which has the higher frequency, red light or blue light?

A worker bee weighs 1*10-4 kg. One hive has 4 * 10 4 worker bees.

A worker honeybee's weight has been estimated to be between 115 and 128 mg [17, 3]. With a median value of 85 g and a 95% percentile of 249 g, BC depth varied (Figure 5 top).

Male mature African elephants can weigh between 1,800 and 6,300 kg (2 and 7 tons/4,000 and 14,000 lb), making them the largest land creatures. Females weigh between 2,700 and 3,600 kilogrammes (3 and 4 tons/6,000 and 8,000 lb), making them lighter than males. Three to four metres (9.8 and 14.2 feet) between the shoulder blades.

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the independent variable and the dependent variable.

The amount of space a wave covers in a certain amount of time, such as the number of meters it covers in a second, is known as its speed of wave.

The formula Speed = Wavelength x Frequency relates wave speed to both wavelength and wave frequency. The formula wave speed = frequency x wavelength relates wave speed to wavelength, frequency, and period. The speed of light, or roughly 300,000 kilometers per second, is the absolute speed limit at which a wave can move according to Einstein's theory of special relativity. A change in the medium is truly necessary to modify the wave's speed since the wave's speed is a feature of the medium. The wave speed is constant if the medium does not alter during the wave's motion.

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When a problem's variables further depend on other variables like time, related rates are used.

The Equation of Ohm's Law: V = IR, where V is the voltage that is applied across the conductor, I is the current that is passing through the conductor, and R is the conductor's resistance to the current flow.

The chain rule can be used to relate the rate of change of z with respect to t to the rates of x and y with respect to t when Z=f(x, y) and the variables x and y themselves depend on the variable t.

When all other rates and variables are known, we can use these relations to determine the rate of any one variable.

Take note that when the variable z changes with respect to t, we get dz/dt0, and when z changes with respect to t, we get dz/dt>0.

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False. X-ray bursters are not similar to novae. They are phenomena that occur in binary systems containing a neutron star and a low-mass star. In these systems, the neutron star attracts material from its companion, and this material accumulates on its surface.

When enough material accumulates, it ignites and releases a burst of X-rays. This process is cyclical and can occur every few hours to every few weeks.

On the other hand, novae are phenomena that occur in binary systems containing a white dwarf and a companion star. In these systems, the white dwarf attracts material from its companion, and this material accumulates on its surface.

When enough material accumulates, it ignites in a thermonuclear explosion that causes a sudden increase in brightness. This process is also cyclical and can occur every few decades to every few centuries.

Therefore, it can be concluded that x-ray bursters are not similar to novae, and the collapsed star in x-ray bursters is a neutron star, not a white dwarf.

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In the first scenario, the energy would be conserved in the system of the girl-wall, The correct answer is option c

In the second scenario, the energy would be conserved in the system of the person-trampoline-earth, The correct answer is option c

In the third scenario, the energy would be conserved in the system of the box-ramp-earth, The correct answer is option a

In the fourth scenario, in a realistic scenario, the energy would not be conserved in any of the given systems due to external work done on the system. The correct answer is option e

For the first scenario of a person wearing roller skates, assuming there is no external work done on the system, the system of the girl-wall would be the appropriate system to consider. The energy would not be conserved in any other system, as there would be external work done on the system due to forces acting on the girl, wall, or both. Therefore option c is correct.

For the second scenario of a person jumping on a trampoline, assuming there is no external work done on the system, the appropriate system to consider would be the system of the person-trampoline-earth, as the energy would be conserved within this closed system.

None of the other systems would conserve energy, as external work would be done on the system due to the forces acting on the person, trampoline, and/or Earth. Therefore option c is correct.

For the third scenario of pushing a box up a ramp, assuming there is no external work done on the system, the appropriate system to consider would be the system of the box-ramp-earth, as the energy would be conserved within this closed system.

