Which electromagnetic wave has wavelengths ranging from the size of a printed period to the length of a pen (1×10-3 to 1×10-1 meters)?
A.
microwaves
B.
radio waves
C.
infrared radiation
D.
x–rays

Answers

Answer 1

Answer: microwaves

Explanation:

Answer 2

Correct Answer:

A. Microwaves


Related Questions

1. A buoyant force of 790 N lifts a 214 kg sinking boat.What is the boat's
net acceleration?

Answers

Answer:

The net acceleration of the boat is approximately 6.12 m/s² downwards

Explanation:

The buoyant or lifting force applied to the boat = 790 N

The mass of the boat lifted by the buoyant force = 214 kg

The force applied to a body is defined as the product of the mass and the acceleration of the body. Therefore, the buoyant force, F, acting on the boat can be presented as follows;

Fₐ = F - W

The weight of the boat = 214 × 9.81 = 2099.34 N

Therefore;

Fₐ = 790 - 2099.34  = -1309.34 N

Fₐ = Mass of the boat × The acceleration of the boat

Given that the buoyant force, Fₐ, is the net force acting on the boat, we have;

F = Mass of the boat × The net acceleration of the boat

F = -1309.34 N =  214 kg × The net acceleration of the boat

∴ The net acceleration of the boat = -1309.34 N/(214 kg) ≈ -6.12 m/s²

The net acceleration of the boat ≈ 6.12 m/s² downwards

The boat's  net acceleration is -6.12 m/s²

Given that:

Buoyant force = 790 N, mass (m) = 214 kg, acceleration due to gravity (g) = 9.81 m/s²

Net force = Buoyant force - mg = 790 - (214 * 9.81) = -1309.34 N

Net acceleration = Net force / mass

Net acceleration = -1309.34 N / 214 kg = -6.12 m/s²

The boat's  net acceleration is -6.12 m/s²

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Which image shows the correct way of lining up vectors to add them together? A. two arrows lined up facing away from each another B. two arrows lined up one after the another C. two arrows lined up facing each another D. two arrows facing opposite to each other

Answers

The image shows the correct way of lining up vectors to add them together, that the two arrows lined up one after the other, therefore the correct answer is option B.

What is a vector quantity?

The quantities that contain the magnitude of the quantities along with the direction are known as the vector quantities.

Examples of vector quantities are displacement, velocity acceleration, force, etc.

Thus, the image shows the correct way of lining up vectors to add them together, that the two arrows lined up one after the other, therefore the correct answer is option B.

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What is the chemical energy content of the 100,000 kg of liquid hydrogen that was stored in the space shuttle's external fuel tank? How long could this energy power human civilization at our consumption rate of 16 TW?

Answers

Answer:

the time required is 0.886 seconds

Explanation:

The computation is shown below:

As we know that the content of the chemical energy that has a calorific value of hydrogen is 141790 kJ /kg

And, the total energy stores is 100,000 kg

Now

E = 141790 ×  100,000 kJ

= 14.179 TJ

The time would be

T = E ÷ P

= 14.179 ÷ 16

= 0.886 sec

hence the time required is 0.886 seconds

a ball is launched from a cliff 50 m high with a velocity of 25 m/sec at 37o above the horizontal. how fast will it be moving when it hits the ground?

Answers

The 15.04 m/s fast will it be moving when it hits the ground.

What is velocity ?

An object's velocity is a key factor in determining its position and rate of motion. It is comprehensible as the distance an object moves in a single interval of time. The term "velocity" describes how far an object travels in a predetermined length of time.

What is mass ?

Measuring inertia, a property of all stuff that cannot be changed. What a body of matter is in essence is the resistance it provides to a change in its speed or location brought about by the application of a force.

The vertical component of velocity is given by

usinθ

Here,u=25m/s and θ=37°

So,vertical component will be 25sin37°

And on further solving it would be 15.04 m/s.

Therefore, 15.04 m/s fast will it be moving when it hits the ground.

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For the three parts of this Quick Quiz, choose from the following choices the correct answer for the elastic modulus that describes the relationship between stress and strain for the system of interest, which is in italics: (a) Young's modulus (b) shear modulus(c) bulk modulus(d) none of those choices(i) A block of iron is sliding across a horizontal floor. The friction force between the block and the floor causes the block to deform.

Answers

The correct answer for the elastic modulus that describes the relationship between stress and strain for the system of interest, which is a block of iron sliding across a horizontal floor, is (b) shear modulus.

Young's modulus, also known as the modulus of elasticity, describes the relationship between stress and strain for an object undergoing uniform tension or compression. It is not applicable in this scenario because the block of iron is not experiencing uniform tension or compression.

