which of the following is not a process that transports carbon between reservoirs in the carbon cycle? vapor deposition sediment burial photosynthesis volcanic eruptions burning of fossil fuels

Answer:

D. gravity

hope this helps

The significant figure in the numbers are as follows:

Significant figures refers to digits which are non-zeroes found in a given number. Also, if zeroes are found between non-zero digits, the zeroes are counted as significant numbers.

The number of non-zero digits gives the number of significant figures in a number.

Significant figures are used in approximating values to determine to how many places the digits in a number are significant.

Considering the given numbers:

A) 1.06 s has 3 sig figs

B) 5003 mL has 4 sig figs

C) 10890 kg has 4 sig figs

D) 50 students has 1 sig figs

E) 0.00001 m has 1 sig figs

F) 100.0 cm² has 1 sig figs

G) 0.00800 s has 1 sig figs

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Answer:Prokaryotic cells carry out cellular respiration within the cytoplasm and eukaryotic cells carry out respiration in the mitochondria

Explanation:

Answer: The magnesium ion Mg2+ is formed when the magnesium atom loses the two electrons from its outer shell to form a stable ion with a noble gas configuration.

Explanation:

Solution :

Partition coefficient Kd

\($=\frac{\frac{\text{mass of caffeine in } CH_2Cl_2}{\text{volume of } CH_2Cl_2}}{\frac{\text{mass of caffeine in water}}{\text{volume of water}}}$\)

= 9.0

A). 1 x 200 mL extraction :

Let m be the mass of caffeine in the water

Mass of caffeine in \($CH_2Cl_2$\) = 100 - m

\($\frac{\frac{100-m}{200}}{\frac{m}{200}} = 9.0$\)

\($=\frac{100-m}{m} = 9.0$\)

\($= 10 m = 100$\)

m = 10

Mass remaining in coffee = m =  10 mg

B). 2 x 100 mL extraction :

First extraction :

Let \($m_1$\) be the mass of caffeine in the water

Mass of caffeine in \($CH_2Cl_2$\) = \($100-m_1$\)

\($\frac{\frac{100-m_1}{100}}{\frac{m_1}{200}} = 9.0$\)

\($=\frac{100-m_1}{m_1} = 4.5$\)

\($ 5.5 \ m_1 = 100$\)

\($m_1$\)  = 18.18

Mass remaining in coffee = \($m_1$\) =  18.18 mg

Second Extraction :

Let \($m_2$\) be the mass of caffeine in the water

Mass of caffeine in \($CH_2Cl_2$\) = \($18.18-m_2$\)

\($\frac{\frac{18.18-m_2}{100}}{\frac{m_2}{200}} = 9.0$\)

\($=\frac{18.18-m_2}{m_2} = 4.5$\)

\($ 5.5 \ m_2 = 18.18$\)

\($m_2$\)  = 3.3

Mass remaining in coffee = \($m_2$\) =  3.3 mg

When dissolved in water, most Group 1 metal salts can be described as strong electrolytes.

When Group 1 metal salts are dissolved in water, they can be described as strong electrolytes. This is because Group 1 metals, such as lithium (Li), sodium (Na), potassium (K), and so on, readily lose their outermost valence electron to form positive ions (cations). These cations then dissociate completely in water, separating from the anions to which they were originally bonded.

The dissociation of Group 1 metal salts in water results in the formation of positively charged metal ions and negatively charged non-metal ions (anions). These ions are free to move and conduct electric current, making the solution a good conductor of electricity. The complete dissociation of Group 1 metal salts in water and the presence of freely moving ions make them strong electrolytes.

Strong electrolytes are substances that ionize completely or almost completely in solution, producing a high concentration of ions. This is in contrast to weak electrolytes, which only partially ionize and produce a lower concentration of ions.

In summary, when Group 1 metal salts are dissolved in water, they form strong electrolytes due to their ability to dissociate completely into ions, leading to a high concentration of freely moving ions in the solution, thus enabling efficient electrical conductivity.

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Answer:

B. are openings in the earth surface

Answer: Te Tellurium

Explanation:

All the elements under VlA (Group 16) contain 6 valence electrons, but it specifically asks for period 5 which is a row going left to right on the periodic table.

The change in temperature (°C) of the water is 43°C.

