Which number will you read 'two-tenths'?
Answers
Answer: two-tenths as a fraction is 2/10, and as a decimal it's 0.2.
Step-by-step explanation: The "0" is the ones place and the "2" is the tenths place. There is a chart below.
Related Questions
he table shows the heights of students in a group.
Student Height (in inches)
A 45
B 48
C 49
D 40
E 53
What is the mean height of the students in the group?
47 inches
49 inches
51 inches
53 inches
Answers
Answer:
47 inches
Step-by-step explanation:
45 + 48 + 49 + 40 + 53 = 235
235/5 = 47
I will mark brainlist please help
Answers
Answer: It is 6
Step-by-step explanation:
Please help, I will give brain list.
Answers
Answer:
12.25
Step-by-step explanation:
3.5*3.5=12.25
Answer:
12.25m^2
Step-by-step explanation:
3 1/2 × 3 1/2
3 1/2 is equivalent to 7/2
7/2 × 7/2= 49/4
this simplifies to 12.25
answer: 12.25 m^2
Which property is being used?
If HJ+5=20, then HJ=15.
Answers
Step-by-step explanation:
HJ+5=20
HJ=20-5
HJ=15
If 26 feet 10 inches is cut from a wire that is 44 feet 8 inches long what is the length of wire that is left ?
Answers
Answer:
17 feet 10 inches
Step-by-step explanation:
Please see the attached image for the work!
whats the mean absolute deviation of 2 2 2 2 2 2 2 2
Answers
Answer:
mad is 0
Step-by-step explanation:
what type of question is this? no offense
Answer:
0
Step-by-step explanation:
9. The following histogram is for the weights (lbs) of 63 male
college students.
a) What is the best description for the approximate shape
of this distribution?
A. Symmetric.
C. Skewed to the right. D. Bimodal
B. Skewed to the left.
b) In the histogram, how many males' weights show to be less than 150 lbs?
c) What proportion (percentage) of the weights of males is more than 230 lbs?
Answers
The distribution is bimodal (a), eight men weigh less than 150 lbs (b), and the percentage of males that weigh more than 230 lbs is 3.17%.
What can be observed in this histogram?A: Distribution: The distribution can be classified as bimodal, which means there are two peaks in the graph.
B. The number of males that weigh less than 150 lbs can be determined as follows:
110 - 120 lbs = 2 males
130 -140 lbs = 2 males
140 - 150 lbs = 4 males
2 + 2 + 4 = 8 males
C. The percentage of males that weigh more than 230 lbs can be calculated as follows:
63 = 100%
2 = x
x= 2 x 100 / 63
x = 200 / 63 = 3.17%
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Is x = 6 a solution to the equation x + 13 = 18?
Answers
Answer:
No, the answer is 5
Answer: No the solution is 5
Step-by-step explanation:
When you substitute x with 6 you get 6+13= 18.
Obviously 6+13 is not 18 so this means that 6 is not a solution.
Hope this helps ;)
The Venn diagram here shows the cardinality of each set. Use this to find the cardinality of the given set.
Answers
With the help of the given Venn diagram, the answer of n(A∪B) is 44 respectively.
What is the Venn diagram?A Venn diagram is a visual representation that makes use of circles to highlight the connections between different objects or limited groups of objects.
Circles that overlap share certain characteristics, whereas circles that do not overlap do not.
Venn diagrams are useful for showing how two concepts are related and different visually.
When two or more objects have overlapping attributes, a Venn diagram offers a simple way to illustrate the relationships between them.
Venn diagrams are frequently used in reports and presentations because they make it simpler to visualize data.
So, we need to find:
A ∪ B
Now, calculate as follows:
The collection of all objects found in either the Blue or Green circles, or both, is known as A B. Its components number is:
8 + 7 + 14 + 6 + 1 + 8 = 44
n(A∪B) = 44
Therefore, with the help of the given Venn diagram, the answer of n(A∪B) is 44 respectively.
