Which of the following errors could cause your percent yield to be falsely high, or even over 100%?

Select ALL that apply.

A.) Heating the sample too vigorously.
B.) Handling the crucible directly with your hands.
C.) Failing to completely decompose the sodium bicarbonate sample.
D.) Taking the mass of the empty crucible without the lid, but including the lid in all other mass measurements.
E.) Taking the mass of all samples with the lid included.

Answer::

Explanation::

A rainbow is produced through a proces that includes refraction, reflection, and dispersion of  sunlight.

A rainbow is formed when sulinght is refracted and reflected by rain drops in the atmospher.

The sunlight is split into its component colors, which is why rainbows appear as having an array of colors. This is due to each color being bent by a different amount during refraction.

The colors of a rainbow are always in the same order, with red on the outside and violet on the inside.

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To determine the universal gas constant (R), we can use the ideal gas law equation: PV = nRT, where P is the total pressure, V is the volume of gas, n is the number of moles, R is the universal gas constant, and T is the temperature in Kelvin.

Barometric pressure of the room: To find the barometric pressure in atm, we convert 766.86 mmHg to atm by dividing it by 760 mmHg/atm, giving us 1.0089 atm.Vapor pressure of water at room temperature (PH2O).The vapor pressure of water at 23.0°C is 0.0313 atm.

Mass difference of butane lighter:The mass difference is calculated by subtracting the initial mass (54.24 g) from the final mass (54.01 g), resulting in a difference of 0.23 g.

Moles of butane gas collected:To find the moles of butane gas, we can use the equation n = m/M, where n is the number of moles, m is the mass, and M is the molar mass of butane (58.12 g/mol). Thus, n = 0.23 g / 58.12 g/mol = 0.003959 mol.

Partial pressure of butane gas:The partial pressure of butane gas is calculated by multiplying the moles of butane gas (0.003959 mol) by the ideal gas constant (R) and the converted temperature (23.0°C + 273.15 K). Let's assume the converted temperature is 296.15 K.

Converted volume of gas collected:The volume of gas collected is given as 100.0 mL, which needs to be converted to liters by dividing it by 1000, resulting in 0.1 L.

Experimental value of R:The experimental value of R can be determined by rearranging the ideal gas law equation to solve for R: R = (P - PH2O) * V / (n * T).

Accepted value of R:The accepted value of R is 0.0821 Latm/molK.

The percent error can be calculated using the formula: (|Experimental value - Accepted value| / Accepted value) * 100.

Factors contributing to percent error could include experimental error in mass measurements, inaccurate temperature measurements, and loss of gas during collection or transfer.

If the gas had not been corrected for the partial pressure of water, the value of R would be lower because the partial pressure of water would contribute to the total pressure, resulting in a smaller value for P in the ideal gas law equation.

To increase accuracy and decrease percent error, the experiment could be repeated multiple times to obtain an average value, use more precise measuring instruments, conduct the experiment in a controlled environment, and ensure accurate calibration of equipment.

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Answer:

Density = 0.17 g/L

Explanation:

It is given that,

Volume of the inflated balloon filled with Helium, \(V=2.2\times 10^3\ L\)

Mass, m = 374 g

We need to find the density of helium. It is equal to its mass per unit volume. It can be given by :

d =m/V

\(d=\dfrac{374\ g}{2.2\times 10^3\ L}\\\\=0.17\ g/L\)

So, the density of helium in the balloon is 0.17 g/L.

Answer:

this shows that the plates are very active in that region. The plate collide a lot.

Explanation:

Answer:

Br-CH2-CH(CH3)2-C(Cl)H-CH(CH3)2-CHO

Explanation:

The molecule has a total of 14 carbon atoms, 13 hydrogen atoms, and 1 bromine atom. The carbon atoms are arranged in a chain with a methyl group attached to the second carbon atom, a chlorine atom attached to the third carbon atom, and two methyl groups attached to the fourth carbon atom. The fifth carbon atom has a carbonyl group attached to it.

The molecule is an aldehyde, which means that it has a carbonyl group (C=O) at the end of the chain. The carbonyl group is polar, and the oxygen atom has a partial negative charge. The hydrogen atom has a partial positive charge. This polarity makes the aldehyde group susceptible to nucleophilic attack.

The bromine and chlorine atoms are both electrophilic, which means that they have a partial positive charge. This makes them susceptible to nucleophilic attack.

The methyl groups are non-polar and do not have any significant reactivity.

The molecule is a chiral molecule, which means that it has a mirror image that is not superimposable on itself. This is because the carbon atom with the carbonyl group is attached to four different groups.

The molecule is a liquid at room temperature and has a strong odor. It is used in a variety of products, including perfumes, flavorings, and plastics.