The change in the temperature of the water is calculated using the formula of heat change as follows:

Heat change = mass * specific heat capacity * temperature change

Heat change = heat generated in burning 2.065 g of propane

Heat generated in burning 2.065 g of propane = 2222 kJ * 2.065/44.11

Heat generated in burning 2.065 g of propane = 104.022 kJ or 104022 J

moles of water = mass/molar mass

molar mas of water = 18.0 g/mol

moles of water = 575.0 / 18 = 31.944 moles

Temperature change = Heat / (mole of water * molar heat capacity)

Temperature change = 104022 / (31.944 * 75.38)

Temperature change = 43°C

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For addition or subtraction operations, we must first round off the values of significant figures in order to make them to the same number of decimal places:

Let's round 4.21 to 4.2.

Now we do the operation:

5.4 - 4.2 = 1.2

After the calculations, we choose as a reference the number with the fewest decimal places. For subtraction operations, we must follow the same reasoning as for addition.

Answer: 1.2

The correct answer is 76.9 g of \(Cl_{2}\) is required to react with 19.5 g of \(Al\). Therefore, the correct option is: 76.9 g.

What is Atomic Mass?

Atomic mass, also known as atomic weight or relative atomic mass, is a measure of the mass of an atom of a chemical element. It is expressed in atomic mass units (amu) or unified atomic mass units (u). Atomic mass is a weighted average mass of the naturally occurring isotopes of an element, taking into account their relative abundances.

The balanced chemical equation for the reaction is:

\(2Al\) (s) + 3\(Cl_{2}\) (g) → \(Al_{2}\)\(Cl_{6}\)

From the equation, we can see that the molar ratio between \(Al\)and Cl2 is 2:3. This means that 2 moles of \(Al\) react with 3 moles of \(Cl_{2}\)

To find out how many grams of \(Cl_{2}\) are required to react with 19.5 g of \(Al\) we need to convert the given mass of \(Al\) to moles using its molar mass, and then use the mole ratio from the balanced equation to calculate the amount of \(Cl_{2}\).

The molar mass of \(Al\) is 27 g/mol, and the molar mass of \(Cl_{2}\) is 2 * 35.45 g/mol = 70.9 g/mol.

Moles of \(Al\)= Mass of \(Al\)/ Molar mass of\(Al\)

Moles of \(Al\) = 19.5 g / 27 g/mol ≈ 0.722 mol

According to the mole ratio from the balanced equation, 2 moles of \(Al\)react with 3 moles of \(Cl_{2} .\)

Moles of \(Cl_{2}\)= Moles of \(Al\) * (3 moles of \(Cl_{2}\) / 2 moles of \(Al\))

Moles of \(Cl_{2}\) = 0.722 mol * (3/2) ≈ 1.083 mol

Now, we can convert moles of \(Cl_{2}\) to grams using its molar mass.

Mass of\(Cl_{2}\) = Moles of \(Cl_{2}\) * Molar mass of \(Cl_{2}\)

Mass of\(Cl_{2}\) = 1.083 mol * 70.9 g/mol ≈ 76.9 g

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Answer:

a. 1 mole O2

b. 2 moles H2O

Explanation:

a. 2 moles H2 x \(\frac{1 mole O2}{2 moles H2}\) = 1 mole O2

B. 2 moles H2 x \(\frac{2 moles H2O}{2 moles H2}\) = 2 moles H20

Answer: The set of quantum numbers for the electrons in Be atom are (2, 1, -1, 1/2), (1, 0, 0, 1/2), (1, 0, 0, -1/2) and (2, 0, 0, -1/2)

Explanation:

There are 4 quantum numbers:

Berylium (Be) is the 4th element of periodic table having electronic configuration of \(1s^22s^2\)

For first electron:

\(n=1\\l=0\text{ (for s-subshell)}\\m=0\\s=+\frac{1}{2}\)

For second electron:

\(n=1\\l=0\\m=0\\s=-\frac{1}{2}\)

For first electron:

\(n=2\\l=0\text{ (for s-subshell)}\\m=0\\s=+\frac{1}{2}\)

For second electron:

\(n=2\\l=0\text{ (for s-subshell)}\\m=0\\s=-\frac{1}{2}\)

Hence, the set of quantum numbers for the electrons in Be atom are (2, 1, -1, 1/2), (1, 0, 0, 1/2), (1, 0, 0, -1/2) and (2, 0, 0, -1/2)

Answer:

methanide

Explanation:

not sure

rise and cold air

it doesn't fall cause I already fall inlove with levi

Answer:

Is this question multiple choice if it is i can most likely answer it!

