Which list contains only animal phyla? mosses, annelids, conifers, chordates mosses, ferns, conifers, flowering plants cnidarians, mollusks, annelids, arthropods, echinoderms, chordates cnidarians, ferns, annelids, arthropods, echinoderms, flowering plants

Answers

Answer 1

Answer:

cnidarians, mollusks, annelids, arthropods,

Explanation:

Living organisms have been grouped using a system of classification that runs from Kingdom to Species. One of those kingdoms is KINGDOM ANIMALIA, which consists of animal species i.e. organisms that are strictly heterotrophic and eukaryotic.

The next taxa after kingdom is PHYLA. According to this question, the phyla which consists of only animals are cnidarians, mollusks, annelids, arthropods. Other options contain ferns, mosses, and flowering plants which belong to Kingdom Plantae.

Answer 2

Answer:

on edge its C

Explanation:


Related Questions

In the laboratory, a student dilutes 29.0 ml of a 7.71 m hydroiodic acid solution to a total volume of 200.0 ml. what is the concentration of the diluted solution?

Answers

The concentration of the diluted solution is 1.11M , using formula M1V1=M2V2 (whereM = molarity , V = volume).

The formula M1V1=M2V2 is the most widely used.

You must ensure that M stands for Molarity and V for Volume in Liters in this formula. You must divide 29.0 mL by 1,000 in order to convert this problem's mL to L units (mL =.0290 L).

M1 is the specified molarity (7.71M), and V1 is the specified molarity's volume (.0290 L).

The final molarity M2 is what we are looking for, and the final volume V2 equals 1000 L. (remember to convert the 200.0 mL to L)

Fill in the formula with your numbers.

(X) × (0.2000 L) = (7.71M) × (0.0290 L)

(7.71M) × (0.0290 L) / (0.2000 L) = (X)

1.11M = X

Given that we maintained the same number of moles in the solution, this makes sense.

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An atom X that has 12 protons and 12 electrons, loses 2 electrons to form an ions, What will be the ion? What will be the number of protons and electrons in the ions?

Answers

An atom X that has 12 protons and 12 electrons, loses 2 electrons to form an ions,  the charge of ion will be X⁺² the number of protons 12 and electrons in the ions is 10.

An atom X has 12 protons and 12 electrons that means X is a neutral atom and the atomic no. is 12 because total no. of protons is equal to atomic number. When it looses the 2 electrons then atom becomes positively charged ion . the charge on the ion is +2.

now, the no. of protons will be = 12

number of electrons will be = 12 - 2 = 10

Thus, An atom X that has 12 protons and 12 electrons, loses 2 electrons to form an ions,  the charge of ion will be X⁺² the number of protons 12 and electrons in the ions is 10.

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A list of changes is shown. Temperature decreases Intermolecular bonds become weaker Melting Intermolecular bonds become stronger Temperature remains constant Temperature increases Vibration of molecules slows down Molecules vibrate faster Which of the above changes would be accompanied by an increase of the kinetic energy of particles in a solid? (4 points)

Answers

Answer:

Intermolecular bonds become weaker

Melting

Temperature increases

Molecules vibrate faster

Explanation:

In the solid phase, intermolecular forces are found to be strongest. However, as the temperature is increased, the molecules of the solid begin to vibrate faster and intermolecular forces between them begin to weaken.

As intermolecular forces of a substance become weaker, the substance melts. The molecules in the liquid state possesses greater kinetic energy than the molecules in the solid state.

Hence the the answer above.

Answer:

B, C, F, and H

Explanation:

These are all things that happen in the increase of the kinetic energy of particles in a solid.

B. Intermolecular bonds become weaker

C. Melting

F. Temperature increases

H. Molecules vibrate faster

Also, just took the test and got it right.

use multisim and I
need calculous
The problem to be solved is the
design of a traffic light to control an intersection of two
avenues. In addition, said traffic light must serve the vehicular
crossin

Answers

Adhere to traffic regulations and guidelines throughout the process.

To design a traffic light system for an intersection using Multisim software and calculus, follow these steps. First, define the intersection and determine traffic flow. Next, establish the traffic light phases based on the traffic patterns. Use calculus to calculate the durations of each phase, considering factors like traffic volume and pedestrian crossing times. Create an optimization problem, setting an objective function to minimize delays and congestion.

Solve the optimization problem using calculus techniques and numerical methods. Implement the optimized timings in Multisim to simulate the traffic light system. Evaluate the simulation results, refine the timings if needed, and consider factors such as pedestrian safety and emergency vehicle prioritization. Adhere to traffic regulations and guidelines throughout the process.