Answer:

The intermolecular forces increase in the following order:

C2H6 < CH4 < CH3F < NH3

The reasoning behind this order is as follows:

C2H6 (ethane) is a nonpolar molecule with only dispersion forces, which are the weakest intermolecular forces.

CH4 (methane) is also nonpolar and only has dispersion forces, but it has a slightly larger molecular weight than ethane, which leads to stronger dispersion forces.

CH3F (fluoromethane) is polar and has dipole-dipole forces in addition to dispersion forces. The dipole-dipole forces are stronger than the dispersion forces in this case.

NH3 (ammonia) is also polar and has hydrogen bonding, which is a stronger type of dipole-dipole force.

Explanation:

The mass of water produced by the reaction of the 23 g of \(SiO_2\)  is 13.8 g.

The given chemical reaction;

\(4Hf (g) \ + \ SiO_2 (s) \ --> \ SiF_4(g) \ + \ 2H_2O(l)\)

In the given compound above, we can deduce the following;

60 g of \(SiO_2\)  --------- 36 g of water

23 g of \(SiO_2\)  ------------- ? of water

\(mass \ of \ water = \frac{23 \times 36}{60} = 13.8 \ g \ of \ water\)

Thus, the mass of water produced by the reaction of the 23 g of \(SiO_2\)  is 13.8 g.

In the reaction of the given compound, \(4Hf (g) \ + \ SiO_2 (s) \ --> \ SiF_4(g) \ + \ 2H_2O(l)\), what mass of water (in grams) is produced by the reaction of 23.0 g of SiO2?

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Answer:

2.35 x 10²⁰ atoms Ga

Explanation:

After converting from mg to g, use the molar mass as the unit converter to convert to moles. Then using Avogadro's number, 6.022 x 10²³ convert from moles to atoms of Ga.

\(27.2mgGa*\frac{1g}{1000mg} *\frac{1 mol Ga}{69.72gGa} *\frac{6.022*10^2^3 atoms Ga}{1 molGa} = 2.349 * 10^2^0 atoms Ga\)

Then round to 3 significant figures = 2.35 x 10²⁰ atoms Ga.

The number of atoms in 27.2 mg sample of Ga is 2.35 × 10²⁰ atoms

From the question, we are to calculate the number of atoms in a 27.2 mg sample of Ga.

First, we will determine the number of moles of Ga present

Using the formula,

\(Number\ of\ moles = \frac{Mass}{Molar\ mass} \)

Mass = 27.2 mg = 0.0272 g

Molar mass = 69.72 g/mol

Then,

\(Number\ of\ moles \ of\ Ga = \frac{0.0272}{69.72} \)

\(Number\ of\ moles \ of\ Ga = \) 0.000390132 moles

Now, for the number of atoms present

From the formula

Number of atoms = Number of moles × Avogadro's constant

Then,

Number of Ga atoms = 0.000390132 × 6.022×10²³

Number of Ga atoms = 2.35 × 10²⁰ atoms

Hence, the number of atoms in 27.2 mg sample of Ga is 2.35 × 10²⁰ atoms

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Answer:

Preventing erosion – Land Reclamation

Protecting nesting areas – Protecting Biodiversity

Preventing littering – Land Reclamation

Preventing habitat disruption – Protecting Biodiversity

Protecting native species – Protecting Biodiversity

Preventing contamination of soil – Land Reclamation

Explanation:

I really hope I'm right! I tried my hardest, please give me brainliest :)

have a good day!

Answer:

I believe it is the last statement.

Explanation:

google

Answer:

neutral and current

Explanation:

sorry if im wrong ;(

ANSWER

3.52 moles are in 95 grams of aluminum

STEP-BY-STEP EXPLANATION:

As you can see from the question provided, you are asked to find the moles of aluminum

Given data

Mass of aluminum = 95 grams

To find the moles of aluminum, we will need to apply the below formula

From the question provided, you can see that the molar mass of aluminum was given

From your periodic table, you will see that the molar mass of aluminum is 27 g/mol

Molar mass of aluminum = 27g/mol

The next thing is to substitute the data given in the above formula

Therefore, we have 3.52 moles are in 95 grams of aluminum

Answer:

Crystallization or crystallisation is the process by which a solid forms, where the atoms or molecules are highly organized into a structure known as a crystal. Some of the ways by which crystals form are precipitating from a solution, freezing, or more rarely deposition directly from a gas.

Answer:

 1.5 Molar solution in KCl

Explanation:

Definition of molarity => moles of solute / Volume of solution in Liters

Given 3.00 moles of solute dissolved in 2Liters of solution

Molarity of [KCl] = 3.00 moles KCl / 2Liters solution = 1.5 Molar solution in KCl

The volume of Na2SiO3 that can react with 0.8000 grams of HF at STP is approximately 0.9663 liters.

