Which inequality is different
X is no more than 12
X is at most 12
X is no less than 12
X is less than or equal to 12

Let the amount of Tilapia bought be "t" and the amount of Salmon bought be "s"

Since Tilapia costs $3 per pound and Salmon costs $5 per pound, we can say:

Cost of Tilapia = 3t

Cost of Salmon = 5s

Their total cost = 3t + 5s

This total cost should be equal to the total budget, which is $210.

We can equate and write:

Answer:

planet of the apes?

a. The composite scores for each location are as follows: Location A: 84.34, Location B: 81.05, Location C: 82.63 (b)  Based on the composite scores, Location A should be chosen for the clothing store.

To determine the composite score for each location, we need to calculate the weighted sum of the factor ratings.

a. The composite score for each location is calculated as follows:

Location A:

Composite score = (Convenience of access * Weight) + (Parking facility * Weight) + (Frontage * Weight) + (Shopper traffic * Weight) + (Operating cost * Weight) + (Neighbourhood * Weight)

Composite score = (0.10 * 92) + (0.15 * 91) + (0.19 * 96) + (0.31 * 79) + (0.10 * 70) + (0.15 * 69)

Composite score = 84.34

Location B:

Composite score = (0.10 * 70) + (0.15 * 73) + (0.19 * 89) + (0.31 * 95) + (0.10 * 95) + (0.15 * 81)

Composite score = 81.05

Location C:

Composite score = (0.10 * 72) + (0.15 * 75) + (0.19 * 74) + (0.31 * 80) + (0.10 * 92) + (0.15 * 96)

Composite score = 82.63

b. Based on the composite scores, we can see that Location A has the highest score of 84.34, followed by Location C with a score of 82.63, and Location B with a score of 81.05. Therefore, Location A should be chosen for the clothing store.

After calculating the composite scores for each location based on the factor ratings and weights, it is determined that Location A has the highest composite score and should be chosen for the clothing store.

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The perimeter of the square is 70.8 meters.

To find the perimeter of a square, we need to know either the length of one side or the area of the square. In this case, we are given the area of the square as 313.29 m².

The formula for the area of a square is:

Area = side length²

We can rearrange this formula to solve for the side length:

Side length = √Area

Substituting the given area into the formula, we have:

Side length = √313.29 m²

Calculating the square root of 313.29, we find that the side length of the square is approximately 17.7 meters (rounded to one decimal place).

Since a square has four equal sides, the perimeter is simply four times the side length:

Perimeter = 4 * 17.7 m = 70.8 meters

As a result, the square's circumference is 70.8 metres.

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The quantity of turnips that Gabrielle bought would be = 17 5/8 pounds

The weight of an object is defined as the quantity of matter that is contained in that object which is usually measured in pounds.

The weight of a bag of parsnips (X )= 3 3/4 pounds

The weight of a bag of turnips = 4 7/10 (X)

Therefore the quantity of turnips that she bought is calculated as follows:

4 7/10 × 3 3/4

Change the above mixed fractions to a single fraction.

= 47/10 × 15/4

= 705/40

= 17 5/8 pounds.

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Answer:

17.6

Step-by-step explanation:

Answer:

80 pennies ; 160 nickels

Step-by-step explanation:

Given the 2 equations

0.01p + 0.05n = 8.80 → (1)

n = 2p → (2)

Substitute n = 2p into (1)

0.01p + 0.05(2p) = 8.80

0.01p + 0.1p = 8.80

0.11p = 8.80 ( divide both sides by 0.11 )

p = 80

Substitute p = 80 into (2)

n = 2 × 80 = 160

There are 80 pennies ; 160 nickels

The distance traveled over 9 hours at a speed of 840 km/h is 7,560 km.

Speed can be thought of as the rate at which an object covers distance.

A fast-moving object has a high speed and covers a relatively large distance in a given amount of time, while a slow

moving object covers a relatively small amount of distance in the same amount of time.

To calculate the distance traveled over 9 hours at a speed of 840 km/h, follow these steps:

1. Identify the time and speed given in the student question: 9 hours and 840 km/h.

2. Use the formula for distance:

distance = speed × time.

