Which of the following are examples of physical properties? Select all that apply.
Melting point
Density
Flammability
Odor

Answer:

yes

Explanation:

This is because all living tissues

have magnetic properties that are affected to some extent by the existence of electromagnetic radiation in the environment.

Answer: The concentration of hydrogen ions is \(10^{-11}M\) and the concentration of hydroxide ions is \(10^{-3}M\). Thus the concentration of hydroxide ions is more than the concentration of hydrogen ions.

Explanation:

pH or pOH is the measure of acidity or alkalinity of a solution.

pH is calculated by taking negative logarithm of hydrogen ion concentration.  

\(pH=-\log [H^+]\)

\(pOH=-\log[OH^-]\)

Putting in the values:

\(11=-\log[H^+]\)

\([H^+]=10^{-11}M\)

\(pH+pOH=14\)

\(pOH=14-11=3\)

\(3=-log[OH^-]\)

\([OH^-]=10^{-3}M\)

Thus the concentration of hydroxide ions is more than the concentration of hydrogen ions.

1. Ammonia is a colorless gas with a chemical formula of NH3, when it comes in contact with water, it will be transformed into Ammonium ion and it will produce one hydroxide ion, and this is why Ammonia will present a more basic (pH) behavior, the reaction that represents this behavior is:

NH3 + H2O -> NH4+ + OH-

Number 4 is the only one that represents it well

Number 3 has the same reaction but since there is a plus sign instead of an arrow, I consider it wrong.

The three significant digits of Strontium-90 are is=3.5 gms

sample will remain= No/Nt= No/2^n

time= n*half life

t=n* t1/2

n=115.2/28.8=4

56/(2)^4= 56/16

sample will reamins = 3.5 gms  

29 years, Strontium-90 is the most prevalent isotope of this element. The half-life is the amount of time needed for a radioactive substance to decay and lose half of its radioactivity. With a half-life of 29 years, strontium-90 decays by releasing comparatively low-energy beta particles.

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Among the given compounds, CO₂ is a compound that is not ionic.

In this question, we have been given four compounds - CaCl₂, CO₂, (NH₄)₂O, and NaI and among these four compounds, we have to tell which compound is not ionic.

A compound can be ionic or covalent. And the compound which is not ionic is also called a covalent compound.

So let us comment on each compound one by one.

CaCl₂ - It is an ionic compound because it is a compound formed between a metal and a non-metal. As a general rule, any compound formed between a metal and a nonmetal is called an ionic compound and a compound between a nonmetal and a nonmetal is called a covalent compound.

(NH₄)₂O - Though this is a compound containing no metallic element, it is still an ionic compound.  NH₄⁺ is an ion, though still a nonmetal. We should remember that NH₄ compounds are exceptions to this rule. All compounds of NH₄ are actually ionic. Hence (NH₄)₂O is an ionic compound.

NaI - It is again a compound made of a metal and a nonmetal. Hence, according to the rule stated above, it is an ionic compound.

CO₂ - It is a compound made of a nonmetal and a nonmetal. Therefore, it is a covalent compound

Hence, among the above-given compounds, CO₂ is a covalent compound.

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The limiting reactant for solid aluminum al and oxygen o2 gas react to form solid aluminum oxide al2o3. suppose you have 2.0 mol of al and 3.0 mol of o2 in a reaction is Al.

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The arrangement of 5 electron groups around a central atom is trigonal bipyramidal. This molecular geometry consists of three groups lying in a trigonal plane around the central atom, with bond angles of approximately 120°. The other two groups lie above and below this plane, creating bond angles of approximately 90°.

Molecular geometry refers to the three-dimensional arrangement of atoms in a molecule. It describes the spatial orientation and relative positions of the atoms, including bond lengths, bond angles, and overall shape of the molecule.

The molecular geometry is determined by the arrangement of electron pairs around the central atom, considering both bonding and nonbonding electron pairs. The electron pairs repel each other, and the molecule adopts a shape that minimizes this repulsion, resulting in specific bond angles and molecular shapes.

