Which example best shows a person using the principle of force in an activity?
A skydiver drops from a plane and descends to earth.
A bowler throws a bowling ball that rolls down the lane
O A coach uses signals to send a play to a quarterback
A hockey player abruptly stops after hitting the rink wall
1 2
3

Answer:

-30m

Explanation:

displacement = final position - initial position, or d = -20-10

The formula for kinetic energy is given as K.E = ¹/₂mv².

Kinetic energy is a type of mechanical energy, and it is defined as the energy possessed by a body due to its motion.

Mathematically, the formula for kinetic energy is given as;

K.E = ¹/₂mv²

where;

From the formula given in the equation above, we can conclude that the kinetic energy of a body increases as the speed of the object increases since mass is always constant.

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Answer:

Hunter is a electrician

Answer: He's an Electrician !

Explanation:

Check the images.. it has a few different questions and answers! Hope it helps

The irrigation frequency is approximately 88.89 and the irrigation period is 3000 hours.

I. To determine the localized ETc (crop evapotranspiration) at peak demand for matured grape plantation, we can use the following formula:

ETc = ETo × Kc × Kr × Groundcover

Given:

ETo (reference evapotranspiration) at peak demand = 6.5 mm/d

Kc (crop coefficient) = 1.2

Kr (reduction coefficient) = 0.94

Groundcover = 80% (0.8)

Calculating:

ETc = 6.5 × 1.2 × 0.94 ×0.8

ETc = 5.11744 mm/d

Therefore, the localized ETc at peak demand for the matured grape plantation is approximately 5.12 mm/d.

II. To calculate the peak net and gross water requirements for mango plantation on sandy soil, we use the formula:

Net Requirement = ETc / Ks

Gross Requirement = Net Requirement / EU

ETc (localized ETc) = 5.12 mm/d

Ks (soil water stress coefficient) = 0.91

EU (water use efficiency) = 85% (0.85)

Calculating Net Requirement:

Net Requirement = 5.12 / 0.91

Net Requirement = 5.62 mm/d

Calculating Gross Requirement:

Gross Requirement = 5.62 / 0.85

Gross Requirement = 6.62 mm/d

Therefore, the peak net water requirement for mango plantation on sandy soil is approximately 5.62 mm/d, and the peak gross water requirement is approximately 6.62 mm/d.

b. To determine the number of emitters per plant, we can use the following formula:

Number of emitters = Wetted area per plant / Wetted area per emitter

Tree spacing = 6 m x 6 m

Percent wetted area (Pw) = 50%

Wetted area for sandy soil = 2 m²

Calculating Wetted area per plant:

Wetted area per plant = Tree spacing ×Tree spacing ×Pw

Wetted area per plant = 18 m²

Calculating Number of emitters per plant:

Number of emitters per plant = Wetted area per plant / Wetted area per emitter

Number of emitters per plant = 18 / 2

Number of emitters per plant = 9 emitters

Therefore, the number of emitters per plant is 9.

c. To determine the irrigation frequency and irrigation period, we need to consider the effective rooting depth, soil available moisture content, manageable allowable depletion, and drip emitter discharge.

Effective rooting depth = 1000 mm

Soil available moisture content = 15 cm/m

Manageable allowable depletion = 25% (0.25)

Drip emitter discharge = 0.005 m³/h

Calculating Irrigation Frequency:

Irrigation Frequency = Effective Rooting Depth / (Soil Available Moisture Content × (1 - Manageable Allowable Depletion))

Irrigation Frequency = 1000 / (15 × (1 - 0.25))

Irrigation Frequency = 1000 / (15 × 0.75)

Irrigation Frequency = 1000 / 11.25

Irrigation Frequency ≈ 88.89

Calculating Irrigation Period:

Irrigation Period = Wetted Depth / Drip Emitter Discharge

Irrigation Period = 15 / 0.005

Irrigation Period = 3000 hours

Therefore, the irrigation frequency is approximately 88.89 and the irrigation period is 3000 hours.\

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Relative humidity indicates the nearness to saturation for the air, which means the amount of water vapor present in the air relative to the maximum amount the air can hold at that temperature. So the correct option is b.