None of the other systems would conserve energy, as external work would be done on the system due to the forces acting on the box, ramp, and/or Earth. Therefore option a is correct.

For the fourth scenario of two cars colliding and coming to a stop, it is important to note that in a realistic scenario, there would be external work done on the system due to forces such as friction, air resistance, and deformation of the cars.

Therefore, the energy would not be conserved in any of the given systems. However, if the scenario were simplified to only consider idealized, perfectly elastic collisions in a vacuum, then the system of both cars would conserve energy. Therefore option e is correct.

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Answer:

F = K Q1 Q2 / R^2       where K = 9 * 10E9  (1 / 4 pi ∈0)

F = 9.00E9 * (4.6E-16)^2 / .01 = 1.90E-19 N

Answer:

The strength of gravity decreases.

An example of that would be if you were in space; you float around because there's no gravity.

According to Maxwell's equations, the speed of light in a vacuum is approximately 299,792,458 m/s.

Maxwell's equations are a set of four equations that describe the behavior of electric and magnetic fields. One of the equations, known as the Ampere-Maxwell equation, relates the speed of light in a vacuum to the electric and magnetic fields. According to Maxwell's equations, the speed of light in a vacuum is determined by the relationship between the electric constant (ε₀) and the magnetic constant (μ₀). The equation is: c = 1 / √(ε₀μ₀)
Where c represents the speed of light in a vacuum. When you plug in the values for ε₀ and μ₀, you find that the speed of light in a vacuum is approximately:
c ≈ 299,792,458 meters per second (m/s)

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The inductance of the inductor is 169Ω and the energy in the inductor is 1.48 x 10⁻³ J.

The resistance of the resistor is 13.7K and the ideal battery has EMF 73.0 V. So, the initial current in the circuit will be,

I = 73/13700

I = 5.3 mA.

The current reaches 2.95 mA after 5.46 mA.

(a). The inductance in the coil can be given by,

E = LΔI/Δt

L is the inductance and E is the EMF, So, Putting values,

73 = L(2.35)/5.46

L = 169Ω.

(b) The energy in the inductor when current is 2.95 mA,

E = 1/2LI²

Putting values,

E = 1/2 x 169 x 2.95 x 2.95 x 10⁻⁶

E = 1.48 x 10⁻³ J.

So, energy in the inductor is 1.48 x 10⁻³ J.

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The initial velocity vector of the ball is;= 25·i + 19.6·j.The falling ball's velocity as a function of time is v = -9.8 (m/s2) t j, and its location as a function of time is r = (4.9 m - 12 9.8 (m/s2) t2) j.

The parameters listed are;The ball's flight time was 4 seconds.The ball is caught 100 meters away from the plate in the horizontal direction.

Assuming that "u" stands for the initial velocity, we have;

100 m is equal to u cos(t) = u cos(4s)

u = cos() / 2 = 25 m/s (1)

∴tan() = 1.568/2 = 0.784 = arctan(0.784) 38.096°. 2usin() =

9.8 m/s2 4 s = 39.2 m/s

The ball's velocity vector's direction is 38.096°.

Equation (1) gives us u cos() = 25 m/s.

31.7672787629 m/s is equal to u = 25 m/s/cos()

= 25 m/s/cos(arctan(0.784))

The initial velocity vector's magnitude is u = 31.7672787629 m/s.

The initial velocity's vertical component is equal to u sin() = 31.7672787629 sin(arctan(0.784)).

Since the ball's starting velocity vector is approximately 31.767 m/s in a direction 38.096° above the horizontal, we can calculate the following:

u = ux(i,j) = 25(i,j) + 19.6(j)

= 25·i + 19.6·j

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Answer:

LOL Diagrams

a way to represent how the energy is stored in the chosen system during various snapshots and to represent any changes in total energy for the system. Each “L” represents how the energy is stored during a particular snapshot (instant). The “O” shows the objects inside and outside the system.

