Which fact is most important in causing phospholipids to behave as they do in water?.

Answer:

According to the Dalton's theory, the description of water molecule is that;

-Water molecules are made of two different kinds of atoms (hydrogen and oxygen atoms).

-All water molecules have twice as many hydrogen atoms as oxygen atoms.

-All water molecules have one oxygen atom for every two hydrogen atoms.

Explanation:

got a 100% on edge

Answer: D. (Liquid fuel)

The Zn atom in Zn(CIO3)2 will be 1.

A chemical element however is uniquely defined by its atoms, which are tiny pieces of substance. An atom is made up of a core nucleus and one or perhaps more electrons with negative charges that orbit it. The positively charged, comparatively hefty protons and neutrons that make up the nucleus may be present.

The given chemical formula is :

Zn(CIO3)2

The number of Zn = 1

The number of Cl atom = 2

The number of O = 6

Hence, it can be said that there are 1 atom of Zn present in the  Zn(CIO3)2 .

Therefore, the correct answer will be option (A)

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The volume of a sample of nitrogen gas is 7.08 L

It is given that

volume of gas at 500°C = 10 L = 773 k

We have to find

volume of gas at 275°C = 548 k

Charles Law states that the volume of a given mass of a gas is directly proportional to its Kevin temperature at constant pressure. In mathematical terms, the relationship between temperature and volume is expressed as

The physical principle known as Charles' law states that the volume of a gas equals a constant value multiplied by its temperature as measured on the Kelvin scale (zero Kelvin corresponds to -273.15 degrees Celsius).

V1/T1 = V2/T2

10/773 = V2/548

V2 = 7.08 L

Hence, volume of a sample of nitrogen gas is 7.08 L

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There are two peaks for anhydride at the above freq. our peaks are at 1759 cm-1 and one at 1838 cm-1  between two carbony1 group increases the freq. while resonance lowers the frequency.    

peak at 1100cm-1 C-O

PEAK at 1600 CM-1 alkene

2850 CM-1-3000 CM-1 ALKANE STRETCH.

3150 CM-1 ALKANE STRETCH

While cracking the dimer it will give us monomer which then reacts with maleic anhydride to give Diels-Alder product. It does not give any unwanted product at higher temperature. If  monomer reaction was low temperature and cracked.

Breaking the dimer at high temperature and it is to be reacted immediately can isolate the pure product.

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Answer:

202?

Explanation:

Since mass is an extensive property, 12.6 grams is a measure of mass and is an extensive property.

Extensive and intensive properties are two types of physical properties of a substance.

The physical properties of a substance refers to the properties that can be observed without making changes to the nature of the substance.

Extensive properties are the properties that vary with the amount of the substance. Examples include mass and volume, and length.

Intensive properties are the properties that do not vary with the amount of the substance. Examples include color, melting point, and boiling point.

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An example of a physical change is the process of tempering steel to form a knife blade.

physical properties include melting, transition to a gas, change of strength, change of durability, changes to crystal form, textural change, shape, size, color, volume and density.

Answer:go molecule you some b1tc1es

Explanation:

The pH value of the solution of NaC₂H₃O₂ is found to be 9.74.

When NaC₂H₃O₂ is dissolved in water, it dissociates into its constituent ions. The equilibrium constant for this reaction is the base dissociation constant, Kb, which is related to the acid dissociation constant, Ka, by the equation,

Kw = Ka x Kb

where Kw is the ion product constant for water, which is 1.0 x 10⁻¹⁴ at 25°C. For acetic acid, the Ka value is given as 1.8 x 10⁻⁵. The Kb value can be calculated using the above equation,

Kw = Ka x Kb

1.0 x 10⁻¹⁴ = (1.8 x 10⁻⁵) x Kb

Kb = 5.6 x 10⁻¹⁰

Now, let's use the Kb value to find the concentration of hydroxide ions in a 0.100 M solution of NaC₂H₃O₂.