Relative humidity indicates the nearness to saturation for the air. Relative humidity is a measure of the amount of moisture present in the air compared to the maximum amount of moisture the air could hold at a particular temperature, expressed as a percentage. It is a measure of how close the air is to being saturated with moisture. When the relative humidity is 100%, the air is fully saturated and cannot hold any more moisture, which often leads to the formation of clouds or precipitation. Conversely, when the relative humidity is lower, the air has the capacity to hold more moisture before reaching saturation. Relative humidity is an important parameter in weather forecasting, as it can affect various atmospheric processes such as cloud formation, evaporation, and precipitation.

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Explanation:

the particles in liquids and gases move faster when they are heated than they do when they are cold. As a result, the particles take up more volume.

Answer:

I believe the answer is A, it is to the west as the right ascension is only east and west

Explanation:

When i took the quiz, I put east and had gotten it incorrect.

The momentum- space wave function, Ф(p) is (mω/πħ)1/4 (1/√2) exp(-p²/2mωħ) and the probability density of finding the particle with momentum, p is (mω/πħ)1/2 exp(-p²/mωħ).

The wavefunction of a particle in the ground state of a one-dimensional harmonic oscillator potential can be written as:

Ψ(x) = (mω/πħ)1/4 exp[-(mω/2ħ)x²]

where ħ is the reduced Planck's constant.

The momentum-space wavefunction is the Fourier transform of the position-space wavefunction:

Φ(p) = (1/√(2πħ)) ∫ exp(-ipx/ħ) Ψ(x) dx

Substituting the expression for Ψ(x) and performing the integration, we obtain:

Φ(p) = (mω/πħ)1/4 (1/√2) exp(-p²/2mωħ)

The probability density of finding the particle with momentum p is given by the square of the momentum-space wavefunction:

|Φ(p)|² = (mω/πħ)1/2 exp(-p²/mωħ)

This is a Gaussian distribution centered at p=0 with a standard deviation of ħ/√(2mω), which is the uncertainty in the momentum of the particle due to the Heisenberg uncertainty principle.

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The question is -

Consider a quantum particle with mass, m, in the ground state of a one-dimensional harmonic oscillator potential with the trapping frequency, ω. Calculate the momentum- space wave-function, Ф(p), and the probability density of finding the particle with momentum, p.

\({ \qquad\qquad\huge\underline{{\sf Answer}}} \)

By formula ;

" Force = Mass × Acceleration "

So, let's proceed ~

\(\qquad \sf  \dashrightarrow \: f = m \times a\)

\(\qquad \sf  \dashrightarrow \: f = 3 \times 8\)

\(\qquad \sf  \dashrightarrow \: f = 24 \: \: N\)

Therefore, the force required to throw that ball provided the given conditions will be 24 Newtons ~

The correct option is option 3.

To find the angular acceleration of the tire, we can use the formula:

angular acceleration (α) = (final angular speed - initial angular speed) / time

Given:

Number of revolutions (n) = 4.73 rev

Time (t) = 1.78 s

First, let's convert the number of revolutions to radians:

Angle (θ) = n * 2π

Substituting the values:

θ = (4.73 rev) * (2π rad/rev)

Now, we can calculate the initial angular speed (ω_initial) using the formula:

ω_initial = 0 rad/s (as the tire starts from rest)

Next, let's calculate the final angular speed (ω_final) using the formula:

ω_final = θ / t

Now, we can calculate the angular acceleration (α) using the formula:

α = (ω_final - ω_initial) / t

Substituting the values:

α = (ω_final - 0 rad/s) / t

Now, let's calculate the angular acceleration:

α = ω_final / t

Substituting the values:

α = (θ / t) / t

Calculating the result:

α ≈ 31.14749 rad/s²

Therefore, the angular acceleration of the tire is approximately 31.14749 rad/s².

