All the given factors are related to surface mining. Thus, option V. ALL A, B, C, and D is the correct answer choices.
Surface mining refers to the process of removal of the terrain surface to obtain minerals underneath. Particularly, surface mining is used to retrieve coal, iron, sand, gravel, stones, and other metals. The following are the factors that are attributed to surface mining:
During surface mining, coal is removed using a loader. With the process of surface mining, approximately 90% of coal can be recovered.Surface mining is best used for thick coal seams that are near the surface.Surface mining helps to remove rock and soil to access the coal."
Complete question is here:
which factors are related to surface mining?
I. ONLY A
II. ONLY B
III. BOTH A and C
IV. BOTH A and B
V. ALL A, B, C and D
a. coal is removed using a loader.
b. approx. 90% coal can be recovered
c. best used for thick coal seams that are close to the surface
d. Removes rock and soil to access the coal
"
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A circuit has two resistors in parallel, each resistor is 6 ohms. This circuit is connected to a single resistor of 6 ohms, to form a series-parallel circuit. What is the total resistance of the circuit?
The tatal resistance of the series-parallel circuit with two resistor connected in parallel which combination is connected in series to a single resistor is 9 ohms.
What is a resistance?
This can be defined as the opposition to current flow in a circuit.
To calculate the total resistance, first we need to find the total resistance of the parallel resistor.
For parallel,
R' = (R₁R₂)/(R₁+R₂)............Equation 1Where:
R' = Total resistance of the parallel resistor.
From the question,
Given:
R₁ = 6 ohmsR₂ = 6 ohmsSubstitute these values into equation 1
R' = (6×6)(6+6)R' = 3 ohms.Finally, we combine the effective parallel resistance in series to the single resistance to the the total resistance of the circuit.
Rt = R'+R₃.................. Equation 2Where:
Rt = Total resistance of the circuit.From the question,
R' = 3 ohmsR₃ = 6 ohmsSubstitute these values into equation 2
Rt = 3+6Rt = 9 ohms.Hence, the total resistance of the circuit is 9 ohms.
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if the aircraft's transponder fails during flight within class b airspace,
If the aircraft's transponder fails during flight within Class B airspace, the pilot should immediately notify air traffic control (ATC) using the appropriate radio frequency, follow any instructions given by ATC, and adhere to established procedures for aircraft without a functioning transponder.
What should a pilot do if the transponder on their aircraft malfunctions while flying within Class B airspace?In the event of a transponder failure while in Class B airspace, it is crucial for the pilot to take immediate action. The first step is to promptly notify air traffic control (ATC) of the situation using the designated radio frequency. This communication ensures that ATC is aware of the transponder failure and can provide necessary guidance and instructions. The pilot should then comply with any directives given by ATC, which may include specific altitude or heading instructions.
Additionally, the pilot must adhere to established procedures for aircraft operating without a functioning transponder within Class B airspace. These procedures typically involve maintaining vigilance, flying predictable patterns, and using visual signals as necessary to communicate with other aircraft.
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19. water is boiling at 1 atm pressure in a stainless steel pan on an electric range. it is observed that 2 kg of
liquid water evaporates in 30 minutes. the rate of heat transfer to the water is:
The rate of heat transfer to the water is 9.04 kW.
The rate of heat transfer to the boiling water can be calculated using the latent heat of vaporization formula. As the water is boiling, the temperature remains constant at 100°C.
The latent heat of vaporization of water is 2260 kJ/kg, which means that 2260 kJ of heat energy is required to convert 1 kg of water at 100°C to steam at the same temperature.
Therefore, the heat energy required to convert 2 kg of water to steam is 2 x 2260 kJ = 4520 kJ.
The time taken for this process is 30 minutes or 0.5 hours. Therefore, the rate of heat transfer to the water is 4520 kJ / 0.5 hours = 9040 kJ/hour or 9.04 kW.
This is the rate at which the electric range is supplying heat to the pan to maintain the water boiling.
