which object has greater acceleration when acted on by gravitational forces? a 2 kg apple, a 7 kg bowling ball, or a 20 kg roc

Answer:

about 50 meters to 60 meters I'm sorry if its not right.

Answer:

1350

Explanation:

30x45

The intensity of spherical waves is 6.61 W/m².

We need to know about the intensity of spherical waves to solve this problem. The intensity of a spherical wave is proportional to power and inversely proportional to the square of the distance. It can be written as

I = P / 4πr²

where I is the intensity, P is the power and r is the distance from the source.

From the question above, we know that:

r1 = 3.5 m

I1 = 140 W/m²

r2 = 9

As we know that intensity is inversely proportional to square of distance, then it can defined as

I ⁓ 1 / r²

By substituting the parameter, we get

I1 / I2 = r2² / r1²

140 / I2 = 9² / 3.5²

I2 = 140 / 21.17

I2 = 6.61 W/m²

Hence, the intensity of spherical waves is 6.61 W/m².

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Answer: A.

Explanation: If you move it from A to D look closely its a straight line.

Answer:

D

Explanation:

The table is NOT in motion, so it will remain still. Newton's second law states that for every action, there's an equal and opposite reaction. Therefore, the table must push back the opposite direction(up) with the same force(15N)

Answer:

We can use Coulomb's law to solve this problem:

F = k * q1 * q2 / r^2

where F is the force between the two charges, k is Coulomb's constant (k = 9 x 10^9 N m^2 / C^2), q1 and q2 are the magnitudes of the charges, and r is the distance between them.

We know the force F, the distance r, and the magnitude of one of the charges q1. We can rearrange the equation to solve for the magnitude of the other charge q2:

q2 = F * r^2 / (k * q1)

Substituting the values we have:

q2 = (250 N) * (0.15 m)^2 / (9 x 10^9 N m^2 / C^2 * 6.5 x 10^-5 C)

Simplifying:

q2 = 8.65 x 10^5 C

Therefore, the magnitude of the other charge is 8.65 x 10^5 C.

Given:

The mass of the automobile is

To find:

The weight of the car in N and its mass in kg

Explanation:

We know,

So, the mass of the automobile is

Answer:

Sarah's classmate is incorrect. The photo shows the slight effect of gravity on the hillside but it is not a process

associated with mass wasting.

Explanation:

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The force responsible for the acceleration of the crate is the frictional force between the crate and the bed of the truck.

When the truck accelerates, the crate tends to remain at rest due to inertia. However, the frictional force between the crate and the bed of the truck acts in the forward direction, allowing the crate to accelerate along with the truck.

This frictional force is a result of the interaction between the surfaces of the crate and the truck bed. Without this frictional force, the crate would slide or move independently from the truck's acceleration.

The frictional force arises due to the microscopically rough surfaces of the crate and the truck bed. As the two surfaces are pressed against each other, intermolecular forces come into play, resulting in the generation of the frictional force

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The focal length f of the mirror that would accomplish this is 10 meters.

To create an image that is 10 meters from an object and half the height of the object using one spherical mirror, we can use the mirror formula:

1/f = 1/do + 1/di

Where f is the focal length of the mirror, do is the distance from the object to the mirror, and di is the distance from the mirror to the image.

Since we want the image to be upright, the image distance must be positive. Also, since the image is half the height of the object, the magnification is -1/2. Therefore, we can use the magnification formula:

m = -di/do = -1/2

Solving for di, we get:

di = -do/2

Substituting this into the mirror formula, we get:

1/f = 1/do - 2/do

Simplifying, we get:

1/f = -1/do

Solving for f, we get:

f = -do

Since the image is 10 meters from the object, the object distance is do = -10 meters. Therefore, the focal length of the mirror that would accomplish this is:

f = -(-10 meters) = 10 meters

So the focal length of the mirror should be 10 meters.

