Answer:
Carbon Monoxide.
With direct fuel injection the gasoline is injected:
Answer:
Gasoline is injected directly into the cylinder.
Explanation:
In a direct injection system, the air and gasoline are not pre-mixed. Rather, air comes in using the intake manifold, while the gasoline is injected directly into the cylinder.
What is the relationship between inductive reactance and frequency?
Answer:
Inductive reactance is denoted by \(X_L\) where
\(X_L=2\pi fL\)
from looking at the equation, you can see that as frequency increases, so does the inductive reactance.
Using three separate situations, record your observations on the ways other drivers handle determining appropriate speed when changing lanes. Where were you? What time of day was it? Could a collision have occurred because of what you saw? Answer in a paragraph containing at least five sentences.
During the next week, observe other people’s driving while you are riding in a vehicle. Are drivers keeping enough space between their vehicles to allow for the total stopping distance? What will you do differently than the people and cars that you observed? Answer in a paragraph containing at least five sentences.
Answer:
Explanation: Changing Lanes Tip 1: scan Explanation: When scanning you check all your mirrors while looking at the road in between, this keeps you aware of your surroundings. Tip 2: check blind spotExplanation: When checking your blind spot you quickly glance to which way you want to change lanes for no more than 2 seconds. Your peripheral vision will pick up any lights or movement. Tip 3: use signals Explanation: When changing lanes use you signal to alert others around you even if no ones around
A steam power plant with a power output of 230 MW consumes coal at a rate of 60 tons/h. If the heating value of the coal is 30,000 kJ/kg, determine the overall efficiency of this plant.
Answer:
\(\eta =46\%\)
Explanation:
Hello!
In this case, we compute the heat output from coal, given its heating value and the mass flow:
\(Q_H=60\frac{tons}{h}*\frac{1000kg}{1ton}*\frac{1h}{3600s}*\frac{30,000kJ}{kg}\\\\Q_H=500,000\frac{kJ}{s}*\frac{1MJ}{1000J} =500MW\)
Next, since the work done by the power plant is 230 MW, we compute the efficiency as shown below:
\(\eta =\frac{230MW}{500MW}*100\% \\\\\eta =46\%\)
Best regards!
Technician A says that tailor-rolled parts may be used for collision energy managements.
Technician B says that tailor-welded parts are aluminum and steel parts joined together. Who is right?
A Only
B only
Both A and B
Neither A nor B
article 515 covers a property or portion of a property where ____ are received by tank vessel, pipelines, tank car, or tank vehicle and are stored or blended in bulk for the purpose of distribution.
Article 515 covers a property or portion of a property where flammable liquids are received by tank vessel, pipelines, tank car, or tank vehicle and are stored or blended in bulk for the purpose of distribution.
Article 515 refers to a section in the National Electrical Code (NEC) that deals with the safety requirements for areas where flammable liquids, gases, or vapors are received, stored, or blended in bulk.
These substances can be received via tank vessels, pipelines, tank cars, or tank vehicles. The primary goal of Article 515 is to minimize the risk of fires, explosions, or other hazards associated with the handling and storage of these potentially dangerous materials.
It sets guidelines for electrical equipment and wiring in these facilities, ensuring that they meet specific safety standards to prevent accidents and protect workers.
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Is a 10 foot ladder long enough to safely reach a landing that is 9 feet above the adjacent floor
Answer:
Definitely not
Explanation:
You should have 1-2 feet of extra ladder on a flat surface so 1 foot on an adjacent floor is a no no
Raven is adding FSMO roles to domain controllers in the domain1.com forest. The forest contains a single domain and three domain controllers, DC1, DC2, and DC3. DC1 contains a copy of the global catalog, and all three domain controllers have the latest version of Windows Server 2019 installed. Which of the following is a best practice that Raven should follow? She should use DC2 or DC3 as the Domain Naming Master. B She should create the Domain Naming Master role on DC1. She should create three Domain Naming Master roles, one for each domain controller. She does not need to create the Domain Master role because DC1 contains a copy of the global catalog.