By definition of acceleration, we know that

Acceleration, a = Change in velocity / Time Taken

= (Final velocity – Initial velocity) / Time

= v-u/t

\({\huge{\fcolorbox{yellow}{red}{\orange{\boxed{\boxed{\boxed{\boxed{\underbrace{\overbrace{\mathfrak{\pink{\fcolorbox{green}{blue}{Answer}}}}}}}}}}}}}\)

acceleration = a

initial velocity = u

final velocity = v

time = t

\( \sf t_1 = time \: of \: initial \: velocity \\ \sf t_2 = time \: of \: final \: velocity\)

As we know

\( \sf \red {a = \frac{v - u}{t_2 - t_1} }\)

so further

\( \sf a = \frac{v - u}{t} \\ \\ \sf at = v - u \\ \\ \sf v = u + at\)

If we will make a velocity-time graph we will observe a linear curve

as shown in attachment

The magnitude of the acceleration of the 5kg crate is 11.69 m/s^2. This means that the crate is accelerating towards the south-east direction with a magnitude of 11.69 m/s^2 due to the net force acting on it.

To find the magnitude of the acceleration, we need to calculate the net force acting on the crate and then use Newton's second law of motion (F=ma) to solve for the acceleration.

First, we need to resolve the two forces into their horizontal and vertical components. The 60N force to the north has no horizontal component, so its vertical component is 60N. The 8N force to the west has no vertical component, so its horizontal component is 8N.

Next, we need to add the horizontal and vertical components of the forces separately to get the net force acting on the crate. The vertical component of the net force is the sum of the vertical components of the two forces, which is:

60N - 0 = 60N (upwards)

The horizontal component of the net force is the sum of the horizontal components of the two forces, which is:

0 - 8N = -8N (to the left)

So the net force acting on the crate has a magnitude of:

|Fnet| = sqrt((60N)^2 + (-8N)^2) = 60.8N

Now we can use Newton's second law of motion to solve for the acceleration:

Fnet = ma

a = Fnet/m = 60.8N/5kg = 11.69 m/s^2 (to the south-east)

The magnitude of the acceleration of the 5kg crate is 11.69 m/s^2. This means that the crate is accelerating towards the south-east direction with a magnitude of 11.69 m/s^2 due to the net force acting on it.

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Stars form from molecular clouds through a process known as stellar formation.

These clouds, characterized by low temperatures and high densities, provide the ideal conditions for atoms to combine and form molecules. With a mass range spanning from a few solar masses to millions of solar masses, molecular clouds serve as the birthplaces of new stars. The Pleiades cluster serves as a notable example of stars that have recently formed within such a stellar nursery.

The formation of stars from molecular clouds involves several key steps. Firstly, gravitational forces acting on regions of higher density within the cloud cause them to collapse under their own gravity. As the cloud collapses, it begins to fragment into smaller, denser clumps called protostellar cores. These cores continue to collapse, and their central regions become increasingly dense and hot. At this stage, they are known as protostars.

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The energy of the characteristic x-ray emitted from a tungsten target 1.36*10³ eV.

The energy of a characteristic x-ray emitted from a tungsten target when an electron drops from an M shell (n=3 state) to a vacancy in the K shell (n=1 state) can be estimated using the equation E =hcZ²Δn²/n². Here Z is the atomic number for tungsten (Z=74) and Δn is the difference between n1, the initial orbital, and n2, the final orbital, (n1 - n2). In this case n1= 3 and n2= 1 giving (3-1=2).

Using the equation E =(hc*74²*2²)/1² = (6.63*10-34*.993*17576)/1= 1.36*10³ eV. Therefore, the estimated energy of the characteristic x-ray emitted from the tungsten target when an electron drops from the M shell (n=3) to a vacancy in the K shell (n=1) is approximately 1.36*10³ eV.

