Which expression describes the heat evolved in a chemical reaction when the reaction is carried out at constant pressure?
ae represents internal energy, which can also be symbolized as au. the symbols w and q represent work and heat,
respectively.
ο δε - w
ο δε - q
ο δε

The answer is B 12.5g

Answer:

0.22 moles of air we carry inside our lungs.

Explanation:

An ideal gas is a theoretical gas that is considered to be composed of point particles that move randomly and do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.

The gas laws are a set of chemical and physical laws that allow determining the behavior of gases in a closed system. The parameters evaluated in these laws are pressure, volume, temperature and moles.

The ideal gas law is an equation that relates the variables pressure P, temperature T and volume V if the amount of substance, number of moles n, remains constant and where R is the molar constant of the gases as follows:

P * V = n * R * T

In this case:

Replacing:

0.98 atm* 5.8 L= n* 0.082 \(\frac{atm*L}{mol*K}\) * 310 K

Solving:

\(n=\frac{0.98 atm* 5.8 L}{0.082 \frac{atm*L}{mol*K} *310 K}\)

n= 0.22 moles

0.22 moles of air we carry inside our lungs.

The mass change in grams accompanying the formation of 1 mol Cu and 1 mol H₂O in the following reaction is:

CuO(s) + H₂(g) → Cu(s) + H₂O(g)  ΔH° = +84.5kJ

63.55 grams for Cu and 18.02 grams for H₂O.

To determine the mass change accompanying the formation of 1 mol of Cu and 1 mol of H₂O in the given reaction, we need to consider the stoichiometry of the reaction and the molar masses of the substances involved.

From the balanced chemical equation:

CuO(s) + H₂(g) → Cu(s) + H₂O(g)

We can see that the reaction consumes 1 mol of CuO and 1 mol of H₂ and produces 1 mol of Cu and 1 mol of H₂O.

Let's calculate the molar mass of Cu using the atomic masses:

Molar mass of Cu = 63.55 g/mol

The formation of 1 mol of Cu will have a mass change of 63.55 grams.

Next, let's calculate the molar mass of H₂O:

Molar mass of H₂O = (2 * 1.01 g/mol for hydrogen) + (16.00 g/mol for oxygen)

= 18.02 g/mol

The formation of 1 mol of H₂O will have a mass change of 18.02 grams.

Therefore, the mass change accompanying the formation of 1 mol of Cu and 1 mol of H₂O in the given reaction is 63.55 grams for Cu and 18.02 grams for H₂O.

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Answer: This lab's goal is to investigate the absorbance patterns created by recently discovered moons and planets.

The first moon consists of Lithium and carbon, the second moon consists of sodium and nitrogen. Moving onto the planets, the first planet consists of hydrogen and carbon, and lastly, the second planet is consistent with helium and carbon.

How to explain the lab report

The theory was right; there have been no flaws in the outcome. The astronomical item observed by the spectrometer is the independent variable. The spectrum of any astronomical object is the dependent variable.

Space consists of bodies with different types of the electromagnetic spectrum. This includes high-energy bodies emitting radiation in short wavelengths and extremely short wavelengths such as in UV spectrum, X rays, and gamma rays. Conversely, other bodies might be emitting radiations in the longer wavelengths such as Microwaves and Radio waves.

The element missing from the moons and the planets would be Oxygen. It is to be remembered that Oxygen forms the base of the sustenance of life forms on Earth and forms an indispensable part of the carbon cycle. In the absence of oxygen, these planets and moons remain lifeless.

Stars emit heat and light. Along with the heat and light, radiations are emitted by the star. These radiations travel outward from stars and work as the signature of the stars. By analyzing the radiations from the stars, scientists back on Earth could deduce the physical conditions in the heart of a star including its constitution, temperature, and surface conditions.

The knowledge of the constitution of the elements making up the moon or planet is necessary to ascertain the life-sustaining capability of the same.

