Which fat-formation pathway is the most efficient and direct?.

Answers

Answer 1

The most efficient and direct fat-formation pathway is the de novo lipogenesis (DNL) pathway.

De novo lipogenesis (DNL) is a metabolic process in which the body converts non-lipid (non-fat) substances, such as carbohydrates, into lipids (fatty acids) in the liver and adipose tissue (fat cells).The DNL pathway is a process in which glucose, a simple sugar, is transformed into a fatty acid in the liver.

DNL is most active in the liver and, to a lesser degree, in adipose tissue.The most efficient and direct fat-formation pathway is the DNL pathway. It has a higher potential for producing triacylglycerol than either re-esterification of free fatty acids (FFA) or dietary fatty acids. Thus, the storage of dietary carbohydrate as fat in adipose tissue is maximized by DNL.

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Related Questions

A school bus travels 40 kilometers in 1 hour. What is the appropriate unit for the average speed of the school bus?

Answers

Answer:

The average speed is = 11.1m/s

Explanation:

Recall that average speed is defined as the total distance traveled with respect to the total number of time, therefore we say that the total distance traveled is 40Km according to your question, remember, the unit of speed is metre per second, so you change 40km by multiplying it with 1000, recall that, 1000m = 1km, so 40km×1000m = 40,000m, also 1h= 60×60, =3600s

Remember the formula for average speed is = Total distance traveled÷ total time taken

Thus; 40000m/3600s

Then we had, 11.1m/s...

You can ask questions

why isn't the most probable distribution of money one where all players have the same quantity of money

Answers

Compared to other possible outcomes, the number of ways the money might be allocated equally among all players was incredibly limited. It was just too unlikely in the game to explain statistical thermodynamics.

What connection exists between an event's entropy value and probability of occurring?

Hence, if a system's entropy S increases, its thermodynamic probability W must do likewise. The fact that W always rises in a spontaneous change, also means that S must rise in the same change.

What does statistical thermodynamics' most probable distribution mean?

The term "most probable" refers to the distribution being possible in a variety of ways. For instance, in a solution, the molecules of the solute are normally distributed evenly throughout the volume of the solution.

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Evaluate 4x+13 when x=-3

Answers

4x + 13

4 * -3 + 13

-12 + 13

1

Which equation would be used to calculate the rate constant from initial
concentrations?

Which equation would be used to calculate the rate constant from initialconcentrations?

Answers

Answer: B

Explanation: I just did it

The equation for calculation of rate constant from initial concentration will be k= rate / \([A^{m}] [B^{n}]\)

What is rate constant?

The proportionality variable in the expression represents the link between both the rate of a reaction as well as the concentrations of the reacting components often called the rate constant, sometimes specific rate constant.

What is equation?

A chemical reaction is represented by a word equation that uses the identities of the substance present.

The equation for calculation of rate constant from initial concentration will be k= rate / \([A^{m}] [B^{n}]\).

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The first four ionization energies for a particular element are 738, 1450, 7730, and 10550 kJ mol¹ respectively. Deduce the group number of the element.​

Answers

The element belongs to the second group of the periodic table.

four ionization energies of the element are 738, 1450, 7730, and 10550 kJ mol¹ .

We can see that, there a large increase in the 3rd ionization energy. Which indicates that below the electrons removed by third and fourth ionization energy is considered as core electrons, and the first two electrons is considered as valence electrons.

So the valency of this element is 2,which indicates that it belongs to the second group of the periodic table and are known as Alkaline earth metals, with the outermost configuration ns2.

The second-most reactive metals in the periodic table are the alkaline earth metals, which include radium, barium, strontium, calcium, and beryllium. They have low electronegativity, low electron affinity, and low ionization energy. They are good electrical conductors and have an oxidation state of +2.

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Calculate the mass of 4.60 x 10^25 atoms of neon?