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True or false It is legal to pass in Florida when approaching within 100 feet of or traversing any railroad crossing grade croead
Find the value of P(-1.5≤Z≤2)
Answer:
0.9104
Explanation:
Suitable technology can tell you the probability.
P(-1.5≤Z≤2) ≈ 0.9104
__
A phone app gives the probability as 0.9104426667829628.
You should always adjust the seat as ____ as possible, while staying comfortable.
A. high
B. even
C. low
D. close
Answer: A. High
Explanation:
In order to have an obstructed view from your seat, you should always adjust your seat as high as possible, while staying comfortable.
Answer:
A
Explanation:
I put high and got it right.
A total station has an ISO 17123-3 specified accuracy of ± 1.6 ′′. What is the estimated precision of an angle observed with two repetitions?
Where the above ISO is given, the estimated precision of an angle observed with two repetitions is: 1.13
Why is this so?To estimate the precision of an angle observed with two repetitions we must use the following formula:
Precision = accuracy/ √n
In this case, n is number of repetitions
So
Precision = 1.6 / √2
Precision = 1.1313708499
So, It is to be noted that the estimated precision of an angle observed with two repetitions is 1.13 (when rounded to 3 significance figures)
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Six forces act on a beam that forms part of a building's
frame. The vector sum of the forces is zero. The magnitudes
|FB| = Fel 20 kN, Fc = 16 kN, and (Fpl = 9 kN.
Determine the magnitudes of FA and FG.
Answer:
FA = 13 kN FG = 15.3 kNExplanation:
write each force in terms of magnitude and directions
Fx = F sin Ф
Fy = F cos Ф
where Ф is to be measured from x axis.
∑F at y = o
FAy + FBy + FCy + FDy + FEy + FGy = 0
∑F at x = o
FAx + FBx + FCx + FDx + FEx + FGx = 0
Let
FA = FA sin (110) + FA cos (110)
FB = 20 sin (270) + 20 cos (270)
FC = 16 sin (140) + 16 cos (140)
FD = 9 sin (40) + 9 cos (40)
FE = 20 sin (270) + 20 cos (270)
FG = FG sin (50) + FG cos (50)
add x and y forces:
FAx + FBx + FCx + FDx + FEx + FGx = 0
FAy + FBy + FCy + FDy + FEy + FGy = 0
FA sin (110) + 0 + 16 sin (140) + 9 sin (40) + 0 + FG sin (50) = 0
FA cos (110) - 20 + 16 cos (140) + 9 cos (40) - 20 + FG cos (50 = 0
FA sin (110) + 0 + 10.285 + 5.785 + 0 + FG sin (50) = 0
FA cos (110) - 20 - 12.257 + 6.894 - 20 + FG cos (50) = 0
FA sin (110) + 16.070 + FG sin (50) = 0
FA cos (110) - 45.363 + FG cos (50) = 0
solving for FA, and FG
FA = 13 kN
FG = 15.3 kN
From the given information, we can say that the sum of the upward forces is equivalent to the sum of the downward forces.
