which expressions are equivalent to 8 13 ?

Answers

Answer 1

The next four equivalent fractions of 8/13 are:

16/2624/3932/5240/65

What are some equivalent fractions of 8/13?

Equivalent fractions are fractions that represent the same value but have different numerator and denominator. To find equivalent fractions of 8/13, we can multiply both the numerator and the denominator by the same non-zero integer.

In this case, we multiplied the numerator and denominator by 2, 3, 4, and 5, respectively, to obtain the next four equivalent fractions: 16/26, 24/39, 32/52, and 40/65. These fractions have different numerators and denominators, but they are equivalent to 8/13 as they represent the same value or amount.

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Related Questions

Can someone pls help me . ASAPPP

Can someone pls help me . ASAPPP

Answers

Volume without holes = 3 x 6 x 11 = 198 cubic inches.

Calculate volume of one hole:

3.14 x 0.5^2 x 3 = 2.355 cubic inches

There are 3 holes: 3 x 2.355 = 7.065

Subtract volume of the holes from the brick:

198 - 7.065 = 190.935 cubic inches.

Rounded to the nearest tenth: 190.9 cubic inches.

Answer:

190.9 inches^3

Step-by-step explanation:

First of all we have to find the total volume:

V = dimension 1 x dimension 2 x dimension 3

V = 3 x 6 x 11 = 198 inches^3

now we have to find the volume of the cylinders:

V= radius^2 x pi x height = 0.5^2 x 3.14 x 3 = 2.355 inches^3

the cylinders are three so:

V = 2.355 x 3 = 7.065 inches^3

at least we have to subtract this value at the total volume:

V= 198 - 7.065 = 190.935 = 190.9 inches^3

What is the perimeter?
Help plz... And
No links
I repeat No links!!

What is the perimeter?Help plz... And No links I repeat No links!!

Answers

Answer:

the perimeter is 25 miles

Answer:

30 mi

Step-by-step explanation:

This is a right triangle, so the Pythagorean Theorem applies:

13^2 + x^2 = 12^2, or

x^2 = 25 and x = 5.

The perimeter is the sum of the dimensions of this triangle:  

12 mi + 5 mi + 13 mi = 30 mi

1. Consider a consumer with utility function
u(x1, x2) = min ( 4 x1 + x2, x1 + 2 x2)


(a) Draw indifference curves passing through points (2; 2), (1; 2) and (4; 2) (Note:
these points may lie on different indifference curves). Make sure you correctly
determine kink points.
(b) Determine all properties of the preferences that you can deduce from the shape of
indifference curves or utility function. For each claimed property, provide either
a formal proof or a graphical visualization that will clearly indicate that the
claimed property holds.
(c) When X -> R2+, does UMP have a solution when Pk = 0? What property of the
preference relation did you use to get your answer?
(d) Assume that prices are positive. Derive the Walrasian demand of each good. Is the
Walrasian demand always single valued? [Hint: graphically depicting the UMP
can pin down the maximizing bundles. If p1=p2 > 4 what can you say about the
location of the utility-maximizing consumption bundle? What is the location if
4 < p1=p2 < 1=2? What about prices such that p1=p2 < 1=2?]


(e) Let p1 = p2 = 1 and w = $60. Suppose that the consumer receives a $10 voucher
from the government that he can spend only on good 1. Draw the new budget
set of the consumer and calculate the quantity of each good demanded by the
consumer. Does receiving the voucher make consumer better-off?

(f) Suppose instead that the government allows the consumer to choose between a
cash payment of $10 that can be spent on both goods and a $10 voucher that
can be spent on good 1 only. Which one would the consumer choose and why?
Would your answer change if the government's assistance were $30? Explain your
answer.

Answers

(a) By plugging in different values for x1, we can plot the indifference curves passing through the given points (2, 2), (1, 2), and (4, 2).

(b) The shape of the indifference curves shows convexity.

(c) The property used to determine this is the non-satiation property of preferences.

(d) The Walrasian demand may not always be single-valued.

(e) Receiving the voucher makes the consumer better-off .

(f) The cash payment allows the consumer to maximize utility by making trade-offs

For 4x1 + x2 = x1 + 2x2, rearranging the equation gives x2 = 3x1, representing the linear part of the indifference curves.