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To determine the mass percent of chloride in the original sample, we need to first calculate the amount of chloride present in the sample. We can do this by using the balanced equation for the reaction between chloride and silver nitrate:

AgNO3 + Cl- → AgCl + NO3-

First, we need to calculate the number of moles of silver nitrate used in the titration:

moles of AgNO3 = volume (L) x molarity (M) = 0.03083 L x 0.7890 M = 0.02439 moles

Next, we can use the balanced equation to find the number of moles of chloride:

moles of Cl- = moles of AgNO3 = 0.02439 moles

Finally, we can use the number of moles of chloride to calculate the mass of chloride in the sample:

mass of Cl- = moles of Cl- x molar mass of Cl- = 0.02439 moles x 35.5 g/mol = 0.868 g

To find the mass percent of chloride in the original sample, we divide the mass of chloride by the total mass of the sample and multiply by 100%.

mass percent of Cl- = (mass of Cl- / total mass of sample) x 100%

Since we don't know the total mass of the sample, we can use the mass of chloride we just calculated and the formula above to find the mass percent of chloride in the original sample.

mass percent of Cl- = (0.868 g / 0.1599 g) x 100% = 54.3%

So, the mass percent of chloride in the original sample is 54.3%.

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The safety relief system is an important component of a process plant. A good safety relief system ensures that the equipment is protected against overpressure situations. Chlorination reactors with organic reactants require the utmost care in the design of the relief systems.

Considerations involved in designing safety relief system and relief scenario for a chlorination reactor with organic reactants are discussed below:

1. Hazard Identification: Identify the hazards associated with the reaction chemistry of the chlorination reactor with organic reactants. Also, assess the potential failure scenarios that may lead to an overpressure event.

2. Relief Scenarios: Consider the design of relief scenarios that will be used to protect the reactor and the surrounding equipment. The scenarios should be designed to address all potential overpressure events.

3. Relief Devices: Choose the right type of relief device(s) based on the process parameters and the required relief scenario. The relief devices must be designed to relieve the pressure within the reactor in a safe manner.

4. Relief Sizing: Calculate the size of the relief devices based on the maximum potential relief flow rate. The sizing should be done in such a way that the device can handle the maximum expected pressure with a reasonable margin of safety.

5. Relief Piping: Design the relief piping such that it has the capacity to handle the maximum expected relief flow rate. The piping should be arranged in such a way that it can relieve the pressure in a safe manner.

6. Relief Header and Disposal: Design the relief header and the disposal system in such a way that it can safely handle the maximum expected relief flow rate. The header and the disposal system should be arranged in such a way that they do not pose a hazard to the surrounding equipment and personnel.

7. Testing and Maintenance: Test the relief system regularly to ensure that it functions as expected. Also, maintain the system in accordance with the manufacturer's recommendations to ensure that it remains in good working order.

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Answer:The relationship which is between bacteria and ungulates with the intestine is or good example of mutualism. Mutualism plays an important role in ecology. We can say that if we measure the exact fitness what we get as a benefit is a mutualistic relationship.example of a mutualistic relationship is that of the oxpecker (a kind of bird) and the rhinoceros or zebra. Oxpeckers land on rhinos or zebras and eat ticks and other parasites that live on their skin. The oxpeckers get food and the beasts get pest control.

Explanation:

hope this helps have a nice night❤️❤️❤️❤️

Explanation:

a human uses dog to protect a flock of sheep

I also din't know about these..

Most reef-building corals contain photosynthetic cells, called zooxanthellae, that live in their tissues.

WHY Jörg Wiedenmann put corals into warm water in his lab?

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Alkylating agents are not used in the acetoacetic ester synthesis of methyl isobutyl ketone. The acetoacetic ester synthesis is a type of organic reaction.

The  response of an alkyl halide, ethyl acetoacetate, with a strong base,  similar as sodium ethoxide, yields a beta- keto ester. The process begins by forming an enolate intermediate, which is  latterly alkylated by the alkyl halide. After that, the product is hydrolyzed and decarboxylated to  give the  needed beta- keto ester.    