3. Plug in the values:

distance = 840 km/h × 9 hours.

4. Calculate the distance:

distance = 7,560 km.

So, the distance traveled over 9 hours at a speed of 840 km/h is 7,560 km.

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Answer:

The fraction that represents the addition model shown above will be 53/100.How to solve the fraction?From the information given, a grid with 10 equal columns is shown with 5 shaded in. This will be expressed as 5/10.Also, a second grid is shown, identical in size, containing 100 squares with 3 shaded in. This will be expressed as 3/100.Therefore, the problem that represents the addition model shown above will be:= 5/10 + 3/100= 50/100 + 3/100= 53/100In this case, the answer given by Emma is incorrect as he added 5 to 3 and got 8/100.

Step-by-step explanation:

Answer: x = 12

Step-by-step explanation:

9 + (x/4) = 12

x/4 = 3

x = 12

Answer:

In the small cuboid

length=4cm

breadth=2 cm

height=7-5=2 cm

Volume=l×b×h

Or, V=4×2×2

or, V=16cm^3

Also,

In the big cuboid

length=6cm

breadth=4 cm

height=5 cm

Volume=l×b×h

Or, V=6×4×5

or, V=120cm^3

Total volume=16cm^3+120cm^3

or, Total volume=136cm^3

Answer:

(x+5)(x-11)=0

Step-by-step explanation:

x^2-6x-55=0

[Multiply the coefficient of last and first, (55*1=55) and find such a factor of it such that its product is equal to the product of coefficient of last and first and such that it adds or subtracts(11-5=6)(depending on the sign of last coefficient) up to the coefficient of middle term]

x^2-11x+5x-55=0

x(x-11)+5(x-11)=0

(x+5)(x-11)=0

There is sufficient evidence to believe that the number of household pets leaving the shelter over the weekend is different from the proportion of wildlife animals leaving the shelter over the weekend.

To determine if there's sufficient evidence,

Let us define the null and alternative hypotheses for this test as follows:

Null hypothesis (H0): The proportion of household pets leaving the shelter over the weekend is the same as the proportion of wildlife animals leaving the shelter over the weekend.

Alternative hypothesis (Ha): The proportion of household pets leaving the shelter over the weekend is different from the proportion of wildlife animals leaving the shelter over the weekend.

The test statistic for two sample test is given by:

z = (p1 - p2) / sqrt(p * (1 - p) * (1/n1 + 1/n2))

where

p1 and p2 are the proportions of household pets and wildlife animals leaving the shelter over the weekend, respectively,

p is the pooled proportion,

n1 and n2 are the sample sizes for household pets and wildlife animals, respectively.

Pooled proportion is

p = (x1 + x2) / (n1 + n2)

where x1 and x2 are the number of household pets and wildlife animals leaving the shelter over the weekend, respectively.

Given

-n1 = 376, n2 = 52, x1 = 29, x2 = 10

p = (29 + 10) / (376 + 52) = 0.091

The observed proportions are:

p1 = x1 / n1 = 29 / 376 = 0.0771

p2 = x2 / n2 = 10 / 52 = 0.1923

The test statistic value

z = (0.0771 - 0.1923) / sqrt(0.091 * (1 - 0.091) * (1/376 + 1/52)) = -3.04

By using a standard normal distribution table,

The p-value is 0.00238.

Since the p-value (0.00238) is less than the level of significance (0.01), we reject the null hypothesis and conclude that there is sufficient evidence to indicate a difference in the number of animals leaving the shelter over the weekend for household pets and wildlife animals.

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In this scenario, we are given three functions: f, g, and h, where the input and output for each function are natural numbers. Additionally, we are given the condition that f(n) < g(n) < h(n) for all natural numbers n.

The objective is to determine the relationship between the three functions based on this condition.Based on the given condition, we can conclude that the output of function g is greater than the output of function f for all natural numbers. Similarly, the output of function h is greater than the output of function g for all natural numbers. This implies that the functions f, g, and h are ordered in increasing order.

