Answer:
The answer for this question is B water vapor
Explanation:
just trust me bro
Which type of physical activity is being performed in the picture
A cardiovascular
B strength training
C flexibility
D cross training
The activity that is performed in the picture is cardiovascular.
What is a physical activity?The term physical activity has to do with the manner in which an action is performed. It has to do with the process of performing an action vigorously in most cases, we are talking about physical exercise.
Now we can see that the physical activity here is the participation in basketball. This is a very strenuous activity that involves an increase in the flow of blood across the body. Hence we can see that the basketballer is involved in a cardiovascular activity.
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We think that a star like the Sun lives for about 10 billion years. Using the relationships in your textbook (Chapter 5, "Twinkle, twinkle, little star" and "Stellar ages"), what is the relative luminosity and lifespan of a star that is 10 times more massive? Of a star that is 1/3 as
massive?
Based on the relationship between a star's mass and its luminosity, as described in Chapter 5 of your textbook, we can determine the relative luminosity and lifespan of stars with different masses compared to the Sun.
For a star that is 10 times more massive than the Sun:
According to the mass-luminosity relationship, more massive stars have higher luminosities. Since the star is 10 times more massive than the Sun, we can assume it will have a greater luminosity. However, without specific data on the exact relationship between mass and luminosity, we cannot determine the precise relative luminosity value. As for its lifespan, more massive stars tend to have shorter lifespans than lower-mass stars. Therefore, we can expect the star that is 10 times more massive than the Sun to have a shorter lifespan compared to the Sun's 10 billion years.
For a star that is 1/3 as massive as the Sun:
Similarly, using the mass-luminosity relationship, less massive stars have lower luminosities. If the star is 1/3 as massive as the Sun, we can expect it to have a lower luminosity compared to the Sun. Again, without specific data, we cannot determine the exact relative luminosity value. Regarding its lifespan, less massive stars typically have longer lifespans. Therefore, we can expect the star that is 1/3 as massive as the Sun to have a longer lifespan compared to the Sun's 10 billion years.
In summary, a star that is 10 times more massive than the Sun would likely have a greater luminosity and a shorter lifespan, while a star that is 1/3 as massive as the Sun would likely have a lower luminosity and a longer lifespan.
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The mass of helium gas in a balloon is ________.
the weight of the gas minus the balloon
the amount of matter inside the balloon
the amount of matter including the balloon
the mass of helium minus the mass of the balloon
Answer:
Option (b).
Explanation:
Mass of an object is defined as the amount of matter contained in it. In this case, the mass of helium gas in a balloon is the amount of matter inside the balloon. It is independent of the outside condition.
Hence, out of 4 options, the correct option is (b).
Answer:
b
Explanation:
3
(in this question, you will need to make use of the
equations of motion that you studied in chapter 2.)
a motorcyclist of mass 60 kg rides a bike of mass
40 kg. as she sets off from the lights, the forward
force on the bike is 200 n. assuming the resultant
force on the bike remains constant, calculate the
bike's velocity after 5.0 s.
The bike's velocity after 5.0 s when a motorcyclist of mass 60 kg rides a bike of mass 40 kg is 10m/s
Given mass of motorcyclist (m) = 60kg
mass of bike (m2) =40kg
Force exerted on bike (F) = 200N
Assuming that the total force on the bike remains constant.
Time taken (t) = 5s
Velocity of bike = v
We know that from newtons laws of motion F = Ma where a is the acceleration. v = u+at where u is the initial velocity = 0. Then a = v/t
So F = Mv/t
Here M be total mass = m1+m2
Then Fnet = (m1+m2) x v/t
v = F x t/(m1+m2) = 200 x 5/(40+60) = 10m/s
Hence Velocity of bike = 10m/s
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Two particles are created in a high-energy accelerator and move off in opposite directions. The speed of one particle, as measured in the laboratory, is 0.650c, and the speed of each particle relative to the other is 0.950c. What is the speed of the second particle, as measured in the laboratory
The speed of the second particle, as measured in the laboratory, is approximately 0.9901 times the speed of light (c).