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The distance traveled while accelerating can be found by multiplying the average velocity by the time taken to accelerate

Complete question:

A boat accelerates from 8.5 m/s west to 1.8 m/s west at a rate of 2.9 m/s^2 east. How far does it travel while accelerating?

The average velocity is the difference between the initial and final velocities, divided by two. The time taken to accelerate is the difference between the initial and final velocities, divided by the rate of acceleration.

Given Data

we know that the expression for computing distance is given as

Distance traveled while accelerating = Average velocity * Time taken to accelerate

Substituting our data in the expression we have

Distance traveled while accelerating = 3.35 m/s * 2.03 s = 6.80 m

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Answer:

55

Explanation:95-40=55

i hope i did the math right if i didnt please tell me

Answer:

10^24 kg

Explanation:

The kinematic relations allow finding the results for the different questions are:

     1.  The acceleraations is a = 375 m/s²

     2. The time is t = 62.5 s

     3. The velocity at the ground is  v = -14.7 m / s

     4.  The time to the bottoncliff is    1.7 s

     5.  The height isy₀ = 122.5 m

     6.

         A) The velocity is v = 25.2 m / s

         B)  The height  for t=1 s is  y = 18.1 m

     7.

         A)  Time in the air is t = 2 s

         B)  The final veloicty is   v = - 19.6 m / s

Kinematics analyzes the movement of bodies, finding relationships between the position, velocity and acceleration of bodies.

Let's look for the answers to a series of questions:

1. They indicate the initial and final velocities of the body and the time to reach it is 20 s, ask how much the acceleration is worth

Let's use the relationship

             v = v₀ + a t

             a = \(\frac{v-v_o}{t}\)

             a = \(\frac{17500-10000}{20}\)

             a = 375 m/s²

2. What is the time it takes to travel a distance of 125 m with an acceleration of 4 m / s²

             x = v₀ t + ½ a t²

As it leaves the direction its initial velocity is zero

             x = ½ to t²

             t = \(\sqrt{\frac{2x}{a} }\)

             t = \(\sqrt{\frac{2 \ 125}{4} }\)

             t = 62.5 s

3. A pencil falls from a height and reaches the floor in a time of 1.5 s what is the speed when reaching the floor

            v = v₀ - g t

As it is released its initial velocity is zero

            v = -g t

            v = - 9.8 1.5

            v = -14.7 m / s

The negative sign indicates that the velocity is directed downwards.

4. From the edge of a cliff 40 m high, an apple is thrown downward with an initial velocity of 15 m / s. How long does it take to get to the bottom?

             y = y₀ + v₀ t - ½ g t²

In this case the initial velocity is negative because it is directed downwards and when it reaches the floor its height is zero, let us substitute

Suppose the acceleration is g = 10 m / s²

             0 = 40 - 15 t - ½ 10 t²

             0 = 40 - 15 t - 5 t²

let's solve the quadratic equation

             t² + 3 t - 8 = 0

             t = -3 + Ts 9 + 4 8/2

            t = -3 + 6. 4/2

             t₁ = - 4.9 s

            t₂ = 1.7 s

The time must be a positive quantity, so the correct answer is 1.7 s

5. A stone is dropped from the ceiling and it takes a time 5 s to reach the floor, which is the height of the ceiling

           y = y₀ +v₀ t - ½ g t²

as it is released from the ceiling its initial velocity is zero and the height upon reaching the floor is zero

          0 = y₀ + 0 - ½ g t²

          y₀ = ½ g t²

          y₀ = ½ 9.8 5²

          y₀ = 122.5 m

6. A man at a height of 30 m throws a ball downward at 7 m / s

    A) The speed when reaching the ground

    B) The height of the ball when a time of 1 s has fallen.