Select one:
a. 0.264 g
b. 5.54 x 10^2 g
c. 1.54 x 10^3 g
d. 0.0382 g

Answers

I think it’s B 5.54 x 10^2g

1.54 x \(10^3\) g is the mass of 4.60 x \(10^{25}\) atoms of neon.

What are moles?

A mole is defined as 6.02214076 × \(10^{23}\)of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

1 mol of atoms = 6.02214076 × \(10^{23}\)

Moles of neon in 4.60 x \(10^{25}\) atoms = \(\frac{mass}{molar \;mass}\)

\(\frac{4.60 X 10^{25}}{ 6.02214076 X 10^{23}}\)

0.7638479709 = 76.38 mol

The molar mass of neon is 20 g/mol

76.38 mol x 20 g/mol

1.54 x \(10^3\) g

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HYDROCARBONS Introduction Hydrocarbons are the simplest organic compounds. Containing only carbon and hydrogen, they can be straight-chain, branched chain, or cyclic molecules. Carbon tends to form four bonds in a tetrahedral geometry. Hydrocarbon derivatives are formed when there is a substitution of a functional group at one or more of these positions. Most hydrocarbons found on Earth naturally occur in crude oil, where decomposed organic matter provides an abundance of carbon and hydrogen which, when bonded, can catenate to form seemingly limitless chains. Procedure The following hydrocarbon samples will be examined; methane, ethylene, acetylene, cyclohexane and toluene for their; clarity, odor, color, and reactivity. A. Sample preparation for ethylene gas 1. Place 15 mL of 95% ethyl alcohol in a 250 mL distilling flask. 2. Slowly add 45 mL of concentrated H2SO4to the flask. Due to the exothermic nature of the reaction, allow the flask to cool down in a water bath with running tap water 3. Attach the flask to the distillation setup. Regulate the temperature at around 165 C−170 C. 4. When the bubbling starts, collect the gas samples. B. Sample preparation for acetylene and methane gas 1. Place 5 g of CaC2 lumps into a distilling flask with stopper. 2. Attach a thistle tube to the flask to introduce water to the CaC2
​ 3. When the gas is generated from the reaction of CaC2and H2O, test tubes were then used to collect the gas samples. 4. On the other hand, slowly collect the methane gas from the Liquefied Petroleum Gas (LPG) tank with the aid of a pressure gauge. C. Ignition test 1. For the liquid hydrocarbons, place 3 drops of the hydrocarbon sample in the evaporating dish. For the gaseous hydrocarbons, fill the test tube with stopper with the gas sample was held in an upright position. 2. Ignite the sample. 3. For all the samples, observe the color and luminosity of flame, and the absence or presence of soot formation. D. Reaction with bromine: effect of light 1. With the sample inside two test tubes (one wrapped with carbon paper), transfer 1 mL of 0.1M solution of Br in CCl 4 into each test tube. 2. Allow the contents in the unwrapped tube to react, and if the reaction is not fast, the test tube was placed under direct sunlight. 3. After decolorization, compare the contents of the wrapped and unwrapped test tubes. 4. To test the presence of hydrogen bromide, add 5 mL of distilled water to the unwrapped test tube. Agitated until two layers form. 5. Dip a glass rod into the test tube to collect small amounts of sample. Test the acidity of the sample with the litmus paper. E. Reaction with Baeyer's reagent or cold dilute KMnO4
1. With the sample inside the test tube, add 3 drops of KMnO 4 2. Agitate the test tube for at least 5 minutes to let the components react. 3. The disappearance of the purple color of KMnO4and the development of brown MnO2 precipitate is the indicator of reaction. F. Tollen's test 1. Add ten drops of Tollen's reagent in a test tube with 2 mL of the sample. 2. Mix the test tube thoroughly. 3. Observe for any formation of a solid precipitate and its color.

Answers

Hydrocarbons are compounds composed of hydrogen and carbon atoms only. These may be either straight or branched chains or rings containing carbon and hydrogen.