For x1 + 2x2 = 4x1 + x2, rearranging the equation gives x2 = 3x1, representing the kink in the indifference curves.

By substituting different values for x1, we can plot the indifference curves. They will be upward sloping straight lines with a kink at x2 = 3x1.

(b) Properties of the preferences deduced from the shape of indifference curves and utility function:

Diminishing Marginal Rate of Substitution (MRS): Indifference curves are convex, indicating diminishing MRS. The consumer is willing to give up less of one good as they consume more of it, holding the other good constant.

Non-Satiation: Indifference curves slope upwards, showing that the consumer prefers more of both goods. They always prefer bundles with higher quantities.

Convex Preferences: The kink in the indifference curves indicates convexity, implying risk aversion. The consumer is willing to trade goods at different rates depending on the initial allocation.

(c) UMP does not have a solution when Pk = 0 and X -> R2+. This violates the assumption of finite resources and prices required for utility maximization. The property used is non-satiation, as a consumer will always choose an infinite quantity of goods when they are available at zero price.

(d) Walrasian demand depends on relative prices:

If p1 = p2 > 4, the maximizing bundle lies on the linear portion of indifference curves, where x2 = 3x1.

If 4 < p1 = p2 < 1/2, the maximizing bundle lies on the linear portion of indifference curves but at lower x1 and x2.

If p1 = p2 < 1/2, the maximizing bundle lies at the kink point where x1 = x2.

Walrasian demand may not be single-valued due to the shape of indifference curves and the kink point, allowing for multiple optimal solutions based on relative prices.

(e) Given p1 = p2 = 1 and w = $60, the initial budget set is x1 + x2 = 60. With a $10 voucher for good 1, the new budget set becomes x1 + x2 = 70. Since p1 = 1, the consumer spends the voucher on good 1, resulting in x1 = 20 and x2 = 40. Receiving the voucher improves the consumer's welfare by allowing more consumption of good 1 without reducing good 2.

(f) If given the choice between a $10 cash payment and a $10 voucher for good 1 only, the consumer would choose the cash payment. It provides flexibility to allocate the funds based on individual preferences. The answer remains the same even if the assistance were $30, as the cash payment still allows optimal allocation based on preferences. Cash payment offers greater utility-maximizing options compared to the voucher, which restricts choices.

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Please solve the following system of equations by
substitution.

x=y-4
-2x+3y=6

Answers

To solve this by using substitution, we have to replace the 2nd equations X with the first
*-2(Y-4)+3Y=6, then we distribute!
*-2Y+8+3Y=6, after that we combine like terms!
*-2Y+3Y+8=6 > Y+8=6, Finally we subtract from both sides!
*Y+8-8=6-8, Which gives us y=-2 as our answer!

Second part!
After that we plug in Y=-2 into the 2ND equation and we solve accordingly!
*-2X+3(-2)=6 >-2X-6=6 > -2X=12
Finally dividing both sides by -2 we get:
X=-6 And Y=-2 as our answers

Word Problem: In 2012, in the United States, approximately 70,000,000,000 pounds of food was wasted and thrown away. The population of the U.S. at the beginning of 2012 was estimated to be approximately 320,000,000 people. Approximately how many pounds of food were wasted per person?

Answers

Answer:

218750

Step-by-step explanation:

Divide 70,000,000,000 by 320,000,000.

Answer:

B

Step-by-step explanation:

The correct answer was B) "Wastage of good food is an environmental hazard that needs to be stopped. By using proper measures to stop wastage of good food, we can help save resources and the environment."

What is4(3x+1) using the distributive property

Answers

12x+4 nnnnnknbhhjnbvgggjjjjij

Answer:

12x + 4

Step-by-step explanation:

multiply and distribute 4 on each number in the ()

so (4 x 3x) + (4 x 1) = 12x + 4

A car rental agency charges $15 a day for driving a car 200 miles or less. If a car is driven over 200 miles, the renter must pay $0.05 for each mile over 200 driven. Which of the following functions represents the cost to drive a car from this agency miles x a day?

A car rental agency charges $15 a day for driving a car 200 miles or less. If a car is driven over 200

Answers

The function which represents the cost to drive a car from this agency miles x a day is :

C(x) = 15, if 0 ≤ x ≤ 200

      = 15 + 0.05x, if x > 200

Given that,

A car rental agency charges $15 a day for driving a car 200 miles or less.

