Answer:
nicotine
Explanation:
Suppose you begin feeling extremely depressed and want a prescription drug to alleviate your depression. the drug you should take should affect the neurotransmitter:_______
When you start feeling extremely depressed and need a prescription drug to help you feel better. The medication you should take should have an effect on the neurotransmitter is : Serotonin.
Serotonin is a chemical that carries messages between nerve cells in the brain and throughout your body. Serotonin, also known as the "feel-good" chemical, is just another neurotransmitter. Serotonin performs numerous functions in the body, including those related to the gut, blood clotting, and sexual function, in addition to assisting with mood regulation.
Studies suggest that depression in some people may be complicated by low levels of certain brain chemicals, or neurotransmitters. The various classes of antidepressant medications may be able to reduce symptoms by restoring the balance of brain chemicals.
Depression is a quite very difficult condition to treat, even with the aid of drugs that help the brain's neurotransmitters balance specific neurotransmitters.
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Conductors of electricity *
A.Nonmetal
B-Metalloid
C-Metal
Answer:
Conductors of electricity?
The Answer is C metal :)
xXxAnimexXx
A cross-country skier moves 36 meters eastward, then 44
meters westward, and finally 22 meters eastward.
For this motion, what is the distance moved?
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Distance = 102
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number pad.
What is the magnitude and direction of the
displacement?
Magnitude =
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Answer:
a) 102 meters
b) 14 meters
c) The direction is eastward.
Explanation:
Distance is said to be the length between two points. It is a scalar quantity.
a) The distance moved = 36 + 44 + 22
= 102 meters
b) Displacement is the distance moved in a specified direction.
Representing the distance moved with specific direction as a directed number, 36 meters eastward = +36, 44 meters westward = -44, and 22 meters eastward = +22
/Displacement/ = +36 -44 +22
= +58-44
= 14
The magnitude of the displacement is 14 meters.
c) The direction is eastward.
So that the magnitude of displacement and his direction is 14 meters eastward.
Juanita studies several free-body diagrams in which a normal force is shown. What is always true about a normal force in a free-body diagram?
Answer: B
Explanation: it is perpendicular to a surface
Answer:
it is perpendicular to a surface
Explanation:
The imaginary, huge, apparently moving sphere on which the stars appear to be mounted is called the __________ sphere
The imaginary, huge, apparently moving sphere on which the stars appear to be mounted is called the celestial sphere.
The celestial sphere is a concept used in astronomy to represent the appearance of the stars as if they are fixed on a gigantic sphere surrounding the Earth. It is a helpful tool for astronomers to study the positions and movements of celestial objects, such as stars, planets, and galaxies.
Although the celestial sphere is an imaginary construct, it provides a convenient reference frame for locating and observing celestial objects. It allows astronomers to measure the positions of stars and track their apparent motion across the sky. By using coordinates on the celestial sphere, such as declination and right ascension, astronomers can precisely describe the location of a celestial object.
One important thing to note is that the celestial sphere is not a physical object but rather a way of visualizing the sky. It is an imaginary projection of the Earth's equator and celestial poles onto the sky. The celestial equator is a projection of the Earth's equator onto the celestial sphere, while the celestial poles are projections of the Earth's North and South Poles.
To summarize, the celestial sphere is an imaginary, huge, apparently moving sphere on which the stars appear to be mounted. It helps astronomers study and understand the positions and movements of celestial objects.
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a concave mirror has a focal length f 20cm. what is the position in cm of the resulting image if the image is inverted and four times smaller than the project
When the concave mirror is to be placed very close to the given object, a magnified and the virtual image is obtained.
What is a concave mirror?A concave mirror is the mirror that is bent in middle towards the inside. Furthermore, looking in the mirror will give you the impression that you are looking in the cave. Furthermore, we must employ the mirror equation when dealing with a concave mirror.
A mirror is the object that reflects light at same angle as it receives it. In addition, the incident angle must equals the angle of reflection in a given mirror. Furthermore, the reflected light had the same intensity as the projected light.
Furthermore, there are three types of known mirrors.