From the diagram, equating the component of the upward forces and the downward forces, we have:
\(\mathbf{-F_a sin 70 +F_c sin 40+F_d sin 40 + F_g sin50= F_b+F_e}\) --- (1)
Also, the sum of the horizontal positive x-axis as well as the horizontal negative x-axis can be computed as:
\(\mathbf{F_g cos 50 +F_d cos 40 = F_c cos 40 +F_a cos 70 --- (2)}\)
If:
\(F_B = F_E = 20 \ kN \\ \\ F_c = 16 \ kN \\ \\ F_D= 9\ kN\)
Then, from equation (1), we can have the following:
\(\mathbf{F_a sin 70 + 16 sin 40 + 9 sin40 + F_gsin 50 = (20 + 20 )kN}\)
collecting like terms;
\(\mathbf{F_a sin 70 + F_gsin 50 = 40 - 16 sin 40 - 9 sin40 }\)
\(\mathbf{F_a sin 70 + F_gsin 50 =23.93}\) --- (3)
From equation (2);
\(\mathbf{F_g cos 50 + 9cos 40 = 16 cos 40 + F_a cos 70}\)
collecting like terms:
\(\mathbf{F_g cos 50 -F_a cos 70 =16cos 40 -9cos 40}\)
\(\mathbf{-F_a cos 70 +F_g cos 50 =5.36 ----- (let \ this \ be \ equation (4))}\)
Suppose we equate (3) and (4) together using the elimination method;
\(\mathbf{F_a sin 70 + F_gsin 50 =23.93}\) --- (3)
\(\mathbf{-F_a cos 70 +F_g cos 50 =5.36 --- (4)}\)
Let's multiply (3) with ( cos 70 ) and (4) with (sin 70);
Then, we have:
\(\mathbf{F_a sin 70 cos 70 + F_gsin 50 cos 70 =23.93 cos 70}\)
\(\mathbf{-F_a cos 70 sin 70 +F_g cos 50 sin 70 =5.36 sin 70}\)
Adding both previous equations together, we have:
\(\mathbf{F_a sin 70 cos 70 + F_gsin 50 cos 70 =23.93 cos 70}\)
\(\mathbf{-F_a cos 70 sin 70 +F_g cos 50 sin 70 =5.36 sin 70}\)
\(\mathbf{(0 + F_g(sin 50 cos 70 + sin70 cos50) = 23.93 cos 70 + 5.36 sin 70)}\)
\(\mathbf{( F_g(0.262 + 0.604)) =(8.19 + 5.04)}\)
\(\mathbf{( F_g(0.866)) =(13.23)}\)
\(\mathbf{ F_g =\dfrac{(13.23)}{(0.866)}}\)
\(\mathbf{ F_g =15.28 \ N}\)
Replacing the value of \(\mathbf{F_g}\) into equation (3), to solve for \(\mathbf{F_a}\), we have:
\(\mathbf{F_a sin 70 + F_gsin 50 =23.93}\)
\(\mathbf{F_a sin 70 + 15.28sin 50 =23.93} \\ \\ \mathbf{F_a sin 70 +11.71 =23.93} \\ \\ \mathbf{F_a sin 70 =23.93-11.71 } \\ \\ \mathbf{F_a sin 70 =12.22 } \\ \\ \mathbf{F_a =\dfrac{12.22 }{sin 70}} \\ \\\)
\(\mathbf{F_a =13.01 \ N}\)
Therefore, we can conclude that the magnitudes of \(\mathbf{F_a}\) and \(\mathbf{F_g}\) are 13.0 N and 15.28 N respectively.
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An insulated piston-cylinder device initially contains 0.3m^3 of carbon dioxide at 200 kPa and 27 degrees celcius. An electric switch is turned on, and an 110-V source supplies current to a resistance heater inside the cylinder for a period of 10min. The pressure is held constant during the process, while the volume is doubled. Determine the current that passes through the residual heater.
The current that passes through the residual heater is 4.94 Ampere.
How to calculate the current passes from the residual heater?Given,
Volume = 0.3 m³
Pressure = 200 kPa
Temperature = 27°C
Voltage = 110 V
Time = 10 minutes
According to the ideal gas equation,
m = PV/RT = 200×10³×0.3/(189×(27+273)) = 1.058 kg
V₁/T₁ = V₂/T₂
T₂ = (V₂/V₂)×T₁ = 2×(27+273) = 600 K = 600 - 273 = 327°C
W = P(V₂ - V₁) = 200×10³ ×(2×0.3 - 0.3) = 60 kJ
Q - W = mCp(T₂ - T₁)
Q - 60 = 1.058×0.839×(327-27)
Q = 326.3 kJ
V×I×t = 326.3 kJ
110×I×(10×60) = 326.3×10³
Current I = 4.94 A
Thus, the current that passes through the residual heater is 4.94 A.
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Type the correct answer in the box. Spell all words correctly.
A genetically engineered hormone, , can treat Mary’s child for growth hormone deficiencies by stimulating body growth and increasing muscle mass.
