Answer:
\43 ° n, 72 ° w
42° 0' 30" N, 71° 30' 58" W
A girl is running in a long distance race. As she runs, her respiration rate 10 points increases. Her body cells must process energy at a faster rate to power her muscles as she runs. Is this action a response to internal stimuli or external stimuli?
A. internal stimuli
B. external stimili
What is it called when particles in a solid or liquid move slower and closer together?
The reason at the time when particles in a solid or liquid move slower and closer together should be explained below.
What are particles?The particles should be in the form of small pieces of matters. Also, the scientist believed that each and everything in the universe should be made of the particles. here the range of the particles should be in the range via the large subatomic particles such as electrons or it has lower microscopic particles.
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Question 6:A particle of mass 0.2 kg is moving in a straight line at speed 2.5ms, a constant force of magnitude FN is applied to it in the direction in which it is moving. The speed of the particle 5 seconds later is 4.5ms Find the value of F, magnitude of the force applied.
First, let's calculate the particle acceleration, using the formula below:
\(\begin{gathered} V=V_0+a\cdot t \\ 4.5=2.5+a\cdot5 \\ 5a=4.5-2.5 \\ 5a=2 \\ a=\frac{2}{5}=0.4\text{ m/s}^2 \end{gathered}\)Now, to find the force applied, let's use the second law of Newton:
\(\begin{gathered} F=m\cdot a \\ F=0.2\cdot0.4 \\ F=0.08\text{ N} \end{gathered}\)Therefore the value of F is 0.08 N.
What is gravitational force
The force of attraction between all masses in the universe; especially the attraction of the earth's mass for bodies near its surface.
HELP!!!! NO LINKS!! Order the events that occur in the removal of thermal energy from an object by a refrigerator.
Answer:
Thermal energy is transferred from the warm object to the coolant in the refrigerator; coolant is compressed and the coolant's temperature rises (work is done on the coolant); thermal energy is transferred from the warm coolant to the outside air; the coolant expands as it passes through the expansion valve and cools.
Explanation:
hope this helps
Thermal energy is transferred from the hot object to the coolant in the refrigerator where the coolant is compressed and the temperature of the coolant rises, so thermal energy is transferred from the hot coolant to the outside air, the coolant expands as it passes through the expansion valve and is cooled.
How is thermal energy transferred in a refrigerator?An evaporator which contains a substance called refrigerant, that evaporates, turning from liquid to gas inside the coil which is located inside the freezer or refrigerator compartment. It transfers thermal energy from the surroundings to the refrigerant molecules.
As a liquid, the refrigerant absorbs thermal energy from the cold air inside the refrigerator and turns into a gas, while as a gas, it transfers thermal energy to the warm air outside the refrigerator and turns back into a liquid.
Thus, thermal energy is transferred from the hot object to the coolant in the refrigerator where the coolant is compressed and the temperature of the coolant rises, so thermal energy is transferred from the hot coolant to the outside air, the coolant expands as it passes through the expansion valve and is cooled.
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True or false? One reason gases are easy to compress is because their particles have higher energy.
The given statement is true as molecules in gas are far away from each other due to weak forces of attraction.
What are forces of attraction?
Forces of attraction is a force by which atoms in a molecule combine. it is basically an attractive force in nature. It can act between an ion and an atom as well.It varies for different states of matter that is solids, liquids and gases.
The forces of attraction are maximum in solids as the molecules present in solid are tightly held while it is minimum in gases as the molecules are far apart . The forces of attraction in liquids is intermediate of solids and gases.
The physical properties such as melting point, boiling point, density are all dependent on forces of attraction which exists in the substances.
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Two students are running in a race. Student 1 has more kinetic energy than student 2. Who will win the race?
You've got a flat tire. To lift your car, you make a homemade lever (see the figure (Figure 1)). A very light 1.6-m-long handle part is pushed down on the right side of the fulcrum and a 0.050-m-long part on the left side supports the back of the car.
How hard must you push down on the handle so that the lever exerts an 6900- N force to lift the back of the car?
How hard you must push down on the handle is by applying a force of 215.63 N
Moment of a forceThe moment of a force about a point is the turning effect of the force about that point.