In other words, for any input value n, the value of f(n) is the smallest, followed by g(n), and then h(n) is the largest. This order is maintained consistently for all natural numbers. This information allows us to establish the relative magnitudes of the outputs of the three functions and the overall ordering of the functions themselves.

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Answer:

d = 1.4 t + 30

Step-by-step explanation:

Head start means any advantage achieved or advantage gained in any race or competition.

In the context, the runner is gained a head start of 30 meter from the starting point.

It is also given that the speed with which the runner is running is 5.0 km per hour.

Therefore, the equation that gives the distance covered by the runner from his start line at any time in seconds is given by d = 1.4 t + 30.

answer:

-13/12

Step-by-step explanation:

use the formula to find slope using points

it is: y2-y1/x2-x1

plug in point values into formula

-3 = x1. 9 = x2

-2= y1. -15 = y2

-15-(-2)/ 9-(-3)

-13/12

Answer:

m= -13/12

Explanation:

formula to solve: x1-y1

                            x2-y2

According to formed equations, the price of one teddy bear and one doll is $7 and $20 respectively.

Let us represent the teddy bear as x and dolls as y. Now, framing the equation for Dolly and Gwinnett.

Cost of teddy bear × number + cost of dolls × number = total expenditure

14x + 3y = 158 : equation 1

8x + 12y = 296 : equation 2

Divide the equation by 4

2x + 3y = 74 : equation 3

Subtraction equation 3 from equation 1

14x + 3y = 158

- 2x + 3y = 74

12x = 84

x = 84/12

x = $7

So, the cost of teddy bear = $7

keep the value of x in equation 3 to find the cost of y

2×7 + 3y = 74

14 + 3y = 74

3y = 74 - 14

3y = 60

y = 60/3

y = $20

Thus, the cost of teddy bear and dolls are $7 and $20.

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Answer:

vertical angle = 2 and 3

supplementary angle = 2 and 4

hope it helps

Answer:

Vertical is like 1 and 4. Supplementary is like 1 and 3.

The described experiment design is a randomized controlled trial (RCT) with a double-blind setup, where participants with chronic pain are randomly assigned to receive either the new pain relief medicine or a placebo, and the order of the treatments is also randomly assigned.

In an RCT, participants are randomly assigned to different groups to receive different interventions or treatments.

In this case, the volunteers with chronic pain are randomly assigned to two groups: one group receives the new pain relief medicine for a 2-week period, followed by a placebo for another 2-week period, while the other group receives the placebo first and then the pain relief medicine.

The random assignment helps minimize selection bias and ensures that any differences observed between the groups can be attributed to the treatments rather than other factors.

Furthermore, the fact that the participants do not know which pill they are taking adds a double-blind element to the experiment. This means that neither the participants nor the researchers assessing the outcomes are aware of the treatment assignment, reducing potential bias in reporting pain levels.

By measuring the difference in overall pain level before and after each treatment period, the researchers can evaluate the effectiveness of the new pain relief medicine compared to the placebo. This design allows for a direct comparison of the outcomes between the two groups, providing valuable evidence on the efficacy of the medication.

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When a correlation is computed while statistically controlling for a third variable, this is called a partial correlation.

Partial correlation is a statistical technique used to measure the strength and direction of the relationship between two variables while controlling for the influence of a third variable.

It allows us to examine the unique relationship between two variables, independent of the third variable's effects.

To compute a partial correlation, you need to use statistical software that offers this functionality.

The process involves calculating the correlation coefficient between the two variables of interest, while simultaneously controlling for the effects of the third variable.

This is typically done by including the third variable as a control variable in the analysis.

A partial correlation is the term used to describe the computation of a correlation while controlling for a third variable.

It helps researchers understand the relationship between two variables while accounting for the influence of additional factors.

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Answer:Objective: Solve systems of equations with three variables using addition/elimination.

Solving systems of equations with 3 variables is very similar to how we solve systems with two variables. When we had two variables we reduced the system down

to one with only one variable (by substitution or addition). With three variables

we will reduce the system down to one with two variables (usually by addition),

which we can then solve by either addition or substitution.

