Which has more potential energy: a baseball held 1 m above the ground or a baseball held 2 m above the ground?

When a pulse encounters a fixed point, such as a wall or a rigid boundary, it undergoes reflection. Reflection occurs when the pulse bounces back upon reaching the fixed point.

During reflection, the pulse experiences a change in direction but retains its original shape and properties. The incident pulse approaches the fixed point and interacts with it. As a result, an equal and opposite pulse is generated and travels back in the opposite direction.

The behavior of the reflected pulse depends on the nature of the incident pulse and the properties of the medium it travels through. If the pulse is inverted (upside-down) before reflection, the reflected pulse will also be inverted. Similarly, if the incident pulse is right-side-up, the reflected pulse will maintain the same orientation.

The reflection process follows the law of reflection, which states that the angle of incidence (the angle between the incident pulse and the normal to the fixed point) is equal to the angle of reflection (the angle between the reflected pulse and the normal). This law ensures that energy and momentum are conserved during the reflection process.

In conclusion, when a pulse encounters a fixed point, it undergoes reflection, resulting in the generation of an equal and opposite pulse traveling in the opposite direction. The reflected pulse retains the same shape and properties as the incident pulse, following the law of reflection.

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Answer:

A ball moving through the air.

Explanation:

The ball has momentum which is a form of kinetic energy.

I don't know if that is correct, but I hope it helps!!!!

To solve this problem, we can use the law of conservation of momentum, which states that the total momentum of a system before a collision is equal to the total momentum of the system after the collision.

The equation for conservation of momentum is:

m1v1 + m2v2 = m1v1' + m2v2'

Where:

m1 = mass of object 1 (2 kg)

v1 = velocity of object 1 before collision (3.5 m/s)

m2 = mass of object 2 (3 kg)

v2 = velocity of object 2 before collision (2.5 m/s)

v1' = velocity of object 1 after collision (unknown)

v2' = velocity of object 2 after collision (5.0 m/s)

Plugging in the given values, we get:

(2 kg)(3.5 m/s) + (3 kg)(2.5 m/s) = (2 kg)(v1') + (3 kg)(5.0 m/s)

Simplifying, we get:

7 + 7.5 = 2v1' + 15

14.5 = 2v1'

v1' = 7.25 m/s

Therefore, the final speed of the 2 kg block after the collision is 7.25 m/s.

answer: the final speed of the 2 kg ball is 0.25 m/s.

explanation:

To solve this problem, we can use the law of conservation of momentum, which states that the total momentum of a system before a collision is equal to the total momentum after the collision.

The momentum of an object is defined as the product of its mass and velocity:

momentum = mass x velocity

So, the total momentum before the collision can be calculated as:

total momentum before = (mass of ball 1 x velocity of ball 1) + (mass of ball 2 x velocity of ball 2)

total momentum before = (2 kg x 3.5 m/s) + (3 kg x 2.5 m/s)

total momentum before = 7 kg m/s + 7.5 kg m/s

total momentum before = 14.5 kg m/s

After the collision, the 3 kg ball moves at 5.0 m/s in its original direction. Let's assume that the 2 kg ball moves at a final velocity of v.

Using the law of conservation of momentum, we can write:

total momentum after = (mass of ball 1 x final velocity of ball 1) + (mass of ball 2 x final velocity of ball 2)

total momentum after = (2 kg x v) + (3 kg x 5.0 m/s)

total momentum after = 2v kg m/s + 15 kg m/s

Since the total momentum before the collision is equal to the total momentum after the collision, we can set these two expressions equal to each other:

total momentum before = total momentum after

14.5 kg m/s = 2v kg m/s + 15 kg m/s

Solving for v, we get:

v = (14.5 kg m/s - 15 kg m/s) / 2 kg

v = -0.25 m/s

Since the final velocity cannot be negative, we know that the 2 kg ball is moving in the opposite direction after the collision. So, we can take the absolute value of v to find the final speed of the ball:

final speed = |v| = |-0.25 m/s| = 0.25 m/s

Therefore, the final speed of the 2 kg ball is 0.25 m/s.