The alkyl halide employed for alkylation in the acetoacetic ester  conflation of methyl isobutyl ketone would be isobutyl iodide, not an alkylating agent. The enolate intermediate of ethyl acetoacetate is alkylated with isobutyl iodide, followed by hydrolysis and decarboxylation to  induce the product, methyl isobutyl ketone.   It's worth mentioning that alkylating chemicals,  similar as nitrogen mustards and alkyl sulfonates, are utilised in cancer treatment as chemotherapeutic agents.

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Answer:

B. A+ B → AB

Explanation:

general form of a synthesis reaction

After one day, approximately 8.67mg of the sample will be remaininga) The function that models the sample of Technetium-99 is given by

f(t) = P₀e^(-kt)

Where,P₀ = initial quantity = 100mgk = decay constantt = timef(t) = remaining quantity after t time.

A half-life of 6 hours is given. The decay constant can be found using the half-life formula:

T½ = (ln 2)/k6

= (ln 2)/kk

= (ln 2)/6f(t)

= P₀e^(-kt)f(t)

= 100e^(-0.1155t)mg

b) After one day, 24 hours = 4 half-lives Remaining amount,

f(t) = P₀e^(-kt)f(24)

= 100e^(-0.1155 × 24)

= 100e^(-2.772)

≈ 8.67mg

After one day, approximately 8.67mg of the sample will be remaining. The function that models the sample is

f(t) = 100e^(-0.1155t), where t is time in hours and f(t) is the remaining quantity in milligrams.

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After one day, approximately 8.67mg of the sample will be remaininga) The function that models the sample of Technetium-99 is given by

f(t) = P₀e^(-kt)

Where,P₀ = initial quantity = 100mgk = decay constantt = timef(t) = remaining quantity after t time.

A half-life of 6 hours is given. The decay constant can be found using the half-life formula:

T½ = (ln 2)/k6

= (ln 2)/kk

= (ln 2)/6f(t)

= P₀e^(-kt)f(t)

= 100e^(-0.1155t)mg

b) After one day, 24 hours = 4 half-lives Remaining amount,

f(t) = P₀e^(-kt)f(24)

= 100e^(-0.1155 × 24)

= 100e^(-2.772)

≈ 8.67mg

After one day, approximately 8.67mg of the sample will be remaining. The function that models the sample is

f(t) = 100e^(-0.1155t), where t is time in hours and f(t) is the remaining quantity in milligrams.

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Answer:

A. Sympathetic

and

C. Parasympathetic

Explanation:

Ap3x

The paired t-test yields a different conclusion than the normal t-test because it accounts for the paired nature of the data, comparing the measurements taken at the top and bottom of the lake separately.

In this scenario, the paired t-test is appropriate because it analyzes the data as pairs, considering the chloride levels measured at the top and bottom of the lake for each sample. By comparing the differences within each pair, the paired t-test determines whether there is a significant difference between the chloride levels at the top and bottom of the lake.

Using the paired t-test, the differences between the paired observations are calculated, and the null hypothesis assumes that the mean difference is zero (no significant difference between the top and bottom chloride levels). The test then determines whether the observed differences are statistically significant at a chosen confidence level, in this case, 95%.

The normal t-test for differences in means, on the other hand, would treat the top and bottom chloride levels as separate and unrelated groups, disregarding their paired nature. By pooling the data and conducting a standard t-test, the analysis assumes that the two sets of measurements are independent, which may not be appropriate in this case. This can lead to a different conclusion compared to the paired t-test.

The different conclusion drawn from using the paired t-test compared to pooling the data and using the normal t-test is due to the consideration of the paired nature of the measurements. The paired t-test takes into account the potential correlation or connection between the measurements taken at the same location (top and bottom of the lake) and assesses the differences within each pair.

Pooling the data and using the normal t-test treats the measurements as independent, disregarding the pairing. This can result in a loss of valuable information and may lead to an inaccurate conclusion. The paired t-test is more appropriate when dealing with dependent or related measurements, ensuring a more accurate assessment of the differences between the top and bottom chloride levels.

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A solution that contains the chemical compounds CsF and HF will serve as a buffer.

When a weak acid, as well as its conjugate base or weak base as well as its conjugate acid, are combined, buffer solutions are created that serve to maintain the solution's pH level even when a little amount of a strong acid is added.