The moment of a force M = Fd where
F = force and d = perpendicular distance of force from pivot point.Now, for you to lift up the car, the moment due to your force about the fulcrum, M equals the moment due to the force on back of car. M'
M = M'
FD = F'd where
F = Force applied, D = distance of force from fulcrum = 1.6 m, F' = force applied on back of car = 6900 N and d = distance of force on back of car from fulcrum = 0.050 mMaking F subject of the formula,we have
F = F'd/D
Substituting the values of the variables into the equation,we have
F = F'd/D
F = 6900 N × 0.050 m/1.6 m
F = 345 Nm/1.6 m
F = 215.625 N
F ≅ 215.63 N
So, how hard you must push down on the handle is by applying a force of 215.63 N
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What is the distance from the moon to the sun?
Answer:
About 150 million kilometers
Explanation:
have good day♡
Which has the greater mass? select one: a. king-size pillow b. automobile battery c. both about the same
An automobile battery has more mass as compared to a king-size pillow.
Mass is defined as the measure of the amount of matter contained in a body. On the other hand, weight is defined as the amount of force particularly gravitational force acting on a body.
Although the weight of the same body can be different for different cases which if were the case we couldn't use weight to tell which body has more mass, but here we are considering the weight is being compared in identical conditions and hence, the body which has more weight has more mass. Which in our case is a car battery.
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A fiber-optic rod consists of a central strand of material surrounded by an outer coating. the interior portion of the rod has an index of refraction of 1.55. if all rays striking the interior walls of the rod with incident angles greater than 59.5° are subject to total internal reflection, what is the index of refraction of the coating?
Answer:
the index of refraction of the coating is 1.33
Explanation:
Given the data in the question;
refraction index of interior portion of the rod η\(_{interior\) = 1.55
angle of incidence θ\(_i\) = 59.5°
From Snell's law, we know that;
η\(_{interior\) × sinθ\(_i\) = η\(_{coating\) × sinθ\(_r\)
where η\(_{interior\) is the index of refraction of the rod ( material 1 )
θ\(_i\) is the angle of incidence
η\(_{coating\) is the index of refraction in outer coating ( material 2 )
θ\(_r\) is the angle of refraction
so we substitute our values into the equation;
η\(_{interior\) × sinθ\(_i\) = η\(_{coating\) × sinθ\(_r\)
1.55 × sin( 59.5° ) = η\(_{coating\) × sin( 90° )
1.55 × 0.861629 = η\(_{coating\) × 1
1.3355 = η\(_{coating\) × 1
η\(_{coating\) = 1.33 { 2 decimal places }
Therefore, the index of refraction of the coating is 1.33
An iPad charger has 45 Ohms of resistance and a current of 0.2
amps flowing through it.
How much voltage is supplied to the iPad charger?
Answer:
V = 9 volts
Explanation:
Ohm's Law gives a relationship between the voltage supply and the current passing through a circuit. The formula given by the Ohm's Law is written as follows:
V = IR
where,
V = Voltage supplied to the charger = ?
I = Current flowing through the circuit of the charger = 0.2 A
R = Resistance of the charger = 45 Ohms
Therefore, using these values in the equation, we get:
V = (0.2 A)(45 Ohms)
V = 9 volts
The largest grand piano in the world is really grand. Built in London, it has a mass of 1,152 kg. Suppose a pianist finishes playing this piano and pushes herself from the piano so that she rolls backwards with a speed of 1.5 m/s. Meanwhile, the piano rolls forward with a constant velocity of 0.06 m/s. Assuming the stool that the pianist is sitting on has a negligible mass, what is the pianist’s mass? Round to the hundredths.
ANSWER:
46.08 kg
STEP-BY-STEP EXPLANATION:
Given
m1 = 1152 kg
v1 = 0.06 m/s
v2 = -1.5 m/s
We apply law of conservation of linear momentum:
\(\begin{gathered} P_i=P_f \\ P_i=0 \\ P_f=m_1\cdot V_1+m_2\cdot V_2 \end{gathered}\)We plug in and calculate for the mass, just like this:
\(\begin{gathered} 0_{}=m_1\cdot V_1+m_2\cdot V_2 \\ 0=1152\cdot0.06+m_2\cdot-1.5 \\ -1.5m_2=-69.12 \\ m_2=\frac{-69.12}{-1.5} \\ m_2=46.08\text{ kg} \end{gathered}\)Which means that the mass of the pianist is 46.08 kg
A volume of air has a temperature of 0 degrees C. An equal volume of air that is twice as hot has a temperature ofA) 0 degrees CB) 64 degrees CC) 100 degrees CD) 273 degrees CE) none of the above choices are correct
The temperature of a volume of air is 0 degrees Celsius. The temperature of an equivalent volume of air that is twice as hot is (D) 273 degrees C.