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The hydrogen gas foed in a chemical reaction is collected over water at 30 ∘C-at a total pressure of 742 mmHg. The vapor pressure of water at 30 C is 31.8 mmHg Part A What is the partial pressure of the hydrogen gas collected in this way? Express your answer in millimeters of mercury to three significant figures.

Answers

The partial pressure of the hydrogen gas collected in this way is 710 mmHg. When collecting a gas over water, the total pressure of the system includes the vapor pressure of water at that temperature

When collecting a gas over water, the total pressure of the system is the sum of the partial pressure of the gas and the vapor pressure of water at that temperature. In this case, the total pressure is given as 742 mmHg, and the vapor pressure of water at 30°C is 31.8 mmHg.

To find the partial pressure of the hydrogen gas, we need to subtract the vapor pressure of water from the total pressure. Therefore, the partial pressure of the hydrogen gas can be calculated as:

Partial pressure of hydrogen gas = Total pressure - Vapor pressure of water

Partial pressure of hydrogen gas = 742 mmHg - 31.8 mmHg

Partial pressure of hydrogen gas = 710 mmHg

In this chemical reaction, the collected hydrogen gas exerts a partial pressure of 710 mmHg.

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Please balance these chemical equations

Answers

The chemical equations given would be balanced below

How should a chemical equation be balanced?

The balanced equation of the various given chemical equations can be determined only when the number of atoms on the product part is the same with the number of atoms on the reactant side.

For 1.)

\(N_{2} + 3H_{2} ----- > 2NH_{3}\)

For 2.)

\(2KCl_{3} ----- > 2KCl + 3O_{2}\)

For 3.)

\(2NaCl + F_{2} ----- > 2NaF + Cl_{2}\)

For 4.)

\(2H_{2} + O_{2} ----- > 2H_{2} O\)

For 5.)

\(Pb(OH)_{2} + 2HCl ----- > 2H_{2} O +PbCl_{2}\)

For 6.)

\(2AlBr_{3} + 3K_{2}SO{4} ---- > 6KBr + Al_{2}(SO_{4})_{3}\)

For 7.)

\(CH_{4} + O_{2} ----- > CO_{2} + 2H_{2} O\)

For 8.)

\(C_{3} H_{8} + 3O_{2} ----- > 3CO_{2} + 4H_{2} O\)

For 9.)

\(C_{8} H_{18} + 8O_{2} ----- > 8CO_{2} + 9H_{2} O\)

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) Consider the general reaction 5Br−(aq)+BrO3​−(aq)+6H+(aq)→3Br2​(aq)+3H2​O(aq) For this reaction, the rate when expressed as Δ[Br2​]/Δt is the same as A) −5Δ[Br−]/Δt B) −0.6Δ[Br−]/Δt C) 3Δ[BrO3−​]/Δt D) −Δ[H2​O]/Δt E) None of these choices are correct.

Answers

The correct choice is A) −5Δ[Br−]/Δt. The rate expressed as Δ[Br2]/Δt is proportional to -5 times the rate of change of Br−.

In the given reaction 5Br−(aq) + BrO3−(aq) + 6H+(aq) → 3Br2(aq) + 3H2O(aq), the stoichiometric coefficients provide information about the relationship between the reactants and products. To determine the rate expressed as Δ[Br2]/Δt, we need to compare it with the rate of change of the other species.

Based on the balanced equation, for every 5 moles of Br− consumed, 3 moles of Br2 are produced. Therefore, the rate of change of Br−, Δ[Br−]/Δt, is related to the rate of change of Br2, Δ[Br2]/Δt, by a factor of -5/3.

The other choices, B) −0.6Δ[Br−]/Δt, C) 3Δ[BrO3−]/Δt, and D) −Δ[H2O]/Δt, do not correspond to the correct relationship based on the stoichiometric coefficients of the reaction. Therefore, the correct answer is A) −5Δ[Br−]/Δt.

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Which statement correctly describes metallic bonds?
O A. They form when certain atoms lose electrons and other atoms gain electrons.
O B.
They involve an attraction between anions and cations.
O C. They always involve both a metal and a nonmetal.
O D.
They can only form between atoms of the same element.
O E.
They form because electrons can move freely between atoms.

Answers

Answer:

e

Explanation:

Why does the atomic radius increase from top to bottom?