A. Sample preparation for ethylene gas1. Place 15 mL of 95% ethyl alcohol in a 250 mL distilling flask.2. Slowly add 45 mL of concentrated H2SO4 to the flask. Due to the exothermic nature of the reaction, allow the flask to cool down in a water bath with running tap water3. Attach the flask to the distillation setup. Regulate the temperature at around 165 C−170 C.4. When the bubbling starts, collect the gas samples.B. Sample preparation for acetylene and methane gas1. Place 5 g of CaC2 lumps into a distilling flask with stopper.2. Attach a thistle tube to the flask to introduce water to the CaC2 3. When the gas is generated from the reaction of CaC2and H2O, test tubes were then used to collect the gas samples.

4. On the other hand, slowly collect the methane gas from the Liquefied Petroleum Gas (LPG) tank with the aid of a pressure gauge.C. Ignition test1. For liquid hydrocarbons, put 3 drops of the hydrocarbon sample in the evaporating dish. For gaseous hydrocarbons, fill the test tube with stopper with the gas sample held in an upright position.2. Ignite the sample.3. For all samples, observe the color and luminosity of the flame and the absence or presence of soot formation.D. Reaction with bromine: effect of light1. With the sample inside two test tubes, transfer 1 mL of 0.1M solution of Br in CCl4 into each test tube.2. Allow the contents in the unwrapped tube to react, and if the reaction is not fast, the test tube was placed under direct sunlight.3. After decolorization, compare the contents of the wrapped and unwrapped test tubes.4. To test the presence of hydrogen bromide, add 5 mL of distilled water to the unwrapped test tube. Agitated until two layers form.5. Dip a glass rod into the test tube to collect small amounts of sample. Test the acidity of the sample with litmus paper.E. Reaction with Baeyer's reagent or cold dilute KMnO41. With the sample inside the test tube, add 3 drops of KMnO42.

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The following chemical reaction takes place in aqueous solution: SnSO 4 (aq)+2 NaOH(aq) Sn(OH) 2 (s)+Na 2 SO 4 (aq) Write the net tonic equation for this reaction.

Answers

The net ionic equation for the reaction between SnSO₄ and NaOH is:

Sn²⁺(aq) + 2OH¯(aq) —> Sn(OH)₂(s)

We'll begin by writing the dissociation equation for SnSO₄ and NaOH.

SnSO₄(aq) —> Sn²⁺(aq) + SO₄²¯(aq)

NaOH(aq) —> Na⁺(aq) + OH¯(aq)

In solution, the reaction will proceed as follow:

SnSO₄(aq) + NaOH(aq) —>

Sn²⁺(aq) + SO₄²¯(aq) + Na⁺(aq) + OH¯(aq) —> Sn(OH)₂(s) + Na⁺(aq) + SO₄²¯(aq)

Cancel the spectator ions (i.e Na⁺ and SO₄²¯) and write 2 before OH¯ to obtain the net ionic equation.

Sn²⁺(aq) + 2OH¯(aq) —> Sn(OH)₂(s)

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Sakura tested the pH of several solutions. Which substances are acidic? Check all that apply. Cola-flavored soda: 2. 6 cranberry juice: 2. 9 dish soap: 7. 3 pickle juice: 5. 5 seawater: 8. 0 lye soap: 13. 0.

Answers

Cola-flavored soda: 2. 6 -Acidic

cranberry juice: 2. 9  -Acidic

dish soap: 7. 3  -Basic

pickle juice: 5. 5  -Acidic

seawater: 8. 0 -Basic

lye soap: 13. 0. -Basic

What is pH?

pH value tells us about the acidity and basicity of any solution. pH means potential hydrogen.

The pH scale is counted from 0 to 14 in which 7 is neutral and the value of pure water.

Below 7 are all acids and the above 7 are all basic.

Thus, all acidic substances are Cola-flavored soda: 2. 6, pickle juice: 5. 5, cranberry juice: 2. 9.

