Which of the following contributes the most hydronium ions to a solution?

weak acid
weak base
strong acid
strong base

Explanation:

Hope this somewhat helped:

a. The equation for the reaction of weak acid, C6H5CO2H, with water is: C6H5CO2H + H2O <=> C6H5CO2^- + H3O^+. We can assume that all the C6H5CO2H has reacted with water to form C6H5CO2^- and H3O^+.

The pH is defined as -log(H30^+ concentration), where H30^+ is the hydronium ion, a measure of the acidic strength of the solution. At the equivalence point, all the C6H5CO2H has reacted with the NaOH to form C6H5CO2^- and Na^+. The stoichiometry of the reaction can be determined by balanced the reaction using the information given.

C6H5CO2H + NaOH <=> C6H5CO2^- + Na^+

This reaction tells us that one mole of C6H5CO2H will react with one mole of NaOH to form one mole of C6H5CO2^- and one mole of Na^+.

0.72 moles SO2 contains 4.33 × \(10^{23}\) molecules.

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Answer:

mass of sodium phosphate required = 25.37 g

Explanation:

Equations of reactions:

3CaCl₂ + 2Na₃PO₄ ---> Ca₃(PO₄)₂ + 6NaCl

3Mg(NO₃)₂ + 2Na₃PO₄ ---> Mg₃(PO₄)₂ + 6NaNO₃

Number of moles of the ions = molarity x volume

Ca²⁺ : 0.052 M x 1.6 L = 0.0832 moles

Mg²⁺ : 0.093 x 1.6 L = 0.1488 moles

From the equations of reaction, number of moles of sodium phosphate required to react with each ion is given as;

For calcium: 2/3 x 0.0832 = 0.0555 moles

For magnesium: 2/3 x 0.1488 = 0.0992 moles

Total number of moles of sodium phosphate required = 0.0555 + 0.0992 = 0.1547 moles

Mass of sodium phosphate = number of moles x molar mass

molar mass of sodium phosphate = 164 g/mol

Mass of sodium phosphate = 0.1547 moles x 164 g/mol = 25.37 g

Therefore, mass of sodium phosphate required = 25.37 g

I believe it is -2, though I might be wrong.

Answer:

Ionic bond, also called electrovalent bond, type of linkage formed from the electrostatic attraction between oppositely charged ions in a chemical compound.

Explanation:

Such a bond forms when the valence (outermost) electrons of one atom are transferred permanently to another atom.

Answer:

ok, here is your answer

Explanation:

i am going to solve this problem by using the ICE table method which is an easy method to determine the pH of a weak base with the given data of the problem.Given:Initial volume of NH3 solution (Vi) = 75.0 mLInitial concentration of NH3 solution (Ci) = 0.200 MInitial moles of NH3 solution (Ni) = Ci x Vi = 0.200 M x 75.0 mL = 0.0150 molesKb = 1.8 x 10^-5Moles of HNO3 added (n) = 0.500 M x 17.0 mL = 0.00850 molesVolume of NH3 solution after the addition of HNO3 (Vf) = 75.0 mL + 17.0 mL = 92.0 mLConcentration of NH3 solution after the addition of HNO3 (Cf) = Ni / Vf = 0.0150 moles / 92.0 mL = 0.163 MTo find the pH after the addition of 17.0 mL of HNO3, we need to use the ICE table method.ICE table method:Initial: NH3 + H2O ⇌ NH4+ + OH-Change: -x 0 +x +xEquilibrium: 0.0150 - x 0 x xKb = [NH4+][OH-] / [NH3]1.8 x 10^-5 = x^2 / 0.163Solving for x, x = 0.00171 M[OH-] = 0.00171 M[OH-] = Kw / [H3O+] = 1.0 x 10^-14 / [H3O+][H3O+] = 5.85 x 10^-12pH = -log[H3O+]pH = -log(5.85 x 10^-12)pH = 11.23Therefore, the pH after the addition of 17.0 mL of HNO3 is approximately 11.23.