This is due to the fact that the absolute temperature scale, or 273.15 Kelvin (K), converts 0 degrees Celsius to K. The temperature of an identical volume of air would be twice as hot as the air at 0 degrees Celsius, or 2 times 273.15 K, or 546.3 K.
However, we must deduct 273.15 from the Kelvin temperature in order to convert this temperature back to degrees Celsius. This is so because the Celsius scale is based on the 273.15 K and 373.15 K freezing and boiling temperatures of water, respectively.
The temperature is 273.15 degrees Celsius, which is the same as the freezing point of water in Celsius, when we subtract 273.15 from 546.3 K. Consequently, 273 degrees Celsius is the right response.
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Ratio of acceleration due to grabity and universal gravitational constant
Answer:
acceleration due to gravity = 9.8m/s^2
universal gravitational constant= 6.67×10 ^_11 nm^2 kg_2
now, ratio=9.8/6.67×10^_11.
an object is thrown straight up with an initial velocity of 20.0 m/s, and there is an air resistance force which would cause an acceleration of 3.00 m/s2 opposite the direction of motion. with what speed does the object return to the ground?
As the object is thrown up with the initial velocity of 20.0 m/s, and there is an air resistance force that would cause an acceleration of 3.00 m/s2, the speed of the object as a return to the ground is 10.8 m/s.
Kinematic equations
The kinematic equations are a set of equations that describe the motion of an object with constant acceleration.
When we have an initial velocity value, it is written as Vo, while for the final velocity, we simply write V or Vt. As an object moves through the air, air resistance slows the object’s speed.
The formula of the kinematic equation used for solving this case is
Vt = V0 + at (the gravity is 10 m/s2)
\(Vt = Vo + (-g-a)t\\\0 = 20 + (-10-3)t\\0 = 20-13t\\\13t = 20\\\t = \frac{20}{13}\)
After the time is known, now we can insert the value into the following formula :
\(Vt = Vo + (g-a)t\\Vt = 0 + 7.\frac{20}{13} \\Vt = 0 + \frac{140}{13} \\\Vt = 10.8 m/s\)
Thus, the speed of the object returns to the ground after being thrown up with an initial velocity of 20.0 m/s and acceleration of 3.00 m/s2, which is 10.8 m/s.
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Rank from earliest to latest. To rank items as equivalent, overlap them.
A. The cloud is large, cool, and slowly rotating
B. The cloud collapses into a disk
C. Competing rotational and gravitational forces begin to flatten the cloud
D. The cloud becomes denser, heats up, and rotates faster
E. The cloud starts to contract under the influence of gravity
The correct order from the earliest to the latest will be: The cloud is large, cool, and slowly rotating, The cloud collapses into a disk, The cloud starts to contract under the influence of gravity, Competing rotational and gravitational forces begin to flatten the cloud, and the cloud becomes denser, heats up, and rotates faster. Therefore, the order will be A, B, E, C, and D.
What is Nebula?A nebula is an enormous cloud of the dust particles and gas which occupies the space between the stars and acting as a nursery for many new stars. Nebulae are made up of dust, basic elements include gases such as hydrogen and other ionized gases.
Nebula Formation include in essence, when portions of the interstellar medium undergo gravitational collapse. Mutual gravitational attraction causes the matter to clump together, forming regions of greater and greater density.
The formation events which occur within a cloud from earliest to latest are:
A. The cloud is large, cool, and slowly rotating
B. The cloud collapses into a disk.
E. The cloud starts to contract under the influence of gravity
C. Competing rotational and gravitational forces begin to flatten the cloud.
D. The cloud becomes denser, heats up, and rotates faster
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Your question is incomplete, most probably the complete question is:
The process of star and planet formation begins with a large cloud of gas and dust called a solar nebula. Rank the formation events that occur within a cloud from earliest to latest.
Rank from earliest to latest. To rank items as equivalent, overlap them.
A. The cloud is large, cool, and slowly rotating
B. The cloud collapses into a disk
C. Competing rotational and gravitational forces begin to flatten the cloud
D. The cloud becomes denser, heats up, and rotates faster
E. The cloud starts to contract under the influence of gravity
2. A disturbance that generates a wave may be a simple pulse or shock.
b. False
a.
