Which equations have a greater unit rate than the rate represented in the table?
xy
32
64
96
Oy=5¹
0 y=r
Oy=11³

The 0.0035 hr⁻¹ first-order degradation rate constant in the 40 °C, 1.0 mg/ml solution, where R = 1.987 cal/mol/degree and 2,000 cal/mol activation energy indicates;

a. The rate constant for first-order degradation of N₂O₂ at room temperature is approximately 4.12595 × 10⁻² hr⁻¹

A first order reaction is one that has a rate that varies linearly with the concentration of one reactant

The given parameters are;

Temperature of the solution = 40°C

T₁ = 40 °C + 273.15 = 313.15 K

The rate constant, K₁ = 0.00351 hr⁻¹

Concentration of the solution = 1.0 mg/ml

Activation energy, Eₐ = 2000 Cal/mol

R = 1.987 cal/mol/degree

The formula by which the rate constant can be found is presented as follows;

\(log\dfrac{k_2}{k_1} =\dfrac{E_a}{2.303\times R} \times \dfrac{T_2-T_1}{T_1\cdot T_2}\)

a. Room temperature = 25 °C

T₂ = 25 °C + 273.15 = 298.15 K

Therefore;

\(log\dfrac{k_2}{0.00351} =\dfrac{2000}{2.303\times 1.987} \times \dfrac{313.15-298.15}{313.15 \times 298.15}\)

\(k_2=0.00351 \times 10^{\left(\dfrac{2000}{2.303\times 1.987} \times \dfrac{313.15-298.15}{313.15 \times 298.15}\right)} \approx 4.12595\times 10^{-2}\)

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Answer: $97.75

Step-by-step explanation:

Ali's dad paid for 7 players, so the cost for just the entrance fee was $10.50 x 7 = $73.50. He paid a total of $76.75, so the scorecard fee must have been $76.75 - $73.50 = $3.25.

If he pays for 9 players, the cost of the entrance fee will be $10.50 x 9 = $94.50. Adding the scorecard fee of $3.25, the total cost will be $94.50 + $3.25 = $97.75.

Therefore, he will need to pay $97.75 if he ends up paying for 9 players. The answer is option D.

Answer:

mynumber 67895437895473

Step-by-step explanation:

Answer:

  see below

Step-by-step explanation:

The first answer choice is the only one that has the first sale correctly represented. Each term is the product of the number of pens of the type and the cost of pens of that type.

  12 dozen roller-ball pens will have a cost of 12x

  5 dozen ballpoint pens will have a cost of 5y

The total cost of these will be 116 (dollars).

The equation is written ...

  12x +5y = 116 . . . . . . . this equation is only found in choice A

The probability that each bill is a $1 bill is given as follows:

1/16.

A probability is calculated as the division of the desired number of outcomes by the total number of outcomes.

The bills are replaced, hence we consider that for each trial, there is a 1/4 probability of selecting a $1 bill, as one out of the four bills are of $1.

Hence the probability that each bill is a $1 bill is obtained as follows:

p = 1/4 x 1/4

p = 1/16.

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The equation of the line perpendicular to y = 5x + 4, passing through the point (1, -2), is y = (-1/5)x - 9/5.

To find an equation in slope-intercept form that passes through the point (1, -2) and is perpendicular to the given equation y = 5x + 4, we need to determine the slope of the perpendicular line.

The given equation y = 5x + 4 is already in slope-intercept form (y = mx + b), where m represents the slope. In this case, the slope of the given line is 5.

To find the slope of a line perpendicular to this, we use the fact that the product of the slopes of two perpendicular lines is -1. So, the slope of the perpendicular line can be found by taking the negative reciprocal of the slope of the given line.

The negative reciprocal of 5 is -1/5.

