Which of the following accurately pairs the part of an atom to its charge? A. Proton—no charge B. Neutron—positive charge C. Electron—negative charge D. Electron—no charge

The empirical formula of this compound is \(Fe_2O_3\)

To calculate the empirical formula of a compound, the value of moles of each element is needed.

As we have the information of the mass value, we will use the molar mass expression, which corresponds to:

\(MM_O = 16g/mol\\MM_Fe = 55.8g/mol\)

                                              \(MM = \frac{m}{mol}\)

                                                   \(16 = \frac{4.8}{x}\)

                                                   \(x = 0.3mol\)

                                                    \(55.8=\frac{11.2}{x}\\x = 0.2\)

As the value of the empirical formula must be an integer, simply multiply the two values ​​by a common factor:

                                                \(O = 0.3 \times 10 = 3\\Fe = 0.2 \times 10 = 2\)

                                                       \(Fe_2O_3\)

So, the empirical formula of this compound is \(Fe_2O_3\).

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The rate constant of the second-order reaction is 0.111 M^-1 min^-1.

The given data represents a second-order reaction where the rate of the reaction is proportional to the square of the concentration of A.

The integrated form of the second-order reaction is:

1/[A]t = kt + 1/[A]0

where [A]t and [A]0 are the concentrations of reactant A at time t and time zero, respectively, k is the rate constant.

We can use the given information to calculate the rate constant (k) of the reaction for the given half-life (t1/2) of 3.15 minutes:

t1/2 = (1 / k[A]0)

Using the percentage decrease in concentration and the given initial concentration, we can calculate the concentration of A at time t:

[A]t = [A]0 - 0.30[A]0 = 0.57126 M

Substituting the given values, we get:

3.15 min = (1 / k)(0.0818 M) / (0.0818 M - 0.57126 M)

Simplifying the equation above, we can solve for k:

k = 0.111 M^-1 min^-1

Therefore, the rate constant of the second-order reaction is 0.111 M^-1 min^-1.

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Answer:

B = 6 grams

Explanation:

please make me brainlist answer

The formula for Co3+ is Co3+ because it represents the ion of cobalt that has lost three electrons, leaving it with a 3+ charge.

What is chemical formula and how they are formed ?

A chemical formula is a symbolic representation of a chemical compound that shows the types of elements present in the compound and the relative number of atoms of each element. For example, the chemical formula for water is H2O, which indicates that it is made up of two hydrogen atoms and one oxygen atom.

Chemical formulas are formed by identifying the elements that make up a compound and determining the relative number of each element in the compound. The number of each element is represented by a subscript following the chemical symbol of the element. For example, the chemical formula for methane is CH4, which indicates that there is one carbon atom and four hydrogen atoms in each molecule of methane.

The formula for Se2- is Se2- because it represents the ion of selenium that has gained two electrons, giving it a 2- charge.

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The molar mass of MgCrO4 is approximately 140.30 g/mol.

To determine the molar mass of MgCrO4 (magnesium chromate), we need to calculate the sum of the atomic masses of each individual element in the compound.

The chemical formula MgCrO4 indicates that the compound consists of one magnesium atom (Mg), one chromium atom (Cr), and four oxygen atoms (O).

The atomic masses of the elements can be found on the periodic table:

Magnesium (Mg) has an atomic mass of approximately 24.31 g/mol.

Chromium (Cr) has an atomic mass of around 51.99 g/mol.

Oxygen (O) has an atomic mass of about 16.00 g/mol.

Now, we can calculate the molar mass of MgCrO4 by summing up the atomic masses of each element, considering the respective subscripts:

Molar mass = (Atomic mass of Mg) + (Atomic mass of Cr) + 4 × (Atomic mass of O)

Molar mass = (24.31 g/mol) + (51.99 g/mol) + 4 × (16.00 g/mol)

Molar mass = 24.31 g/mol + 51.99 g/mol + 64.00 g/mol

Molar mass ≈ 140.30 g/mol

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Answer:

640 g

Explanation:

Step 1: Given and required data

Step 2: Calculate the moles of oxygen gas

We will use the ideal gas equation

P × V = n × R × T

n = P × V / R × T

n = 25 atm × 20 L / (0.082 atm.L/mol.K) × 300 K = 20 mol

Step 3: Calculate the mass corresponding to 20 moles of oxygen

The molar mass of oxygen is 32.00 g/mol.