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I assume you want to find the magnitudes of the horizontal and vertical components of the velocity and the maximum height reached by the cannonball.

Using the given initial velocity of 30 m/s and angle of 60 degrees above the horizontal, we can find the horizontal and vertical components of the velocity as:

vx = v0 cosθ = 30 cos(60) = 15 m/s

vy = v0 sinθ = 30 sin(60) = 25.98 m/s

The magnitude of the horizontal component of the velocity is 15 m/s, and the magnitude of the vertical component of the velocity is 25.98 m/s.

To find the maximum height reached by the cannonball, we can use the equation:

y = y0 + vy0t - (1/2)gt^2

where y0 is the initial height (assume it is zero), vy0 is the initial vertical velocity (25.98 m/s), g is the acceleration due to gravity (-9.8 m/s^2), and t is the time it takes for the cannonball to reach its maximum height.

At the maximum height, the vertical velocity is zero, so we can set vy = 0 and solve for t:

0 = 25.98 - 9.8t

t = 2.65 s

Now we can use this time to find the maximum height:

y = 0 + 25.98(2.65) - (1/2)(9.8)(2.65)^2

y ≈ 34.3 m

Therefore, the magnitudes of the horizontal and vertical components of the velocity are 15 m/s and 25.98 m/s, respectively, and the maximum height reached by the cannonball is approximately 34.3 meters.

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As the distance between charged tape and charged rod decreases, the force of interaction between them increases.

The force of interaction between the charged tape and charged rod is governed by Coulomb's Law.

This law states that the force between two charged objects is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.

So, as the distance between the charged tape and charged rod decreases, the force of interaction increases.

This is because the charges on the objects are now closer to each other, allowing for a stronger attraction or repulsion, depending on the nature of the charges (like charges repel, opposite charges attract).

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The urban legend of the car thief is an example of A Cautionary Tale.

A cautionary tale makes reference to a given tale aimed at the warning the person of some type of danger, which is generally used to alert about a given behavior and may be very useful to modify a behavior pattern in children.

Therefore, with this data, we can see that A cautionary tale is based on warning and can help to modify certain behavior in c children depending on the ability to create conscious.

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Answer:

ok what is the question

Explanation:

I don't know what the question is

Answer:

Most certainly yes

Explanation: First you have to define what friction is "A force that resist motion" while Mechanical advantage " is simply a measure of the output force to the input force". Hence in a mechanical system if you increase friction in the system, it reduces the mechanical advantage and vice versa.

Answer:

Heavier than 2.2 pounds

Explanation:

In Part A, if the force is doubled, the acceleration of the object will also double. In Part B, if the object's mass is doubled, the acceleration will be halved. In Part C, if both the force and the object's mass are doubled, the acceleration will remain the same. In Part D, if the force is doubled and the object's mass is halved, the acceleration will be quadrupled.

According to Newton's second law of motion, the acceleration of an object is directly proportional to the force applied and inversely proportional to its mass. Mathematically, this can be represented as F = ma, where F is the force, m is the mass, and a is the acceleration.

In Part A, if the force is doubled while keeping the mass constant, the acceleration will also double. This is because the force and acceleration are directly proportional.

In Part B, if the object's mass is doubled while keeping the force constant, the acceleration will be halved. This is because the mass and acceleration are inversely proportional.

In Part C, if both the force and the object's mass are doubled, the acceleration will remain the same. This is because doubling both the force and the mass cancels out the effect on acceleration.

In Part D, if the force is doubled and the object's mass is halved, the acceleration will be quadrupled. This is because doubling the force and halving the mass results in a net effect of four times the acceleration.

Therefore, the relationship between force, mass, and acceleration can be summarized as follows: doubling the force or halving the mass results in a proportional change in acceleration.

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When the radius is multiplied by x, acceleration changes by a factor of 1/x.

Acceleration is a measure of how quickly the velocity of an object changes over time. It is defined as the rate of change of velocity, and is usually expressed in units of meters per second squared (m/s^2).