To solve this problem, use the relativistic velocity addition formula. The formula states that the velocity (v) of an object in one frame of reference is related to its velocity (u) in another frame of reference by:
v = (u + w) / (1 + (u * w) / c^2)
where u is the velocity of the object relative to the first frame of reference, w is the velocity of the second frame of reference relative to the first frame of reference, and c is the speed of light in a vacuum.
Given:
u (speed of one particle measured in the laboratory) = 0.650c
w (speed of each particle relative to the other) = 0.950c
We can substitute these values into the formula to find the speed (v) of the second particle as measured in the laboratory:
v = (0.650c + 0.950c) / (1 + (0.650c * 0.950c) / c^2)
Simplifying the equation:
v = (1.6c) / (1 + 0.6175)
v = (1.6c) / 1.6175
v ≈ 0.9901c
Therefore, the speed of the second particle, as measured in the laboratory, is approximately 0.9901 times the speed of light (c).
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PLEASE HELP ME!
as your friend skateboards down a hill, you measure their velocity at 1.0-second intervals. you record the following data: (0.0 s, 0.0m/s), (1.0 s, 2.3 m/s), (2.0 s, 4.6 m/s). Determine your friends acceleration.
Answer:
Explanation:
it should be 3.2 m/s^2
The acceleration is 3.2 m/ s2. Acceleration is change in velocity per time.
What is acceleration?Any procedure where the velocity varies is referred to as acceleration. There are only two ways to accelerate: changing your speed or changing your direction, or changing both. This is because velocity is both a speed and a direction.
A moving object can occasionally alter its velocity by the same amount every second. The data table above depicts an item altering its velocity by 10 m/s every second, as was described in the paragraph above. Since the velocity is changing by a fixed amount every second, this is known as a constant acceleration.
Therefore, The acceleration is 3.2 m/ s2. Acceleration is change in velocity per time.
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If the inside of a container has a surface area of 20cm², what will be the pressure on each square inch of the container if 117.6kg of force are applied to the container?
Answer:
Explanation:
given :-
force applied = 117.6N
Area = 20 m^2
Pressure =?
solution:-
Pressure = Force / Area
= 117.6 N / 20 m^2
= 5.88 Pascals
Hope it helps :D!
Explanation:
Please helpp !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Let's begin by determining the equilibrium position of a seesaw pivot. You and a friend play on a seesaw. Your mass is 90 kg and your friend's mass is 60 kg. The seesaw board is 3.0 m long and has negligible mass. Where should the pivot be placed so that the seesaw will balance when you sit on the left end and your friend sits on the right end? Part A let's look at the same scenario we just worked through, but instead the board now has a non-zero mass of 29 kgkg . where should the pivot be placed for balance?
The pivot should be placed 1.31 m from the left end of the board to balance the seesaw when you sit on the left end and your friend sits on the right end, taking into account the mass of the board.
T1 = 90 kg * g * (x - 1.5 m)
T2 = 60 kg * g * (1.5 m - x).
T3 = Mg * (L/2 - x)
In the equilibrium position, we set the sum of the torques equal to zero:
T1 + T2 + T3 = 0
90 kg * g * (x - 1.5 m) + 60 kg * g * (1.5 m - x) + Mg * (L/2 - x) = 0
Simplifying and solving for x, we get:
x = (45 kg * L + 1.5 m * (90 kg - 60 kg)) / (M + 150 kg)
Substituting the values given in the problem, with M = 29 kg, we get:
x = (45 kg * 3.0 m + 1.5 m * 30 kg) / (29 kg + 150 kg)
x = 1.31 m
Torque is a measure of the force that causes an object to rotate around an axis or pivot point. It is often described as the rotational equivalent of force. The amount of torque an object experiences is dependent on both the magnitude and direction of the applied force, as well as the distance between the axis of rotation and the point where the force is applied.