True airspeed is best described as calibrated airspeed corrected for: C. altitude and non-standard temperature.

INS is abbreviation for Inertial Navigation System and it can be defined as a navigation instrument that is designed and developed to make use of motion sensors, a computer, and rotation sensors, in order to continuously calculate by dead reckoning the following parameters about a moving object:

In the Aviation and Engineering filed, true airspeed (TAS) is an important input which is required from an analogue to digital converter (ADC) to allow the Inertial Navigation System (INS) calculate W/V with respect to altitude and non-standard temperature.

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Complete Question:

True airspeed is best described as calibrated airspeed corrected for what?

installation or instrument error.

non-standard temperature.

altitude and non-standard temperature.

Answer:

D!!!!!

Explanation:

A hypothesis is a supposition or proposed explanation made on the basis of limited evidence as a starting point for further investigation.

Answer:

D. An educated guess about the outcome of an experiment.

Explanation:

Hypothesis is an educated guess about the outcome of an experiment.

Hope this helps ;) ❤❤❤

Answer:

Folk dance

Explanation:

hope i helped :)

Answer:

162 should be the answer because 18x3x3=162.

Answer:

Magnets create a field of influence that

attracts or repels magnetic objects.

Explanation:

Hope it helps :)

Answer: The magnet has a magnetic field that either attracts or repels another magnet or magnetic metal. It is because of this magnetic field that things move.

Explanation: N/A

Answer:

5/100 =120=0.05or 5%

Explanation:

I had this same thing this morning

When comparing solids to fluids, the following is true: For elastic solids, stress is linearly related to strain, for non-Newtonian fluids, stress is non-linearly related to strain rate.

In the mechanical sense, solids and fluids are differentiated based on their reaction to applied stresses. Solids can resist external forces of tension, compression, and torsion, and fluids deform continuously under the same conditions.Stress is a measure of how much force is applied to a specific area, while strain is the resulting deformation that occurs under stress. Elastic solids have the property of returning to their original shape when the stress is removed. A solid's behavior under stress is determined by its modulus of elasticity, which determines the linear relationship between stress and strain. A non-Newtonian fluid is a fluid that exhibits non-Newtonian behavior, in which the stress is non-linearly related to strain rate.

Stress is linearly related to strain in elastic solids, while stress is non-linearly related to strain rate in non-Newtonian fluids.

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As long as the applied stress is removed, a material that is linearly elastic experiences stress and strain that are directly proportional within the elastic limit.

In a material that is linearly elastic, the Young's modulus (E), stress, and strain are all related by the equation you supplied, E =. Here is a quick definition of each phrase:

(E) Young's modulus It is a way to gauge how hard or stiff a material is. Within the elastic limit of the material, it indicates the stress to strain ratio. The stiffer the material, the higher the Young's modulus.

Stress (): The force exerted to a material's surface area is called stress. The internal resistance of a material to deformation under an applied force is measured by stress.

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The terminal velocity of the 64 kg and the 93 kg skydiver are 102.85 m/s and 123.983 m/s respectively.

The formula for the terminal velocity of a falling object or person is

V = √(2mg/ρCA), where m is the mass of the object, g is the acceleration due to gravity, ρ is the density of the fluid (air in this case), A is the frontal area, and C is the drag coefficient.

Given: masses of the skydiver, m₁ =64 kg, m₂ = 93 kg.

the altitude of airplane h = 5950 m,

the density of air, ρ = 1.21 kg/m³

Drag coefficient, C = 0.7

Frontal area, A = 0.14 m²

putting all the values in the formula for terminal velocity, we get

V1 =  √(2×64×9.8/(1.21 × 0.7 × 0.14)) = 102.85 m/s

V2= √(2×93×9.8/(1.21 × 0.7 × 0.14)) = 123.983 m/s

Therefore, the terminal velocities of the 64 kg and the 93 kg skydiver are 102.85 m/s and 123.983 m/s respectively.