20 mol × 32.00 g/mol = 640 g

Answer:

-.30

Explanation:

H2SO4/sulfuric acid/dihydrogen sulfate is a strong acid, meaning that it easily releases an H+. You have to be careful with this problem, however, as H2SO4 is really only a strong acid for one of its hydrogens. In other words, after it becomes HSO4- upon releasing an H+, it is no longer a strong acid and therefore should not be factored into our calculation.

Now, moving onto the calculation, there are two key things we need to carry it out. First is the pH equation. pH = -log [H+]. And second is the concentration of H2SO4, which is equivalent to the concentration of that H+ released: 2.0 M.  Simply plug in your values.

pH = -log [2.0].

pH = -.30

Answer:

Sorry I don't know what you

According to law of conservation of mass as mass is neither created nor destroyed mass of compound should be reported as 1.86 g that is by subtracting mass of compound from mass of compound and container.

According to law of conservation of mass, it is evident that mass is neither created nor destroyed rather it is restored at the end of a chemical reaction .

Law of conservation of mass and energy are related as mass and energy are directly proportional which is indicated by the equation E=mc².Concept of conservation of mass is widely used in field of chemistry, fluid dynamics.

Law needs to be modified in accordance with laws of quantum mechanics under the principle of mass and energy equivalence.This law was proposed by Antoine Lavoisier in the year 1789.

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Answer:

oxidation- reduction

Explanation:

where gaining electronic reduces one element and losing them oxidize the other nitric acid is not only strong it is also a oxidizing agent

When copper is changed to copper(II) nitrate by the nitric acid, it is an example of an oxidation-reduction.

Molecule is defined as number of atoms combined together, that shows the most smaller chemical compound's fundamental unit that participate in chemical reaction. In the combination of atoms attractive forces play a vital role and it helps to bound the atoms by a chemical bond.

Liquid consist of small range of order and the reason behind this is intermolecular attractive force which is very strong and due to this reason molecules are packed together tightly. Due to presence of high kinetic energy the molecules present in the liquid move rapidly and fastly  with one another.

Water is considered to be the simpler molecule and it consist of hydrogen and oxygen atom bounded together and due to the reason of high electronegativity of the oxygen's atom the bonds present are polar as well as covalent.  Due to presence of high kinetic energy the molecules present in the liquid move rapidly and fastly  with one another.

Therefore, When copper is changed to copper(II) nitrate by the nitric acid, it is an example of an oxidation-reduction.

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Answer:

2C4H10 + 13O2 -＞ 8CO2 + 10H2O

Explanation:

c = 8 8

h = 20 20

o = 26 26

Answer:

your welcome :)

Explanation:

Answer:

2.87 gram

N2 is the limiting agent

Explanation:

We will find out if there is sufficient N2 and h2 to produce NH3

a) For 2.36 grams of N2

Molar mass of N2 = 28.02

Number of moles of N2 in 2.36 grams = 2.36/28.02

Mass of NH3 = 17.034 g

Now NH3 produced form 2.36 grams of N2 =  

2.36/28.02 * 2 * 17.034 = 2.87 g NH3

b) For 1.52 g of H2  

NH3 produced = 1.52/2.016 * (2/3) * 17.034 = 8.56

N2 Is not enough to produce 2.87 g of NH3 and also H2 is not enough to make 8.56 g of NH3.  

N2 is the limiting agent as it has smaller product mass

Answer:

Burning of fossil fuels

Cutting of tress

Also CO2 is produce in industries like cement manufacturing.

Explanation:

Answer:1

Explanation:

1

To transfer heat in radiation electromagnetic waves must be transmitted.

Heat transfer occurs through conduction, convection and radiation.