Answers

go to Russia and ask them. they know a lot about nukes

the metal germanium melts at a temperature of 937 °c and boils at 2830 °c, whereas the metal bismuth melts at a temperature of 271 °c and boils at 1560 °c.
(a) Which metal will be more volatile at room temperature? (b) Predict which of the two molten metals has the larger surface tension at its melting point. High in the mountains, an explorer notes that the water for tea is boiling vigorously at a temperature of 88 °C. Use the data in the table below to estimate the atmospheric pressure at the altitude of the camp Estimate AHn for water between S8 and 90 °C Atmospheric pressure = atm kJ/mol AHvap= Vapor Pressure of Water at Various Temperatures. T °C P atm 77 78 0.413 0.431 0.449 79 0.467 80 81 0.486 0.506 82 83 0.527 0.548 0.571 84 85 0.593 86 87 0.617 0.641 88 0.666 89 0.692 0.719 0.746 90 91 92 0.774 0.804 93 94

Answers

Bismuth will be more volatile at room temperature because it has a lower boiling point than germanium. Germanium is predicted to have the larger surface tension at its melting point. The atmospheric pressure at the altitude of the camp is approximately 0.641 atm.

Volatility refers to a substance's ability to vaporize or evaporate. Bismuth has a lower boiling point (1560 °C) compared to germanium (2830 °C), which means that it requires less energy to convert bismuth into a gas. As a result, bismuth will be more volatile at room temperature than germanium. Surface tension refers to the attractive force between the molecules at the surface of a liquid. At the melting point, the intermolecular forces between the molecules are weakened, which results in a decrease in surface tension. However, germanium has a higher boiling point (2830 °C) compared to bismuth (1560 °C), which means that germanium has stronger intermolecular forces between its molecules. As a result, germanium is predicted to have a higher surface tension at its melting point compared to bismuth.

Atmospheric pressure estimation for:
1. Identify the given boiling point of water at the camp: 88 °C.
2. Use the provided table to find the corresponding vapor pressure at 88 °C: P(atm) = 0.666 atm.
3. The vapor pressure at boiling point is equal to the atmospheric pressure. Thus, the atmospheric pressure at the altitude of the camp is approximately 0.641 atm.

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Bismuth will be more volatile at room temperature because it has a lower boiling point.

Germanium would have a larger surface tension at its melting point because it has a higher melting point.

Based on the given data, the atmospheric pressure at the altitude of the camp is 0.666 atm.

What are bismuth and germanium?

Bismuth is a heavy metal element with the atomic number 83. It is the most naturally diamagnetic element and has a silvery-white appearance.

Germanium is a metalloid element with the atomic number 32. It has a grayish-white appearance and is chemically similar to tin and silicon.

The atmospheric pressure is determined as follows:

The boiling point of water at the altitude of the camp is 88 °C.

The table of temperatures and vapor pressure of water is given below:

T °C P atm

77 0.413

78 0.499

79 0.467

80 0,486

81 0.506

82 0.527

83 0.548

84 0.571

85 0.593

86 0.617

87 0.641

88 0.666

89 0.692

90 0.719

91 0.746

92 0.774

93 0.804

From the given table, the corresponding vapor pressure at 88 °C, P(atm) is 0.666 atm.

Thus, the atmospheric pressure at the altitude of the camp can be estimated to be approximately 0.666 atm as given in the table.

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(h) Bohr stated that the energy of the electron is quantised. What does this mean?

Answers

Explanation:

It suggests that the extranuclear part consists of electrons in specific spherical orbits around the nucleus.

The concept is based on the premise that the electrons move round the nucleus in certain permissible orbits or energy levels. The ground state is the lowest energy state available to the electrons. It is the most stable state. The excited state is any higher energy level than the ground state. An electron in an energy level has a definite amount of energy associated with it at that level. The electron can undergo transitions from one level to another. This way energy of an electron is quantized to each level.

Explain why a solution of calcium conducts electricity but solid calcium chloride does not

Answers

Answer:

because the ions arent firmly held in place!

Explanation:

Question 1 (1 point)
ROOTS--What is NOT a root function in plants?

Answers

Answer:

deez nuets

Explanation:

bf gm Jr rj if dl if did fll j fll kd golf du is no u to

the radioactive element carbon-14 has a half-life of about 5,750 years. the percentage of carbon14 present in the remains of animal bones can be used to determine age. how old is an animal bone that has lost 40% of its carbon-14?

Answers

The animal bone is approximately 19,028 years old based on the 40% loss of carbon-14.