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What is the measure of one exterior angle of a 15-sided regular polygon?
O 12 degrees
O 168 degrees
O24 degrees
O 156 degrees
Answers
Answer:
24°
Step-by-step explanation:
For an n-sided regular polygon, the sum of internal angles = (n-2)×180°
Since all internal angles are equal, the internal angle can is given as:
Here, it is given that the polygon has 15 sides.
So n = 15
So each internal angle is 156°.
Internal and external angles are always supplementary. So the sum of the internal and external angles is 180°.
So external angle = 180° - 156° = 24°.
The measure of each external angle is 24°.
6. Journalise the following transactions
1. Bricks for Rs 60,000 and timber for Rs 35,000 purchased for
the construction of building. The payment was made by cheque.
2. Placed in fixed deposit account at bank by transfer from current
account Rs 13,000.
3. Appointed Mr. S.N. Rao as Accountant at Rs 300 p.m. and
Received Rs 1000 as security Deposit at 5% p.a. interest.
4. Sold goods to shruti for Rs 80,000 at 15% trade discount and
4% cash discount. Received 75% amount immediately through a
cheque.
5. Purchased goods from Richa for Rs 60,000 at 10% trade
discount and 5% cash discount. 60% amount paid by cheque
immediately.
6.
On 18th jan,Sold goods to shilpa at the list price of Rs 50,000
20% trade discount and 4% cash discount if the payment is made
within 7 days. 75% payment is received by cheque on Jan 23rd.
7. On 25th jan, sold goods to garima for Rs 1,00,000 allowed her
20% trade discount and 5% cash discount if the payment is made
within 15 days. She paid 1/4th of the amount by cheque on Feb 5th
and 60% of the remainder on 15th in cash.
8. Purchased land for Rs 2,00,000 and paid 1% as brokerage and
Rs 15,000 as registration charges on it. Entire payment is made by
cheque.
9. Goods worth Rs 25,000 and cash Rs 40,000 were taken away
by the proprietor for his personal use.
10. Sold goods costing Rs 1,20,000 to charu at a profit of 33% 3 %
on cost less 15% trade discount.
9
11. Paid rent of building Rs 60,000 by cheque. Half the building is
used by the proprietor for residential purpose.
12. Sold goods costing Rs 20,000 to sunil at a profit of 20% on
sales less 20% trade discount .
13. Purchased goods for Rs 1000 from nanda and supplied it to
helen for Rs 1300. Helen returned goods worth Rs 390, which in
turn were returned to nanda.
14. Received invoice at 10% trade discount from rohit and sons
and supplied these goods to madan, listed at Rs 3000.
Answers
1.Bricks and timber purchased for construction. (Debit: Bricks - Rs 60,000, Debit: Timber - Rs 35,000, Credit: Bank - Rs 95,000)
2.Transfer of Rs 13,000 to fixed deposit account. (Debit: Fixed Deposit - Rs 13,000, Credit: Current Account - Rs 13,000)
3.Appointment of Mr. S.N. Rao as Accountant. (Debit: Salary Expense - Rs 300, Debit: Security Deposit - Rs 1,000, Credit: Accountant - Rs 300)
4.Goods sold to Shruti with discounts. (Debit: Accounts Receivable - Shruti - Rs 80,000, Credit: Sales - Rs 80,000)
5.Goods purchased from Richa with discounts. (Debit: Purchases - Rs 60,000, Credit: Accounts Payable - Richa - Rs 60,000)
6.Goods sold to Shilpa with discounts and received payment. (Debit: Accounts Receivable - Shilpa - Rs 50,000, Credit: Sales - Rs 50,000)
7.Goods sold to Garima with discounts and received partial payment. (Debit: Accounts Receivable - Garima - Rs 1,00,000, Credit: Sales - Rs 1,00,000)
8.Purchase of land with additional charges. (Debit: Land - Rs 2,00,000, Debit: Brokerage Expense - Rs 2,000, Debit: Registration Charges - Rs 15,000, Credit: Bank - Rs 2,17,000)
