Which of the following is a benefit to creating computer-based models for tracking a hurricane?
People can see if they should prepare to evacuate an area.
Forecasters can determine exactly where the hurricane is likely to make landfall.
Emergency crews can determine the number of floods the hurricane will produce.
all of the above

Answer:

Nucleus 3 i believe

Answer:

Did you get the answer to this?

Explanation:

I need this too.

Step 1

The equation for the boiling point elevation used here:

m = molality, which is calculated as follows:

Kb = boiling constant

-------------------------

Step 2

Information provided:

Solute = C9H8O

Solvent = carbon tetrachloride

Mass of solute = 97.1 mg

(1 g = 1000 mg => 97.1 mg x (1 g/1000 mg) = 0.0971 g)

Mass of solvent = 1.00 g

(1 kg = 1000 g => 1.00 g x (1 kg/1000 g) = 1x10^-3 kg)

---

Information needed:

The molar mass of solute = 132.1 g/mol (please, the periodic table is useful here)

-------------------------

Step 3

The number of moles of solute: n

n = mass of solute/the molar mass of solute = 0.0971 g/ 132.1 g/mol = 7.35x10^-4 moles

----

Molality, m:

m = moles of solute/mass of solvent (kg) = 7.35x10^-4 moles/1x10^-3 kg = 0.735 moles/kg or m

----

The boiling point elevation:

ΔTb = Kb x m = 5.03 °C/m x 0.735 m = 3.69 °C

Answer: ΔTb = 3.69 °C

Answer:

The molarity of the sulfuric acid in the solution is 1.77 M.

Explanation:

The molarity of the sulfuric acid in the solution can be found using the following equation:

\( C_{i}V_{i} = C_{f}V_{f} \rightarrow C_{f} = \frac{C_{i}V_{i}}{V_{f}} \)    

Where:

\(C_{i}\): is the initial concentration of the acid

\(V_{i}\): is the initial volume of the solution = 22.6 cm³

\(V_{f}\): is the final volume of the solution = 88.5 cm³

The initial concentration of the H₂SO₄ is:

\( C_{i} = \frac{n}{V} = \frac{m}{M*V} = \frac{d*\% ^{m}_{m}}{M} \)

Where:

n: is the number of moles

m: is the mass

M: is the molar mass = 98.079 g/mol

d: is the density of the acid = 1.39 g/cm³

%: is the percent by mass = 49.0 %

\( C_{i} = \frac{1.39 \frac{g}{cm^{3}}*\frac{1000 cm^{3}}{1 L}*\frac{49 g}{100 g}}{98.079 \frac{g}{mol}} = 6.94 M \)          

Finally, the final concentration of H₂SO₄ after the dilution is:

\( C_{f} = \frac{6.94 M*22.6 cm^{3}}{88.5 cm^{3}} = 1.77 M \)

Therefore, the molarity of the sulfuric acid in the solution is 1.77 M.

I hope it helps you!

Answer:

Explanation:

239 Np

93

22202 are the number of atoms to be placed side by side to span a distance of 6.0um.

The smallest unit of substance into which it is possible to divide without releasing electrically charged particles is the atom.

In addition, it is the smallest unit of matter with chemical element-like characteristics. The atom is thus the fundamental component of chemistry.

An atom of Rhodium (Rh) diameter d = 2.7x\(10^{-10}\) m.

Now assuming that keeping n atoms side by side , the distance will be L= 6um = 6.5 x \(10^{-6}\) m.

Now, the total length is given by total sum of diameter,

so the equation is given by,

L= nd

n= \(\frac{L}{d}\)

n= \(\frac{6.0x 10^{-6} m}{2.7x10^{10} } m\)

n= 22202 atoms.

Hence, there are total 22202 Rh atoms have to be placed side by side to span a distance.

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The pH value of 500 mL of an aqueous solution of 0.005 mole HCl is 2

We'll begin our calculations by obtaining the molarity of the solution. Details below:

Molarity = mole / volume

Molarity = 0.005 / 0.50

Molarity = 0.01 M

Next, we shall obtain the concentration of the hydrogen ion, H⁺ in the solution. Details below:

HCl(aq) <=> H⁺(aq) + Cl¯(aq)

From the balanced equation above,

1 mole of HCl contains 1 mole of H⁺

Therefore,

0.01 M HCl will also contain 0.01 M H⁺

Thus, the concentration of the hydrogen ion, H⁺ in the solution is 0.01 M

Finally, we shall determine the pH of the solution. Details below:

pH = -Log H⁺

pH = -Log 0.01

pH = 2

Thus, we can conclude that the pH of the solution is 2

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Initial solution concentration of the original sulfuric acid solution is 1.66.