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Answer:

Given,

Object distance, u=25cm

Focal length, f=20cm

From mirror formula

f

1

​

=

v

1

​

+

u

1

​

−20

1

​

=

v

1

​

−

25

1

​

⇒

v

1

​

=−

20

1

​

+

25

1

​

v=100cm

The image will be real, inverted magnified

Explanation:

Given,

Object distance, u=25cm

Focal length, f=20cm

From mirror formula

f

1

​

=

v

1

​

+

u

1

​

−20

1

​

=

v

1

​

−

25

1

​

⇒

v

1

​

=−

20

1

​

+

25

1

​

v=100cm

The image will be real, inverted magnified

Answer:

The unit that is a radical among the options is;

a. NH₄⁺

Explanation:

A radical is an atom, group of atoms molecule or ion that contains an electron that is unpaired. The presence of the unpaired electrons make radical very reactive as such most radicals enter into reactions with other species or with themselves to form new compounds making them not last long.

Radicals are also known as free radicals. Examples of radicals includes; Ammonium ion, NH₄⁺

Nitrate ion NO₃⁻ (From a salt)

Hydroxide ion OH⁻ (From a base)

Sulphate ion SO₄²⁺ (From an acid)

All of which are formed in aqueous solution of acids, salts and bases.

Explanation:

It is given that,

Initial position of the person is 2 m and final position is 25 m

The trip takes 4.5 seconds

Person's average velocity is equal to the displacement divided by time.

Displacement = final position-initial position

D = 25 m - 2 m

D = 23 m

Average velocity = \(\dfrac{23}{4.5}=5.12\ m/s\)

Distance covered = 25 m + 2 m = 27 m

Average speed = \(\dfrac{27}{4.5}=6\ m/s\)

Hence, this is the required solution.

You would need to cycle 1 hour 50 minute  to work for 200 g chips.

Energy is measured in calories. Calories in nutrition relate to the energy that humans obtain from the food and liquids they consume as well as the energy they expend when engaging in physical activity.

On every food package, the nutritional information includes a list of calories.

200 grams of potato chips have 1074 calories.

Calorie burn on 30 minute Cycling is   298 calories.

So, to burn 1074 calories, you have to cycle = (1074 ÷ 293) × 30 minute

= 110 minute

= 1 hour 50 minute.

Hence,  you would need to cycle 1 hour 50 minute  to work for 200 g chips.

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Answer:

The best glasses have a wider bowl than rim to allow for proper swirling. The swirl releases volatile aroma compounds and creates a vortex in the center of the glass towards which these compounds are drawn

Explanation:\\\

Answer: To find the isentropic efficiency of the compressor, we can use the specific entropy values at the inlet and outlet states to calculate the ideal or isentropic work, and then compare it to the actual work output of the compressor. The isentropic efficiency is defined as the ratio of the actual work output to the ideal work output.

First, we need to determine the thermodynamic properties of refrigerant 134a at the inlet and outlet states. We can use a refrigerant table to find the specific entropy values at the given pressures and temperatures.

At the inlet state of 100 kPa and 0°C, the specific entropy of refrigerant 134a is s1 = 0.3475 kJ/kg·K.

At the outlet state of 400 kPa and 80°C, the specific entropy of refrigerant 134a is s2 = 1.1086 kJ/kg·K.

The mass flow rate of refrigerant is 0.2 kg/s.

Next, we can calculate the ideal or isentropic work using the specific entropy values at the inlet and outlet states:

h1 = hf1 + x1 * (hg1 - hf1)

h1 = 15.5 + 0.0 * (143.9 - 15.5) = 15.5 kJ/kg

h2s = hf2 + x2 * (hg2 - hf2)

h2s = 177.2 + 0.0 * (509.6 - 177.2) = 177.2 kJ/kg

isentropic work = m_dot * (h1 - h2s)

isentropic work = 0.2 * (15.5 - 177.2) = -32.34 kW

Note that the isentropic work is negative because energy is being added to the refrigerant by the compressor.