9.Proprietor took goods and cash for personal use. (Debit: Proprietor's Drawings - Rs 65,000, Credit: Goods - Rs 25,000, Credit: Cash - Rs 40,000)
10.Goods sold to Charu with profit and discount. (Debit: Accounts Receivable - Charu - Rs 1,20,000, Credit: Sales - Rs 1,20,000)
11.Rent paid for the building. (Debit: Rent Expense - Rs 60,000, Credit: Bank - Rs 60,000)
12.Goods sold to Sunil with profit and discount. (Debit: Accounts Receivable - Sunil - Rs 24,000, Credit: Sales - Rs 24,000)
13.Purchased goods from Nanda and supplied to Helen. (Debit: Purchases - Rs 1,000, Debit: Accounts Payable - Nanda - Rs 1,000, Credit: Accounts Receivable - Helen - Rs 1,300, Credit: Sales - Rs 1,300)
14.Purchased goods from Rohit and Sons and supplied to Madan. (Debit: Purchases - Rs 2,700, Credit: Accounts Payable - Rohit and Sons - Rs 2,700, Debit: Accounts Receivable - Madan - Rs 3,000, Credit: Sales - Rs 3,000)
Here are the journal entries for the given transactions:
1. Bricks and timber purchased for construction:
Debit: Bricks (Asset) - Rs 60,000
Debit: Timber (Asset) - Rs 35,000
Credit: Bank (Liability) - Rs 95,000
2. Transfer to fixed deposit account:
Debit: Fixed Deposit (Asset) - Rs 13,000
Credit: Current Account (Asset) - Rs 13,000
3. Appointment of Mr. S.N. Rao as Accountant:
Debit: Salary Expense (Expense) - Rs 300
Debit: Security Deposit (Asset) - Rs 1,000
Credit: Accountant (Liability) - Rs 300
4. Goods sold to Shruti:
Debit: Accounts Receivable - Shruti (Asset) - Rs 80,000
Credit: Sales (Income) - Rs 80,000
5. Goods purchased from Richa:
Debit: Purchases (Expense) - Rs 60,000
Credit: Accounts Payable - Richa (Liability) - Rs 60,000
6. Goods sold to Shilpa:
Debit: Accounts Receivable - Shilpa (Asset) - Rs 50,000
Credit: Sales (Income) - Rs 50,000
7. Goods sold to Garima:
Debit: Accounts Receivable - Garima (Asset) - Rs 1,00,000
Credit: Sales (Income) - Rs 1,00,000
8.Purchase of land:
Debit: Land (Asset) - Rs 2,00,000
Debit: Brokerage Expense (Expense) - Rs 2,000
Debit: Registration Charges (Expense) - Rs 15,000
Credit: Bank (Liability) - Rs 2,17,000
9. Goods and cash taken away by proprietor:
Debit: Proprietor's Drawings (Equity) - Rs 65,000
Credit: Goods (Asset) - Rs 25,000
Credit: Cash (Asset) - Rs 40,000
10. Goods sold to Charu:
Debit: Accounts Receivable - Charu (Asset) - Rs 1,20,000
Credit: Sales (Income) - Rs 1,20,000
Credit: Cost of Goods Sold (Expense) - Rs 80,000
Credit: Profit on Sales (Income) - Rs 40,000
11. Rent paid for the building:
Debit: Rent Expense (Expense) - Rs 60,000
Credit: Bank (Liability) - Rs 60,000
12. Goods sold to Sunil:
Debit: Accounts Receivable - Sunil (Asset) - Rs 24,000
Credit: Sales (Income) - Rs 24,000
Credit: Cost of Goods Sold (Expense) - Rs 20,000
Credit: Profit on Sales (Income) - Rs 4,000
13. Goods purchased from Nanda and supplied to Helen:
Debit: Purchases (Expense) - Rs 1,000
Debit: Accounts Payable - Nanda (Liability) - Rs 1,000
Credit: Accounts Receivable - Helen (Asset) - Rs 1,300
Credit: Sales (Income) - Rs 1,300
14. Goods received from Rohit and Sons and supplied to Madan:
Debit: Purchases (Expense) - Rs 2,700 (after 10% trade discount)
Credit: Accounts Payable - Rohit and Sons (Liability) - Rs 2,700
Debit: Accounts Receivable - Madan (Asset) - Rs 3,000
Credit: Sales (Income) - Rs 3,000
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I WILL GIVE BRAINLIEST Justin is trying to find a new cell phone plan and was deciding between Verizon and AT&T. The following graph shows the rates of the phones over a period of time:
If Justin is only looking for a plan for 2 years, which is a better plan?
