which compound(s) will not form a yellow precipitate when treated with excess iodine in the presence of naoh? select the unreactive structure(s):

The necessary voltage to power the electrolysis of molten sodium chloride is 4V.

Electrolysis is the breakdown of a compound into the elements it is formed from by passing electricity through it. It is actually a chemical reaction in which one element loses electrons and the other may gain electrons. The process of electrolysis has wide applications in electroplating, metallurgical processes, production of chlorine gas, etc.

Molten sodium chloride is generally used in the production of chlorine gas and sodium metal. This molten or aqueous form of sodium chloride is also known as brine. The process is carried out in a cell called the Down's cell.

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Answer:

b,c,d

Explanation:

bc i got it right

The apparatus that could be used to detect that a chemical change occurred with a substance in a laboratory setting are as follows:

Thus, the correct options for this question are B and C.

A chemical change may be defined as an alteration in the properties of one material into another. New materials or substances are formed with different properties along with appearance. It results when a substance combines with another to form a new substance.

An odor test and detecting the liberation of gas in the experiment are some of the best ways to reveal whether a chemical change may occur during the reaction or not, while the rest of the options are not as much as practical.

Therefore, the correct options for this question are B and C.

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Answer:

brain HSHSHSHSHHSSHSHS

Answer:

\(Al^{3+}\)

Explanation:

Aluminum has 13 protons. When it loses electrons it becomes positive. So losing each electron adds +1 making the resulting ion \(Al^{3+}\)

The diffferent ways birds use to protect itself are:

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Answer:

in science a lot as a general statement that explains a large number of observations before being accepted a llama be verified many times under many conditions law are therefore considered the highest form of scientific knowledge and are generally thought to be inviolable scientific laws for form the core of scientific knowledge 1 scientific law that provides the foundation for understanding in chemistry is the law of conservation of matter states that in any given system that is closed the transfer of matter in an out the amount of matter in the system stays constant the concise way of expressing this law is to say that the amount of matter in a system is conserved

Answer: ≈ 67.4 g

Explanation:

A(t) = amount remaining in t years        = A0ekt, where A0 is the initial amount and k is a constant to                     be determined.   Since A(1690) = (1/2)A0 and A0 = 80,                   we have 40 = 80e1690k                  1/2 = e1690k                  ln(1/2) = 1690k                  k = -0.0004 So, A(t) = 80e-0.0004t  Therefore, A(430) = 80e-0.0004(430)                             = 80e-0.172                             ≈ 67.4 g

Answer:

total displacement \time

Explanation:

Answer:

Choice A: approximately \(0.12\; \rm M\).

Explanation:

Note that the unit of concentration, \(\rm M\), typically refers to moles per liter (that is: \(1\; \rm M = 1\; \rm mol\cdot L^{-1}\).)

On the other hand, the volume of the two solutions in this question are apparently given in \(\rm cm^3\), which is the same as \(\rm mL\) (that is: \(1\; \rm cm^{3} = 1\; \rm mL\).) Convert the unit of volume to liters:

Calculate the number of moles of \(\rm H_2SO_4\) formula units in that \(0.02\; \rm L\) of the \(0.09\; \rm M\) solution:

\(\begin{aligned}n(\mathrm{H_2SO_4}) &= c(\mathrm{H_2SO_4}) \cdot V(\mathrm{H_2SO_4})\\ &= 0.02 \; \rm L \times 0.09 \; \rm mol\cdot L^{-1} = 0.0018\; \rm mol \end{aligned}\).

Note that \(\rm H_2SO_4\) (sulfuric acid) is a diprotic acid. When one mole of \(\rm H_2SO_4\) completely dissolves in water, two moles of \(\rm H^{+}\) ions will be released.

On the other hand, \(\rm NaOH\) (sodium hydroxide) is a monoprotic base. When one mole of \(\rm NaOH\) formula units completely dissolve in water, only one mole of \(\rm OH^{-}\) ions will be released.

\(\rm H^{+}\) ions and \(\rm OH^{-}\) ions neutralize each other at a one-to-one ratio. Therefore, when one mole of the diprotic acid \(\rm H_2SO_4\) dissolves in water completely, it will take two moles of \(\rm OH^{-}\) to neutralize that two moles of \(\rm H^{+}\) produced. On the other hand, two moles formula units of the monoprotic base \(\rm NaOH\) will be required to produce that two moles of \(\rm OH^{-}\). Therefore, \(\rm NaOH\) and \(\rm H_2SO_4\) formula units would neutralize each other at a two-to-one ratio.