Finally, we can calculate the actual work output of the compressor using the same equation, but with the actual specific enthalpy value at the outlet state:

h2 = hf2 + x2 * (hg2 - hf2)

h2 = 177.2 + 1.0 * (509.6 - 177.2) = 509.6 kJ/kg

actual work = m_dot * (h1 - h2)

actual work = 0.2 * (15.5 - 509.6) = 98.42 kW

Therefore, the isentropic efficiency of the compressor is:

isentropic efficiency = actual work / isentropic work

isentropic efficiency = 98.42 / (-32.34)

isentropic efficiency ≈ -3.04

The negative value for the isentropic efficiency indicates that the compressor is not working properly, since it is producing more work output than the ideal or isentropic work. This could be due to factors such as mechanical inefficiencies, leaks, or incorrect operation. As an efficiency cannot be negative, we can assume that there is an error in the calculation and that the actual work output is less than the ideal work output. In this case, we cannot determine the actual value of the isentropic efficiency.

Answer:

Explanation:

The oly way we can figure this out is if the boy is pulling the sled at a constant velocity. If not, we need a value for acceleration, and you don't have that here. If the boy is pulling the sled at a constant velocity, then the value for acceleration is 0, making this a really simple problem. I'm going with that, since there is no way to answer you otherwise. If velocity is not constant, please either repost the question or put it in the notes section under the question as it stands. If acceleration is 0, then

F - f = ma becomes

F - f = m(0) which is

F - f = 0 and

F = f which says that the applied force is the same as the frictional force. We need then to find the frictional force, which has an equation of

f = μ\(F_n\) where normal force is the same as the weight of the 2 girls. We will find that, then:

Each girl's mass is different so the normal force/weight equation is

w = (30.0)(9.8) + (40.0)(9.8) to get

w = 290 + 390 and

w = 680. Plug that into the frictional force equation:

f = (.120)(680) so

f = 82N

The 1s peaks for lithium and beryllium different explained by coulumb's law as follow:

According to Coulomb's law, the atomic number and electron configuration of an element determine the strength of attraction or repulsion between electrons and the nucleus.

The 1s peaks for lithium and beryllium are different because they have different atomic numbers and electron configurations.

The 1s peak for lithium is less than that for beryllium because lithium has a lower atomic number and electron configuration than beryllium. The 1s peak for beryllium is greater because beryllium has a higher atomic number and electron configuration than lithium.

Beryllium is more massive than lithium, meaning that its nucleus has a greater positive charge. As a result, the 1s electron of beryllium is more tightly bound to the nucleus than that of lithium. This difference in electron configuration results in a difference in the intensity of the 1s peak for the two elements, with beryllium having a greater 1s peak than lithium.

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Answer:

Mass and kinetic energy have a positive relationship, which means that as mass increases, kinetic energy increases, if all other factors are held constant.

In this state, Kinetic energy is equal to half of the product mass and velocity. SI unit is joules. So it's if the mass is doubled then the kinetic energy also gets doubled.

Answer:

KE = 1/2(m)(v^2)

Explanation:

Answer:

I hope this helps

Explanation:

The correct order of increasing impedance is:

C. PZT, gel, skin, matching layer

Impedance is a measure of the opposition to the flow of sound waves in a medium. It depends on the density and speed of sound in the material. In the given options, the order of increasing impedance can be determined by considering the properties of the materials involved.

PZT (lead zirconate titanate) has a higher impedance than gel, skin, and the matching layer. PZT is a piezoelectric material commonly used in ultrasound transducers and has a higher density and speed of sound, leading to higher impedance.

Gel has a lower impedance compared to PZT but higher impedance than skin and the matching layer. Gel is used as a coupling medium between the transducer and the skin to enhance acoustic coupling and minimize impedance mismatch.

Skin has a lower impedance than both gel and the matching layer. It is the outermost layer and acts as an interface between the transducer and the biological tissue.

The matching layer has the lowest impedance among the given options. It is designed to match the impedance of the PZT to the impedance of the tissue being imaged, facilitating efficient sound transmission.

Therefore, the correct order is C.

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