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A solid is decomposed in HCl, producing a
gas. The product gas took 2. 23 times as long
to effuse as the same amount of CO2 under the
same conditions of temperature and pressure. What is the molar mass of the product gas?
Answer in units of g/mol

Answers

The molar mass of the product gas is 12.061 g/mole. This is determined by using the concept of  Graham's law of effusion.

According to  Graham's law of effusion.

rate1 / rate2  = \(\sqrt{(MM2 / MM1 )}\)

where, rate1 is the rate of effusion of first gas and  rate2 is the rate of effusion of second gas , MM1 is the molar mass of first gas and MM2 is the molar mass of second gas.

According to the given problem,

rate of effusion of unknown gas(rate1 ) / rate of effusion of CO2 (rate2 )  = 1.91

And, we know that, MM2  = molar mass of CO2 = [12+ (2*16)] g/mol = 44 g/mole

We need to find out MM1 (molar mass of unknown gas)

Putting these values in the Mathematical Formula, we get,

1.91 = \(\sqrt{(44g/mol / MM1 )}\)

(1.91)2 = 44g/mole / MM1

MM1  = (44 g/mole ) / 3.6481  = 12.061 g/mole

The molar mass of the product of gas calculated is 12.061 g/mole.

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help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!1

help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!1

Answers

The compound that does not conform to the law of constant proportion law is is CO2 whose ratio by mass ought to be 8:3 and not 3:4.

What is the law of constant proportions?

The law of constant proportions portrays the ideas that the composition of a pure sample of a substances has a fixed composition by mass.

Following the law of constant proportion, the compound that does not conform to this law is is CO2 whose ratio by mass ought to be 8:3 and not 3:4.

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Answer:

your cool

Explanation:

What is the mass of n2 in the equilibrium mixture?.

Answers

The mass of N₂ in the equilibrium mixture can be determined through the mole concept and the application of the ideal gas law. Since the equilibrium mixture contains both N₂ and O₂ gases, the equation that will be used to determine their masses is as follows:

2N₂(g) + O₂(g) ⇌ 2NO(g)

The balanced equation shows that two moles of N₂ react with one mole of O₂ to produce two moles of NO. This means that the initial number of moles of N₂ in the mixture will be twice the number of moles of NO. The mass of N₂ can be calculated using the ideal gas law, which is PV = nRT.

The given conditions can be used to calculate the partial pressure of N₂, which can then be used to determine the number of moles of N₂ in the mixture and the corresponding mass of N₂.

To calculate the partial pressure of N₂, the mole fraction of N₂ must first be determined. This can be done using the equation:

X(N₂) = n(N₂) / n(total)

where X(N₂) is the mole fraction of N₂, n(N₂) is the number of moles of N₂, and n(total) is the total number of moles of gas in the mixture. Since there are no other gases in the mixture, the mole fraction of N₂ will be equal to the number of moles of N₂ divided by the total number of moles of gas.

Using the ideal gas law, the partial pressure of N₂ can then be calculated:

P(N₂) = X(N₂) * P(total)

where P(N₂) is the partial pressure of N₂, X(N₂) is the mole fraction of N₂, and P(total) is the total pressure of the mixture. The total pressure can be calculated using Dalton's law of partial pressures, which states that the total pressure is equal to the sum of the partial pressures of all the gases in the mixture. Once the partial pressure of N₂ has been determined, the number of moles of N₂ in the mixture can be calculated using the ideal gas law:PV = nRTwhere P is the partial pressure of N₂, V is the volume of the mixture, n is the number of moles of N₂, R is the gas constant, and T is the temperature in Kelvin. Rearranging this equation to solve for n, we get:

n = PV / RT

Finally, the mass of N₂ in the mixture can be calculated using the molar mass of N₂ and the number of moles of N₂:

mass(N₂) = n(N₂) * M(N₂)

where M(N₂) is the molar mass of N₂.

