficient to the left of the respective term. In the event that your coefficient would be "1" be sure to write "1" as opposed to leaving it blank.
Answer:
H3PO4 + 3NaOH ----> Na3PO4 + 3H2O
Explanation:
The balanced equation is given below
H3PO4 + 3NaOH ----> Na3PO4 + 3H2O
Answer:
\(H_3PO_4 (aq) + 3NaOH (aq) \rightarrow 3H_2O (l) + Na_3PO_4 (aq)\)
Explanation:
Hello,
In this case, for the given reaction:
\(H_3PO_4 (aq) + NaOH (aq) \rightarrow H_2O (l) + Na_3PO_4 (aq)\)
We must assure the law of conservation of mass is respected, so we equal the number of atoms at each side of the equation by adding the stoichiometric coefficients to the left of each compound as shown below:
\(H_3PO_4 (aq) + 3NaOH (aq) \rightarrow 3H_2O (l) + Na_3PO_4 (aq)\)
So the coefficients are 1, 3, 3 and 1 respectively for each species in the chemical reaction.
Regards.
A solution that contains 3 grams of solute dissolved in 100 millimeters of solution is:
a) 3% m / m
b) 3% m / v
c) 10% m / v
Answer:
the answer is correct part another is a part
Explanation:
c part
Based on the context in paragraph 4 fossils refers to
Answer:
i am not sure i am really just doing it for the points but yea
Explanation:
im just ok lol i wish you guys the best
Answer:
shtfu
Explanation:
a tire will burst if the air inside it reaches a pressure greater than 1.4 x 10^3 kpa. at what temperature will the tire burst if it has a volume of 30L and contains 2.5 mol of air? assume that the air behaves as an ideal gas. assuming that these values are representative, do you need to worry about your car tire bursting from overheating of they are in good condition?
This extremely high temperature indicates that under normal conditions, you do not need to worry about your car tire bursting from overheating as it is unlikely to reach such extreme temperatures.
To determine the temperature at which the tire will burst, we can use the ideal gas law equation:
PV = nRT
Where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.
Rearranging the equation to solve for temperature, we have:
T = PV / (nR)
Given that the pressure threshold for bursting is 1.4 x 10^3 kPa, the volume is 30 L, and the number of moles of air is 2.5 mol, we can substitute these values along with the ideal gas constant R = 8.314 J/(mol K) into the equation.
T = (1.4 x 10^3 kPa) * (30 L) / (2.5 mol * 8.314 J/(mol K))
Converting kPa to Pa and L to m^3, and simplifying the equation, we find:
T ≈ 20,993 K
This extremely high temperature indicates that under normal conditions, you do not need to worry about your car tire bursting from overheating as it is unlikely to reach such extreme temperatures.
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Are pressure and volume directly or inversely proportional
Pressure and volume can be regarded as the entity that is inversely proportional.
What is the relationship between Pressure and volume?It should be noted that this explanatin an be done using the law in chemistry which is the Boyle's law which states that, for a given amount of gas and constant temperature, the volume is inversely proportional to the pressure.
However the Equal quantities of all gases can be seen to have same number of molecules when subjected to the same temperature and pressure (Avogadro's law).
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How many total atoms are there in 62.5 g
of carbon disulfide ( CS2)?
Total atoms:
Answer:
first molecular mass of cs2= 12+2×32=76amu
no of moles=62.5/76=0.822moles
total no of molecules=6.022×\(10^{23}\)×0.822=4.95×\(10^{23}\)
total no of atoms ( one carbon disulfide has 3 atoms)=3×4.95×\(10^{23}\)=14.85×\(10^{23}\) atoms
Explanation:
i hope you find it helpful, have a nice day
In 62.5 g of carbon disulfide (CS2), there are approximately 1.48 x 10^24 total atoms. This is calculated by first finding the number of moles in 62.5 g, then multiplying this by the number of atoms in each mole (Avogadro's number).
Explanation:To calculate the total atoms in a 62.5 g of carbon disulfide (CS2), you need to first find the molar mass of CS2 which is 76.14 g/mol (12.01 g for C + 2 * 32.06 g for S). Using Avogadro's number (6.02 x 10^23) which represents the number of entities in a mole, we can calculate the number of moles and then the total number of atoms.
First, calculate the number of moles in 62.5 g of CS2: 62.5 g / 76.14 g/mol = 0.820 moles
Second, calculate the total atoms: 0.820 moles * 3 atoms/mole * 6.02 x 10^23 = 1.48 x 10^24 atoms
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Why is scientist Robert Hazen using pressure bombs to blow up minerals
Answer:
Hazen uses small metal cylinders called pressure bombs to blast minerals with insanely high pressures and temperatures. He's using that knowledge to figure out how ancient minerals might have been involved in the evolution of the first primitive life-forms.
Explanation:
Consider the structure of chloride ion. Draw the conjugate acid for chloride ion. Remember to include charges and non-bonding electrons where necessary. Select Draw Rings More Erase H CI C17
The chloride ion (Cl-) has a single negative charge and a full octet of electrons in its outermost shell. It has a tetrahedral shape, with three equatorial lone pairs and one axial bond to a hydrogen or other positively charged ion.