Now that we have the slope (-1/5) and a point (1, -2), we can use the point-slope form of the equation:

y - y1 = m(x - x1)

Substituting the values:

y - (-2) = (-1/5)(x - 1)

Simplifying:

y + 2 = (-1/5)(x - 1)

To convert the equation into slope-intercept form (y = mx + b), we need to simplify it further:

y + 2 = (-1/5)x + 1/5

Subtracting 2 from both sides:

y = (-1/5)x + 1/5 - 2

Combining the constants:

y = (-1/5)x - 9/5

Therefore, the equation of the line perpendicular to y = 5x + 4, passing through the point (1, -2), is y = (-1/5)x - 9/5.

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Answer:

Step-by-step explanation:

For each ounce of strawberry juice, Molly uses two times as many ounces of water. This means that for every one ounce of strawberry juice, she will use two ounces of water.

Let's call the amount of strawberry juice she uses "x" (in ounces). Then, the amount of water she will need to add is 2x.

So, the total amount of liquid (in ounces) will be x + 2x = 3x.

We know that the total amount of strawberry infused water she wants to make is 72 ounces. So, we can set up the equation:

3x = 72

Solving for x, we get:

x = 24

Therefore, Molly needs 24 ounces of strawberry juice and 2 times as much water, which is 2x = 2 * 24 = 48 ounces of water to make 72 ounces of strawberry infused water.

Answer:

5 years

Step-by-step explanation:

Since the tree grows 4 feet every single year and the second year it was 12 feet tall then that means that when you bought the tree it was 8 feet tall (12-4 = 8). Therefore, using these values we can write an equation to calculate the number of years it will take for the height of the tree to be 28 feet. We do this by multiplying 4ft by the variable of a number of years (x) and then adding that product to 8ft which is the initial height. All of which should add up to 28 ft.

28 ft. = 8 ft. + 4x    ... subtract both sides by 8

20 ft. = 4x   ... divide both sides by 4

5 years = x

Therefore, it will take 5 years from the initial purchase for the tree to be 28ft tall.

Answer:

27

Step-by-step explanation:

The area of this parallelogram is its base times height. 6x4.5 is 27.

Hope this helps! (please mark me brainliest)

Answer:

4x(3y+1)

Step-by-step explanation:

Hey there! Here is your answer:

102,600 would be in a group. 19 would not be in a group.

Step-by-step explanation:

We can figure this out by doing 102,619 divided by 57. This gives us:

1,800 R 19

Now we need to multiply 1800 by 57 to see how many residents there are:

1,800 x 57 = 102,600

Our remainder tells us how many residents would not fit into a group. Since our remainder is 19, 19 would not be in a group.

I hope this helps!

Answer:

We conclude that a compact microwave oven consumes a mean of more than 250 W.

Step-by-step explanation:

We are given that an appliance manufacturer claims to have developed a compact microwave oven that consumes a mean of no more than 250 W with a population standard deviation of 15 W.

They take a sample of 20 microwave ovens and find that they consume a mean of 257.3 W.

Let \(\mu\) = mean power consumption for microwave ovens.

So, Null Hypothesis, \(H_0\) : \(\mu\) \(\leq\) 250 W     {means that a compact microwave oven consumes a mean of no more than 250 W}

Alternate Hypothesis, \(H_A\) : \(\mu\) > 250 W     {means that a compact microwave oven consumes a mean of more than 250 W}

The test statistics that would be used here One-sample z test statistics as we know about the population standard deviation;

                                T.S. =  \(\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }\)  ~ N(0,1)

where, \(\bar X\) = sample mean power consumption for ovens = 257.3 W

            σ = population standard deviation = 15 W

            n = sample of microwave ovens = 20

So, the test statistics  =  \(\frac{257.3-250}{\frac{15}{\sqrt{20} } }\)

                                      =  2.176

The value of z test statistics is 2.176.

Now, at 0.05 significance level the z table gives critical value of 1.645 for right-tailed test.

Since our test statistic is more than the critical value of t as 2.176 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that a compact microwave oven consumes a mean of more than 250 W.

using SOH CAH TOA

Tan 85.144 =h/130

h=tan 85.144*130

h=1530.19 fr

Answer:

If i´m correct and read the answer correct it should be:

-18x³+80x²+65x+5

Step-by-step explanation:

Hopefully this is correct, I couldn't understand if (-2x 2+10x) was spaced or if it was being multiplied.

