Which is a valid prediction about the continuous function f(x)?

Answer:

\(\boxed{\sf x=-15}\)

Step-by-step explanation:

\(\sf 10=x+25\)

\(\sf x+25=10\)

\(\boxed{\mathrm{Subtract\:}25\mathrm{\:from\:both\:sides}}\)

Answer:

x = -15

Step-by-step explanation:

If G is not a PRG, then Construction 3.17 cannot be EAV-secure. This shows the contrapositive of Theorem 3.18.

To prove the opposite, we need to show that if G is not a pseudorandom generator (PRG), then Construction 3.17 cannot be EAV-secure (indistinguishable encryptions in the presence of an eavesdropper).

Let's assume that G is not a PRG. This means that there exists some efficient algorithm D that can distinguish the output of G from random strings with non-negligible advantage. We will use this assumption to construct an adversary A that can break the EAV-security of Construction 3.17.

The adversary A works as follows:

1. A receives a security parameter n.

2. A runs the key generation algorithm Gen and obtains the key k.

3. A chooses two distinct messages m0 and m1 of length ℓ(n).

4. A computes the ciphertexts c0 = G(k) ⊕ m0 and c1 = G(k) ⊕ m1.

5. A chooses a random bit b and sends cb to the challenger.

6. The challenger encrypts cb using the encryption algorithm Enc with key k and obtains the ciphertext c*.

7. A receives c* and outputs b' = D(G(k) ⊕ c*).

8. If b = b', A outputs 1; otherwise, it outputs 0.

We analyze the probability that A can distinguish between encryptions of messages m0 and m1. Since G is not a PRG, D has a non-negligible advantage in distinguishing G's output from random strings. Therefore, there exists a non-negligible function negl such that:

|Pr[D(G(k)) = 1] - Pr[D(U) = 1]| ≥ negl(n),

where U denotes a truly random string of length ℓ(n).

Now, consider the probability of A winning the PrivK game:

Pr[PrivK_A,Π

eav

(n) = 1] = Pr[b = b']

           = Pr[D(G(k) ⊕ c*) = D(G(k))]

           = Pr[D(G(k)) = 1]

           ≥ Pr[D(U) = 1] - negl(n).

Since negl(n) is non-negligible, we have:

Pr[PrivK_A,Π

eav

(n) = 1] ≥ 2^(-1) + negl(n).

Thus, if G is not a PRG, then Construction 3.17 cannot be EAV-secure. This shows the contrapositive of Theorem 3.18.

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Answer: Wade's iPhone is longer.

Step-by-step explanation: 4 12/8 = 5 4/8 > 5 3/8 Brainliest please?

Rounding to the nearest tenth, the area of the triangular windowpane is approximately 8.2 square feet.

To find the area of a triangular windowpane, we need to use the formula for the area of a triangle, which is:

Area = (1/2) x Base x Height

In this case, the base is 4 feet 8 inches and the height is 3 feet 6 inches. However, we need to convert these measurements to the same units before we can calculate the area. Since there are 12 inches in 1 foot, we can convert the measurements as follows:

Base = 4 feet + 8 inches/12 = 4.67 feet

Height = 3 feet + 6 inches/12 = 3.5 feet

Now we can plug in these values into the formula and calculate the area:

Area = (1/2) x 4.67 feet x 3.5 feet

Area = 8.1675 square feet

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To determine whether or not to play this game, the following steps are necessary:

Step 1: Draw up a table that shows the sum of the outcomes when the two cubes are tossed together, as follows:

The table above shows that there are a total of 36 outcomes when the two cubes are tossed together, and shows the sum of the values on the faces of the cubes for each outcome.

Step 2: Use the values in the table to find the probabiity of obtaining a sum greater than or equal to 8, and the probability of obtaining a sum less than 8, as below:

Also:

Step 3: Compute the expectation, using the probabilities and the tokens to be won or lost, as follows:

Now, since the total expectation is -5 tokens, it means that 5 tokens will be lost at the end of this game. Now, would you play a game where you get to lose? Certainly not.