Answer: This lab's goal is to investigate the absorbance patterns created by recently discovered moons and planets.

The first moon consists of Lithium and carbon, the second moon consists of sodium and nitrogen. Moving onto the planets, the first planet consists of hydrogen and carbon, and lastly, the second planet is consistent with helium and carbon.

How to explain the lab report

The theory was right; there have been no flaws in the outcome. The astronomical item observed by the spectrometer is the independent variable. The spectrum of any astronomical object is the dependent variable.

Space consists of bodies with different types of the electromagnetic spectrum. This includes high-energy bodies emitting radiation in short wavelengths and extremely short wavelengths such as in UV spectrum, X rays, and gamma rays. Conversely, other bodies might be emitting radiations in the longer wavelengths such as Microwaves and Radio waves.

The element missing from the moons and the planets would be Oxygen. It is to be remembered that Oxygen forms the base of the sustenance of life forms on Earth and forms an indispensable part of the carbon cycle. In the absence of oxygen, these planets and moons remain lifeless.

Stars emit heat and light. Along with the heat and light, radiations are emitted by the star. These radiations travel outward from stars and work as the signature of the stars. By analyzing the radiations from the stars, scientists back on Earth could deduce the physical conditions in the heart of a star including its constitution, temperature, and surface conditions.

The knowledge of the constitution of the elements making up the moon or planet is necessary to ascertain the life-sustaining capability of the same.

Answer:

It would take 21.8 mL of 1.75 M beryllium nitrate solution to produce 5.4 g of aluminum nitrate

Explanation:

Using the balanced chemical equation and the molar mass of aluminum nitrate provided, we can calculate the amount of aluminum nitrate produced from the given mass:

1 mole of aluminum nitrate (Al(NO3)3) has a mass of 213.01 g.

So, 5.4 g of Al(NO3)3 is equivalent to (5.4 g) / (213.01 g/mol) = 0.0254 mol.

From the balanced chemical equation, we can see that 3 moles of beryllium nitrate (Be(NO3)2) produce 2 moles of aluminum nitrate. So, the amount of beryllium nitrate needed to produce 0.0254 mol of aluminum nitrate is:

(0.0254 mol Al(NO3)3) x (3 mol Be(NO3)2 / 2 mol Al(NO3)3) = 0.0381 mol Be(NO3)2

Now we can use the concentration and the amount of beryllium nitrate to calculate the volume of the solution required:

0.0381 mol of Be(NO3)2 is present in (0.0381 mol) / (1.75 mol/L) = 0.0218 L = 21.8 mL of 1.75 M beryllium nitrate solution.

Therefore, it would take 21.8 mL of 1.75 M beryllium nitrate solution to produce 5.4 g of aluminum nitrate, assuming the reaction proceeds to completion.

The standard enthalpy of formation (ΔHf°) is the enthalpy change that occurs when one mole of a compound is formed from its constituent elements, under standard conditions (usually at 25°C and 1 atm pressure).

The equation for the standard enthalpy of formation of liquid carbon tetrachloride (CCl4) can be written as:

CCl4 (l) → CCl4 (l) ΔHf° = ?

In this equation, the reactant is the hypothetical elemental form of carbon (C) and chlorine (Cl2), and the product is liquid carbon tetrachloride (CCl4). The ΔHf° value represents the enthalpy change associated with the formation of one mole of liquid carbon tetrachloride from its constituent elements, at standard conditions.

The specific value of the standard enthalpy of formation of liquid carbon tetrachloride (ΔHf°) can be obtained from reliable sources such as thermodynamic databases or experimental measurements. It represents the energy change associated with the formation of the compound and is usually expressed in units of kilojoules per mole (kJ/mol).

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The most common elemental form of nitrogen is N2 (option 1).

Nitrogen is a chemical element (symbol N) with an atomic number of 7 and atomic weight of 14.0067. It is a colorless and odorless gas.