The diagrams given above that represents a parallelogram is indicated by Yes in the following numbers:

1.). yes 5.) No. 9.) No

2.).yes 6.) No

3.) yes 7.) No

4.) yes 8.) yes

A parallelogram is defined as the type of quadrilateral that has four sides and has the following unique properties and characteristics such as follows:

Therefore, in conclusion, the diagram that exhibit the properties of a parallelogram are numbers, 1,2,3,4 and 8 while the rest are not parallelograms.

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Answer:

8

Step-by-step explanation:

f(x) = 2x + 8

x=0

f(0) = 2(0) + 8

f(0)=0+8

f(x)=8

Answer:

8

Step-by-step explanation:

f(x)=2x+8

x=0

f(0)=2(0)+8

f(0)=0+8

F(0)=8

Step-by-step explanation:

y = mx + b

m = 3

b = 2

y = 3x + 2

______________________

y = mx + b

m = 1/2

b = -1

y = 1/2x + (-1)

y = 1/2x -1

The airplane's groundspeed is approximately 242.25 km/h, and the resultant bearing is approximately 55.04° (relative to true north, measured clockwise).

How to solve for the airplane's groundspeed

To determine the resultant velocity of the airplane, we need to break down the airplane's velocity and the wind's velocity into their respective components and add them. Let's assume that the angles are measured clockwise from true north.

Let's denote:

Vp = airplane's speed = 250 km/h

θp = airplane's heading = 075 degrees

Vw = wind's speed = 85 km/h

θw = wind's heading = 300 degrees

We can then find the eastward (x) and northward (y) components of the velocities:

For the airplane:

Vpx = Vp * cos(θp) = 250 * cos(75 degrees) = 64.95 km/h

Vpy = Vp * sin(θp) = 250 * sin(75 degrees) = 241.92 km/h

For the wind:

Vwx = Vw * cos(θw) = 85 * cos(300 degrees) = 73.60 km/h

Vwy = Vw * sin(θw) = 85 * sin(300 degrees) = -42.50 km/h

We then sum the x and y components of the two velocities to find the resultant velocity components:

Vrx = Vpx + Vwx = 64.95 km/h + 73.60 km/h = 138.55 km/h

Vry = Vpy + Vwy = 241.92 km/h - 42.50 km/h = 199.42 km/h

The magnitude of the resultant velocity, which represents the groundspeed (Vr), is found using the Pythagorean theorem:

Vr = sqrt((Vrx)^2 + (Vry)^2) = sqrt((138.55)^2 + (199.42)^2) = 242.25 km/h

The bearing (θr) of the resultant velocity (relative to north) can be found using inverse tangent:

θr = atan2(Vry, Vrx) = atan2(199.42, 138.55) = 55.04 degrees

Therefore, the airplane's groundspeed is approximately 242.25 km/h, and the resultant bearing is approximately 55.04° (relative to true north, measured clockwise).

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The basic ratio of minutes of painting to minutes of instruction is 7 : 6

From the question, we have the following parameters that can be used in our computation:

Painting = 63 minutes

Instruction = 54 minutes

The ratio can be represented as

Ratio = Painting : Instruction

When the given values are substituted in the above equation, we have the following equation

Painting : Instruction = 63 : 54

Simplify

Painting : Instruction = 21 : 18

Simplify

Painting : Instruction = 7 : 6

This  ratio cannot be simplified

Hence, the solution is 7 : 6

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(a) The equation of the secant line connecting (1, f(1)) and (0.9, f(0.9)) is y = -x + 2.1.

(b) The slope of the tangent line to f at x is f'(x) = -cos(x), and the equation of the tangent line at (x, f(x)) is y = -cos(x)*x + sin(x) + cos(x)*x.

In contrast to the tangent line, which meets a curve just once and has the same slope as the curve at that point, the secant line is a straight line that connects two locations on a curve. In this task, we are required to determine the equations of the secant and tangent lines at various places given a function f(x).