Answer:
recombinant human growth
Explanation:
Answer:
recombinant human growth
Explanation:
yes
What is the biggest challenge in performing password cracking on pre-shared keys and getting results that are worthwhile
The biggest challenge in cracking pre-shared keys is obtaining the encrypted passwords in the first place. If the password hashes are not obtainable, cracking becomes infeasible.
What is cracking on pre-shared keys ?Pre-shared key password cracking entails making an effort to identify the original password or key that was used to encrypt data or safeguard a system. To guess the original password, different strategies like brute-force, dictionary attacks, or hybrid assaults are generally used after getting the encrypted password hashes, which are mathematical representations of the original password.
The sheer volume of potential password combinations that must be examined presents the biggest obstacle to breaking pre-shared keys. The quantity of possible password combinations and the computing power at hand directly influence how long it takes to crack a password. Therefore, even with powerful computers, breaking strong passwords that are lengthy and contain a combination of letters, numbers, and symbols might take a while.
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Two routes connect an origin and a destination. Routes 1 and 2 have performance functions t1 = 2 + X1 and t2 = 1 + X2, where the t's are in minutes and the x's are in thousands of vehicles per hour. The travel times on the routes are known to be in user equilibrium. If an observation for route 1 finds that the gaps between 30% of the vehicles are less than 6 seconds. Estimate the volume and average travel times for the two routes
Solution :
Given
\($t_1=2+x_1$\)
\($t_2=1+x_2$\)
Now,
\($P(h<5)=1-P(h \geq5)$\)
\($0.4=1-P(h \geq5)$\)
\($0.6=P(h \geq5)$\)
\($0.6= e^{\frac{-x_1 5}{3600}}$\)
Therefore, \($x_1=368 \ veh/h$\)
\($=\frac{368}{1000} = 0.368$\)
Given, \($t_1=2+x_1$\)
= 2 + 0.368
= 2.368 min
At user equilibrium, \($t_2=t_1$\)
∴ \($t_2$\) = 2.368 min
\($t_2=1+x_2$\)
\($2.368=1+x_2$\)
\($x_2 = 1.368$\)
\($x_2 = 1.368 \times 1000$\)
= 1368 veh/h
what is most delicious fod in the philippines?
Answer:
Well there are a lot of delicious food in the philppines but my most favorite is the Lechon, Adobo, Sisig, Chicken Curry, Crispy pata and Sinigang
A total of 10 rectangular aluminum fins (k = 203 W/m·K) are placed on the outside flat surface of an electronic device. Each fin is 100 mm wide, 20 mm high and 4 mm thick. The fins are located parallel to each other at a center-to-center distance of 8 mm. The temperature at the outside surface of the electronic device is 72°C. The air is at 20°C, and the heat transfer coefficient is 80 W/m^2·K. Determine:
a. the rate of heat loss from the electronic device to the surrounding air
b. the fin effectiveness.
Answer:
a. the rate of heat loss from the electronic device to the surrounding air
A total of 10 rectangular aluminum fins (k = 203 W/m·K) are placed on the outside flat surface of an electronic device. Each fin is 100 mm wide, 20 mm high and
4 mm thick. The fins are located parallel to each other at a center-to-center distance of 8 mm. The temperature at the outside surface of the electronic device is 72°C. The air is at 20°C, and the heat transfer coefficient is 80 W/m2·K. Determine (a) the rate of heat loss from the electronic device to the surrounding air and (b) the fin effectiveness.
Explanation:
Sorry if wrong, Hope I helped
~#Lilly
Calculate the power required for heating a 1.5 kg sample of water for 10 minutes in a thermal system. What is the amount of energy required to raise the temperature of the water from 25°C to 60°C ? How much minimum amount of power does the heater have to supply per unit time? Why does the actual power rating of the heater need to be higher than this minimum amount? (The specific heat of water is 4.18 J/g°C .)
*60 points to anyone who can help*
Answer:
Power= Heat energy\ time
heat energy= mc∆T
specific heat of water = 4180
1.5*4180*(60-25)
=219450
time = 10× 60= 600 secs
power = 219450/600
Power= 365.75 Watt
=0.37 KW
Explanation:
the actual has to be bigger because the heater might be required to handle more ...also to accommodate extra energy.