Shear modulus, also known as the modulus of rigidity, describes the relationship between shear stress and shear strain for an object undergoing shearing forces. In this case, as the block of iron slides across the floor, the friction force causes the block to deform, which involves shearing forces. Therefore, the shear modulus is the appropriate elastic modulus for this scenario.

Bulk modulus describes the relationship between volumetric stress and volumetric strain for an object undergoing uniform changes in volume. It is not relevant to the situation of a block of iron sliding across a floor since there are no significant changes in volume occurring.

Thus, the correct choice for the elastic modulus in this case is (b) shear modulus.

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T/F the combined weight of the load and the platform is 200 lb, with the center of gravity located at g. a constant couple moment with magnitude

Answers

Constant couple moment with magnitude is 2.24rad/s.

Kinetic Energy and work:

Since the weight of the links is negligible and the crate and the platform undergo curvilinear translation, the kinetic energy of the system is

T = 1/2mv² = 1/(200/32.2)v²

T = 3.1056v²

Since the system is initially at the rest T₁ = 0. Bx, By, Dx, and Dy does no work while M does positive work and W does negative work. When θ =60, W displaces upward through a distance of h = 4sin60 ft = 3.464ft. Thus, the work done by M and W is

UM = mθ = 900(Π/3) = 300Π ft.lb

UW = - Wh = -200(3.464) = -692.82ft.lb

Principle of Work and Energy

T1 + Σ U1-2 = T2

0 + [300Π - 692.82] = 3.1056v²

v = 8.966ft/s

Thus,

wab = wcd = v/ρ = 8.966/4 = 2.24rad/s

Thus the moment with magnitude is 2.24rad/s.

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can someone help with this part of the sentence fills

can someone help with this part of the sentence fills

Answers

F = ma, or force equal to mass times acceleration, is Newton's second law of motion.

What happens in the second law of Newton?

Second Law of Movement by Newton Since it shows how powers and movement are connected, F=ma is essential. You can use it to determine an object's velocity and position, as well as its acceleration with known forces. For inventors, scientists, and engineers, This is extremely helpful.

As per Newton's Second Law of Movement, when a power works on a mass, the mass speeds up (gains speed) (object). When you ride a bicycle, you can see this law of motion in action in a great way. Your bike makes up the mass. Your leg muscles press against the bicycle's pedals to produce the force.

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What is the number at the end of an isotope’s name? atomic number neutron number mass number electron number

Answers

Answer:

C) mass number

Explanation:

I got it correct on edge

Answer:  c

Explanation:

What are the two goals of the Artemis Mission?

Answers

Answer:

The Artemis program is a U.S. government-funded international human spaceflight program that has the goal of landing the first woman and the next man on the Moon, specifically at the lunar south pole region, by 2024.

Follow me please

Mark brainliest

Pls pls help i have to submit in 10 min pls help

Pls pls help i have to submit in 10 min pls help

Answers

Answer:

left to right

Explanation

1. illonois

2. texas

3. Maine

4. Arizona

45oN 100oW

35oN 90oW

During construction, a crane lifts a 2,000-newton weight to the top of a 50-meter-tall building. How much power must the crane have to perform this task in 5 seconds? Use commas where appropriate and round to the nearest tenth.

watts:

kilowatts:

horsepower:

Answers

Answer:

Work is defined as force thru a distance:   W = F * S

Power is defined as Work per unit time  P = W / t

So we an write:  P = F * S / t  = 2000 N * 50 m / 5 s = 20,000 N-m/s

Since a Joule/sec is equivalent to a Watt

The power required is 20,000 Watts or 20  Kw

Also, you can convert to Hp since 1 Hp = 746 Watts

A 15kg object is travelling 10m/s and hit a stationary 10kg object and stuck together. What is the final velocity of the objects?

Answers

Answer:

first object final velocity =2m/s

second = 12m/s

Explanation:

i hope this will help you,..,

A 15kg object is travelling 10m/s and hit a stationary 10kg object and stuck together. What is the final

What is the energy of a photon with a frequency of 2.2 x 1016 Hz? Planck's constant is 6.63 x 10-34 Jos.
O 1.5 x 10-17
8.8 x 10-17
O 1.5 10-16
O 8.8 10-16

Answers

Answer: 1.5 × 10^-17

Explanation:

Given the following :

Frequency(f) = 2.2 × 10^16 Hz

Planck's constant(h) = 6.63 × 10^-34

The energy of a photon 'E' is given as the product of frequency and the planck's constant

E = hf

E = (6.63 × 10^-34) × (2.2 × 10^16)

E = 6.63 × 2.2 × 10^(-34 +16)

E = 14.586 × 10^-18

E = 1.4586 × 10^-17

E = 1.5 × 10-17 (2 S. F)

Answer:

C. 1.5 × 10–16 J

Explanation:

Just need the answer to D please

Just need the answer to D please

Answers

The boat has to pull with MORE force. Don't forget about the force of friction with the water, pulling the skier in the backwards direction. The force that accelerates him is the NET force ... boat force minus water resistance. So the boat force has to be greater than the net accelerating force.

