Which of the following describes freezing?
A substance changing from the liquid to the gaseous state.
A substance changing from the gaseous state to the liquid state.
A substance changing from the liquid state to the solid state.
A substance changing from the solid state to the liquid state.

Answer:

"most likely to help others"

Explanation:

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The amount of nitrogen atoms present in 5.40 g of a) glycine b) magnesium nitride c) calcium nitrate d) dinitrogen tetroxide is 4.33 × 10²² atoms, 3.22 × 10²² atoms, 1.98 × 10²² atoms, and 3.53 × 10²² atoms, respectively.

To find the number of nitrogen atoms present in 5.40 g of each compound, we need to use the formula:

n = (mass of sample/molar mass) × Avogadro's number

Where n is the number of atoms, mass of sample is the given mass of the compound, molar mass is the mass of one mole of the compound, and Avogadro's number is 6.022 × 10^23 atoms/mol.

a) Glycine (C₂H₅NO₂):

Molar mass = 2(12.01) + 5(1.01) + 14.01 + 2(16.00) = 75.07 g/mol

n = (5.40 g/75.07 g/mol) × 6.022 × 10²³ atoms/mol

n = 4.33 × 10²² atoms of nitrogen

b) Magnesium nitride (Mg₃N₂):

Molar mass = 3(24.31) + 2(14.01) = 100.95 g/mol

n = (5.40 g/100.95 g/mol) × 6.022 × 10²³ atoms/mol

n = 3.22 × 10²² atoms of nitrogen

c) Calcium nitrate (Ca(NO₃)₂):

Molar mass = 40.08 + 2(14.01 + 3(16.00)) = 164.10 g/mol

n = (5.40 g/164.10 g/mol) × 6.022 × 10²³ atoms/mol

n = 1.98 × 10²² atoms of nitrogen

d) Dinitrogen tetroxide (N₂O₄):

Molar mass = 2(14.01) + 4(16.00) = 92.02 g/mol

n = (5.40 g/92.02 g/mol) × 6.022 × 10²³ atoms/mol

n = 3.53 × 10²² atoms of nitrogen

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Oxygen always has an oxidation number of -2 when bonded in a compound. Here -2 represents that oxygen atom has gained two electrons.

The Oxidation Number can be defined as the number that is allocated to elements in a chemical combination. The oxidation number is basically the count of electrons that atoms in a molecule can share, lose or gain while forming chemical bonds with other atoms of a different element.

A positive oxidation number shows loss of electrons, and a negative oxidation number shows gain of electrons.

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Answer:

Divide; mass.

Explanation:

The acceleration of an object is equal to the net force exerted on the object divided the object's mass. This theory is known as Newton's second law of motion.

Force is given by the multiplication of mass and acceleration.

Mathematically, Force is;

\( F = ma\)

Where;

F represents force.

m represents the mass of an object.

a represents acceleration.

Making acceleration (a) the subject, we have;

\(Acceleration (a) = \frac{F}{m}\)

Therefore, the acceleration of an object is equal to the net force exerted on the object divided the object's mass.

The acceleration of an object is equal to the net force exerted on the object divided by the object's mass.

The net force applied to an item divided by its mass gives the object's acceleration.

To put it another way, the equation that connects mass (m), net force (\(F_{net\)), and acceleration (a) is:

a = \(F_{net\) / m

This equation is derived from Newton's second rule of motion, which states that an object's acceleration is inversely proportional to its mass and directly proportional to the net force acting on it.

Thus, it shows that an item accelerates more quickly the more net force that is applied to it, and that an object accelerates more quickly the more mass that is added to it.

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To convert 25 g of liquid water to vapor at 100°C, we need 67.7 kJ of energy.

To change 25 g of liquid water to steam, we need to calculate the energy required for the following two processes:

Heating the water from 100°C to its boiling point at atmospheric pressure (100°C).

Vaporizing the water at its boiling point at atmospheric pressure (100°C) to steam at the same temperature.