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The volume units that are greater than one liter are kiloliter and megaliter. Kiloliter is equal to 1,000 liters, and megaliter is equal to 1,000,000 liters.

The other volume units listed are smaller than one liter. Milliliter is equal to one-thousandth of a liter, centiliter is equal to one-hundredth of a liter, deciliter is equal to one-tenth of a liter, and nanoliter is equal to one-billionth of a liter.

Knowing the conversions between these volume units is essential in science and everyday life, as they are used to measure the volumes of liquids and gases in different contexts.

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The percent composition of hydrogen, phosphorous and oxygen in phosphoric acid is 3.06 %,31.60%,65.31 % respectively.

Percent composition is defined as a convenient way to record concentration of solution.It is a expression which relates solute to solvent as,mass of solute/mass of solution ×100.There are two types of percentage composition percent weight by volume and percent volume by volume .

Percent composition of hydrogen=3/97.99×100=3.06%.

Percent composition of phosphorous=30.97/97.99×100=31.60%

Percent composition of oxygen=64/97.99×100=65.31%

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The reaction would go left under increased pressure.

Though the question is incomplete and I can't find the complete answer online, I can try to give you an overview about the reaction. If we look at this reaction we can see that it is a reversible reaction.

We then know that the conditions of the reaction is what is going to determine the direction that the reaction is going to go in the system. Given the fact that we have more volumes on the left than on the right, the reaction would move to the left if the pressure is increased.

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Answer:

I believe that the answer is true.

Hope this helped :-))

(A) Possible Galvanic cells:

Li(s) | Li+ solution || H+ solution | H2(g) | Pt(s)

Half-cell reactions: Li(s) → Li+(aq) + e-; 2H+(aq) + 2e- → H2(g)

Overall reaction: 2Li(s) + 2H+(aq) → 2Li+(aq) + H2(g)

Eºcell = -3.04 V

Zn(s) | Zn2+ solution || H+ solution | H2(g) | Pt(s)

Half-cell reactions: Zn(s) → Zn2+(aq) + 2e-; 2H+(aq) + 2e- → H2(g)

Overall reaction: Zn(s) + 2H+(aq) → Zn2+(aq) + H2(g)

Eºcell = -0.76 V

Zn(s) | Zn2+ solution || O2(g) | H2O(l) | Pt(s)

Half-cell reactions: Zn(s) → Zn2+(aq) + 2e-; O2(g) + 4H+(aq) + 4e- → 2H2O(l)

Overall reaction: Zn(s) + O2(g) + 4H+(aq) → Zn2+(aq) + 2H2O(l)

Eºcell = 1.56 V

(B) The most powerful reducing agent is the one with the lowest Eo value, indicating the greatest proclivity to lose electrons and experience reduction. Based on the Galvanic cells, Li has the most negative Eo value (-3.04 V), making it the most powerful reducing substance.

(c). we can use Faraday's laws of electrolysis to calculate the current and the amount of H₂ gas produced:

Calculate the number of electrons transferred:

From the balanced reaction, we see that 2 moles of electrons (4 e⁻) are transferred for each mole of H₂ produced.

The mass of Zn consumed in 2 hours is 50 g, which is equivalent to 50/65.38 = 0.765 moles of Zn (where 65.38 g/mol is the molar mass of Zn).

Therefore, the total number of electrons transferred is 4 x 0.765 = 3.06 moles of electrons.

Calculate the current:

Faraday's first law states that the amount of chemical change in an electrolytic cell is proportional to the amount of electricity that flows through the cell.

The proportionality constant is the Faraday constant, which is equal to 96,485 C/mol e⁻.

Therefore, the total charge (Q) required to transfer 3.06 moles of electrons is:

Q = 3.06 x 96,485 = 295,038 C

The time (t) taken for this charge to flow through the circuit is 2 hours = 7,200 seconds.

