Which equation represents an exponential function that passes through the point (2, 80)?

f(x) = 4(x)5
f(x) = 5(x)4
f(x) = 4(5)x
f(x) = 5(4)x

The formula of the volume is given by;

Where:

s = 11 in

h = 11.5 in

So, we have:

Round to the nearest whole number is 464

Answer: 464 in^3

The cοοrdinates οf the mid pοint M οf the line segment AB are ( 3,1 ) .

A midpοint οf a line segment is the pοint οn a segment that bisects the segment intο twο cοngruent segments. In οther wοrds, The midpοint is halfway between the twο end pοints.

Fοr the given line segment AB with cοοrdinates as (2, -3) and (4, 5) οf A and B respectively.

x₁ = 2           y₁ = -3                  (Cοοrdinates οf A)

x₂ = 4          y₂ = 5                   (Cοοrdinates οf B)

Midpοint οf a line segment = [ (x₁ + x₂ ) / 2   ;    (y₁ +  y₂) /2  ]

= [  (2 +4) /2  ;    (-3 + 5) / 2  ]

= [ 6/2  ;   2/2 ]

= (3,1)

=> Thus, the cοοrdinates οf M are (3,1).

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Answer:

$14.43¢

Step-by-step explanation:

We are given; \(1\frac{2}{5}\) pounds, 1 pound = $4.20 and \(2\frac{1}{4}\) pounds,1 pound = $3.80 that Andrea bought.

Now we need to find her total cost. To do that, we must first find the cost of the avocados. To do so, let us set up a graph. But before that is done, convert \(1\frac{2}{5}\) to a decimal. It is 1.4. Now we can set up a graph.

Avocados

\(\frac{4.2}{1}=\frac{x}{1.4}\)

Switch sides

\(\frac{x}{1.4}=\frac{4.2}{1}\)

Apply rule: \(\frac{a}{1}=a\)

\(\frac{x}{1.4}=4.2\)

Multiply both sides by 1.4

\(\frac{1.4x}{1.4}=4.2\cdot \:1.4\)

Simplify

\(x=5.88\)

So, her cost for avocados is $5.88¢

Now we must first find the cost of the avocados. To do so, let us set up a graph. But before that is done, convert \(2\frac{1}{4}\) to a decimal. It is 2.25. Now we can set up a graph.

Asparagus

\(\frac{3.8}{1}=\frac{x}{2.25}\)

Switch sides

\(\frac{x}{2.25}=\frac{3.8}{1}\)

Apply rule : \(\frac{a}{1}=a\)

\(\frac{x}{2.25}=3.8\)

Multiply both sides by 2.25

\(\frac{2.25x}{2.25}=3.8\cdot \:2.25\)

Simplify

\(x=8.55\)

So, her cost for asparagus is $8.55¢

Total cost

Now that we have found out how much both of the fruits Andrea bought costs, we need to sum it up (meaning add it) to find the total cost:

$5.88¢ + 8.55¢ =

5.88 + 8.55 = 14.43

Therefore, Andrea's total cost of the fruits is $14.43¢

This question is incomplete

Complete Question

A scientist poured 1.6 x 10³ milliliters of water into a container that already had 2.8 x 10⁴ milliliters of salt water and 9.4 x 10³ milliliters of sugar water. How many milliliters of liquid were in the container?

A.1.7 x 10⁴ milliliters

B.3.58 x 10⁴ milliliters

C.3.74 x 10⁴ milliliters

D.3.9 x 10⁴ milliliters

Answer:

C. 3.74 x 10⁴ milliliters

Step-by-step explanation:

The milliliters of liquid that WERE in the container = The milliliters of liquid that were in the container before adding 1.6 x 10³ milliliters of water

This equals to:

2.8 x 10⁴ milliliters of salt water and 9.4 x 10³ milliliters of sugar water.

Hence:

2.8 x 10⁴ milliliters of salt water + 9.4 x 10³ milliliters of sugar water

= (2.8 × 10⁴) + (9.4 × 10³)

= 37400

= 3.74 x 10⁴ milliliters

Therefore, option C is correct

Answer:

3

Step-by-step explanation:

- 4x³y² + 6

the x is raised to the power of 3 , that is exponent of x is 3

Answer:

You haven't provided expressions, so I can work out the problem for you. When we divide fractions, remember always "keep, switch, flip!" That's what we're gonna do here. We keep the 2/5, switch the sign to multiplication, and flip the 7/8 to 8/7. Therefore, we have 2/5*8/7. That gives us 16/35. Hope this helps!