The answer is that you should not play this game

Answer:

73

Step-by-step explanation:

Answer:

B

Step-by-step explanation:

WHEN WE add

the values of b

and the values in the shape

it equals to 360

All of the interior angels in a quadrilateral add to 360

Answer:

D: 200

Step-by-step explanation:

Given that

The DVD player shipped 960 players last month

There is a record that out of every 24 players, the 5 would be the repaired

So we need to find the number of DVD players were repaired in this 960 players

So

= 960 × 5 ÷ 24

= 200 players

Hence, the option is d.

The inside function is g(x) = 8 - x^2 and the outside function is f(u) = 3u.

The inside function, u = g(x), is the function that is inside the parentheses of the outside function, y = f(u). In this case, the inside function is g(x) = 8 - x^2. The outside function, y = f(u), is the function that contains the inside function. In this case, the outside function is f(u) = 3u.

So, to identify the inside and outside functions in the given equation, y = f(g(x)) = 3(8 - x^2), we can use the following steps:

1. Identify the inside function, u = g(x): The inside function is the function inside the parentheses of the outside function. In this case, the inside function is g(x) = 8 - x^2.

2. Identify the outside function, y = f(u): The outside function is the function that contains the inside function. In this case, the outside function is f(u) = 3u.

Therefore, the inside function is g(x) = 8 - x^2 and the outside function is f(u) = 3u.

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Brad needs to score between 26 and 62 on the fourth test to achieve a C for the semester with an average between 70 and 79 inclusive.

To determine the range of scores Brad can achieve on the fourth test to secure a C for the semester, considering an average between 70 and 79 inclusive, we need to find the minimum and maximum possible scores.

Let's denote the score on the fourth test as "x". Since all four tests are equally weighted, we can calculate the average using the sum of all four scores divided by 4:

(83 + 95 + 76 + x) / 4

To obtain a C for the semester with an average between 70 and 79 inclusive, we set up the following inequality:

70 ≤ (83 + 95 + 76 + x) / 4 ≤ 79

Now we solve for the range of scores on the fourth test, "x":

70 ≤ (83 + 95 + 76 + x) / 4 ≤ 79

Multiplying through by 4:

280 ≤ 83 + 95 + 76 + x ≤ 316

Combining like terms:

280 ≤ 254 + x ≤ 316

Subtracting 254 from all sides:

26 ≤ x ≤ 62

Therefore, Brad needs to score between 26 and 62 on the fourth test to achieve a C for the semester with an average between 70 and 79 inclusive.

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The measure of angle ZCBD is 90°. Therefore, the correct option is J. 90.

To find the measure of angle ZCBD, we need to examine the given information.

From the figure, we know that angle CDE is 155°.

Since the opposite angles of a rectangle are congruent, angle BCD is also 155°.

In a rectangle, the sum of the interior angles at a vertex is always 90°.

Therefore, angle CBD is 90°.

Hence, the measure of angle ZCBD is 90°.

Therefore, the correct option is J. 90.

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The amount that will accumulate by the end of the sixth and final payment is approximately $41,666.60.

To calculate the accumulated amount by the end of the sixth and final payment, we can use the future value of an ordinary annuity formula:

Future Value = Payment × Future Value of an Ordinary Annuity Factor

The payment is $5,800, and the interest rate is 9%. Since the payments are made at the end of each year, we can use the future value table for an ordinary annuity at 9%.

Looking up the factor for 6 years at 9% in the future value table, we find it to be 7.169858.

Now we can calculate the accumulated amount:

Future Value = $5,800 × 7.169858 = $41,666.60

Therefore, the amount that will accumulate by the end of the sixth and final payment is approximately $41,666.60. The correct answer is not among the options provided.

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Answer:

Combining like terms

Step-by-step explanation:

Answer: Combing like terms

The answer to the math problem is 76.2 if the r means remainder

Step-by-step explanation: Hope this helps

Thanks for the points:)

Hello!