The output of a power supply is assumed to be normally distributed. 16 observations taken at random on voltage are as follows: 10. 35, 9. 30, 10. 00, 9. 96, 11. 65, 12. 00, 11. 25, 9. 58, 11. 54, 9. 95, 10. 28, 8. 37, 10. 44, 9. 25, 9. 38 and 10. 85. (a) Test the hypothesis that the mean voltage equals 12V against a two-sided alternative using α=0. 5. (b)Construct a 95% confidence interval on µ. (c) Test the hypothesis that σ2 =1 using α=0. 5. (d)Construct a 95% two-sided confidence interval on σ. (e) Construct a 95% upper confidences interval on σ
As the typical value can be represented by the mean, it acts as a benchmark for all observations.
Explain about the Mean?A dataset's mean (also known as the arithmetic mean, which differs from the geometric mean) is calculated by dividing the sum of all values by the total number of values. It is frequently referred to as the average and is the most widely used measure of central tendency.
The mean is the average or most frequent value among a set of numbers. It is a statistical measure used to determine the median and mode of a probability distribution's central tendency. It is additionally known as an expected value.
Finding the "average" value involves adding up all the data points and dividing by the total number of data points.
Use the R codes listed below to replicate the answers:
d = c(10.35, 9.30, 10.00, 9.96, 11.65, 12.00, 11.25, 9.58, 11.54,
9.95, 10.28, 8.37, 10.44, 9.25, 9.38, 10.85)
mean(d)
sd(d)
se = sqrt(length(d)) / sd(d)
se
Mean(d) - 1.96* se = CIl
mean(d) + 1.96* se CIU
CI = c (CIl, CIU)
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(a) Define and explain engineering
function and applications of each of the following geophysical
survey methods: (i) Seismic;
(ii) Magnetic;
(iii) Gravity and
(iv) Electrical.
Seismic surveys involve generating and recording waves of energy. Magnetic surveys measure variations in the Earth's magnetic field , Gravity surveys measure variations in the Earth's gravitational field Electrical surveys involve measuring the electrical properties.
(i) Seismic Survey: Seismic surveys involve generating and recording waves of energy that propagate through the subsurface. By analyzing the response of these waves, seismic surveys can provide information about the subsurface structure, rock layers, and the presence of oil and gas reservoirs. In engineering, seismic surveys are used for site investigations, assessing subsurface conditions for infrastructure projects, identifying potential geological hazards, and locating underground utilities.
(ii) Magnetic Survey: Magnetic surveys measure variations in the Earth's magnetic field caused by variations in the magnetic properties of subsurface materials. These surveys are useful in identifying magnetic anomalies associated with different rock types, mineral deposits, and geological structures. In engineering, magnetic surveys are applied to locate buried ferrous objects, mapping geological structures, and identifying potential archaeological sites.
(iii) Gravity Survey: Gravity surveys measure variations in the Earth's gravitational field caused by variations in subsurface density. They are effective in identifying variations in rock density, mapping subsurface structures, and locating potential mineral deposits. In engineering, gravity surveys are used for mapping geological formations, identifying subsurface faults, and assessing groundwater resources.
(iv) Electrical Survey: Electrical surveys involve measuring the electrical properties of subsurface materials, such as resistivity or conductivity. By studying the variations in electrical properties, these surveys can provide insights into subsurface lithology, groundwater presence, and contaminant plumes. In engineering, electrical surveys are applied in groundwater exploration, site characterization for construction projects, locating underground utilities, and assessing the stability of slopes.
Overall, these geophysical survey methods play crucial roles in engineering by providing valuable information about subsurface conditions, geological features, and potential hazards. They help engineers and geoscientists make informed decisions during the planning, design, and construction phases of various projects, ensuring the safety and efficiency of engineering endeavors.
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What rank is Cal Poly SLO engineering?
U.S. News ranks Cal Poly San Luis Obispo's engineering programme first among public universities in the western United States.