Step-by-step explanation:

The standard deviation of x when the variable is normally distributed is 19.53125 .

Let X be the random variable.

Here, random variable X is normally distributed with mean 1000.

As 40% area is left of the mean and remaining 40% area is right side of the mean, we can say that the probability that the value of the random variable is lied between 925 and 1000 is 0.4 .

The area under normal curve is evenly distributed with respect to the mean (0).

So, 80% of area around the mean is evenly distributed with mean that mean 40% area is left of the mean and 40% area is right of the mean.

By using one of the above, the value of the standard deviation can be obtained.

As the probability that the value of the random variable X is lies between (1000 , 1025 ) is 0.8 .

From the z-table of P(0<Z<z), it can be fount that in the row 1.2 and column 0.08, value is 0.4.

So, by looking in z-table, it is found that the value of P(0<Z<1.28) is 0.4.

By comparing equation (i) and (ii), we have,

Hence, the value of the standard deviation is 19.53125 .

Given that the 80 % confidence interval around X is given by (975 , 1025). That means there are 80% chances that value of the random variable X lies between (975 , 1025).

So, the probability that the value of the random variable X is lies between (975 , 1025) is 0.8.

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The height of the triangular face is 15 yards.

To find the height of the triangular face, we will use the formula for the volume of a triangular prism:
Volume = (1/2) * Base * Height * Length.

We are given the following values:
- Volume (V) = 720 cubic yards
- Length (L) = 8 yards
- Base (B) = 12 yards
We need to find the height of the triangular face (H).

Let's plug in the given values into the formula and solve for H:
720 = (1/2) * 12 * H * 8
First, simplify the equation:
720 = 6 * H * 8
720 = 48 * H
Now, divide both sides by 48 to find the value of H:
H = 720 / 48
H = 15 yards.

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The first case given is a deigned experiment and the second case is an observational study.

i. This is a designed experiment because the tunas were randomly assigned to two different treatments (polluted and non-polluted water) in an attempt to determine the effect of the treatment (methyl mercury) on the outcome (survival times). The experiment was intentionally designed and carried out to test a hypothesis.

ii. This is an observational study because the data was collected by simply observing the natural occurring relationship between increasing amounts of phosphorus in the lake and decreasing number of lake trout over time, without any manipulation or intervention by the biologist. The purpose is to describe or understand the relationship between two variables rather than to test a hypothesis.

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Answer:

Step-by-step explanation:

72.34 x .2

the tip would be $14.47

Answer:

Your restaurant bill is $72.34. You want to leave about a 20% tip. Which is the best estimate of a 20% tip?A. $14.00B. $14.40C. $14.60D. $14.70

Step-by-step explanation:B is the right answer. You have to multiply 72.34 by 0.2 and you get 14.468. So B is the closest.

Therefore, the volume of the paper cone to the nearest tenth is 418.7 inches cubed.

The volume of the paper cone that Gretchen made to hold a gift for a friend is given by;V= (1/3)πr²hWhere;r = radius of the paper coneh = height of the paper coneπ = 3.14

Given that;Height of the paper cone (h) = 16 inches Radius of the paper cone (r) = 5 inchesWe are to find the volume (V) of the paper cone to the nearest tenth of an inch.

To obtain the volume of the paper cone, we can substitute the values of r and h in the formula above to obtain;

\(V= (1/3)\pir^2hV\)= \((\frac{1}{3} ) \times 3.14\times5^2 \times16V = (\frac{1}{3} ) \times 3.14\times25\times16V = (\frac{1}{3}) \times 1256V=418.7\)

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Answer:

Area

4 and width 8 equals 32

Perimeter

length 4 and width 8 equals 24

Area

length 20 and width 22 equals 440

Perimeter

length 20 and width 22 equals 88

Area

length 12 and width 8 equals 96

Perimeter

length 12 and width 8 equals 40

Area

length 15 and width 20 equals 300

Perimeter

length 15 and width 20 equals 70

Isn't this what you are asking for or is it something else. I hope this helps, If I did the answer wrong tell me and I will change it

Answer:

463×10³

463×1000

=0.463

Sample 1: Mean=10.01, Standard deviation=13.90 Sample 2: Mean

=11.43, Standard deviation

=14.10

Sample size of 1st year = n1

= 1012Mean of 1st year sample

= X1 = 10.01Standard deviation of 1st year sample

= s1

= 13.90Sample size of 2nd year

= n2

= 1012Mean of 2nd year sample

= X2

= 11.43

Standard deviation of 2nd year sample = s2

= 14.10 Let us assume a significance level of α = 0.05, which implies that the critical region consists of 2.5% in both tails (since it is a two-tailed test).