Except for CsF and HF, all of the aforementioned pairings will create a buffer solution since CsF is a weak base whereas F is the organic compound with the formula of HF acid.

A buffer is a substance that can withstand a pH shift when acidic or basic substances are added. It can maintain the solution's pH by neutralizing modest quantities of additional acid or base.

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Answer:1. Introduction

The main air pollutants are represented by gases forms, particles in suspension, different ionizing radiation and noise.

The gases forms are: oxidized and reduced forms of carbon (CO2, CO, CH4), of nitrogen (NO2, NO, N2O4, NH3, NH4+), SO2, O3, C6H6 vapours, Hg, volatile phenols, Cl2, etc.

The particulate forms are: PM10 and PM2.5 particulate matter, heavy metals with toxic effect (Pb, Ni, Cd, As), polycyclic aromatic hydrocarbons PAHs, etc.

Atmospheric pollutants have a negative effect on the plants; they can have direct toxic effects, or indirectly by changing soil pH followed by solubilization of toxic salts of metals like aluminum. The particulate matters have a negative mechanical effect. They cover the leaf blade reducing light penetration and blocking the opening of stomata. These impediments influence strongly the process of photosynthesis which rate declines sharply.

Explanation:

Answer:

A More air pollution because there are fewer trees to take in carbon dioxide

C Fewer birds and other wildlife because they have fewer places to live

Explanation:

I took the test on A P E X

The mass of hydrogen present in the 300 mL sample is approximately 18.14 grams. To determine the mass of hydrogen present in the sample, we need to account for the partial pressure of hydrogen and correct for the presence of water vapor.

The total pressure in the sample is the sum of the partial pressure of hydrogen and the vapor pressure of water:

Total pressure = Partial pressure of hydrogen + Vapor pressure of water

The partial pressure of hydrogen can be calculated using Dalton's law of partial pressures:

Partial pressure of hydrogen = Total pressure - Vapor pressure of water

Now, we can use the ideal gas law equation to calculate the number of moles of hydrogen:

PV = nRT

where:

P = Partial pressure of hydrogen (in atm)

V = Volume of hydrogen (in L)

n = Number of moles of hydrogen

R = Ideal gas constant (0.0821 L·atm/(mol·K))

T = Temperature (in Kelvin)

Let's convert the volume from milliliters to liters:

Volume of hydrogen = 300 mL = 300/1000 L = 0.3 L

Now, we can rearrange the ideal gas law equation to solve for the number of moles:

n = PV / RT

n = (729 torr * 0.3 L) / (0.0821 L·atm/(mol·K) * 294.15 K) [21°C converted to Kelvin]

Performing the calculation:

n = (218.7 torr·L) / (24.11 L·atm/(mol·K))

n ≈ 9.07 mol

Finally, we can calculate the mass of hydrogen using the molar mass of hydrogen (H₂):

Mass of hydrogen = Number of moles * Molar mass of hydrogen

Molar mass of hydrogen = 2 g/mol

Mass of hydrogen = 9.07 mol * 2 g/mol

Mass of hydrogen ≈ 18.14 g

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Answer:

In your science class, you will learn about Newton’s laws of motion. Do you know why these laws are so important? When you throw a baseball or you bounce a basketball on the court, you can use Newton’s laws to explain the motion of the baseball or basketball. In fact, almost all motion in the world can be explained by these laws. Newton’s laws are useful when people design airplanes, trains, cars, sports equipment, toys, and many things that have to do with motion. Some people have trouble understanding Newton’s laws of motion because it’s hard to see how the laws work without any examples. One great way to understand these laws is to look at how they relate to cars in everyday life.

The First Law of Motion

“Every object persists in its state of rest or uniform motion in a straight line unless it is compelled to change that state by forces impressed upon it.”