Conduction requires direct physical contact whereas in convection the particles must circulate and move in a liquid or gas. Both of the transfer heat only in the presence of air.

Radiation is a type of heat transfer that occurs everywhere through electromagnetic waves. In radiation, electromagnetic waves must be transmitted for the transfer of heat. It happens even in vacuum.

Every object radiates thermal energy. Even humans radiate heat at all times. It does not have to move from cold to hot objects.

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The limiting reactant is Na₂S and the theoretical yield of SnS₂ is 60.9%.

Moles of SnBr₄ = Molarity × volume (L)

                         = 0.605 mol/lit × 0.045 lit

                         = 0.02722 mole

Moles a Na₂S. = Molarity x volume (L).

                        = 0.181 mol/lit X 00538 (lit)

                        = 0.00973 mol

From the balanced chemical equation.

I mole of SnBr₄ = 2 mole of Na₂S

Multiply by 0.02722

0.02722 mole SnBr₄ = 2 x 0.02722 mol Na₂S.

Moles Na₂S required = 0.0544 mol

Moles of Na₂S Present = 0.00973 mol

Hence the limiting reactant is Na₂S.

2 Mole of Na₂S = 1 mole of SnS₂

1 Mole of Na₂S = 1/2 mole of SnS₂

multiply by 0.00973

0.00973 mol Na₂S = 0.009731 mol × 1/2 mol SnS₂

mole of SnS₂ = 0.004865 mol·

Gram of SnS₂ = No of moles x Molar mass

                       = 0.004865m × 182.89 g/mol

                       = 0.889 g

Percent. yield = Practical field / Theoretical yield × 100

= (0.541)/(0.889) × 100

= 60.85%

= 60.9%

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In an acetic acid solution:

1. To make a buffer with pH = 5.00, have a ratio of

\(\frac{[A-]}{[HA]} = 10^{-5.50}\) = 0.316.

The volume of sodium hydroxide needed:

V(NaOH) = (0.316 M - 0.200 M) / 4.50 M = 0.0316 L = 31.6 mL

Therefore, 31.6 mL of 4.50 M sodium hydroxide must be added to 250.0 mL of 0.200 M acetic acid solution to make a buffer with pH = 5.00.

2. The pH of the buffer is calculated as follows:

pH = pKa + log(\(\frac{[A-]}{[HA]}\))

= 4.76 + log(0.2/0.1)

= 4.86

Therefore, the pH of the buffer is 4.86.

3. The mass of salt that must be dissolved in 0.25 dm³ of 1 mol dm³ propanoic acid to give a buffer of pH 4.87:

\(\frac{[A-]}{[HA]} = 10^{-4.87}\) = 0.0114

Therefore, the mass of acetate that must be dissolved:

Mass of acetate = (0.0114 mol dm³)(0.25 dm³) = 0.00285 g

Therefore, 0.00285 g of sodium propanoate must be dissolved in 0.25 dm³ of 1 mol dm³ propanoic acid to give a buffer of pH 4.87.

4. The pH of the buffer is calculated as follows:

pH = pKa + log(\(\frac{[A-]}{[HA]}\))

= 4.74 + log(0.1/0.1)

= 4.74

Therefore, the pH of the buffer is 4.74.

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Answer: \(2HCl(aq)+Zn(s)\rightarrow ZnCl_2(aq)+H_2(g)\)

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products formed must be equal to the mass of reactants taken.

In order to get the same mass on both sides, the atoms of each element must be balanced on both sides of the chemical equation.

A single replacement reaction is one in which a more reactive element displaces a less reactive element from its salt solution.

The salts which are soluble in water are designated by symbol (aq) and those which are insoluble in water and remain in solid form are represented by (s) after their chemical formulas. Gases are represented by (g) after their chemical formulas.

Thus  2 hydrogen chloride molecules in aqueous solution react with solid zinc. The reaction produces zinc chloride in aqueous solution and hydrogen gas is represented as :

\(2HCl(aq)+Zn(s)\rightarrow ZnCl_2(aq)+H_2(g)\)

Because HCl is a stronger acid than acetic acid, the pH of 0.01M acetic acid has greater value than the pH of 0.01M HCl. 2.88 is the  pH of a 0.01 M acetic acid.