True
That's true.
-- a bell starts ringing (wave) when you tap it (simple pulse)
-- a pond starts rippling (wave) when a stone drops in (simple shock)
-- a guitar strings starts waving when you pluck it
If you were standing at the very end of the roller coaster, watching as the car came straight toward you, what kind of movement would you see?
When the roller coaster moves downwards, kinetic energy is created due to the speed and mass of the roller coaster
(rlly just guessing what this question relates to so take this with a grain of salt)
1) Un cuerpo se mueve desacelerando a razón de 8m/s2, calcula: a) La velocidad que tenía 5 segundos antes de detenerse. b) La distancia recorrida los últimos 5 segundos de su trayectoria.
Answer:
Initial velocity (u) = 40 m/s
Distance travel in last 5 seconds = 100 m
Explanation:
Given:
Acceleration (a) = 8 m/s²
Final velocity (v) = 0 m/s
Find;
1] Initial velocity before 5 sec
2] Distance travel in last 5 seconds
Computation:
1] Initial velocity before 5 sec
v = u + at
0 = u + (-8)(5)
u - 40 = 0
Initial velocity (u) = 40 m/s
2] Distance travel in last 5 seconds
s = ut + (1/2)(a)(t²)
s = (40)(5) + (1/2)(-8)(5²)
s = 200 - 100
Distance travel in last 5 seconds = 100 m
Select all statements below that are true about sound waves.
A(Sound is caused when something vibrates.
B(Sound moves by longitudinal waves.
C(Sound is a type of mechanical energy.
D(A medium is not required for sound to travel, but sound can move through a vacuum (empty space).
E(Pitch and loudness are not characteristic of sound waves
The true statement about sound waves include; Sound is caused when something vibrates, and Sound moves by longitudinal waves.
option A and B are the correct answers.
What is a mechanical wave?
A mechanical wave is a type of wave that requires material medium for its propagation.
A mechanical wave can be of two types based on mode of propagation;
longitudinal wavetransverse waveA longitudinal wave travels parallel to the direction of the wave's vibration, while transverse wave travels perpendicular to the direction of the wave's vibration.
An example of longitudinal wave is sound wave. Pitch and loudness are basic characteristic of sound waves because they determine the quality of the sound.
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A solid substance A is soluble in water to the extent of 10 mg/mL of water at 25°C and 100 mg/mL of water at 100°C. You have a sample that contains 100 mg of A and an impurity B. Assume that the solubilities of A and B are unaffected by the presence of the other substance. a. Assuming that 2 mg of B are present along with 100 mg of A, describe how you can purify volume of solvent needed. Assuming that 2 mg of the impurity B are present along with 100 mg of A, describe how you can purify A if B has the same solubility behavior as A. Will one crystallization produce pure A? Assume that 25 mg of B are present along with 100 mg of A. How can you purify A if B has the same solubility behavior as A? Each time, use the minimum amount of water to A if B is completely insoluble in water. Your description should include the b. c. just dissolve the solid. Show your work. Will one crystallization produce pure A? If not, how many crystallizations will be needed? How much pure A will be recovered?
a) To purify A, dissolve the sample in hot water, filter, and cool to room temperature. One crystallization may not produce pure A. b) Repeat the process until pure A is obtained. Recovery depends on yield.
To decontaminate A when 2 mg of contamination B is available alongside 100 mg of A, we can disintegrate the example in the base measure of water expected to break up A totally. Then, we can channel the answer for eliminate any insoluble pollutants. Then, we can cool the answer for 25°C to take into consideration the precipitation of unadulterated A. Since B has a similar solubility conduct as A, it will likewise encourage out of arrangement alongside A. One crystallization won't deliver unadulterated An as B will likewise be available. Consequently, numerous crystallizations will be expected to clean A totally. How much unadulterated A recuperated will rely upon the proficiency of the crystallization cycle and the solvency of An at the given temperature. To sanitize A when 25 mg of debasement B is available, a similar interaction can be followed, yet various crystallizations will be expected to totally eliminate B.
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A 1,725 kg car accelerates from 3.0 m/s for 4.4 s and reaches a velocity of 12.0 m/s. Ignoring friction, what is the applied force from the engine?
