Which is the only plate has all margins as convergent boundaries

Answer:

Mass = 43.45 g

Explanation:

Density is a value for mass, such as kg, divided by a value for volume, such as m3. Density is a physical property of a substance that represents the mass of that substance per unit volume. To find the mass of the substance, we need to multiply the volume occupied by the substance.

Mass = Density x Volume

Mass = 7.9 g/cm^3 (5.5 cm)^3

Mass = 43.45 g

The principle of option D. Uniformitarianism states that the physical, chemical, and biological processes at work shaping the Earth today have also operated in the

Option D. Uniformitarianism is the principle stating that the physical, chemical, and biological processes at work shaping the Earth today have also operated in the geologic past. It is based on the idea that the present is the key to the past. In other words, the same natural laws that operate in the universe today have been operating since the beginning of time.

James Hutton was the first to propose this principle in the late 18th century. He suggested that the Earth was shaped by slow-acting geological forces such as erosion, sedimentation, and uplift over long periods of time. He believed that the same processes were still happening today and that they had operated in the past.

This principle is an important concept in geology because it allows scientists to interpret the Earth's history based on the processes that they observe today. By understanding how these processes work and how they have changed over time, scientists can reconstruct the history of the Earth and its environments.

Uniformitarianism has been tested and proven through many observations and experiments. For example, the study of sedimentary rocks has shown that they were formed in the past through the same processes that are observed today, such as deposition of sediment by water, wind, or ice.

Similarly, the study of volcanoes has shown that they are formed by the same processes as today, such as the movement of magma from deep within the Earth.

In conclusion, Uniformitarianism is the principle that allows us to interpret the Earth's history by observing the processes that shape it today. It is a fundamental concept in geology and has been tested and proven through many observations and experiments.

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The first two chemical equations are reversible while the other two are irreversible.

Chemical equation is a symbolic representation of a chemical reaction which is written in the form of symbols and chemical formulas.The reactants are present on the left hand side while the products are present on the right hand side.

A plus sign is present between reactants and products if they are more than one in any case and an arrow is present pointing towards the product side which indicates the direction of the reaction .There are coefficients present next to the chemical symbols and formulas .

The first chemical equation was put forth by Jean Beguin in 1615.By making use of chemical equations the direction of reaction ,state of reactants and products can be stated. In the chemical equations even the temperature to be maintained and catalyst can be mentioned.

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Answer:

(CH3COO)2 + redP + Cl2 → ClCH2COOH + HCl

Explanation:

This is an example of halogenation of carboxylic acids at alpha carbon atom. In this reaction, red phosphorus and chlorine are treated with carboxylic acids having alpha hydrogen atom followed by hydrolysis to form alpha chloro carboxylic acid.

Answer:

the correct answer is argon: 1s 2^2s 2^2p 6^3s 2^3p^6​

Explanation:

With a rate constant of 7.30104 s1, the half-life of the first-order reaction is around 949.23 seconds, or 15.82 minutes.

To calculate the half-life of a first-order reaction with a rate constant of 7.30×10−4 s−1, we can use the following equation:

t1/2 = ln(2)/k

where t1/2 is the half-life, ln is the natural logarithm, and k is the rate constant.

Plugging in the given value of k, we get:

t1/2 = ln(2)/(7.30×10−4 s−1) ≈ 949.23 seconds or 15.82 minutes

Therefore, the half-life of the first-order reaction with a rate constant of 7.30×10−4 s−1 is approximately 949.23 seconds or 15.82 minutes.

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Actually the main difference:

Homogeneous mixture is a mixture consisting of constituent substances that are mixed evenly.  As a result, each part of the mixture has the same properties

 In contrast to heterogeneous mixtures where the constituent substances are not mixed evenly.  Thus, there are parts of the mixture that have different properties.

Differences between Homogeneous and Heterogeneous Mixtures in detail

1. Differences Between Homogeneous and Heterogeneous Mixtures Based on Their Definitions

Homogeneous is a mixture that is uniform in all its parts and forms a single phase.  An example of a homogeneous mixture is air.  In addition, homogeneous mixtures can also be commonly referred to as solutions.

Meanwhile, heterogeneous mixture is a mixture that is not similar or not uniform, and the formation of two or more phases, as well as the existence of a clear boundary between the phases.  Examples of heterogeneous mixtures include oil and water, a mixture of lime and sand, then a mixture of iron powder and carbon, and many others.

2. Differences Between Homogeneous and Heterogeneous Mixtures Based on Their Characteristics

The characteristics of this homogeneous mixture are in the form of constituent particles that cannot be distinguished from one another, have almost the same color, and have a similar taste.  Not only that, substances that have been mixed have the same ratio, have the same concentration level, and are in the form of solids, gases, and liquids.

And this mixture cannot be separated, if you use a mechanical method, but you can separate it when you use a more difficult method.  The example of such separation is similar to that of distillation.  That is one of the differences between homogeneous and heterogeneous mixtures based on their characteristics.

3. Difference between Homogeneous and Heterogeneous Mixtures Based on Their Properties

The nature of this homogeneous mixture has the property that if every part of a homogeneous mixture is often the same, both in terms of color, taste, and comparison.  An example of the nature of the homogeneous mixture is a spoonful of sugar dissolved in water.

While the nature of a heterogeneous mixture is a mixture of two or more substances, which have properties, the constituent substances are not the same or the alias is not uniform.  So that the two mixed substances can still be distinguished by the particles.

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Answer:

the phenotype of TT is the right answer

Acetyl CoA is the starting metabolite in ketone body biosynthesis. Acetyl CoA is produced from the breakdown of fatty acids and can enter the citric acid cycle to produce energy.

In conditions where glucose is not readily available, such as during fasting or a low-carbohydrate diet, the liver converts acetyl CoA into ketone bodies, including beta-hydroxybutyrate, acetoacetate, and acetone.

Ketone bodies can then be used as an alternative source of energy by tissues such as the brain and skeletal muscle. However, excessive production of ketone bodies can lead to a buildup of acidity in the blood, known as ketoacidosis, which can be dangerous.

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I would need more specific information about the equilibrium systems in your lab.

Please provide the details of the specific equilibrium systems being studied, including any reactants and products involved, as well as any observable characteristics or stresses on the equilibrium. Additionally, if there are any secondary reactions that occurred, please provide the relevant information.

With this information, I will be able to write the balanced chemical equations, describe the stresses and responses of the system, and explain the system's response using Le Chatelier's principle.

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Answer:

Organisms can be classified into one of three domains based on differences in the sequences of nucleotides in the cell's ribosomal RNAs (rRNA), the cell's membrane lipid structure, and its sensitivity to antibiotics. 3. The three domains are the Archaea, the Bacteria, and the Eukarya.

Explanation:

Answer: The butterfly effect

Explanation:

In the reaction of 2-chloro-2-methylpropane with \(AgNO3\) in ethanol, the other product that could form is silver chloride (AgCl).

The reaction mechanism for this reaction can be explained as follows: First, the 2-chloro-2-methylpropane reacts with AgNO3 to form 2-methyl propyl nitrate and silver chloride as follows: \($$\mathrm{C}_4\mathrm{H}_9\mathrm{Cl} + \mathrm{AgNO}_3 \longrightarrow \mathrm{C}_4\mathrm{H}_9\mathrm{ONO}_2 + \mathrm{AgCl}$$\\\)The formation of silver chloride is a substitution reaction because the chlorine atom of 2-chloro-2-methylpropane has been replaced by the nitrate ion. This is a nucleophilic substitution reaction because the nitrate ion (NO3-) is acting as the nucleophile. The silver ion (Ag+) is a spectator ion and does not participate in the reaction. This reaction is called an S_N1 reaction because it proceeds through a two-step mechanism in which the leaving group (Cl-) departs before the nucleophile (NO3-) attacks. The reaction mechanism for the formation of 2-methyl propyl nitrate is as follows:$$\mathrm{C}_4\mathrm{H}_9\mathrm{Cl} \longrightarrow \mathrm{C}_4\mathrm\({H}_9^+ + \mathrm{Cl}^-$$$$\mathrm{C}_4\mathrm{H}_9^+ + \mathrm{NO}_3^- \longrightarrow \mathrm{C}_4\mathrm{H}_9\mathrm{ONO}_2$$\\\). This reaction is also called an S_N1 reaction because it proceeds through a two-step mechanism in which the leaving group (Cl-) departs before the nucleophile (NO3-) attacks. The intermediate (C4H9+) is a carbocation and is stabilized by the methyl groups on either side.

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Answer:

A

No, because the number of carbon, hydrogen & oxygen atoms on both sides of the equation are not equal.

Hope this helps!

Answer:

use wire nettings

Explanation:

and cages

The energy an object has during its motion is known as the kinetic energy and the energy stored in an object is called the potential energy. The potential energy of the egg drop is 1.8 J.

The sum of potential energy and kinetic energy of an object is known as the mechanical energy. It describes the energy of an object due to its motion or position or both.

The equation of mechanical energy is:

Mechanical energy = Potential energy + Kinetic energy

Potential energy = Mechanical energy - Kinetic energy

2.3 J - 0.5 J = 1.8 J

Thus the potential energy of the egg drop is  1.8 J.

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\(H_2 + O_2 = H_2O\)

Here H is balanced but Obis unbalanced

So put 2 to H20 to balance O

\(H_2 + O_2 = 2H_2O\)

now H becomes unbalanced

So put 2 before H2

\(2H_2 + O_2 = 2H_2O\)

option a is correct

~Tulpe⚘

Answer:

-6.31°C

Explanation:

To solve this problem, we can use the principle of heat transfer:The heat gained by the lead (q_lead) equals the heat lost by the water (q_water).The formula to calculate heat transfer is:

q = m * c * ΔTWhere:

q = heat transfer

m = mass

c = specific heat

ΔT = change in temperatureFor the lead:

q_lead = m_lead * c_lead * ΔT_leadFor the water:

q_water = m_water * c_water * ΔT_waterGiven values:

m_lead = 322 g

c_lead = 0.138 J/gºC

ΔT_lead = T_final - T_initial_lead (unknown)

m_water = 264 g

c_water = 4.18 J/gºC (specific heat of water)

ΔT_water = T_final - T_initial_water = 46°C - 25°C = 21°CSince the heat gained by the lead is equal to the heat lost by the water, we can set up the equation:

m_lead * c_lead * ΔT_lead = m_water * c_water * ΔT_waterSubstituting the given values:

322 g * 0.138 J/gºC * ΔT_lead = 264 g * 4.18 J/gºC * 21°CSimplifying the equation:

44.436 J/ºC * ΔT_lead = 2325.12 J/ºCDividing both sides of the equation by 44.436 J/ºC:

ΔT_lead = 2325.12 J/ºC / 44.436 J/ºC ≈ 52.31°CFinally, we can find the initial temperature of the lead:

T_initial_lead = T_final - ΔT_lead

T_initial_lead = 46°C - 52.31°C ≈ -6.31°CTherefore, the initial temperature of the lead was approximately -6.31°C.

The heat needed to change 14.0 g of mercury at 20°C to mercury vapor at its boiling point is calculated by adding the heat required to raise the temperature and the heat of vaporization, while the final water temperature after adding 27.0 g of copper pellets at 300°C to 110 mL of water at 20.0°C can be determined by equating the heat lost by copper to the heat gained by water.

To calculate the heat needed to change 14.0 g of mercury at 20°C into mercury vapor at its boiling point, we need to consider two steps: heating the mercury to its boiling point and then vaporizing it.

Step 1: Heating the mercury to its boiling point

First, we need to calculate the heat required to raise the temperature of the mercury from 20°C to its boiling point. The specific heat capacity of mercury is approximately 0.14 J/g°C.

Q1 = mass × specific heat capacity × ΔT

Q1 = 14.0 g × 0.14 J/g°C × (boiling point - 20°C)

Step 2: Vaporizing the mercury

To convert the mercury from its liquid state to vapor, we need to calculate the heat required for vaporization. The heat of vaporization of mercury is approximately 296 kJ/kg.

Q2 = mass × heat of vaporization

Q2 = 14.0 g × (296 kJ/kg / 1000 g/kg)

Finally, we can find the total heat required:

Total heat = Q1 + Q2

Now let's move on to the second part of the question.

When the 27.0 g of copper pellets at 300°C are dropped into 110 mL of water at 20.0°C, they will lose heat until reaching thermal equilibrium. We can use the heat gained by the water to calculate the final temperature.

The specific heat capacity of copper is approximately 0.39 J/g°C, and the specific heat capacity of water is about 4.18 J/g°C.

Q1 (copper) = mass × specific heat capacity × ΔT

Q1 (copper) = 27.0 g × 0.39 J/g°C × (final temperature - 300°C)

Q2 (water) = mass × specific heat capacity × ΔT

Q2 (water) = 110 g × 4.18 J/g°C × (final temperature - 20.0°C)

Since the system is insulated, the total heat lost by the copper will be equal to the total heat gained by the water:

Q1 (copper) = Q2 (water)

Using this equation, we can solve for the final temperature.

Finally, let's move on to the last part of the question regarding the main-sequence star Regulus A.

Given that Regulus A has a mass of 3.8 times the mass of the sun (M sun) and a radius of 3.1 times the radius of the sun (R sun), we can use the formula P/P sun = 1.5(M/M sun )^3.5 to calculate the total radiated power relative to the sun.

P/P sun = 1.5 × (3.8)^3.5

Solving this equation will give us the total radiated power relative to the sun.

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Answer:

let me tell u what ASAP stands for Explanation:

Explanation:

When air is sucked out of a drinking straw, the air pressure inside if decreases and the atmospheric pressure outside

Answer:

The pressure of the liquid (blood) forces the liquid to move into the syringe when its plunger is withdrawn. When air is sucked out of a drinking straw, the air pressure inside if decreases and the atmospheric pressure outside forces the liquid to go inside the straw.

Answer:

Frequency = Velocity / Wavelength

or

f = v / λ

Answer:

https://newshamchem.weebly.com/uploads/2/2/0/3/22035226/molarity_&_worksheet_answer.pdf

question 9.

Explanation:

Answer:

.0125 moles

Explanation:

Molarity = moles/volume

.05 M = moles/.250L

.0125 = moles

When, pH of the resulting solution is 2.41. Then, the Ka for the weak acid is 1.75 × 10⁻⁴.

The first step is to set up the balanced equation for the ionization of the weak acid;

HA + H₂O ⇌ A⁻ + H₃O⁺

Next, write out the expression for the acid dissociation constant, Ka;

Ka = [A⁻][H₃O⁺] / [HA]

Since the concentration of the weak acid is given as 0.0194 M, we can assume that the initial concentration of HA is 0.0194 M. Let x be the concentration of H₃O⁺ ions and A⁻ ions formed when the acid dissociates.

HA + H₂O ⇌ A⁻ + H₃O⁺

Initial; 0.0194 M 0 0

Change; -x +x +x

Equilibrium; 0.0194 - x x x

We know that the pH of the solution is 2.41, so we can use the pH expression to find the concentration of H3O+ ions:

pH = -log[H₃O⁺]

2.41 = -log[H₃O⁺]

[H₃O⁺] = \(10^{(-2.41)}\)

= 6.43 × 10⁻³ M

Substitute the equilibrium concentrations into the Ka expression and solve for Ka;

Ka = [A-][H₃O⁺] / [HA]

Ka = (x)(6.43 × 10⁻³) / (0.0194 - x)

Since the weak acid is monoprotic, the concentration of A⁻ ions formed will be equal to the concentration of H₃O⁺ ions formed;

x = [A⁻] = 6.43 × 10⁻³ M

Substitute this value of x into the Ka expression and solve for Ka;

Ka = (6.43 × 10⁻³)² / (0.0194 - 6.43 × 10⁻³)

Ka = 1.75 × 10⁻⁴

Therefore, the Ka for the weak acid is 1.75 × 10⁻⁴.

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Answer:

I'm sorry but I can't do this one.

Explanation:

I'm not gonna lie, I think I'm missing something too.

The per cent recovery of cinnamaldehyde is 0.678%, which means that only a small amount of cinnamaldehyde was recovered from the cinnamon.

In this case, the student used 9.00 grams of ground cinnamon to isolate 61.0 milligrams (mg) of cinnamaldehyde.

To calculate the per cent recovery, we need to convert the mass of cinnamaldehyde from milligrams to grams by dividing by 1000, since there are 1000 milligrams in a gram. So, 61.0 mg is equal to 0.061 grams.

To calculate the per cent recovery, we divide the mass of cinnamaldehyde obtained (0.061 g) by the mass of cinnamon used (9.00 g) and then multiply by 100 to get the percentage. The calculation is as follows:

First, we need to convert the mass of cinnamaldehyde from milligrams to grams. Since there are 1000 milligrams in a gram, 61.0 mg is equal to 0.061 grams.

Next, we calculate the per cent recovery by dividing the mass of cinnamaldehyde obtained by the mass of cinnamon used and multiplying by 100.

Per cent recovery = (0.061 g / 9.00 g) x 100

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Answer:

Explanation:

Hello friend!!!!!

here's ur answer

The unit to describe volume is cubic meter.

Hope this helps

plz mark as brainliest!!!

Answer:

7249.1

Explanation:

Multiply 7.1x1021= 7249.1

Answer:

False

Explanation:

Always add acid to the water, it dilutes the acid the other way around.