  A) Let's use the kinematics relation

              v² = v₀² - 2 g (y -y₀)

              v = 7² - 2 9.8 (0 -30)

              v = 25.2 m / s

 B)   y = y₀ + v₀ t - ½ g t²

        y = 30  7 1 - ½ 9.8 1²

        y = 18.1 m

7.  A watermelon is dropped from rest from the top of a 20m cliff.  

 A) time in the air

 B) ground speed

  A) Let's use the relation

       y = y₀ + v₀ t - ½ g t²

It is released its initial velocity is zero and when it reaches the ground its height is zero (y = 0)

       0 = y₀ + 0 - ½ g t²

       t = \(\sqrt{\frac{2y_o}{g} }\)

       t = \(\sqrt{\frac{2 \ 20}{9.8} }\)

       t = 2 s

B) the speed when reaching the ground

       v = v₀ - g t

       v = 0 - 9.8 2

       v = - 19.6 m / s

The negative sign indicates that the speed is down

In conclusion using the kinematic relations we can find the results for the different questions are:

   1.  The acceleraations is a = 375 m/s²

   2. The time is t = 62.5 s

   3. The velocity at the ground is  v = -14.7 m / s

   4.  The time to the bottoncliff is    1.7 s

   5.  The height isy₀ = 122.5 m

   6.

      A) The velocity is v = 25.2 m / s

      B)  The height  for t=1 s is  y = 18.1 m

  7)

      A)  Time in the air is t = 2 s

      B)  Te final veloicty is   v = - 19.6 m / s

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The given equation,F = (9/5)C + 32gives the Fahrenheit temperature corresponding to the Celsius. To find the Fahrenheit temperature equivalent to 25 Celsius, we will substitute the given value of Celsius into the above equation.

So, F = (9/5)(25) + 32F = 45 + 32F = 77Hence, the Fahrenheit temperature equivalent to 25 Celsius is 77 degrees Fahrenheit.

To find the Fahrenheit temperature equivalent to a given Celsius temperature, we use the equation

F = (9/5)C + 32, whereF is the Fahrenheit temperature andC is the Celsius temperature.

The equation is derived from the relationship between the Celsius and Fahrenheit temperature scales.In this equation, 9/5 is a conversion factor used to convert the Celsius temperature to Fahrenheit.

The constant 32 is added to the product of the conversion factor and the Celsius temperature to get the Fahrenheit temperature.The question asks us to find the Fahrenheit temperature equivalent to 25 Celsius. To do this, we substitute the given value of Celsius into the equation.

So, we haveF = (9/5)(25) + 32Simplifying the right-hand side, we getF = 45 + 32Evaluating the expression,

we getF = 77Therefore, the Fahrenheit temperature equivalent to 25 Celsius is 77 degrees Fahrenheit.

Thus, we can conclude that the Fahrenheit temperature equivalent to 25 Celsius is 77 degrees Fahrenheit, which we found using the equation F = (9/5)C + 32.

This equation is used to convert Celsius temperatures to Fahrenheit temperatures. The conversion factor 9/5 is multiplied by the Celsius temperature, and 32 is added to the result to get the Fahrenheit temperature.

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Answer:

Inside the guts of a microwave, a device called a magnetron channels electrical energy from a power outlet to a heated filament, creating a flow of electrons that in turn transmits microwaves into the cooking chamber through an antenna

Answer:

Microwaves use radiation as the method of heat transfer.

Explanation:

Radiation refers to heat transfer via electromagnetic waves, such as microwaves. Conduction is heat transfer via direct contact between two objects.

The evidence for dark matter comes from observations of the gravitational effects it has on visible matter and cosmic microwave background radiation.

The existence of dark matter was first proposed to explain the observed gravitational effects on visible matter, such as stars in galaxies and clusters of galaxies, that could not be accounted for by the visible matter alone. These observations suggested the presence of a large amount of matter that is not visible, hence the term "dark" matter. Additional evidence for dark matter comes from observations of the cosmic microwave background radiation, which is the remnant radiation from the Big Bang. The patterns of the cosmic microwave background radiation suggest that dark matter played a critical role in the formation of the large-scale structure of the universe. While the nature of dark matter is still unknown, its presence is inferred from its gravitational effects on visible matter and radiation.

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The magnification is M = -q/p = 1.56, indicating that the image is larger than the object and upright.