Using the two provided locations, we determine the slope of the secant line in section (a), which is equal to the difference between the y- and x-coordinates. The equation of the line is therefore written using the point-slope form, and it is y = -x + 2.1.

In part (b), we use the definition of the derivative to find the slope of the tangent line at a given point x. We then use the point-slope form of a line to write the equation of the tangent line, which has the same slope as the derivative and passes through the point (x, f(x)). In this case, the slope of the tangent line is -cos(x), and the equation of the tangent line is

y = -cos(x)*x + sin(x) + cos(x)*x.

The complete question is provided in the image below.

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Answer:

12 (who has 12 friends?)

Step-by-step explanation:

make the fractions, I think its called a denominator,  the same.

6/7 tums into 12/14

so if you give each friend 1/14 then you could feed 12 friends

this answer only works if you're not eating as well

The volume of the pyramid is 576 cubic inches.

To find the volume of a square base pyramid, you can use the formula:

Volume = (1/3) x base area x height

In this case, the side of the square base is given as 12 inches, and the height is given as 12.5 inches.

First, calculate the base area of the pyramid:

Base area = side²

= 12²

= 144 square inches

Now, substitute the values into the volume formula:

Volume = (1/3) x 144 x 12.5

Volume = 576 cubic inches

Therefore, the volume of the pyramid is 576 cubic inches.

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Answer:

0.375

Step-by-step explanation:

3/2 equals 1 and a half, and 1 and a half divided by 4 will get you 0.325

Answer:

4x - 2 = 3x + 1. Solution We substitute the value 3 for x in the equation and see if the left-hand member equals the right-hand member. 4(3) - 2 = 3(3) + 1.

Step-by-step explanation:

the answer is in the above image

Answer:

(-2,3,10,8)

Step-by-step explanation:

eg

(x,y)=(domain,range)

x components are domain and y components are range in the given set of ordered pairs

Answer: 7

Step-by-step explanation:

Since there are 42 tubes and each tray can hold 6 tubes, it will be 42/6 which is 7.

The rate (in km/h) at which the distance from the plane to the radar station is increasing a minute later is 0 km/h (rounded to the nearest whole number).

To solve this problem, we can use the concepts of trigonometry and related rates.

Let's denote the distance from the plane to the radar station as D(t), where t represents time. We want to find the rate at which D is changing with respect to time (dD/dt) one minute later.

Given:

The plane is flying with a constant speed of 360 km/h.

The plane passes over the radar station at an altitude of 1 km.

The plane is climbing at an angle of 30°.

We can visualize the situation as a right triangle, with the ground radar station at one vertex, the plane at another vertex, and the distance between them (D) as the hypotenuse. The altitude of the plane forms a vertical side, and the horizontal distance between the plane and the radar station forms the other side.

We can use the trigonometric relationship of sine to relate the altitude, angle, and hypotenuse:

sin(30°) = 1/D.

To find dD/dt, we can differentiate both sides of this equation with respect to time:

cos(30°) * d(30°)/dt = -1/D^2 * dD/dt.

Since the plane is flying with a constant speed, the rate of change of the angle (d(30°)/dt) is zero. Thus, the equation simplifies to:

cos(30°) * 0 = -1/D^2 * dD/dt.

We can substitute the known values:

cos(30°) = √3/2,

D = 1 km.

Therefore, we have:

√3/2 * 0 = -1/(1^2) * dD/dt.

Simplifying further:

0 = -1 * dD/dt.

This implies that the rate at which the distance from the plane to the radar station is changing is zero. In other words, the distance remains constant.

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The surface area of the rectangular prism in this problem is given as follows:

A. 426 m².

The surface area of a rectangular prism of height h, width w and length l is given by:

S = 2(hw + lw + lh).

This means that the area of each rectangular face of the prism is calculated, and then the surface area is given by the sum of all these areas. -> net method.

The dimensions for this problem are given as follows:

5 m, 12 m and 9 m.

Hence the surface area of the prism is given as follows:

S = 2(5 x 12 + 5 x 9 + 12 x 9)

S = 426 m².

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