Which of the following are advantages of
assessments? Check all that apply.
They can provide an accurate picture of
someone's personality.
They may be used to target salary increases.
They can be used to target employee training.
They may lead to increased patience.
They may lead to lower turnover rates.

Answer:

a:s

b:s

c:r

d: r

e: s

f:  s

g: s

Explanation:

Answer: decantation and screening

Explanation:

Answer:

it is A

Explanation:

the person above me helped

Answer:

this is formula

Explanation:

Answer:

r56

Explanation:

As a result of the block being slightly lowered and then released, the oscillation frequency is  f = 3.5Hz.

In physics, what do oscillation and frequency mean?

Periodic to-and-fro motion that repeatedly repeats the same pattern is known as oscillatory motion. The to-and-fro movement of an object relative to its mean location is referred to as oscillatory motion. The frequency of oscillating particles is defined as the number of cycles that they complete in a second.

One oscillation is what?

The periodic to-and-fro oscillation of the a Simple pendulum was referred to as its oscillatory motion .One oscillations of a pendulum is defined as the motion of a bob starting from one tip and returning to the other.

We know that:

\(\begin{aligned}& F=-\mathrm{kx} \\& |F|=k x \\& m g=k x \\& \frac{\mathrm{k}}{\mathrm{m}}=\frac{\mathrm{g}}{\mathrm{x}} \\& \mathrm{f}=\frac{1}{2 \pi} \sqrt{\frac{\mathrm{k}}{\mathrm{m}}}=\frac{1}{2 \pi} \sqrt{\frac{g}{x}}=\frac{1}{2 \pi} \sqrt{\frac{9.8}{0.02}}=3.523 \mathrm{~Hz}\end{aligned}\)

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The principles which allow aircraft to fly are also applicable in car racing. The only difference being the wing or airfoil shape is mounted upside down producing downforce instead of lift. The Bernoulli Effect means that: if a fluid (gas or liquid) flows around an object at different speeds, the slower moving fluid will exert more pressure than the faster moving fluid on the object. The object will then be forced toward the faster moving fluid. The wing of an airplane is shaped so that the air moving over the top of the wing moves faster than the air beneath it. Since the air pressure under the wing is greater than that above the wing, lift is produced. The shape of the Indy car exhibits the same principle. The shape of the chasis is similar to an upside down airfoil. The air moving under the car moves faster than that above it, creating downforce or negative lift on the car. Airfoils or wings are also used in the front and rear of the car in an effort to generate more downforce. Downforce is necessary in maintaining high speeds through the corners and forces the car to the track. Light planes can take off at slower speeds than a ground effects race car can generate on the track. An Indy ground effect race car can reach speeds in excess of 230 mph using downforce. In addition the shape of the underbody (an inverted wing) creates an area of low pressure between the bottom of the car and the racing surface. This sucks the car to road which results in higher cornering speeds.

The total aerodynamic package of the race car is emphasized now more than ever before. Teams that plan on staying competitive use track testing and wind tunnels to develop the most efficient aerodynamic design. The focus of their efforts is on the aerodynamic forces of negative lift or downforce and drag. The relationship between drag and downforce is especially important. Aerodynamic improvements in wings are directed at generating downforce on the race car with a minimum of drag. Downforce is necessary for maintaining speed through the corners. Unwanted drag which accompanies downforce will slow the car. The efficient design of a chassis is based on a downforce/drag compromise. In addition the specific race circuit will place a different demand on the aerodynamic setup of the car.

A road course with low speed corners, requires a car setup with a high downforce package. A high downforce package is necessary to maintain speeds in the corners and to reduce wear on the brakes. This setup includes large front and rear wings. The front wings have additional flaps which are adjustable. The rear wing is made up of three sections that maximize downforce.

The speedway setup looks much different. The front and rear wings are almost flat and are used as stabilizers. The major downforce is found in the shape of the body and underbody. Drag reduction is more critical on the speedway than on other circuits. Since the drag force is proportional to the square of the speed, minimizing drag is a primary concern in the speedway setup. Lap speeds can average over 228 mph and top speeds can exceed 240 mph on a speedway circuit. Effective use of downforce is especially pronounced in highspeed corners. A race car traveling at 200 mph. can generate downforce that is approximately twice its own weight.