Diverging lenses always produce virtual images, regardless of the position of the object. The magnification equation is M = -q/p, where p is the object distance, q is the image distance, and the negative sign indicates that the image is upright (positive M) and virtual. In the simulation, placing the object at 50 cm with a height of 25 cm and a diverging lens with a focal length of -50 cm produces an image that is virtual, upright, and farther away than the object. Using the thin lens equation with p = +80 cm and f = -50 cm, the image distance q can be calculated as -125 cm, indicating that the image is virtual, upright, and farther away than the object. The magnification is M = -q/p = 1.56, indicating that the image is larger than the object and upright.
5. The magnification equation is M = -q/p. For diverging lenses, p is positive, and q is negative, resulting in a positive M value. This means the object is always upright for diverging lenses.

6. In the simulation with a diverging lens (f = -50 cm), object distance (p = 50 cm), and object height (h = 25 cm), you will observe a virtual, upright image, agreeing with the magnification computations.

7. Using the thin lens equation, 1/f = 1/p + 1/q, plug in values for f (-50 cm) and p (80 cm). Solving for q, you get q = -28.57 cm. This indicates a virtual image with a negative distance.

8. To find magnification, M, use M = -q/p. With p = 80 cm and q = -28.57 cm, M = 0.357 (positive). The object is upright, as M is positive.

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Answer:T=1316.21 N

Explanation:

The tension has two components: Vertical and Horizontal. The

horizontal component is ma, the vertical component is mg. Using

Pythagoras theorem, we can find the tension as:

T=((ma)^2 (mg)^2)^(1/2)

So

T=((129*2.84)^2 (129*9.8)^2)^(1/2)

T=1316.21 N

Complete Question:

The length, breadth and height of an object are 20 cm, 15 cm and 25 cm respectively. Its mass is 7 kg. Find its volume and density

Answer:

a. Volume of cuboid = 7500 cm³

b. Density = 0.000933 Kg/cm³

Explanation:

Given the following data;

a. To find the volume of the object.

An object that has a length, breadth and height is a cuboid.

Mathematically, the volume of a cuboid is given by the formula;

Volume of cuboid = length * breadth * height

Substituting into the formula, we have;

Volume of cuboid = 20 * 15 * 25

Volume of cuboid = 7500 cm³

b. To find the density of the object;

Density can be defined as mass all over the volume of an object.

Simply stated, density is mass per unit volume of an object.

Mathematically, density is given by the formula;

\( Density = \frac {mass}{volume} \)

Substituting into the formula, we have;

\( Density = \frac {7}{7500} \)

Density = 0.000933 Kg/cm³

Answer:

please find attached pdf

Explanation:

The angular height of the sun above the horizon. This is the explanation of the term "sun's altitude". A long answer could go on to explain how the sun's altitude changes throughout the day and throughout the year due to the tilt of the Earth's axis and the Earth's rotation around the sun.

The altitude of the sun affects the amount and intensity of sunlight received at different latitudes and seasons, which has important implications for climate and weather patterns.

b) the angular height of the sun above the horizon.

To explain further, the sun's altitude is measured in degrees and represents the angle between the sun and the observer's local horizon. It ranges from 0 degrees when the sun is at the horizon to 90 degrees when the sun is directly overhead. This value is important for determining the intensity of sunlight received at a specific location and time.

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The vrms for helium atoms at 5.00 K, just one degree above helium's liquefaction temperature, is approximately 1228 m/s.

The root-mean-square velocity (vrms) of helium atoms at a temperature of 5.00 K, just one degree above helium's liquefaction temperature, can be calculated using the formula:

vrms = √(3kT/m)

where:

k is the Boltzmann constant (1.38 × 10^-23 J/K)

T is the temperature in Kelvin

m is the mass of one helium atom (4.0026 atomic mass units or 6.646 × 10^-27 kg)

Plugging in the values:

vrms = √(3 * 1.38 × 10^-23 J/K * 5.00 K / 6.646 × 10^-27 kg)

vrms ≈ 1228 m/s

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Answer:

the sun is plasma

Explanation:

it is a hot ball of gas made out of oxygen

Answer:

Plasma

Explanation:

All stars are made of gas, however the sun is so hot that most of that gas is plasma

The net force acting on the ball while it is traveling upward is in the opposite direction of the ball's motion (downward) and equal in magnitude to the gravitational force pulling the ball downward.