NaC₂H₃O₂ + H₂O → Na⁺ + C₂H₃O₂⁻ + OH⁻

At equilibrium, the concentration of OH⁻ is x, and the concentrations of Na⁺ and C₂H₃O₂⁻ are each 0.100 M - x (assuming that the dissociation of water is negligible). The Kb expression is,

Kb = [HC₂H₃O₂][OH⁻] / [C₂H₃O₂⁻]

Since we want to find the pH of the solution, we can solve for [OH⁻],

Kb = [HC₂H₃O₂][OH⁻] / [C₂H₃O₂⁻]

5.6 x 10⁻¹⁰ = (x)(0.100 M - x)/(0.100 M)

Simplifying and solving for x gives,

x = 1.4 x 10⁻⁶ M

The pH of the solution can be calculated using the equation,

pH = -log[H⁺]

Since [H⁺] = Kw/[OH⁻], we have,

pH = -log(Kw/[OH⁻])

pH = -log(1.0 x 10⁻¹⁴/1.4 x 10⁻⁶)

pH = 9.74

Therefore, the pH of a 0.100 M solution of NaC₂H₃O₂ is 9.74.

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The given statement "A wet mount requires the addition of certain dyes and cell fixatives approximately 12 hours before viewing the specimen" is false. Because staining techniques typically require specific procedures and timing, but they are not typically performed 12 hours before viewing the specimen.

A wet mount is a simple technique in which a small sample is placed on a microscope slide with a drop of liquid, such as water or saline, and then covered with a cover slip. This allows for direct observation of living organisms or structures in a sample under a microscope.

Wet mounts generally do not require the addition of dyes or cell fixatives. However, staining techniques such as Gram staining or Acid-fast staining may be used to enhance the contrast of certain structures or organisms in a wet mount.

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Discussion:

Conclusion: You can use this basic outline, to structure your conclusion, and expand it from there.

By investigating/measuring/using a....... it was determined that........ This is consistent/not consistent with the expected result/theory of...... due to/because of...........

The equation of the reaction for the formation lithium oxide from lithium and oxygen is given as:

\(2Li + O_2 \rightarrow Li_2O\)

Lithium oxide is a compound formed from the reaction between lithium and oxygen.

The equation for the chemical reaction is given below:

\(2Li + O_2 \rightarrow Li_2O\)

Therefore, the reaction between lithium and oxygen yields lithium oxide.

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The chair structure I has the trans confirmation and the chair structure II has the cis confirmation.

A particular structure can have two isomers, namely, the cis and the trans isomers. The confirmation is said to be cis confirmation when both the substituents are facing in same axial or equatorial plane. The confirmation is said to be trans when both the substituents are facing in the opposite planes.

In the structure I, we can see that both the groups are facing in the opposite planes and hence the structure must have a trans confirmation. In structure two, the groups are in the same plane and hence the confirmation is a cis confirmation.

Hence, the correct option is  c. I = trans; II = cis.

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Answer:

a. To compare the concentration of 80 g/litre NaOH solution and 3 M NaOH solution, we need to convert one of the concentrations to the other unit.

One mole of NaOH weighs 40 grams. So, to convert 80 g/litre NaOH to Molarity, we can divide 80 g/litre by 40 g/mol to get:

80 g/litre NaOH = 2 M NaOH

Therefore, 3 M NaOH has a higher concentration than 80 g/litre NaOH solution.

b. To compare the concentration of 5.3 g/litre Na2CO3 and N/10 Na2CO3 solution, we need to first understand what N/10 solution means.

N/10 Na2CO3 means that the solution contains 1/10th of the normal concentration of Na2CO3. The normal concentration of Na2CO3 is the molar concentration of Na2CO3 that corresponds to the formula weight of Na2CO3, which is 106 g/mol.

So, the normal concentration of Na2CO3 is 1 mol/L or 1 M Na2CO3.

Therefore, N/10 Na2CO3 solution has a concentration of 1/10 M Na2CO3.