Answer:

107

Step-by-step explanation:

Hope this helps

Answer:

17

Step-by-step explanation:

d

Answer:

The correct answer is B. In set B, the input of -2 does not correspond to exactly one output.

The series of numbers that meets the requirements is 5+6+8+9+4+6+7+3+9+2+8+9+1.

To verify that the series meets the requirements, we must establish what the requirements are:

To verify that every 3 consecutive numbers add up to 19, we separate them into 4 groups of 3 and one number is left over.

In total there must be 14 numbers and they must add up to 77.

5+6+8+9+4+6+7+3+9+2+8+9+1 = 77

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1)The pdf of U is f(u) = (1/(2√u)) exp(-u/2) for u > 0 and f(u) = 0 otherwise.

2)U follows a gamma-distribution with parameter a = 3/2 or a = 1/2.

3)x = (y²/2) and dx = y dy using exponential distribution

We can rewrite the integral as:

I(1/2) = ∫₀^∞ y exp(-y²) dy

       = 1/2 ∫₀^∞ exp(-u/2) du

This is the same as the integral for f(u) when u = 1/2.

Therefore, we have:

I(1/2) = V1

(1) For U = Z², we can use the method of transformations.

Let g(z) be the transformation function such that

U = g(Z)

   = Z².

Then, the inverse function of g is given by h(u) = ±√u.

Thus, we can apply the transformation theorem as follows:

f(u) = |h'(u)| g(h(u)) f(u)

     = |1/(2√u)| exp(-u/2) for u > 0 f(u) = 0 otherwise

Therefore, the pdf of U is given by:

f(u) = (1/(2√u)) exp(-u/2) for u > 0 and f(u) = 0 otherwise.

(2) We are given that f(1/2) = VT, where V is a constant.

We can substitute u = 1/2 in the pdf of U and equate it to VT.

Then, we get:VT = (1/(2√(1/2))) exp(-1/4)VT

                            = √2 exp(-1/4)

This gives us the value of V.

Now, we can use the pdf of the gamma distribution to find the parameter a such that the gamma distribution matches the pdf of U.

The pdf of the gamma distribution is given by:

f(u) = (u^(a-1) exp(-u)/Γ(a)) for u > 0 where Γ(a) is the gamma function.

We can use the following relation between the gamma and the factorial function to simplify the expression for the gamma function:

Γ(a) = (a-1)!

Thus, we can rewrite the pdf of the gamma distribution as:

f(u) = (u^(a-1) exp(-u)/(a-1)!) for u > 0

We can now equate the pdf of U to the pdf of the gamma distribution and solve for a.

Then, we get:

(1/(2√u)) exp(-u/2) = (u^(a-1) exp(-u)/(a-1)!) for u > 0 a = 3/2

Therefore, U follows a gamma distribution with parameter

a = 3/2 or equivalently,

a = 1/2.

(3) We need to show that I(1/2) = V1.

Here, I(1) = ∫₀^∞ exp(-x) dx is the integral of the exponential distribution with rate parameter 1 and V is a constant.

We can use the change of variables y = √(2x) to simplify the expression for I(1/2) as follows:

I(1/2) = ∫₀^∞ exp(-√(2x)) dx

Now, we can substitute y²/2 = x to obtain:

x = (y²/2) and

dx = y dy

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The total amount of money in Ms. Jones' account at the end of the twentieth year is $139,379.51.

Ms. Jones deposited $400 at the end of each month for 20 years into a savings account earning 3% interest compounded monthly.