The function can be written as,

C(x) = 15 if 0 ≤ x ≤ 200

If a car is driven over 200 miles, the renter must pay $0.05 for each mile over 200 driven.

C(x) = 15 + 0.05x, if x > 200

Hence the correct option is D.

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screen shot below evaluating functions please help!

screen shot below evaluating functions please help!

Answers

Answer:

g(5) = -19

Step-by-step explanation:

Step 1: Define

g(x) = -3x - 4

g(5) = x = 5

Step 2: Substitute and evaluate

g(5) = -3(5) - 4

g(5) = -15 - 4

g(5) = -19

Answer:

g(5) = - 19

Step-by-step explanation:

To evaluate g(5), substitute x = 5 into g(x), that is

g(5) = - 3(5) - 4 = - 15 - 4 = - 19

Help fast pls before i go missing

Help fast pls before i go missing

Answers

Answer:

D) The mode and the median are equal

Step-by-step explanation:

8, 13, 15, 15, 34

The median is the middle number, and the mode is the number that appears the most. Both of them are 15.

now why would u even go missing

What's the circumference of a
circle with a radius of 5 inches?
Use 3.14 for pie
C = [?] inches

Answers

Answer:

the circumstance is 31.42

4/9x1/9
(Simplify the answer if possible)

Answers

5/81 is the answer. It is multiplication on fractions

Which equations represent circles that have a diameter of 12 units and a center that lies on the y-axis? Select two options.
x2 + (y – 3)2 = 36
x2 + (y – 5)2 = 6
(x – 4)² + y² = 36
(x + 6)² + y² = 144
x2 + (y + 8)2 = 36

Answers

\(Answer: \displaystyle\left {{x^2+(y-3)^2=36} \atop {x^2+(y+8)^2=36}} \right. .\)

Step-by-step explanation:

\(D=12\ \ \ \ O(0;b)\\\displaystyle\\R=\frac{D}{2}\\R=\frac{12}{2} \\ R=6.\\Circle \ equation\ is:\\(x-a)^2+(y-b)^2=R^2.\\a=0\ \ \ \ \ R=6\\x^2+(y-b)^2=6^2\\x^2+(y-b)^2=36\\Henese:\\\displaystyle\\\left {{x^2+(y-3)^2=36} \atop {x^2+(y+8)^2=36}} \right. .\)

A man has a 100-acre ranch that he wishes to stock with cows and sheep. Cows require ten acres of grazing land per animal and sheep require three acres of grazing land per animal. If he wishes to fully utilize the land, how many ways are there to stock the ranch so that it includes at least one cow and at least one sheep?

Answers

Answer:

3 ways

Step-by-step explanation:

From the question:

Number of acres of the land = 100 acres

1 cow = 10 acres of land

1 sheep = 3 acres of land

To fully utilize the land, the number of ways to stock the ranch so that it includes at least one cow and at least one sheep is calculated as:

1) 1 cow and 30 sheep

1 cow × 10 acres + 30 sheep × 3 acres

10 + 90 = 100 acres

2) 4 cows and 20 sheep

4 cow × 10 acres + 20 sheep × 3 acres

40 + 60 = 100 acres

3) 7 cows and 10 sheep

7 cow × 10 acres + 10 sheep × 3 acres

70 + 30 = 100 acres

Therefore, to fully utilize the land, the number of ways to stock the ranch so that it includes at least one cow and at least one sheep is 3 ways

In a study, the sample is chosen by asking our 40 closest friends What is the sampling method? Simple Random Stratified Convenience None of these

Answers

The sampling method described in the scenario is convenience sampling.

Convenience sampling is a non-probability sampling technique where individuals are selected based on their convenience or accessibility to the researcher.

In this case, the sample is chosen by asking the researcher's 40 closest friends, which implies that the selection is based on the convenience and availability of those individuals rather than a random or systematic approach.

Convenience sampling is often used in situations where it is difficult or impractical to obtain a representative sample from the population of interest. It is commonly seen in informal surveys, pilot studies, or situations where the researcher has limited resources or time constraints.

While convenience sampling can be quick and easy to implement, it is important to note that it introduces potential biases into the sample.

The sample obtained through convenience sampling may not accurately represent the larger population, as it relies on the availability and willingness of individuals to participate.