The best practice that Raven should follow is to use DC2 or DC3 as the Domain Naming Master of the following is a best practice that Raven should follow. The correct option is A.
The management of the addition or deletion of domains from the forest is the responsibility of the Domain Naming Master. For redundancy and fault tolerance, it is advised to split the FSMO roles among several domain controllers.
Since DC1 already has a copy of the global catalog, it is advantageous to choose a different domain controller (DC2 or DC3) as the Domain Naming Master to disperse the workload and guarantee high availability. This ensures that the forest's operations may continue even if one domain controller goes offline and prevents the creation of a single point of failure.
Thus, the ideal selection is option A.
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Which technique controls deflection during installation?
The technique that controls deflection during installation is called bracing. Bracing provides temporary support to structures during construction, ensuring stability and preventing excessive deflection. This is essential for maintaining structural integrity and safety during the installation process
The technique that controls deflection during installation is known as preloading or pre-tensioning. This involves applying a certain amount of tension or compression to the structure or component before it is loaded with the actual loads. By doing so, it reduces the amount of deflection that occurs during installation, ensuring that the final structure is within the required tolerances. Other techniques that can also help control deflection during installation include using temporary supports, adjusting the sequence of installation, and using jacks or hydraulic systems to precisely position the components.
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concrete can take up to ~30 mpa of compressive stress. the density of concrete is about 2.4 g/cc. what is the height limit of a vertical concrete pillar, without fail on its own weight?
The maximum height shall not exceed 4 meters, while the minimum height for buildings without air conditioning is 2.75 meters.
For typical constructions, the minimum distance between columns is 2.5 meters and the maximum span is 7.5 meters. How does the cost of the construction change as the space between columns increases? The cost of the structure rises when the distance between reinforced concrete columns is increased. Most people consider L/r ratios up to 16 for columns' height to be acceptable, but in a rare instance, I once saw a structural consultant's design that had L/r ratios up to 22. L stands for free standing height. "r" refers to the column's breadth, which is its smallest lateral dimension.
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Any one know the answer?
Answer:
151.2 N
Explanation:
The upward force at A is 135/(135+325) times the total weight of the generator. The CW torque about point O that produces is ...
(460 mm)(135/460)(160 kg)(9.8 m/s^2) = 211.68 N·m
For F to produce half that torque, it must be ...
F(0.7 m) = (211.68 N·m)/2
F = 211.68 N·m/(1.4 m) = 151.2 N
If a bearing needs 4. 0 s to solidify enough for impact, how high must the tower be?.
In order to determine the height of the tower, we would apply the second equation of motion and assume that the downward motion is negative.
Mathematically, the second equation of motion is given by this formula:
S = ut + ½gt²
Where:
S represents the distance or height.u represents the initial velocity.a represents the acceleration.t represents the time.Substituting the given parameters into the formula, we have;
S = S₀ + ut - ½gt²
0 = S₀ + (0)4.0 - ½ × (9.8) × 4.0²
0 = S₀ - 4.9 × 16.0
Height, S₀ = 78.4 meters.
How to calculate the bearing's impact velocity?In order to calculate the bearing's impact velocity, we would apply the first equation of motion:
V = u - at
V = 0 - 9.8(4.0)
Impact velocity, V = 39.2 m/s.
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Complete Question:
Ball bearings can be made by letting spherical drops of molten metal fall inside a tall tower, called a shot tower, and solidify as they fall.
a. If a bearing needs 4.0 s to solidify enough for impact, how high must the tower be?
b. What is the bearing's impact velocity?
Two pass shell and tube HX Hot fluid flow rate {q2mb} kg/h 6000 Cold fluid flow rate 12000 kg/h Hot and cold fluid are same, oil with Cp 3200 J/kgk Hot fluid temperature inlet 80 deg C Cold fluid temperature inlet 22 deg C UA product 11487.5 W/K Calculate NTU
The NTU (Number of Transfer Units) value for the given shell and tube heat exchanger can be calculated as follows:
NTU = (UA) / (C_min)
The NTU method is used to analyze heat transfer in a heat exchanger. It provides a dimensionless parameter that represents the effectiveness of the heat transfer process. NTU is calculated using the formula NTU = (UA) / (C_min), where UA is the overall heat transfer coefficient multiplied by the surface area of the heat exchanger, and C_min is the minimum heat capacity rate of the two fluids involved.