Now, let's compare the two concentrations:

5.3 g/litre Na2CO3 = (5.3/106) M Na2CO3 = 0.05 M Na2CO3

Since 0.05 M Na2CO3 is greater than 1/10 M Na2CO3, the concentration of 5.3 g/litre Na2CO3 solution is higher than that of N/10 Na2CO3 solution.

Explanation:

Answer:

Ionic

Explanation:

Answer:

Ionic Bond

Explanation:

CuS has an ionic bond between it as it it formed by the combination of two ions Cu⁺² and S⁻².

In the given reaction N2 (g) + 3H2 (g) â 2NH3 (g), the reactants are N2 and H2, and the product is NH3.

During the course of the reaction, the reactants will decrease in concentration as they are being consumed to form the product. Therefore, both N2 and H2 will decrease in concentration. At the same time, the concentration of the product NH3 will increase.

The reaction stoichiometry tells us that one molecule of N2 reacts with three molecules of H2 to produce two molecules of NH3. This means that the decrease in concentration of N2 will be twice as much as the decrease in concentration of H2.

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The following question may be like this:

If only reactants are initially added to a reaction flask, which species decrease in concentration during the course of the reaction N2 (g) + 3H2 (g) â 2NH3 (g)? Select all that apply.

The bonding you would expect to find in a coin made out of copper is metallic bonding.

Metallic bonding is the strong attraction between positively charged metal ions and the surrounding delocalized electrons in a metallic lattice. Copper is a metal and its atoms are closely packed together, forming a lattice structure. In the case of a copper coin, copper atoms lose their outermost electrons to form positively charged copper ions (Cu⁺), which are then held together by the delocalized electrons that move freely throughout the metal lattice. This type of bonding gives copper its characteristic properties such as electrical conductivity, malleability, and ductility making it an ideal material for coinage.

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Answer:

Two major scientific discoveries provide strong support for the Big Bang theory: • Hubble's discovery in the 1920s of a relationship between a galaxy's distance from Earth and its speed; and • the discovery in the 1960s of cosmic microwave background radiation.

Explanation:

The substance with the highest melting point among the given choices should be CO.

The melting point of a substance depends on its intermolecular forces, which are the forces that hold its molecules together. Generally, the stronger the intermolecular forces, the higher the melting point of the substance.

Among the given choices, CO has both London dispersion forces and dipole-dipole interactions, while Ne, N2, and Xe only have London dispersion forces. Dipole-dipole interactions are generally stronger than London dispersion forces.

Therefore, CO should have the highest melting point among the given substances because it has stronger intermolecular forces than the other covalent molecules.

In summary, the substance with the highest melting point among the given choices should be CO.

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Answer:

50

Explanation:

If you want a percent as a decimal so you can divide you must make it a decimal for example in your case it would be like this, 0.05, then all you do is divide 1,000 by 0.05

Explanation:

The statement "It is the currently accepted atomic model" is true. The electron-cloud model, also known as the electron cloud or electron orbital model, is the currently accepted model of the atom. It describes the behavior of electrons in an atom by representing them as existing in regions of high probability called electron clouds or orbitals. This model successfully explains many properties and behaviors of atoms and has been widely accepted by the scientific community.

When attempting to pick up a stock bottle, it is important to hold the bottle properly to prevent accidents and spills.

Here are the general steps to follow: Ensure that the bottle is properly labeled and that you have the correct bottle for the intended use. Check the condition of the bottle for any signs of damage or leaks. If you detect any damage or leaks, do not use the bottle and notify the appropriate personnel. Put on any necessary personal protective equipment (PPE), such as gloves and safety glasses, before picking up the bottle. Hold the bottle with both hands, with one hand on the bottom of the bottle and the other hand on the neck of the stock bottle. This helps provide stability and balance. Lift the bottle slowly and steadily, being careful not to tip the bottle or drop it. If the bottle is heavy, use a cart or a dolly to transport it instead of carrying it by hand. When placing the bottle down, do so gently and carefully to avoid any spills or damage.