What engineering is Cal Poly known for?Cal Poly, also known as California Polytechnic State University, is renowned for its engineering programmes. It is regarded as one of the best engineering schools in the country, and its engineering programmes are consistently ranked among the best in the country.
Mechanical engineering, civil engineering, electrical engineering, aerospace engineering, and computer engineering are just a few of the engineering programmes available at Cal Poly. The school is well-known for its hands-on approach to learning, which emphasises project-based learning, collaboration, and the development of practical skills. Cal Poly engineering graduates are in high demand by employers, and the school has a proven track record of producing successful engineers and industry leaders.
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a Compass is a weak magnet that aligns itself to the local Electric Field
Select one:
True
False
Answer:
true
Explanation:
my mother lives just the corner from me
My mother lives.
From the point of view of the sentence, the mother is living far away from the point of her child. She is living not very far but from the point of view of the streets. She is living in her old apartment that is at the end of the road.
Hence says lives just the corner from me.
The statement describes the relations with the mother and child where the child expresses he feeling towards the mother that is used to living in her house that is just comer from her.Hence making the statement dramatic.Learn more about just the corner from me.
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1. What does the designation w21x68 refer to in a steel beam? [explain (w) and (21) and (68)] 2. What is the difference between shear and moment connections? 3. What is composite construction and what are the advantages? 4. What are the advantages/ disadvantages of steel structure with respect to fire, and how can the disadvantages be overcome? provide examples. 5. What is an open web steel joist, and how is the lightweight steel decking attached? 6. Sketch a web joist
The answer response are:
1. In a steel beam, the designation w21x68 refers to its size and shape. The "W" stands for wide flange and the number "21" indicates the depth of the beam in inches. The weight per foot of the beam is approximately 68 pounds.
2. Shear connections are designed to resist shear forces in a beam, while moment connections are designed to resist bending moments. Shear connections typically have bolts or welds connecting the beam to the supporting column, while moment connections have additional plates and bolts to provide extra strength against bending moments.
3. Composite construction is a type of building construction that combines two materials, usually steel and concrete, to create a more efficient and cost-effective structure. The advantages of composite construction include increased strength and stiffness, improved fire resistance, and reduced construction time and costs.
4. Steel structures have the advantage of being strong and durable, but they can also be vulnerable to fire due to their high melting point. To overcome this disadvantage, steel structures can be coated with fire-resistant materials or designed with additional fire protection measures, such as sprinkler systems or fire-resistant insulation. An example of a steel structure that has been designed for fire resistance is the World Trade Center in New York City.
5. An open web steel joist is a type of steel beam that has a web consisting of a series of smaller steel bars or rods. The lightweight steel decking is attached to the joist using special clips or fasteners that are designed to hold the decking securely in place.
What is the steel beam about?A steel beam is a structural element made of steel that is used to support heavy loads in construction and engineering projects. Steel beams come in a variety of shapes and sizes, including I-beams, H-beams, and wide flange beams.
Therefore, They are designed to resist bending and shearing forces, and are often used to span long distances or support the weight of other structural components, such as floors, roofs, and walls. Steel beams are popular in construction due to their strength, durability, and versatility, and can be found in a wide range of buildings, from skyscrapers to residential homes.
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Two kg of a two phase liquid vapor mixture of carbon dioxide(co2) exists at a - 40C in a 0.05 tank
The question is incomplete. Here is the complete question.
Two kg of a two phase liquid vapor mixture of carbon dioxide (CO₂) exists at -40°C in a 0.05m³ tank. Determine the quality of the mixture, if the values of specific volume for saturated liquid and saturated vapor CO₂ at -40°C are \(v_{f}\) = 0.896 x 10⁻³m³/kg and \(v_{g}=\) 3.824 x 10⁻²m³/kg, respectively.
Answer: x = 1
Explanation: In a phase change of a pure substance, at determined pressure and temperature, the substance exists in two different phases: saturated liquid and saturated vapor.