This can result in a sample that is not truly representative and may lead to biased or misleading conclusions.

Therefore, it is crucial to interpret the results of studies based on convenience sampling with caution, as they may not generalize well to the broader population.

For more accurate and reliable results, researchers often opt for probability sampling methods, such as simple random sampling or stratified sampling, which provide a higher level of representativeness and reduce the potential for bias.

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Find the signal probability, probability that the output will be 1, and the activity factor coefficient at each node \( n_{I} \) through \( n_{4} \). Assume \( P_{A}=P_{B}=P_{C}=0.5 \).

Answers

The signal probability, probability that the output will be 1, and the activity factor coefficient at each node are as follows:

\(\( P_{n_I} = 1 \), \( P_{n_{II}} = 0.5 \), \( P_{n_{III}} = 0.5 \), \( P_{n_{IV}} = 0.25 \), \( P_{n_{1}} = 0.25 \), \( P_{n_{2}} = 0.125 \), \( P_{n_{3}} = 0.0625 \), \( P_{n_{4}} = 0.03125 \)\)

To find the signal probability, probability that the output will be 1, and the activity factor coefficient at each node \(\( n_I \) through \( n_4 \),\) we need to analyze the given system and its inputs.

Let's assume that\(\( P_A = P_B = P_C = 0.5 \),\) which means that the inputs A, B, and C have an equal probability of being 0 or 1.

The signal probability, probability that the output will be 1, and the activity factor coefficient at each node are as follows:

\(\( P_{n_I} = 1 \)\( P_{n_{II}} = 0.5 \)\( P_{n_{III}} = 0.5 \)\( P_{n_{IV}} = 0.25 \)\( P_{n_{1}} = 0.25 \)\( P_{n_{2}} = 0.125 \)\( P_{n_{3}} = 0.0625 \)\( P_{n_{4}} = 0.03125 \)\)

In the given system, each node's output depends on the inputs it receives. Here's how we can determine the signal probability, probability that the output will be 1, and the activity factor coefficient at each node:

- Node \( n_I \) is always active, so its signal probability is 1.

- Nodes \( n_{II} \) and \( n_{III} \) receive inputs A, B, and C. Since each input has a probability of 0.5, the probability that any of them is active is also 0.5.

- Node \( n_{IV} \) receives the outputs from nodes \( n_{II} \) and \( n_{III} \). The activity factor coefficient at this node is the product of the probabilities of the inputs being active, which is 0.5 * 0.5 = 0.25.

- Nodes \( n_{1} \), \( n_{2} \), \( n_{3} \), and \( n_{4} \) follow a similar calculation based on their respective inputs.

By analyzing the system and considering the given input probabilities, we can determine the signal probability, probability that the output will be 1, and the activity factor coefficient at each node.

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Let S and T be non-empty subsets of a topological space (X,τ) with S⊆T. (i) If p is a limit point of the set S, verify that p is also a limit point of the set T. (ii) Deduce from (i) that Sˉ⊆Tˉ. (iii) Hence show that if S is dense in X, then T is dense in X. (iv) Using (iii) show that R has an uncountable number of distinct dense subsets.

Answers

Since there are uncountably many distinct pairs of real numbers, we get an uncountable family of dense subsets of R.

Let S and T be non-empty subsets of a topological space (X,τ) with S⊆T.

Here is the solution:(i) If p is a limit point of the set S, then every open set that contains p contains a point q of S, distinct from p. If U is an open set containing p, then U also contains q ∈ S ⊆ T, so p is a limit point of T.(ii) We know that Sˉ, the closure of S is the set of all limit points of S. Hence, Sˉ consists of points p of X that satisfy the condition that every open set U containing p intersects S in a point q distinct from p. If p ∈ Sˉ, then every open set U containing p intersects S in a point q.

In particular, every open set V containing p also intersects T in a point q ∈ S ⊆ T. Therefore, p ∈ Tˉ.(iii) If S is dense in X, then Sˉ = X. From part (ii) of the question, we know that Sˉ ⊆ Tˉ. Therefore, Tˉ = (Sˉ)ˉ = X.

In other words, T is dense in X.(iv) To show that R has an uncountable number of distinct dense subsets, we make the following observation: for any distinct a,b ∈ R, the sets a + Z and b + Z are dense in R.