Therefore, we do not have sufficient evidence to conclude that the mean number of hours per week spent on the Internet differs between 2010 and another year.

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Answer:

Since there's only one option that's wrong,

The y-intercept is (0,6)

The x-intercept is (3,0)

the correct graph is the one where the line goes through these two points.

Step-by-step explanation:

graphing calculator

(a) To find the partial derivatives, we differentiate the function f(x, y) with respect to x and y while treating the other variable as a constant.

fx(x, y) = d/dx [ (4x^2 + 2xy + 4y^2) / (x^2 + y^2) ]

          = [(8x(x^2 + y^2) - (4x^2 + 2xy + 4y^2)(2x)) / (x^2 + y^2)^2]

          = [(8x^3 + 8xy^2 - 8x^3 - 4x^2y - 8xy^2) / (x^2 + y^2)^2]

          = [-4x^2y / (x^2 + y^2)^2]

fy(x, y) = d/dy [ (4x^2 + 2xy + 4y^2) / (x^2 + y^2) ]

          = [(8y(x^2 + y^2) - (4x^2 + 2xy + 4y^2)(2y)) / (x^2 + y^2)^2]

          = [(8xy^2 + 8y^3 - 8xy^2 - 4x^2y - 8y^3) / (x^2 + y^2)^2]

          = [-4x^2y / (x^2 + y^2)^2]

(b) To find fx(0, 0) and fy(0, 0), we substitute x = 0 and y = 0 into the partial derivative expressions:

fx(0, 0) = -4(0)^2(0) / ((0)^2 + (0)^2)^2 = 0

fy(0, 0) = -4(0)^2(0) / ((0)^2 + (0)^2)^2 = 0

(c) Both partial derivatives, fx(x, y) and fy(x, y), are continuous at every point in the set {(x, y): (x, y) ≠ (0, 0)}.

However, at the point (0, 0), the partial derivatives fx(0, 0) and fy(0, 0) are both 0, indicating that the partial derivatives are continuous at that point as well.

Therefore, the correct answer is (a) Yes, both the partial derivatives are continuous at every point in that set.

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Answer:

Step-by-step explanation:

A plan to only spend x amount of money while shopping

Because {{{no}}} sides are marked as {{{congruent}}} in this figure, the classification {{{by}}}{{{ sides}}} is {{{scalene}}}.

Answer:

shown below

Explanation:

so first you can graph a dot at (2,-1), since it must go through that line. Then you can use the slope, 3, to figure out the next dot. The slope 3 can be put into a fraction, liking like 3/1. Then you use rise/run from your point (2,-1). You go up 3, and right 1. Using that, your next point is (3,2). Plot that dot, and then use a straight edge to draw your line. It looks like how it is in the picture.

The objective of this research is to collect data on a specific component of the off-campus student population.The amount of time they spend travelling to courses each week.

a) The population for this study is all off-campus students at this college, and the sample is a random sample of 45 off-campus students who are polled. The sample is chosen at random to be representative of the entire population.

b) The data being gathered is the amount of time the surveyed students spend each week travelling to school. Because it reflects a numerical measurement, this is quantitative data. This information will be used to calculate the average commuting time for off-campus students and to identify any possible concerns or areas for improvement in commuting.

c) This is a descriptive research, since it seeks to characterise and summarise the features of the off-campus student population in terms of commuting time. The study's purpose is to better understand off-campus students' commuting patterns and gather ideas into how to enhance their commuting experience.

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Answer:

I see you are rolling a standard fair six-sided die twice. There are 6 equally likely outcomes on each roll of the die. Die Roll #1: P(Perfect square) =1/3 The winning outcomes are 1 and 4, this makes the fraction 2/6, which reduces to 1/3.

Step-by-step explanation:

PLEASE MARK ME AS BRAINLIEST

The probabilities for the following statements are:

a) 1/4

b) 1/18

c) 1/3

d) 1/12

e) 1/6

f) 1/36

It is the chance of an event to occur from a total number of outcomes.