Simple MirrorMirror with Concave SurfaceMirror with Convex SurfaceA concave mirror is a mirror that is to be bent in the middle towards the inside.For the given concave mirror,
f = -20 cm
M=v/u=2
⇒v=−2u
1st case (Virtual image)
1v+1u=1f
⇒12u−1u=1f
⇒12u=1f
⇒u=f2=10 cm
∴ The positions are 10 cm or 30 cm from the concave mirror.
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Electromagnetic waves are a form of what type of energy?
Let me know if its correct or incorrect.
Answer:
The correct answer is - radiant.
Explanation:
Electromagnetic waves are the transverse waves that get energy as radiation from the source and transfer to an absorber so, the radiant energy is the energy of electromagnetic waves.
Electromagnetic waves are can travel in space unlike mechanical waves and are made up of photons, tiny packets of energy. Electromagnetic waves or spectra include radio waves, infrared, light, microwaves, UV, X-rays, and gamma rays.
During which interval is the cart accelerating?
the barriers if the interval are Aand B the of displacement goes up.
from B to C it just stays the same, then from C to D no Movement, and from time D to E movement, but steady
A motorcycle cop, parked at the side of a highway reading a magazine, is passed by a woman in a red Ferrari 308 GTS doing 120.0 km/h. After a few attempts to get his cycle started, the officer roars off 2.00 s later. At what average rate must he accelerate if 159 km/h is his top speed and he is to catch her just at the state line 3.04 km away?
Answer:
XZXDHF
Explanation:ZDHF
What does the pressure at a point in a fluid depend on? select all that apply.
The pressure at a point in a fluid depends on depth of the point in the fluid, density of the fluid, gravity, acceleration at the point
When we talk about fluids, pressure is defined as the force exerted per unit area by the molecules in motion. The pressure of a fluid at a particular point depends on many factors. These include the density of the fluid, depth of the point in the fluid, gravity, and acceleration at the point. The deeper a point is, the higher the pressure is, since the weight of the fluid above it increases.
As the density of the fluid increases, the pressure also increases. The acceleration at the point can affect pressure since it can alter the pressure gradient within the fluid. The formula for calculating pressure at a point in a fluid is P = ρgh. Here, P is the pressure, ρ is the density of the fluid, g is the acceleration due to gravity, and h is the depth of the point in the fluid. So therefore the pressure at a point in a fluid depends on the depth of the point in the fluid, the density of the fluid, gravity and acceleration at the point
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the equation F=(9)/(5)C+32 gives the fahrenheit temperature corresponding to the celsius find the fahrenheit temperature equivalent to 25 celsius
The given equation,F = (9/5)C + 32gives the Fahrenheit temperature corresponding to the Celsius. To find the Fahrenheit temperature equivalent to 25 Celsius, we will substitute the given value of Celsius into the above equation.
So, F = (9/5)(25) + 32F = 45 + 32F = 77Hence, the Fahrenheit temperature equivalent to 25 Celsius is 77 degrees Fahrenheit.
To find the Fahrenheit temperature equivalent to a given Celsius temperature, we use the equation
F = (9/5)C + 32, whereF is the Fahrenheit temperature andC is the Celsius temperature.
The equation is derived from the relationship between the Celsius and Fahrenheit temperature scales.In this equation, 9/5 is a conversion factor used to convert the Celsius temperature to Fahrenheit.
The constant 32 is added to the product of the conversion factor and the Celsius temperature to get the Fahrenheit temperature.The question asks us to find the Fahrenheit temperature equivalent to 25 Celsius. To do this, we substitute the given value of Celsius into the equation.
So, we haveF = (9/5)(25) + 32Simplifying the right-hand side, we getF = 45 + 32Evaluating the expression,
we getF = 77Therefore, the Fahrenheit temperature equivalent to 25 Celsius is 77 degrees Fahrenheit.
Thus, we can conclude that the Fahrenheit temperature equivalent to 25 Celsius is 77 degrees Fahrenheit, which we found using the equation F = (9/5)C + 32.
This equation is used to convert Celsius temperatures to Fahrenheit temperatures. The conversion factor 9/5 is multiplied by the Celsius temperature, and 32 is added to the result to get the Fahrenheit temperature.
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A bullet of mass 0.01 kg is fired into a sandbag of mass 0.49 kg hanging from a tree .The sandbag, with the bullet embedded into it, swings away at 10m/s.
find:
a.The momentum after the collision.
b.The momentum before the collision.
c.The velocity of the bullet.