At what velocity does a 10kg book dropped from 5 meters hit the ground at?

Answers

Answer:

10m

Explanation:

v²=u²+2as

=0²+2×10×5

=100

v =10m/s

The electric potential is 300 V at x = 0 cm , is -100 V at 1x = 5 cm, and varies linearly with x. If a positive charge is released from rest at x = 2.5 cm , and is subject only to electric forces, what will the charge do?(a) Move to the right.(b) Move to the left.(c) Stay at 2.5 cm(d) Not enough information to tell.

Answers

The charge will move to the left.

The electric potential varies linearly with x, so we can find the equation for the potential as:

V(x) = mx + b,

where m is the slope and b is the y-intercept. We can use the given points to solve for m and b:

300 V = m(0 cm) + b

-100 V = m(5 cm) + b

Subtracting the first equation from the second, we get:

-400 V = 5m

m = -80 V/cm

Substituting this value for m into one of the equations, we get:

300 V = -80 V/cm * (0 cm) + b

b = 300 V

So the equation for the potential is:

V(x) = -80 V/cm * x + 300 V

Now we can use the electric field to determine the direction of the force on the positive charge. The electric field is the negative gradient of the potential:

E(x) = -dV/dx = 80 V/cm

At x = 2.5 cm, the electric field is:

E(2.5 cm) = 80 V/cm

Since the charge is positive, it will experience a force in the direction of the electric field, which is to the left. Therefore, the charge will move to the left.

The answer is (b) Move to the left.

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Instead of lifting the box straight up, suppose you push it up a 1. 0- m -high ramp that makes a 30 ∘ degree angle with the horizontal, as shown in (Figure 1). Being clever, you choose a ramp with no friction. How much force is required to push the box straight up the slope at a constant speed?.

Answers

The required force to push the box straight up at a constant speed is zero.

Net force on the box at constant speed

The net force on the box is calculated by applying Newton's second law of motion as follows;

∑F = 0

F - Ff = ma

(at constant speed, acceleration is zero)

\(F- F_f = ma\\\\F - 0 = 0\\\\F = 0\)

Thus, the required force to push the box straight up at a constant speed is zero.

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A speedboat increases in speed from 17.3 m/s to 27.1 m/s in a distance 172 m. Find the magnitude of its acceleration. Answer in units of m/s2.
Show work please:)​

Answers

Answer:

1.26 m/s²

Explanation:

Given:

Δx = 172 m

v₀ = 17.3 m/s

v = 27.1 m/s

Find: a

v² = v₀² + 2aΔx

(27.1 m/s)² = (17.3 m/s)² + 2a (172 m)

a = 1.26 m/s²

Two sources vibrating in phase are 6.0cm apart. A point on the first nodal line is 30.0cm from a midway point between the sources and 5.0cm (perpendicular) to the right bisector
a) What is the wavelength?
b) Find the wavelength if a point on the second nodal line is 38.0cm from the midpoint and 21.0cm from the bisector
c) What would the angle be for both points

Answers

(a)  the wavelength is 66.0 cm, (b) the wavelength for the second nodal line is 82.0 cm and (c) the angle be for both points are θ = 0.1651 and θ' = 0.5049

To solve this problem, let's consider the interference pattern created by the two vibrating sources. We'll assume that the sources emit sound waves with the same frequency and are vibrating in phase.

a) To find the wavelength, we need to determine the distance between two consecutive nodal lines. In this case, we are given that a point on the first nodal line is 30.0 cm from the midway point between the sources.

Since the sources are 6.0 cm apart, the distance from one source to the midpoint is 3.0 cm (half the separation distance).

The distance between consecutive nodal lines corresponds to half a wavelength. Therefore, the wavelength (λ) can be calculated as follows:

λ = 2 × (distance from one source to the midpoint + distance from the midpoint to the first nodal line)

= 2 × (3.0 cm + 30.0 cm)

= 2 × 33.0 cm

= 66.0 cm

Therefore, the wavelength is 66.0 cm.

b) Similarly, for the second nodal line, we are given that a point on it is 38.0 cm from the midpoint and 21.0 cm from the bisector. Again, the distance from one source to the midpoint is 3.0 cm.