The formula for torque is τ = r × F, where τ is the torque, r is the distance between the axis of rotation and the point of force application, and F is the magnitude of the applied force. Torque is typically measured in units of Newton meters (Nm) or pound-feet (lb-ft). Torque is an important concept in many areas of physics, including mechanics, engineering, and robotics. It plays a critical role in the operation of machines and engines, as well as in the movement and control of vehicles and aircraft.
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Which form of electromagnetic radiation would be blocked in the stratosphere by ozone?
Select one:
A. cosmic rays
B. ultraviolet
C. infrared
D. microwaves
E. visible light
Ultraviolet is correct answer .UV radiation is the type of electromagnetic energy that ozone would block in the stratosphere.
The ozone layer in the stratosphere blocks ultraviolet (UV) radiation, which is a form of electromagnetic radiation. This is important because UV radiation can be harmful to living organisms, including humans, causing skin damage and increasing the risk of skin cancer.
The majority of the sun's dangerous ultraviolet (UV) radiation, especially UV-B rays, are absorbed by ozone in the stratosphere, which serves as a natural filter. In addition to causing skin cancer, cataracts, and other health issues, UV radiation can be dangerous to living things. The majority of UV-B radiation falls within the 200–300 nanometer (nm) band of UV light that is absorbed by ozone. This is one of the reasons the ozone layer is crucial for life on our planet because it shields it from the damaging effects of UV radiation. Ozone in the stratosphere does not appreciably absorb other types of electromagnetic radiation, such as cosmic rays, infrared, microwaves, and visible light.
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A ball thrown straight upward returns to its original level in 2.5 seconds. A second ball is thrown at an angle of 40 degrees above the horizontal. What is the initial speed ball if it also returns to its original level in 2.5 seconds?
Answer:
The velocity is \(u = 19.1 \ m/s\)
Explanation:
From the question we are told that
The time taken by the ball is t = 2.5 seconds
The angle made with the horizontal is \(\theta = 40^o\)
Generally the vertical component of the initial velocity is mathematically represented as
\(u_y = u sin (\theta )\)
Generally at maximum height of the ball the velocity is v = 0 m/s and the time take to reach this maximum height is
=> \(t_m = \frac{t}{2} = \frac{2.5}{2} = 1.245 \ s\) [This because t is duration for the to a fro travel of the ball]
Generally from kinematic equation
\(v = u_y + gt\)
Here \(g = -9.8 m/s^2\) given that the direction is against gravity
=> \(0 = u sin (40) - 9.8 * [1.25]\)
=> \(0 = 0.6428u - 12.25\)
=> \(u = 19.1 \ m/s\)
A nightlight uses 4.0W of power when plugged into an outlet. The current of the circuit is .034A. What is the voltage across the light bulb's filament?
Answer:
Voltage V = 117.65 volts
the voltage across the light bulb's filament is 117.65 V
Explanation:
The power of a light bulb can be expressed with respect to voltage and current flow.
Power = voltage × current
P = VI
Making Voltage V the subject of formula;
V = P/I
Given;
Power P = 4.0W
Current I = 0.034A
Substituting the given values;
V = 4/0.034
V = 117.65 volts
Which part of the electromagnetic spectrum is nearest to radio waves?
X-rays
microwaves
gamma rays
ultraviolet light
Answer:
i believe it is the microwaves that is closest to the radio waves.
Explanation:
The microwaves are the part of the electromagnetic spectrum is nearest to radio waves.
What is meant by electromagnetic spectrum?The range of all EM radiation arranged from high to low frequency (short to long wavelength) according to their frequency or wavelength. is known as the electromagnetic spectrum (EM).
Here,
The visible light from a bulb in your home and the radio waves from a radio station are two examples of electromagnetic radiation. Radiation is energy that travels and disperses as it does.
The properties of the electromagnetic spectrum include the ways in which signals can propagate and how much data they can carry. Signals delivered at higher frequencies typically propagate more quickly but can carry more data in a given amount of space.
