Which of the following is NOT a benefit of cool down activities?
A.
reduced muscle soreness
B.
maximal lightheadedness
C.
injury prevention
D.
gradually reduced heart rate


Please select the best answer from the choices provided.

A
B
C
D

The equigravity between two planets is determined from the product and their masses and square of distance between them.

The gravitational force between two planets is calculated as follows;

F = GM₁M₂/R²

where;

Use the mass ratio of the two planets to determine their individual masses.

Thus, the equigravity between two planets is determined from the product and their masses and square of distance between them.

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The speed at which the rider is spinning when the floor drops out beneath her is 5.42 m/s.

The acceleration of the rider when the normal force is half their weight is calculated as follows;

Fn = 0.5(W)

ma = 0.5 x mg

65 x a  = 0.5 x 65 x 9.8

a =  0.5 x 9.8

a = 4.9 m/s²

a = v²/r

v² = ar

v = √ar

v = √(4.9 x 6)

v = 5.42 m/s

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A scale which reads 0 in the vacuum of space is placed on the surface of planet Physica. On the planet's surface, the scale indicates a force of 10,000 Newtons. The surface area of the scale is 0.125 square meters.

To calculate the surface area of the scale, we can use the formula:

P = F/A

where P is the pressure, F is the force, and A is the surface area.

Given that the atmospheric pressure on the surface of Physica is 80,000 Pascals and the scale indicates a force of 10,000 Newtons, we can plug in these values into the equation:

80,000 Pa = 10,000 N / A

To solve for A, we can rearrange the equation:

A = 10,000 N / 80,000 Pa

A = 0.125 m²

In summary, based on the given information, the surface area of the scale on the surface of planet Physica is calculated to be 0.125 square meters.

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Answer:

The average speed of a car will be "30 mph".

Explanation:

The given values are:

Distance = 120 mi

Let the speed be "x".

As we know,

\(Time = \frac{Distance}{Speed}\)

         \(=\frac{120}{x}\)

According to the question,

If the speed of a car = x + 10

then the time will be:

=  \(\frac{120}{x} -1\)

Now,

⇒  \(Speed\times Time=(x+10)(\frac{120}{x}-1)\)

⇒  \(120=120+\frac{1200}{x} -x-10\)

On multiplying "x" both sides, we get

⇒  \(120x=120x+1200-x^2-10x\)

⇒  \(x^2+10x-1200\)

⇒  \(x^2+40x-30x-1200=0\)

⇒  \(x(x+40)-30(x+40)=0\)

⇒  \((x+40)(x-30)=0\)

                   \(x+40=0\)

                           \(x=-40\)

Or,

                   \(x-30=0\)

                          \(x=30\)

So that the average speed will be "30 mph".

The force acting on the electron is 1.92 x 10^-17 N.

The problem states that an electron of charge 1.6 x 10^-19 is located in a uniform electric field of 120 Vm^-1, and it asks us to determine the force acting on it.

We can use Coulomb's law, which states that the force between two point charges is proportional to the product of their charges and inversely proportional to the square of the distance between them. If the charges are of opposite signs, the force is attractive, while if the charges are of the same sign, the force is repulsive.

The formula for Coulomb's law is F = kq1q2/r^2, where F is the force between the charges, k is Coulomb's constant, q1 and q2 are the magnitudes of the charges, and r is the distance between them.

Since the electron has a charge of 1.6 x 10^-19 C, and the electric field strength is 120 Vm^-1, we can use the equation F = qE to find the force acting on it.

F = qE = (1.6 x 10^-19 C)(120 Vm^-1) = 1.92 x 10^-17 N.

Therefore, the force acting on the electron is 1.92 x 10^-17 N.

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Answer:

V₂ = 12.6 cm³ -  volume of the NOT immersed part:

Explanation:

Given:

m = 33 g

V = 39 cm³

ρ = 1.25 g/cm³

____________

V₂ - ?

Gravity:

F = m·g

Strength of Archimedes:

Fa = ρ·g·V₁

V1 - the volume of the submerged

The object is floating, so:

F = Fa

m·g = ρ·g·V₁

m = ρ·V₁

V₁ = m /  ρ = 33 / 1.25 ≈ 26,4  cm³

V₂ - volume of the NOT immersed part:

V₂ = V - V₁ = 39 - 26.4 = 12.6 cm³

Move numbers to the boxes to show the factor pairs of 14:

Blank space 1: 1

Blank space 2: 1

Blank space 3: 2

Blank space 4: 7

A factor pair of a number is a pair of whole numbers that can be multiplied together to give the original number. For the number 14, the factor pairs are (1,14) and (2,7). So, we can put 1 in the first blank, 14 in the second blank, 2 in the third blank, and 7 in the fourth blank to show the factor pairs of 14.