The energy of the photon of light can be obtained as 6.27 * 10^-20 J.

We know that a photon has to to do with a particular unit of light. We know that light can be said to be composed of very tiny corpuscles and these corpuscles of light is what we call the photon of the light.

We can be able to us the equation that is derived by Max Plank to be able to get the value of the energy of the photon of light. Now we know that a photon of light can have an energy that is able to be obtained by;

E = hf

h = Plank's constant

f = Frequency

Then;

E = 6.6 * 10^-34 Js * 9.5 * 10^13 Hz

= 6.27 * 10^-20 J

Thus as we can see from the parameters in the question, the energy of the photon is 6.27 * 10^-20 J.

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31.7 g of water formation in the given reaction releases 783.02 kJ of heat energy.

The change in heat in the given equation is -890.8 kJ/mol. This means that when one mole of CH4 reacts with 2 moles of O2, it produces one mole of CO2 and 2 moles of H2O while releasing 890.8 kJ of heat energy.Now, we have to find out how much heat energy will be released when 31.7 g of water is formed. To do this, we need to first calculate the number of moles of water formed from 31.7 g of H2O.Molar mass of H2O = 2 × 1.008 + 15.999 = 18.015 g/molNumber of moles of H2O = 31.7 g / 18.015 g/mol = 1.759 molNow we know that 2 moles of H2O are formed when 1 mole of CH4 reacts. Therefore, the number of moles of CH4 required to produce 1.759 mol of H2O will be:1 mole of CH4 : 2 moles of H2Ox moles of CH4 : 1.759 moles of H2Ox = 1.759/2 = 0.8795 molSo, 0.8795 moles of CH4 are required to produce 1.759 moles of H2O. And the heat released during the reaction of 0.8795 mol CH4 can be calculated using the given change in heat.ΔH = -890.8 kJ/molHeat released during the reaction of 0.8795 mol CH4= ΔH × number of moles= -890.8 kJ/mol × 0.8795 mol= -783.02 kJ.

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At before Duberinor,Mendeleev tried to use atomic weight but they failed .

There will be 0.39 moles

Take a look at the He gas in the tank:

P = 2.80 atm, or pressure

Volume = 5.00 liters.

T = (273 + 155) is the temperature. K = 428 K

R = 0.08206 L atm/L of gas (mol K)

Charle's law, Boyle's law, and Gay-Lussac law are the three gas laws that make up the combined gas law, commonly referred to as a general gas equation. For a certain amount of gas, the law illustrates the relationship between temperature, volume, and pressure.

Gas law PV = nRT

So, n = PV/. (RT)

He gasses number = 2.80 x 5.00 / (0.08206 x 428) mol equals 0.39 mol.

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Taking into account the change of units, 100 meters are 109.361 yards and 328.084 feets.

The rule of three is a way of solving problems of proportionality between three known values and an unknown value, establishing a relationship of proportionality between all of them.

That is, what is intended with it is to find the fourth term of a proportion knowing the other three.  

If the relationship between the magnitudes is direct, that is, when one magnitude increases, so does the other (or when one magnitude decreases, so does the other) , the direct rule of three must be applied.

To solve a direct rule of three, the following formula must be followed, being a, b and c known data and x the variable to be calculated:

a ⇒ b

c ⇒ x

So: \(x=\frac{cxb}{a}\)

The direct rule of three is the rule applied in this case where there is a change of units.

To perform in this case the conversion of units, you must first know that:

Then, you can apply the following rules of three:

1 meter ⇒ 1.09361 yards

100 meters ⇒ x

So: \(x=\frac{100 metersx1.09361 yards}{1 meter}\)

Solving:

x= 109.361 yards

1 meter ⇒ 3.28084 feets

100 meters ⇒ x

So: \(x=\frac{100 metersx3.28084 feets}{1 meter}\)

Solving:

x= 328.084 feets

In summary, 100 meters are 109.361 yards and 328.084 feets.

