Which of the following is not a measurement?

0.50 ppm

120

65 mph

24°C

Answer:

I think the dish contracts and shrinks

Answer:

The dish cracks or breaks.

Explanation:

When glass changes temperature rapidly, it may undergo thermal shock. This is stress that is produced by a sudden change in temperature.

Answer:

1.43 moles N₂

Explanation:

To determine the moles of nitrogen gas (N₂), you need to multiply the given value by the molar mass. The molar mass is a ratio comparing the mass (g) of nitrogen gas per 1 mole. It is important to arrange this ratio in a way that allows for the cancellation of units (grams should be in the denominator). The final answer should have 3 sig figs to match the given value.

Molar Mass (N₂): 2(14.007 g/mol)

Molar Mass (N₂): 28.014 g/mol

 40.0 grams N₂                1 mole
-------------------------  x  ------------------------  =  1.43 moles N₂
                                    28.014 grams

Balance the half-reactions to guarantee that the number of electrons transferred in both reactions is the same:

NO3- + 8H+ + 10e- N2 + 4H2O H2 2H+ + 2e- NO3- + 8H+ + 10e-

The next step is to figure out how many electrons are moved when 145 molecules of H2 are oxidized. We can see from the balanced equation for the H2 half-reaction that 1 molecule of H2 makes 2 electrons:

2H+ + 2e- → H2

As a result, 145 molecules of H2 will yield:

145 molecular units H2 has two protons per molecule. 290 electrons Equals H2

Finally, we can use the denitrification reaction balanced equation to calculate how many molecules of N2 are created for 290 electrons:

1 molecule of N2 is produced by 10 electrons.

Therefore, 1 molecule N2 290 electrons/10 electrons = 29 molecules N2

29 molecules of N2 gas will be created.

To answer the second query, we must balance the half-reactions:

SO42- + 8H+ + 8e- H2S + 4H2O CO2 + 8H+ + 8e- CH3COO- + 2H2O SO42- + 8H+ + 8e- H2S + 4H2O

The balanced formulae show that 8 electrons are transferred in both half-reactions. As a result, in order to oxidize 48 molecules of CH3COO-, 6 molecules of SO42- must be reduced:

There are 48 nuclei CH3COO- 8 electrons per atom 384 protons = CH3CO-

384 electrons (eight electrons per atom) 48 units of SO42- SO42-

As a result, 48 molecules of CH3COO- reduced to CO2 will yield:

six electrons 4 H2O/molecule SO42- 24 units of SO42- H2O

The answer is that 24 molecules of water will be created.

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Answer:

I would say to keep the oxygen we breathe in or to filter out the bed uv rays from the sun like radiation.

Explanation:

im guessing

The partial pressure of \(N_2\)is 165.6 kPa and the partial pressure of \(H_2\)is 434.4 kPa.

To calculate the partial pressures of \(H_2\)and \(N_2\)in the 10dmcube container, we need to use the ideal gas law equation, which states that the pressure of a gas is directly proportional to its number of moles and temperature, and inversely proportional to its volume.

First, we need to calculate the number of moles for each gas. Since we are given the volume of each gas and the volume of the container, we can use the formula:

Number of moles = Volume / Molar volume

The molar volume is the volume occupied by one mole of a gas at a given temperature and pressure. At standard temperature and pressure (STP), the molar volume is 22.4 L/mol.

For \(N_2\), the number of moles is 2 dmcube / 22.4 L/mol = 0.089 mol
For \(H_2\), the number of moles is 5 dmcube / 22.4 L/mol = 0.223 mol

Next, we can calculate the partial pressures of each gas using the formula:

Partial pressure = (Number of moles / Total number of moles) * Total pressure

The total pressure is the sum of the pressures of each gas:

Total pressure = Pressure of N2 + Pressure of \(H_2\)

Given that the pressure of N2 is 100 kPa and the pressure of \(H_2\)is 500 kPa, we have:

Total pressure = 100 kPa + 500 kPa = 600 kPa

Now we can calculate the partial pressure of \(N_2\):

Partial pressure of \(N_2\)= (0.089 mol / (0.089 mol + 0.223 mol)) * 600 kPa = 165.6 kPa

Similarly, we can calculate the partial pressure of \(H_2\):

Partial pressure of H2 = (0.223 mol / (0.089 mol + 0.223 mol)) * 600 kPa = 434.4 kPa

Therefore, the partial pressure of \(N_2\)is 165.6 kPa and the partial pressure of \(H_2\)is 434.4 kPa.