\(\rm H_2SO_4 + 2\; NaOH \to Na_2SO_4 + 2\; H_2O\).

\(\displaystyle \frac{n(\mathrm{NaOH})}{n(\mathrm{H_2SO_4})} = \frac{2}{1} = 2\).

Previous calculations show that \(0.0018\; \rm mol\) of \(\rm H_2SO_4\) was produced. Calculate the number of moles of \(\rm NaOH\) formula units required to neutralize that

\(\begin{aligned}n(\mathrm{NaOH}) &= \frac{n(\mathrm{NaOH})}{n(\mathrm{H_2SO_4})}\cdot n(\mathrm{H_2SO_4}) \\&= 2 \times 0.0018\; \rm mol = 0.0036\; \rm mol\end{aligned}\).

Calculate the concentration of a \(0.03\; \rm L\) solution that contains exactly \(0.0036\; \rm mol\) of \(\rm NaOH\) formula units:

\(\begin{aligned}c(\mathrm{NaOH}) &= \frac{n(\mathrm{NaOH})}{V(\mathrm{NaOH})} = \frac{0.0036\; \rm mol}{0.03\; \rm L} = 0.12\; \rm mol \cdot L^{-1}\end{aligned}\).

Molecular mass/ empirical formula mass = n

Where n is a whole number.

For the above question, n = 2

The above formula is used to calculate the formula mass of a compound.

Where n, that is the answer, should be a whole number or very close to a whole number.

Molecular mass = 220.771 g/mol

Se molecular weight =78.96

Cl molecular weight = 35

The formula mass = 78.96+35.45 = 114.41

Thus, n = 220/114 = 2

Hence value of n=2  

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The pressure of the gas in the container when the volume is 132.5 mL is 465.54 torr (rounded to the nearest 0.01) with units of torr.

To solve this question, we can use the ideal gas law equation, PV = nRT, where P is the pressure, V is the volume, n is the number of moles of gas, R is the universal gas constant, and T is the temperature. Since the sample of neon is at a constant temperature and the number of moles of gas is constant, we can use the equation P1V1 = P2V2, where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume.
Using the given values, we can write:
P1V1 = P2V2
(757.2 torr) x (81.4 mL) = P2 x (132.5 mL)
Solving for P2, we get:
P2 = (757.2 torr x 81.4 mL) / 132.5 mL
P2 = 465.54 torr
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The molar concentration of a 12% sodium chloride solution is approximately 2.05 M.

To determine the molar concentration of a 12% sodium chloride solution, we need to convert the given percentage concentration into molarity.

First, we need to understand that the percentage concentration refers to the mass of the solute (sodium chloride) relative to the total mass of the solution.

In this case, a 12% sodium chloride solution means that there are 12 grams of sodium chloride in 100 grams of the solution.

To convert this into molar concentration, we need to consider the molar mass of sodium chloride, which is 58.5 g/mol.

We can start by calculating the number of moles of sodium chloride in 12 grams:

Moles of sodium chloride = mass of sodium chloride / molar mass of sodium chloride

Moles of sodium chloride = 12 g / 58.5 g/mol = 0.205 moles

Next, we calculate the volume of the solution in liters using the density of the solution. Since the density is not provided, we assume a density of 1 g/mL for simplicity:

Volume of solution = mass of solution / density

Volume of solution = 100 g / 1 g/mL = 100 mL = 0.1 L

Finally, we calculate the molar concentration (Molarity) by dividing the number of moles by the volume in liters:

Molar concentration = moles of solute / volume of solution

Molar concentration = 0.205 moles / 0.1 L = 2.05 M

Therefore, the molar concentration of a 12% sodium chloride solution is approximately 2.05 M.


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Answer:

As an indicator

Answer:

II and III

Explanation:

(second and third)

Matter is made of particles. Which can be best explained using the model of dissolving salt in water forming a salt solution.Thus option 2 is correct.

A solution is made of a solvent solute particles. A compound is made from the combination of one or more different atoms. Thus the basic unit of every substances is atoms. Atoms are made of subatomic particles electrons, protons and neutrons.

In a compound the basic units that its molecules can be called as the constituent particles of the compound. Similarly for a solution the constituent particles are solvent molecules and solute molecules.

When we dissolve salt in water, the salt molecules are combining with the solvent molecules and forming a compound. Hence, we are making a  compound by it constituent particles. Thus, option 2 is correct.