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Answer:

An atom is a particle of matter that uniquely defines achemical element. An atom consists of a central nucleus that is usually surrounded by one or more electrons. Each electron is negatively charged. The nucleus is positively charged, and contains one or more relatively heavy particles known as protons and neutrons.

Answer:

An atom is a particle of matter that uniquely defines achemical element. An atom consists of a central nucleus that is usually surrounded by one or more electrons. Each electron is negatively charged. The nucleus is positively charged, and contains one or more relatively heavy particles known as protons and neutrons.

The pressure exerted by a column of mercury that is about 760 mm high corresponds to approximately 0.987 atm.

To calculate the pressure exerted by a column of mercury, we can use the formula:

Pressure = density * gravity * height

Given:

Density of mercury = 13.6 g/cm³

Height of the mercury column = 760 mm = 76 cm

Acceleration due to gravity = 9.8 m/s²

First, we need to convert the height of the mercury column from centimeters to meters:

Height = 76 cm * (1 m / 100 cm) = 0.76 m

Now, we can calculate the pressure:

Pressure = 13.6 g/cm³ * 9.8 m/s² * 0.76 m

To ensure consistent units, we need to convert the density from grams per cubic centimeter (g/cm³) to kilograms per cubic meter (kg/m³):

Density = 13.6 g/cm³ * (1 kg / 1000 g) * (1 cm³ / (1e-6 m³))

Density = 13600 kg/m³

Plugging in the values into the pressure formula:

Pressure = 13600 kg/m³ * 9.8 m/s² * 0.76 m

Pressure = 99992.8 Pa

We can express the pressure in terms of atmospheric pressure:

1 atm = 101325 Pa (approximately)

To compare the pressure with atmospheric pressure, we can convert 99992.8 Pa to atm:

Pressure in atm = 99992.8 Pa / 101325 Pa/atm

Pressure in atm ≈ 0.987 atm

The pressure exerted by a column of mercury that is about 760 mm high corresponds to approximately 0.987 atm. Since atmospheric pressure near sea level is approximately 1 atm, this calculation supports the claim that atmospheric pressure near sea level is equivalent to the pressure exerted by a column of mercury about 760 mm high.

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The reaction is

moles of acid

Molarity of acid

The answer is: the molarity of the acid solution is 0.51 M

The molecules in a copper penny is closely packed and and has no space to move apart thus the material will be denser than that in the molten state. That's why the penny sink in the molten copper.

Copper is a transition metal exhibiting all the metallic properties. The molten state of metals is the fluid state where the molecule are not strongly held by the metallic bonds.

Molten material is made by melting them and the liquid like state contains molecules with some space to move apart. Whereas, in solid state as in a copper penny, the molecules are closely packed and have no space to move apart.

An object will sink in a liquid if it is less dense than the liquid. Copper penny is denser than the molten copper because the molecules are densely packed and it will sink on to it.

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Answer:

see explanations

Explanation:

              PCl₅  =>     PCl₃     +     Cl₂

C(eq):   [PCl₅]       0.054M        0.34M

a.  Keq = [PCl₃][Cl₂]/[PCl₅]

b.  7.9 = (0.054)(0.34)/[PCl₅] => [PCl₅] = (0.054)(0.34)/(7.9) = 0.0023M

c.  If [PCl₃] = 0.054M; [Cl₂] = 0.34M and [PCl₅] = 0.0023M then the reaction is at equilibrium and will not shift forward or in reverse. In order to determine if reaction is not at equilibrium, a set of concentration values needs to be given in problem, used to calculate Qeq and compared to the given Keq value.  The following defines direction of shift ...

Keq  <  Qeq  =>  rxn shifts left

Keq  =  Qeq  =>  rxn is at equilibrium (no shift)

Keq  >  Qeq  =>  rxn shifts right

NOTE: If Keq is listed first followed by Qeq in the above conditions, the inequality symbol indicates direction of shift.