However, she deposited an additional $1000 at the end of the tenth year. The total amount of money in her account at the end of the twentieth year is calculated as follows:

1. First, determine the monthly interest rate:3% annual interest rate/12 months in a year = 0.25% monthly interest rate

2. Next, determine the total number of monthly deposits:20 years x 12 months/year = 240 total monthly deposits

3. Determine the future value of the monthly deposits:We will use the formula for the future value of an annuity with a formula FV = PMT x [(1 + r)n - 1] / r, where:PMT is the monthly deposit ($400)R is the monthly interest rate (0.25%)n is the total number of monthly deposits (240)FV = $400 x [(1 + 0.0025)^240 - 1] / 0.0025= $137,992.83 (rounded to the nearest cent)

4. Determine the future value of the additional deposit in the tenth year :We will use the formula for the future value of a single amount with a formula FV = PV x (1 + r)n, where:PV is the present value of the deposit ($1000)R is the monthly interest rate (0.25%)n is the number of months in the tenth year from when the deposit was made to the end of the twentieth year (120 months).FV = $1000 x (1 + 0.0025)^120= $1,386.68 (rounded to the nearest cent)

5. Add the future value of the monthly deposits in Step 3 to the future value of the additional deposit in Step 4:$137,992.83 + $1,386.68 = $139,379.51

The total amount of money in Ms. Jones' account at the end of the twentieth year is $139,379.51.

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The values of x, y and z are given as follows:

The Pythagorean Theorem states that in the case of a right triangle, the square of the length of the hypotenuse, which is the longest side,  is equals to the sum of the squares of the lengths of the other two sides.

Hence the equation for the theorem is given as follows:

c² = a² + b².

In which:

Applying the geometric mean theorem, we have that the value of x is given as follows:

x² = 4 x 25

x² = 100

x = 10.

The value of y is given as follows:

y² = 4² + 10²

\(y = \sqrt{4^2 + 10^2}\)

y = 10.77.

The value of z is given as follows:

z² = 10² + 25²

\(z = \sqrt{10^2 + 25^2}\)

z = 26.92.

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The expression that results in an irrational number is option 2 only: 1/2 + square root 2.

To determine which expression results in an irrational number, let's analyze each expression:

-5/8 + 3/5:

The result of this expression can be computed by finding a common denominator, which is 40. The expression simplifies to (-25 + 24) / 40 = -1/40. This is a rational number, not an irrational number.

1/2 + square root 2:

The expression involves adding a rational number (1/2) to an irrational number (square root 2). When adding a rational and an irrational number, the result is always an irrational number. Therefore, this expression results in an irrational number.

(Square root 5) x (square root 5):

The expression simplifies to 5, which is a rational number, not an irrational number.

3 x (square root 49):

The square root of 49 is 7. Therefore, the expression simplifies to 3 x 7 = 21, which is a rational number, not an irrational number.

Based on the analysis above, the expression that results in an irrational number is:

1/2 + square root 2.

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Answer:

The answer is x = \(\frac{-5}{3}\).

Step-by-step explanation:

First, we expand the brackets. Therefore:

\(2x+6 = -4x+(-4)\)

\(2x+6 = -4x -4\)

Then, we separate the like terms:

\(2x+4x = -4-6\)

Then we add the like terms up and solve for x:

\(6x = -10\)

Therefore:

\(x = \frac{-10}{6}\)

which, simplified, is:

\(x = \frac{-5}{3}\).

Answer:

6 1/4 and 1 1/4

1 and 1/5

Step-by-step explanation:

These are the only ones I think

\(6\frac{1}{4}\) kilometer:  \(1\frac{1}{4}\) minutes and 1 kilometer: 1/5 minutes has unit rate as 5.

A ratio is an ordered pair of numbers a and b, written a / b where b does not equal 0.

The given, ratios are:

4/5 km : 5 minutes

\(3\frac{1}{10}\) km: 3/10 minutes

1 kilometer: 1/5 minutes

1/3 kilometer: \(1\frac{2}{3}\) minutes

\(4\frac{1}{2}\) kilometer: 2 minutes

\(6\frac{1}{4}\) kilometer:  \(1\frac{1}{4}\) minutes

We need to check which ratios have 5 as unit rate.