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The overall enthalpy change i.e ΔH for the system is -1300 kJ.

Enthalpy change in a reaction is defined as the difference in the potential energy of the products and the potential energy of the reactants.

This is represented by ΔHreaction.

The reaction of enthalpy change is given as

ΔHreaction= ΔHproducts -  ΔHreactants

where ΔHproducts is the potential energy of the products

=[(-200) + (-300)]kJ

= -500kJ

And,  ΔHreactants is the potential energy of the reactants

=800KJ

Therefore, by putting these values ΔHreaction can be calculated as

ΔHreaction

= [-500-800] KJ

=-1300 KJ

Thus, the overall enthalpy change is -1300KJ

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This battery could be made stronger when we make lithium the anode and make zinc the cathode.

We know that the term electron affinity has to do with the fact the a specie is able to attract electrons. Hence, the specie that can be able to attract electrons is said to be have a greater electron affinity.

If we look at the order of the reactivity of the metals, we can see that the lithium has more tendency to exist as a positive ion as such the electron affinity of the lithium atom is very negative and it does not attract electrons.

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19.9 L

Explanation:

Given:

n = 21 mole, P = 78 atm , T = 900k ,

V = ? , R = 0.0821

Solution:

Ideal gas equation, PV = nRT

                                  V =  nRT / P

                                      = 21 × 0.0821 × 900/ 78

                                       = 19.89 L    

Yes, a student can accurately determine the concentration of an unknown acid when titrating it with sodium hydroxide, even without knowing the specific acid or the number of acidic hydrogens it has.

To do this, they can follow these steps:
1. Measure a known volume of the unknown acidic solution and transfer it into a flask.
2. Add a suitable indicator (e.g., phenolphthalein) to the acidic solution, which changes color when the solution becomes neutral.
3. Measure and record the initial volume of sodium hydroxide in the burette.
4. Begin titrating by slowly adding sodium hydroxide to the acidic solution while stirring until the indicator changes color, indicating the equivalence point where the acid and base have reacted completely.
5. Measure and record the final volume of sodium hydroxide in the burette.
At this point, the student can calculate the moles of sodium hydroxide used in the titration by subtracting the initial volume from the final volume and multiplying the result by the concentration of sodium hydroxide. Since the mole ratio of sodium hydroxide to acidic hydrogens is 1:1, the moles of acidic hydrogens in the unknown acid will be equal to the moles of sodium hydroxide used.
Now, the student can determine the concentration of the unknown acid by dividing the moles of acidic hydrogens by the volume of the acidic solution used in the titration. This will give the student the accurate concentration of the unknown acid, regardless of the specific acid or the number of acidic hydrogens it contains.

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If 250 mL of methane (CH4) effuses through a small hole in 48 s, the time required for the same volume of helium to pass through the hole is approximately 96 s.

The effusion rate of a gas is inversely proportional to the square root of its molar mass, according to Graham's law of effusion. In this case, we need to compare the effusion rates of methane and helium.

Since the volume is constant, we can use the ratio of their times of effusion.

Let's assume the molar mass of methane (CH4) is M1 and the molar mass of helium (He) is M2. According to Graham's law, the ratio of the effusion times is given by:

(time for methane) / (time for helium) = √(M2 / M1)

Given that the time for methane is 48 s, we need to find the time for helium. Rearranging the equation, we have:

(time for helium) = (time for methane) / √(M2 / M1)

By substituting the molar masses of methane (16.04 g/mol) and helium (4.00 g/mol), we can calculate:

(time for helium) = 48 s / √(4.00 g/mol / 16.04 g/mol)

(time for helium) = 48 s / √(0.25)

(time for helium) = 48 s / 0.5

(time for helium) = 96 s

Therefore, the time required for the same volume of helium to pass through the hole is approximately 96 seconds.

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