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Answer:

they are only efficient in certain areas

Explanation:

Wind turbine are efficient only in certain areas it is a problem with using wind turbines to produce energy.

Wind turbine convert the wind energy into the electricity. It is a power generating device that converts the kinetic energy in to electrical energy.

Now lets check all option one by one:

Option (A): Wind turbines are efficient only in certain areas it is a problem with using wind turbines to produce energy because the flow of air from areas of high pressure towards the lower pressure.

So, it is correct option.

Option (B): Wind turbines occupy a lot of space to work.

So, it is incorrect option.

Option (C): Wind turbines produce a large amount of energy is not a problem.

So, it is incorrect option.

Option (D): Wind turbines does not create a pollution or it does not pollute the air or water.

So, it is incorrect option.

Thus, we can say that Wind turbines are efficient only in certain areas it is a problem with using wind turbines to produce energy because the flow of air from areas of high pressure towards the lower pressure.

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The product formed when the given compound is treated with LDA in THF solution at low temperature followed by CH3CH2I is the corresponding alkene (an elimination product).

The given response includes two stages: first, treatment with LDA (lithium diisopropylamide) in THF (tetrahydrofuran) arrangement at low temperature, and second, response with CH3CH2I. LDA is areas of strength for an and is many times utilized in natural science as a reagent for deprotonation responses. For this situation, it will extract a proton from the carbon neighboring the nitrogen iota, bringing about the development of an enolate middle of the road. This halfway is then gone after by the electrophilic CH3CH2I, prompting the end of a leaving bunch (normally LDA or THF) and the development of the comparing alkene. Generally, this response is an illustration of an end response and is usually utilized in natural combination to shape alkenes from proper beginning materials.

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Mixing hydrochloric acid (HCl) and potassium cyanide (KCN) can indeed form a toxic gas. When HCl and KCN are combined, they react to form hydrogen cyanide gas (HCN).

Hydrogen cyanide is a highly toxic gas that can cause rapid asphyxiation due to its ability to bind to hemoglobin in the blood and prevent oxygen from being transported to the body's tissues. Inhaling even small amounts of hydrogen cyanide gas can be fatal.

It's important to note that this reaction should be handled with extreme caution, as both HCl and KCN are highly corrosive and toxic substances. It's not recommended to mix these substances, and if it is necessary to do so, appropriate safety precautions should be taken, such as wearing protective gear and handling the substances in a well-ventilated area.  

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To solve this problem, let's use the definition for molarity:

Replacing the values of the problem:

Now, to find the mass, we multiply by the molecular weight of NaCl. (Which is about 58.44g/mol)

The answer is approximately 22.2g of NaCl

Answer:

Chemistry reactions are used in art for the following processes;

1) Analog photography

The photographic paper used in analog photography react when exposed to light such that the image on the film stains the photopaper

A series of chemicals are further used to develop the images now carried on the paper and water is used to rinse of the chemicals after the other chemical processes are complete

The photopaper, now bearing the developed photo is hung for it to be dried

2) Paint used for painting consists of several chemicals, including, minerals that serve as pigment, oils that serve as carrying agent, a thinner to prevent the paint from turning to solid

An artist therefore combines different chemicals for a given paint task

3) In the sculpting process

An original sculpture is produced by the artist with the aid of clay or plaster, from the original sculpture, on which wax coatings and chemicals are used to make a replica mold.

Copies of the sculpture can then be made by pouring material into the mold

Explanation:

The reaction is;

2Na + 2H2O → 2NaOH + H2

Answer:

4.4 × 10^(23) atoms

Explanation:

The reaction is;

2Na + 2H2O → 2NaOH + H2

2 moles of Na produces 1 mole of H2 from the equation reaction.

Thus, since 8.2 L of hydrogen gas at STP are produced. And we know that at STP, 1 mole of a gas will have a volume of 22.4 L, and also, We know according to avogadro's number that, 1 mol = 6.02 × 10^(23) atoms, Thus;

8.2 L of H2 × (1 mole of H2/22.4 L) × (2 mole of Na/1 mole of H2) × (6.02 × 10^(23) atoms/1 mole of Na) = 4.4 × 10^(23) atoms

Answer:

c) more OH⁻ ions than H₃O⁺ ions

Explanation:

A substance with a PH of 9 implies that it has more OH⁻ ions than H₃O⁺ ions.

Such substances are said to be an alkaline or a base.

A base is a substance the produces excess hydroxyl ion in aqueous solutions.

An acid will produce excess hydroxonium ions in a solution.