In this case, the hot and cold fluids have the same flow rate and specific heat capacity. Since the specific heat capacity (Cp) of the fluid is not given, it is assumed to be constant. Therefore, the minimum heat capacity rate (C_min) can be determined by selecting the fluid with the lower mass flow rate.
By plugging in the given values for the UA product (11487.5 W/K) and the flow rates, we can calculate the NTU value for the heat exchanger.
Step 3: Calculation
C_min = min(q2mb * Cp, q1mb * Cp) = min(6000 kg/h * 3200 J/kgK, 12000 kg/h * 3200 J/kgK) = 6000 kg/h * 3200 J/kgK = 1,920,000 J/hK
NTU = (UA) / (C_min) = 11487.5 W/K / (1,920,000 J/hK) = 0.00598
Therefore, the NTU value for the given shell and tube heat exchanger is approximately 0.00598.
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What type of caliper is shown here?
Answer:
its a floating caliper definetly
This part of the proposal begins with a capsule statement and then proceeds to introduce the subject to a stranger
Answer:
nsnsndndnndndndnhhhh
A specimen of steel having an initial diameter of 0.503 in was tested in tension using a gauge length of 2 in. The following data were obtained for the elastic and plastic states: Elastic State Load P lbf Elongation in 1 000 0.0004 2 000 0.0006 3 000 0.0010 4 000 0.0013 7 000 0.0023 8 400 0.0028 8 800 0.0036 9 200 0.0089 Plastic State Load P lbf Area A; in? 8 800 0.1984 9 200 0.1978 9 100 0.1963 13 200 0.1924 15 200 0.1875 17 000 0.1563 16 400 0.1307 14 800 0.1077 Note that there is some overlap in the data. (a) Plot the engineering or nominal stress-strain diagram using two scales for the unit strain , one scale from zero to about 0.02 in/in and the other scale from zero to maximum strain. (6) From this diagram find the modulus of elasticity, the 0.2 percent offset yield strength, the ultimate strength, and the percent reduction in area. (C) Characterize the material as ductile or brittle. Explain your reasoning. (d) Identify a material specification from Table A-20 that has a reasonable match to the data.
400 x 8 = 50, 40,000 x 800 = 50, and 40,000 x 80 = 500 will be the correct formulae. Then C, D, and E are the appropriate choices.
A fraction number is a number that denotes a portion of an entire number, where the entire number itself can be any integer. It takes the shape of a denominator and a numerator. Let's examine each option, and then we have A. 400 ÷ 80 ≠ 50 B. 4, 000 ÷ 80 ≠ 5 C. 400 ÷ 8 = 50 D. 40,000 ÷ 800 = 50 E. 40,000 ÷ 80 = 500. 400 x 8 = 50, 40,000 x 800 = 50, and 40,000 x 80 = 500 will be the correct formulae. Then C, D, and E are the appropriate choices. The maximum stress on the stress vs. strain graph corresponds to the tensile strength, which can be roughly calculated at 370Mpa (complete plot)
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what is geometrical shape?
Explanation:
Geometric Shapes can be defined as figure or area closed by a boundary which is created by combining the specific amount of curves, points, and lines.
Answer:
Geometric shapes are mathematical shapes. They are perfect and regular. They are characterized by straight lines, angles and points. An exception to this would be a perfect circle as it has no straight lines or points. Other geometric shapes are squares, rectangles, triangles, parallelograms, hexagons, etc.
Explanation:
Hi im ***ar and im doing sculptural but what should it be about star wars or Marvel
Answer:
Cool I think u should do Marvel first
Inhalation is the most common way for a(n)
to enter the body.
electrical current
Information
Chemical
Water
inhalation is the most common way for chemical to enter the body
What is the purpose of a pinnacle that sits on the out edge of a flying buttress?
The purpose of a pinnacle that sits on the outer edge of a flying buttress is to provide additional support and stability to the structure.