Generating the necessary downforce is concentrated in three specific areas of the car. The ongoing challenge for team engineers is to fine tune the airflow around these areas.

Answer:

The volume of the coin is 4.236 x 10⁻⁷ m³

Explanation:

Given;

radius of a coin, r = 1.06 cm = 0.0106 m

thickness of the coin, h = 1.2 mm = 0.0012 m

The volume of the coin is given by;

volume = Area x thickness

Area of the coin = πr² = π (0.0106)² = 3.5304 x 10⁻⁴ m²

The volume of the coin = (3.5304 x 10⁻⁴ m²) x (0.0012 m)

The volume of the coin = 4.236 x 10⁻⁷ m³

Therefore, the volume of the coin is 4.236 x 10⁻⁷ m³

answer :

Visible: Our eyes detect visible light. Fireflies, light bulbs, and stars all emit visible light. Ultraviolet: Ultraviolet radiation is emitted by the Sun and are the reason skin tans and burns. "Hot" objects in space emit UV radiation as well.

Which objects emit electromagnetic waves?

All objects emit electromagnetic radiation according to their temperature. Colder objects emit waves with very low frequency (such as radio or microwaves), while hot objects emit visible light or even ultraviolet and higher frequencies.

Answer:

Gravitational Potential Energy = Mass*Gravity*Height.

GPE = 852 * 9.8 * 3.2

GPE = 26718.72 Newtons.

The approximate speed of the roller coaster is 32m/s.  

Considering that the earth and the roller coaster are both parts of one system.

We can use the law of conservation of energy,

This law states that in a system, the sum of total energy is always conserved.

So we can say that the energy at the top of roller coaster will be equal to the energy at the bottom of the roller coaster.

At top, whole energy is potential energy and the bottom whole energy is kinetic energy,

So we can write,

PE = KE

Mgh = 1/2Mv²

Where M is mass of roller coaster,

v is the speed of roller coaster,

g is acceleration due to gravity and,

h is the height of the roller coaster,

Putting all the values,

gh = 1/2v²

v² = 2gh

v² = 2×9.8×51

v² = 999.6

v = 31.61 m/s.

The speed of roller coaster at the end is 32 m/s approx.

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Answer:

F = M ω^2 R     is the centripetal force on the ball

f = 7 / 10 = .70 / sec      revolutions / sec

ω = 2 pi f = 4.40 / sec

ah = F / m = 4.4^2 * 2 = 38.7 m/s^2

horizontal acceleration = 38.7 m/s^2

vertical acceleration = 9.80 m/s^2

a = (38.7^2 + 9.8^2)^1/2 = 39.9 m/s^2    total acceleration

The chemical energy used to drive the light independent reactions, also known as the Calvin cycle, is in the form of ATP and NADPH.

ATP, or adenosine triphosphate, is a high-energy molecule that stores and releases energy. It is produced during the light-dependent reactions of photosynthesis through the process of photophosphorylation. NADPH, or nicotinamide adenine dinucleotide phosphate, is another high-energy molecule that is also produced during the light-dependent reactions through the process of non-cyclic electron flow.

Both ATP and NADPH are used in the light independent reactions to power the conversion of carbon dioxide into glucose and other sugars. The energy from these molecules is used to drive the fixation of carbon dioxide by an enzyme called rubisco, which converts it into a carbohydrate called 3-phosphoglycerate. This process is the key to the synthesis of glucose and other sugars in photosynthesis.

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The weak force and the electromagnetic force are two fundamental forces in nature that have distinct characteristics. One notable contrast between them is their range of influence.

The weak force acts within the nucleus of an atom, specifically within protons and neutrons, and has a very short-range, limited to distances on the order of nuclear dimensions.

In contrast, the electromagnetic force has an infinite range, meaning it can act over long distances, reaching out to infinity.

Furthermore, the nature of the forces' interactions differs. The weak force is both attractive and repulsive, meaning it can either attract or repel particles depending on the circumstances.