So, the pH scale is used to indicate whether a substance is an acid or base or non of them.

Acids have pH of less than 7

Bases have pH of > 7

We know that a chemical reaction has occurred by the appearance of a solid, evolution of a gas or change of color.

A chemical reaction refers to an interaction between reactants which leads to the formation of a product. A chemical reaction is represented using a chemical reaction equation.

We know that a chemical reaction has occurred when new substances appear in the system. This is signaled by the appearance of a solid, evolution of a gas or change of color.

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Answer:

1. a

2.b

Explanation:

1. B, the energy associated with the motion of an object

2. C, 12.4 g/mL

3. C, 5

1) B) Kinetic energy is energy associated with the motion of an object.

2) B) Density equals mass divided by volume: 1.38 g/mL

3) C) There are 5 significant figures in 20.300

4) A) 80 is the atomic number for mercury on the periodic table.

5) E) The formula for copper (II) sulfate pentahydrate is CuSO4•5H2O

So in summary:

• Kinetic energy is the energy of a moving object due to its motion.

• Density is calculated by dividing an object's mass by its volume.

• Significant figures refer to the known precision of a measurement based on the digits reported.

• Atomic symbols represent elements on the periodic table.

• Chemical formulas use symbols of the elements to show the proportions of atoms in a compound.

a) The Avogadro constant, which represents the number of particles (atoms, molecules, ions, etc.) in one mole of a substance, is approximately equal to 6.02 x \(10^23\). Therefore, the number of moles of carbon present in 2 x \(10^23\) atoms of carbon can be calculated as follows:

moles of carbon = (number of atoms of carbon) / (Avogadro's constant)

moles of carbon = 2 x\(10^23\)/ 6.02 x \(10^23\)

moles of carbon = 0.332 moles (rounded to three significant figures)

b) To determine the mass of carbon represented by 2 x \(10^23\) atoms, we need to know the molar mass of carbon. The molar mass of carbon is approximately 12.01 g/mol. Therefore, the mass of carbon represented by 2 x \(10^23\) atoms can be calculated as follows:

mass of carbon = (moles of carbon) x (molar mass of carbon)

mass of carbon = 0.332 mol x 12.01 g/mol

mass of carbon = 3.99 g (rounded to three significant figures)

c) To determine the mass of 2 x \(10^23\) molecules of hydrogen chloride, we need to know the molar mass of hydrogen chloride. The molar mass of hydrogen chloride is approximately 36.46 g/mol (1.01 g/mol for hydrogen and 35.45 g/mol for chlorine). Therefore, the mass of hydrogen chloride represented by 2 x \(10^23\) molecules can be calculated as follows:

mass of hydrogen chloride = (moles of hydrogen chloride) x (molar mass of hydrogen chloride)

moles of hydrogen chloride = (number of molecules of hydrogen chloride) / (Avogadro's constant)moles

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a) In the set of compounds (Lithium ethoxide, Lithium diisopropylamide, Lithium acetate), the most basic compound is Lithium diisopropylamide, while the least basic compound is Lithium acetate.

Lithium diisopropylamide (LDA) is a strong base commonly used in organic synthesis. It is highly reactive and capable of deprotonating a wide range of acidic compounds. Lithium ethoxide is also a basic compound, but it is less basic compared to LDA. Lithium acetate, on the other hand, is a salt and does not possess significant basic properties.

b) In the set of compounds (Sodium p-chlorobenzoate, Sodium p-nitrobenzoate, Sodium p-methoxybenzoate), the most basic compound is Sodium p-methoxybenzoate, while the least basic compound is Sodium p-nitrobenzoate.

The presence of electron-donating groups, such as the methoxy group (–OCH3), increases the electron density on the benzene ring, making the compound more basic. Sodium p-chlorobenzoate is less basic because the chlorine atom withdraws electron density from the ring. Sodium p-nitrobenzoate is the least basic as the nitro group (–NO2) strongly withdraws electron density from the ring.

c) In the set of compounds (Sodium acetate, Sodium methoxide, Sodium phenoxide), the most basic compound is Sodium methoxide, while the least basic compound is Sodium acetate.

Sodium methoxide (NaOCH3) is a strong base due to the presence of the methoxy group (–OCH3), which can readily donate electrons. Sodium phenoxide (NaOC6H5) is moderately basic because the phenoxide group (–OC6H5) has electron-donating properties. Sodium acetate (NaOAc) is the least basic compound in this set as it does not possess strong electron-donating groups.

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