The wavelength (λ') between consecutive nodal lines can be calculated as:

λ' = 2 × (distance from one source to the midpoint + distance from the midpoint to the second nodal line)

= 2 × (3.0 cm + 38.0 cm)

= 2 × 41.0 cm

= 82.0 cm

Therefore, the wavelength for the second nodal line is 82.0 cm.

c) To find the angles at both points, we can use the properties of similar triangles. Let's consider the first point on the first nodal line.

The perpendicular distance from the point to the right bisector forms a right triangle with the distance from the point to the midpoint (30.0 cm) and the distance between the sources (6.0 cm).

Let's call the angle formed between the right bisector and the line connecting the midpoint to the point as θ.

Using the properties of similar triangles:

tan(θ) = (perpendicular distance) / (distance to the midpoint)

= 5.0 cm / 30.0 cm

= 1/6

Taking the inverse tangent of both sides:

θ = tan^(-1)(1/6) = 0.1651

Similarly, for the second point on the second nodal line:

tan(θ') = (perpendicular distance) / (distance to the midpoint)

= 21.0 cm / 38.0 cm

θ' = tan^(-1)(21.0/38.0) = 0.5049

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Newton’s first law of motion states that an object's motion remains the same unless a force acts upon it. What would be an example of this law in action?

Answers

Answer:

A driver breaks suddenly and the passengers are flung forward

(310-15(3)) Where conductors of different insulation are associated together, the limiting temperature of any conductor shall not be exceeded.(True/False)

Answers

True. When conductors of different insulation types are associated together, the limiting temperature of any conductor should not be exceeded.

Equation 310-15(3) is a reference to section 310-15 of the National Electric Code (NEC) which outlines rules for sizing conductors based on factors such as current-carrying capacity and temperature ratings. In this case, the statement is referring to situations where conductors with different types of insulation are used together, and emphasizes the importance of ensuring that the temperature limit for any individual conductor is not exceeded. This is critical for ensuring safe and reliable operation of electrical systems. This is to ensure the safety and proper functioning of all conductors, as well as preventing damage to the insulation and potential electrical hazards.

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Drift velocity (v) of the charge carriers is given by the equation...

Answers

The drift velocity (v) of charge carriers in a conductor is given by the following equation: v = I / (n \(\times\) A \(\times\) q).

v = I / (n \(\times\) A \(\times\) q)

where:

v is the drift velocity, measured in meters per second (m/s)

I is the current flowing through the conductor, measured in amperes (A)

n is the number of charge carriers per unit volume of the conductor, measured in per cubic meter (\(m^(-3)\))

A is the cross-sectional area of the conductor, measured in square meters (m^2)

q is the charge of a single carrier, such as an electron, measured in coulombs (C)

This equation relates the drift velocity of the charge carriers to the current flowing through the conductor, the number of charge carriers per unit volume, the cross-sectional area of the conductor, and the charge of a single carrier. The drift velocity represents the average velocity of the charge carriers as they move through the conductor in response to an applied electric field.

The number of charge carriers per unit volume (n) depends on the material of the conductor and the temperature. In metals, the charge carriers are typically electrons, and the number density is on the order of 10^28 to 10^29 electrons per cubic meter.

The cross-sectional area (A) of the conductor is the area of the cross-section of the conductor perpendicular to the direction of the current flow, and is a measure of the amount of material available for the charge carriers to move through.

The charge of a single carrier (q) is typically the charge of an electron, which is approximately 1.6 x \(10^{-19\) coulombs.

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Which one of these is Newton's 2 Law?
A=M*F
M=A*F
F=M+A
F=M*A

Answers

F=M*A is Newton’s 2 law

A string under a tension of 170 N has a frequency of 300 Hz.What will its frequency become if the tension is increased to 340 N?

Answers

The speed of the wave on a string is given by Taylor's formula:

\(v=\sqrt[]{\frac{F}{\mu}}\)

where

F = tension force

μ = linear density = mass per unit length

But also we can say the speed of any wave is given by:

\(v=\lambda\times f\)

where:

λ = wave length

f = frequency

Plug the second equation in the first one. We get:

\(\lambda\times f=\sqrt[]{\frac{F}{\mu}}\)

Now solve for f:

\(f=\frac{1}{\lambda}\times\sqrt[]{\frac{F}{\mu}}\)

Lets say wave length is the same on the second case. Since it's the same string μ will also be the same.