The mass of N₂ in the equilibrium mixture can be determined using the ideal gas law and the mole concept. The partial pressure of N₂ can be calculated using the mole fraction of N₂ and the total pressure of the mixture. The number of moles of N₂ can then be calculated using the partial pressure, volume, temperature, and gas constant. Finally, the mass of N₂ can be calculated using the number of moles and the molar mass of N₂.

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when a parcel of air sinks in the atmosphere, there is usually _________.

Answers

an increase in temperature! hope this helps

What element is being reduced in the following redox reaction? Cr(OH)4-(aq) ClO-(aq) → CrO42-(aq) Cl-(aq).

Answers

The element that is being reduced in the given redox reaction is Cl (Chlorine)

The given redox reaction is

Cr(OH)₄⁻(aq) + ClO⁻(aq) → CrO₄²⁻(aq) + Cl⁻(aq)

First, we will define the terms oxidation and reduction

Oxidation can be defined as an increase in oxidation number

Reduction is defined as a decrease in oxidation number

This means the element that is being reduced in the reaction would have a decrease in oxidation number.

Oxidation number of Cr in Cr(OH)₄⁻ is +3; and the oxidation number of Cr in CrO₄²⁻ is +6. This is an increase in oxidation number and it means Cr is being oxidized.

Oxidation number of Cl in ClO⁻ is +1; and the oxidation number of Cl in Cl⁻ is -1. This is a decrease in oxidation number and it means Cl is being reduced.

Hence, the element that is being reduced in the given redox reaction is Cl (Chlorine).

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If a response is towards a stimulus it's described as _______; if a response is away from the stimulus it's described as _____.

Answers

Answer: Positive tropism, negative tropism

Explanation:

Stimulus can be define as external and internal agent which generate a response in an organism. If the growth and action is towards the stimulus it is called as positive tropism. If the growth and action is away from the stimulus it is called as negative tropism. Example, the growth of the stem towards the sunlight is called positive tropism whereas the growth of the root away from the sunlight is called negative tropism. Here, sunlight is the stimulus.

1. What is the molarity of a solution which contains 0.256 mol of a substance dissolved in 143 mL of solution.

2. What is the molarity of a solution containing 4.89 g of NaCl dissolved in 600. mL of solution?

3. If 895 g of KCl is dissolved in 950. mL of solution, what is the molarity of the solution?

4. How many formula units of solute are there in a 5.50 L of 0.460 M silver nitrate solution.?

5. How many grams of FeCl2 are needed to make 700. mL of a 1.4 M solution?

6. Find the mass required to prepare 2500 mL of a 0.250 M solution of strontium sulfate.

7. Calculate the molarity of a solution when 75.0 g of calcium nitrite is dissolved in 500.0 mL of solution.

8. How many molecules of glucose (C6H12O6) are contained in 150.0 mL of a 0.100 M solution?

9. What mass of potassium bromide is needed to prepare 1.00 L of 0.250 M solution?

10. If I have 350 mL of a 0.400 M NaBr solution, what will the concentration be if I add 250. mL more water to it?

11. If I dilute 270. mL of 0.250 M lithium acetate solution to a volume of 800 mL, what will the concentration of this solution be?

12. The molar mass of an unknown gas is to be determined. The gas at STP occupies 0.861 L and its mass is 3.22 g. With this information calculate the molar mass of the gas. Theo claims the gas to be a noble gas. Assuming Theo to be correct, what would the identity of the gas be?

13. What mass of sulfur dioxide gas at STP is needed to fill a 300.0 mL volumetric flask?

14. Suppose you fill up a 5.00 L scuba tank with oxygen at STP. How many molecules of oxygen are there in the tank?

15. The store manager at Party City weighs the helium tank before opening the store and then at the end of the day. The mass of the helium before and after the working day are entered in the table below. How many atoms of helium gas at STP were used to fill up balloons in that day?

