Which is true about the temperature of a gas? (2 points)
оа
At a higher temperature, the particles have a higher average kinetic energy.

At a higher temperature, the volume of the gas is smaller.
Ос
At a lower temperature, there are more particles in the gas.
Od
At a lower temperature, the particles in the gas move faster.

Answers

Answer 1
Answer d move faster

Related Questions

If an object can make 10 revolutions in two minutes what’s it’s period

Answers

Answer:

12\(s^{-1}\)

Explanation:

Period= how long for each revolution

Since we have 10 revolutions in 120 seconds.

120/10=12s

The Moon's center is 3.9x10 m from Earth's center. The Moon is 1.5x10^8 km from the Sun's center. If the mass of the Moon is 7.3x10^22 kg, find the ratio of the gravitational forces exerted by Earth and the Sun on the Moon

Answers

Explanation:

It is given that The Moon's center is 3.9x10⁸ m from Earth's center. The moon 1.5x10⁸ km from the Sun's center. We need to find the ratio of the gravitational forces exerted by Earth and the Sun on the Moon.

The gravitational force is given by :

\(F=\dfrac{Gm_em_m}{r^2}\)

It means \(F\propto \dfrac{1}{r^2}\)

So,

\(\dfrac{F_1}{F_2}=\dfrac{r_2}{r_1}\)

r₁ = 3.9x10⁸ km

r₂= 1.5x10⁸ km

So,

\(\dfrac{F_1}{F_2}=\dfrac{1.5\times 10^8}{3.9\times 10^8}\\\\\dfrac{F_1}{F_2}=\dfrac{5}{13}\)

Hence, the ratio of the gravitational forces exerted by Earth and the Sun on the Moon is 5:13.

if you sit on the edge of a very light table, it is likely the table will topple over. explain?​

Answers

Answer:

This question heavily relies on the weight of the table and the weight of the person sitting on it, if a 90 pound person sits on the side of a 40 pound table, it will topple over.

Explanation: Tables are generally have a 50/50 weight distribution ratio so that they are even on the ground and can stay upright, but if a table is too light and the person or object sitting on it is heavier than the side they/it is placed on, it will fall.

How much POWER is used in 30 seconds when you complete 150 Joules of work?

Answers

Answer:

Power of 5 watts is used

Explanation:

Mechanical Work and Power

Mechanical work is the amount of energy transferred by a force.

Being F the force vector and s the displacement vector, the work is calculated as:

\(W=\vec F\cdot \vec s\)

If both the force and displacement are parallel, then we can use the equivalent scalar formula:

W=F.s

Power is the amount of energy converted per unit of time. The SI unit of power is the watt, equal to one joule per second.

The power can be calculated as:

\(\displaystyle P=\frac {W}{t}\)

Where W is the work and t is the time.

It's required to calculate the power used in t=30 seconds when W=150 Joules of work are completed. Substitute in the formula:

\(\displaystyle P=\frac {150}{30}\)

P = 5 Watt

Power of 5 watts is used

Where does a body have more weight the poor at the eqator of the earth.​

Answers

At the North Pole or South Pole but ur body itself doesn’t not change it is the force of gravity that changes as u approach the pole

Answer:

Explanation:

Your body weighs more at the pole for two important reasons. Both have to do to the spin of the earth on its axis.

Because of its spin the earth is thicker around the equator than it is through the poles. This means that when you stand on the equator, you are farther away from the center of earth than you would be at the poles. As gravity decreases with the inverse of the square of distance, gravity will be weaker at the equator.

As you are also spinning with the earth, you will have a required centripetal acceleration and force to keep you attached to the ground, This force decreases the effect of gravity so again, you would weigh less at the equator.

8. In explosives, potential energy is generally
stored in the form of
a thermal energy
b. electromagnetic energy
c. nuclear energy
d. chemical energy

Answers

Answer:

In explosives,potential energy is in the stored form of chemical energy.