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The little sister is sitting closer to the fulcrum in the center of the seesaw.

To determine which child is sitting closer to the fulcrum (center) of the seesaw, compare their distances from the fulcrum.

Assume that the boy is sitting at a distance of x meters from the fulcrum, and the little sister is sitting at a distance of y meters from the fulcrum.

The torque is given by the product of the force and the distance from the fulcrum: Torque = Force × Distance.

For the boy: Torque_boy = 800 N × x

For the little sister: Torque_sister = 400 N × y

Since the seesaw is balanced, Torque_boy = Torque_sister.

800 N × x = 400 N × y

To determine which child is closer to the fulcrum, we need to compare the values of x and y. Since the torque is directly proportional to the distance, the child sitting at the smaller distance from the fulcrum will exert a larger torque.

Therefore, the little sister is sitting closer to the fulcrum in the center of the seesaw.

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Answer:it is c i just did it and got it right. :3

Explanation:

The rotational speed of the axle when the car is traveling 20 m/s is approximately 64.52 rad/s.

What is Rotational speed ?

Rotational speed, also known as angular velocity, is the measure of how quickly an object rotates around an axis or a center of rotation. It is usually measured in radians per second (rad/s) or revolutions per minute (RPM).

The linear speed of the car is related to the rotational speed of the axle by the formula:

v = rω

where v is the linear speed, r is the radius of the tire (half the diameter), and ω is the angular speed of the axle.

In this case, the linear speed of the car is 20 m/s and the radius of the tire is:

r = 0.62 m / 2 = 0.31 m

So we can rearrange the formula to solve for ω:

ω = v / r

ω = 20 m/s / 0.31 m

ω ≈ 64.52 rad/s

Therefore, the rotational speed of the axle when the car is traveling 20 m/s is approximately 64.52 rad/s.

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The kinematic relations allow finding the results for the different questions are:

     1.  The acceleraations is a = 375 m/s²

     2. The time is t = 62.5 s

     3. The velocity at the ground is  v = -14.7 m / s

     4.  The time to the bottoncliff is    1.7 s

     5.  The height isy₀ = 122.5 m

     6.

         A) The velocity is v = 25.2 m / s

         B)  The height  for t=1 s is  y = 18.1 m

     7.

         A)  Time in the air is t = 2 s

         B)  The final veloicty is   v = - 19.6 m / s

Kinematics analyzes the movement of bodies, finding relationships between the position, velocity and acceleration of bodies.

Let's look for the answers to a series of questions:

1. They indicate the initial and final velocities of the body and the time to reach it is 20 s, ask how much the acceleration is worth

Let's use the relationship

             v = v₀ + a t

             a = \(\frac{v-v_o}{t}\)

             a = \(\frac{17500-10000}{20}\)

             a = 375 m/s²

2. What is the time it takes to travel a distance of 125 m with an acceleration of 4 m / s²

             x = v₀ t + ½ a t²

As it leaves the direction its initial velocity is zero

             x = ½ to t²

             t = \(\sqrt{\frac{2x}{a} }\)

             t = \(\sqrt{\frac{2 \ 125}{4} }\)

             t = 62.5 s

3. A pencil falls from a height and reaches the floor in a time of 1.5 s what is the speed when reaching the floor

            v = v₀ - g t

As it is released its initial velocity is zero

            v = -g t

            v = - 9.8 1.5

            v = -14.7 m / s

The negative sign indicates that the velocity is directed downwards.