On the other hand, the electromagnetic force is solely attractive, leading to the attraction of charged particles and the binding of electrons to atomic nuclei.

In summary, the weak force acts within protons and neutrons, with a limited range, and exhibits both attractive and repulsive behavior, while the electromagnetic force has an infinite range, acts between charged particles, and is exclusively attractive.

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General expression for the resonant wavelength in an open-closed resonator for any n:

a. λ=4L/n.

The resonant wavelength in an open-closed resonator can be found using the general expression λ=4L/n, where L is the length of the resonator and n is the mode number. This equation is valid for any value of n and is used to determine the resonant wavelengths for a variety of applications, such as in laser cavities and microwave resonators.

The expression shows that the resonant wavelength is inversely proportional to the mode number and directly proportional to the length of the resonator.

Therefore, the correct answer is a. λ=4L/n.

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Answer: \(-\frac{1}{2}\times \frac{d[Br^.]}{dt}=+\frac{d[Br_2]}{dt}\)

Explanation:

Rate of a reaction is defined as the rate of change of concentration per unit time.

Thus for reaction:

\(2Br^.\rightarrow Br_2\)

The rate in terms of reactants is given as negative as the concentration of reactants is decreasing with time whereas the rate in terms of products is given as positive as the concentration of products is increasing with time.

\(Rate=-\frac{d[Br^.]}{2dt}\)

or \(Rate=+\frac{d[Br_2]}{dt}\)

Thus \(-\frac{d[Br^.]}{2dt}=+\frac{d[Br_2]}{dt}\)

Answer: the answer is d $19.95

Explanation:

chicken dinner: 6.95 x 3 = 20.85

burger: 5.75

20.85 + 5.75 = 26.6

26.6 divided by 4 (bc theres 4 ppl and the bill needs to be split equally)

26.6/4= 6.65

and since 3 friends are paying him back u gotta do 6.65 x 3 = 19.95

Answer:

water process?

Explanation:

Always wash your hands, hand washing skills. By the way you spelt thanks* improperly.

Available options are:

A. –4500 N

B. –2500 N

C. 2500 N

D. 4500 N

Answer:

-4500 N

Explanation:

Given that we have F₁ = 3000N? (force of the barge)

the force of the tugboat is F '

To pull the barge, the force of the tugboat must be greater than or equal to the force of the barge.

Hence, according to Newton's third law which states that for every action or force in nature, there is an opposite reaction.

Therefore considering the available option the correct answer is "- 4500N, " this is because it is greater than the force of the barge and it's in opposition to the force exerted.

Answer:

The answer is -4500 N

Explanation:

Answer:

i vigilate

Explanation:

(a) The initial temperature is 373.95 K.

(b) The final temperature is 546.15 K.

(c) The total internal energy change of the fluid during this process is 515.4 kJ.

(d) The process can be represented as an isochoric heating process on the P-v diagram and as an isobaric expansion process on the T-v diagram.

(a) To find the initial temperature, we can use the saturated steam tables. At a pressure of 200 kPa, the corresponding saturation temperature is 373.95 K.

(b) Since the volume doubles, the process is an isochoric (constant volume) heating process. Using the ideal gas law, we can determine the final temperature. The initial and final volumes are related by the equation V_final = 2V_initial. Since the mass remains constant, the specific volume (v) is inversely proportional to the density (ρ). Therefore, ρ_final = ρ_initial/2. Using the ideal gas law, we can calculate the final temperature to be 546.15 K.

(c) The total internal energy change can be calculated using the equation ΔU = mC_vΔT, where m is the mass of the fluid and C_v is the specific heat at constant volume. Given the mass as 0.5 kg, the specific heat of water at constant volume, and the temperature change, we can find that the total internal energy change is 515.4 kJ.

(d) On the P-v diagram, the process is represented as a vertical line at 200 kPa, indicating constant pressure. On the T-v diagram, the process is shown as an upward-sloping line, indicating an isobaric expansion process. The initial state is represented as a point on the left, and the final state is represented as a point on the right. The path between the initial and final states is a straight line connecting these two points.