Answer:
B is the best option but A is also good it's up to you but I'm leaning more towards B
Answer:
momentum after=momentum before
momentum before=Mbullet*Vbullet
Momentum after=(.49+.01)10=Mb*Vb
solve for V bullet
As you walk to science class, you start out at a speed of 2 m/s, for a time of 120 seconds (you’re really excited to get to class). Then you see your friend and slow down to a speed of 0.5m/s for 30 seconds. You stop at your locker for 40 seconds (a speed of 0 m/s). You realize that you are about to be late so you hurry to class at a speed of 1 m/s and get to class just as the bell rings (4 minutes after your trip started). How far did you travel total?
The total travelled distance is • Speed, time and distance is one of the most common and important topics in the Mathematics or Quant section.
What is Speed?Velocity is the pace and direction of an object's movement, whereas speed is the time rate at which an object is travelling along a path. In other words, velocity is a vector, whereas speed is a scalar value.
For instance, 50 km/hr west denotes the velocity of a car whereas 50 km/hr (31 mph) denotes the speed at which it is moving down a route.
The average speed of an object is determined by dividing the distance traveled by the amount of time it takes the object to reach the distance.
Therefore, The total travelled distance is • Speed, time and distance is one of the most common and important topics in the Mathematics or Quant section.
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A ball dropped and accelerates downwards at a rate of 10m/s^2 for 15 seconds how much will the balls velocity increase
Answer:
v = 150 m/s
Explanation:
Given that,
The acceleration of the ball, a = 10 m/s²
Time, t = 15 s
We need to find the increase in ball's velocity. When it is dropped its initial velocity is equal to 0. Let v be the velocity,
v = u+at
v = 0 +10(15)
v = 150 m/s
So, the ball's final velocity is 150 m/s.
Hello please .
How far would a person run in seconds at an average speed of 7ms-1
At an average speed of 7m/s, the distance covered in one second is 7 meters.
What is the distance covered in one second?Speed is simply referred to as distance traveled per unit time.
It is expressed mathematically as;
Speed = Distance ÷ time.
Given the data in the question;
Speed = 7m/sElapsed time = 1 secondDistance traveled = ?Plug the given values into the above formula and solve for distance traveled.
Speed = Distance ÷ time
Distance = Speed × Time
Distance = 7m/s × 1.0s
Distance = 7ms/s
Distance = 7m
Therefore, in a second, the person covers 7 meters.
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10-1 The license-free IEEE802.11 radio, also known as the Wi-Fi, can operate in the 2.4GHz industrial, scientific, and medical (ISM) radio band that has a frequency range of 2.4-2.4835 GHz. Each Wi-Fi transmission takes 22MHz bandwidth. (a) Determine how many non-overlapping channels can be accommodated in the 2.4GHz ISM band. (b) IEEE 802.11 standard allows 13 overlapping channel settings in this band from Channel 1 (centered at 2.412GHz ) up to Channel 13 (centered at 2.472GHz ). Adjacent channel center frequencies are 5MHz apart. If one of your close neighbors has set up his/her Wi-Fi on Channel 4 centered at 2.427GHz, what are possible channel settings you should use for your Wi-Fi network in this ISM band to avoid interference?
The Wi-Fi radio with a transmission bandwidth of 22MHz can accommodate 4 non-overlapping channels within the 2.4G Hz ISM radio band.
Channels 1, 6, and 11 are the possible channel settings you could use for your Wi-Fi network in the ISM band if your neighbour has set up his/her Wi-Fi on Channel 4 centred at 2.427 GHz to avoid interference.
The Wi-Fi radio (IEEE802.11) with a transmission bandwidth of 22MHz can accommodate non-overlapping channels within the 2.4GHz ISM radio band.
The range of the ISM band frequency is 2.4-2.4835 G Hz. In order to find the number of non-overlapping channels within the 2.4GHz ISM radio band, we will first find the number of available channels. We use the formula given below:
Number of channels = (Frequency Range)/(Bandwidth)
Number of channels = (2.4835-2.4)/22 MHz 3.8 4
Hence, there are 4 non-overlapping channels available in the 2.4GHz ISM radio band.