The acceleration of an object moving in a circular path depends on its speed and the radius of the circle. Specifically, the acceleration of the object is given by the formula a = v^2/r, where v is the speed of the object and r is the radius of the circle.

If we multiply the radius by a factor of x, the acceleration of the object will change. To see how this happens, let's rewrite the formula for acceleration in terms of x. We have:

a = v^2/(rx)

Since v is constant, the acceleration is inversely proportional to the radius. This means that if we increase the radius by a factor of x, the acceleration will decrease by a factor of x^(-1), or 1/x. Similarly, if we decrease the radius by a factor of x, the acceleration will increase by a factor of x.

For example, let's say we have an object moving in a circular path with a radius of 2 meters and a speed of 10 m/s. The acceleration of the object is:

a = (10 m/s)^2 / 2 m = 50 m/s^2

If we multiply the radius by a factor of 3, the new radius is 6 meters, and the acceleration becomes:

a = (10 m/s)^2 / 6 m = 16.67 m/s^2

This is approximately one-third of the original acceleration. Similarly, if we divide the radius by a factor of 2, the new radius is 1 meter, and the acceleration becomes:

a = (10 m/s)^2 / 1 m = 100 m/s^2

This is twice the original acceleration.

In summary, the acceleration of an object moving in a circular path is inversely proportional to the radius of the circle. If we multiply the radius by a factor of x, the acceleration will change by a factor of 1/x.

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The hydronium ion concentration in the HCl solution with a pH of 4.65 is approximately 2.2 x 10⁻⁵ M. On the other hand, the hydroxide ion concentration in the NH₃ solution is approximately ≈ 2.2 x 10⁻⁵ M

To calculate the hydronium ion (H3O+) concentration in a solution of HCl with a pH of 4.65, you can use the formula: pH = -log [H3O+].

First, you'll need to rearrange the formula to solve for [H3O+]. You can do this by taking the inverse logarithm (antilog) of both sides:
[H3O+] = 10^(-pH)

Now, plug in the given pH value of 4.65:
[H3O+] = 10^(-4.65)

Calculating the value, you get:
[H3O+] ≈ 2.2 x 10⁻⁵ M

So, the hydronium ion concentration in the HCl solution with a pH of 4.65 is approximately 2.2 x 10⁻⁵ M.

The pOH is defined as the negative logarithm (base 10) of the hydroxide ion concentration ([OH-]).

The relationship between pOH and [OH-] is as follows:

pOH = -log[OH-]

To find [OH-], we rearrange the equation:

[OH-] = 10^(-pOH)

Given a pOH of 4.65, we can calculate the hydroxide ion concentration as follows:

[OH-] = 10^(-4.65)

[OH-] ≈ 2.2 x 10⁻⁵ M

The hydroxide ion concentration in the NH₃ solution is approximately ≈ 2.2 x 10⁻⁵ M (moles per liter)

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Answer:

avoid verbal argument and walk away

C) the visible light from planets will be blocked by interstellar dust along our line of sight while the IR radiation will not

The essential reason why it is way better to rummage around for extrasolar planets straightforwardly utilizing infrared radiation instead of obvious radiation is that interstellar tidy can square obvious light, but not infrared radiation.

As light voyages through space, it can experience tidy particles that scramble and assimilate the light.

This could make it troublesome to identify planets that are found behind interstellar clean clouds. In differentiation, infrared radiation can enter through tidy clouds, permitting us to watch planets that would be imperceptible in unmistakable light.

Additionally, a few planets emit more infrared radiation than they reflect in obvious light, making them simpler to identify within the infrared spectrum.

Usually particularly true for gas monster planets, which are exceptionally hot and radiate a parcel of infrared radiation.

In any case, this can be not the essential reason why it is way better to rummage around for extrasolar planets utilizing infrared radiation.

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On March 17, 2019 Chloe Cunliffe, a senior high school student from West Seattle High School, vaulted 4.48 m to earn the position of top female athlete in the United States. If Chloe weighed 49 kilograms on the day of the jump, her maximum potential energy was (P)= 2.15 kJ.