\(6\frac{1}{4}\) kilometer:  \(1\frac{1}{4}\) minutes has unit rate as 5

25/4/5/4

5

1 kilometer: 1/5 minutes

5

Hence, \(6\frac{1}{4}\) kilometer:  \(1\frac{1}{4}\) minutes and 1 kilometer: 1/5 minutes has unit rate as 5.

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Answer:

C is the answer

Step-by-step explanation:

The distance from the point (4, 0, 0) to the plane -2x + 2y - 5z = 3 is approximately 1.85 units.

To find the distance from a point to a plane, we can use the formula:

distance = \(|ax + by + cz + d| / sqrt(a^2 + b^2 + c^2)\)
where (a, b, c) is the normal vector of the plane, d is the constant term in the plane equation, and (x, y, z) is any point on the plane.

First, we need to find the normal vector of the plane -2x + 2y - 5z = 3. The coefficients of x, y, and z in the plane equation give us the normal vector (-2, 2, -5).

Next, we can choose the point (4, 0, 0) as our point outside the plane. Substituting the coordinates into the plane equation, we get:
-2(4) + 2(0) - 5(0) = -8
So d = -8.

Now we can plug in the values into the distance formula:
distance = \(|(-2)(4) + (2)(0) - 5(0) + (-8)| / sqrt((-2)^2 + 2^2 + (-5)^2) = 10 / sqrt(29)\)

Therefore, the distance from the point to the plane is approximately 1.85 units.

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Answer:

The addition problem is the equation of which you have to solve. The sum is the answer to that problem...

Answer:

an addition problem is an entire equation, the blueprint of something. it shows how you got your answer and what you had to do to find it. a sum is like the final product, you use the blueprints (the problem) to get the house (the sum) the sum is the result of everything you did to work out the problem

Answer:

A) 200 students

B) 24

C) 46%

D) 46% are driven by car

Step-by-step explanation:

To sketch and describe the locus of points in a plane in the interior of a right triangle with sides of 6 in., 8 in., and 10 in. and at a distance of 1 in. from the triangle, we need to first understand what a locus of points is.

A locus of points refers to the set of points that satisfy a given condition.
In this case, the given condition is that the points must be located at a distance of 1 in. from the right triangle with sides of 6 in., 8 in., and 10 in. To visualize this, we can imagine a circle with a radius of 1 in. drawn around each of the three vertices of the triangle.
The locus of points that we are interested in is the region that is enclosed by these three circles. This is because any point that is located within all three circles is at a distance of 1 in. from each of the three sides of the right triangle.
We can see that this region takes the shape of a smaller triangle that is located in the interior of the original right triangle. This smaller triangle has sides that are each 2 in. shorter than the corresponding sides of the original triangle.
To summarize, the locus of points in a plane in the interior of a right triangle with sides of 6 in., 8 in., and 10 in. and at a distance of 1 in. from the triangle is a smaller triangle that is located in the interior of the original triangle. This smaller triangle has sides that are each 2 in. shorter than the corresponding sides of the original triangle.

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Answer:

D is correct.

Step-by-step explanation:

\(3 |x + 1| < 6\)

\( |x + 1| < 2\)

\( - 2 < x + 1 < 2\)

\( - 3 < x < 1\)

x > 3 and x < 1, so D is correct.

The probability that the flight would be delayed when it is not raining is 12.46%.

Probability is a branch of math which deals with finding out the likelihood of the occurrence of an event. Probability measures the chance of an event happening and is equal to the number of favorable events divided by the total number of events. The value of probability ranges between 0 and 1, where 0 denotes uncertainty and 1 denotes certainty.

To determine what is the probability that the flight would be delayed when it is not raining, the following calculation must be performed:

Probability that it will not rain = 1 - probability that it will rain

X = 1 - 0.11

X = 0.89

Probability that the flight would be delayed when it is not raining = probability that it is not raining x probability that the flight will be delayed

X = 0.89 x 0.14

X = 0.1246

0.1246 x 100 = 12.46

Therefore, the probability that the flight would be delayed when it is not raining is 12.46%.

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