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The minimal speed at which a mass must be ejected off the surface of the Earth in order to escape the gravitational pull of the planet is known as the escape speed.

The gravitational constant G, the mass of the attracting mass M, and the distance r from the centre of that mass are used to calculate the escape velocity, vesc, which is represented as vesc = Square root of 2GMr.

The speed at which a body must move in order to escape the gravitational pull of a certain planet or other object is known as the escape velocity. Let's imagine that a body is orbiting a planet of mass M at a distance r from it. Ve=r2GM, a body's escape velocity, where G is the gravitational constant. Explanation in video.

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The answer to the digits rounded to one significant figure is 100.

Significant figures are the most important figures in a number of digits.

The closer a digit is to the beginning of a number, the more important  or significant  it is.

But, the rule for rounding up a set of numbers to the first significant or to one significant figure is that:

From the numbers 98.907, 9 is the most significant digit followed by 8.

8 is greater than 5 so we should round up by adding one to 9 making the number 100.

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In cartesian coordinates, we can write the position vectors as-

a) → r = 12.4 m , θ = 170°    ↔     - 12.21 i + 2.15 j

b) → r = 4 cm , θ = 50°   ↔    2.57 i + 3.06 j

c) → r = 20 inches , θ = 210°   ↔    - 17.32 i - 10 j

It is two-dimensional coordinate system which uses a straight line distance (from a reference point) and the angle made by it (with respect to reference direction) to represent a point in the X-Y plane.

Given are the position vectors in polar coordinates of three points in X-Y coordinate system.

The transformation from polar coordinates (r, θ) into cartesian coordinates (x, y) is done using the following formulae -

x = r cosθ

y = r sinθ

a) → r = 12.4 m , θ = 170°

x = 12.4 x cos (170°) = 12.4 x -0.98480775301 = -12 .21

y = 12.4 x sin (170°) = 12.4 x 0.17364817766 = 2.15

In cartesian form → ( -12.21 i + 2.15 j )

b) → r = 4 cm , θ = 50°

x = 4 x cos (50°) = 4 x 0.64278760968 = 2.57

y = 4 x sin (170°) = 4 x 0.76604444311 = 3.06

In cartesian form → ( 2.57 i + 3.06 j )

c) → r = 20 inches , θ = 210°

x = 20 x cos (210°) = 20 x -0.86602540378 = -17.32

y = 20 x sin (210°) = 20 x -0.5= -10

In cartesian form → ( -17.32 i - 10 j )

Therefore, in cartesian coordinates, we can write the position vectors as -

a) → r = 12.4 m , θ = 170°    ↔     - 12.21 i + 2.15 j

b) → r = 4 cm , θ = 50°   ↔    2.57 i + 3.06 j

c) → r = 20 inches , θ = 210°   ↔    - 17.32 i - 10 j

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Answer:

a moving car

Explanation:

a body remains in its constant state unless un extenal force is applied.

The  mass of the large truck is determined as 5680 kg.

The mass of the truck is calculated as follows;

P = mv

where;

m = P/v

m = 125000/22

m = 5680 kg

Thus, the  mass of the large truck is determined as 5680 kg.

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Answer:

C. 5680

Explanation:

edg2023

We know that, Velocity is the rate of displacement covered. Displacement is the shortest path between the Initial and Final point covered by the body. So,

And, when it comes to Average velocity, It is the total displacement by total time taken. So, By using this let's solve this question.....

✏️ Refer to the attachment...

Let the body goes to point A that is 7 m East of the Initial point. Then it comes backward because West is opposite to East in perpendicular direction. It covers 1.5 m backwards in the same line to reach B which is the Final point.

So,

⇛ Displacement = 7 m - 1.5 m

⇛ Displacement = 5.5 m

Total time taken,

⇛ 2 hours + 1 hour

⇛ 3 hours

Finding Average displacement,

⇛ Total displacement / Total time taken

⇛ 5.5 m / 3 hours

⇛ 1.83333.... hours

So, the Final answer is,

\( \huge{ \boxed{ \bold{ \purple{1.8 \bar{3}m}}}}\)

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