The electromagnetic spectrum begins with the lowest frequency radio waves and moves up in frequency and down in wavelength from there. Radio waves are followed by visible light, infrared radiation, and lastly microwaves.
Hence,
The microwaves are the part of the electromagnetic spectrum is nearest to radio waves.
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The end of a metal spoon is placed in a bowl of hot soup. After a few minutes, the handle of the spoon feels warm.
1. If a 15 cm object is placed 50 cm from an object, and forms a real image 30 cm from the focal
length? (18.75 cm)
a. What is the radius of the curvature of the mirror?
b. If the image is 30.5 cm high, what is the height of the object?
The negative sign for the height of the object indicates that it is inverted with respect to the axis of the mirror. Therefore, the height of the object is 50.8 cm.
a. To find the radius of curvature of the mirror, we can use the mirror formula:
1/f = 1/v + 1/u
where f is the focal length of the mirror, v is the distance of the image from the mirror, and u is the distance of the object from the mirror.
We are given that the object is placed 50 cm from the mirror (i.e., u = 50 cm), and the image is formed 30 cm from the focal point (i.e., v = 30 cm). We can use these values to solve for the focal length:
1/f = 1/30 + 1/50
1/f = (5/150) + (3/150)
1/f = 8/150
f = 18.75 cm
Therefore, the radius of curvature of the mirror is twice the focal length, i.e., R = 2f = 37.5 cm.
b. The magnification of the mirror is given by:
m = -v/u
where the negative sign indicates that the image is inverted.
We are given that the image is 30.5 cm high. Using the magnification formula, we can find the height of the object:
m = -v/u = -30/50 = -0.6
h_i/h_o = -m
h_o = h_i/m = 30.5/-0.6 = -50.8 cm
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why is a layer of pollution in the air more visible in winter than summer
Answer:
During winters the planetary boundary layer is thinner as the cooler air near the earth's surface is dense. The cooler air is trapped under the warm air above that forms a kind of atmospheric 'lid'. This phenomenon is called winter inversion
Explanation:
Will give brainliest! Superman does 14500 J of work pushing a boulder 2.35 m. How much force did he exert? A. 34100 N B. 0.000162 N C 14500 N D. 6170 N
Answer:
\(\boxed {\boxed {\sf D. \ 6170 \ N}}\)
Explanation:
We want to find how much force Superman exerted while pushing a boulder.
Work is the energy transferred to or from an object when force is applied along a displacement. It is the product of force and distance.
\(W=Fd\)
Superman did 14,500 Joules of work. We can convert the units to make the problem easier later. 1 Joule is equal to 1 Newton meter.
He pushed the boulder 2.35 meters.
W= 14,500 N*m d= 2.35 mSubstitute the values into the formula.
\(14,500 \ N*m= F* 2.35 \ m\)
We are solving for the force he exerted, so we must isolate the variable F. It is being multiplied by 2.35 meters. The inverse operation of multiplication is division, so we divide both sides by 2.35 meters.
\(\frac{14,500 \ N*m}{2.35 \ m}= \frac{F* 2.35 \ m}{2.35 \ m}\)
\(\frac{14,500 \ N*m}{2.35 \ m}=F\)
The units of meters cancel.
\(\frac{14,500 \ N}{2.35 }=F\)
\(6170.21277 \ N= F\)
Round to the nearest whole number. The 2 in the tenth place tells us to leave the 0.
\(6170 \ N \approx F\)
Superman exerted approximately 6170 Newtons of force.
Answer:
6170
Explanation:
Name all the energy transfers that occur to make a solar-powered traffic light work (name what generates the energy, and what kind of energy it turns to):
Two sunbathers were sitting on a raft. One noted that the raft bobbed up and down at a frequency of 0.20 Hz. The other observed that a crest took 5.0 s to cover the 15.0 m to shore. How far apart are the crests of the wave?
Answer:
15 m
Explanation:
We'll begin by calculating the speed of the wave. This can be obtained as follow:
Time = 5 s
Distance = 15 m
Speed =?