A flying buttress is an architectural element that is used to distribute the weight of a structure away from the walls and towards the ground. The weight of the structure is transferred to the flying buttress, which in turn transfers it to the ground.
The pinnacle, which sits on top of the flying buttress, provides additional support and stability to the structure by preventing the flying buttress from moving or shifting. It also helps to distribute the weight of the structure evenly across the flying buttress, reducing the stress on any one point.
In addition to providing support and stability, the pinnacle also serves a decorative function. It is often ornately carved or decorated with sculptures or other artistic elements, adding to the beauty of the structure.Overall, the purpose of a pinnacle on the outer edge of a flying buttress is to provide both structural support and aesthetic appeal to the building.
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The hydrofoil boat has an A-36 steel propeller shaft that is 100 ft long. It is connected to an in-line diesel engine that delivers a maximum power of 2490 hp and causes the shaft to
The question is incomplete. The complete question is :
The hydrofoil boat has an A-36 steel propeller shaft that is 100 ft long. It is connected to an in-line diesel engine that delivers a maximum power of 2590 hp and causes the shaft to rotate at 1700 rpm . If the outer diameter of the shaft is 8 in. and the wall thickness is \($\frac{3}{8}$\) in.
A) Determine the maximum shear stress developed in the shaft.
\($\tau_{max}$\) = ?
B) Also, what is the "wind up," or angle of twist in the shaft at full power?
\($ \phi $\) = ?
Solution :
Given :
Angular speed, ω = 1700 rpm
\($ = 1700 \frac{\text{rev}}{\text{min}}\left(\frac{2 \pi \text{ rad}}{\text{rev}}\right) \frac{1 \text{ min}}{60 \ \text{s}}$\)
\($= 56.67 \pi \text{ rad/s}$\)
Power \($= 2590 \text{ hp} \left( \frac{550 \text{ ft. lb/s}}{1 \text{ hp}}\right)$\)
= 1424500 ft. lb/s
Torque, \($T = \frac{P}{\omega}$\)
\($=\frac{1424500}{56.67 \pi}$\)
= 8001.27 lb.ft
A). Therefore, maximum shear stress is given by :
Applying the torsion formula
\($\tau_{max} = \frac{T_c}{J}$\)
\($=\frac{8001.27 \times 12 \times 4}{\frac{\pi}{2}\left(4^2 - 3.625^4 \right)}$\)
= 2.93 ksi
B). Angle of twist :
\($\phi = \frac{TL}{JG}$\)
\($=\frac{8001.27 \times 12 \times 100 \times 12}{\frac{\pi}{2}\left(4^4 - 3.625^4\right) \times 11 \times 10^3}$\)
= 0.08002 rad
= 4.58°
Water flows around a 6-ft diameter bridge pier with a velocity of 12 ft/s. Estimate the force (per unit length) that the water exerts on the pier. Assume that the flow can be approximated as an potential fluid flow around the front half of the cylinder, but due to flow seperation, the average pressure on the rea half is constant and approximately equal to 1/2 the pressure at point A.
Answer: hello the diagram related to your question is missing please the third image is the missing part of the question
Fx = 977.76 Ib/ft
Explanation:
Estimate the force that water exerts on the pier
V = 12 ft/s
D( diameter ) = 6 ft
first express the force on the first half of the cylinder as
Fx1 = - \(-2\int\limits^\pi _\frac{\pi }{2} {Ps*cos\beta *a} \, d\beta\) ---------------- ( 1 )
where ; Fy = 0
Ps = Po + 1/2 Pv^2 ( 1 - 4 sin^2β ) ------------- ( 2 )
Input equation (2) into equation ( 1 ) (note : assuming Po = 0 )
attached below is the remaining part of the solution
An elevation is.... * 10 points a. A detailed description of requirements, composition and materials for a proposed building. b. A view of a building seen from one side, a flat representation of one façade. This is the most common view used to describe the external appearance of a building. c. The development of the last remaining lots in an existing developed area, the new development within an area already served by existing infrastructure and services, or the reuse of already developed, but vacant properties. d. The practice of creating structures and using processes that are environmentally responsible and resource-efficient throughout a building's life-cycle from siting to design, construction, operation, maintenance, renovation and deconstruction.