A standard mercury thermometer consists of a hollow glass cylinder, the stem, attached to a bulb filled with mercury. As the temperature of the thermometer changes, the mercury expands (or contracts) and the height of the mercury column in the stem changes. Marks are made on the stem to denote the height of the mercury column at different temperatures such as the freezing point (0∘C ) and the boiling point (100∘C ) of water. Other temperature markings are interpolated between these two points. Due to concerns about the toxic properties of mercury,many thermometers are made with other liquids. Consider drainingthe mercury from the above thermometer and replacing it withanother, such as alcohol. Alcohol has a coefficient of volumeexpansion 5.6 times greater than that of mercury. The amount ofalcohol is adjusted such that when placed in ice water, thethermometer accurately records 0 C. No other changes are made tothe thermometer.

Required:
a. When the alcohol thermometer is placed in 22 C water,what temperature will the thermometer record?
b. When the alcohol thermometer is placed in a -12 Csubstance, what temperature will the thermometer record?

c. If you want to design a thermometer with the same spacingbetween temperature markings as a mercury thermometer, how must thediameter of the inner hollow cylinder of the stem of the alcoholthermometer compare to that of the mercury thermometer? Assume thatthe bulb has a much larger volume than the stem.

1. 5.6 times wider
2. √5.6 times wider
3. the same diameter but different bulbsize
4. √5.6 times smaller
5. 5.6 times smaller

Answers

Answer:

a)  T_alcohol = 123.2ºC , b) T_alcohol = -67.2ºC  and c)  r_alcohol =√5,6 r_mercury  

Explanation:

We can solve this problem using the thermal expansion equation

            ΔV = β Vo ΔT

indicates that alcohol has a coefficient of expansion 5 times that of mercury

           β_alcohol = 5 β_mercury

the amount of alcohol used from a correct reading at zero degrees, let's substitute in the equation for alcohol

           ΔV = β_ alcohol ΔT

           ΔV = 5.6 β_mercury ΔT

we see that the expansion is 5 times the expansion of mercury

           T_alcohol = 5.6 T_mercury

           T_alcohol = 5.6 22

           T_alcohol = 123.2ºC

b) in the case of T = -12ºC

          T_alcohol = 5.6 (-12)

          T_alcohol = -67.2ºC

c) In this case we want the division to give the same value for the two thermometers

let's use the volume ratio

          V = A L

where A is the area of ​​the circle and L the length that the alcohol travels

We know that the volume of alcohol is 5.6 times the volume of mercury

        V_alcohol = 5.6 V_mercury

        A_alcohol V = 5.6 A_mercury L

        A_alcohol = 5.6 A_mercury

if the area of ​​a plum is A = π r², when substituting in this equation

         π r_alcohol² = 5.6 π r_mercury²

           r_alcohol =√5,6 r_mercury

the consequence the radius of the alcohol thermometer must be √5.6 times the radius of the Mercury thermometer; the correct answer is 2

most elements in nature exist as mixture of two or more isotopes
t or f

Answers

Answer:

Atomic mass is a value that depends on the distribution of an element's isotopes in nature and the masses of those isotopes. Circle the letter of each sentence that is true about a carbon-12 atom. ... Most elements exist as a mixture of two or more isotopes.

So the answer is true.

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a flexible container at an initial volume of 8.15 l 8.15 l contains 8.51 mol 8.51 mol of gas. more gas is then added to the container until it reaches a final volume of 13.7 l. 13.7 l . assuming the pressure and temperature of the gas remain constant, calculate the number of moles of gas added to the container.

Answers

The number of moles of gas added to the container is -3.56 mol, and the negative sign means that the number of moles of gas decreased, or in other words, the gas was compressed.

The number of moles of gas can be calculated using the Ideal Gas Law:

PV = nRT

where P is pressure, V is volume, n is the number of moles, R is the ideal gas constant, and T is temperature.