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Answer:

Substances which are non heat-resistant and volatile organic liquid with flammable vapor.

Explanation:

Bunsen Burner are used as a source of fire in the laboratory for heating up substances. Extra care however should be taken during heating in order to prevent fire or other forms of accidents.

Heating of mind heat resistant substances should be frowned at as the substances may get heated up and melt thereby exposing the liquid substances which may be flammable to fire thereby causing fire outbreak.

Heating of volatile organic liquid with flammable vapor should also be discouraged to prevent fire accidents.

Answer:

true

Explanation:

They all have a hydrocarbon plus oxygen.

The given statement that "all combustion reactions have oxygen as a reactant" is true. Combustion is a type of chemical reaction where a fuel (usually a hydrocarbon) combines with oxygen gas to produce heat, light, and new chemical compounds, such as carbon dioxide and water.

For combustion to occur, there must be a fuel source, oxygen, and a source of ignition, such as a spark or heat. Oxygen acts as a reactant because it combines with the fuel source to produce the new compounds. Without oxygen, the reaction cannot occur. It is important to note that not all reactions involving oxygen are combustion reactions. For example, rusting of iron is a reaction that involves oxygen, but it is not a combustion reaction.

In combustion reactions, the heat and light produced are often used for industrial processes, transportation, or heating. However, the reaction can also be destructive if not controlled, such as in wildfires or explosions. In conclusion, all combustion reactions have oxygen as a reactant, as it is necessary for the reaction to occur and produce the desired products.

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The initial temperature of the water that resulted in the final temperature of the water-metal mixture is 20.7 ⁰C.

"Your question is not complete, it seems to be missing the following information;"

the specific heat capacity of the metal is 0.45 J/g⁰C.

The given parameters;

The initial temperature of the water will be calculated by applying the principle of conservation of energy;

heat gained by water = heat lost by metal

\(Q_{water} = Q_{metal}\)

\(m_wc_w \Delta t_w = mc\Delta t\)

where;

\(c_w\) is the specific heat capacity of the water = 4.184 J/g⁰C.

Substitute the given values;

45 x 4.184 x (22 - t) = 8.5 x 0.45 x (85 - 22)

4142.16  - 188.28t = 240.98

188.28t  = 4142.16  - 240.98

188.28t  = 3901.18

\(t = \frac{3901.18}{188.28} \\\\t = 20.7 \ ^0 C\)

Thus, the initial temperature of the water that resulted in the final temperature of the water-metal mixture is 20.7 ⁰C.

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The metal X has an approximate molar mass of 42.36 g/mol and the metal is most likely calcium.

The molar mass of the metal carbonate XCO₃ and identify the metal X, we need to calculate the number of moles of XCO₃ and CO₂ using the given masses and molar masses.

The molar mass of CO₂ (carbon dioxide) is 12.011 g/mol (for carbon) + 2 * 15.999 g/mol (for oxygen) = 44.01 g/mol.

The number of moles of CO₂ can be calculated using the formula:

moles of CO₂ = mass of CO₂ / molar mass of CO₂

moles of CO₂ = 0.855 g / 44.01 g/mol

moles of CO₂ ≈ 0.01944 mol

Since the reaction stoichiometry is 1:1 between XCO₃ and CO₂, the number of moles of XCO₃ is also approximately 0.01944 mol.

molar mass of XCO₃ = mass of XCO₃ / moles of XCO₃

molar mass of XCO₃ = 2.012 g / 0.01944 mol

molar mass of XCO₃ ≈ 103.38 g/mol

The molar mass of XCO₃ is approximately 103.38 g/mol.

To determine the metal X:

molar mass of X = molar mass of XCO3 - molar mass of CO3

molar mass of X = 103.38 g/mol - (12.011 g/mol + 3 * 15.999 g/mol)

molar mass of X ≈ 42.36 g/mol

Metal X is most likely Calcium that has a molar mass of 40 g/mol

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Answer:

A metal M readily forms water-soluble sulphate MSO4, water-insoluble hydroxide M(OH)2 and oxide MO. The oxide and hydroxide are soluble in NaOH. The M is:

Answer:

(3rd option) Asexually reproduced offsprings have the same amount of genetic information as the parent, while sexually reproduced offsprings have half as much genetic information.