Can you see why it’s hard for some people to understand the first law? Those are some complicated words. To help you to understand better, let’s break it down and use the example of a car. The first part deals with an object in a “state of rest”. This means that the object is not moving. When your mom or dad parks the car in the garage or the shopping mall, the car is said to be in a “state of rest” because it is not moving. The car will not move until the engine is started and somebody drives it away. The second part deals with an object in “uniform motion”. This means that the object is moving at the same speed. When you mom or dad is using “cruise control” on a highway at 60 miles per hour, the car will be moving at that speed in a “straight line” until something happens to change it. What is this change? It depends. By using the brakes, your mom or dad can slow the car down or bring it to a stop. On the other hand, the car’s direction will be changed if it is hit by another motor vehicle.Explanation:

Answer:

Personality tests are often used to gain insight into who people are, along with what motivates them. From an employer perspective, understanding the personality of a potential hire can shed light on their work style and how they might fit into the company's work culture

methane

Which molecule has a tetrahedral arrangement of electron pairs but is not a tetrahedral molecule? methane

Answer:

0.2 nm

Explanation:

i. The mass of air inside the tank is calculated using the ideal gas law: m₁ = (P₁V₁) / (RT₁), and m₂ = (P₂V₂) / (RT₂).

ii. The final pressure inside the tank after cooling is determined using Boyle's Law: P₁V₁ = P₂V₂.

iii. Repeat the calculations for heating from 25°C to 175°C using the given temperatures and equations to determine mass and final pressure, then compare the results.

a) Charles' Law states that at constant pressure, the volume of a gas is directly proportional to its temperature, expressed mathematically as V₁ / T₁ = V₂ / T₂. Boyle's Law states that at constant temperature, the pressure of a gas is inversely proportional to its volume, expressed as P₁V₁ = P₂V₂.

b)

i. To determine the mass of air inside the tank, we need to use the ideal gas law equation:

PV = mRT, where P is pressure, V is volume, m is mass, R is the gas constant, and T is temperature.

Step 1: Convert temperatures to Kelvin:

T₁ = 110°C + 273.15 = 383.15 K

T₂ = 55°C + 273.15 = 328.15 K

Step 2: Calculate the initial mass using the ideal gas law:

m₁ = (P₁V₁) / (RT₁)

Step 3: Calculate the final mass using the ideal gas law:

m₂ = (P₂V₂) / (RT₂)

ii. To determine the final pressure inside the tank after cooling, we can use Boyle's Law:

P₁V₁ = P₂V₂

c)

To calculate the mass and final pressure for heating from 25°C to 175°C, we follow the same steps as in part b, using the given temperatures and applying the ideal gas law and Boyle's Law.

Step 1: Convert temperatures to Kelvin:

T₁ = 25°C + 273.15 = 298.15 K

T₂ = 175°C + 273.15 = 448.15 K

Step 2: Calculate the mass using the ideal gas law:

m₁ = (P₁V₁) / (RT₁)

m₂ = (P₂V₂) / (RT₂)

Step 3: Calculate the final pressure using Boyle's Law:

P₁V₁ = P₂V₂

Finally, compare the obtained results for both cases to analyze the effect of cooling and heating on the mass and final pressure of the air inside the tank.

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The true options for purifying water are:

Boiling vigorously for at least one minute: This is a simple and effective way to kill most types of bacteria, viruses, and parasites that can be found in water. It's recommended to boil the water for at least one minute (or three minutes at higher altitudes) to ensure that all pathogens are killed.

Chemically treating water with chlorine or iodine: Adding chlorine or iodine to water can also be an effective way to kill most types of bacteria, viruses, and parasites. These chemicals are often used in emergency situations or for camping and hiking trips.

Purifying with a commercial micro filter: A commercial micro filter can remove most types of bacteria, parasites, and some viruses from water. These filters can be used for camping and hiking trips or for home use.

Filtering water with tightly woven material (option c) is not an effective method for purifying water as it can only remove larger particles and sediments and not pathogens.

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Answer:

0.0035

Explanation:

3.5 millimetres = 0.0035 meters

Answer:

0.0035 m

Explanation:

since 1000 mm is equal to 1 m

then 3.50 mm will be equal to lets say x

1000 mm = 1 m

3.50 mm = x m

cross multiply

1000 × x = 3.50 × 1

divide both sides by 1000

x = 3.50/1000

x= 0.0035 m