To determine the age of an animal bone based on the percentage of carbon-14 remaining, we can use the concept of half-life. The half-life of carbon-14 is approximately 5,750 years, which means that after this time, half of the carbon-14 originally present will have decayed.

If the bone has lost 40% of its carbon-14, it means that only 60% of the original carbon-14 remains. We can calculate the number of half-lives that have passed to reach this percentage.

Let's assume the original amount of carbon-14 in the bone was 100 units. After one half-life, 50 units of carbon-14 would remain (50% of the original amount). After two half-lives, 25 units would remain (50% of 50 units). Similarly, after three half-lives, 12.5 units would remain (50% of 25 units).

To find out how many half-lives it took to reach 60%, we can set up the following equation:

12.5 units (remaining amount) = 100 units (original amount) * (1/2) ^ n (number of half-lives)

Solving for n:

12.5 = 100 * (1/2) ^ n

Dividing both sides by 100:

0.125 = (1/2) ^ n

Taking the logarithm of both sides:

log(0.125) = log[(1/2) ^ n]

n * log(1/2) = log(0.125)

n = log(0.125) / log(1/2)

Using a calculator, we can find:

n ≈ 3.3219

Therefore, approximately 3.3219 half-lives have passed.

Since each half-life is approximately 5,750 years, we can calculate the age of the bone:

Age = Number of half-lives * Half-life duration

Age = 3.3219 * 5,750 years

Age ≈ 19,028 years

Thus, the animal bone is approximately 19,028 years old based on the 40% loss of carbon-14.

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What is the area of the stratosphere with a high concentration of ozone?

A.) exosphere

B.) ionosphere

C.) O ozone layer

Answers

Answer:

C.) Ozone layer

Most ozone (about 90%) is found in the stratosphere, which begins about 10–16 kilometers (6–10 miles) above Earth's surface and extends up to about 50 kilo- meters (31 miles) altitude. The stratospheric region with the highest ozone concentration is commonly known as the “ozone layer” (see Figure Q1-2).

Your answer should be O’ zone layer.

A piece of word has a mass of 3.16 g; when placed in 20.0 mL of water, the water volume increased to 23.4 mL. What is the density of this piece of wood?

Answers

Answer:

0.93g/mL

Explanation:

Given parameters

Mass of wood  = 3.16g

Initial volume of water  = 20mL

Volume of water + wood  = 23.4mL

Unknown:

Density of the wood  = ?

Solution:

Density is the mass per volume of a substance.

 It is mathematically expressed as;

       Density  = \(\frac{mass}{volume}\)

Volume of wood = 23.4mL  - 20mL = 3.4mL

So,

    Density = \(\frac{3.16}{3.4}\)   = 0.93g/mL

Identifying map types

Answers

Answer:

Political Map. A political map shows the state and national boundaries of a place. ...

Explanation:

In a solution with a pH of 3 a. Litmus Is blue and phenolphthalein is colorless b. Litmus is blue phenolphthalein is red c. Litmus Is red phenolphthalein is colorless d. Litmus is red phenolphthalein is red.

Answers

Answer

c. Litmus Is red phenolphthalein is colorless

Explanation

A solution with a pH of 3 is acidic. The main use of litmus is to test whether a solution is acidic or basic, blue litmus turns red under acidic conditions, and red litmus turns blue under basic or alkaline conditions. Phenolphthalein is often used as an indicator in acid–base titrations. phenolphthalein, it turns colorless in acidic solutions and pink in basic solutions.

Therefore, the correct option for a solution with a pH of 3 is:

c. Litmus Is red phenolphthalein is colorless

A ___________
is a process that occurs when
one or more substances are changed into one or more new
substances. For example, when zinc and sulfur are mixed
together with the addition of energy in the form of heat, zinc
sulfide (ZnS) is produced.

Answers

Answer:

Reaction??

Explanation:

explain why is energy input required to add an electron to zinc

Answers

Answer: When you add an electron to zinc, it needs some extra energy. This is because zinc atoms naturally don't like having an extra electron. The extra electron and the electrons already present in zinc repel each other due to their negative charges. So, you have to give some energy to the zinc atom to overcome this repulsion and make it accept the additional electron. Basically, energy input is required to make zinc accept an extra electron because the electron doesn't fit easily and needs some force to be added.

Explanation: hope this helps

explain why an oxygen ion has a larger radius than an oxgen atom

Answers

Answer:

Explanation:

The two electrons in the outer orbit, together with the other negatively charged electrons, repel each other and that make the diameter of the O^2- ion larger.