If Justin is looking for a plan for 7 years, which is a better plan?
What happens at point A?
Answers
What is the solution to the inequality?
15<4+x
Answers
Answer:
Step-by-step explanation:
Hello!
15 < x + 4
We can subtract 4 from both sides, to cancel it out.
15 - 4 is 11.
11 < x
x = {12,13,14,15,16,..........................................................................Infinity}
Hope I Helped!
A bus holds 39 passengers. How many buses will 420 people need
Answers
Answer:
11 buses
Step-by-step explanation:
The revenue for a business, as a function of units produced, x, is shown below by R(x). C(x) represents the cost of producing x units. Calculate the profit function and then determine how many units must be produced for the business to break even.
R(x) = 12x
C(x) = x + 264
Answers
The profit function for the revenue R(x) = 12x and the cost, C(x) = x + 264 is 11x-264 and units must be produced for the business to break even is 24 units.
What is revenue profit?Profit refers to net income after deducting expenses from earnings, whereas revenue refers to income generated through business operations. Sales, fee-based income, and property-based income are just a few of the different ways that money can come in.
Here,
R(x)=12x
C(x)=x+264
It represents the difference between total revenues and total outlays.
Revenue minus costs equals profit.
Profit = Revenue - Cost
P(x)=R(x)-C(x)
P(x)=12x-x-264
P(x)=11x-264
For the company to break even,
R(x) = C(x)
12x=x+264
11x=264
x=24
The break-even point for the business is 24 units, and the profit function for the revenue R(x) = 12x and the cost C(x) = x + 264 is 11x-264.
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Solve the system of equations by using elimination.
-8a+7b=-69
-3a-3b=-9
ANSWERS;
A)5,-6
B)-6,5
C)6-3
D)-36
Answers
Answer: a=6, b=-3 (choice c) Let me know if you need step by step.
Step-by-step explanation:
10. Two stores are having deals on video games.
Store A: 5 video games for $8.95
0:23
Store B: 7 video games for $10.50. Find the price per video game for store A. Round to the nearest cent. SHOW YOUR WORK.
Answers
The calculated price per video game for store A is $1.79 per game
How to find the price per video game for store A.From the question, we have the following parameters that can be used in our computation:
Store A: 5 video games for $8.95Store B: 7 video games for $10.50The price per video game for store A is calculated as
Price per video game = Total price/Number of games
using the above as a guide, we have the following:
Price per video game = 8.95/5
Evaluate the quotient
So, we have
Price per video game = 1.79
Hence, the price per video game for store A is $1.79 per game
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Answer ASAP for brainlest
Answers
Answer:
none
Step-by-step explanation:
p=lw
24, not squared
if your are calculating the perimeter of area, then it would be squared
if you subtract 1/2 from a number and multiply the result by 1/2 you get 1/8. What is the no.