Quality (x) is the ratio of saturated vapor in the mixture and can be written as:
\(x=\frac{m_{vapor}}{m_{liquid}+m_{vapor}}\)
It has value between 0 and 1: x = 0 for saturated liquid and x = 1 for saturated vapor.
When related with volumes, quality is rearranged as:
\(x=\frac{v-v_{f}}{v_{g}-v_{f}}\)
Solving for x:
\(x=\frac{0.05-0.896.10^{-3}}{3.824.10^{-2}-0.896.10^{-3}}\)
\(x=\frac{0.049104}{0.037344}\)
x = 1.3
Quality of mixture of carbon dioxide is x = 1, which means it's for saturated vapor.
2-design a set of simple test programs to determine the type compatibility rules of a c compiler to which you have access. Write a report of your findings
When designing a set of simple test programs to determine the type compatibility rules of a C compiler to which you have access, it is important to consider the different data types that are used in C programming. An example of a set of test programs that can be used to determine the type compatibility rules of a C compiler:
Integer Test the compatibility of the C compiler with integer data types. It declares two variables of type int, initializes them with values, and then adds them together. The result is printed to the screen. If the program compiles and runs without any errors, then the C compiler is compatible with integer data types.
Floating-Point Test the compatibility of the C compiler with floating-point data types. It declares two variables of type float, initializes them with values, and then adds them together. The result is printed to the screen. If the program compiles and runs without any errors, then the C compiler is compatible with floating-point data types.
By running the set of simple test programs described above, you can determine the type compatibility rules of a C compiler to which you have access. If any of the programs do not compile or run without errors, then you can determine which data types are not compatible with the C compiler and adjust your code accordingly.
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The reading on the 0 to 25 mm micrometer provided is
A. 15.20
B. 15.70
C. 15.45
D. 0.1520
Based on the image attached, the reading of micrometer is= 15.20.
What do the numbers on a micrometer represent?You will see a line of numbers running down the barrel of your micrometer, starting with the barrel scale. On the barrel scale, each number corresponds to 0.100. Looking at the barrel, 1 equals 0.100, 2 equals 0.200, 3 equals 300, and so on. The distance between each tick mark and the larger numbers on the barrel is 0.025, or 25 thousandths.
Note that micrometer is one that is also referred to as a micrometer screw gauge—is a tool with a calibrated screw that is frequently used for precise measurement of components in mechanical engineering, and others.
Looking at the image, you will see the stop ends at 15 and and 20 so adding them together will be option A. 15.20.
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decrypting gene regulation: accelerated transcriptomic biomarker discovery utilizing a novel omics based machine learning framework
Using a cutting-edge omics-based machine learning framework, deciphering gene regulation will speed the development of transcriptome biomarkers for human health and disorders.
A machine is a physical system that employs power to apply forces, regulate movement, and carry out an action. Both naturally occurring biological macromolecules, such as molecular machines, and man-made systems that involve engines or motors are frequently referred to by the expression. Machines can be propelled by people, animals, wind, water, chemical, thermal, electrical, and other natural forces. They also have a collection of mechanisms that alter the actuator input to produce particular output forces and movements. Mechanical devices that track activities and organise movement, commonly referred to as computers and sensors, may also be included. The six primary mechanisms that move a weight were identified by Renaissance natural philosophers.
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Realice un analisis tecnologico de un frasco de vidrio.Teniendo en cuenta todos los niveles de analisis: analisis morfologico estructural,analisis de ls funcion y del funcionamiento,analisis tecnologico economico y analisis historico,por favor ayudenmen necesito entregarlo hoy
Answer:
b
Explanation:
water flows into the sink at a rate of 2 gal/min. if the drain is closed, the water will eventually flow through the overflow drain holes rather than over the edge of the sink. how many 0.4-in.- diamter drain holes are needed to ensure that the water does not overflow the sink? neglect viscous effects.
Therefore, roughly 12 drain holes with a diameter of 0.4 inches would be required to prevent the sink from overflowing with water.
Two gal of water per minute enter the sink. The water will eventually go through the overflow drain holes if the drain is closed as opposed to over the edge of the sink. number of 0.4-in.