As earlier said, nitrogen is a gaseous element at room temperature. This means that it naturally exists as a gas in the atmosphere.

The chemical formula of elemental nitrogen is N, however, it exists as atmospheric nitrogen with the chemical formula of N2.

N2 denotes that two atoms of nitrogen have chemically combined to form a nitrogen molecule.

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The volume is occupied by 19.6 g of methane (ch4) at 27 degrees celsius and 1.59 atm will be 18.89 L.

A theoretical gas known as an ideal gas is made up of several randomly traveling point particles with no interparticle interactions. Because it complies with the ideal gas law, a condensed equation of state, and can be examined using statistical mechanics, the ideal gas concept particularly helpful.

Ideal gas equation can be written as:

PV = nRT

P = pressure

V = volume

n = Number of mole

R = gas constant

T = temperature

Given data:

P = 1.59 atm

n = 19.6 g / 16 = 1.22

T = 27 +273= 300 K

Volume can be determined by using the formula:

PV =nRT

1.59 × V = 1.22 × 0.0821 × 300

V = 18.89 L

Therefore, the volume of the methane will be 18.89 L.

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Answer:

194.65 K

Explanation:

(−78.5 °C −109.3 °F)

Answer:

equal to the mass of the solid dry ice.

Explanation:

The mass of the gas is dependent on the mass of the solid dry ice.

The best site for tritium labeling would not exchange the tritium ions for protons in water. All of the N−H sites (II−IV) would readily exchange tritium protons due to their lone pair-facilitating protonation and subsequent tritium exchange with water, but the C−H site (I), lacking a lone pair, would retain its tritium label.

Water is an inorganic, clear, tasteless, odorless, nearly colorless chemical substance that is the main component of the earth's hydrosphere and the fluid of all known living organisms. Although it provides no food, energy, or organic micronutrients, it is essential to all known forms of life.

There are three atoms in the water molecule. Two hydrogen atoms (H) and one oxygen atom (O). This is why water is sometimes called H2O. One drop of water contains billions of water molecules. Water is wet in the sense that it is a highly mobile liquid. This is because the molecules are fairly loosely bound and thus have low viscosity.

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Answer:

si estoy de acuerdo cien por ciento

Answer:

In graphite, each carbon atom is covalently bonded to 3 other carbon atoms. ... These extra electrons are delocalised, or free to move, in the area between layers of carbon atoms. As these electrons are free to move they are able to carry charge and thus graphite can conduct electricity.

Explanation:

Graphite has a layered structure, with each layer consisting of a two-dimensional hexagonal lattice of carbon atoms. Within each layer, carbon atoms are covalently bonded in a flat, trigonal planar arrangement, forming strong σ bonds.

In graphite, carbon atoms are arranged in a flat, hexagonal lattice within each layer, forming strong covalent σ bonds. These layers are stacked on top of each other, held together by weaker van der Waals forces, which allow for easy slippage.

The presence of π bonds between the carbon atoms in each layer results in delocalized π electrons above and below the plane, creating a "sea" of mobile electrons. This delocalization gives graphite its remarkable properties, including electrical conductivity and lubrication.

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Answer:

9.1% error

Explanation:

Full Question:

Answer:

Y E S

Explanation:

Hibiscus tea has plenty of skin care qualities, from helping your natural levels of collagen and elastin to reducing breakouts to balancing oil production. Hibiscus is known for its rich level of antioxidants, including vitamin C and beta-carotene.

I hope this helps ✍(◔◡◔)

The concentration of Ca(OH)2 in the solution is approximately 1.33 x 10^(-6) M.

To find the concentration of Ca(OH)2 in a solution with a pH of 8.57, we need to use the concept of pOH, which is the negative logarithm of the hydroxide ion concentration ([OH-]). The pOH can be calculated by subtracting the pH from 14, which gives us 14 - 8.57 = 5.43.