Since the pressure and temperature remain constant, we can equate the initial and final state of the gas:

n1 × (8.15 L) × (T) = n2 × (13.7 L) × (T)

Dividing both sides by T, we get:

n1 × 8.15 L = n2 × 13.7 L

Solving for n2:

n2 = (n1 × 8.15 L) / (13.7 L)

n2 = (8.51 mol) × (8.15 L) / (13.7 L)

n2 = 4.95 mol

So, the number of moles of gas added to the container is:

n2 - n1 = 4.95 mol - 8.51 mol = -3.56 mol.

Note that the answer is negative, which means that the number of moles of gas decreased, or in other words, the gas was compressed.

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If a = 8i + j - 2k and b = 5i - 3j + k show that a) a x b = -5i - 18j - 29k b) b X a = 50 + 18j +29k​

Answers

Recall the definition of the cross product with respect to the unit vectors:

i × i = j × j = k × k = 0

i × j = k

j × k = i

k × i = j

and that the product is anticommutative, so that for any two vectors u and v, we have u × v = - (v × u). (This essentially takes care of part (b).)

Now, given a = 8i + j - 2k and b = 5i - 3j + k, we have

a × b = (8i + j - 2k) × (5i - 3j + k)

a × b = 40 (i × i) + 5 (j × i) - 10 (k × i)

… … … … - 24 (i × j) - 3 (j × j) + 6 (k × j)

… … … … + 8 (i × k) + (j × k) - 2 (k × k)

a × b = - 5 (i × j) - 10 (k × i) - 24 (i × j) - 6 (j × k) - 8 (k × i) + (j × k)

a × b = - 5k - 10j - 24k - 6i - 8j + i

a × b = -5i - 18j - 29k

Answer:

Explanation:

If a = 8i + j - 2k and b = 5i - 3j + k show that a) a x b = -5i - 18j - 29k b) b X a = 50 + 18j +29k​

A magnet gets demagnetized when it is heated.​

Answers

Answer:

The delicate balance between temperature and magnetic domains is destabilized when a magnet is subjected to high temperatures. If a magnet is exposed to this temperature for an extended length of time or heated over its Curie temperature, it will lose its magnetism and become irreversibly demagnetized.

Explanation:

What is energy anything that takes up space and has mass a change in the position of an object a push or pull the ability to cause change in matter

Answers

Energy is that which has the ability to cause change in matter.

What is energy?

Energy is the quantitative property that is transferred to a body or to a physical system, recognizable in the performance of work and in the form of heat and light. Energy is a conserved quantity—the law of conservation of energy states that energy can be converted in form, but not created or destroyed.

So in simple definition we can say that energy is that which has the ability to cause change in matter.

Based on the given statements we can classify them as;

anything that takes up space and has mass - matter.cause a change in the position of an object through push or pull - forcethe ability to cause change in matter - energy.

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a plane wall is 250mm thick and it's wall area is 4.5m^2. if the thermal conductivity is 9.35w/m°c and surface temperature are steady at 150°c and 40°c. calculate the heat flow across the plane wall and the temperature gradient in the flow direction​

Answers

The temperature gradient in the flow of direction is 294525 W.

What is Temperature gradient?

A temperature gradient is the gradual variance in temperature with distance. The slope of the gradient is consistent within a material. A gradient is established anytime two materials at different temperatures are in physical contact with each other.

Q= T/( L/ KA)

Q= ( 1500 − 450) / 0.15 / 9.35v * 4.35)

   = 294525 W

Units of measure of temperature gradients are degrees per unit distance, such as °F per inch or °C per meter.

Many temperature gradients exist naturally, while others are created. The largest temperature gradient on Earth is the Earth itself. Q= T/Ka.

Therefore, The temperature gradient in the flow of direction is 294525 W.