To reduce from three variables down to two it is very important to keep the work

organized. We will use addition with two equations to eliminate one variable.

This new equation we will call (A). Then we will use a different pair of equations

and use addition to eliminate the same variable. This second new equation we

will call (B). Once we have done this we will have two equations (A) and (B)

with the same two variables that we can solve u

Step-by-step explanation:

sorry my answer was wrong

The phase that is not a part of the planning process for both statistical and non-statistical sampling is determining the sample size.

Determining the sample size is an essential step in statistical sampling, as it involves calculating the number of observations needed to ensure statistical validity. However, in non-statistical sampling, the focus is on selecting specific cases or items for examination based on subjective criteria, rather than relying on statistical principles or sample size calculations. Instead, non-statistical sampling emphasizes judgment and expert knowledge to choose representative samples. By excluding the determination of sample size, non-statistical sampling allows for greater flexibility and adaptability in the sampling process, enabling a more tailored approach to the specific objectives of the study or investigation.

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Answer:

-29.4

Step-by-step explanation:

(-2.1)(-1.4) - 29.4 - 2.94

2.94 - 29.4 - 2.94

          -29.4

Answer:

7 times 1/5

Step-by-step explanation:

Answer:

92% of Income is  Rs 18400

Step-by-step explanation:

I = 18400/.92 = Rs 20000

Answer: 1,176 miles

Step-by-step explanation:

490 / 5 = 98 miles

98 mph X 12 hours is 1,176

The elements of the arithmetic sequences of the first part are:

The general terms of the arithmetic sequences of the second part are:

Arithmethic sequences are sequences whose elements are generated linear equations of the form:

y = a + b · n, n ≥ 0         (1)

Where:

In the first part we need to calculate the first five elements for six sequences:

The second part consists in finding the general term of the arithmetic sequence, that is, looking for the formula that generates all elements:

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The factored expression to the expression is (4y + 1)(y + 6)

From the question, we have the following parameters that can be used in our computation:

4 y2 + 25 y + 6

Express properly

So, we have the following representation

4y² + 25 y + 6

Expand the expression

This gives

4y² + 24y + y + 6

Next, we factor the expression

4y(y + 6) + 1(y + 6)

Factor out y + 6

(4y + 1)(y + 6)

Hence, the solution is (4y + 1)(y + 6)

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Answer:

Step-by-step explanation:

First, find the circumference

4.6 * \(\pi\) =14.4513

Then set up a proportion to find how far the wheel turns in the given angle let x be the distance the wheel has rolled

\(\frac{14.4513}{360} =\frac{x}{337}\)

solve for x

x=13.528

Round to nearest tenth

13.5

Answer:

p/2

Step-by-step explanation:

Written as a fraction, p/2 is the same as p divided by 2.

To determine which option gives a better chance of winning, we need to calculate the expected number of A's and B's in the 1,000 draws and compare it to the conditions for winning in each option.

Let's calculate the expected number of A's and B's:

Number of A's in "ARABIA": 3

Number of B's in "ARABIA": 1

Total number of letters in "ARABIA": 6

Probability of drawing an A: 3/6 = 1/2

Probability of drawing a B: 1/6

Expected number of A's in 1,000 draws: (1/2) * 1,000 = 500

Expected number of B's in 1,000 draws: (1/6) * 1,000 = 166.67

Now let's analyze the conditions for winning in each option:

Option A: You win a dollar if the number of A's among the draws is 10 or more above the expected number (500 + 10 = 510 or more).

Option B: You win a dollar if the number of B's among the draws is 10 or more above the expected number (166.67 + 10 = 176.67 or more).

Comparing the two options:

Option A requires having 510 or more A's out of the 1,000 draws.

Option B requires having 176.67 or more B's out of the 1,000 draws.

Since it is not possible to have a fraction of a letter, the number of B's will always be an integer. Therefore, it is impossible to reach the condition for winning in option B, as there can't be 176.67 B's.

Therefore, the correct answer is:

(i) Option A gives a better chance of winning than option B.

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