Explanation:

This is variation is caused as a result of both gamete production and fertilisation.

Answer:

1st = saturated

Explanation:

Bro first ka answer saturated he

Answer:

thank you for he points ty

Answer:

8757

Explanation:

There are 10 centimeters in a decimeter.

Hope this helps!

Step 1

The gas is assumed to be ideal. Therefore, the next formula is applied:

------------------------------------------------

Step 2

Information provided:

p = pressure = 147 kPa x (1000 Pa/1 kPa) = 147000 Pa

V = volume = unknown

n = number of moles = 2.10 moles

T = absolute temperature = 340.0 K

R = gas constant = 8.314 m^3 x Pa/mol K (according to the variables and units provided)

-------------------------------------------------

Step 3

Procedure:

V is found from (1):

Next, V = 0.0403 m^3 x (1000 L/1 m^3) = 40.3 L

Answer: V = volume = 40.3 L

1. The mass of the wagon is 11 Kg

2. The acceleration of the wagon, given that it was pulled with a force of 300 N is 7.5 m/s²

1. How do I determine the mass of the wagon?

The mass of the wagon can be obtained as illustrated below"

Mass of wagon = Total mass - (mass of son + mass of son's friend)

Mass of wagon = 40 - (14 + 15)

Mass of wagon = 40 - 29

Mass of wagon = 11 Kg

2. How do I determine the acceleration of the wagon?

The acceleration of the wagon can be obtained as shown below:

Force = mass × acceleration

300 = 40 × a

Divide both sides by 40

a = 300 / 40

a = 7.5 m/s²

Thus, the wagon is accelerating at 7.5 m/s²

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Answer:

A

Explanation:

Conducts electricity:

-Steel

-Gold

-Copper

-Aluminum

Does not conduct electricity:

-Plastic

-Glass

-Rubber

-Wood

Metallic bonding causes metals to conduct electricity. Some metals are more highly conductive than others.

Hope this helps :)

Answer:

The first table correctly classifies the materials.

Explanation:

In table 1, all the elements on the left side are transition metals, expect for steel. Steel is not an element, it's an alloy (Which is a combination of two or more elements).Transition metals are very good conductors of heat and electricity. The reason why transition metals make such good conductors is because their outer electrons can move freely in their atom.

The right side of table 1 correctly classifies the materials that do not conduct electricity. The reason why those materials are poor conductors is because they all have their electrons tightly bound to their atoms.

In table 2, it classifies copper has a poor conductor which is wrong. It also classifies wood as a good conductor which also wrong for the reasons I stated above.

Answer:

d

Explanation:

Answer: The concentration of ethyl ethanoate at equilibrium is \(0.653mol/dm^3\)

Explanation:

Given values:

Equilibrium concentration of ethanol = \(0.42mol/dm^3\)

Equilibrium concentration of ethanoic acid = \(0.42mol/dm^3\)

\(K_c=0.27\)

The given chemical equation follows:

\(CH_3COOC_2H_5+H_2O\rightleftharpoons C_2H_5OH+CH_3COOH\)

The expression of \(K_c\) for above equation follows:

\(K_c=\frac{[C_2H_5OH][CH_3COOH]}{[CH_3COOC_2H_5]}\)

Putting values in above expression, we get:

\(0.27=\frac{0.42\times 0.42}{[CH_3COOC_2H_5]}\)

\([CH_3COOC_2H_5]=\frac{0.42\times 0.42}{0.27}=0.653mol/dm^3\)

Hence, the concentration of ethyl ethanoate at equilibrium is \(0.653mol/dm^3\)

Answer:

the answer is 0.81 mol/dm³

Answer:

It's due to the forces that are known as balanced forces and it might also be because there is no friction

Answer:

The forces between you and the rock are balanced.

