Which of the following equations is 2x + 3y = 6 written in slope-intercept form.
oy--(2/3)x + 6
y=-2/3)x+ 2
y=-(3/2)x+ 2

Answer:

y=3/2x-2

Step-by-step explanation:

Find the slope first:

\(m=\frac{y_{2-y_{1} } }{x_{2}-x_{1} } =\frac{1-(-2)}{2-0}=\frac{3}{2}\)

Then solve for y-intercept:

\(y=\frac{3}{2}x+b\\-2=\frac{3}{2}(0)+b\\-2=b\)

Now, write out your complete equation:

y=3/2x-2

Answer:

A = 264 m²

Step-by-step explanation:

the shaded area (A) is calculated as

A = outer rectangle area - inner rectangle area

   = (44 × 26) - (40 × 22)

   = 1144 - 880

   = 264 m²

The proportion equivalent with Two-thirds would be 6/9.

Since we know that the proportion is a fraction of a total amount, and the measures are related using a rule of three.

The relations between variables, either direct or inverse proportional, can be built to find the desired measures in the problem.

We are given that the  proportion with Two-thirds

If you actually divide it’ll make since , so first  we want to divide the 2 , then you want to multiply the third of the two

2/3 x 3/3

6/9

thus, the answer will be 6/9.

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Answer:

p(f)=5f-200

Step-by-step explanation:

----------------

The percentage of the semicircle shaded section is approximately 23,606 %.

The percentage of the area of the semicircle is equal to the ratio of the semicircle area minus the half-cross area to the semicircle area. In other words, we have the following expression:

\(r = \left(\frac{A_{s}-A_{h}}{A_{s}} \right)\times 100\,\%\)

\(r = \left(1-\frac{A_{h}}{A_{s}} \right)\times 100\,\%\) (1)

Where:

And the percentage of the shaded section is:

\(r = \left[1-\frac{4 \cdot (2\,cm)^{2}+4\cdot \left(\frac{1}{2} \right)\cdot (2\,cm)^{2}}{0.5\cdot \pi\cdot (16\,cm^{2}+4\,cm^{2})} \right]\times 100\)

\(r \approx 23.606\,\%\)

The percentage of the semicircle shaded section is approximately 23,606 %.

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Answer:

11/10

Step-by-step explanation:

divide both the terms of 55 & 50 with 5: like this ⬇️

put it in the fraction form: ⬇️

I hope this information helps.

The expected difference in the member's scores is 0, the standard deviation is 6.8, and P(Z>0.88) is 0.3788.

A continuous random variable's bell-shaped frequency distribution curve is known as the normal distribution. It refers to a symmetrical depiction of data around its mean value, where the standard deviation determines the width of the curve.

Given that mean is 20.9 and the standard deviation is 4.8.

A) The expected difference in the score of members is given by,

\(\begin{aligned}\text{Expected difference E[x-y]}&=E[x]-E[y]\\&=20.9-20.9\\&=0\end{aligned}\)

B) The standard deviation in the score of the members is given by,

\(\begin{aligned}\text{Standard deviation}\;\sigma&=\sqrt{\text{Var [x-y]}}\\&=\sqrt{4.8^2+4.8^2}\\&=\sqrt{46.08}\\&=6.8\end{aligned}\)

C) The probability that the difference in the two students' scores is greater than 6,

\(\begin{aligned}Z &= \pm\mathrm{\frac{(mean-x)}{SD}} \\&= \pm\frac{(0-6)}{6.8}\\& =\pm0.88 \end{aligned}\)

From the z-table,

\(\begin{aligned}P(Z < -0.88 \;\text{or}\;Z > 0.88)&=2\times P(Z > 0.88)\\&=2\times 0.1894\\&=0.3788\end{aligned}\)

The required answers are 0, 6.8, and 0.3788.

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The mean, mean deviation mode, median standard deviation, and coefficients of variation, CV, are as follows;

1. The mean deviation about the mean, median mode are;

2.653, 3.709, and 3.709, respectively

The coefficients of variation are;

0.364, 0.337, 0.337, respectively

The variance is about 9.462

The standard deviation is about 3.076

2. Section A has a higher relative dispersion than section B

3. City 2

4. a. Mean ≈ 43.85

b. Mode 40 - 54 inches

c. Median ≈ 45.16

The variance ≈ 125.8056

Standard deviation ≈ 11.216

Coefficient of variation ≈ 0.268

The coefficient of variation of a data quantifies or is a measure of the variability of the values in the set of data.