Answer:
b. A view of a building seen from one side, a flat representation of one façade. This is the most common view used to describe the external appearance of a building.
Explanation:
An elevation is a three-dimensional, orthographic, architectural projection that reveals just a side of the building. It is represented with diagrams and shadows are used to create the effect of a three-dimensional image.
It reveals the position of the building from ground-depth and only the outer parts of the structure are illustrated. Elevations, building plans, and section drawings are always drawn together by the architects.
consider the kb a => c b <=> c d => a (b and e) => g b => f e d show that this entails g (if possible) by i. forward chaining ii. backward chaining iii. resolution
The given knowledge base contains a set of logical implications. The task is to determine if the entailment of "g" can be derived from the knowledge base using forward chaining, backward chaining, or resolution. Given the knowledge base (KB) with the rules a => c, b <=> c, d => a, (b and e) => g, b => f, and e, d,
(i) Forward Chaining: Starting with the known facts, we apply the rules in the knowledge base to derive new conclusions. By applying the given implications iteratively, we can determine if "g" can be derived. In this case, forward chaining would result in "g" being derived.
(ii) Backward Chaining: We start with the goal "g" and work backward, using the implications in reverse to find supporting facts. By applying the rules in reverse, starting with "g" and checking if the preconditions are satisfied, we can determine if "g" can be derived. In this case, backward chaining would also result in "g" being derived.
(iii) Resolution: Resolution is a method of logical inference that involves resolving logical clauses to derive new conclusions. It involves constructing a logical proof by negating the goal and using resolution steps with the clauses in the knowledge base. By applying resolution steps to the given knowledge base and the negation of "g," we can determine if a contradiction is reached. If a contradiction is reached, then "g" can be derived. In this case, resolution would also result in deriving "g."
Therefore, all three methods of forward chaining, backward chaining, and resolution would entail the derivation of "g" from the given knowledge base.
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Determine the combined moment about O due to the weight of the mailbox and the cross member AB. The mailbox weighs 3.2 lb and the uniform cross member weighs 10.3 lb. Both weights act at the geometric centers of the respective items. The moment will be positive if counterclockwise, negative if clockwise.
Answer:
Attached is the complete question but the weight of the mailbox and cross bar differs from the given values which are : weight of mail box = 3.2 Ib, weight of the uniform cross member = 10.3 Ib
Answer : moment of inertia = 186.7 Ib - in
Explanation:
Given data
weight of the mailbox = 3.2 Ib
weight of the uniform cross member = 10.3 Ib
The origin is of mailbox and cross member is 0
The perpendicular distance from Y axis of centroid of the mailbox
= 4 + (25/2) = 16.5"
The centroid of the bar =( ( 1 + 25 + 4 + 4 ) / 2 ) - 4 = 13"
therefore The moment of Inertia( Mo) = (3.2 * 16.5) + ( 10.3 * 13)
= 52.8 + 133.9 = 186.7 Ib-in
The combined moment about O due to the weight of the mailbox and the cross member AB is; M_o = 122.4 lb.in (ccw)
We are given;
Weight of mailbox; W_m = 3.2 lb
Weight of uniform cross member; W_c = 10.3 lb
Now, from the attached diagram, let us calculate the geometric location of the mailbox and uniform cross section from point O.
Geometric location of mailbox from point O; g_m = 3 + (19/2) = 12.5 in
Geometric location of cross member from point O;
g_c = (¹/₂(1 + 19 + 3 + 7)) - 7
g_c = 8 in
Thus. combined moment about point O is;
M_o = (W_m × g_m) + (W_c × g_c)
M_o = (3.2 × 12.5) + (10.3 × 8)
M_o = 122.4 lb.in
Since positive then it is counterclockwise. Thus;
M_o = 122.4 lb.in (ccw)
The image of this question is missing and so i have attached it.