Answers
Step-by-step explanation:
1/6
1/6- 1/2 = 1/4
1/4*1/2= 1/8
Step by step
1/(N-1/2)•1/2=1/8
2/N-1/2=1/8 divided 1/2 But the 1/2 in the other side by dividing
3/ N-1/2=1/4
4/N=1/4+1/2
5/N=3/4
If you check
3/4-1/2=1/4
1/4•1/2=1/8
don’t send links; PLEASE HELP FAST I WILL DO ANYTHING, I’LL GIVE U 2K ON BLOXBURG
Answers
Answer:
i think its 90
Step-by-step explanation:
you would multiply the right box which is 2 x 3 ( i got 3 because its half of 6 which is at the top) then you would multiply the left box which is 3 x 5
2 x 3 = 6
3 x 5 = 15
15 x 6 = 90
i dont need the 2k on bloxburg
if its right could i get brainliest?
Sean A = < - 7, 5 ] U [10, 18 >, B = [ - 2, 8 > U < 13, 23 ]
C = < 1, 15>.
Hallar: (A ∩ B ) - C
Answers
The result of the expression (A ∩ B) - C is [-2, 5] U [13, 18] is [-2,5,13,18].
To find the result of the expression (A ∩ B) - C, where A, B, and C are sets, we need to perform the following steps:
Find the intersection of sets A and B, denoted as (A ∩ B).Subtract set C from the intersection (A ∩ B).Given the sets:
A = < - 7, 5 ] U [10, 18 >
B = [ - 2, 8 > U < 13, 23 >
C = < 1, 15 >
1.Find the intersection of sets A and B (A ∩ B):
To find the intersection, we need to find the overlapping region between the intervals.The intersection of the intervals [-7, 5] and [-2, 8] is [max(-7, -2), min(5, 8)] = [-2, 5].The intersection of the intervals [10, 18] and [13, 23] is [max(10, 13), min(18, 23)] = [13, 18].Therefore, the intersection of sets A and B is [-2, 5] U [13,18].2. Subtract set C from the intersection (A ∩ B):
Subtracting set C = <1, 15> from the intersection [-2, 5] U [13, 18] means removing any elements that are present in set C from the intersection.
Since set C = <1, 15> does not overlap with either [-2, 5] or [13, 18], the subtraction (A ∩ B) - C results in the same set as the intersection:
(A ∩ B) - C = [-2, 5] U [13, 18].
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10.8 Cesar Santiago recorded his housing expenses for the month of September as follows: $575.16 for mortgage payment, $23.70 for insurance premium, $87.40 for realestate taxes, $76.36 for electricity, $21.18 for telephone service, and $19.30 for water. What is his total monthly housing cost?O a. 5563.00Ob. $783.10Od. $912.07Oc. $803.10
Answers
The total montly housing cost is 575.16 + 23.70 + 87.40 + 76.36 + 21.18 + 19.30 = $803.10
A sample of 342 students at a university is surveyed. The students are classified according to gender ("female" or "male"). They are also classified according tomajor ("blology", "business", "engineering", "mathematics", or "computer science"). The results are given in the contingency table below.Biology Business Engineering Mathematics Computer scienceFemale4623501837Male4815461544What is the relative frequency of male students in the sample?Round your answer to two decimal places.0Х5.?
Answers
The relative frequency of an event is the quotient of the division between the event and the total number of the sample
From the given table
Add the numbers of males to find their total
\(48+15+46+15+44=168\)Then add the numbers of females and males to find the total of the sample
\(168+46+23+50+18+37=342\)Now, divide the number of males by the total to find the relative frequency
\(\begin{gathered} R\mathrm{}F=\frac{168}{342} \\ R\mathrm{}F=0.4912280702 \end{gathered}\)Round it to 2 decimal places, then
The relative frequency of the male students = 0.49
If a ball is kicked with a speed of 2.5 m/s, how long does it take the ball to move 40 meters? (no units required for your answer)
Answers
Answer:
16
Step-by-step explanation:
40 divided by 2.5 equals 16
100 Points! Algebra question. Photo attached. Please show as much work as possible. Thank you!
Answers
The values of the trigonometry functions are sin(θ) = 3/√13, cos(θ) = 2/√13, tan(θ) = 3/2, csc(θ) = √13/3, sec(θ) = √13/2 and cot(θ) = 2/3
Finding the values of the trigonometry functionsfrom the question, we have the following parameters that can be used in our computation:
The right triangle
The hypotenuse of the right triangle is calculated as
h² = 2² + 3²
When evaluated, we have
h = √13
The values of the trigonometry functions are then evaluated as
sin(θ) = 3/√13
cos(θ) = 2/√13
tan(θ) = 3/2
csc(θ) = √13/3
sec(θ) = √13/2
cot(θ) = 2/3
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Find the range of possible measures for the third side 25,38
Answers
The range of possible measures for the third side is 13 ≤ c ≤ 63
Finding the range of possible measures for the third sideFrom the question, we have the following parameters that can be used in our computation:
The length of two sides = 25 and 38
Using the triangle inequality theorem, we have
a + b ≥ c
Using the above as a guide, we have the following:
25 + 38 ≥ c
c + 38 ≥ 25
c + 25 ≥ 38
Evaluate the like terms
63 ≥ c
c ≥ -13
c ≥ 13
Rewrite as
63 ≥ c
c ≥ 13
When combined, we have
13 ≤ c ≤ 63
Hence, the range of possible measures for the third side is 13 ≤ c ≤ 63
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help pledssssssssssssssssssssssss
Answers
15+15+1+1
=32
Your answer is 32!
The sum of two consecutive integers is -11. Find the number
Answers
Answer:
-5 and -6
Step-by-step explanation:
Lets do the equation: x+x+1=-11
Add: 2x+1=-11
Subtract: 2x=-12
Divide: x=-6
The smaller integer is -6
The larger integer is -5
Write the slope intercept form of the equation of the described line:4) through: (4, 3), perp. to y = 2x + 4
Answers
To find the slope-intercept equation of a line, remember the general equation of a line in the slope-intercept form:
\(y=mx+b\)Where m is the slope of the line and b is the y-intercept.
Notice that the equation y=2x+4 is written in the slope-intercept form. Therefore, its slope is 2.
For two lines to be perpendicular, their slopes should have a product of -1.
Since we are looking for a line perpendicular to y=2x+4, the slope of the desired line should be -1/2.
\(m=-\frac{1}{2}\)Use the point-slope formula to find the line with slope -1/2 that goes through the point (4,3):
\(y=m(x-x_0)+y_0\)Substitute m=-1/2, x_0=4 and y_0=3:
\(y=-\frac{1}{2}(x-4)+3\)To find the slope-intercept form of this equation, use the distributive property to rewrite -1/2 (x-4) as -1/2 x -(1/2)(-4):
\(y=-\frac{1}{2}x-\frac{1}{2}\cdot(-4)+3\)Simplify the product (-1/2)(-4):
\(\begin{gathered} y=-\frac{1}{2}x+2+3 \\ \Rightarrow \\ y=-\frac{1}{2}x+5 \end{gathered}\)Therefore, the slope intercept form of the equation of a line perpendicular to y=2x+4 and which goes through the point (4,3), is:
\(y=-\frac{1}{2}x+5\)Suppose you need 6.0m of Grade 70 bow chain, which has a diameter of 3/8" and weighs 2.16 kg/m to tow a car How would you calculate theme of this much chain
Answers
The mass of the tow chain will be equal to 12.96 kg.
What is an expression?The mathematical expression is the combination of numerical variables and operations denoted by addition, subtraction, multiplication, and division signs.
Mathematical symbols can be used to represent numbers (constants), variables, operations, functions, brackets, punctuation, and grouping. They can also be used to denote the logical syntax's operation order and other properties.
Given that 6.0m of Grade 70 bow chain, which has a diameter of 3/8" and weighs 2.16 kg/m.
The mass of 1 m chain = 2.16 kg
Mass of 6-meter chain = 2.16 x 6
Mass of 6-meter chain = 12.96 kg
Therefore, the mass of the tow chain will be equal to 12.96 kg.
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