HINT: 1 lb = 454 g

Mass of helium tank before opening the store 1565 lb

Mass of helium tank after closing the store 1329 lb

Answers

Answer:

The equation for molarity is moles/liter for the first question you would do 0.256/0.143 liters to get 1.790 mol/L

Explanation:

The second problem you would do need to find the moles of NaCl which you would do by doing 4.89 g/58.44g/mol= 0.08367 then do 0.08367/0.600= 0.139 mol/L

The third problem would be the same steps as the second one.

The fourth problem would be (0.460M)(5.50L)= 2.53 moles

The molarity of a solution which contains 0.256 mol of a substance dissolved in 143 mL of solution is 1.79.

What is Molarity?

Molarity of a given solution is known as the total number of moles of solute per litre of the solution.  A solution that is 1.00 molar (written 1.00 M) contains 1.00 mole of solute for every liter of solution.

Molarity = (No. of moles of solute ÷ Volume of solution in liters)

The unit of molarity is mol L⁻¹.

Molarity is temperature dependent because as temperature changes, volume of the solution also changes.

Given,

No. of moles = 0.256

Volume of solution = 143ml

Molarity = (0.256 ÷ 0.143) = 1.79

Therefore, The molarity of a solution which contains 0.256 mol of a substance dissolved in 143 mL of solution is 1.79.

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An element that has 2 core electrons and 3 valence electrons

Answers

Answer:

Boron

Explanation:

You can find this by looking at the number of protons in Boron, 5.

Then calculate how many electrons you are given, in this case the 2 core plus the 3 valence equal 5 total electrons

Neutral elements have the same number of protons and electrons, so your answer would be the element with 5 electrons, Boron.

You can also know this by using electron configuration. Since you kow there are 5 electrons then you can use EC to find out where your element is. In this case it is: 1s2 2s2 2p1

does this suggest that your reaction worked? use three key signals to justify your answer 1-methoxy-2-chloro-4-nitrobenzene

Answers

Yes, the reaction worked. Three key signals that suggest the reaction worked include the appearance of the product, the presence of the expected starting material, and the absence of any other byproducts.

The product, 1-methoxy-2-chloro-4-nitrobenzene, can be identified by its distinct color, smell, and boiling point. Additionally, if the expected starting material is present, then it shows that the reaction has taken place.

Lastly, the absence of any other byproducts such as unreacted starting material implies that the reaction was successful. All together, all three signals indicate that the reaction worked.

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When water boils and becomes steam at around 100 degrees Celsius, this is an example of a
A. Physical change
B. Chemical change
C. Chemical reaction
D. Covalent bond?

Answers

A. Physical change.
- Temperature is causing the change, which is always physical. Also, steam is still water and vice versa. This, it is a physical change.

HELPPPP A student has 32.3 g of carbon dioxide (CO2). How many moles of carbon
dioxide are contained in this sample?

HELPPPP A student has 32.3 g of carbon dioxide (CO2). How many moles of carbondioxide are contained in

Answers

Almost certain it is 0.731660 so F for your question.

Do you have the answers for this test ?!?Im taking it right now and grades are due this friday so I need to pass this test

One day after school, two students begin tracking the number of steps they took each minute while walking home. they each write a function, s(m), that they think can be used to track the amount of steps after m minutes. use the drop-down menus to explain why each function does or does not represent the amount of steps after m minutes.

Answers

To assess whether each function represents the number of steps after m minutes, we need to consider the characteristics of step tracking. Here are a few key points to consider:

Steps are cumulative: The total number of steps increases over time. The function should reflect this cumulative nature.

Linear relationship: Assuming a constant walking pace, the number of steps should have a linear relationship with time. If the number of steps consistently increases by the same amount for each minute, the function will likely be linear.

Non-negative values: The number of steps cannot be negative. The function should output non-negative values for all valid input values.