Therefore, the current (I) is:

I = Q/t = 295,038/7,200 = 40.97 A

Calculate the amount of H₂ gas produced:

From the balanced reaction, we know that 1 mole of H₂ gas is produced for every 2 moles of electrons transferred.

Therefore, the number of moles of H₂ gas produced is:

0.765 moles of Zn x (1 mole of H₂/2 moles of electrons) = 0.383 moles of H₂ gas

The molar mass of H₂ is 2 g/mol, so the mass of H₂ gas produced is:

0.383 moles of H₂ gas x 2 g/mol = 0.766 g of H₂ gas

Therefore, the Galvanic cell produces 0.766 g of H₂ gas when it consumes 50 g of Zn metal for 2 hours at a current of 40.97 A.

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There are 5.79 x 10²¹ representative particles in 2.62g of the molecular compound.

Determine the number of moles of the molecular compound.

We can use the formula:

moles = mass / molar mass

where mass is 2.62g and molar mass is 273g/mol.

moles = 2.62g / 273g/mol

moles = 0.00961 mol

Use Avogadro's number to convert from moles to representative particles.

We can use the formula:

representative particles = moles x Avogadro's number

where Avogadro's number is 6.022 x 10²³.

representative particles = 0.00961 mol x 6.022 x 10²³

representative particles = 5.79 x 10²¹

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Answer:

Redox reaction (Reduction-oxidation reaction) is simply the addition of oxygen in a reactant (oxidation) & its reduction in any other reactant (reduction).

For example, Fe2O3 + 3CO ⟶ 2Fe + 3CO2 is a redox reaction because Fe gets reduced while CO is oxidised (refer to the attachment).

________

Note: Remember that the equation should match the law of conservation of mass which states that the mass of the products should match the mass of the reactants always as energy can neither be gained or reduced.

________

Hope it helps ⚜

Answer: 0.66 g/mL

Explanation: The formula for density is d= m/v where m=mass and v=volume.

The mass was given in the problem, m= 1.32kg

The volume was also given in the problem, v= 2.0L

d= m/v ---> d= 1.32kg/2.0L ---> d=0.66kg/L

The problem calls for the answer to be written in g/mL, so we must convert the units. 1 kg contains 1000g and 1 L contains 1000 mL.

1000g/1000mL = 1 so the units change but the 0.66 does not. Therefore, your answer is 0.66g/mL (Two significant figures because 2.0 only has 2 significant figures).

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Answer: C3H8 + 5O2 ---> 3CO2 + 4H2O

Explanation: This is an example!

I hope this helped!

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Answer:

rip you

Explanation:

Answer:

A Elements

Explanation:

The substances on the periodic table are examples of elements.

An element is a distinct substance that cannot be split-up into simpler substances. Such substances consists of only one kind of atom.

There are over one hundred elements that are known to date.

Answer:

1) (5 moles of calcium bromide) x 2 / 1 = 10 moles

2) (2.00 moles of calcium bromide) = 2.00 moles of calcium sulfate

so (2.00) x (136.1 g/mol) = 272.2 g

3) (845 grams of calcium sulfate) /  136.14 g/mol = 6.21 moles

6.21 moles of calcium sulfate = 6.21 moles of calcium bromide

(6.21 moles of calcium bromide) x 199.89 g/mol = 1241.32 g

Answer:

109

Explanation:

Let silver-107 be isotope A

Let silver-109 be isotope B

Let silver-107 abundance be A%

Let silver-109 abundance be B%

The following data were obtained from the question:

Atomic weight of silver = 108

Mass of isotope A (silver-107) = 107

Abundance of isotope A (silver-107) = 51.8%

Abundance of isotope B (silver-109) = 48.2%

Mass of isotope B (silver-109) =?

Now, we shall determine the mass silver-109 as follow:

Atomic weight = [(Mass of A x A%)/100] + [(Mass of B x B%)/100]

108 = [(107 x 51.8)/100] + [(Mass of B x 48.2)/100]

108 = 55.426 + (Mass of B x 0.482)

Collect like terms

Mass of B x 0.482 = 108 – 55.426

Mass of B x 0.482 = 52.574

Divide both side by 0.482

Mass of B = 52.574/0.482

Mass of B = 109

Therefore, the mass of silver-109 is 109.