The mean for the data can be calculated as follows;

Mean  = (3×10 + 6×15 + 11×25 + 2×6 + 4×4 + 10×3 + 5×2 + 7×8 + 8×9 + 9×4)/(10+15+25+6+4+3+2+8+9+4) ≈ 7.29

The median is the 86/2 value = 43rd value

10 + 15 + 25 = 50

Therefore, the median is in the class with a frequency of 25, which is 11

The mode of the data, which is the value with the highest frequency in the data set is 11

The mean deviation from the mean is therefore;

(|3 - 7.29|×10 + |6 - 7.29|×15 + |11 - 7.29| ×25 + |2 - 7.29| ×6 + |4 - 7.29| ×4 + |10 - 7.29| ×3 + |5 - 7.29| ×2 + |7 - 7.29|×8 + |8 - 7.29| ×9 + |9 - 7.29| ×4)/(10+15+25+6+4+3+2+8+9+4) ≈ 2.653

The coefficient for the mean deviation about the mean is therefore; 2.653/7.29 ≈ 0.364

The mean deviation about the median is therefore;

(|3 - 11|×10 + |6 - 11|×15 + |11 - 11| ×25 + |2 - 11| ×6 + |4 - 11| ×4 + |10 - 11| ×3 + |5 - 11| ×2 + |7 - 11|×8 + |8 - 11| ×9 + |9 - 11| ×4)/(10+15+25+6+4+3+2+8+9+4)

The mean deviation about the median = 319/86 ≈ 3.709

The coefficient ≈ 3.709/11 ≈ 0.337

The median = The mean deviation about the mode ≈ 3.709

The coefficient is about 0.337

The variance = (10×(3 - 7.29)² + 15×(6 - 7.29)² + 25×(11 - 7.29)² + 6×(2 - 7.29)² + 4×(4 - 7.29)² + 3×(10 - 7.29)² + 2×(5 - 7.29)² + 8×(7 - 7.29)² + 9×(8 - 7.29)² + 4×(9 - 7.29)²)/(10+15+25+6+4+3+2+8+9+4) ≈ 9.462

The standard deviation, s ≈ √(9.462) ≈ 3.076

2. The coefficient of variation, CV, can be used to compare the variability of the datasets comprising of different scales as follows;

CV = Standard deviation/( The mean of the data)

Therefore; CV for section A = 23/79 ≈ 0.2911

CV for section B = 11/64 ≈ 0.172

The higher CV value for section A indicates that the scores of section A have a higher relative dispersion than the scores for the section B

3. The consistency values can be obtained by finding the standard deviation for the values in the data for each city, using a web based tool as follows;

City 1; Mean = 23

Variance = 50/4

Standard deviation, City 1 = (√(50))/2 = 5·√2/2

City 2; Mean = 21.8

Sample variance = 2.2

Standard deviation, City 2 = √(2.2) ≈ 1.483

City 3; Mean = 29.2

Sample variance = 18.7

Standard deviation, City 3 = √(18.7) ≈ 4.324

The standard deviation of city 2, which is the smallest compared tom the other cities, indicates that the City 2, has the most consistent temperature

4. The mean of the data obtained from the data using the midpoint of the data, is; Mean = ∑fx/∑f

Therefore; The mean obtained using an online tool is; 43.85

The mode is the data that occurs most frequently, which is the data with the value; 40 - 54 inches

The median is the value at the middle of the data set, which is the value with a frequency of 53, and in the interval 40 - 54 inches

The median is; 39.5 + (54.5 - 39.5) × (50 - 30)/53 ≈ 45.16

The standard deviation found for the grouped data, using an online tool is as follows;

Variance, σ² ≈125.8056

The standard deviation, σ ≈ √(125.8056) ≈ 11.216

The coefficient of variation is; 11.216/41.83 ≈ 0.268

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Answer:

14-16

Step-by-step explanation:

It is the value that appears the most in the whole group.

Answer:

Step-by-step explanation:

Given an assistant bricklayer laying 50 bricks an hour has worked 2 hours longer than a master bricklayer laying 80 bricks an hour, you want an equation stating they have laid the same number of bricks. You also want to know how long each has worked.

The output of each bricklayer is the product of the rate at which they lay bricks and the time for which they do it. If t is the time spent by the master bricklayer, their output will be 80t. The time spent by the assistant will be (t+2) hours, and their output will be 50(t+2).

Here is the equation that says their output is the same:

  80t = 50(t+2)

Solving the equation for t, we have ...

  80t = 50t +100

  30t = 100 . . . . . . . . . subtract 50t

  t = 3 1/3 . . . . . . . divide by 30

The master bricklayer has worked 3 1/3 hours when they have laid the same number of bricks.

The assistant bricklayer has worked 5 1/3 hours at that time.

__

Additional comment

Each will have laid (80)(3 1/3) = 266 2/3 bricks.

The length of the shorter string is 18 inch while that of the longer string is 30 inch.

An equation is an expression used to show the relationship between two or more variables and numbers.