Speed = distance / time
Speed = 15 / 5
Speed = 3 m/s
Finally, we shall determine the distance between the crests of the wave. This can be obtained as follow:
Speed (v) = 3 m/s
Frequency (f) = 0.2 Hz
Distance between the crest (λ) =?
v = λf
3 = λ × 0.2
Divide both side by 0.2
λ = 3 / 0.2
λ = 15 m
Therefore, the distance between the crests of the wave is 15 m
who is the richest artist in the Gambia 2020
Answer:
Jaliba Kuyateh is the most famous and wealthiest Gambian musician.
Unpolarized light is incident onto three polarizers with their transmission axes oriented in such a way that the first and the last make a 39 angle between them, and the middle one makes the same angle with the first and the last one. Find the percentage of the incident light which passes through these three polarizers.
Answer:
I₃ = I₀ 0.395
Explanation:
Polarized light passing through a polarizer must comply with Malus's law
I = I₀ cos² θ
Before starting, let's analyze the angle between the polarizers, the second has the same angle with the first and the third, so it is at the midpoint
θ₂ = 39/2 = 19.5
now let's analyze the light that passes through each polarizer, as the incident is unpolarized through the first polarizer half the intensity comes out
I₁ = I₀ / 2
the second polarizer comes out
I₂ = I₁ cos² 19.5
I₂ = I₀ / 2 cos² 19.5
through the third polarized the intensity passes
I₃ = I₂ cos² 19.5
I₃ = (I₀ /2 cos² 19.5) cos² 19.5
I₃ = I₀ 0.395
The school bus slows from 60 km/h to 40 km/h when entering the school zone.
Given that this change of speed occurred over 8 seconds, calculate the average deceleration of the bus.
To calculate the average deceleration of the bus, we can use the following formula:
Average deceleration = (Final velocity - Initial velocity) / Time takenHere, the initial velocity (v1) is 60 km/h, the final velocity (v2) is 40 km/h, and the time taken (t) is 8 seconds. To make the units consistent, we'll convert the velocities from km/h to m/s.
1 km/h = 1000 m / 3600 s = 5/18 m/sv1 = 60 km/h * (5/18) = (60 * 5) / 18 = 50/3 m/s v2 = 40 km/h * (5/18) = (40 * 5) / 18 = 100/9 m/sNow, we can plug the values into the formula:
Average deceleration = (v2 - v1) / t Average deceleration = ((100/9) - (50/3)) / 8Now, we'll find a common denominator for the fractions and simplify:
Average deceleration = ((300 - 450) / 27) / 8 = (-150 / 27) / 8Lastly, we'll divide the fraction by 8:Average deceleration = -150 / (27 * 8) = -150 / 216So, the average deceleration of the bus is approximately -150/216 m/s².
explain why wind and wave power could not be relied on to provide a country's entire electricity supply .
Answer:
because if the plant that produced that type of energy broke down you would need another type of energy to replace it.
Explanation:
A 1.2kg ball is rolling at a speed of 5m/s. Find the amount of KE it gains.
When, a 1.2kg ball is rolling at a speed of 5m/s. Then, the ball gains 15 Joules of kinetic energy (KE).
Kinetic energy is the energy an object possesses due to its motion. It is a scalar quantity and is dependent on the mass and velocity of the object.
The formula for kinetic energy is KE = 1/2mv², where m will be the mass of the object and v is its velocity.
Substituting the given values, we get;
KE = 1/2 x 1.2kg x (5m/s)²
KE = 1/2 x 1.2kg x 25m²/s²
KE = 15J
Therefore, the ball gains 15 Joules of kinetic energy.
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How do you calculate the refractive index of a material using the critical angle? (GCSE Physics)
Answer:
µ = \(\frac{1}{sinC}\)
Explanation:
µ = 1/ sinC
µ -----> refractive index of medium
C ----> critical angle
Hope this helps!
lamp 1 and lamp 2 are in a series circuit
lamp 1 stops working
explain why lamp 2 also stops working
Lamps 1 and 2 are connected in series. lamp 1 stops working because the circuit is not complete.