The rate law show how concentration changes affect the rate of reaction. Correct answer is B.

The concentration of our reactants can affect how quickly a reaction proceeds. The rate law of a chemical reaction is an equation that outlines the connection between the concentrations of the reactants and the reaction rate.

The reaction rate is constant and independent of the N 2 O concentration, according to the rate law. In other words, the reaction is both zeroth order overall and zeroth order in N 2 O. C Doubling the concentration of N 2 O will have no impact on the reaction rate since the reaction rate is independent of the concentration.

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Answer:

A

Explanation:

will group 2 elements gain electrons to bond with non-metals in group 16 in a 2:1 ratio

From the equation 2PbS + 3O2 ⟶ 2Pb + 2SO3 we can produced 8.12 g of lead  if 2.54 g of PbS is burned with 1.88 g of O2.

To find the mass of lead produced, we need to find the limiting reactant (i.e. the reactant that is consumed first).

We can find the limiting reactant by calculating the number of moles of each reactant and then using the mole ratio from the balanced equation.

Number of moles of PbS = mass / molar mass = 2.54 / 239.27 = 0.0106 mol

Number of moles of O2 = mass / molar mass = 1.88 / 32 = 0.0588 mol

From the balanced equation, the mole ratio of PbS to O2 is 2:3.

Therefore, for every 2 moles of PbS, we need 3 moles of O2.

We can use this information to calculate how many moles of O2 are needed for 0.0106 moles of PbS.0.0106 mol PbS × (3 mol O2 / 2 mol PbS) = 0.0159 mol O2.

Since the actual amount of O2 we have is less than what is needed (0.0159 mol), O2 is the limiting reactant.

This means that PbS is in excess and we can calculate the mass of lead produced using the amount of O2 that reacted.

The balanced equation tells us that 3 moles of O2 produce 2 moles of lead.

Therefore,0.0588 mol O2 × (2 mol Pb / 3 mol O2) = 0.0392 mol PbFinally, we can calculate the mass of lead produced using the number of moles and the molar mass of lead.mass of Pb = number of moles × molar mass= 0.0392 mol × 207.2 g/mol= 8.12 g.

Therefore, 8.12 g of lead will be produced if 2.54 g of PbS is burned with 1.88 g of O2.

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Answer:

D. no definite shape or. definite volume

Explanation:

Gases do not have a definite shape or volume because the molecules in gases are very loosely packed, they have large intermolecular spaces and hence they move around. The particles of solid are closely packed and occupy less space while particles of gases are loosely packed and occupy the complete space available.

Answer:

1000ml=1l

35ml. = ?

Explanation:

35×1/1000

0.035litres

Answer:

A. 5H²O=23

B.ZnCL²=135

Answer:

0.674 moles HNO₃

Explanation:

To find the moles of HNO₃, you need to (1) convert grams NO₂ to moles NO₂ (via molar mass) and then (2) convert moles NO₂ to moles HNO₃ (via mole-to-mole ratio from equation coefficients). It is important to arrange the conversions in a way that allows for the cancellation of units. The final answer should have 3 sig figs to match the sig figs of the given value (46.5 g).

Molar Mass (NO₂): 14.007 g/mol + 2(15.998 g/mol)

Molar Mass (NO₂): 46.003 g/mol

3 NO₂(g) + H₂O (l) ------> 2 HNO₃(g) + NO(g)

46.5 g NO₂            1 mole                2 moles HNO₃
-------------------  x  -------------------  x  --------------------------  =  0.674 moles HNO₃
                              46.003 g             3 moles NO₂

The correct answer is A.

The nuclear equation that correctly characterizes a nuclear reaction is one where the sum of the atomic numbers and the sum of the mass numbers on both sides of the equation are equal.

\(_{92}^{235}\textrm{U}+_{0}^{1}\textrm{n}\rightarrow _{54}^{140}\textrm{Xe}+_{38}^{94}\textrm{Sr}+3_{0}^{1}\textrm{n}\)

         \(_{92}^{235}\textrm{U}+_{0}^{1}\textrm{n}\rightarrow _{54}^{140}\textrm{Xe}+_{38}^{94}\textrm{Sr}+3_{0}^{1}\textrm{n}\)

The correct answer is A.

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