Indeed, let U be an open set in R. Let r be any real number. Then U contains an open interval (r - ε, r + ε) for some ε > 0. Let n be any integer. Then the set (a + nε/2, b + nε/2) intersects U.

Therefore, (a + Z) ∪ (b + Z) is dense in R.

Since there are uncountably many distinct pairs of real numbers, we get an uncountable family of dense subsets of R.

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Julianne fong started a company which sells equipment to retrofit buildings for the physically challenged. julianne will pay $485.60 for a wheel chair access water cooler, with front and side push bars to activate that water fountain. if she decdes to mark up the pricr 37.5% based on cost, what will be the selling price ot the water cooler?

Answers

The selling price of the water cooler, after a 37.5% markup, will be $667.70.

To determine the selling price of the water cooler, we need to calculate the markup based on the cost and add it to the original cost. Given that Julianne will pay $485.60 for the water cooler, we need to find the markup price of 37.5% based on the cost.

To calculate the markup price, we multiply the cost by the markup percentage:

Markup price = Cost * Markup percentage

Markup price = $485.60 * 37.5%

To find the selling price, we add the markup price to the original cost: Selling price = Cost + Markup price

Selling price = $485.60 + Markup price

Let's calculate the markup price:

Markup price = $485.60 * 37.5% = $182.10

Now, we can calculate the selling price:

Selling price = $485.60 + $182.10 = $667.70

Therefore, the selling price of the water cooler, after a 37.5% markup, will be $667.70.

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A survey was done that asked people to indicate whether they preferred to ride a
street bike or a mountain bike. The results of the survey are shown in the two-way
table.
Amjed is making a relative frequency table from this data.
What operation should Amjed perform to determine the relative frequency of a
person over 30 years old who prefers to ride a mountain bike? 1) Subtract 25 from 462, then divide by 462. 2) Divide 25 by 462. 3) Add 180 to 462, then divide by 463. 4) Divide 180 by 462

A survey was done that asked people to indicate whether they preferred to ride astreet bike or a mountain

Answers

The operation that Amjed should perform to determine the relative frequency of a person over 30 years old who prefers to ride a mountain bike is given as follows:

2) Divide 25 by 462.

How to calculate a probability?

The parameters that are needed to calculate a probability are listed as follows:

Number of desired outcomes in the context of a problem or experiment.Number of total outcomes in the context of a problem or experiment.

Then the probability is calculated as the division of the number of desired outcomes by the number of total outcomes, hence it is the same as a relative frequency.

The total number of people is given as follows:

58 + 164 + 215 + 25 = 462.

Out of these people, 25 prefer mountain bike, hence the relative frequency is given as follows:

25/462.

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Write proportion statement and find missing side of the polygon.

Write proportion statement and find missing side of the polygon.

Answers

The proportion statement is 2/3. The missing angles are CK = 12, GN = 15 and GT = 9

How to write the proportion statement and find the missing sides?

Given that: Polygon ROCK ~  Polygon GNAT.

The symbol ~ means the polygons are similar to each other. That means the ratios of all their corresponding sides are the same. Thus:

CO/AN = 4/6 = 2/3 (This is the proportion statement)

We can also say CK/AT= 2/3 because the ratios of all their corresponding sides are the same

With this, we can determine  the missing sides:

CK/AT= 2/3     where AT = 18

CK/18= 2/3

CK = (18×2)/3 = 12

OR/GN = 2/3    where OR = 10

10/GN = 2/3

2GN = 10×3

2GN = 30

GN = 30/2 = 15

KR/GT = 2/3   where KR = 6

6/GT = 2/3

2GT = 6×3

2GT = 18

GT = 18/2 = 9

Therefore, the proportion statement is 2/3, and the missing angles are CK = 12, GN = 15 and GT = 9

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Industrial quality control programs often include inspection of incoming materials from suppliers. If parts are purchased in large lots, a typical plan might be to select 20 parts at random from a lot and inspect them. A lot might be judged acceptable if one or fewer defective parts are found among those inspected. Otherwise, the lot is rejected and returned to the supplier. Use technology or SALT to find the probability of accepting lots that have each of the following:


a. 5% defective parts

P(lot will be accepted) =


b. 15% defective parts

P(lot will be accepted) =


c. 20% defective parts

P(lot will be accepted) =

Answers

The possibilities of accepting lots with 5%, 15%, and 20% faulty elements are approximately 0.3585, 0.0313, and 0.0115, respectively.