The Wi-Fi radio (IEEE802.11) has 13 overlapping channel settings in the 2.4 GHz ISM band.
The channel settings range from channel 1 centred at 2.412 GHz to channel 13 centred at 2.472 GHz. The adjacent channel centre frequencies are 5MHz apart. A close neighbour has set up his/her Wi-Fi on Channel 4 centred at 2.427GHz.
To avoid interference, possible channel settings you could use for your Wi-Fi network in the ISM band are as follows:
Channels 1, 6, and 11 have no overlapping with Channel 4 because they are at a separation of at least 25MHz away from Channel 4.
Therefore, you should choose any of these channels for your Wi-Fi network.
The Wi-Fi radio with a transmission bandwidth of 22MHz can accommodate 4 non-overlapping channels within the 2.4G Hz ISM radio band. Channels 1, 6, and 11 are the possible channel settings you could use for your Wi-Fi network in the ISM band if your neighbour has set up his/her Wi-Fi on Channel 4 centred at 2.427 GHz to avoid interference.
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Alllura is running to the blue lion so she can join the others in forming voltron. if allura starts off
running at 2.50m/s and after 3.00s she has reached a velocity of 8.25m/s. what is her acceleration
over this time in meters per second
The acceleration will be 1.9166 m/s². According to Newton's second law, the eventual effect of all forces applied to a body is its acceleration.
What is acceleration?The rate of change of velocity with respect to time is known as acceleration.
Given data:
u(Initial velocity)=2.50m/s
v(Final velocity)=8.25m/s
t(time period)= 3.00s
The acceleration of the Allura will be :
\(\rm a = \frac{v-u}{t} \\\\ a= \frac{8.25-2.50 }{3.00 }\\\\ a= 1.9166 \ m/s^2\)
Hence, the acceleration will be 1.9166 m/s².
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Im struggling on my physics work about velocity
Answer:
53.8
Explanation:
Knowns:
Distance - 1,400
Speed - 52
Unknowns:
Velocity - ?
V = 2(\(\frac{Distance}{Time}\))
V = 2(\(\frac{1,400}{52}\))
V = 2(26.9)
V = 53.8
SOMEONE HELP W THESE QUESTIONS PLEASEEE
3m/s²
5m/s²
I hope it helps
What does the root cand mean in the word candescent?
The candescent quality of the room was improved by the southern exposure.
Answer:
Glowing
Explanation:
Temperature of an object is 250 K. Find its temperature in centigrade.
help me in this assignment
Answer:
T = 526°C
Explanation:
Given the following data;
Temperature in Kelvin = 250K
To convert kelvin to centigrade;
Temperature can be defined as a measure of the degree of coldness or hotness of a physical object. It is measured with a thermometer and its units are Celsius (°C), Kelvin (K) and Fahrenheit (°F)
Mathematically, it is given by the formula;
250 = 273 + C
Substituting into the equation, we have;
C = 273 + 250
T = 526°C
Two planets X and Y travel counterclockwise in circular orbits about a star, as seen in the figure. The radii of their orbits are in the ratio 2:1. At some time, they are aligned, as seen in (a), making a straight line with the star. Five years later, planet X has rotated through 90.9°, as seen in (b). By what angle has planet Y rotated through during this time?
By 272.7 degrees angle has planet Y rotated through during this time.
What is Kepler's 3rd law?The cubes of the semi-major axes of the planets' orbits are precisely proportional to the squares of the planets' orbital periods. According to Kepler's Third Law, as an orbiting planet's radius rises, so does the time of its orbit around the Sun.
Using Kepler's 3rd law, which says that the period of any planet's orbit squared is proportional to the radius of the orbit cubes, we can establish that
(period X / period Y)^2 = (radius X / radius Y)^3
(period X / period Y)^2 = 2^3 = 8
take sq root
period X / period Y = √8 = 2.82≅ 3
this means it takes planet X 2.82≅ 3 times longer to go through one orbit... so planet Y travels 2.82≅ 3 times as far (in its orbit...) as planet X!
