which is the following is a modern method used to pressure food

1. sprey drying

2.salting

3. smoking

4. Honey​

Answer:

If it is a true mixture, the mixing enthalpy is negligible, and there is no reaction or phase change, then you can do this using exclusively the temperatures of the individual compounds and their heat capacities. Any other process that takes place needs to be taken into account separately.

The solution can be found by understanding that we’re only using state variables. You can design any complicated process that starts with the starting situation and ends up at the ending situation, and the state variables will be the same. And sometimes a complicated process is easier to calculate than the simple one-step process, like here when mixing multiple components.

One way that will work is to start by bringing all compounds to the lowest temperature of either of the compounds. All but one of the compounds must be cooled down for this; make sure to calculate for each of the components how much energy is released. Now, mix all the components together. In the simplest situation sketched above you can calculate the heat capacity of the mixture by adding all the heat capacities of the components. Use this total heat capacity to calculate how much you can heat up the mixture using the energy you saved in cooling down the components earlier. This will be your desired end situation.

In case there are any phase changes or other processes in between, you need to take the energy needed for those into account too but in very similar ways.

Answer:

false

Explanation:

the energy an object has by virtue of its position is gravitational energy.

the energy which an object possess due to its motion is kinetic energy.

hope it helps !

Answer:

If I understand correctly. Line B is parallel to the circle. Also, the angle is less than 90.

'Circle' is characterized as "a two-dimensional geometric figure comprising of the set of all those points in a plane that are at equal distance from the center."

1). Line B would be considered as the 'tangent' in association with the given circle.

2). The angle lying among the lines A and B would be of 90° i.e. right angle.

Given that,

A circle with line A drawn through its center

Line B moves while touching the edge of the circle and intersects line A outside the circle.

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The pressure at point B is 622.5 kPa.

Based on the information provided, we can determine the velocity of the water through the 40-mm-diameter elbow using the formula Q = Av, where Q is the volumetric flow rate (0.012 m³/s), A is the cross-sectional area of the elbow (πr², where r is the radius of the elbow), and v is the velocity of the water.

We can rearrange the formula to solve for v:

v = Q / A

The radius of the elbow can be determined by dividing the diameter by 2:

r = 40 mm / 2 = 20 mm = 0.02 m

The cross-sectional area of the elbow can then be calculated using the formula A = πr²:

A = π(0.02 m)² = 0.00126 m²

Substituting these values into the formula for velocity:

v = 0.012 m³/s / 0.00126 m² = 9.52 m/s

Now that we know the velocity of the water, we can use Bernoulli's equation to determine the pressure at point B:

P₁ + 0.5ρv₁² + ρgh₁ = P₂ + 0.5ρv₂² + ρgh₂

Where P₁ is the pressure at point A (170 kPa), ρ is the density of water (1000 kg/m³), g is the acceleration due to gravity (9.81 m/s2), h₁ and h₂ are the heights of points A and B above a reference level (we can assume they are the same), and P₂ is the pressure at point B (what we want to find).

Rearranging the equation and substituting in the known values:

P₂ = P₁ + 0.5ρ(v₁² - v₂²)

P₂ = 170 kPa + 0.5(1000 kg/m³)(9.522 - 02) = 170 kPa + 452.5 kPa

P₂ = 622.5 kPa

Therefore, the pressure at point B is 622.5 kPa.

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A promising evidence of a habitat that might support life on the planet Mars is water.

There is evidence supporting the existence of liquid water on Mars from numerous sources. The finding of repeated black streaks on Martian slopes and the presence of hydrated minerals suggest the potential of seasonal or location-specific briny water flows. A necessary component of life as known is liquid water.

Additionally, Mars possesses underground ecosystems that could provide defence against radiation and severe surface conditions. Researchers have found evidence of ancient underground hydrothermal systems as well as beneath ice. These settings might offer consistent conditions for the development of microbial life.  Methane gas has been found in the Martian atmosphere, along with variations over time, and this has led to questions regarding its origin. Both geological and biological processes can result in the production of methane.

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Answer:

\(a=0.611\ m/s^2\)

Explanation:

Given that,

Mass of a refrigerator, m = 90.01 kg

She is able to slide the refrigerator across the floor with 55  N of force.

We need to find the acceleration of the refrigerator.

Let it is a. Using second law of motion:

F = ma

\(a=\dfrac{F}{m}\\\\a=\dfrac{55\ N}{90.01\ kg}\\\\a=0.611\ m/s^2\)

So, its acceleration is \(0.611\ m/s^2\).