4. From the edge of a cliff 40 m high, an apple is thrown downward with an initial velocity of 15 m / s. How long does it take to get to the bottom?

             y = y₀ + v₀ t - ½ g t²

In this case the initial velocity is negative because it is directed downwards and when it reaches the floor its height is zero, let us substitute

Suppose the acceleration is g = 10 m / s²

             0 = 40 - 15 t - ½ 10 t²

             0 = 40 - 15 t - 5 t²

let's solve the quadratic equation

             t² + 3 t - 8 = 0

             t = -3 + Ts 9 + 4 8/2

            t = -3 + 6. 4/2

             t₁ = - 4.9 s

            t₂ = 1.7 s

The time must be a positive quantity, so the correct answer is 1.7 s

5. A stone is dropped from the ceiling and it takes a time 5 s to reach the floor, which is the height of the ceiling

           y = y₀ +v₀ t - ½ g t²

as it is released from the ceiling its initial velocity is zero and the height upon reaching the floor is zero

          0 = y₀ + 0 - ½ g t²

          y₀ = ½ g t²

          y₀ = ½ 9.8 5²

          y₀ = 122.5 m

6. A man at a height of 30 m throws a ball downward at 7 m / s

    A) The speed when reaching the ground

    B) The height of the ball when a time of 1 s has fallen.

  A) Let's use the kinematics relation

              v² = v₀² - 2 g (y -y₀)

              v = 7² - 2 9.8 (0 -30)

              v = 25.2 m / s

 B)   y = y₀ + v₀ t - ½ g t²

        y = 30  7 1 - ½ 9.8 1²

        y = 18.1 m

7.  A watermelon is dropped from rest from the top of a 20m cliff.  

 A) time in the air

 B) ground speed

  A) Let's use the relation

       y = y₀ + v₀ t - ½ g t²

It is released its initial velocity is zero and when it reaches the ground its height is zero (y = 0)

       0 = y₀ + 0 - ½ g t²

       t = \(\sqrt{\frac{2y_o}{g} }\)

       t = \(\sqrt{\frac{2 \ 20}{9.8} }\)

       t = 2 s

B) the speed when reaching the ground

       v = v₀ - g t

       v = 0 - 9.8 2

       v = - 19.6 m / s

The negative sign indicates that the speed is down

In conclusion using the kinematic relations we can find the results for the different questions are:

   1.  The acceleraations is a = 375 m/s²

   2. The time is t = 62.5 s

   3. The velocity at the ground is  v = -14.7 m / s

   4.  The time to the bottoncliff is    1.7 s

   5.  The height isy₀ = 122.5 m

   6.

      A) The velocity is v = 25.2 m / s

      B)  The height  for t=1 s is  y = 18.1 m

  7)

      A)  Time in the air is t = 2 s

      B)  Te final veloicty is   v = - 19.6 m / s

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Given data

*The half-life of iodine-131 is t = 8.07 days

*The amount of quantity left is N = 0.25 g

*The number of days is T = 40.35 days

The expression for the radioactivity decay is given as

Substitute the values in the above expression as

Answer:

See below

Explanation:

40.35 days / (8.07 day per half life) = 5 half lives

.25 = x ( 1/2)^5

.25 / ( 1/2)^5 = x = 8 gm originally

Frequency and wavelength are inversely proportional to each other. The wave with the greatest frequency has the shortest wavelength. Twice the frequency means one-half the wavelength. For this reason, the wavelength ratio is the inverse of the frequency ratio.

A. Kilometers per hour of the following are units that can be used to describe vector quantities

Every vector has a unit vector that may be used to represent it as a collection of its components. A vector's unit vectors are pointed in the axes. The vector v in the three-dimensional plane will be represented by three perpendicular axes (x, y, and z-axis). The unit vector along the x-axis is denoted by the letter I in mathematical notations.

In addition to having a dimension or magnitude, vector quantities also have a direction known as their line of action. Hence, a 50 km/h direct east speed, a 9.8 m/s2 vertical downhill acceleration, and a 15 N force at a 30° angle are all instances of vector quantities.