I need help :/
:) :) :)

I need help :/ :) :) :)

Answers

Answer: I want to say 1

Explanation:

I think

A top fuel dragster is designed to go from 0 to 100 miles per hour in a mere 0.8
seconds. Calculate its acceleration. Show your work and include units.

Answers

Answer:

Acceleration, \(a=55.88\ m/s^2\)

Explanation:

It is given that, A top fuel dragster is designed to go from 0 to 100 miles per hour in a mere 0.8.

Initial velocity, u = 0

Final velocity, v = 100 mph

1 mph = 0.44704 m/s

100 mph = 44.704 m/s

Time, t = 0.8 s

We need to find its acceleration. Rate of change of velocity equals acceleration.

\(a=\dfrac{v-u}{t}\\\\a=\dfrac{44.704-0}{0.8}\\\\a=55.88\ m/s^2\)

So, the acceleration is \(55.88\ m/s^2\)

9. What is the process of nuclear fusion? *
(10 Points)
O A. The process of carrying light
B. The process of two atoms fusing
O C. The process of gravity and inertia keeping the universe together
O D. The process of fusing two stars

Answers

Answer:

the process of carrying light

Why can’t neon store energy in this way?

Answers

Answer:

Neon is a noble gas, it is monoatomic in nature, which implies that it has only one atom present. If we compare neon with water, water has three atoms present, two hydrogen atoms and one oxygen atom. Hence water stores more energy than neon because it is polyatomic and contains chemical bonds.

What are the formulas to go back and forth from concentration to pH?

Answers

Answer:

To calculate the pH of an aqueous solution you need to know the concentration of the hydronium ion in moles per liter (molarity). The pH is then calculated using the expression: pH = - log [H3O+].

Explanation:

when a person is standing on a scale, the magnitude of what force is displayed by the scale?

Answers

When a person is standing on a scale, the magnitude of normal force of the scale acting on the person is displayed by the scale. So, the correct choice is option(d).

When a person is standing on scale, the only forces acting on the person are his weight →W and the upward force of the scale →Fₛ. On the basic of Newton's third law, which states that every action has an equal and opposite reaction. So, normal force, Fₚ and Fₛ are equal in magnitude and opposite in direction, so that we need to determine Fₛ in order to determine what the scale reads. The force exerted normally on the scale creates a same equal and opposite reaction force exerted by the scale on the person. So it is the magnitude of force which is shown in the scale.

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Complete question:

When a person is standing on a scale, the magnitude of what force is displayed by the scale?

a)The mass of the person multiplied by their acceleration.

b)The force of the scale acting on the person minus the acceleration of the person multiplied by the person's mass.

C)The person's weight.

d)the normal force of the scale acting on the person.

how would the ir spectrum of the amine formed after procedure step 3 differ from the spectrum of the final amide product? suggest a brief procedure for isolating this amine as a solid produc g

Answers

Because both components are easily deactivated by the transfer of a proton from the acid to the amine, and because the hydroxy unit on the carbonyl of the acid is a relatively poor leaving group, amines are typically not accessible by the direct condensation of amines with carboxylic acids.

However, it is frequently surprisingly easy to create five- and six-membered rings provided that additional elements may be utilized to aid in condensation.

By merely sublimating the amino acid at 80 °C, Kirby's team, for instance, showed how to create the "most twisted amide," based on the adamantane structure.

Surprisingly, despite the amide being at room temperature and pH 4, the reaction also takes place there.

Thus, Because both components are easily deactivated by the transfer of a proton from the acid to the amine, and because the hydroxy unit on the carbonyl of the acid is a relatively poor leaving group, amines are typically not accessible by the direct condensation of amines with carboxylic acids.

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Is the Earth's surface covered with the same materials?

What was different about each scientific drilling site?

What is the same for all of the drilling sites we examined?

Answers

The Earth's surface is not covered with the same materials ; however, some areas share similar materials.Several drilling sites have been dug in various regions of the planet to analyze the Earth's surface.

Each drilling site is unique, with differing characteristics and results. Despite these differences, all of the drilling sites analyzed offer scientists a more in-depth knowledge of the Earth's surface.In essence, the scientific drilling sites each had different lithologies, stratigraphies, and geologies. Each site had different types of rocks, depths, and ages, which led to varying drilling conditions, depths, and equipment used. Different types of equipment were also used to reach the depths required, which was a significant difference in each drilling site.The scientific drilling sites also had different purposes. Scientists had specific goals they wanted to achieve at each location. For example, the scientific drilling site in the Iceland region was focused on analyzing a unique layer of igneous rocks. The primary objective was to investigate the formation of the rock layer.The same materials were not found at each scientific drilling site.