See that 340 N = 2 x 170, so we can write:

\(\begin{gathered} f_{new}=\sqrt[]{2}\times\frac{1}{\lambda}\sqrt[]{\frac{F}{\mu}} \\ f_{new}=\sqrt[]{2}\times f_{old} \\ f_{new}=\sqrt[]{2}\times300 \\ f_{new}\approx424Hz \end{gathered}\)

UVA and UVB rays can cause skin damage and skin cancer. True False

Answers

Answer:

true

Explanation:

they can cause skin damage

UVB rays have slightly more energy than UVA rays. They can damage the DNA in skin cells directly, and are the main rays that cause sunburns. They are also thought to cause most skin cancers.

a hiker of mass 59 kg is going to climb to the top of mount tam, which has an elevation of 2,574 ft.part (a) if the hiker starts climbing at an elevation of 560 ft, what will their change in gravitational potential energy be, in joules, once they reach the top? assume the zero of gravitational potential energy is at sea level.

Answers

457280.13 8 J change in gravitational potential energy is needed.

where

m = 68 kj

H = 2574 ft

where = 32 5 ft

a )if Gravitational potential energy is zero at see level .

then at strating

point,

Equation

G. P . E ( Ui ) = mgh

Change in G PE ;

AU = UJ - Vi

= mgy- mgh = mg ( H-h)

= 68 x9.81 [2574 - 325 0.3048

AU = 457280' 138 Joules

at top

GPE ( Uf ) = mgy

P . E = 0

GPF = Gravitational potential Energy .

at Top ape = 0

b)then change in GPE ;

ΔU = U(top) - Vata

= 0 - [-mg ( 4-h )]

= mg ( H-h j

= 68 * 9 . 81 [ 257 4 - 325 ) 0.3048

ΔU = 45 7280 . 13 8 J.

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(3.) A tourist travels 320 km in 3.6 h. What is her average speed for the trip?

Answers

Answer:

The average speed of the tourist is 88.89 km/h

Explanation:

Given;

distance of travel, d = 320 km

time of travel, t = 3.6 h

Average speed is given as;

average speed = distance / time

average speed = 320 km / 3.6 h

average speed = 88.89 km/ h

Therefore, the average speed of the tourist is 88.89 km/h

A car travels north along a certain highway at a constant speed of 40 miles per hour. It immediately turns around and returns south along the same highway at a constant speed of 50 miles per hour. What was its average speed for the entire round trip? (Hint: the answer is NOT 45 miles per hour)

Answers

Answer:

44.44 mph/44 4/9

Explanation:

It asks for distance and not time. If it said it travels 1 mile each way then it won't be 45 mph. If it was 1 hour one way and an hour back then it would be different distances but 45 mph.

We can just say the car traveled 40 miles and use it for this equation.

40 mph for 40 miles is 1 hour

50 mph for 40 miles is 48 minutes

48+60 minutes is 108

This is 44.44 miles per hour

or 44 4/9 if you want to show it more accurately

The force of gravity between two students is 3.5E-8 Newtons. If
the first students mass is 71.0 kg and the second students mass is
67.0 kg, how far apart must the students be from each other?

Answers

Answer:

I put both in an image so there is no plagiarizing.

Explanation:

Hope it helps!

The force of gravity between two students is 3.5E-8 Newtons. Ifthe first students mass is 71.0 kg and
The force of gravity between two students is 3.5E-8 Newtons. Ifthe first students mass is 71.0 kg and

an object that is 2.84 tall is located 25.2 in front of a lens. a virtual image is formed at a distance 36.6 from the lens. what is the focal length of the lens (in )?

Answers

To find the focal length of the lens, we can use the lens formula:

1/f = 1/v - 1/u

Where:

f is the focal length of the lens,

v is the distance of the virtual image from the lens, and

u is the distance of the object from the lens.

In this case, the object is located 25.2 inches in front of the lens, so u = -25.2 inches (negative because it is in front of the lens). The virtual image is formed at a distance of 36.6 inches from the lens, so v = 36.6 inches.

Substituting these values into the lens formula, we have:

1/f = 1/36.6 - 1/(-25.2)

Simplifying this equation, we get:

1/f = (1/36.6) + (1/25.2)

To combine the fractions, we need to find a common denominator. In this case, the least common multiple of 36.6 and 25.2 is 918, so we rewrite the equation as:

1/f = (25.2 + 36.6) / (36.6 * 25.2)

1/f = 61.8 / 918

1/f ≈ 0.0673

Now, we can take the reciprocal of both sides to find f:

f ≈ 1 / 0.0673

f ≈ 14.84 inches

Therefore, the focal length of the lens is approximately 14.84 inches.

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