Any hydrogen that comprises a material capable of giving a proton (a hydrogen ion) to another chemical is defined as acid. A base is indeed a molecule or ion that can receive a hydronium ion from just an acid.

1)Because HCl is a stronger acid than acetic acid, the pH of 0.01M acetic acid has greater value than the pH of 0.01M HCl. The pH value of stronger acid is lower.

2)CH\(_3\)COOH + H\(_2\)O  ⇄ CH\(_3\)COO⁻+  H\(_3\)O⁺

 0.01             0               0

 -x              +x                +x

 0.01-x           +x        +x

Ka=[ CH\(_3\)COO⁻][H\(_3\)O⁺]/[CH\(_3\)COOH]

1.8×10⁻⁵ = [x][x ]/[  0.01-x ]

x=1.34×10⁻³

pH = -log[H⁺]

     =  -log[1.34×10⁻³]

     =2.88

Therefore, because HCl is a stronger acid than acetic acid, the pH of 0.01M acetic acid has greater value than the pH of 0.01M HCl. 2.88 is the   pH of a 0.01 M acetic acid.

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To prepare solution E, approximately 100 ml of solution A is needed. The initial volume reading on the burette is 100.0 ml, and the final volume reading is 0.01 ml.

To prepare solution E in the provided volumetric flask by dispensing solution A from the burette, we need to calculate the volume of solution A required and determine the initial and final volume readings on the burette.To find the volume of solution A needed, we can use the formula:

Volume (ml) = (Number of moles * Molar volume) / Molar concentration

Given that the number of moles of solution A is 0.011665 mol and the molar concentration is 0.1166 M, we can substitute these values into the formula:Volume (ml) = (0.011665 mol * 1000 ml/mol) / 0.1166 M ≈ 99.99 ml

Approximately 100 ml of solution A is required to prepare solution E.

The initial volume reading on the burette before dispensing will be the same as the final volume of solution A, which is 100.0 ml. After dispensing the required volume of solution A (approximately 100 ml) into the volumetric flask, the final volume reading on the burette will be 0.01 ml (assuming the burette has a resolution of 0.01 ml).

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Answer:

A logic bomb and a time bomb are both types of malicious software or code that are designed to cause harm to a computer system or network. Here's a brief explanation of each:

Logic Bomb:

A logic bomb is a piece of code or software that is intentionally inserted into a system to execute a malicious action when specific conditions are met. It remains dormant until triggered by a predefined event or circumstance, such as a specific date, time, or user action. Once triggered, the logic bomb may perform various harmful actions, such as deleting files, corrupting data, or disrupting system functionality. The purpose of a logic bomb is often to cause damage or to gain unauthorized access to a system.

Time Bomb:

A time bomb is similar to a logic bomb, but it is specifically designed to activate or execute its malicious payload at a certain date or time. It is usually programmed to remain undetected until the predetermined time arrives. The time bomb can be set to trigger after a specific time period or on a particular date, at which point it may carry out destructive actions. Time bombs can be used by attackers to target specific events or to coordinate an attack to occur simultaneously across multiple systems.

Both logic bombs and time bombs are considered forms of malicious code or malware and are used with malicious intent to disrupt, damage, or compromise computer systems or networks. They can be extremely harmful, and it is important to have strong security measures, such as antivirus software and regular system updates, to protect against such threats.

Explanation:

The correct order of the particles that give texture to the soil from smallest to largest is clay, silt, and sand; option C.

Soil texture refers to a physical classification of the component and types of soils based on their physical texture either as coarse or fine particles.

There are several types of soils and these various types of soils have different textures.

The types of soils and their arrangement based on increasing particle size are as follows:

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\(pH = - \log[\text{H}^{+}] = -\log \left(1.75 \times 10^{-11} \right) = 10.757\)

political geography

People study Political Geography when they look at geography and think about how people think about states, borders, and how they relate to them.