Let's start with the first step. The specific heat capacity of water is 4.18 J/g°C, so we need:

q1 = m * c * ΔT

where

m = mass of water = 25 g

c = specific heat capacity of water = 4.18 J/g°C

ΔT = change in temperature = (100 - 0)°C = 100°C

q1 = 25 g * 4.18 J/g°C * 100°C

q1 = 10450 J

This means that we need 10450 J of energy to heat 25 g of water from 0°C to 100°C.

Now let's move on to the second step, which is vaporizing the water. The molar heat of vaporization of water is 40.6 kJ/mol.

Since we know the mass of water (25 g), we need to convert it to moles:

n = m / M

where

m = mass of water = 25 g

M = molar mass of water = 18.015 g/mol

n = 25 g / 18.015 g/mol

n = 1.387 mol

The energy required to vaporize the water is:

q2 = n * Δ\(H_v_a_p\)

where

Δ\(H_v_a_p\) = molar heat of vaporization of water = 40.6 kJ/mol

q2 = 1.387 mol * 40.6 kJ/mol

q2 = 56.3 kJ

Therefore, the total energy required to change 25 g of liquid water to steam at 100°C is the sum of q1 and q2:

q = q1 + q2

q = 10450 J + 56.3 kJ

q = 67.7 kJ

So, we need 67.7 kJ of energy to change 25 g of liquid water to steam at 100°C.

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We must take into account the following stages in order to determine the amount of energy needed to convert 25 g of liquid water into steam at 100°C: Calculate how many moles of water (H2O) are contained in 25 g.

Number of moles of H2O = mass/molar mass = 25 g / 18.015 g/mol = 1.388 mol. The molar mass of H2O is 18.015 g/mol. Determine the amount of energy needed to evaporate one mole of water. Water has a molar heat of vaporization (Hvap) of 40.6 kJ/mol. Determine the amount of energy necessary to evaporate 1.388 moles of water. 1.388 moles of water must be vaporized in order to produce 40.6 kJ/mol of energy, which equals 56.4 kJ. Hence, 56.4 kJ of energy are needed to convert 25 g of liquid water to steam at 100°C. The molar heat of vaporization for liquid water is 40.6 kj/mole.

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we can conclude that the scale is precise but not accurate. The correct option is d.This means that the scale consistently gives the same measurements, but they are not accurate or close to the true value.

To understand whether the scale is precise, accurate, both, or neither, we need to define these terms. Precision refers to the consistency or reproducibility of measurements, while accuracy refers to how close the measured value is to the true or accepted value. In this case, the true value is 1.000g, and the measurements captured are 0.843 g, 0.842 g, and 0.843 g.Looking at these measurements, we can see that they are not accurate since none of them are close to 1.000g. However, we can also see that they are precise since they are all very similar to each other, with a difference of only 0.001g between the highest and lowest measurement.
Therefore, To improve accuracy, the scale may need to be recalibrated or replaced.

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complete question: Testing precision and accuracy of scale, weigh block exactly 1.000g. these are measurements captured:

a. 0.843 g

b. 0.842 g

c. 0.843 g

d. Is the scale precise, accurate, both, or neither?

Answer:

Explanation:

In Combustion reaction usually occurs when a hydrocarbon reacts with oxygen to produce carbon dioxide and water. 

The volume of the gas is high and molar volume is also high.

A eudiometer is used to measure the change in the volume of the gas produced in the physical and chemical change. Air in the eudiometer is recorded during the experiment. leaked in to the water bath is also recorded during the experiment.so the measured volume is high. As the volume of the hydrogen gas is high. The volume is directly proportional to the number of moles of the gas ,the molar volume of the gas is also high. This is according to the Avogadro's law. Due to the presence of leaked air there are high volume of gas as well as high molar volume .

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Molality of a solution is defined as the number of moles of solute per kilogram of solvent. It is represented by the symbol ‘m’. 10.5 g of sodium chloride is dissolved in 250.0 g of water, the molality of the resulting solution is 0.604 m.