Let s represent the length of the shorter string.

One piece is 12 inches longer than the other

Length of longer string = s + 12

Since a 48-inch piece of string is cut into two pieces. Hence:

s + (s + 12) = 48

2s + 12 = 48

2s = 36

s = 18

Length of longer string = 18 + 12 = 30

The length of the shorter string is 18 inch while that of the longer string is 30 inch.

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Solution:

Given:

Two triangles are similar if their corresponding angles are congruent and corresponding sides are in equal proportion.

The triangles can be sketched as shown;

Since both triangles have congruent angles, we check if the ratio of their corresponding sides is equal to confirm if they are similar or not.

Hence,

Therefore, the ski lodge and home are similar.

They are similar because they have corresponding congruent angles and also the ratio of corresponding sides is similar.

Step-by-step explanation:

10:30:45 *divided by 5*

2:6:9

The time for Kierra work overtime is,

The pay for the overtime work for an hour is,

Determine the gross pay of the week.

So gross pay for the week is $680.85.

Answer:

3/9 = 1/3 of a minute or 20 seconds

Step-by-step explanation:

Answer:

1/3 of a minute

Step-by-step explanation:

1/3 x 3 = 1 bottle

1/9 x 3 = the time

1/9 x 3 = 3/9 or 1/3

To calculate the interest for 1/2 a month over a period of 8 years, we first need to calculate the total number of months in 8 years:

Total number of months = 8 years x 12 months/year = 96 months

Next, we can calculate the interest for half a month:

Interest = Principal x Rate x Time

Where:

- Principal = $90,900.00

- Rate = 8.25% (annual interest rate)

- Time = 0.5/12 years (half a month, expressed in years)

Rate needs to be converted to a monthly rate, so we divide it by 12:

Rate = 8.25% / 12 = 0.6875% (monthly interest rate)

Time needs to be expressed in years, so we divide it by 12:

Time = 0.5/12 years

Now we can calculate the interest:

Interest = $90,900.00 x 0.006875 x 0.0416667

Interest = $25.08 (rounded to the nearest cent)

Therefore, the interest for 1/2 a month on a principal of $90,900.00 with an annual interest rate of 8.25% over a period of 8 years is $25.08.

Answer:

The interest for 1/2 month is $312.47, and the total interest for 8 years is $30, 032.64

Step-by-step explanation:

Make a plan:

Draw the conclusion:

Hope this helps!

Step-by-step explanation:

12800000

or 567777000

$27500000

Answer:

We need 108 cubes to fill the rectangular prism

Step-by-step explanation:

We are given the dimensions of a cube with an edge length of 1/3 inch.

A rectangular prism is to be filled out with those cubes. The dimensions of the prism are 3 inches x 1 inch x 1 1/3 inches.

The fraction 1 1/3 is expressed as:

\(1\frac{1}{3}=1+\frac{1}{3}=\frac{4}{3}\)

We need to know how many cubes fit in each dimension. It can be found by dividing them by their edge length:

\(\displaystyle \frac{3}{\frac{1}{3}}=3*3 =9\)

\(\displaystyle \frac{1}{\frac{1}{3}}=1*3 =3\)

\(\displaystyle \frac{\frac{4}{3}}{\frac{1}{3}}=\frac{4}{3}*3=4\)

Now we multiply the number of cube per dimension:

9*3*4=108

We need 108 cubes to fill the rectangular prism

Answer: 141.4

Step-by-step explanation:

(π)(1.5)(30)= 141.37

141.37 rounded to the nearest tenth is 141.4

Answer:

\(a_n=-301 +37(n-1)\)

Step-by-step explanation:

arithmetic sequence formula:  \(a_n=a +(n-1)d\)

where \(a\) is the first term and \(d\) is the common difference

Given:

  \(a_{10}=32\)

⇒ \(a +(10-1)d=32\)

⇒ \(a+9d=32\)

Given:

    \(a_{12}=106\)

⇒ \(a +(12-1)d=106\)

⇒ \(a+11d=106\)

Rearrange the first equation to make \(a\) the subject:

a = 32 - 9d

Now substitute into the second equation and solve for \(d\)

    (32 - 9d) + 11d = 106

⇒ 32 + 2d = 106

⇒ 2d = 106 - 32 = 74

⇒ d = 74 ÷ 2 = 37

Substitute found value of \(d\) into the first equation and solve for \(a\):

a + (9 x 37) = 32

a + 333 = 32

a = 32 - 333 = -301

Therefore, the equation is: \(a_n=-301 +37(n-1)\)

The random variable x has a sampling distribution that has a mean of 3.2 inches, a sampling distribution that is approximately Normal by the central limit theorem and a sampling distribution that has a standard deviation of 3 inches. So the option D is correct.