Based on these considerations, let's evaluate the proposed functions:

Student 1: s(m) = m^2

Explanation: The function s(m) = m^2 represents a quadratic relationship, not a linear one. In this case, the number of steps would increase quadratically with time, which is not realistic for step tracking. Therefore, this function does not accurately represent the number of steps after m minutes.

Student 2: s(m) = 5m + 10

Explanation: The function s(m) = 5m + 10 represents a linear relationship. It accounts for a constant increase in the number of steps (5 steps per minute) along with an initial offset of 10 steps. This function aligns with the characteristics of step tracking, making it a reasonable representation of the number of steps after m minutes.

In summary, Student 2's function, s(m) = 5m + 10, is more likely to accurately represent the number of steps after m minutes, as it reflects the cumulative, linear relationship between time and step count.

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How does the circulatory system work at the tissue level?

Answers

Answer:

Answer. Answer: The circulatory system is a network consisting of blood, blood vessels, and the heart. This network supplies tissues in the body with oxygen and other nutrients, transports hormones, and removes unnecessary waste products.

Explanation:

Answer:

ME AND YOU HAVE THE SAMEEEE USER BUT LOOK

The circulatory system is a network consisting of blood, blood vessels, and the heart. This network supplies tissues in the body with oxygen and other nutrients, transports hormones, and removes unnecessary waste products.

Explanation:

calculate the mass of camphor c10h16o that contains a million ×1.000106 hydrogen atoms. be sure your answer has a unit symbol if necessary, and round it to 4 significant digits.

Answers

The mass of camphor (C10H16O) that contains a million hydrogen atoms is approximately 15.068 g.

To calculate the mass of camphor (C10H16O) that contains a million (1,000,000) hydrogen atoms, we need to determine the molar mass of camphor and then use it to calculate the mass.

The molar mass of camphor (C10H16O) can be calculated by summing the atomic masses of its constituent atoms:

- Carbon (C) has a molar mass of 12.01 g/mol.

- Hydrogen (H) has a molar mass of 1.008 g/mol.

- Oxygen (O) has a molar mass of 16.00 g/mol.

So, the molar mass of camphor is:

(10 * 12.01 g/mol) + (16 * 1.008 g/mol) + (1 * 16.00 g/mol) = 152.23 g/mol.

Now, to calculate the mass of camphor containing a million hydrogen atoms, we need to determine the ratio of hydrogen atoms to camphor molecules.

From the molecular formula of camphor, we see that there are 16 hydrogen atoms per camphor molecule (C10H16O).

Therefore, the mass of camphor containing a million hydrogen atoms is calculated as follows:

Mass = (1,000,000 hydrogen atoms / 16 hydrogen atoms per camphor molecule) * (1 camphor molecule / 6.022 × 10²³ camphor molecules per mole) * (152.23 g/mol)

        = (1,000,000 / 16) * (1 / 6.022 × 10²³) * 152.23 g

Mass     ≈ 15.068 g (rounded to 4 significant digits)

The mass of camphor (C10H16O) that contains a million hydrogen atoms is approximately 15.068 g.

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The enzyme that catalyzes the synthesis of atp as hydrogen ions flow down their concentration gradient is called.

Answers

The enzyme that catalyzes the synthesis of ATP as hydrogen ions flow down their concentration gradient is called ATP synthase.

What is ATP synthase?

In the inner mitochondriаl membrаne, hydrogen ions hаve just one chаnnel аvаilаble: а membrаne-spаnning protein known аs АTP synthаse. Conceptuаlly, АTP synthаse is а lot like а turbine in а hydroelectric power plаnt. Insteаd of being turned by wаter, it’s turned by the flow of hydrogen ions moving down their electrochemicаl grаdient. Аs АTP synthаse turns, it cаtаlyzes the аddition of а phosphаte to АDP, cаpturing energy from the proton grаdient аs АTP.

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According to kineric molecular theory which statement descrives the particles in a sample of an ideal gas

Answers

Answer:

According to the kinetic molecular theory, which statement describes the particles in a sample of an ideal gas? The motion of the gas particles is random and in a straight-line.