The molality of the solution prepared by dissolving 10.5 g of sodium chloride in 250.0 g of water is 0.604 m. The given data is: Mass of sodium chloride = 10.5 g Mass of water = 250.0 g Molar mass of sodium chloride = 23 + 35.5 = 58.5 g/mol Number of moles of NaCl = (mass of solute / molar mass) = (10.5 / 58.5) moles = 0.179 moles Number of moles of solvent (water) = (mass of solvent / molar mass) = (250 / 18) moles = 13.89 moles Molality of the solution = (number of moles of solute / mass of solvent in kg) = (0.179 / 0.25) kg = 0.604 m Therefore, the molality of the solution prepared by dissolving 10.5 g of sodium chloride in 250.0 g of water is 0.604 m.

When 10.5 g of sodium chloride is dissolved in 250.0 g of water, the molality of the resulting solution is 0.604 m.

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The molar mass of powdered fruit drink mix can be calculated using the molar mass of sucrose (C12H22O11). To determine the mass of powdered drink mix needed to make a 1.0 M solution of 100 mL, stoichiometry can be applied.

1. The molar mass of sucrose (C12H22O11) can be calculated as follows:

12(atomic mass of carbon) + 22(atomic mass of hydrogen) + 11(atomic mass of oxygen) = molar mass of sucrose.

2. To calculate the mass of powdered drink mix needed to make a 1.0 M solution of 100 mL, the molarity formula can be rearranged to solve for moles:

Molarity = moles/volume.

3. Using this equation, the moles of drink mix can be calculated by rearranging the formula as:

moles = Molarity * volume.

4. Once the moles of drink mix are determined, the mass can be calculated using the molar mass and the mole-to-gram conversion.

5. To find the mass of powdered drink mix needed to make a 0.5 M solution of 100 mL, the same steps can be followed using the given molarity value of 0.5 M instead of 1.0 M.

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Answer:

volume = 16.8

Explanation:

From the question

The Mass = 1.5g.

Molar mass = H2

= 1×2 =2

mole = ?

\(mole = \frac{mass}{molar \: mass} \\ mole = \frac{1.5}{2} \\ mole = 0.75mol\)

Therefore the volume =

\(v = v {dm}^{3} \times n\)

Where mole(n)=0.75mol.

vdm³=22.4dm³

\(v = 22.4 \times 0.75 \\ v = 16.8\)

Therefore the volume = 16.8.

Answer:

4.70 grams of NH4Cl is needed to prepare 350 mL of a 0.25 M ammonium chloride solution.

We need approximately 4.68 grams of NH4Cl to prepare a 0.25 M ammonium chloride solution with a volume of 350 mL.

To determine the mass of NH4Cl needed to prepare the solution, we us use the formula:

m=M x V x MM ... (i)

where,

m= mass in grams

M=molarity of solution

MM= molar mass of compound

V= volume in litres

The number of moles of NH4Cl needed can be calculated using:

  Moles = Molarity x Volume ...(ii)

  Moles = 0.25 mol/L x 0.350 L

  Moles = 0.0875 mol

Hence we can replace M x V with number of moles in equation i.

The molar mass of NH4Cl is :

  Molar mass of NH4Cl = (1 x 14.01 g/mol) + (4 x 1.01 g/mol) + (1 x 35.45 g/mol)

  Molar mass of NH4Cl = 53.49 g/mol

We have all the variables

Putting them in equation i.

Hence,

  Mass (g) = Moles x Molar mass

  Mass (g) = 0.0875 mol x 53.49 g/mol

  Mass (g) = 4.68 g

Therefore, you would need approximately 4.68 grams of NH4Cl to prepare a 0.25 M ammonium chloride solution with a volume of 350 mL.

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hope this is correct

Answer:

D

Explanation:

Iron is the fourth most abundant element, by mass, in the Earth's crust. The core of the Earth is thought to be largely composed of iron with nickel and sulfur. The most common iron-containing ore is haematite, but iron is found widely distributed in other minerals such as magnetite and taconite.

The volume of Solution of glucose is 8.75 ml.

According to dilution law:

\(M_{1} V_{1} = M_{2} V_{2}\)

where,

\(M_{1}\) = molarity of stock solution = 1.00 M

\(V_{1}\) = volume of stock solution =?