The number of column inches of classified advertisements appearing on Mondays in a certain daily newspaper has mean 320 inches.

The number of column inches of classified advertisements appearing on Mondays in a certain daily newspaper has standard deviation 30 inches.

A sample is 100.

So, the mean number of column inches of classified advertisements in the sample = Mean/Sample number

The mean number of column inches of classified advertisements in the sample = 320/100

The mean number of column inches of classified advertisements in the sample = 3.2

Normal distribution

The standard deviation of column inches of classified advertisements in the sample = standard deviation/√Sample number

The standard deviation of column inches of classified advertisements in the sample = 30/10

The standard deviation of column inches of classified advertisements in the sample = 3

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Answer:

Your answer would require a 7 in the hundreds place

Step-by-step explanation:

The mechanical advantage of the given machine is 40, Velocity ratio is 80 and efficiency is 0.5.

The given question is concerned with finding the mechanical advantage, velocity ratio and efficiency of a weight lifting machine.

The problem has provided the following information:

Weight of the object, W = 1 kN = 1000 NEffort applied, E = 25 NHeight through which the object is lifted, h = 100 mm = 0.1 m Distance through which the effort is applied, d = 8 m

We know that, mechanical advantage = load/effort = W/E and velocity ratio = distance moved by effort/distance moved by the load.Mechanical advantage

The mechanical advantage of the given machine is given by; Mechanical advantage = load/effort = W/E= 1000/25= 40Velocity ratioThe velocity ratio of the given machine is given by;

Velocity ratio = distance moved by effort/distance moved by the load.= d/h = 8/0.1= 80EfficiencyThe efficiency of the given machine is given by;

Efficiency = (load × distance moved by load) / (effort × distance moved by effort)Efficiency = (W × h) / (E × d)= (1000 × 0.1) / (25 × 8)= 0.5

Therefore, the mechanical advantage of the given machine is 40, velocity ratio is 80 and efficiency is 0.5.

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The value in the solution of the inequality is 32

Inequality expressions are mathematical statements where the opposite sides are not equal

From the question, we have the following expression that can be used in our computation:

1/4y 8

When expressed properly, we have the following representation

1/4y ≤ 8

Multiply through both sides of the inequality expression by 4

So, we have the following representation

4 * 1/4y ≤ 8 * 4

Evaluate the products

This  gives

y ≤ 8 * 4

Evaluate the products

This  gives

y ≤ 32

This means that values less than or equal to 32 are included in the solution

A sample of this number is 32

Hence, the value in the solution is 32

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Possible question

which value is a solution of the ineqality 1/4y ≤ 8

Answer: The Answer is 32

Step-by-step explanation: Took Quiz

Answer: 15

Step-by-step explanation:

casue

Answer:

x = 1

Lemme know if you need the steps.

Please mark brainliest if possible :)

Answer:use this procidure

Step-by-step explanation:

Answer:

0.8

Step-by-step explanation:

It is 0.8 because since you have y=1.8-0.2x (which is in the form of y=mx+b); and you have the value that x=5, all that you have to do is plug in 5 into the X in the equation.

Here is shown work:

y=1.8-0.2x

y=1.8-0.2(5)

y=1.8-1

y=0.8

Hopefully this helps! :)

The predicted depth value when the velocity value is 5 will be 0.8 feets

Given the regression model :

yˆ=1.8−0.2x

yˆ = Predicted value

x = velocity

To calculate the predicted depth, at a given velocity, x ;

Substitute the value of x and solve for yˆ in the equation

When x = 5

yˆ=1.8−0.2(5)

yˆ=1.8− 1.0

yˆ = 0.8

Therefore, the predicted depth value in feet is 0.8

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Step-by-step explanation:

\( \underline{ \underline{ \text{Given}}} : \)

\( \underline{ \underline{ \text{To \: find}}} : \)

\( \underline{ \underline{ \text{Using \: pythagoras \: theorem}}} : \)

\( \boxed{ \sf{ {Hypotenuse}^{2} = {Perpendicular}^{2} + {Base}^{2} }}\)

⤑ \( \sf{ Perpendicular = \sqrt{ {(Hypotenuse)}^{2} - {(Base)}^{2} } }\)

⤑ \( \sf{ \sqrt{ {(10)}^{2} - {(8)}^{2} } }\)

⤑ \( \sf{ \sqrt{100 - 64}} \)

⤑ \( \sf{ \sqrt{36}} \)

⤑ \( \boxed{ \sf{6\: units}}\)

\( \pink{ \boxed{ \boxed{ \tt{Our \: final \: answer : \boxed{ \underline { \tt{6 \: units}}}}}}}\)

Hope I helped ! ツ

Have a wonderful day / night ! ♡

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