Explanation:

s = ut + 1/2at²

= 0(10) + 1/2×6.6×(10)²

= 3.3 × 100

= 330 m

Eating less red meat so fewer cattle need to be raised would help reduce global warming.

The production of red meat, particularly beef, is a major contributor to greenhouse gas emissions. Cattle produce methane, a potent greenhouse gas, and the production of feed for cattle also requires large amounts of energy, water and land. Additionally, the clearing of forests for grazing land and feed production also contributes to carbon emissions.

Riding a bicycle rather than walking to school would also help reduce global warming because it would decrease the amount of CO2 emissions produced by cars and other vehicles.

Clearing more forests to produce more farmland and using more fertilizers to increase crop production would not help to reduce global warming, as the clearing of forests causes a release of stored carbon into the atmosphere and the use of fertilizers and pesticides also has an environmental impact.

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According to the Skygazer's Almanac for 2022 at 40 degrees, Venus and Saturn will be in opposite parts of the sky on December 17, 2022.

The Skygazer's Almanac provides astronomical information for a specific location and year. In this case, at a latitude of 40 degrees, the almanac indicates that Venus and Saturn will be in opposite parts of the sky on December 17, 2022. This means that Venus and Saturn will appear at opposite sides of the celestial sphere as observed from Earth. However, it's important to note that the almanac's predictions are approximate and can be influenced by various factors, including atmospheric conditions and the observer's specific location. To obtain the most accurate and up-to-date information, it is recommended to consult more recent astronomical sources or use specialized software that can provide precise positions and dates for celestial events.

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Answer:

lol

Explanation:

it was funny

The length of the cylindrical bar of cast iron is approximately 77259.6 meters.

To find the length of the cylindrical bar of cast iron, we can use the formula: Volume = Base Area * Length

As per data,

Base Area = 1.50 cm²

Density = 7.76 g/cm³

Mass = 898 kg

First, we need to convert the base area from cm² to m²:

1 cm² = 0.0001 m²

Base Area = 1.50 cm² * 0.0001 m²/cm²

Base Area = 0.00015 m².

Next, we need to convert the density from g/cm³ to kg/m³:

1 g/cm³ = 1000 kg/m³

Density = 7.76 g/cm³ * 1000 kg/m³

Density = 7760 kg/m³.

Now, we can rearrange the formula to solve for the length:

Length = Mass / (Base Area * Density)

Length = 898 kg / (0.00015 m² * 7760 kg/m³)

Length ≈ 77259.6 m.

Therefore, the length of the cylindrical bar is approximately 77259.6 meters.

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Answer:

S = 1/2 a t^2      since intial speed is zero

Vav = 210 m/s / 2 = 105 m/s

t = .7 m / 105 m/s = 6.67E-3 sec    (6.67 * 10^-3 s)

a = 2 S / t^2

a = 2 * .7 / (6.67E-3)^2

a = 31,500 m/s^2

Check:

Ave Speed * time = length of barrel

105 * 6.67E-3 = .70 m

High-mass stars are so luminous that their radiation strips gas from the outer layers and driving it into space whereas high-mass stars achieve much hotter temperatures in their cores and interior layers

Low mass stars are cooler and are reddish in color. High mass stars are hotter, and are white or blue white in color. Extremely high mass stars may also shine as a pale violet, which is more blue than blue white. High mass stars are brighter compared to low mass stars, because they produce more energy.

A low mass star is less than three solar masses whereas high mass star is above eight solar masses.

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By using Lami's theorem, Mass m = 1.75 kg approximately

Given that a strong weightless rope has a mass, m, hanging from the middle of it. If the tension force on each rope is 25 N, and the rope droops at an angle of 20.0 degrees to the horizontal.

By using Lami's theorem, we can get how much mass is hanging from the rope.

Let the angle between the rope = α = 180 - 40

α = 140 degrees

The angle between one of the rope and mass = β = 20 + 90

β = 110 degrees

The angle between the mass and the other rope = γ = 360 - (140 + 110)

γ = 360 - 250

γ = 110 degrees

W/ sinα = T/ sinβ = T/sinγ

W/ sinα = T/ sinβ

Substitute all the necessary parameters

W/sin140 = 25/sin 110

W / 0.643 = 25 / 0.939

W = 17.1 N

Weight W = mg

17.1 = 9.8m

mass m = 17.1/9.8

Mass m = 1.7455 kg

Mass m = 1.75 kg approximately

Therefore, 1.75 kg mass is hanging from the rope.