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On the sonometer shown below, a horizontal cord of length 5 m has a mass of 1.45 g. When the cord was plucked the wave produced had a frequency of 120 Hz and wavelength of 6 cm. (a) What was the tension in the cord? (b) How large a mass M must be hung from its end to give it this tension? ​

Answers

Answer:

(a) T = 0.015 N

(b) M = 1.53 x 10⁻³ kg = 1.53 g

Explanation:

(a) T = 0.015 N

First, we will find the speed of waves:

\(v =f\lambda\)

where,

v = speed of wave = ?

f = frequency = 120 Hz

λ = wavelength = 6 cm = 0.06 m

Therefore,

v = (120 Hz)(0.06 m)

v = 7.2 m/s

Now, we will find the linear mass density of the coil:

\(\mu = \frac{m}{l}\)

where,

μ = linear mass density = ?

m = mass = 1.45 g = 1.45 x 10⁻³ kg

l = length = 5 m

Thereforre,

\(\mu = \frac{1.45\ x\ 10^{-3}\ kg}{5\ m}\\\\\mu = 2.9\ x\ 10^{-4}\ kg/m\)

Now, for the tension we use the formula:

\(v = \sqrt{\frac{T}{\mu}}\\\\7.2\ m/s = \sqrt{\frac{T}{2.9\ x\ 10^{-4}\ kg/m}}\\\\(51.84\ m^2/s^2)(2.9\ x\ 10^{-4}\ kg/m) = T\)

T = 0.015 N

(b)

The mass to be hung is:

\(T = Mg\\\\M = \frac{T}{g}\\\\M = \frac{0.015\ N}{9.8\ m/s^2}\\\\\)

M = 1.53 x 10⁻³ kg = 1.53 g

Calculate the speed for a car that went a distance of 125 miles in 2 hours time.

Answers

Answer:

65 miles per hour

Explanation:

Speed= Distance/Time

Following this formula, we just need to insert the values.

The distance is 125 miles and the time is 2 hours

125=2=65

65 miles per hour

The speed of the car was exactly 125 mi per 2 hours.

In a more familiar unit,  125mi/2hr = 62.5 mi/hr.

a stationary 165 kg football player is tackled by a 178 kg player running at 8 m/s. How fast are they moving after the collision ?

Answers

After the impact, the two players are moving side by side at a speed of roughly 4.12 m/s.

Does the principle of conservation of momentum is constant inside a certain problem domain?

Momentum is never created or destroyed inside a problem domain, according to the principle of momentum conservation. Momentum is only changed by the action of forces as they are described by Newton's equations of motion.

\(p1 = m1 * v1 + m2 * v2\)

\(p1 = 165 kg * 0 m/s + 178 kg * 8 m/s = 1424 kg*m/s\)

\(p2 = (m1 + m2) * v\)

Substituting the values, we get:

\(p2 = (165 kg + 178 kg) * v = 343 kg * v\)

Since the total momentum is conserved, we can equate p1 and p2:

p1 = p2

\(165 kg * 0 m/s + 178 kg * 8 m/s = 343 kg * v\)

\(v = (165 kg * 0 m/s + 178 kg * 8 m/s) / 343 kg ≈ 4.12 m/s\)

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IS
When a 0.622 kg basketball hits
the floor, its velocity changes from
4.23 m/s down to 3.85 m/s up.
What impulse was given to the
ball?
(Unit = kg*m/s)
Remember: up is +, down is -
Enter

Answers

Answer:

5.03

Explanation:

trust me

Suppose a boat is moving 6m/s relative to the pier, but you are walking on the boat -1 m/s relative to the boat' What would be your relative velocity to the pier? What direction would the boat be moving? Is this a one or two-dimensional problem?

Answers

Answer:

V₁ = 5 m/s

This is the problem of one dimension

Explanation:

Before using the concepts of relative velocity, we must first define the variables for each velocity here:

V₁ = Person's Velocity Relative to Pier = ?

V₂ = Boat's Velocity Relative to Pier = 6 m/s

V₁₂ = Person's Velocity Relative to Boat = - 1 m/s

Now, from the relative velocity, we know that:

V₁₂ = V₁ - V₂

- 1 m/s = V₁ - 6 m/s

V₁ = 6 m/s - 1 m/s

V₁ = 5 m/s

This is the problem of one dimension

because, the velocity is along single dimension with opposite directions. No, second dimension is involved.

What is the momentum of a 5 kg object that has a velocity of 1.2 m/s?
a) 3.8 kg • m/s
b) 4.2 kg • m/s
c) 6.0 kg • m/s
d) 6.2 kg • m/s

Answers

Explanation:

answer is 6.0Kg •m/s because

momentum= mass • velocity

that is 5 • 1.2 = 6

in the circuit at right, the bulbs are identical, and the battery is ideal. rank the brightness of the bulbs in the ircuit at right

Answers

Brightest resistor is the one with the most current. The current via bulb C is the highest since it receives the same amount of current as the battery.

What is an example of a resistor?

Digital potentiometers and rheostats are variable resistors. Electrical parts called rheostats are constructed from resistive thin wire around for a ceramic core. They were once employed to regulate the quantity of power utilized by ovens, heaters, and motors.

How do resistors function?

By decreasing the voltage and obstructing the passage of electricity, the resistance absorbs the electrical energy, which is then released as heat. The heat dissipation in electronic circuits today is typically a few hundredths of a watt.

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I gotta give the dog his treat, where do I put the items?​

Answers

Wait for the dog to do the trick and give it to him

Type your essay here.

Answers

Answer:

my essay

i typed my my essay like u said

Odina walked down the hall at school from the cafeteria to the band room, a distance of 100.0m. A class of physics students
recorded and graphed her position every 2.0s, noting that she moved 2.6m every 2.0s. Odina was 25m from the band room
at 58s.
Please select the best answer from the choices provided
Т
F

Answers

Find distance she traveled:

100m -25m = 75m


58 seconds / 2 second intervals = 29

29 x 2.6m = 75.4 meters total.


if the distance wasn’t rounded the statement was False.


Answer: False

The answer of this question is t

In the diagram, q1 = +6.39*10^-9 C. Theelectric field at point P is zero. What isthe value of the charge q2? Include a +or - sign.(Remember, E points away from + charges,and toward charges.)(The answer is *10^-8 C. Just fill in thenumber, not the power.)

In the diagram, q1 = +6.39*10^-9 C. Theelectric field at point P is zero. What isthe value of the charge

Answers

As the problem tells us, the field at point P is 0, thus, the field exerted by charges q1 and q2 have the same magnitude, and exactly the opposite direction, as it can be seen on the following drawing:

Thus, we know that charge q2 will have to be a source of field (as opposed to a sink), and thus, a positive charge. Now all we have to do is find out what charge could produce a field with the same magnitude of the one from q1. As the electric field can be written as:

\(E=\frac{kq}{d^2}\)

We'll have:

\(\frac{kq_1}{d_1^2}=\frac{kq_2}{d_2^2}\Rightarrow\frac{6.39*10^{-9}}{0.424^2}=\frac{q_2}{0.636^2}\Rightarrow q_2=\frac{6.39*10^{-9}*0.636^2}{0.424^2}\)\(q_2=1.43775*10^{-8}C\)

Thus, our answer is q2=1.43775*10^(-8)C

Note: Your lesson requests the answer to be inserted as: +1.44

In the diagram, q1 = +6.39*10^-9 C. Theelectric field at point P is zero. What isthe value of the charge

A convex lens has a focal length of 0.33 m. The object distance is 0.7 m. What is the image distance?

Answers

Answer:

Explanation:

1/v - 1/u = 1/f

given, f = 0.3 m, u = -0.4m

so, 1/v - 1/-0.4 = 1/0.3

or, 1/v = 1/0.3 - 1/0.4 = 1/1.2

v = 1.2 m

now, differentiating 1/v - 1/u = 1/f with respect to t,

-1/v² dv/dt + 1/u² du/dt = 0

or, dv/dt = (v/u)² du/dt

putting, du/dt = 0.01 m/s , v = 1.2 m and u = -0.4 m

so, dv/dt = (1.2/-0.4)² × 0.01

= 0.09 m/s

hence, speed of image with respect to lens is 0.09 m/s .

from formula of magnification

magnification, m = v/u

differentiating with respect to time both sides,

dm/dt = (u dv/dt - vdu/dt)/u²

= (-0.4 × 0.09 - 1.2 × 0.01)/(-0.4)²

= (-0.036 - 0.012)/0.16

= -0.048/0.16

= -0.3 m/s

hence, magnitude of rate of change of lateral magnification is 0.3 m/s


A 6 kg block is moving at 8 m/s. What will be the block's velocity after a 24 Ns impulse
was applied to it?

Answers

The change in velocity of an object is given by the equation Δv = F * t / m, where Δv is the change in velocity, F is the force applied, t is the time over which the force is applied, and m is the mass of the object.

In this case, the impulse applied to the block is 24 Ns, and the mass of the block is 6 kg. The time over which the force is applied can be calculated as t = Impulse / Force = 24 Ns / 24 N = 1 s.

Using these values, we can calculate the change in velocity of the block as follows:

Δv = F * t / m = 24 N * 1 s / 6 kg = 4 m/s

So, the velocity of the block after the impulse is applied would be v = v0 + Δv = 8 m/s + 4 m/s = 12 m/s.

It is necessary to to secure an inflated balloon tightly give reason

Answers

Yea if you want it to be filled up but if not then no

7. An object moves along a plane such that the x- and y-coordinates of its
velocity are defined by the functions vx (t) = 3t^2 - 3 and vy (t) = 2t^2 - 8. At what
time is the object's velocity purely horizontal?

Answers

The object's velocity is purely horizontal at the time "2 s".

This question can be solved using the given equations of x and y coordinates of the velocity.

At the time, when the velocity of the object is purely horizontal, the y-coordinate of the velocity must be equal to zero. Therefore, by setting the y-coordinate of the velocity to zero, we can find out the time at which the velocity of the object is purely horizontal.

\(v_y(t)=2t^2-8 = 0\\2t^2 = 8\\t^2 = 4\\\)

t = 2 s

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The attached picture shows velocity components.

7. An object moves along a plane such that the x- and y-coordinates of itsvelocity are defined by the

What is an independent variable?

Answers

Answer:

a variable (often denoted by x) whose variation does not depend on that of another.

Explanation:

An 12.000 milligram particle is sliding across a friction-less one-dimensional path at 55.000 m/s and collides with a 68.000 milligram particle moving at -48.000 m/s in a perfectly inelastic collision. What are the velocities of the particles after the collision?
answer with correct units​

Answers

Answer:

-3525.000 m/s

Explanation:

In a perfectly inelastic collision, the two particles stick together and move with a common velocity after the collision. We can use the conservation of momentum to solve for this common velocity.

The initial momentum of the system is:

p_initial = m1 * v1 + m2 * v2

= (12.000 mg)(55.000 m/s) + (68.000 mg)(-48.000 m/s)

= -282.000 kg·m/s

Here, we convert the masses to kilograms to match the units of velocity.

Since the particles stick together after the collision, their masses add up:

m_final = m1 + m2

= 12.000 mg + 68.000 mg

= 80.000 mg

= 0.080 g

Now, we can use the conservation of momentum to find the final velocity:

p_final = m_final * v_final

where p_final = p_initial and m_final = 0.080 g.

Therefore:

v_final = p_final / m_final

= -282.000 kg·m/s / 0.080 g

= -3525.000 m/s

Other Questions
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