Since Ca(OH)2 produces two OH- ions for every molecule of Ca(OH)2 that dissolves, the concentration of OH- ions will be twice the concentration of Ca(OH)2. Thus, we have [OH-] = 2x, where x represents the concentration of Ca(OH)2.

Taking the antilogarithm of the pOH, we find that [OH-] = 10^(-pOH) = 10^(-5.43).

Since [OH-] = 2x, we can write 2x = 10^(-5.43) and solve for x.

x = (10^(-5.43))/2 ≈ 1.33 x 10^(-6) M

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Answer: Fluorine

Explanation:

The answer is fluorine as it is in the 9th

Answer:

B, D, C

Explanation:

the solution may have more than one solute, a solution is a homogenous mixture of 2 or more substances and not all solutions are liquid

A solution is formed by the mixture of substances dissolved in water. There may have more than one solute. Not all solutions are liquid but there exists solid solutions too. Hence, options A, B, C are correct.

A solution is a combination of a solvent and a solid solute. The solute can be completely dissolved in the solvent and can have a partial solubility.

Water is a good solvent which dissolve majority of compounds. But there are other solvents too forming solution with suitable solutes. Solutions can be homogenous or heterogenous. Homogenous solutions are forming one phase and the solute particles are uniformly arranged.

Heterogeneous solutions are those where the solute particles are arranged in a non-uniformity and they form a different phase from the solvent.

There can be more than one solute in a solution provided that the solute can be of miscibility with each other.

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By using the ideal gas law to get volume we have"

Where v is volume, T is temperatute, n is number of moles, R is the molar gas constant and P is pressure. At STP P= 101,325 Pa, T= 273.15 K and R= 8.314 J/mol K

We must first convert mass to moles:

By substituting this value into the ideal gas law we have:

1.9502e-6L of H2 gas reacted at STP

The order of a reaction refers to the power to which the concentration of a reactant or product is raised in the rate law equation. The rate law equation describes the rate of a reaction as a function of the concentration of the reactants.

For example, if the rate law equation for a reaction is given by Rate = k [A]² [B]³, then the reaction is second-order with respect to A and third-order with respect to B. The overall reaction order is the sum of the orders of all the reactants in the rate law equation, which in this case would be (2 + 3) = 5.

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The balanced half-reactions are: Oxidation half-reaction: 4Co → 4Co2+ + 8e-Reduction half-reaction: O2 + 2e- → 2O2 -

Given equation: 3O2+4Co⟶2Co2O3Using the symbol e− for an electron. The redox reaction can be broken down into two half-reactions. The reduction half-reaction is the one in which a species gains electrons and the oxidation half-reaction is the one in which a species loses electrons. The half-reactions are as follows: Reduction Half-reaction Half-reaction equation: O2 + 2e- → 2O2 -Oxidation number of oxygen in O2=0 and in O2^-= -1Charge on the left side = 0Charge on the right side = 2 x (-1) = -2Thus, 2 electrons are added to the left side to balance the charge, making the half-reaction:O2 + 2e- → 2O2 -Oxidation Half-reaction Half-reaction equation: 4Co → 4Co2+ + 8e-Oxidation number of cobalt in Co=0 and in Co2+ =+2Charge on the left side = 0Charge on the right side = 4 x (+2) + 8 x (-1) = -4Thus, 8 electrons are added to the right side to balance the charge, making the half-reaction:4Co → 4Co2+ + 8e-Thus, the balanced half-reactions are: Oxidation half-reaction: 4Co → 4Co2+ + 8e-Reduction half-reaction: O2 + 2e- → 2O2 -

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The slow carbon cycle involves processes that take place over geological timescales, including the transfer of carbon between the atmosphere, oceans, rocks, and soils. The total amount of carbon in each of these reservoirs can change over time due to various factors, such as natural and human-induced processes.