When a 2 kg ball is thrown vertically upward and air resistance is ignored, the net force acting on the ball while it is traveling upward is in the opposite direction of the ball's motion and equal in magnitude to the gravitational force pulling the ball downward.

The net force acting on an object is the vector sum of all the forces acting upon it. In this case, two main forces are acting on the ball: the force due to gravity and the force exerted by the thrower.

When the ball is traveling upward, the force due to gravity pulls it downward. According to Newton's third law, for every action, there is an equal and opposite reaction. Therefore, the force exerted by the thrower on the ball is in the upward direction, opposing the gravitational force.

While the ball is traveling upward, the net force acting on it is the difference between these two forces. Since the force exerted by the thrower is less than the force due to gravity, the net force is directed downward. Its magnitude is equal to the difference between the two forces, which is the gravitational force acting on the ball.

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When light travels in a certain medium and falls on the surface of another medium a part of it turns back in the same medium This phenomenon is called Reflection.

A wavefront may alter its course at an interface between two different media and return to the first medium, a phenomenon known as reflection. Common examples are the reflection of light, sound, and water waves.

Reflection of light refers to the occurrence where light strikes an item and bounces back off its surface. Examples: using a flat mirror to reflect. by a spherical mirror's reflection. There are essentially two types of reflection that apply to light. While diffuse reflection is caused by rough surfaces that tend to reflect light in all directions, specular reflection is described as light reflected off a smooth surface at a specific angle.

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Electrostatic forces are non-contact forces; they pull or push on objects without touching them.

A photocopier or a photocopy machine is one of the best examples of electrostatic force in real life. The original paper is placed on a glass screen. The image of this original paper is transferred to a drum that is positively charged. The ink powder or the toner used is usually charged with a negative polarity. Static electricity can be seen when a balloon is rubbed against one's hair, for example. Another common example is the shock one receives after walking across a carpet and then touching a door knob. Lightning is also the result of static electric discharge.

The magnitude of the force of attraction between Star and Tony, given that they are 20 m apart is 5.84×10¯¹⁰ N

From the question given above, the following data were obtained:

Applying the Newton's law of universal gravity formula, we can obtain the magnitude of the force of attraction between Star and Tony as illustrated below:

F = GM₁M₂ / r²

F = (6.67×10¯¹¹ × 70 × 50) / 20²

F = 0.00000023345 / 400

F = 5.84×10¯¹⁰ N

Thus, from the above calculation, we can conclude that the magnitude of the force between them is 5.84×10¯¹⁰ N

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hope that helps and please tell me if i am wrong :)

The total change in the internal energy of a system is the sum of the energy transferred as heat and/or work.

The internal energy of a system is the sum of the kinetic and potential energies of the particles that make up the system. Heat is a form of energy that is transferred from a body at a higher temperature to a body at a lower temperature. The transfer of heat is always accompanied by a change in the internal energy of the system. If heat is absorbed by the system, the internal energy of the system increases, and if heat is lost by the system, the internal energy of the system decreases.

Work, on the other hand, is the product of force and distance, and it is a form of energy that is transferred when a force is applied to an object to move it a certain distance. If work is done on a system, the internal energy of the system increases, and if work is done by the system, the internal energy of the system decreases.

The first law of thermodynamics, also known as the law of conservation of energy, states that the total energy of an isolated system is constant. This means that the change in the internal energy of a system is equal to the heat added to the system minus the work done by the system.

Thus, the sum of the energy transferred as heat and/or work is the total change in the internal energy of a system.

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