To show the factor pairs of 14 in the given response area with 4 blank spaces, we need to find the two numbers that can be multiplied together to give 14. These two numbers are called factor pairs of 14.

To begin, we can start listing the factors of 14. The factors of 14 are 1, 2, 7, and 14. We can then use these factors to form factor pairs by multiplying them together. The factor pairs of 14 are (1, 14) and (2, 7).

To show these factor pairs in the given response area, we can put the first factor of each pair in the first and third blank spaces, and the second factor of each pair in the second and fourth blank spaces. Therefore, we can put 1 in the first blank, 14 in the second blank, 2 in the third blank, and 7 in the fourth blank to show the factor pairs of 14.

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Answer:

?

Explanation:

When using a dial test indicator (DTI), it is essential to ensure that the gauge is positioned at a right angle to the contact surface for accurate readings.

However, in certain situations, it may be challenging to achieve a perfect right angle alignment. In such cases, adjustments can be made to compensate for the misalignment and obtain accurate measurements.To adjust the DTI reading when the gauge is not positioned at a right angle to the contact surface, the following steps can be taken:Determine the misalignment angle: Measure the angle at which the DTI is misaligned from the right angle position. This can be done using a protractor or by estimating the deviation visually.Calculate the correction factor: Based on the misalignment angle, calculate the correction factor using trigonometric functions such as sine or cosine. The correction factor accounts for the difference between the actual displacement and the displacement measured by the DTI.Apply the correction factor: Multiply the correction factor by the DTI reading to adjust the measurement. This compensates for the misalignment and provides a more accurate reading.It's important to note that adjusting the DTI reading can introduce some degree of error, especially if the misalignment is significant. Therefore, it is always preferable to position the gauge at a right angle to the contact surface whenever possible to obtain the most precise measurements.

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Answer:

Explanation:

It's graph A because the pressure in the tire is increasing as the amount of air going into it increases. B says the pressure drops exponentially as air goes in, and C says that the pressure stays the same as air goes in. Pressure in a tire increases proportionally to the amount of air in it.

Answer:

The process by which the balloon is attracted and possibly sticks to the wall is known as static electricity which is the attraction or repulsion between electric charges which are not free to move.

The wall is an insulator.

Explanation:

When a balloon is blown and tied off, and then the balloon is rubbed on the woolly object once in one direction, and the side that was rubbed against the wool is brought near a wall and then released, it is observed that the balloon is attracted to and sticks to the wall. The above observation is due to static electricity.

Static electricity refers to electric charges that are not free to move or that are static. One of the means of generating such charges is by friction. When the balloon is rubbed on the woollen material, electrons are given away to the balloon's surface. Since the balloon is an insulator (materials which do not allow electricity to pass through them easily), the electrons are not free to move. When the balloon is brought near to a wall, there is a rearrangement of the charges present on the wall. Negative charges on the wall move farther away while the positive charges on the wall are attracted to the electrons on the balloon's surface. Because the wall is also an insulator, the charges are not discharged immediately. Therefore, this attraction between opposite charges as well as the static nature of the charges results in the balloon sticking to the wall.

The match is going to be as follow:

1 -  a

2 - b

3 - d

4 - c

5 - b

6 - e

1 - Crest : The crest is the highest point or crest of the wave. This is the point at which the wave reaches its maximum positive change or amplitude.

2- Wavelength : Wavelength is the distance between two consecutive points of a wave that have the same phase. It is usually represented by the symbol λ (lambda) and is usually measured in units of length such as meters (m), centimeters (cm), or nanometers (nm).

3- Trough : A trough is the lowest point or valley in a wave. This is the point at which the wave reaches its maximum negative displacement or amplitude.

4- Amplitude : Amplitude refers to the maximum displacement or magnitude of a wave at its equilibrium or resting point. In other words, it represents the maximum distance at which the wave oscillates or deviates from its position or zero.

5-Wavelength : Wavelength is the distance between two consecutive points of a wave that have the same phase. It is usually represented by the symbol λ (lambda) and is usually measured in units of length such as meters (m), centimeters (cm), or nanometers (nm).

6-Amplitude : Amplitude refers to the maximum displacement or magnitude of a wave at its equilibrium or resting point. In other words, it represents the maximum distance at which the wave oscillates or deviates from its position or zero.

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The weight of the ant is the force that acts on the anthill in the downward direction and at angle of 30° rom the vertical.