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Answer:

Explanation:

In this case, gravity is pulling down on them ( both teams ), the strong - arm team is excerting thrust by trying to pull the rope, and you've got the drag of the other team pulling back.

When waves move from deep water to shallow water, the velocity of the waves decreases. The distance between the wave crest and the seabed decreases in shallow water, making it more challenging for the wave to move forward. As a result, the speed of the waves slows down.The waves bend as they come across the shallow water region because the water depth varies.

As a result, the wave front becomes warped resulting in a decrease in speed. As the wave enters shallow water its wavelength becomes shorter and its amplitude increases, but its frequency remains constant.The wave's velocity changes depending on the medium's density.

The denser the medium, the slower the wave travels, and vice versa. Since the speed of sound in water is quicker than that in air, sound waves travel faster through water than they do through air. As a result, the answer to the question is that the waves move slower through the second medium.

In the shallow water area, waves slow down and their shape changes. The energy of the wave is forced upward and outward, causing the wave to break. At the edges of the shallow area, the waves bend and change direction. As the waves come closer to shore, their circular motion causes them to collide with one another and pile up.

As a result, the waves become higher and steeper, resulting in a more turbulent environment for boats and swimmers.

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Answer: Well that's an easy one. Your mother birthed you but you are still alive today because you choose to continue to push forward and strive to live. As humans we all have struggles but some of choose to strive or sit in our humiliation like a kicked puppy. Pick your option.

In general, the most stable point in simulations involving energy, potential, or force usually refers to a point of equilibrium where the forces acting on the system are balanced, and there is no net movement or change in the system.

An experiment in science is a carefully designed and controlled procedure that is carried out to test a hypothesis or answer a research question. It is a systematic and empirical approach to investigating phenomena and understanding the natural world.

In an experiment, a researcher manipulates one or more variables and observes the effects of the manipulation on the dependent variable. The independent variable is the variable that is manipulated, while the dependent variable is the variable that is being measured or observed to see if it changes in response to the manipulation.

The goal of an experiment is to establish cause-and-effect relationships between variables by controlling for other factors that could influence the outcome. The experiment should be designed to minimize bias and confounding factors that could affect the results, and the results should be analyzed statistically to determine the significance of any observed effects.

Experiments are an essential part of the scientific method and are used in many scientific disciplines, including physics, chemistry, biology, psychology, and others. They allow researchers to test hypotheses, make predictions, and draw conclusions based on empirical evidence.

Here in the question,

The similarity of the most stable point in different trials will depend on the specifics of the simulation and the initial conditions set up for each trial. If the simulations involve similar systems and starting conditions, then the most stable point may be similar in terms of the position, potential energy, force, or other parameters being measured.

Therefore, Simulations involving energy, potential, or force usually refer to a point of equilibrium where the forces acting on the system are balanced.

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Answer:9700 N

Explanation: i js know

Answer:

It is cause by radiation that's the answer

Explanation: the heat project sun rays towards the popcorn which causes it to pop

Answer:

ans is 420ml

Explanation:

0.42L×1000ml

420ml

The Schrödinger equation plays a crucial role in understanding the dual nature of electrons and the probabilistic description of their locations.

The Schrödinger equation is a fundamental equation in quantum mechanics that describes the behavior of particles, like electrons, at the quantum level. It is essential in understanding two key concepts:

The electron has both particle and wave behavior, represented by wave functions, ψ: This statement is correct. The Schrödinger equation incorporates the dual nature of electrons, treating them as both particles and waves. The wave function (ψ) is a mathematical representation of the electron's wave-like behavior, which contains information about the electron's position and momentum.

The location of an electron must be described statistically instead of absolutely: This statement is also correct. The Schrödinger equation implies that we cannot know the exact position of an electron; instead, we can only describe its probable location using a statistical approach. The square of the wave function (|ψ|^2) gives the probability density of finding an electron in a particular region of space.

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