Given:
The mass of the car is m = 1725 kg
The initial velocity of the car is
\(v_i=\text{ 3 m/s}\)The final velocity of the car is
\(v_f=\text{ 12 m/s}\)The time is t = 4.4 s
To find the applied force.
Explanation:
The force can be calculated by the formula
\(F=\text{ ma}\)Here, a is the acceleration.
The acceleration can be calculated as
\(\begin{gathered} a=\frac{v_f-v_i}{t} \\ =\frac{12-3}{4.4} \\ =2.045\text{ m/s}^2 \end{gathered}\)On substituting the values, the force applied will be
\(\begin{gathered} F=ma \\ =1725\times2.045 \\ =3527.625\text{ N} \end{gathered}\)Thus, the applied force is 3527.625 N
Suppose that you walk 15 meters at 30 degrees as measured from the East. Then you walk another 25 meters at 60 degrees from the East what is your net displacement
Answer:
The net displacement is
\(R= \sqrt{A^2+B^2+2AB \cos \theta}\)
\(=\sqrt{15^2+25^2+2AB \cos 30^\circ} \\\\=\sqrt{225+625+ \cos30^0} \\\\=38.7m\)
Explanation:
Suppose that you walk 15 meters at 30 degrees as measured from the East. Then you walk another 25 meters at 60 degrees from the East what is your net displacement
Given data
A = 15 m
B = 25 m
Angle between the vectors A and B is θ = 30°
The net displacement is
\(R= \sqrt{A^2+B^2+2AB \cos \theta}\)
\(=\sqrt{15^2+25^2+2AB \cos 30^\circ} \\\\=\sqrt{225+625+ \cos30^0} \\\\=38.7m\)
what is observed when a charged perspex rod is placed close to a suspended polystyrene sphere
When a charged body is placed near the conductor, the opposite charge is appeared on the one side of the uncharged conductor body near the charged body under the effect of induction.
The opposite charge on the another body is also known as the induced charge.
The perpex rod in the given question is charged.
let the charge on the perpex is positive as shown in the figure.
Then, the polystrene sphers (insulator uncharged sphere) will not have any charge induced as the charges are not free to move inside the insulator.
Thus, when a charged perspex rod is placed close to a suspended polystyrene sphere then the induced charge on the sphere is not observed under the phenomenon of induction process and sphere remain uncharged.
if we measure distance with foots how much error generates?
Answer:
It generates many of the mistakes
Explanation:
When we meassure the distance with foot uniform velocity there there may arise many problems people foots are different to each other When we are measuring the distance from foot that is uniform velocity we must be very careful the timing of time and foot should be similar If not than there may generate many errors
The great mathematician Pythagoras also used the measurement with foot and he was successful because of his timing due to this he find the circumference of earth
20 POINTS
A 1400 kg car moving north at 24.0 m/s collides with a 2200 kg car moving east at 18.0 m/s. The
two cars stick together after the collision. What is the speed and direction of the two cars after
the collision?
When a marble rolls from starting point to a stopping point the type of motion is called __________ _______.
Answer: Rotational motion
Explanation: The two types of motion of the rolling ball are translational motion and rotational motion. The center of mass of the ball undergoes translational motion whereas the ball undergoes rotational motion in the center of mass frame.
Two microwave frequencies are authorized for use in microwave ovens, 890 and 2550 MHz. Calculate the wavelength (in cm) of each.
The wavelengths are approximately 33.71 cm for 890 MHz and 11.76 cm for 2550 MHz.
The wavelength of a wave is inversely proportional to its frequency. The formula to calculate wavelength is λ = c/f, where λ represents the wavelength, c is the speed of light (approximately \(3*10^8\) meters per second), and f is the frequency of the wave. To convert the frequency from megahertz (MHz) to hertz (Hz), we multiply the frequency by \(10^6\).
For the first frequency of 890 MHz, we can calculate the wavelength as follows:
λ = c/f = \((3*10^8 m/s)/(890*10^6 Hz)\) ≈ 33.71 cm.
Similarly, for the second frequency of 2550 MHz:
λ = c/f = \((3*10^8 m/s)/(2550*10^6 Hz)\) ≈ 11.76 cm.
Hence, the wavelength of the authorized microwave frequencies used in microwave ovens is approximately 33.71 cm for 890 MHz and 11.76 cm for 2550 MHz. These wavelengths determine the size and shape of the microwave oven cavity, ensuring that the microwaves are resonant and can efficiently heat food.
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