Still, they had some similarities. They all provided geologists with vital information about the Earth's surface. The data provided from each drilling site was used to piece together the Earth's geologic history and how it has changed over time.

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How many moles of iron(Il) oxide are produced from
3.0 moles of oxygen and excess Iron Sulfide as described by the chemical equation below?
4FeS + 502 - 2Fe,03 + 4502

Answers

Answer:

6 moles of Iron(II) Oxide

Answer:

1.2 mol

Explanation:

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One-half StartFraction 7 Over 8 EndFraction StartFraction 19 Over 24 EndFraction StartFraction 6 Over 8 EndFraction What role did the government play in Progressive goals? g: what are the array elements corresponding to the mid-values in the first and second iterations of a binary search in an array arr 1 point9. A 70 kg diver drops from a board 10 m above the water's surface.Neglect air resistance. What is the diver's Kinetic Energy just before he hitsthe water? Show work. NO work shown, NO credit. *10.0 mKE;= 0PE;= mgyi5.00 mmKE, = mvPE, = 00Your answer !ONLY ANSWER IF YOU KNOW THE ANSWER OTHERWISE UR WASTING POINTS!Read the diary entries.Nicholass Diary: April 2 and 3Friday, April 2Well, its only 10 more hours until my father and I leave for our treasure hunt. Every Saturday morning for as long as I can remember I have seen him leave, always by himself, to look for treasure. I have always longed to go with him, and hes always told me that someday I would get the chance. I was so excited when he told me I would finally have my chance that I was bouncing off the walls like a rubber ball and springing from one place to the next the rest of the day.He has always been as quiet as a mouse about the treasure that he finds, scurrying away with his equipment in the morning and piling up his treasure in his study. Even though he says he always comes home with something, he has never shown it to me or even told me what type of treasure it is. Is it gold, or silver, or maybe its precious jewels? Whatever it is, tomorrow I will find out, and hopefully hell let me bring some to class so that I can show my friends since Ive been bragging about it to them ever since Dad told me I could go!Saturday, April 3The treasure hunt was fun, but it was not what I expected. Dad and I left early in the morning and headed for the same woods that we sometimes go hiking in on Sundays. I never would have thought they hold treasure, but what was really odd was when Dad told me to leave the shovels at home because we wouldnt need them. But what he did bring with him was a bright yellow GPS . I had seen it in his truck many times before. I always wondered what he did with it. Today I found out.Dad and I wandered into the woods, first staying on the hiking path I had taken several times before and then veering off the path. The forest was like a statue; it was still and covered in damp moss and dead leaves; it didn't even seem alive. It appeared that no one had been there for a long time so I knew that this treasure must be old and far under the ground. How were we going to get to it without shovels?As Dad kept his eyes on the GPS , I looked around, and suddenly I noticed a patch of leaves that was disturbed and a log that looked like it had been moved. When I asked Dad about it, his eyes lit up, and he said he saw the treasure. He reached under the log and pulled out a plastic box with a label that read Official Geocache.I didnt know what an official geocache was, but I soon found out when Dad opened it. Inside was a little notebook and a bunch of small items like a set of dice, a toy car, and a large silver dollar. Dad said that he thought the toy car was cool, so he took it out and put it in his pocket and then pulled a golf ball from his other pocket and put it in the box. He wrote his name and my name in the little notebook and then closed the box and put it back where he found it.Geocaching, which is what Dad later told me this type of treasure hunting is called, was much different than digging for gold in the ground. But I thought it was fun, and I hope Dad takes me again next Saturday.Part AIn "Nicholas's Diary: April 2 and 3," what is Nicholass first thought when he and his father leave home to go treasure hunting?It is not going to be the type of treasure hunt that he thought it would be.He will not be finding gold or silver, but something far more important.He will not have a very good story to tell his friends at practice on Monday.The treasure will be carefully hidden and closely guarded.Question 2Part BWhich sentence from the text best supports the answer in Part A?what was really odd was when Dad told me to leave the shovels at home because he said we wouldnt need them.As Dad kept his eyes on the GPS , I looked around, and suddenly I noticed a patch of leaves that was disturbed and a log that looked like it had been moved.Dad and I left early in the morning and headed for the same woods that we sometimes go hiking in on Sundays."The forest was like a statue; it was still and covered in damp moss and dead leaves; it didn't even seem alive."