Given the following data:

In Science, a free-body diagram can be defined as a graphical illustration which is typically used to visualize moments, tension, and applied forces that are acting on an isolated or rigid body (object) while using arrows pointing in the direction of these forces.

In this scenario, the weight of the ant is the force that acts on the anthill in the downward direction and at angle of 30° rom the vertical.

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Answer:

A force is a push or a pull and it affects our daily lives because without force,people would not be able to open and close stuff or lift up our arms or legs .....or anything, for that matter.

Explanation:

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Answer:

sediment accumulation in a lake near a farm.

Explanation:

In Agriculture, there are various techniques adopted by farmers for the growth and development of their crops. An effective and efficient agricultural technique would have a significant impact on the level of productivity attained by the farmers and as such meeting the unending requirements or needs of the consumers.

There are various agricultural techniques used in farming and these includes;

I. Mixed farming.

II. Arable farming.

III. Pastoral farming.

IV. Bush fallowing.

V. Shifting cultivation.

VI. Nomadic herding.

VII. Subsistence farming.

Generally, these agricultural techniques adopted by farmers has an effect or impact on the environment where it is practiced.

For example, one of such effect on the environment is the accumulation of sediments in a lake near the farm. Thus, this could lead to the formation of new materials such as silt, sand, clay, organic debris, etc., inside the lake.

Answer:

sediment accumulation in a lake near a farm.

Explanation:

Answer:

The moon does not have an atmosphere because it does not have enough gravity to hold onto the gases that make up an atmosphere. The moon also does not have plate tectonic activity because it does not have enough internal heat to drive the movement of the plates.

Explanation:

Answer:

Hello! Your answer would be, O False

Explanation:

Hope I helped! Brainiest plz!♥ Have a nice morning! Hope you make a 100%! -Abby

Answer:

False is the correct answer.

Explanation:

plz mark me as brainliest.

The description that tells two processes that scientists think move Earth's lithospheric plates is convection in the mantle and pressure of magma on the edge of the plate.

The Earth's lithosphere is the rocky outer part of Earth which is made up of the brittle crust and the top part of the upper mantle.

The Earth's lithosphere deflects the convections and as the convections churn clockwise of anticlockwise, they drag the  lithosphere with it via friction an this is what is stipulated to cause tectonic plate movements.  

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Answer: convection in the mantle and pressure of magma on the edge of the plate

Explanation: I took the unit test

In a DC generator, the generated electromotive force (emf) is directly proportional to the rotational speed of the generator's armature and the strength of the magnetic field within the generator.

This relationship is described by the equation for the generated emf in a DC generator:

Emf = Φ * N * A * Z / 60

Where:

Emf is the generated electromotive force (in volts),

Φ is the magnetic flux density (in Weber/meter^2\(meter^2\) or Tesla),

N is the number of turns in the armature winding,

A is the effective area of the armature coil (in square meters),

Z is the total number of armature conductors, and

60 is a constant representing the conversion from seconds to minutes.

From this equation, we can see that the generated emf is directly proportional to the magnetic flux density (Φ) and the product of the number of turns (N), effective area (A), and the total number of armature conductors (Z). This means that increasing any of these factors will result in a higher generated emf.

The magnetic flux density (Φ) can be increased by using stronger permanent magnets or increasing the strength of the field windings in the generator.

The number of turns (N) and the effective area (A) are design parameters and can be optimized for a specific generator. Increasing the number of turns or the effective area will result in a higher generated emf.

Similarly, the total number of armature conductors (Z) can be increased to enhance the generated emf.

By controlling and optimizing these factors, the generated emf in a DC generator can be increased, resulting in higher electrical output. However, it is important to note that there are practical limits to these factors based on the design and construction of the generator.

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Answer:1/64. im glad i could at least try to help lol im in middle school and i just ran through a bunch of articles 4 u

(a) The induced current in the circuit is clockwise.

b. To find the power (P) using P = Fd/t or P = Fv (since d/t = v). Here, F = ILB (from the Lorentz force), so P = (ILB)v.

(a) The induced current in the circuit is clockwise.

This can be determined using the right-hand rule.

As the metal bar moves to the left through the magnetic field directed out of the plane, the generated force on the electrons (Lorentz force) will push them toward the top rail, creating a clockwise current.