The conjugate acid of chloride ion is HCl (hydrogen chloride), which is formed when the chloride ion accepts a proton (H+) from an acid. The resulting molecule has a positive charge and a linear shape, with a single bond between the hydrogen and chlorine atoms.
The conjugate acid of chloride ion, HCl, is a strong acid that readily donates a proton (H+) to a base to form the chloride ion. In water, HCl dissociates completely to form H+ and Cl- ions. The hydrogen ion (H+) has a positive charge and no electrons, while the chloride ion (Cl-) retains its original tetrahedral shape and three lone pairs of electrons.
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Balance equation of gas burns carbon dioxide and water
gas = methane
burn with O₂ (oxygen)
CH₄(g) + 2O₂(g) → CO₂(g) + 2H₂O(l)
how do you balance this equation
2h2s+3o2+so2
The balanced equation is: 4 \(H_2S\)+ 3 \(O_2\)→ 4 \(SO_2\)+ 8 \(H_2O\)
The given chemical equation is unbalanced. To balance it, we need to adjust the coefficients in front of each chemical species until the number of atoms on both sides of the equation is equal.
The unbalanced equation is:
2 \(H_2S\)+ 3 \(O_2\)→ \(SO_2\)
Let's start by balancing the sulfur (S) atoms. We have two sulfur atoms on the left side and one sulfur atom on the right side. To balance the sulfur, we can place a coefficient of 2 in front of the \(SO_2\):
2 \(H_2S\)+ 3 \(O_2\)→ 2 \(SO_2\)
Now, let's balance the hydrogen (H) atoms. We have four hydrogen atoms on the left side (2 from each \(H_2S\)) and none on the right side. To balance the hydrogen, we can place a coefficient of 4 in front of the water (H2O) on the right side:
2 \(H_2S\)+ 3 \(O_2\)→ 2 \(SO_2\)+ 4 \(H_2O\)
Finally, let's balance the oxygen (O) atoms. We have six oxygen atoms on the right side (3 from \(O_2\) and 3 from 2 \(SO_2\)) and three on the left side (2 from \(H_2S\)). To balance the oxygen, we can place a coefficient of 3/2 in front of the O2:
2 \(H_2S\)+ (3/2) \(O_2\)→ 2 \(SO_2\)+ 4 \(H_2O\)
To remove the fractional coefficient, we can multiply all coefficients by 2:
4 \(H_2S\) + 3 \(O_2\)→ 4 \(SO_2\)+ 8 \(H_2O\)
Now the equation is balanced, with an equal number of atoms on both sides. The balanced equation is:
4 \(H_2S\)+ 3 \(O_2\)→ 4 \(SO_2\)+ 8 \(H_2O\)
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When a red blood cell is placed in a solution that is more concentrated than the interior of the cell, it can be damaged. Saline solution is intended to be isotonic with animal cells having an approximate concentration of 0.900g sodium chloride per 100 mL of water. To prepare 1.00 liter of saline solution, how many grams of sodium chloride would be needed?
Given that there is a concentration of 0.9 gram of NaCl per 100mL of water.
Therefore for 1000mL ,i.e., 1 litre of water, NaCl requirement is 0.900 × 10 = 9 grams.
Make an argument about the following claim: Exothermic reactions only release thermal energy
Exothermic reactions only release thermal energy, raising the temperature of the immediate environment. The environment is cooled through an endothermic process that absorbs heat.
What is an exothermic reaction ?An exothermic process is one in which energy is given off as heat or light. In contrast to an endothermic process, which draws energy from its surroundings, an exothermic reaction transfers energy into the environment.
The most exothermic reaction is the burning of methane because it generates a significant quantity of heat.
Thus, Exothermic reactions only release thermal energy.
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Please help me out I have 20 mins, show work !
Answer:
8)Dinitrogen tetraoxide
9)+5
10)NH4HSO4
Explanation:
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Xenon-133 has a half life of 5.2 days. A 237 gram sample of Xenon is collected and stored. It is later measured to be 29.625 grams. How long has it been in storage?
A. 15.6 days
B. 39.9 days
C. 20.8 days
D. 8 days
Answer:
A. 15.6 days
Explanation:
We have a general formula used to solve for questions dealing with half life.
N(t) = No (1/2)^t/t½
Where
N(t) = Quantity of sample left after t days
No = Initial amount of sample
t½ = Half life of sample
t = Duration or time required for sample to decay
In the above question, we are asked to determine how long(time) that the sample has been in storage.
The formula for time (t) has been derived as:
t =[ t½ × In(Nt/No)] ÷ - In 2
Where
No = 237 grams
N(t) = 29.625 grams
t½ = 5.2 days
t = ????? Unknown
t = [ t½ × In(Nt/No)] ÷ - In 2
t = [ 5.2 × In(29.625/237)] ÷ - In 2
t = [5.2 × -2.0794415417] ÷ - In 2
t = -10.813096017 ÷ - ln 2
t = 15.6 days
Therefore, the sample has been in storage for 15.6 days.