The formula for probability is given as:

Probability = Number of required events / Total number of outcomes.

We have,

The sample space for rolling a die twice.

= {1, 2, 3, 4, 5, 6 } x {1, 2, 3, 4, 5, 6}

= {(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6), (3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6), (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6), (5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6), (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6) }

The number of possible outcomes.

= 36.

Now,

The number of outcomes where both are odd.

= { (1, 1), (1, 3), (1, 5), (3, 1), (3, 3), (3, 5), (5, 1), (5, 3), (5, 5) }

The probability that both are odd.

= 9/36

= 1/4

The number of outcomes where both are a perfect square.

= {1, 1), (4, 4) }

The probability that both are perfect squares.

= 2/36

= 1/18

The number of outcomes where the first is even and the second is less than 5.

= { (2, 1), (2, 2), (2, 3), (2, 4), (4, 1), (4, 2), (4, 3), (4, 4), (6, 1), (6, 2), (6, 3), (6, 4) }

The probability that where first is even and second, is less than 5.

= 12/36

= 1/3

The number of outcomes where the first is prime and the second is 6.

= { (2, 6), (3, 6), (5, 6) }

The probability where the first is prime and the second is 6.

= 3/36

= 1/12

The number of outcomes where both are the same.

= { (1, 1), (2, 2), (3, 3), (4, 4), (5, 5), (6, 6) }

The probability that both are the same.

= 6/36

= 1/6

The number of outcomes of at least 4 both times.

= {(4, 4)}

The probability that at least 4 both times.

= 1/36

Thus,

The probabilities for each statement are given above.

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The area of the given trapezoidal site is 250,000 sq. ft.

The area of the trapezoidal with the dimensions of both bases and the height is given by the formula,

Area = 1/2 × height × (base1 + base2)

Units: square units

The given trapezoidal site has a base of 150 feet, i.e., base1 = 150 ft; a height of 2000 ft, i.e., height = 2000 ft and a parallel base of 100 feet, i.e., base2 = 100 ft.

Then, the area of the trapezoidal is

= 1/2 × 2000 × (150 + 100)

= 1/2 × 2000 × 250

= 250,000 sq. ft

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Report on Commonalities Among Three Chosen Regions

For this assignment, three regions of the world have been selected to identify commonalities among them. The chosen regions are North America, Europe, and East Asia. Through internet research, several commonalities have been identified that are shared among these regions. Below are five commonalities found:

Economic Development:

All three regions, North America, Europe, and East Asia, are characterized by significant economic development. They are home to some of the world's largest economies, such as the United States, Germany, China, and Japan. These regions exhibit high levels of industrialization, technological advancement, and trade activities. Their economies contribute significantly to global GDP and are major players in international commerce.

Technological Advancement:

Another commonality among these regions is their emphasis on technological advancement. They are known for their innovation, research and development, and technological infrastructure. Companies and industries in these regions are at the forefront of technological advancements in fields such as information technology, automotive manufacturing, aerospace, pharmaceuticals, and more.

Cultural Diversity:

North America, Europe, and East Asia are culturally diverse regions, with a rich tapestry of different ethnicities, languages, and traditions. Immigration and historical influences have contributed to the diversity seen in these regions. Each region has a unique blend of cultural practices, cuisines, art, music, and literature. This diversity creates vibrant multicultural societies and fosters an environment of cultural exchange and appreciation.

Democratic Governance:

A commonality shared among these regions is the prevalence of democratic governance systems. Many countries within these regions have democratic political systems, where citizens have the right to participate in the political process, elect representatives, and enjoy individual freedoms and rights. The principles of democracy, rule of law, and respect for human rights are important pillars in these regions.

Education and Research Excellence:

North America, Europe, and East Asia are known for their strong education systems and institutions of higher learning. These regions are home to prestigious universities, research centers, and educational initiatives that promote academic excellence. They attract students and scholars from around the world, offering a wide range of educational opportunities and contributing to advancements in various fields of study.

In conclusion, the regions of North America, Europe, and East Asia share several commonalities. These include economic development, technological advancement, cultural diversity, democratic governance, and education and research excellence. Despite their geographical and historical differences, these regions exhibit similar traits that contribute to their global significance and influence.