Explanation:

The scandium III oxide would act as a base and the reaction equation would be; \(Sc_{2} O_{3} + 6HCl + xH_{2} O ----- > 2ScCl_{3} .xH_{2} O+ 3H_{2} O\)

We need to  look again at the nature of the solution that is formed by the scandium III oxide. Let us remind ourselves that the oxides of the metals are basic in nature. This implies that the oxide of a base would react to form a base.

The implication of this is that the oxide of any metal is going to work just like a base. What i mean by saying that it would work as a base is that it is going to react with and acid in order to form salt and water only.

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The balanced equation for the reaction between cobalt(III) nitrate (\(Co(NO_3)_3\)) and potassium sulfide (\(K_2S\)) is:

\(3 Co(NO_3)3 + 2 K_2S - > 3 CoS + 6 KNO_3\)

In the balanced equation, the stoichiometric coefficient for potassium nitrate (\(KNO_3\)) is 6.

A molecular reaction is a chemical reaction in which two or more molecules combine to form a new compound. Molecular reactions include a wide range of natural and synthetic phenomena, ranging from enzyme-catalyzed transformations to protein folding and drug binding. In a chemical equation, stoichiometric coefficients reflect the relative number of molecules of each reactant and product.

Potassium nitrate is a chemical compound that is commonly used in fertilizers, fireworks, and rocket propellants. It is an ionic salt with the formula \(KNO_3\). Potassium nitrate is a white crystalline substance that is soluble in water. It is also known as saltpeter.What is the balanced chemical equation for the reaction of potassium nitrate and potassium sulfide?\(Co(NO_3)_3 + K_2S → CoS + 3KNO_3\)

This is the balanced chemical equation for the reaction of potassium nitrate and potassium sulfide. The stoichiometric coefficient for potassium nitrate is 3, which means that three molecules of KNO3 are required to react with one molecule of \(K_2S\). On the other hand, the stoichiometric coefficient for \(Co(NO_3)_3\) is 1, which means that only one molecule of  \(Co(NO_3)_3\) is required to react with one molecule of \(K_2S\) .

The stoichiometric coefficient for CoS is also 1, which means that one molecule of CoS is produced for every molecule of \(K_2S\)that reacts.

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The acidity or alkalinity of a solution depends upon its hydronium ion concentration and hydroxide ion concentration. The pH scale is introduced by the scientist Sorensen. Here the given solution of pH 11.9 is basic.

The pH of a solution is defined as the negative logarithm to the base 10 of the value of the hydronium ion concentration in moles per litre. At 298 K, For pure water pH will be 7 and concentration of H₃O⁺ is 10⁻⁷M.

For a basic solution the pH will be greater than 7 and the concentration of H₃O⁺ will be less than  10⁻⁷M. For an acidic solution pH will be less than 7 and concentration of H₃O⁺ will be greater than 10⁻⁷M.

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A solution with a pH of 11.9 is considered a basic or alkaline solution.

This indicates a high concentration of hydroxide ions (OH-) in the solution. The pH scale is a measure of the acidity or basicity of a solution, ranging from 0 (most acidic) to 14 (most basic). A pH of 7 indicates a neutral solution, while a pH greater than 7 indicates a basic solution.

In practical terms, a solution with a pH of 11.9 could be found in various settings, such as in the alkaline batteries, household cleaning products, or industrial chemicals. Such a solution can be corrosive to metals and harmful to human skin and eyes. It is important to handle such solutions with care and appropriate protective equipment.

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Answer:2

Explanation: Acids do indeed conduct electricity (Love the one peice pfp btw)

Answer:

Explanation:

The reaction of benzoyl chloride with NH₄OH to produce benzamide is:

Benzoyl chloride + ammonia → Benzamide + NH₄Cl

Molar mass of benzoyl chloride: 140.57 g/mol. Density 1.21g/mL

Molar mass benzamide: 121.14g/mol.

To know percent yield you must know the theoretical yield of the reaction (How many grams are produced assuming a yield of 100%). Percent yield will be (Actual yield / Theoretical Yield) ₓ 100

Moles of 2.83mL of benzoyl chloride are:

2.83mL ₓ (1.21g/mL) ₓ (1mol / 140.57g) = 0.02436 moles of benzoyl chloride.