To discover the possibility of accepting lots with unique probabilities of faulty components, we are able to use the binomial chance formulation.

The formula for the probability of accepting plenty whilst choosing 20 components at random is:

P(lot might be widely wide-spread) =\((nCr) * p^x * (1-p)^(n-x)\)

wherein:

n is the variety of components decided on (20 in this example)

r is the number of faulty components allowed (1 or fewer in this case)

p is the chance of a part being faulty

x is the variety of faulty elements determined among the ones inspected

a. For plenty with 5% faulty parts:

n = 20

r = 1

p = 0.05 (5%)

x = 0 (no defective elements found)

P(lot can be accepted) = \((20C0) * 0.05^0 * (1-0.05)^(20-0)\)

Using a calculator or statistical software program, we can compare this expression to discover:

P(lot can be prevalent) ≈ 0.3585

b. For a lot with 15% faulty elements:

n = 20

r = 1

p = 0.15 (15%)

x =0 (no defective components observed)

P(lot may be popular) =\((20C0) * 0.15^0 * (1-0.15)^(20-0)\)

Calculating this expression, we discover:

P(lot could be frequent) ≈ 0.0313

c. For a lot with 20% faulty parts:

n = 20

r = 1

p = 0.20 (20%)

x = 0 (no defective components discovered)

P(lot might be familiar) =\((20C0) * 0.20^0 * (1-0.20)^(20-0)\)

Evaluating this expression, we get:

P(lot can be customary) ≈ 0.0115

Therefore, the probabilities of accepting plenty with 5%, 15%, and 20% defective parts are approximately 0.3585, 0.0313, and 0.0115, respectively.

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a publisher reports that 53s% of their readers own a particular make of car. a marketing executive wants to test the claim that the percentage is actually different from the reported percentage. a random sample of 250250 found that 44d% of the readers owned a particular make of car. is there sufficient evidence at the 0.010.01 level to support the executive's claim? step 1 of 7 : state the null and alternative hypotheses.

Answers

There is sufficient evidence to support the claim that the average percentage of readers who own a particular make of car is above 53%

     2. There is not sufficient evidence to support the claim that the average percentage of readers who own a particular make of car is above 53%

What is null and alternative hypothesis??|
The alternative hypothesis of a test expresses your research's prediction of an effect or relationship, whereas the null hypothesis of a test always predicts no effect or no association between variables.

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what is the answer for this, I have to solve the proportion,
n/18 = 12/7.5

Answers

Answer:

n = 28.8

Step-by-step explanation:

\(\frac{n}{18} =\frac{12}{7.5}\)

n × 7.5 = 18 × 12

7.5n = 216

7.5n ÷ 7.5 = 216 ÷ 7.5

n = 28.8

This table shows how many students from two high schools attended a
football game
Attended the game
Total
Did not attend
the game
90
Westville
60
150
North Beach
110
90
200
Total
170
180
350
A student is randomly selected.
What is the probability that a student attended the game, given that the
student is from North Beach? Round your answer to two decimal places,
O A. 0.57
B. 0.48
C. 0.55
OD. 0.65

This table shows how many students from two high schools attended afootball gameAttended the gameTotalDid

Answers

Answer:

The answer was 0.55

Step-by-step explanation:

I took the quiz

The probability that a student attended the game, given that the

student is from North Beach is 0.55, the correct option is C.

What is the probability?

Probability refers to a possibility that deals with the occurrence of random events.

The probability of all the events occurring need to be 1.

The formula of probability is defined as the ratio of a number of favorable outcomes to the total number of outcomes.

P(E) = Number of favorable outcomes / total number of outcomes

We are given that;

The table

Now,

Out of the 200 students from Westville and the 150 students from North Beach, a total of 170 + 110 = 280 students attended the game.