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g ) Water is the working fluid in an ideal regenerative Rankine cycle with one closed feedwater heater. Superheated vapor enters the turbine at 16 MPa, 560 oC, and the condenser pressure is 8 kPa. The cycle has a closed feedwater heater using extracted steam at 1 MPa. Condensate drains from the feedwater heater as saturated liquid at 1 MPa and is trapped into the condenser. The feedwater leaves the heater at 16 MPa and a temperature equal to the saturation temperature at 1 MPa. The mass flow rate of steam entering the first-stage turbine is 120 kg/s. Determine (a) the net power developed, in kW.
Answer:
146494 kw
Explanation:
Given data:
Turbine inlet pressure ( p1 ) = 16 MPa
Turbine inlet temperature ( T1 ) = 560°C
condenser pressure : P3 = 8Kpa
Extracted steam at pressure ( P2 ) = 1 MPa
mass flow rate of steam ( m ) = 120 kg/s
a) The net power developed
= 146494 kw
note: values of h1, h2, y, Wp are all calculated values not included in the solution to make the solution less cumbersome.
Equipment costing $12,000 with a 10-year useful life and an estimated $2,000 salvage value is acquired and started operating on January 1. The equipment is estimated to produce 2,000 units of product during its life. It produced 300 units in the first year.
Record the journal entries for equipment depreciation for the first year under straight-line, units-of-production, and double-declining-balance.
Straight-line: Depreciation Expense $1,000, Accumulated Depreciation $1,000; Units-of-production: Depreciation Expense $1,500, Accumulated Depreciation $1,500; Double-declining-balance: Depreciation Expense $2,400, Accumulated Depreciation $2,400.
Define the term Depreciation
Depreciation refers to the process of allocating the cost of a tangible asset (such as a building, machinery, or equipment) over its useful life in a systematic and rational manner. Depreciation is a way to recognize the decrease in the value of an asset over time due to wear and tear, obsolescence, and other factors that cause the asset to become less useful or less valuable. The purpose of depreciation is to match the cost of an asset with the revenue it generates over its useful life and to properly report the value of assets on the balance sheet.
Straight-line depreciation:
The annual depreciation expense is calculated as follows:
($12,000 - $2,000) / 10 years = $1,000 per year.
Journal entry for straight-line depreciation at the end of the first year:
Depreciation Expense $1,000
Accumulated Depreciation $1,000
Units-of-production depreciation:
The depreciation expense is based on the number of units produced in a year. The per-unit depreciation rate is calculated as follows:
($12,000 - $2,000) / 2,000 units = $5 per unit.
Journal entry for units-of-production depreciation at the end of the first year:
Depreciation Expense $1,500 ($5 x 300 units produced)
Accumulated Depreciation $1,500
Double-declining-balance depreciation:
The double-declining-balance method depreciates the asset at twice the straight-line rate. The annual depreciation expense is calculated as follows:
2 x ($12,000 - $2,000) / 10 years = $2,000 per year.
Journal entry for double-declining-balance depreciation at the end of the first year:
Depreciation Expense $2,400 ($2,000 x 300 / 2,000)
Accumulated Depreciation $2,400
Therefore, the double-declining-balance method may not result in the salvage value being reached at the end of the asset's useful life. If the accumulated depreciation exceeds the asset's cost minus salvage value, the excess is considered to be "over-depreciation" and should be reversed.
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Draw Shear and Moment Diagrams for the beam shown blow, and find the Reactions, Vmax, and Max. Answer the following questions, and you can also upload a file showing the calculations at the end of the quiz.
15 kips
35 kips
12 kips
- 1.2 kips/ft
A
6'-0"
B
9'_0"
14'_0"
10'-0"
Answer: Can't help
Explanation:
uestion 10
0
On a day where the temperature is (25 C) and the pressure is
101.2 kPa, and assuming that the take-off speed is (150 miles per
hour). How much drag is produced if the coefficient of drag is
0.045? The wing area is 22 m2 and has a mass of 1250 kg.
A plate of width 84mm and thickness 10mm is to be welded to another plate by means of double parallel fillets. The plates are subjected to a static load of 86kN and the maximum permissible shear stress is 3.5MPa.. 1. Find the length of the weld in millimeters(mm).
Answer:
d
Explanation:
i did the test