As 1 mole of benzoyl chloride produce 1 mole of benzamide (Theoretical yield), theoretical moles of benzamide produced are 0.02436. In mass:

0.02436 moles ₓ (121.14g / mol) = 2.95g of benzoyl chloride

As there are produced just 1.95, percent yield is:

(1.95g / 2.95g) ₓ 100 = 66.1%

Answer:

C3H8 + 502+3CO2 + 4H20

Explanation:

In order to get this answer you would have to would balance out the carbons on the products side by multiplying CO2 by 3. The new equation will be 

C3H8 + 02 ----> 3CO2 + H20

Now, that the carbons are balanced, we will look at the hydrogens. We can multiply the number of waters on the product side by 4, to make 4 H20 molecules. This gives both sides of the equation 8 hydrogens. Next we can check our oxygens. There will be 10 oxygens on the products side and 2 on the reactants so to balance these out, we multiply the 02 on the reactants side by 5. 

Answer:

Water sweated by water from the leaf cells evaporating into the air, which pulls water and nutrients from the leaf into the air.

Answer:

Its A - A solution with a PH of 2 is a base.

Explanation:

What is a pH of 2?

Strong acids and bases

The pH is then equal to minus the logarithm of the concentration value. Hydrochloric acid (HCl) is an example of a strong acid. The pH of a 0.01M solution of HCl is equal to −log10(0.01), that is, pH = 2.

Answer:

I would say 4.) Biomass

Explanation:

This looks like the best possible answer because it is plant based. Worst case scenario we could run out of plants. In comparison, wind will pretty much always be around along with wave/tidal power and solar.

Answer:

see below

Explanation:

A. The given reaction releases energy, indicating that it is an exothermic reaction.

B. The △H value for the reaction can be written as △H = -571.7 kJ, with a negative sign indicating the energy is released.

C. The balanced equation for the reaction between hydrogen and oxygen to form water is:

2H2(g) + O2(g) → 2H2O(l)

D. To calculate the amount of energy released when 10.0g of hydrogen is reacted with an excess of oxygen, we need to first determine the amount of hydrogen involved in the reaction.

The molar mass of hydrogen is 1.008 g/mol, so 10.0 g of hydrogen is equivalent to 10.0 g / 1.008 g/mol = 9.92 mol of hydrogen.

From the balanced equation, we can see that 2 mol of hydrogen is required for every 1 mol of oxygen, so the amount of oxygen involved in the reaction is twice the amount of hydrogen.

Therefore, the amount of oxygen needed for 9.92 mol of hydrogen is 2 × 9.92 mol = 19.84 mol.

Assuming that there is an excess of oxygen, all of the hydrogen will react, so the limiting reactant is oxygen.

Using the △H value of -571.7 kJ, we can calculate the amount of energy released as follows:

-571.7 kJ / 2 mol H2 = -285.9 kJ/mol H2

So the energy released when 10.0 g of hydrogen reacts with an excess of oxygen is:

-285.9 kJ/mol H2 × 9.92 mol H2 = -2836.53 kJ

Therefore, the reaction releases 2836.53 kJ of energy when 10.0 g of hydrogen reacts with an excess of oxygen.

Answer:

With the adsorption of cations like zinc as Zn (OH)+ or ZnCl+ or both, the anion exchange is known to increase. The solid phase has an impact on the anions' concentration in the soil solution. Anions are negatively adsorbed as a result of the exchange complex's overall negative charge.

Answer:

12 moles Cl⁻

Explanation:

To find the moles Cl⁻, you need to (1) calculate the moles of magnesium chloride (MgCl₂) using the molarity equation and then (2) convert moles MgCl₂ to moles Cl⁻ (via the mole-to-mole ratio from formula subscripts). It is important to arrange the conversions in a way that allows for the cancellation of units.

Molarity (M) = moles / volume (L)

2 M = moles / 3 L

6 = moles MgCl₂

1 MgCl₂ = 1 Mg²⁺ and 2 Cl⁻

6 moles MgCl₂            2 moles Cl⁻
------------------------  x  -----------------------  =  12 moles Cl⁻
                                   1 mole MgCl₂

If Sherman suggests that reproduction always creates individuals with adaptive traits, then he/she is not correct because variation may lead to non-adaptive phenotypes.

The presence of genetic variation in individuals of a given population is not adaptive per se, but instead, it provides the raw material for natural selection that leads to the differential survival and reproduction of the most adaptive phenotypes.

The genetic variation in individuals of a given population does not crate adaptive traits and it may derive from sexual reproduction.

Therefore, with this data, we can see that the presence of genetic variation in individuals of a given population may or not be adaptive in the function of the environment in which the individual produced by means of sexual reproduction is developed and therefore it is an advantage for the population but the individual may be harmful.

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