One part of the slow carbon cycle in which the total amount of carbon is most likely decreasing the most is the process of sedimentation of organic matter in ocean sediments. This occurs because the organic matter that sinks to the seafloor is buried and undergoes diagenesis, a process by which it is transformed into more stable forms of carbon, such as kerogen or graphite. The decrease in carbon occurs because the rate of sedimentation of organic matter is faster than the rate of carbon input from sources such as volcanoes, weathering of rocks, and human activities.

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Answer:

Carbon

Explanation:

Carbon has 6 valence electrons and 4 electron shells.

Answer:

0.59

Explanation:

Is 0.59 because you are dividing 35.0g by 58.5 which will than give you 0.59

Answer: Group 18, non-reactive noble gas

Explanation:

This electron configuration denotes the elements Argon. It is at the end of the 3p subshell and we can tell this because it says 6 for the value in 3p. This element is in group 18 and something important about that group is that they are typically non-reactive gases, because they have a full electron shell.

Group 18

non-reactive noble gas

The approximate pH of a 0.10 M solution of a weak acid with a Ka of 5x10-5 M is 4.8.

To calculate the approximate pH of a weak acid solution, we can use the Henderson-Hasselbalch equation, which states that pH = pKa + log([A-]/[HA]).

In this equation, [A-] is the concentration of the conjugate base and [HA] is the concentration of the weak acid. In this case, [HA] is 0.10 M and [A-] is 5x10-5 M.

Calculate the molarity of the weak acid:

Molarity = 0.10 m (given)

Calculate the Ka of the weak acid:

Ka = 5 x 10-5 m (given)

Calculate the concentration of the conjugate base:

Conjugate base concentration = Ka x molarity = 5 x 10-5 m x 0.10 m = 5 x 10-6 m

Calculate the pH of the solution:

pH = -log[conjugate base] = -log(5 x 10-6) = 4.8

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The true structure of a resonance hybrid is a weighted average of all possible resonance structures. It is stabilized because electron density is delocalized over two or more atoms.

Resonance structures are different representations of a molecule or ion that can be obtained by moving electrons while keeping the overall arrangement of atoms unchanged. These resonance structures differ in the placement of double bonds, lone pairs, or formal charges. The resonance hybrid represents the actual molecule or ion, which is a combination of all the resonance structures.

The electron density in a resonance hybrid is spread out or delocalized over multiple atoms. This delocalization of electron density provides stability to the molecule or ion. It prevents excessive accumulation of charge in one area and allows for a more even distribution of electron density.

Overall, the resonance hybrid is a representation of the weighted average of all resonance structures, and its stability arises from the delocalization of electron density over two or more atoms.

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Answer:

  The probability would be 50%.                                                    

Answer:

Your first flip has a 1/2 or 50% chance of getting tails. In order to get 2 tails in a row you have to get tails first and then again. The first flip is 1/2 and the second one is another 1/2. Combined you have a 1/4 chance of getting 2 tails in a row.

Each time you flip you have 1/2 a chance, but when you look at all the flips at once, each consecutive flip of the same side has a smaller probability.

A suitable hypothesis for the above experiment conducted by the chemist is as follows: IF the temperature is increased, THEN the rate of chemical change will also increase.

Experiment is a test under controlled conditions made to either demonstrate a known truth, examine the validity of a hypothesis, or determine the efficacy of something previously untried.

A hypothesis is an educated guess or a tentative conjecture explaining an observation or scientific problem.

According to this question, a chemist is designing an experiment to investigate the effect of temperature on the rate of a chemical change.

This suggests that a suitable hypothesis for the above experiment conducted by the chemist is as follows: IF the temperature is increased, THEN the rate of chemical change will also increase.

Also, the Independent variable is the temperature because it is the variable that is changed.

Dependent variable is the rate of chemical change because it is the measured variable.

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Answer:

A suitable hypothesis for the above experiment conducted by the chemist is as follows: IF the temperature is increased, THEN the rate of chemical change will also increase.

Independent variable - Temperature

Dependent variable - Rate of chemical change

controlled variable - pressure or concentration of the reactants