To calculate the volume of Na2SiO3 (sodium silicate) that can react with 0.8000 grams of HF (hydrofluoric acid) at standard temperature and pressure (STP), we need to use stoichiometry and the ideal gas law.

Write the balanced chemical equation for the reaction between Na2SiO3 and HF:

Na2SiO3 + 6HF → Na2SiF6 + 3H2O

Determine the molar mass of HF:

The molar mass of HF is:

H (hydrogen) = 1.008 g/mol

F (fluorine) = 18.998 g/mol

So, the molar mass of HF = 1.008 + 18.998 = 20.006 g/mol

Convert the given mass of HF to moles:

Mass of HF = 0.8000 g

Molar mass of HF = 20.006 g/mol

Moles of HF = Mass of HF / Molar mass of HF

Moles of HF = 0.8000 g / 20.006 g/mol

Moles of HF = 0.03999 mol (rounded to five decimal places)

Use the stoichiometry of the balanced equation to determine the molar ratio between Na2SiO3 and HF:

From the balanced equation, we can see that 6 moles of HF react with 1 mole of Na2SiO3.

Use the ideal gas law to calculate the volume of Na2SiO3 at STP:

The ideal gas law is given by:

PV = nRT

where:

P = Pressure (at STP, P = 1 atm)

V = Volume

n = Number of moles of gas (in this case, moles of Na2SiO3)

R = Ideal gas constant (0.0821 L atm / mol K)

T = Temperature (at STP, T = 273.15 K)

Rearrange the formula to solve for volume (V):

V = nRT / P

Plugging in the values:

n = 0.03999 mol (from step 3)

R = 0.0821 L atm / mol K

T = 273.15 K (at STP)

P = 1 atm (at STP)

V = 0.03999 mol * 0.0821 L atm / mol K * 273.15 K / 1 atm

V = 0.9663 L (rounded to four decimal places)

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The reasonable ground-state electron configuration would be \(1S^2,2S^2,2P^6\)

According to the rules of electron configurations, lower energy level orbitals are filled before higher energy level orbitals.

Thus, the order of filling orbitals according to their energy levels would be: 1S, 2S, 2P, 3S, 3P. etc.

Also, there is a need to be conversant with the number of electrons each orbital can take. S can only take 2, and P can take a maximum of 6 electrons.

Thus, the only reasonable electron configuration would be  \(1S^2,2S^2,2P^6\)

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Answer:

Condensation

Explanation:

Zoe is quite keen to have noticed what we call condensation. Air contains many components, one of those being water vapor. Like how sugar is soluble in water, water can be said to be "soluble" in air. Water will evaporate into the air to a certain extent. The higher the temperature of the air, the more water the air can hold. If the air has more water that it can hold (potentially because of a temperature decrease), the extra water will come out of the air. Zoe's water bottle was cold, and because the air around Zoe's bottle had cooled down, the air can not hold as much water as it could when it was warm, so the air deposited the extra water in the form of liquid water onto the bottle, giving the illusion that her bottle was sweating.

Answer: trial b

Explanation:

The number of moles of NaCl dissolved in the water to make the given solution is 1 mole.

A mole can be described as a unit that is employed to calculate the count of particles. The particles which are counted are usually identical entities, individually distinct.

The amount of chemical substance can be measured in the terms of the mole and the number of entities in one mole is approximately equal to 6.023 × 10 ²³.

Given, the one liter of a 1 M solution of NaCl.

The concentration of the NaCl solution = 1 M

The molarity of the given solution, \(M = n/V\)

The number of moles of NaCl, n = M ×V = \(\displaystyle {1 mol L^{-1}}\times{1L}\) = 1 mol

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Answer:

It is a noble gas

Explanation:

It can form some compounds under various extreme conditions

Answer:

this is Ar, a noble gas, a gas at STP and are basically has little chemical reactivity,

aplanation

:he electron configuration of an element is shown below.

1s^2 2s^2 2p^6 3s^2 3p^6

Based on the electron configuration, write one chemical property of this element.

all of the s an p orbitals ae filled, so this is a noble gas  with atomic # =

2 + 2 + 6 + 2 + 6 = 18 so

this ie element #18 and is Argon,Ar

all noble gases are gases at STP and are basically hae little chemical reactivity,a

1. The balanced chemical equation for the reaction is:

PCl₃ + Cl₂ → PCl

From the equation, the stoichiometric ratio between PCl₃ and Cl₂ is 1:1. This means that for every 1 mole of PCl₃, 1 mole of Cl₂ is needed to completely react.

Given that we have 5.40 moles of PCl₃, we can conclude that we also need 5.40 moles of Cl₂ to completely react.

Therefore, 5.40 moles of chlorine gas are needed to completely react with 5.40 moles of PCl₃ in the reaction.