Explanation:

The force of your push against the rock and the opposing force of the rock pushing back on you are equal and opposite, meaning they balance each other out. This results in the rock not moving, because the net force on the rock is zero. This situation is referred to as static friction, which acts to prevent an object from moving when there is a force being applied to it. The force of static friction is always equal in magnitude but opposite in direction to the force being applied, until the force becomes large enough to overcome the static friction and cause the object to start moving.

Answer:

1) No, 2) Yes, 3) Yes

Explanation:

Refer to solubility rules to understand if a precipitate occurs between a mix of solutions.

Two solutions form a precipitate if they react to yield an insoluble product.

Let us now consider each of the reacting species one after the other.

In the first case;

Zn(NO3)2(aq) + FeI2(aq) ----> ZnI2(aq) + Fe(NO3)2(aq)

The two products of the reaction are soluble so no precipitate is formed.

In the second case;

2KBr(aq) + Pb(NO3)2(aq) ------>  2KNO3(aq) + PbBr2(s)

An insoluble product PbBr2 is formed hence a precipitate is formed.

In the third case;

NH4Br(aq) + NaOH(aq) -------> NH4OH(aq) + NaBr(aq)

No insoluble product is formed so the there is no precipitate.

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The only chiral center in the molecule is carbon 4 because is attached to four different atoms or groups.

The term chiral center refers to a carbon atom that is attached to four different atoms or groups. This kind of carbon atom is able to rotate the direction of plane polarized light.

We can see from the structure of the molecule that the only chiral center in the molecule is carbon 4 because is attached to four different atoms or groups.

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Answer:frh

Explanation:

Answer:

149.63 grams of CO2 are produced when 3.4 moles of CH4 are burned.

let's see, oh I get it let me give you a hint. You need to do something with _Mgs+_ and _CaSO4>_ in order to get product 1 and product 2

Answer:

116.6 lbs

Explanation:

There are 2.2 lbs per Kilogram of weight - and likewise 0.454 Kilograms per pound - but instead of dividing by .454 I multiplied the weight by 2.2 to get 116.6 pounds (of course you could round up and get 117 but 116.6 is a little more accurate).

The weight of the stone in pounds will be 116.8 pounds.

We have a large stone of which weighs 53 Kg.

We have to find its weight in pounds.

In 1 kilogram there are 2.2046 lbs.

According to the question -

Weight of stone in kilograms = 53 Kg

Assume that the weight of stone is equal to A kg. Then -

A = 53 Kg

Now, in order to convert A kg into pounds, we will multiply it by 2.2046.

Therefore, Weight of stone in kilograms is equivalent to = 53 x 2.2046 = 116.8 pounds.

Hence, the weight of the stone in pounds will be 116.8 pounds.

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The balanced equation for the reaction between cobalt(III) nitrate (\(Co(NO_3)_3\)) and potassium sulfide (\(K_2S\)) is:

\(3 Co(NO_3)3 + 2 K_2S - > 3 CoS + 6 KNO_3\)

In the balanced equation, the stoichiometric coefficient for potassium nitrate (\(KNO_3\)) is 6.

A molecular reaction is a chemical reaction in which two or more molecules combine to form a new compound. Molecular reactions include a wide range of natural and synthetic phenomena, ranging from enzyme-catalyzed transformations to protein folding and drug binding. In a chemical equation, stoichiometric coefficients reflect the relative number of molecules of each reactant and product.

Potassium nitrate is a chemical compound that is commonly used in fertilizers, fireworks, and rocket propellants. It is an ionic salt with the formula \(KNO_3\). Potassium nitrate is a white crystalline substance that is soluble in water. It is also known as saltpeter.What is the balanced chemical equation for the reaction of potassium nitrate and potassium sulfide?\(Co(NO_3)_3 + K_2S → CoS + 3KNO_3\)

This is the balanced chemical equation for the reaction of potassium nitrate and potassium sulfide. The stoichiometric coefficient for potassium nitrate is 3, which means that three molecules of KNO3 are required to react with one molecule of \(K_2S\). On the other hand, the stoichiometric coefficient for \(Co(NO_3)_3\) is 1, which means that only one molecule of  \(Co(NO_3)_3\) is required to react with one molecule of \(K_2S\) .

The stoichiometric coefficient for CoS is also 1, which means that one molecule of CoS is produced for every molecule of \(K_2S\)that reacts.

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