\(M_{2}\) = molarity of glucose solution = 1.75×10−2

\(M_{2}\) = volume of glucose solution = 500 ml

Applying all the given values to the above law gives the volume of the stock solution:

(1.00M) x \(V_{1}\) = ( 1. 75×\(10^{2}\)M) x (500ml)

\(V_{1}\) = 8.75 ml

The volume of the 1.00 M stock solution is 8.75 mL of the required volume.

To determine the amount of stock solution required divide the number of moles of glucose by the molarity of the stock solution. A 1 M glucose stock solution can be prepared by dissolving 18 g of glucose in distilled/deionized water to a final volume of 100 ml. The total mass of a solution is the mass of the solvent plus the mass of the solute. Weigh the mass using a laboratory balance or convert the solvent volume to mass using the density formula D = m/V. Add the mass of the solute to the mass of the solvent to get the final volume.

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Answer:36

Explanation:

To solve this problem, we need to set up an ICE (Initial, Change, Equilibrium) table and use the given equilibrium constant (Kc) to determine the equilibrium concentrations. Let's start with the initial concentrations:

[CO2] = 3.50 mol / 7.00 L = 0.50 M (since the volume is given as 7.00 L)

[CO] = 0 M (since no CO is initially present)

[O2] = 0 M (since no O2 is initially present)

Next, let's assume that x mol/L of CO and O2 are formed at equilibrium. Since the stoichiometry of the reaction is 2:2:1 (2 CO2 : 2 CO : 1 O2), the change in concentration of CO and O2 will be equal to x mol/L.

Now, we can fill in the equilibrium concentrations in the ICE table:

        | 2CO2(g) ⇌ 2CO(g) + O2(g)

--------------------------------------

Initial  |   0.50     |     0       |   0

Change  |   -2x       |    +2x     |   +x

Equilibrium| 0.50 - 2x |    2x       |   x

According to the equilibrium constant expression (Kc), we have:

Kc = [CO]^2 * [O2] / [CO2]^2

Plugging in the equilibrium concentrations:

Kc = (2x)^2 * (x) / (0.50 - 2x)^2

Given that Kc = 3.2 × 10^(-8), we can set up the equation:

3.2 × 10^(-8) = (2x)^2 * (x) / (0.50 - 2x)^2

Solving this equation will give us the value of x, which represents the equilibrium concentration of O2. Once we have the value of x, we can calculate the equilibrium concentrations of CO and CO2 using the equilibrium expressions:

[CO] = 2x

[CO2] = 0.50 - 2x

Please note that solving the equation may involve using numerical methods, such as the quadratic formula or an equation solver.

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Answer:

Eukaryotic cells have membrane bound organelles including:

- Nucleus

- Mitochondria

- Golgi apparatus

- Vacuoles

- Endoplasmic reticulum

- Chloroplasts

Prokaryotic cells do not have these organelles.

Answer:

b. 760 g

Explanation:

The mass of the solution = 800 g

5% of NaCl by mass of the solution can be determined as follows;

    5% of 800  =  \(\frac{5}{100}\) × 800

                       = 5 × 8

                       = 40 g

The mass of NaCl in the solution is 40 g.

The mass of water = mass of solution - mass of NaCl

                               = 800 - 40

                              = 760 g

Therefore, the mass of water required is 760 g.

I'm assuming that C is carbon.

\(4.590 \: mol \: c \times \frac{12.01 \:g \: c}{1 \: mol \: c} \)

55.1259 g of C

Answer:

i think right artrium but not full aure

Carbon dioxide is produced when 5 mL of methane gas interacts.

Methane, a hydrocarbon, is the primary component of natural gas. Methane has an effect on the climate and temperature of the earth because it is a greenhouse gas (GHG). Methane is released into the atmosphere through a variety of natural and anthropogenic (caused by humans) sources.

Methane is non-toxic and safe to breathe in small amounts, but if it is allowed to replace air in large quantities, the absence of oxygen could result in suffocation.

\(CH_{4}(g) + 2O_{2} \rightarrow CO_{2} + 2H_{2}O(g)\)

1 volume of \(CH_{4}\) = 1 volume of \(CO_{2}\)

5 ml of \(CH_{4}\) = 1 × 5 mL CO2

                    = 5 mL CO2

So, volume of methane = 5mL

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The answer is D. 0.170 mol.