Answer:

For this assignment, three regions of the world have been selected to identify commonalities among them. The chosen regions are North America, Europe, and East Asia. Through internet research, several commonalities have been identified that are shared among these regions. Below are five commonalities found:

Economic Development:

All three regions, North America, Europe, and East Asia, are characterized by significant economic development. They are home to some of the world's largest economies, such as the United States, Germany, China, and Japan. These regions exhibit high levels of industrialization, technological advancement, and trade activities. Their economies contribute significantly to global GDP and are major players in international commerce.

Technological Advancement:

Another commonality among these regions is their emphasis on technological advancement. They are known for their innovation, research and development, and technological infrastructure. Companies and industries in these regions are at the forefront of technological advancements in fields such as information technology, automotive manufacturing, aerospace, pharmaceuticals, and more.

Cultural Diversity:

North America, Europe, and East Asia are culturally diverse regions, with a rich tapestry of different ethnicities, languages, and traditions. Immigration and historical influences have contributed to the diversity seen in these regions. Each region has a unique blend of cultural practices, cuisines, art, music, and literature. This diversity creates vibrant multicultural societies and fosters an environment of cultural exchange and appreciation.

Democratic Governance:

A commonality shared among these regions is the prevalence of democratic governance systems. Many countries within these regions have democratic political systems, where citizens have the right to participate in the political process, elect representatives, and enjoy individual freedoms and rights. The principles of democracy, rule of law, and respect for human rights are important pillars in these regions.

Education and Research Excellence:

North America, Europe, and East Asia are known for their strong education systems and institutions of higher learning. These regions are home to prestigious universities, research centers, and educational initiatives that promote academic excellence. They attract students and scholars from around the world, offering a wide range of educational opportunities and contributing to advancements in various fields of study.

In conclusion, the regions of North America, Europe, and East Asia share several commonalities. These include economic development, technological advancement, cultural diversity, democratic governance, and education and research excellence. Despite their geographical and historical differences, these regions exhibit similar traits that contribute to their global significance and influence.

Answer:

21 degrees

Step-by-step explanation:

The inscribed angle theorem states that when two cords (lines in a circle) make contact with the circumference of the circle (outer edge), and the two cords do not pass through the center of the circle, then the angle between the two cords is equal to half of the length of its surrounding arc. This means that the measure of arc (WV) is half of the measure of angle (WXV). Therefore, one can form an equation and solve for the length of the arc (WV).

2 (WV) = (m<WXV)

Substitute,

2 (WV) = (42)

Inverse operaitons,

2 (WV) = (42)

/2            /2

(WV) = 21

Answer:

\(7x ^ 5 - x ^ 3- x ^ 2 + 4x\)

Step-by-step explanation:

1) \(3x ^ 4 + 2x ^ 3 - 5x ^ 2 + 4x ^ 2 + 6x - 2x - 3x ^ 4 + 7x ^ 5 - 3x ^ 3\)

Rearrange the expression.

2) \(7x ^ 5+3x ^ 4- 3x ^ 4 + 2x ^ 3 - 3x ^ 3- 5x ^ 2 + 4x ^ 2 + 6x - 2x\)

Solve.

3) \(7x ^ 5 - x ^ 3- x ^ 2 + 4x\)

Answer:

x = 20

p =54

y= 54

Step-by-step explanation:

2x-4 = 96-3x

5x = 100

x = 20

2x-4 = 40-4 = 36

(180 - (36 x 2))/2

(180-72)/2

108/2

p = y =54

Answer:

1

Step-by-step explanation:

The amount of money Mayte can spend on a daily basis is given by $ 111 .

Sellers and purchasers of products and services both accept money as a form of payment. When we purchase goods like food, clothing, a house, groceries, etc., we provide money in exchange. We exchange money for everything we buy. This is a straightforward swap.

In mathematics, division is the process of dividing a number into equal parts and calculating the maximum number of equal parts that can be made. For instance, dividing 15 by 3 results in the division of 15 into 3 groups of 5 each. The division sign, "," or occasionally "/," is used in computer code.

Mayte get a total money of  $977 from her parents so,

total = 977

She saves $200 for herself so now the remaining sum is

977 - 200 = 777

The rest she has to distribute in 7 days so, by using the simple dividation rule we get,

777/7 = 111

Therefore, much money can you spend daily is $111.

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Complete question:

Mayte is a foreign student and receives his parents $977 per week. She saves $200 and the rest is distributed among the 7 days of the week, How much money can you spend daily?​