What is a series circuit?In a series circuit, the amount of current flowing through any component is the same and the sum of the individual resistances equals the overall resistance of any series circuit.
The voltage in a series circuit is equal to the total of the individual voltage drops.
For the bulb to glow the circuit should be complete. If the circuit is not completed the bulb will not glow.
Lamps 1 and 2 are connected in series. lamp 1 stops working because the circuit is not complete.
Hence, lamp 1 stops working.
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On the balloon simulation what do the red circles represent? What kind of charge do they have
In the balloon simulation, the red circles represent positive charges.
Electrostatics is the branch of physics that studies electric charges at rest. The interaction between electric charges is the foundation for electrostatics. These interactions can either be repulsive or attractive, depending on the types of charges. Electrostatics plays an important role in many aspects of our daily lives.
For example, we use it in the design of electrical circuits, lightning rods, and particle accelerators. The simulation demonstrates the following electrostatic principles: Like charges repel and opposite charges attract.
Each balloon has an equal amount of positive and negative charges when it is neutral.When a balloon is rubbed, electrons are transferred from one surface to the other, creating an imbalance of positive and negative charges.The excess charge is spread over the surface of the balloon. This charge creates an electric field.
As the balloon is rubbed, some of the electrons from the balloon's surface are transferred to the wool. The balloon becomes positively charged while the wool becomes negatively charged. As the balloon is brought closer to the wall, the positive charges on the surface of the balloon repel the positive charges on the surface of the wall.
This repulsion results in the balloons sticking out from the wall, indicating that the charges on the balloon are repelling the charges on the wall.The red circles in the simulation represent the positive charges.
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a ball of mass m collides completely inelastically in one dimension with another ball of mass 3m that is initially at rest (the balls stick together after the collision). what fraction of the initial kinetic energy is lost in the collision
Fraction of the initial kinetic energy is lost in the collision f = 3/4.
Two balls of masses M and 3M kinetic energy
Initially before collision:
Speed of ball of mass M = −V0 (Right direction is taken as negative)
Speed of ball of mass 3M = +V0
Finally after collision: Speed of ball of mass M = v
Speed of ball of mass 3M = V02
\(Finding the fraction(f) of initial kinetic energy lost in the collisionf=1−Final Kinetic EnergyInitial Kinetic Energyf=1−12×M×(v02)2+12×3M×(v02)212×M×(−v0)2+12×3M×(v0)2f=1−v024v02f=1−14=34\)
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If someone is driving 100 miles in 60 minutes then drives 150 miles in 100 minutes west, what is his acceleration rate.
Answer:
his acceleration rate is -0.00186 m/s²
Explanation:
Given;
initial position of the car, x₀ = 100 miles = 160, 900 m ( 1 mile = 1609 m)
time of motion, t₀ = 60 minutes = 60 mins x 60 s = 3,600 s
final position of the car, x₁ = 150 miles = 241,350 m
time of motion, t₁ = 100 minutes = 100 mins x 60 s = 6,000 s
The initial velocity is calculated as;
u = 160, 900 m / 3,600 s
u = 44.694 m/s
The final velocity is calculated as;
v = 241,350 m / 6,000 s
v = 40.225 m/s
The acceleration is calculated as;
\(a = \frac{\Delta V}{\Delta t} = \frac{v- u}{t_1 - t_ 0} = \frac{40.225 - 44.694}{6000-3600} = -0.00186 \ m/s^2\\\\\)
Therefore, his acceleration rate is -0.00186 m/s²
In your own words, describe how an object's potential energy can be affected by its position.
Answer:
Explanation:
The higher the object is relative to some defined baseline (like the ground), the greater the potential energy.
Potential Energy = U = mgh
U is directly proportional to h (height of the object), so the greater the h the greater the U.