2. To calculate the number of grams of NO₂ produced, we need to determine the molar mass of N₂O and the stoichiometry of the reaction.

The molar mass of N₂O can be calculated as follows:

N₂O:

N = 2 atoms of nitrogen

O = 1 atom of oxygen

The molar mass of nitrogen (N) = 14.01 g/mol

The molar mass of oxygen (O) = 16.00 g/mol

Molar mass of N₂O = (2 * 14.01 g/mol) + (1 * 16.00 g/mol) = 44.02 g/mol

Now, we need to determine the stoichiometry of the reaction to find the mole ratio between N₂O and NO₂.

From the balanced equation:

N₂O(g) + O₂(g) → 2 NO₂(g)

According to the balanced equation, 1 mole of N₂O reacts to produce 2 moles of NO₂.

Now, let's calculate the number of moles of N₂O using its molar mass:

Moles of N₂O = mass of N₂O / molar mass of N₂O

Moles of N₂O = 315.0 g / 44.02 g/mol

Moles of N₂O ≈ 7.14 mol

Since the stoichiometric ratio between N₂O and NO₂ is 1:2, we can determine the number of moles of NO₂ produced:

Moles of NO₂ = 2 * moles of N₂O

Moles of NO₂ = 2 * 7.14 mol

Moles of NO₂ ≈ 14.28 mol

Finally, we can calculate the mass of NO₂ produced using its molar mass:

Mass of NO₂ = moles of NO₂ * molar mass of NO₂

Mass of NO₂ = 14.28 mol * (46.01 g/mol)  (molar mass of NO₂)

Mass of NO₂ ≈ 657.42 g

Therefore, approximately 657.42 grams of NO₂ are produced when 315.0 grams of N₂O reacts with excess oxygen gas.

3.

A. Acid - [H+] < [OH-]

B. Acid - pH = 2.4

C. Acid - [H+]= 1.0 x 10⁻¹³ M

D. Acid - red litmus paper stays red

E. Neutral there is no reaction with the metal

F. Acid Hydrogen ion donor

G. Base feels slippery

H. Acid and Base conduct electricity

I. Base hydrogen ion acceptor

J. Acid HCI

K. Acid blue litmus paper turns red

4.

A. Conjugate acid-base pairs:

   Acid: H₂SO₄

   Base: OH-

Conjugate acid: HSO₄-

Conjugate base: H₂O

B. Conjugate acid-base pairs:

Acid: H₃O+

Base: OH

Conjugate acid: H₃O+

Conjugate base: H₂O

5. The balanced equation for the reaction is:

3Sb₂S₃(s) + 6Fe(s) → 2Sb(s) + 6FeS(s)

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Answer:

Monsoon: It is a seasonal wind system that lasts for a period of months.

Humid is the amount of water vapor or moisture content in the air

Explanation:

According to the given question, the words in column A has been unscrambled and they are "monsoon" and "Humid".

The concentration of Zn²⁺ ions at the cathode of the concentration cell is 0.646 M.

The concentration of the Zn²⁺ ions at the cathode of the concentration cell is determined as follows:

At the anode, oxidation half-reaction: Zn(s) ---> Zn²⁺ (aq) + 2 e⁻ [Zn⁺] = 0.100 M

At the cathode, reduction half-reaction: Zn²⁺ (aq) + 2 e⁻ ----> Zn (s)  [Zn⁺] =  x

The Ecell = 24.0 mV or 0.024 V

Using the Nernst equation:

Ecell = E°cell - 0.0592/n * log([Zn⁺]anode/[Zn⁺]cathode)

E°cell of a concentration cell = 0

where;

n is the number of moles of ions = 2

0.024 =  0 - 0.0592/2 * log (0.1/x)

y = 0.646 M

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The balanced half-reaction is Fe²⁺ + 2e⁻ --------> FeO₄²⁻

The given reaction is a redox reaction. Balancing a redox reaction is a bit different than solving a normal chemical reaction. The first step is to find the oxidation state of each element in the reactant as well as the product side. By doing so we get,

The oxidation state of Fe - +2

On the product side, we get,

The oxidation state of Fe - +6

The oxidation state of O - -2

The next step is to calculate the difference between the oxidation states.

The difference in oxidation state of Fe - +6 - (+2) = +4

The difference in oxidation state of O - 0 -2 = -2

To balance this reaction, 2 electrons should be added to the reactant side so that the oxidation states of O and Fe get balanced equally. By doing so we get,

Fe²⁺ + 2e⁻ --------> FeO₄²⁻

This is a balanced half-reaction in acid

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Answer:

gahwidsuacsgsuacayau1joagavahiq8wtw8quavakiafabajozyavqhaigavayquata

Explanation:

vahaiqgahiavavqugafayqigqvsbjsiagwyeiwvvs

Answer:

its sodium hydroxide

Explanation: