One of the most effective ways to reduce greenhouse gases is using a car powered by fuel cells.
What are greenhouse gases?The term greenhouse gases refers to those gases that lead to a rise in the temperature of the earth due to the re-radiation of infrared rays towards the surface of the earth.
It is very important to take vital steps in order to prevent the emission of these gases. One of the most effective ways to reduce greenhouse gases is using a car powered by fuel cells.
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Answer:
Using a car powered by fuel cells
Explanation:
B On Edge
What is the IUPAC name of the following substance?
The International Union of Pure and Applied Chemistry (IUPAC) provides a standard system for naming organic compounds.
It is essential to learn this nomenclature system to communicate correctly about the chemical structures of compounds and how they relate to each other. Here is the IUPAC name of the following substance.Below is the structure of the given compound: In the given compound, there are four carbon atoms that are connected with single bonds. Carbon atoms are also attached to hydrogen atoms. Since it has four carbons in the main chain, the root name will be "but-". The functional group present in the molecule is the carboxylic acid group (-COOH), which gives the suffix "-oic acid." Therefore, the IUPAC name of the given substance is Butanoic acid.Thus, the IUPAC name of the given compound is Butanoic acid. It is essential to know the IUPAC naming of organic compounds to communicate correctly about the chemical structures of the compounds.
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Give the full electron configuration of Nitrogen and state why Nitrogen is classed as a p
block element
Explanation:
If the last electron enters the p-orbital after the electron configuration of the element, then that element is called the p-block element. The electron configuration of nitrogen(N) shows that the last electron of nitrogen enters the p-orbital. Therefore, nitrogen is the p-block element.
A sample of pure calcium fluoride with a mass of 15.0 g contains 7.70 g of calcium. How much calcium is contained in 30.0 g of calcium fluoride?
Answer:
15.40 g
Explanation:
15.0 g of calcium fluoride contains 7.70 g of calcium
30.0 g of calcium fluoride contains (30.0 x 7.70)/15.0 = 15.40 g
On page 49, the phrase "seemed genuinely suprised", is used. What does the word "genuinely" mean as it is used in this section? In the book tangerine
Explanation:
the definition of genuine:
genuinly means honestly or truley
FILL IN THE BLANK Using the following general equation for a nuclear reaction, complete the statements below.
The atomic number for Uranium is____ .
The mass of the reactant neutron is___ .
The atomic mass for Krypton is ___ .
There are ___ Barium neutrons.
The number of neutrons this reaction emits is ___ .
The atomic number for Uranium is 92. The mass of the reactant neutron is 1.00 amu. The atomic mass for Krypton is 36. There are naturally 81 Barium neutrons. The number of neutrons this reaction emits is 3.
Since uranium atoms all have 92 protons, they all have the same atomic number.
The neuron has one neuronic mass (the mass of one neutron - hence the subscript 0 because this generally describes the number of protons present).
The mass number of an atom is the sum of its protons and neutrons in its nucleus. This mass number is usually demonstrated as a superscript on the element symbol.
To get the number of neutrons in an isotope, we have to subtract the mass number from the atomic number.
The number of neutrons emitted is 3 because the number in front of an element symbol in a reaction indicates the amount of that element in that reaction (in moles) (either in the reactants or products side).
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The fake pill or medicine taken by members of a control group is a * what could the answer be
A. placebo.
B. hypothesis.
C. double-blind experiment.
D. Variable
Answer:
placebo
Explanation:
A placebo is usally given when trying to analyse data. it helps to also helps to ascertain the impact of yhe mesication.
Calculate the relative formula mass of Zn(NO3)2. Round your answer to the nearest whole number?
Answer:
189
Explanation:
189
The relative formula mass of Zn(NO₃)₂ is 189.38g.
How do we calculate the mass of any compound?Molecular mass of any formula of compound will be calculated by adding the molar mass of each atoms present in the given compound.
Molecular mass of Zn(NO₃)₂ = Sum of the molar mass of Zinc, nitrogen and oxygen atoms.
Molecular mass of Zn(NO₃)₂ = 65.38g/mol + 2(14g/mol) + 6(16g/mol) = 189.38g
Hence the required mass of Zn(NO₃)₂ is 189.38g.
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Based upon the intermolecular forces present, rank the following substances according to the expected boiling point for the substance.
a. HCl
b. NaCl
c. N2
d. H2O
how far would you travel moving 12 m/s for 3.00 minutes
NH3 is a weak base ( b=1.8×10−5 ) and so the salt NH4Cl acts as a weak acid. What is the pH of a solution that is 0.012 M in NH4Cl at 25 °C?
Answer:
NH3 is a weak base (Kb = 1.8 × 10-5)
and so the salt NH4Cl acts as a weak acid.
What is the pH of a solution that is 0.032 M in NH4Cl? ... The pH of the resulting solution is 2.53
Consider the following reaction:
2CH4(g)⇌C2H2(g)+3H2(g)
The reaction of CH4 is carried out at some temperature with an initial concentration of [CH4]=0.092M. At equilibrium, the concentration of H2 is 0.014 M.
Find the equilibrium constant at this temperature.
The equilibrium constant at this temperature is Kc= 4.17 x 10⁻⁶.
What is equilibrium?Since the equilibrium constant depends on the equilibrium concentration of both the reactants and the products of the chemical reaction.
Balanced reaction equation
2CH₄(g)⇌C₂H₂(g)+3H₂(g)
The initial concentration of the CH₄ = 0.093 M
The equilibrium concentration of the H = 0.017 M
Equilibrium constant = ?
Let's make the ice table
2CH₄(g) ⇌ C₂H₂(g) + 3H₂(g)
0.093 M 0 0
-2x +x +3x
0.093-2x x 0.017 M
3x = 0.017 M
Therefore, x =0.017 M /3 = 0.00567 M
Therefore, the equilibrium concentration of CH₄ =
0.093 M – 2x = 0.093 M – (2 x 0.00567 M) = 0.0817 M
Equilibrium concentration of the C₂H₄ = x = 0.00567 M
Let's write the equilibrium constant expression
Kc= [C₂H₄[H2]³/[CH₄]²
Let's put the values in the formula
Kc= [0.00567][0.017]³/[0.0817]²
Kc= 4.17 x 10⁻⁶
Therefore, the equilibrium constant is 4.17 x 10⁻⁶.
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what is the percent by mass of nitrogen in the following fertilizers? NH3
The percent by mass of nitrogen in ammonia (NH3) is approximately 82.15%
Calculating the mass of nitrogen to the total mass of the compound and then expressing the result as a percentage will allow us to determine the percent by mass of nitrogen in NH3 (ammonia).
Ammonia's molecular structure, NH3, indicates that it is made up of one nitrogen atom (N) and three hydrogen atoms (H). We must take both the molar masses of nitrogen and ammonia into account when calculating the percent by mass of nitrogen.
Nitrogen's (N) molar mass is roughly 14.01 g/mol. The molar masses of nitrogen and hydrogen are added to determine the molar mass of ammonia (NH3). Since hydrogen's molar mass is around 1.01 g/mol, ammonia's molar mass is:
(3 mol H 1.01 g/mol) + (1 mol N 14.01 g/mol) = 17.03 g/mol = NH3.
Now, we can use the following formula to get the nitrogen content of ammonia in percent by mass:
(Mass of nitrogen / Mass of ammonia) / 100% is the percentage of nitrogen by mass.
Ammonia weighs 17.03 g/mol and contains 14.01 g/mol of nitrogen by mass. By entering these values, we obtain:
(14.01 g/mol / 17.03 g/mol) 100% 82.15 % of nitrogen by mass
Ammonia (NH3) has a nitrogen content that is roughly 82.15 percent by mass.
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Which portion of a molecule of F2O has partial positive charge?
Question 3 options:
A)
The F atoms
B)
The central O atom
C)
The partial charge on each atom is zero
D)
The partial charge on each atom is negative
The partial charges on each fluorine atom are negative. Option B) The central O atom is the correct answer. Option B
The partial charges in a molecule are determined by the electronegativity values of the atoms involved. Electronegativity is the ability of an atom to attract electrons towards itself in a chemical bond. In the case of \(F_2O\), fluorine (F) is more electronegative than oxygen.
Fluorine is the most electronegative element on the periodic table, meaning it has a high ability to attract electrons. Oxygen is also relatively electronegative but less so than fluorine. When fluorine atoms bond with oxygen, the shared electrons will be pulled more towards the fluorine atoms, creating a polar covalent bond.
In \(F_2O\), each fluorine atom will pull the shared electrons towards itself, resulting in a higher electron density around the fluorine atoms. This creates a region of partial negative charge around the fluorine atoms.
Conversely, the oxygen atom will have a region of lower electron density and, therefore, a partial positive charge. This is because the shared electrons spend more time around the fluorine atoms due to their higher electronegativity.
Option B
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What is the mass percent of barium in barium cyanide?
Answer:
72.521%
Explanation:
The mass percent of barium in barium cyanide is 72.1%
What is Mass percent?Mass per cent is a way of expressing a concentration or describing the component in a particular mixture.
The solution composition can be described in mass percentage which shows the mass of solute present in a given mass of solution
The Mass percent formula is expressed as solving for the molar mass also for the mass of every element in 1 mole of the compound.
Given,
Molecular mass of Ba(CN)₂ = 190
Atomic mass of Ba = 137
mass percent = (mass of Ba ÷ molecular mass of compound) × 100
= (137 ÷ 190) × 100
= 72.1 %
Therefore, the mass percent of barium in barium cyanide is 72.1%
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assume that the density of all solutions are 1.000g/ml 1. Calculate the molarity of calcium in 1.9g of calcium chloride diluted in 100 ml of Di water. 2 Calculate the concentration of both calcium and chloride lons in problem 1 in units of mg/mL, ug/L, mg/L and ug/mL. 3. Calculate the concentration of both calcium and chloride ion in problem 1 in units of ppm and ppb. You may assume that the density of the solution is 1.0 g/ml 4. You have been provided 100 ml of a 1000 ug/ml barium standard. What volume of this standard must be diluted to a final volume of 50 ml using DI water to produce a 30 ug/mL standard
Answer:
1. 0.1712M
2. 6.86mg/mL Ca, 12.14mg/mL Cl, 6860000ug/L Ca, 12140000ug/L Cl, 6860mg/L Ca, 12140mg/L Cl, 6860ug/mL Ca, 12140ug/mL Cl.
3. 6860ppm Ca and 12140ppm of Cl.
4. 1.5mL of the 1000ug/mL barium standatd must be taken.
Explanation:
1. Molarity is defined as the amount of moles of solute (Calcium chloride) present in 1L of solution.
The moles of CaCl₂ are:
1.9g CaCl₂ * (1mol / 110.98g) = 0.01712 moles
In 100mL = 0.10L:
0.01712mol / 0.10L = 0.1712M
2. The masses of Calcium and Chloride ions are:
1.9g * (40.078g Ca / 110.98g) = 0.686g Ca
And:
1.9g - 0.686g Ca = 1.214g Cl
mg/mL:
686mg Ca / 100mL = 6.86mg/mL Ca
1214mg Cl / 100mL = 12.14mg/mL Cl
ug/L:
686000ug / 0.1L = 6860000ug/L Ca
1214000ug/ 0.1L = 12140000ug/L Cl
mg/L:
686mg Ca / 0.1L = 6860mg/L Ca
1214mg Cl / 0.1L = 12140mg/L Cl
ug/mL:
686000ug Ca / 100mL = 6860ug/mL Ca
1214000ug Cl / 100mL = 12140ug/mL Cl
3. ppm are defined as mg/L, the ppm of Ca are 6860ppm Ca and 12140ppm of Cl
4. The solution must be diluted from 1000ug/mL to 30ug/mL, that is a dilution of:
1000ug/mL / 30ug/mL:
33.33 times must be diluted the solution.
As final volume of the diluted solution must be 50mL, the volume of the standard needed is:
50mL / 33.33 times = 1.5mL of the 1000ug/mL barium standatd must be taken
14. A sample of carbon dioxide occupies a 2.54 dm² container at STP. What is the volume of the gas at a
pressure of 150.0 kPa and a temperature of 26.0°C?
0.180 dm
c. 2.24 dm3
b. 1.88 dm
d. 4.65 dm3
By using combined gas law , volume will be 1.88 \(dm^{3}\).
What is combined gas law?
The combined gas law contains the laws of Charles, Boyle, and Gay-Lussac. When you know the pressure, volume, and temperature of a system and need to modify one of these, you can apply this law to compute the resulting unknown.
Combined gas law is expressed as:
\($\frac{P_{1} V_{1}}{T_{1}}=\frac{P_{2} V_{2}}{T_{2}}$\)
Calculation of volume by using combined gas law
It is given that, \(V_{1}\) = 254\(dm^{3}\), at STP P = 101.3 kPa and T = 273 K
Now, put the value of given data in above equation.
\(V_{2}\) = (254\(dm^{3}\)) (101.3 kPa) (26+273) /(150 kPa) (273)
\(V_{2}\) = 1.88 \(dm^{3}\).
By using combined gas law volume will be 1.88 \(dm^{3}\).
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One day you experience violent thunderstorms followed by a few days of colder weather.
Which type of front most likely moved through your area?
occluded front
stationary front
warm front
cold front
Answer: Cold front
Answer:
Cold front lol
Explanation:
Hopefully this helps :)
3. A Wilkinson’s catalyst is widely used in the hydrogenation of alkenes. Show a catalytic cycle, including: i. chemical structure of the catalyst, with complete stereochemistry ii. molecular geometry of catalyst iii. type of reactions involved iv. the appropriate starting material, reagent and solvent v. major and minor end-products vi. all intermediates, for each reaction stated in (iii)
We can see here that the catalytic cycle for the hydrogenation of alkenes using Wilkinson's catalyst involves several steps.
What are the steps involved?Here's an overview of the catalytic cycle, including the necessary details:
i. Chemical structure of the catalyst:
Wilkinson's catalyst, also known as chloridotris(triphenylphosphine)rhodium(I), has the following chemical structure: [RhCl(PPh3)3]
ii. Molecular geometry of the catalyst:
The Wilkinson's catalyst has a trigonal bipyramidal geometry around the rhodium center. The three triphenylphosphine (PPh3) ligands occupy equatorial positions, while the chloride (Cl) ligand occupies an axial position.
iii. Type of reactions involved:
The catalytic cycle involves several reactions, including:
Oxidative addition: The rhodium center undergoes oxidative addition, reacting with molecular hydrogen (H2) to form a dihydride intermediate.Alkene coordination: The alkene substrate coordinates to the rhodium center, forming a π-complex.Hydrogenation: The coordinated alkene undergoes hydrogenation, resulting in the addition of hydrogen atoms to the double bond and formation of a metal-alkyl intermediate.Reoxidation: The metal-alkyl intermediate reacts with a hydrogen molecule to regenerate the rhodium dihydride species.iv. Starting material, reagent, and solvent:
The starting material is an alkene, and the reagent is Wilkinson's catalyst ([RhCl(PPh3)3]). The reaction is typically carried out in a suitable solvent, such as dichloromethane (CH2Cl2) or tetrahydrofuran (THF).
v. Major and minor end-products:
The major end-product of the hydrogenation reaction is the fully saturated alkane, resulting from the addition of hydrogen across the double bond. The minor end-product may include cis- or trans-configured alkanes if the original alkene substrate possesses geometric isomers.
vi. Intermediates:
The intermediates in the catalytic cycle include:
Rhodium dihydride complex: [RhH2(PPh3)3]Alkene-Rhodium π-complex: [Rh(η2-alkene)(PPh3)3]Metal-alkyl intermediate: [Rh(alkyl)(PPh3)3]These intermediates play a crucial role in facilitating the hydrogenation reaction and enabling the catalytic cycle to proceed.
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HELPPP PLZ
PLZZZZZZZZZ
Answer:
Average speed or just speed
Explanation:
Average speed is the total distance an object travels divided by the total amount of time it took to travel the distance.
how to synthesize 2-benzyl pentanoic acid from acetoacetic ester?
If you're attempting to synthesize 2 benzyl pentanoic acid from acetoacetic ester, keep in mind that you can do so fairly quickly by following these simplified instructions:
Begin by dissolving your acetoacetic ester into anhydrous diethyl ether and adding benzyl bromide and sodium hydroxide to the mix. Stir it all together at room temperature for around thirty minutes before reacting it with hydrochloric acid so that any remaining solvent evaporates out of your crude mixture; Lastly refine your creation by recrystallizing it from ethanol until you have pure 2 benzyl pentanoic acid.What is acetoacetic ester?From its pungent free scent to its solid state at temperatures ranging from 118 120°C, acetoacetic ester (better known as ethyl acetoacetate) offers significant value for those working within organic synthesis.
As one of many potent ketones utilized by researchers around the globe its unique properties make it ideal for building complex molecules essential for modern medicine and more.
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Convert 3.52 × 10^22 atoms of gold to moles
Answer:
5.85 x 10⁻² mol Au
Explanation:
Divide the atoms of gold with Avogadro's number to find the solution.
m A 10.00g sample of a substance is found to contain 5.12g of water. What is the percent by of water in the compound? A
. 5.12% B. 4.88% C. 48.8% D. 51.2%
Answer:
The answer is D) 51.2%
Explanation:
5.12g of 10.00g of the substance is water:
percentage of water= 5.12 x 10.00 =51.2%
Answer:
b
Explanation:
When NH3(g) reacts with O2(g) to form N2O(g) and H2O(l), 342 kJ of energy are evolved for each mole of NH3(g) that reacts. Write a balanced thermochemical equation for the reaction with an energy term in kJ as part of the equation.
Answer: \(2NH_3(g)+2O_2(g)\rightarrow N_2O(g)+3H_2O(l)+684kJ\)
Explanation:
The skeletal thermochemical equation for the reaction is:
\(NH_3(g)+O_2(g)\rightarrow N_2O(g)+H_2O(l)+342kJ\)
The balanced thermochemical equation for the reaction is:
\(2NH_3(g)+2O_2(g)\rightarrow N_2O(g)+3H_2O(l)+684kJ\)
When 1 mole of \(NH_3\) reacts with oxygen , heat released = 342 kJ
Thus when 2 moles of \(NH_3\) reacts with oxygen , heat released = \(\frac{2}{1}\times 342 kJ=684kJ\)
How does a vaccine impact the individuals who receive it?
O They will likely still develop the disease but will not die from i
O They will not be able to get the disease but can still pass it or
O Their bodies will remember the disease and be able to fight it
O They will become sick with the illness but then recover.
Answer fast pls
Answer:
I want to say (A) but i also want to say (C) but i can be wrong. most likely (C)
Explanation:
hope this helps lol and have a great day
Answer:
honestly this is kind of an opinionanated question because some people think that the vaccine dosen't work. Like I think that, but some other people might think differently so im gonna go with answer c.
Explanation:
A famous experiment that generated organic molecules from a mixture of gases thought to
resemble the early Earth's atmosphere was carried out in 1953 by ________.
A) Stanley Miller
B) Charles Darwin
C) Thomas Cech
D) J. S. Haldane
E) Aniela Wochner
A famous experiment that generated organic molecules from a mixture of gases thought to resemble the early Earth's atmosphere was carried out in 1953 by Stanley Miller.
To put Oparin and Haldane's theories to the test, Stanley Miller and Harold Urey conducted an experiment in 1953. They discovered that under reducing conditions supposed to match those of early Earth, organic compounds might be generated spontaneously.
Miller and Urey created a closed system with a heated water pool and a concoction of gases that were supposed to be common in the early earth's atmosphere (H2O, NH3, CH4, H2). Miller and Urey fired electrical sparks through their experimental apparatus to mimic the lightning that could have provided power for chemical processes in Earth's early atmosphere.
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Energy Resources Activity
Which of the following is a problem associated with the use of fossil fuels?
production of water
acid rain
nuclear waste
Answer:
acid rain is a problem associated with the use of fossil fuels
Explain why the elements Cobalt and Nickel in the fourth period violate the original periodic law as stated by Mendeleev.
Answer:
Explanation:
Dmitri Mendeleev was a Russian scientist that proposed the first periodic table of elements. Elements in his periodic table were arranged according to there relative atomic mass; however cobalt (Co) with an atomic mass of 58.93 was placed before nickel (Ni) with an atomic mass of 58.69 which was an anomaly as according to his law, nickel should come before cobalt since nickel has a lesser mass compared to cobalt.