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Answer:

A. Analog signal

Explanation:

:)

Answer:

The magnetic field is doubled.

Explanation:

What happens to the strength of the magnetic field if one more 1.5 v dry cell is added?

The magnetic field due to a current carrying conductor is directly proportional to the current flowing in the wire.

If we connect one more battery of 1.5 V so the voltage is doubled and according to the Ohm's law, as the resistance of wire is constant, so the current in the wire is also doubled.

When the current doubles, the magnetic field produced by the wire is also  doubled.

Photodetectors that rely on the external photoelectric effect are known as photoemissive detectors (sometimes spelled photoelectric detectors).

A photocathode of some kind is present in such a device, where incident light is partially absorbed to produce photoelectrons, which are released into free space.

The light reflected off of particles by a light beam inside the sensor chamber is used by smoke detectors to detect smoke. When there are no particles in the sensing chamber, the beam's light does not hit the light detector, signaling that everything is in order.

Ionization smoke alarms detect smoke from rapidly blazing fires, while photoelectric smoke detectors are best for detecting smoke from smoldering fires.

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Answer:

you would fall forward due to inertia of motion..

With low-frequency stimulation, the muscle relaxes fully between contractions, resulting in identical twitches twitches per stimulus.

Alpha motor neurons are the motor neurons that innervate the fibers of the skeletal muscle. A number of branches, each innervating a different muscle fiber, are formed as the alpha motor neuron enters the muscle. A motor unit is made up of one alpha motor neuron and all of the muscle fibers it innervates. Small motor units with 3-5 muscle fibers per motor neuron are found in muscles that are involved in delicate, coordinated control. Our hand and eye muscles, as well as those that control eye movement, have very small motor units.

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Answer:

c

Explanation:

because its c

gggfffgggyvg gt you jyngy6bht

Explanation:

Current : Flow of charge per unit time is current. Its unit is ampere. I (Current) = Voltage(V) / Resistance(R)

Resistance : Hindrance to the flow of current is called resistance. Its unit is ohm. R = V/I

Each lamp cause 12 volt drop in voltage so 240/12= 20 lamps will be enough to be connected in series.

Each lamp will light with same brightness because these are connected in series and the current (number of charges passing per unit time) is same through all of these.

If anything want to learn, you are welcome to ask in comments.

Please mark it branliest if the answer is little bit satisfying.

Thanking in anticipation.

The acceleration of the object would be found to stay the same.

Let us note that the acceleration would have to do with the rate at which the velocity of the object would change with time. In the case that we have here, we can see that there is a point where the net force is the same as we can see on the graph.

We know that it is a change in the net force that is acting on the object that would cause the object to be accelerated as such if the net force stays as a constant then the acceleration of the object would also stay the same.

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Over the first 100. m, the driver accelerates from rest to a speed v such that

v² - 0² = 2 (13.2 m/s²) (100. m)

⇒   v ≈ 51.4 m/s

For the next 0.500 s, the driver maintains this speed and covers a distance of

(51.4 m/s) (0.500 s) ≈ 25.7 m

The remaining length of track is

180. m - 100. m - 25.7 m = 54.3 m

and the driver must have a minimum acceleration a such that

0² - (51.4 m/s)² = 2a (54.3 m)

⇒   a ≈ -24.3 m/s²

Answer:

V = 1280 [V]

Explanation:

To solve this problem we must use ohm's law which tells us that the voltage is equal to the product of the resistance by the current.

Therefore we have:

V = I*R

where:

V =  voltage [V] (Units of volts)

I = current = 4 [amp]

R = resistance = 320 [ohms]

V = 4*320

V = 1280 [V]

Answer:

T = 640N

Explanation:

In order to calculate the tension on the wire you use the following formula:

\(v=\sqrt{\frac{T}{m/L}}\\\\T=\frac{v^2m}{L}\)   (1)

T: tension on the wire

v: speed of the transverse wave

L: length of the wire = 1.0 m

m: mass of the wire = 100 g = 0.1kg

Then, you need to calculate the speed of the wave by using the information about the wavelength and the frequency of the wave. You use the following formula:

\(v=\lambda f\)     (2)

λ: wavelength = 0.10 m

f: frequency = 800Hz

You replace the values of the parameters in the equation (2):

\(v=(0.10m)(800Hz)=80\frac{m}{s}\)

Next, with the information about the speed of the wave you can calculate the tension on the wire by using the equation (1):

\(T=\frac{(80m/s)^2(0.1kg)}{1.0m}=640N\)

The tension on the wire is 640 N

 The charge Q is uniformly distributed throughout the sphere. The correct answer is (B)

When a solid conducting sphere is given a positive charge Q, the charge will distribute itself evenly throughout the surface of the sphere due to the repulsion of like charges. This is known as the "Faraday's ice pail experiment".