Answer:

pH ≈ 6.3

Explanation:

To calculate the pH of an aqueous solution, you need to know the hydronium ion (H₃O+) concentration in moles per liter (molarity).  The pH is then calculated using the expression:

      pH = - log [H₃O+]

Since the solution has an H₃O+ ion concentration of 5.2 × 10⁻⁷ M, we can plug that in and solve:

      pH = - log [5.2 × 10⁻⁷]

      pH = 6.28

Answer: Boiling because it makes the molecules in water bounce around.

Hope it helps.

Subaquatic soil can be classified as sediment or soil based on its geological properties and formation processes.

Sediment refers to any material that is transported and deposited by water, wind, ice, or gravity. Sediments can be composed of various materials, such as minerals, rocks, organic matter, and even human-made debris.

Sediments can accumulate in different environments, such as rivers, lakes, oceans, and deserts, and can be deposited in layers over time.

Subaquatic soil can be classified as sediment or soil based on its geological properties and formation processes. If it has primarily formed through sediment deposition, it is more appropriate to classify it as sediment.

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Answer:

\(m_{H_2O}=0.676gH_2O\)

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to calculate the maximum mass of water by firstly setting up the undergoing chemical reaction as follows:

\(CH_4+2O_2\rightarrow CO_2+2H_2O\)

Thus, we are able to firstly calculate the moles of water produced by both methane and oxygen in order to identify the limiting reactant, which is related to maximum of water:

\(0.963 gCH_4*\frac{1molCH_4}{16gCH_4}*\frac{2molH_2O}{1molCH_4} =0.120molH_2O\\\\1.2gO_2*\frac{1molO_2}{32gO_2}*\frac{2molH_2O}{2molO_2} =0.0375molH_2O\)

Thus, we infer the limiting reactant is O2 and therefore we can obtain up to 0.0375 moles of water, which are related to the following mass:

\(m_{H_2O}=0.0375molH_2O\frac{18.02gH_2O}{1molH_2O}=0.676gH_2O\)

Regards!

The name of the aromatic hydrocarbon shown in the photo is 1,4-dimethylbenzene.

Xylene, xylol or dimethylbenzene is a derivative of benzene. It is made up of carbon and hydrogen. It is a colorless, flammable liquid with a toluene-like odor. This aromatic hydrocarbon is a good solvent, we find it in many fuel formulations.

This aromatic hydrocarbon is found in different substances such as some oils, in coke gases (combustible gases that have a luminous flame when burned) and in gases obtained from the distillation of wood.

Xylenes are substances that can affect the functions of living beings, their vapors can give different symptoms such as nausea, headache and discomfort.

Therefore, we can confirm that the name of the aromatic hydrocarbon shown in the photo is 1,4-dimethylbenzene.

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Answer:

Ionic bond.

Explanation:

Group 7 elements like Bromine (Br) and group 2 elements like Magnesium,(Mg) involved loss and gain of electrons which is typical with Ionic bonding.

The reference point in this scenario is the starting position of the toy car​.

A reference point is can be defined as the frame of reference or point mark from the various of measurement of the car's motion is determined.

When an object starts its motion from zero origin, its reference is point will be the zero origin.

Generally, the reference point of an object in motion is usually the starting position of the object.

Thus, the reference point in this scenario is the starting position of the toy car​.

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31.5 g of Sulfuric acid can be produced from the given amounts of Sulfur trioxide and Water.

Option 'c' is the right response to this question because sulphur trioxide cannot be directly dissolved in water to create sulphuric acid because doing so produces a thick fog of the acid that is difficult to condense.

Sulfur trioxide + Water → Sulfuric acid

moles of Sulfur trioxide = mass/molar mass = 25.7 g / 80.06 g/mol = 0.321 mol

moles of Water = volume x density/molar mass = 12.7 mL x 1.00 g/mL / 18.02 g/mol = 0.705 mol

The amount of Sulfuric acid that can be produced is equal to the number of moles of Sulfur trioxide, which is 0.321 mol. To convert this to grams, we multiply by the molar mass of Sulfuric acid:

mass of Sulfuric acid = moles of Sulfuric acid x molar mass = 0.321 mol x 98.08 g/mol = 31.5 g

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