(b) To find the rate at which the applied force is doing work on the bar, first calculate the induced EMF (ε) using Faraday's law:

induced EMF (ε) using Faraday's law:

ε = BLv

= (0.65 T) * (0.36 m) * (5.9 m/s)

= 1.389 Tm²/s

= 1.389 V (since 1 Tm²/s = 1 V)

induced current (I) using Ohm's law:

I = ε/R

= 1.389 V / 45 Ω

= 0.03086 A

force (F) from the Lorentz force law, where F = ILB:

F = ILB

= (0.03086 A) * (0.36 m) * (0.65 T)

= 0.00723 N

Finally, we find the power (P) using P = Fv:

P = Fv

= (0.00723 N) * (5.9 m/s)

= 0.04266 W

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Answer:

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 10 × 2

We have the final answer as

Hope this helps you

When a 2.5 kg sledgehammer hit a cement block with a force of 6.0 Newtons. The force the sledgehammer exerted on the cement block is greater in magnitude and opposite in direction to the force the cement block exerted on the sledgehammer.

This refers to forces that act on an object in opposite directions. The net force is gotten by solving for the difference between the two forces.

When the opposing forces are equal or balanced, the net force is zero.  The sledgehammer hits with a force and the cement block is receiving the impart as a stationary object.

Obviously, the force the sledgehammer exerted on the cement block is greater in magnitude and opposite in direction to the force the cement block exerted on the sledgehammer.

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A pitcher throws a baseball towards a batter at 30m/s. The batter swings his bat and hits the baseball, then there is a transfer of energy in this situation : c) Yes, because the force from the bat changes the motion of the ball.

Although baseball may appear hard and solid, it actually behaves much like a rubber ball. In the fraction of a second that ball collides with the swinging bat, ball compresses as the energy of motion goes into deforming the ball and transforms it into an elastic potential energy.

The collision of baseball with bat is elastic and the collision between baseball and glove is nearly inelastic.

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The electron must be placed at a distance of 3.734×10^-5 m from the point charge q in the opposite direction of the gravitational force.

To find the position where the electric force on the electron is exactly opposite to its weight, we need to set up the equation for the electric force and weight and solve for the position.

The electric force (Fe) between the point charge q and the electron is given by Coulomb's law:

Fe = (1/4πε₀) * (q * e) / r²

where  

ε₀ is the electric constant,

r is the distance between the two charges, and

e is the charge of the electron.

The weight (Fg) of the electron is given by:

Fg = m * g

where

m is the mass of the electron and

g is the acceleration due to gravity.

We want to find the distance r where

Fe = -Fg

So we have:

|Fe| = |Fg|

(1/4πε₀) * (q * e) / r² = m * g

Solving for r, we get:

r = sqrt[(1/4πε₀) * (q * e) / (m * g)]

Plugging in the values for the constants and the given charge and mass, we get:

r = sqrt[(1/4π * 8.99×10^9 N⋅m²/C²) * (0.55×10^-9 C * 1.60×10^-19 C) / (9.11×10^-31 kg * 9.81 m/s²)]

r = 3.734×10^-5 m

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Answer:

Slipher developed spectrographic methods that allowed researchers to see a Doppler effect in the distances of what were then called “spiral nebula,” what we today call galaxies. Simply put, by measuring the longer wavelength red shift (objects moving away) and shorter wavelength blue shift (objects moving closer), Slipher demonstrated that the universe was not static.

Explanation:

1.) The relative humidity is 100 percent. 2.)To saturate the air at 20°C, 0.018g of water should evaporate.

(i) To calculate the relative humidity at room temperature, compare the amount of water vapour in the air to the maximum amount of water vapour that the air can hold at that temperature.

The saturated vapour pressure at that temperature determines the maximum amount. The relative humidity is stated as a percentage and can be calculated using the formula:

(Actual vapour pressure / Saturated vapour pressure) times 100% = Relative humidity

The saturation vapour pressure at room temperature (20°C) is 17.54mmHg. The relative humidity is 100% if the actual vapour pressure in the air equals the saturation vapour pressure.This signifies that the air has held the most water vapour it can at that temperature.

(ii) Using the ideal gas law, we can calculate the amount of water that should evaporate to saturate the air at 20°C. PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin, according to the ideal gas equation.

This equation can be rearranged to calculate the amount of moles of water:

n = (PV) / (RT)

We know that the required pressure is 17.54mmHg, which is equal to 2.338 kPa. We also know that the temperature is 20° C, which is 293.15 K.The volume is not specified, but we can assume it is constant and hence ignore it. The gas constant is 8.31 joules per mol-K.

n = ((2.338 kPa) / (8.31 J/mol-K * 293.15K))

To calculate the mass of water, multiply the number of moles by the molar mass of water, which is about 18.015 g/mol.

0.01796 g = 0.000997 mol * 18.015 g/mol mass of water

To saturate the air at 20°C, around 0.018g of water should evaporate.

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Answer:

16000 Joules

Explanation:

8000W x 2