According to the principle of electrostatics, the charge on a conductor always resides on its surface and distributes itself in a way that the electric field inside the conductor is zero. Since the charge on a conductor always resides on its surface, it follows that the charge Q in this case must be uniformly distributed throughout the surface of the sphere.

Option (A) is not true because the charge is not concentrated at the center of the sphere. If the charge was concentrated at the center of the sphere, the electric field would not be zero inside the conductor, which contradicts the principle of electrostatics.

Option (C) and (D) are not true because the density of the charge does not change radially outward from the center. If the density decreased or increased radially outward, the electric field inside the conductor would not be zero, which again contradicts the principle of electrostatics.

Option (E) is not true because the charge is distributed throughout the entire volume of the sphere, not just on its surface. A solid conductor has free charges that can move throughout its entire volume, so the charge will distribute itself throughout the entire volume of the sphere until the electric field inside the conductor is zero.

Therefore, the correct answer is (B) it is uniformly distributed throughout the sphere.

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Answer:

A

Explanation:

t=s/t

t=21km/h:14km/hr

t=21/14* km/km *hr

t=1,5 hr

Answer:

A

Explanation:

To run a 21 km race at a 14 km/h would take 1.5 hours

Answer:

\(0.361\ \text{m}\)

Explanation:

\(f_s\) = Frequency of source = 375 Hz

\(\Delta f\) = Difference between the maximum and minimum sound frequencies = 2.75 Hz

v = Speed of sound in air = 343 m/s

T = Time period = 1.8 s

\(v_m\) = Maximum speed of the microphone

We have the relation

\(\Delta f=2f_s\dfrac{v_m}{v}\\\Rightarrow v_m=\dfrac{\Delta fv}{2f_s}\\\Rightarrow v_m=\dfrac{2.75\times 343}{2\times 375}\\\Rightarrow v_m=1.26\ \text{m/s}\)

Amplitude is given by

\(A=\dfrac{v_mT}{2\pi}\\\Rightarrow A=\dfrac{1.26\times 1.8}{2\pi}\\\Rightarrow A=0.361\ \text{m}\)

The amplitude of the simple harmonic motion is \(0.361\ \text{m}\).

Answer:

A. the time of fire is 15 seconds, and the angle of fire is approximately 23.794° above the horizontal

B. The angle of fire is increased to approximately 35.4126° above the horizontal

Explanation:

A. The height of the bridge, h = 70 m

The speed with of the shell, v₀ = 100 m/s

The location of the speedboat = 3000 m

The direction of the speedboat = 26 m/s

The acceleration of the speedboat, a = 11 m/s²

Let t represent the time of firing the shells, and let x represent the distance of the speedboat from the bridge, and let θ, represent the angle to fire with, we have;

For the speedboat, t = x/(100 × cos(θ))

We note that the time the shell can travel the 3,000 m = 30 seconds

Therefore an adequate time to fire is, t = 15 seconds

The distance the speedboat covers in 15 seconds is given as follows;

s = u·t + 1/2·a·t²

s = 26 × 15 + 1/2 × 11 × 15² = 1627.5 m

At the point the speedboat had traveled 1,627.5 m, the distance of the speedboat, x is then 3000 - 1,627.5 = 1,372.5 m from the bridge, the angle of fire is given from the following formula;

t = x/(100 × cos(θ))

15 = 1,372.5/(100 × cos(θ))

cos(θ) = 1,372.5/(15 × 100) = 0.915

θ = cos⁻¹(0.915) ≈ 23.794°

The angle of fire, θ ≈ 23.794° above the horizontal in the direction of the speedboat

B. Given that a 10 m/s wind is blowing towards East, we have;

The horizontal velocity towards East = 10 + v₀ × cos(θ)

The angle of firing is therefore, given as follows;

15 = 1,3725.5/(10 + 100 × cos(θ))

(10 + 100 × cos(θ)) = 1,3725.5/15

100 × cos(θ) = 1,372.5/15 - 10

cos(θ) = (1,372.5/15 - 10)/100 = 0.815

θ = cos⁻¹(0.815) ≈ 35.4126°

Therefore, the angle of fire, θ, will be increased to approximately 35.4126° above the horizontal in the remote controlled speedboat direction.