Energy is a physical term that means a object of mass m how much work have been done on it. It called the energy. It can be measured by Joule.

To calculate the energy we are using the formula,

P=mgh

Here we are given,

m= The mass of the body. = 49 kg.

g= The acceleration due to gravity. = 9.8 m/s²

h= The height of the jump. = 4.48 m

Now we have to calculate the potential energy of the body = PJ.

Now we put the values in above equation,

P=mgh

or, P= 49*9.8*4.48

Or, P=2,151.296 J

Or, P=2.151 kJ

So we can say that, If Chloe weighed 49 kilograms on the day of the jump, her maximum potential energy was (P)= 2.15 kJ.

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To read a ruler in cm, locate the zero mark on the ruler, then read the measurement where the object being measured ends, aligning the end of the object with the appropriate line on the ruler, and counting the number of centimeters to that line.

When reading a ruler in cm, it is important to identify the zero mark on the ruler and align it with the beginning of the object being measured. Then, locate the end of the object and align it with the appropriate line on the ruler, counting the number of centimeters to that line.

Each centimeter on the ruler is divided into 10 smaller units called millimeters, so it is also possible to measure to the nearest millimeter by identifying the smallest line on the ruler that aligns with the end of the object.

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This lamp's estimated current consumption is 8 amperes.

Electric current is the rate of charge (electron) passing in a conductor. The SI unit for electric current is the ampere. As current does not obey vector addition, it is a scalar quantity.

Given information:

amount of charge flowing through the lamp, Q = 28800 C;

The charge flow time was t = 1 hour = 3600 seconds.

Hence, the current passing through the bulb as a result.

I = Q/t

= 28800/3600 ampere,

= 8 ampere

Therefore, this lamp consumes 8 amperes of current.

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Answer:

1)  10 kg-m/s

2)  2 kg

3)  20 m/s

Explanation:

The momentum of an object can be calculated using the equation:

\(\large\boxed{p=mv}\)

where:

\(\hrulefill\)

For this question we need to find the momentum of a bowling ball whose mass is 4.0 kg is rolling at a rate of 2.5 m/s.

Given values:

Substitute the given values into the momentum formula and solve for p:

\(p=4.0\;\text{kg} \cdot 2.5\;\text{m/s}\)

\(p=10\;\text{kg m/s}\)

Therefore, the momentum of the bowling ball is 10 kg-m/s.

\(\hrulefill\)

For this question we need to find the mass of a skateboard rolling at a velocity of 3.0 m/s with a momentum of 6.0 kg-m/s.

Given values:

As we want to find mass, rearrange the momentum formula to isolate m:

\(\large\boxed{m=\dfrac{p}{v}}\)

Substitute the given values into the formula and solve for m:

\(m=\dfrac{6.0\; \text{kg m/s}}{3.0\; \text{m/s}}\)

\(m=2\;\text{kg}\)

Therefore, the mass of the skateboard is 2 kg.

\(\hrulefill\)

For this question we need to find the velocity of a baseball with a mass of 0.5 kg and a momentum of 10 kg-m/s.

Given values:

As we want to find velocity, rearrange the momentum formula to isolate v:

\(\large\boxed{v=\dfrac{p}{m}}\)

Substitute the given values into the formula and solve for v:

\(v=\dfrac{10\; \text{kg m/s}}{0.5\; \text{kg}}\)

\(v=20\;\text{m/s}\)

Therefore, the velocity of the baseball is 20 m/s.

Answer:

Nedecito puntos para mi tares

The cooling power P is a measure of the rate at which energy is removed from a system, typically in the form of heat.

If the cooling power is constant, it means that the rate at which energy is removed from the system remains the same over time.

In other words, if a system is losing heat at a constant rate, then the cooling power is constant. Mathematically, the cooling power P is given by:

P = Q/t

where Q is the amount of heat removed from the system and t is the time interval over which the heat is removed.

The units of cooling power are typically expressed in watts (W), which is equivalent to joules per second (J/s).

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