Equation: The rate of flow through a circular hole can be determined.
\(Q = C \times A \times \sqrt{(2gH) (2gH)}\)
Calculate the following to determine the cross-sectional area of a hole with dimension d:
\(A = \frac{\pi}{4} \times d^2\)
To prevent the water from overflowing the sink, we can set the flow rate through each hole to be equal to the incoming flow rate and solve for the necessary number of holes.
\(n = \frac{2}{(0.61 \times \frac{\pi}{4} \times 0.16 \times \sqrt{(64.4 \times 6)})}\)
\(= \frac{2}{(0.61 \times \frac{\pi}{4} \times 0.16 \times 2.51)}\)
≈ 12
where,
2 gal/min
\(= n \times C \times \frac{\pi}{4} \times d^{2} \times \sqrt{(2gH)}\)
Now,
\(n = \frac{2}{C \times \frac{\pi}{4} \times d^{2} \times \sqrt{(2gH)}}\)
\(= \frac{2}{(0.61 \times \frac{\pi}{4} \times (0.4^{2}\ i\ n^2) \times \sqrt{(2 \times 32.2 \times H)})}\)
\(= \frac{2}{(0.61 \times \frac{\pi}{4} \times 0.16 \times \sqrt{(64.4 \times H)})}\)
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When a customer goes to shop in a supermarket, he/she starts by filling all the items they need on the trolley. The customer then pushes the trolley to the trolley to the cashier who calculates the total cost of all the items and presents the same o the customer. Thereafter, the customer may decide to pay in cash or present a card. The credit card is then swiped by the cashier through a card reader that debits the same amount from the customer’s account. The cashier then returns the card to the customer. represent the above using a use-case diagram
A Use-Case Diagram (UCD)refers to all the possible interactions that a person or one system can possibly have with another system, represented in a graphical format.
There are four main constituents of a use-case diagram. They are:
The actors who interact with the systemthe systemthe use cases andthe lines that represent the relationshipsUCDs are used to
capture the requirements of a systemacquire the external persons' point of viewidentify risk factors associated with a project.See the attached picture and the link below for more about Use-Case Diagrams:
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two technicians are discussing catalytic converters technician a says that the exhaust mixture must fluctuate between rich and lean mixture for the best l efficiently technician b says that the air fuel mixture must be leaner than 14:7:1 for best performance from a three way catalytic converter who is correct
Answer:
A
Explanation:
Kirby is conducting a literature review in preparation for his study of “expectations regarding the sharing of financial and practical responsibilities among married and cohabiting couples in which both partners are between the ages of 20 and 29.” Conducting a keyword search on “couples” and “responsibility,” Kirby has generated a lengthy list of research articles. He decides to shorten the list of potential articles by eliminating all articles that were not published in prestigious research journals. He will include all the remaining articles in his literature review. What is your opinion of Kirby’s approach to selecting articles for the literature review?
Answer:
My opinion towards Kirby's approach in choosing articles for literature reviews is that, it is not the considered a good approach because when choosing articles based only on Journal it can't be considered the best.
Various methods needs to be considered by Kirby's before selecting articles, which are stated in the explanation section below
Explanation:
Solution:
Kirby’s method in choosing articles is not regarded to be a better proposal because choosing articles with regards to the journal can’t be seen as good. There are other things that should to be taken into consideration by Kirby which is explained below:
It is also important to confirm the editors who are in charge of the journals. It is advisable to view the profile of the editors in various links such as LinkedIn, Google scholar, before choosing their articles.It is very important to stay away from people who might find a way to exploit this situation. some research articles may be produced just for the aim of making money & there might exist no good quality information that is needed by the researcher for conducting his research.A proper journal is the one that produces work on the journal that the paper addresses & it is the one that presents the researcher’s needs through its authenticity and aspirations.Some particular journals are regarded to offer good source of information for research. examples are Thomson Reuters website etc.The various information produced aside from quality, is also important to consider when choosing the source of information that the article presents.