This means...
planet Y travels 3 * 90.9 = 272.7 degrees
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In the cost equation T C = F + V X , V is best described as the: (a) Costs that do not vary with changes in the activity level (b) Intercept of the cost equation (c) Slope of the cost equation (d) Activity level used to estimate the dependent variable
In the cost equation TC = F + VX, V is best described as the slope of the cost equation. Hence, option (c) is correct.
In this equation, TC represents the total cost, F represents the fixed costs (costs that do not vary with changes in activity level), X represents the activity level, and V represents the variable cost per unit of activity. The variable cost is the portion of the total cost that varies with the level of activity.
The slope of the cost equation (V) represents the rate at which the total cost changes with respect to changes in the activity level. It indicates the increase in total cost for each additional unit of activity.
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what is the difference between mechanical advantage and distance advantage?
A gymnast balancing on a beam will put her arms out. Why does this help?
By keeping their centre of gravity over the beam, a gymnast may balance himself. The gymnast increases their moment of inertia, or resistance to rotational motion, by spreading their arms out to the sides, making it harder to unintentionally tilt or spin. As a result, their body is more stable, aiding in balance maintenance. Moreover, the centre of mass can be slightly adjusted with the arm movements to make up for any minor deviations from the equilibrium position. The gymnast can also orient oneself in relation to the beam using the visual clues provided by the arms. Overall, while balancing on a beam, a gymnast can gain various advantages from extending their arms to the side, including increased stability and many more.
A planet's moon travels in an approximately circular orbit of radius 8.6 107 m with a period of 6 h 25 min. Calculate the mass of the planet from this information.
Answer:
m v^2 / R = G M m / R^2 gravitational attraction = centripetal force
M = v^2 R / G solving for M
period = 6 h 25 min = (6 * 3600 + 25 * 60) sec = 23,100 sec = T
v = 2 pi R / T
M = 4 pi^2 R^3 / (G T^2)
M = 39.5 * (8.6E7)^3 / (6.67E-11 * 2.31E4^2)
M = 39.5 * 636 / (6.67 * 5.34) * 10^24
M = 7.05 * 10^26 kg
A force of 49N causes a box to move with an acceleration of 7m/s2. Find the mass of the object
Answer:
The answer is 7 kgExplanation:
To find the mass of the object given the force and acceleration we use the formula
\(m = \frac{f}{a} \\ \)
where
f is the force
a is the acceleration
m is the mass
From the question
f = 49 N
a = 7 m/s²
We have
\(m = \frac{49}{7} \\ \)
We have the final answer as
7 kgHope this helps you
what is the difference between copernicus and kepler description of planetary orbits?
Answer:
Kepler refined the Copernican model. Orbits are not circles along which planets move at a constant speed, but ellipses, in the central focus of which is the Sun. The planet moves in an ellipse with a variable speed depending on the distance to the Sun. On this basis, Kepler significantly simplified the Copernican model and formulated the laws of planetary motion in their orbits.
Jimmy walks at 60 meters per minute. It takes him 21 minutes to walk from home to school. If he runs at 180 meters per minute, how long does it take him to run from school to home
Answer:
it takes him 7 minutes to return home. the unit is the same. just faind the difference between 180 and 60 you doughnut
A woman is standing on a steep hillside in the rain and is not moving. A
sudden gust of wind blows down the hillside, which makes her start sliding
down the hill. When the wind stops blowing, the woman continues to slide.
Which of the following statements explains why she continues to slide down
the hillside?
A. The component of the woman's weight along the hillside is larger
than the kinetic friction between the woman and the ground.
B. The component of the woman's weight along the hillside is less
than the kinetic friction between the woman and the ground.
C. The component of the woman's weight along the hillside is larger
than the static friction between the woman and the ground.
D. The component of the woman's weight along the hillside is less
than the static friction between the woman and the ground.
SUBMIT
Answer:
The correct option is;
A. The component of the woman's weight along the hillside is larger than the kinetic friction between the woman and the ground
Explanation:
Given that the coefficient of static friction is always larger than the coefficient of kinetic friction, we have that before the wind blew, the component of the woman's weight along the hillside was lesser than the static friction between the woman and the ground, when the wind blew the total force of the wind and the component of the woman's weight put her into motion such that the acting frictional force was then the kinetic frictional force which was lesser than the kinetic frictional force so the woman continues to slide down the hillside without the wind.