The probability that a student attended the game, given that they are from North Beach, can be calculated using Bayes' theorem:

P(attended game | from North Beach) = P(from North Beach | attended game) * P(attended game) / P(from North Beach)

P(from North Beach | attended game) is the probability that a student is from North Beach, given that they attended the game. This can be calculated as:

P(from North Beach | attended game) = P(from North Beach and attended game) / P(attended game)

There were 110 students from North Beach who attended the game, so:

P(from North Beach and attended game) = 110 / 280 = 0.3929

The probability of attending the game is P(attended game) = 280 / 350 = 0.8

The probability of being from North Beach is P(from North Beach) = 150 / 350 = 0.4286

P(attended game | from North Beach) = 0.3929 / 0.8 * 0.4286 = 0.55 (rounded to two decimal places)

Therefore, by the probability the answer will be 0.55.

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the table below shows the total number of goals scored in each of 43 soccer matches in a regional tournament. what is the average number of goals scored per match, to the nearest 0.1 goal?

Answers

Average number of goals = 2.8

From the question, we have

Average  =  total number of matches/ total number of goals

​=(4×0+10×1+5×2+9×3+7×4+5×5+6×1+7×2)/43

​=120/43

=2.79=2.8

Addition:

The act of combining two or more items is known as addition. The process of computing the sum of two or more numbers in mathematics is called addition. It is a fundamental mathematical procedure that is frequently used in daily life. When we work with money, figure out our food bills, or figure out the time, we frequently employ addition. One-digit numbers can be added simply for solving addition problems, however for bigger numbers, we divide the numbers into columns using their corresponding place values, such as ones, tens, hundreds, thousands, and so on.

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Combine the like terms to create an equivalent expression.
-y+6y

Answers

Answer:

Step-by-step explanation:

6y - y = y(6 - 1) = y * 5

The answer is 5y.

How would you explain 2-3?

Answers

Use a number line and start from 2 and go backwards by 3, if you did it correctly then you should have gotten to the answer of -1. Or you can just go 2-2=0-1=-1

Find the mean, variance, and standard deviation of the binomial distribution with the given values of n and p n-50, p 0.3 The mean, μ, is [ ]. (Round to the nearest tenth as needed.) The variance, σ2, is (Round to the nearest tenth as needed.) The standard deviation, σ, is . (Round to the nearest tenth as needed.)

Answers

Answer:

The mean (μ) is 15, the variance (σ^2) is 10.5, and the standard deviation (σ) is approximately 3.24.

Step-by-step explanation:

To find the mean (μ), variance (σ^2), and standard deviation (σ) of a binomial distribution, we use the formulas:

Mean (μ) = n * p

Variance (σ^2) = n * p * (1 - p)

Standard Deviation (σ) = √(n * p * (1 - p))

Given n = 50 and p = 0.3, we can substitute these values into the formulas:

Mean (μ) = 50 * 0.3 = 15

Variance (σ^2) = 50 * 0.3 * (1 - 0.3) = 10.5

Standard Deviation (σ) = √(50 * 0.3 * (1 - 0.3)) ≈ 3.24

Therefore, the mean (μ) is 15, the variance (σ^2) is 10.5, and the standard deviation (σ) is approximately 3.24.

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From the top of a 45 ft tower a person can see the other on the ground with an angle of depression of 40° what is the horizontal distance from the person at the base of the tower

Answers

Answer:

Step-by-step explanation:

32

How many grams are equal to 7 kilograms

Answers

Answer:

7 kilograms is 7000 grams

Step-by-step explanation:

Determine which of the four levels of measurement​ (nominal, ordinal,​ interval, ratio) is most appropriate.
Ranks of cars evaluated by a consumer's magazine.
Choose the correct answer below.
A. The ordinal level of measurement is most appropriate because categories are ordered, but differences cannot be found or are meaningless.
. B. The ratio level of measurement is most appropriate because ratios are​ meaningful, and there is also a natural zero.
C. The nominal level of measurement is most appropriate because data cannot be arranged in an ordering schemein.
D. The interval level of measurement is most appropriate because differences are​ meaningful, but there is no natural zero.

Answers

The data can be arranged in an ordering scheme, but differences cannot be found or are meaningless, making the ordinal level of measurement most appropriate.

The most appropriate level of measurement for the ranks of cars evaluated by a consumer's magazine is the ordinal level of measurement. This is because the ranks of the cars can be ordered based on their performance, but the differences between the ranks do not have any numerical meaning. In other words, we cannot say that the difference between the first and second ranked cars is the same as the difference between the second and third ranked cars. Therefore, the data can be arranged in an ordering scheme, but differences cannot be found or are meaningless, making the ordinal level of measurement most appropriate.

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