I hope this helps you

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Answer:

A

Explanation:

195.49 g K x 1 mole / 39.01 g x 6.022 x 10^23 atoms/mole = 30.11 x 10^23 = 3.011 x 10^24

The number of K atoms present in 195.49 grams of K is 3.0110 × 10²⁴ atoms. The correct option is a 3.0110 x 10²⁴.

From the question,

We are to determine the number of K atoms present in 195.49 grams of K.

First, we will determine the number of moles K present

Using the formula,

\(Number\ of\ moles = \frac{Mass}{Atomic\ mass}\)

Atomic mass of K = 39.0983 g/mol

Number of moles of K present = \(\frac{195.49}{39.0983}\)

Number of moles of K present = 4.99996 moles

Number of moles of K present ≅ 5 moles

Now, for the number of atoms present

From the formula

Number of atoms = Number of atoms × Avogadro's constant

Number of K atoms present = 5 × 6.022 × 10²³

Number of K atoms present = 5 × 6.022 × 10²³

Number of K atoms present = 30.11 × 10²³

Number of K atoms present = 3.0110 × 10²⁴ atoms

Hence, the number of K atoms present in 195.49 grams of K is 3.0110 × 10²⁴ atoms. The correct option is a 3.0110 x 10²⁴.

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Answer: The answer is 9.8 m/s^2 south

Explanation:

When dissolved in water, most Group 1 metal salts can be described as strong electrolytes.

When Group 1 metal salts are dissolved in water, they can be described as strong electrolytes. This is because Group 1 metals, such as lithium (Li), sodium (Na), potassium (K), and so on, readily lose their outermost valence electron to form positive ions (cations). These cations then dissociate completely in water, separating from the anions to which they were originally bonded.

The dissociation of Group 1 metal salts in water results in the formation of positively charged metal ions and negatively charged non-metal ions (anions). These ions are free to move and conduct electric current, making the solution a good conductor of electricity. The complete dissociation of Group 1 metal salts in water and the presence of freely moving ions make them strong electrolytes.

Strong electrolytes are substances that ionize completely or almost completely in solution, producing a high concentration of ions. This is in contrast to weak electrolytes, which only partially ionize and produce a lower concentration of ions.

In summary, when Group 1 metal salts are dissolved in water, they form strong electrolytes due to their ability to dissociate completely into ions, leading to a high concentration of freely moving ions in the solution, thus enabling efficient electrical conductivity.

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The Sun-Earth-Moon system is important because it sustains life on Earth, regulates Earth's climate, and influences natural phenomena like tides.

The Sun-Earth-Moon system plays a vital role in supporting and sustaining life on Earth. The Sun is the primary source of energy for our planet, providing heat and light necessary for photosynthesis, the process by which plants convert sunlight into food and oxygen. Sunlight is also crucial for maintaining Earth's temperature and driving weather patterns.

The Moon, as Earth's only natural satellite, contributes to several essential functions. Its gravitational pull creates the tides, which influence coastal ecosystems and shape coastal landscapes.

The Moon's orbit also stabilizes Earth's axial tilt, providing a stable climate for life to thrive. Additionally, the Moon's phases have cultural and historical significance, influencing human activities such as agriculture, navigation, and calendar systems.

The Sun-Earth-Moon system's interactions are responsible for natural phenomena like eclipses, both solar and lunar, which have fascinated humans throughout history and continue to be important for scientific study and exploration.

Understanding these celestial events enhances our knowledge of astrophysics and helps us comprehend the vastness and complexity of the universe.

Furthermore, the study of the Sun-Earth-Moon system provides insights into celestial mechanics, orbital dynamics, and the broader field of planetary science. By examining the interplay between these celestial bodies, scientists can gain a deeper understanding of Earth's place in the universe and explore potential habitable conditions on other celestial bodies.

Overall, the Sun-Earth-Moon system is of immense importance as it sustains life, regulates climate, influences natural phenomena, and provides a platform for scientific exploration and discovery.

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Explanation:

p=mv

=(4.237)(2.5x10^-2)^3

=6.6x10^-5 kgm-3