Explanation:

Consider a pure crystalline solid that is heated from absolute zero to a temperature above the boiling point of the liquid. Which of the following processes produces the greatest increase in the entropy of the substance?
a) melting the solid
b) heating the liquid
c) heating the gas
d) heating the solid

Answers

The question is incomplete, the complete question is;

Consider a pure crystalline solid that is heated from absolute zero to a temperature above the boiling point of the liquid. Which of the following processes produces the greatest increase in the entropy of the substance? A ) melting the solid B ) heating the gas C ) vaporizing the liquid D ) heating the solid E ) heating the liquid

Answer:

vaporizing the liquid

Explanation:

We generally define entropy in chemistry as the degree of disorderliness in a system. The entropy of gases is greater than that of liquids and the entropy of liquids is greater than that of solids. It then logically follows that the degree of entropy in gases is the greatest among all the states of matter while the entropy of solids is the least among all the states of matter since solid particles remain in their mean positions and can only vibrate or sometimes rotate. Liquid particles may translate while gaseous particles move at high velocity with negligible intermolecular forces of attraction between them.

A phase transition from liquid to gaseous state now represents the greatest change in the entropy of the system since gases posses the highest entropy among all the states of matter, hence the answer.

if I have 22.1 grams of CO2 gas at -188 degrees Celsius and 165 ml what is the pressure of the gas in kPa​

Answers

Answer:

P = 2.145kPa

Explanation:

Mass = 22.1g

Molar mass of CO2 = 44g/mol

Vol = 165mL = 0.165L

T = -188°C = (-188 + 273.15)K = 85.15K

R = 8.314J/mol.K

From ideal gas equation,

PV = nRT

P = pressure of the ideal gas

V = volume the gas occupies

n = number of moles if the gas

R = ideal gas constant

T = temperature of the gas

n = number of moles

n = mass / molar mass

n = 22.1 / 44 = 0.50moles

PV = nRT

P = nRT/ V

P = (0.5 × 8.314 × 85.15) / 0.165

P = 2145.26Pa = 2.145kPa

Pressure of the gas is 2.145kPa

Which statement accurately describes the reactants of a reaction?


substances that do not participate in a reaction


new substances formed in the reaction


new substances that are present at the end of a reaction


substances that are used up in a reaction

Answers

Answer:

Substances that are used up in a reaction.

Explanation:

E.g In the Scientific equation Sodium +Chlorine=Sodium Chloride, Sodium and Chlorine are the reactants and the product is Sodium Chloride.

Hope this helps

What’s the formula for sodium oxide

Answers

The formula of sodium oxide is Na2O .

Answer:

The answer to this is Na2O

4. The mass of a silver liberty (coin) was measured three times and each measurement was made
to five digits. The mass values were 12.519 9.12.521 g, and 12.496 g. The average mass was
reported as 12.512 g.
Why is the average mass of the gold coin reported to five significant figures, even though you
had to divide by "3" to obtain the average?

Answers

Answer:

The average mass of the gold coin reported to five significant figures, even though you  had to divide by "3" to obtain the average.

Explanation:

Given that,

The mass of a silver liberty was measured three times and each measurement was made  to five digits.

The mass values are,

\(m_{1}=12.519\ g\)

\(m_{2}=12.521\ g\)

\(m_{3}=12.496\ g\)

The average mass of the gold  coin is 12.512 g.

We know that,

Significant figures :

Significant figures is explained the nonzero, leading zero and zeros between two nonzero digits.

For example,

The digits is 0.003405

In the digit, 345 = nonzero

0.00 = leading zero

The average mass of the gold coin reported to five significant figures because average mass is 12,512. All digits are nonzero.

Nonzero digit are significant.

Hence, The average mass of the gold coin reported to five significant figures, even though you  had to divide by "3" to obtain the average.

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