A student wants to conduct an experiment that tests if pH balance affects plant growth. What is the dependent variable?
a. pH
b. Plant growth
c. Time
d. The student
Answer:
C
Explanation:
that is the only dependent variable
Starting with 0.3500 mol CO(g) and 0.05500 mol COCl2(g) in a 3.050 L flask at 668 K, how many moles of CI2(g) will be present at equilibrium?
CO(g) + Cl2(g)》COCl2(g)
Kc= 1.2 x 10^3 at 668 K
At equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.
1: Write the balanced chemical equation:
\(C_O\)(g) + \(Cl_2\)(g) ⟶ \(C_OCl_2\)(g)
2: Set up an ICE table to track the changes in moles of the substances involved in the reaction.
Initial:
\(C_O\)(g) = 0.3500 mol
\(Cl_2\)(g) = 0.05500 mol
\(C_OCl_2\)(g) = 0 mol
Change:
\(C_O\)(g) = -x
\(Cl_2\)(g) = -x
\(C_OCl_2\)(g) = +x
Equilibrium:
\(C_O\)(g) = 0.3500 - x mol
\(Cl_2\)(g) = 0.05500 - x mol
\(C_OCl_2\)(g) = x mol
3: Write the expression for the equilibrium constant (Kc) using the concentrations of the species involved:
Kc = [\(C_OCl_2\)(g)] / [\(C_O\)(g)] * [\(Cl_2\)(g)]
4: Substitute the given equilibrium constant (Kc) value into the expression:
1.2 x \(10^3\) = x / (0.3500 - x) * (0.05500 - x)
5: Solve the equation for x. Rearrange the equation to obtain a quadratic equation:
1.2 x \(10^3\) * (0.3500 - x) * (0.05500 - x) = x
6: Simplify and solve the quadratic equation. This can be done by multiplying out the terms, rearranging the equation to standard quadratic form, and then using the quadratic formula.
7: After solving the quadratic equation, you will find two possible values for x. However, since the number of moles cannot be negative, we discard the negative solution.
8: The positive value of x represents the number of moles of \(Cl_2\)(g) at equilibrium. Substitute the value of x into the expression for \(Cl_2\)(g):
\(Cl_2\)(g) = 0.05500 - x
9: Calculate the value of \(Cl_2\)(g) at equilibrium:
\(Cl_2\)(g) = 0.05500 - x
\(Cl_2\)(g) = 0.05500 - (positive value of x)
10: Calculate the final value of \(Cl_2\) (g) at equilibrium to get the answer.
Therefore, at equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.
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(b) Two compounds, A and B, have the molecular formula C₂H6O. On treatment with Na metal, compound A releases H2 gas and compound B does not.
Can you give a reason to help to explain the observation better?
The observation that compound A releases H2 gas while compound B does not when treated with Na metal can be explained by considering the structural differences between the two compounds and their ability to undergo specific reactions.
Compound A and compound B both have the molecular formula C₂H₆O, which indicates that they both contain two carbon atoms, six hydrogen atoms, and one oxygen atom. However, the difference lies in the arrangement of these atoms within the molecules. One possible explanation for the observed difference is that compound A is an alcohol, specifically ethanol (CH₃CH₂OH), while compound B is an ether, such as dimethyl ether (CH₃OCH₃). The presence of the hydroxyl group (-OH) in ethanol enables it to undergo a reaction with sodium metal, known as the metal-acid reaction. In this reaction, the metal displaces the hydrogen from the hydroxyl group, forming sodium ethoxide (CH₃CH₂ONa) and releasing hydrogen gas (H₂). On the other hand, ethers like dimethyl ether lack the hydroxyl group and therefore cannot undergo the metal-acid reaction. Consequently, when compound B is treated with sodium metal, no hydrogen gas is released. The ability of compound A to release hydrogen gas while compound B does not when treated with sodium metal can be attributed to the presence of a hydroxyl group in compound A (ethanol), enabling it to undergo a metal-acid reaction, whereas compound B (dimethyl ether) lacks the necessary functional group and thus does not undergo this reaction.
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