First  we need to use the balanced chemical equation for the decomposition of dinitrogen pentoxide:

2N2O5 → 4NO2 + O2

According to the equation, for every 2 moles of N2O5 decomposed, 1 mole of O2 is produced.

Therefore, we need to first calculate the number of moles of N2O5 in 36.7 g of the compound, and then use this value to determine the number of moles of O2 produced.

The molar mass of N2O5 is:

2 x (14.01 g/mol) + 5 x (16.00 g/mol) = 108.02 g/mol

The number of moles of N2O5 in 36.7 g is:

36.7 g / 108.02 g/mol = 0.3397 mol

Since 2 moles of N2O5 produce 1 mole of O2, the number of moles of O2 produced is half the number of moles of N2O5 decomposed:

0.3397 mol / 2 = 0.1699 mol (rounded to four significant figures)

Therefore, the answer is D. 0.170 mol.

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Answer:

H2SO4 + Cu(OH)2​ ---> CuSO4+ 2H2O

Answer:

D.  

They have a positive charge and are present in the nucleus of an atom along with the neutrons.

explanation:

Protons have a positive charge.

Nuclear bombs and high-drag GP (General Purpose) bombs have a few common characteristics, including:

They are both explosive devices that release a large amount of energy quickly.

They are designed to cause damage and destruction to a target.

They can be delivered to a target by an aircraft or other means.

They both rely on a chemical reaction to produce the explosion, although the nature of the reaction is different.

However, it's important to note that there are also significant differences between nuclear bombs and high-drag GP bombs. Nuclear bombs rely on nuclear fission or fusion reactions to release an enormous amount of energy, whereas high-drag GP bombs typically rely on a conventional explosive reaction, such as the detonation of TNT or other high-explosive material. The destructive power of a nuclear bomb is much greater than that of a high-drag GP bomb, as nuclear bombs can release energy equivalent to many thousands or even millions of tons of TNT.

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Answer:

Ag+

Explanation:

If you imagine as if the problem were double replacement, you would pair the Cl with one of the following ions provided in the choices. As seen on Table F, Ag+ paired with Cl- produces an insoluble compound, hence the precipitate. All the other ions shown in the multiple choice section, when paired with Cl- will produce a soluble compound, as a result NOT a precipitate.

According to the balanced equation, 31.7 grams of nitrogen gas (N₂) reacting with excess hydrogen gas (H₂) will produce a 2.264 moles of ammonia gas (NH₃).

To determine the moles of ammonia formed, we need to convert the given mass of nitrogen gas to moles using its molar mass and the stoichiometric ratio of the balanced equation.

The molar mass of nitrogen gas (N₂) is 28.02 g/mol. To calculate the number of moles of nitrogen gas, we divide the given mass by its molar mass:

31.7 g / 28.02 g/mol = 1.132 mol

According to the stoichiometry of the balanced equation, the ratio between nitrogen gas and ammonia gas is 1:2. This means that for every 1 mole of nitrogen gas, 2 moles of ammonia gas are produced.

Therefore, using the stoichiometric ratio, we can determine the moles of ammonia formed:

1.132 mol N₂ * (2 mol NH₃ / 1 mol N₂) = 2.264 mol NH₃

Thus, upon the complete reaction of 31.7 grams of nitrogen gas with excess hydrogen gas, 2.264 moles of ammonia gas will be formed.

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The answer of the mathematical operation to the correct number of significant figures is 1.71x10⁻⁴

The answer of the mathematical operation to the correct number of significant figures is 7.2

The no of significant figures in the answer depends on the no of significant figures in the problem given.

It is given 1.05x10⁻³/6.135 , so the number of significant figures in 1.05x10⁻³ is 3 and in 6.135 is 4. So the answer of this operation will be rounded off to have 3 significant figures only. Since the calculated amount comes out as 0.17114x10⁻³. But it has to be rounded to 4 significant figures. So the answer will be 1.71x10⁻⁴

It is given 21-13.8 , so the number of significant figures in the operation are 2 and 3 respectively. So the calculated amount comes to be 7.2 and it already has 2 significant figures.

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